Answer:
x = ±sqrt(26)
Step-by-step explanation:
ln ( x^2 -25) = 0
Raise each side to base e
e^ln ( x^2 -25) = e^0
x^2 -25 = 1
Add 25 to each side
x^2 -25 +25 = 1+25
x^2 = 26
Take the square root of each side
sqrt(x^2) = ±sqrt(26)
x = ±sqrt(26)
Answer:
The third option
Step-by-step explanation:
If we rewrite this in log form, we get
[tex]e {}^{0} = {x}^{2} - 25[/tex]
Remeber anything to the 0 power is 1, so simplifying the equation first
[tex]1 = {x}^{2} - 25[/tex]
Add 25 to both sides
[tex]26 = {x}^{2} [/tex]
Take the square root of both sides
[tex]x = \sqrt{26} [/tex]
Square root are both so
[tex]x = - \sqrt{26} [/tex]
Is also a answer.
The third option is the answer
By the third day of a particular week, 2 accidents have already occurred in the intersection. What is the probability that there will be less than a total of 4 accidents during that week
Answer:
The right answer is "0.70".
Step-by-step explanation:
The given query seems to be incomplete. Please find below the attachment of the full query.
By using the Bayes' theorem, we get
⇒ [tex]P[(X<4)|(X \geq 2)] = \frac{P(2 \leq X < 4)}{P(X \geq 2)}[/tex]
By putting the values, we get
[tex]=\frac{[P(2)+P(3)]}{[1-P(0)-P(1)]}[/tex]
[tex]=\frac{(0.20+0.15)}{1-0.20-0.30}[/tex]
[tex]=\frac{0.35}{0.5}[/tex]
[tex]=0.70[/tex]
Determine if the two figures are congruent and explain your answer.
Simplify 3/4 + 5/8 over 3/4 - 1/2
Answer:
11/2
Step-by-step explanation:
[tex]\frac{\frac{3}{4} + \frac{5}{8} }{\frac{3}{4} - \frac{1}{2} }[/tex]
= 3/4 + 5/8 = 11/8 (take LCM)
3/4 - 1/2 = 1/4 (take LCM)
11/8 ÷ 1 /4
= 11/8 x 4
= 11/2
Answered by Gauthmath
write your answer in simplest radical form
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Answer:
f = 3 units
Step-by-step explanation:
The ratios of side lengths in this 30°-60°-90° triangle are ...
1 : √3 : 2
So, the ratio of interest is ...
1 : √3 = √3 : f
We can see that the numbers in the second ratio are √3 times the numbers in the first ratio, so
f = √3 × √3 = 3
f = 3 units
Umm.. Hi there! Can someone please help me out with this? (only for those who know the answer)
Bcoz I really need this rn :(
DUEEEE AFTERRR LUNCHH! :(:(:(:(
If your answer is NONSENSE it will be deleted as soon as possible!
But if your answer is CORRECT, HELPFUL, HAS AN EXPLANATION, I'll chose your answer as the BRAINLIEST ANSWER!
Answer:
The Exterior Angle of triangle LDR is angle d. The Remote Interior Angles are a and b.
The Exterior Angle of triangle PDR is angle 4. The Remote Interior Angles are angles 1 and 2
Explanation:
Interior angles are the angles that are inside the shape. The remote interior angles would be the 2 angles away from the exterior angle.
The exterior angle is the angle, made by the side of the shape and a line drawn out from an adjacent side.
I hope this helps!
Answer:
In LDR
Exterior = d Interior = a, bIn PDR
Exterior = 4Interior = 1, 2Exterior angle of a triangle is formed when one side of the triangle is extended .
Interior remote angles the angles in the triangle that do not lie on the extended side.
I need help finding the answer to this question on edge.
Answer:
6
Step-by-step explanation:
We need to evaluate :-
[tex]\rm\implies \displaystyle\rm\sum^4_n (-1)^n (3n + 2 ) [/tex]
Here the [tex]\Sigma[/tex] is the sum operator . And here we need to find the sum from n = 1 to n = 4 . We can write it as ,
[tex]\rm\implies (-1)^1 ( 3*1 +2) + (-1)^2 ( 3*2+2) + (-1)^3(3*3+2) + (-1)^4(3*4+2) [/tex]
Now we know that for odd powers of -1 , we get -1 and for even powers we get 1 . Therefore ,
[tex]\rm\implies -1 ( 3 + 2 ) + 1 (6+2)+-1(9+2)+1(12+2)[/tex]
Now add the terms inside the brackets and then multiply it with the number outside the bracket . We will get ,
[tex]\rm\implies -1 * 5 + 1 * 8 + -1*11 + 1*14 \\\\\rm\implies -5 + 8 - 11 + 14 \\\\\rm\implies\boxed{\quad 6 \quad}[/tex]
Hence the required answer is 6.
A ball is thrown from an initial height of 7 feet with an initial upward velocity of 23 ft/s. The ball's height h (in feet) after 1 seconds is given by the following.
h = 7+23t-16t^2
Find all values of 1 for which the ball's height is 15 feet.
Answer:
Step-by-step explanation:
If we are looking for the time(s) that the ball is at a height of 15, we simply sub in a 15 for the height in the position equation and solve for t:
[tex]15=-16t^2+23t+7[/tex] and
[tex]0=-16t^2+23t-8[/tex]
Factor this however you factor a quadratic in class to get
t = .59 seconds and t = .85 seconds.
This means that .59 seconds after the ball was thrown into the air it was 15 feet off the ground. Then the ball reached its max height, gravity took over, and began pulling it back down to earth. The ball passes the height of 15 feet again on its way down after .85 seconds.
Someone please help me I’m having trouble!!!!
Answer:
(c) [tex]x = 0.6[/tex] and [tex]x = 0.7[/tex]
(d) [tex](x,y) = (0.67,2.33)[/tex]
Step-by-step explanation:
Given
See attachment
First, we complete the table
[tex]y = -x + 3[/tex] [tex]y = 2x + 1[/tex]
[tex]y = -0.6 + 3 = 2.4[/tex] [tex]y = 2 * 0.6 + 1 = 2.2[/tex]
[tex]y = -0.7 + 3 = 2.3[/tex] [tex]y = 2 * 0.7 + 1 = 2.4[/tex]
[tex]y = -0.8 + 3 = 2.2[/tex] [tex]y = 2 * 0.8 + 1 = 2.6[/tex]
[tex]y = -0.9 + 3 = 2.1[/tex] [tex]y = 2 * 0.9 + 1 = 2.8[/tex]
So, we have:
[tex]\begin{array}{ccc}x & {y = -x + 3} & {y = 2x + 1} & {0.5} & {2.5} & {2} & {0.6} & {2.4} & {2.2} & {0.7}&{2.3} & {2.4} & {0.8}&{2.2} & {2.6} & {0.9}&{2.1} & {2.8} & {1}&{2} & {3} \ \end{array}[/tex]
Solving (c): Between which values is y
The values of y are for both equations are closest at:
[tex]x = 0.6[/tex] and [tex]x = 0.7[/tex]
Hence, the solution is between
[tex]x = 0.6[/tex] and [tex]x = 0.7[/tex]
Solving (d): Approximated value of the solution
We have:
[tex]y = -x + 3[/tex]
[tex]y = 2x + 1[/tex]
[tex]y=y[/tex]
So:
[tex]-x + 3 = 2x + 1[/tex]
Collect like terms
[tex]2x + x = 3 - 1[/tex]
[tex]3x= 2[/tex]
Divide both sides by 3
[tex]x = 0.67[/tex]
Substitute [tex]x = 0.67[/tex] in [tex]y = -x + 3[/tex]
[tex]y =-0.67 + 3[/tex]
[tex]y =2.33[/tex]
So, the solution is:
[tex](x,y) = (0.67,2.33)[/tex]
The number 0 is a critical point of the autonomous differential equation dx/dt = 7xn, where n is a positive integer. For what values of n is 0 asymptotically stable? Semi-stable? Unstable?
Answer:
a) 0 is stable when n = odd
b) 0 is semi-stable when n = even
c) 0 is unstable when n is odd
Step-by-step explanation:
Th differential equation for this question
dx/dt = x^n
n = positive integer
a) value of n where 0 is stable
0 is stable when x^n is replaced with -x^n
because considering n to be an odd number
-x^n > 0 when x < 0 while -x^n < 0 when x > 0
∴ In this scenerio we can conclude that 0 is stable when n = odd number
b) Value of n where 0 is Semi-stable
assuming n is an even number
x^n > 0 for all the values of x
c) Value of n where 0 is unstable
lets assume n is odd
when n < 0, xⁿ < 0
when n > 0, xⁿ > 0
i.e. 0 is asymptotically unstable when n is an odd number
−3 1/2 ÷ 1 1/4
khan academy
answer in simplified proper fraction
or
simplified improper fraction
Answer:
Step-by-step explanation:
Change the mixed numbers to improper fractions.
Solve the rational equation:
Answer:
Step-by-step explanation:
C. f(x) will be a very small negative number, approaching -∞
What is the product?
(-2d^2+5)(5d^2-6s)
Answer:
= -10d^4 + 12d^2s + 25d^2 - 30s
Left on together, the cold and hot water faucets of a certain bathtub take 4 minutes to fill the tub. If it takes the hot water faucet minutes to fill the tub by itself, how long will it take the cold water faucet to fill the tub on its own?
Do not do any rounding.
Answer:
[tex]Cold = \frac{1}{6}\ mins[/tex]
Step-by-step explanation:
The correct given parameters are:
[tex]Both = \frac{1}{4}\ mins[/tex]
[tex]Hot = \frac{1}{12}\ mins[/tex]
Required
Time taken by the cold water faucet
We have:
[tex]Cold + Hot = Both[/tex]
Make Cold the subject
[tex]Cold = Both -Hot[/tex]
So, we have:
[tex]Cold = \frac{1}{4}-\frac{1}{12}[/tex]
Take LCM
[tex]Cold = \frac{3-1}{12}[/tex]
[tex]Cold = \frac{2}{12}[/tex]
Divide by 2
[tex]Cold = \frac{1}{6}[/tex]
HELPP PLEASEEEEEEEEEEEEEEEEEEEEEE
The sum of 6 and 12 divided by 9.
If Sultan Akbar goes to the Grand Bazaar With 8000 Rupees and 20% is spent on a carpet, how much has the carpet cost him?
Si el sultan Akbar va al Gran Bazar Con 8000 Rupias y se gasta el 20 % en una alfombra, cuanto le ha costado la alfombra?
Answer:
1600 Rupees
Step-by-step explanation:
20 divided by 100 times 8000 will give you 1600 so the carpet costed him 1600
Evaluate − x 2 −5 y 3 when x = 4 and y =−1
Answer:
-11
Step-by-step explanation:
I am going to assume that it is -x^2-5y^3.
-(4^2)-5(-1^3)
-16-5(-1)
-16+5
-11
Answer:
- 11
Step-by-step explanation:
If x = 4, y = -1
then,
- x^2 - 5y^3 = - (4)^2 - 5(-1)^3
= - 16 + 5
= - 11
find c.round to the nearest tenth
Answer:
we need a picture...
Step-by-step explanation:
Use the functions below to complete Parts 1 and 2.
f(x)= |x| g(x)= |x+2| - 3
Part 1: Graph f(x) and g(x) on the grid below. Label each graph.
HINT: Making a table of values for each function may help you to graph them.
Part 2: describe how the graph of g(x) relates to the graph of its parent function, f(x).
HINT: Think about how f(x) was shifted to get g(x).
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Answer:
1. see below
2. g(x) is f(x) translated left 2 and down 3
Step-by-step explanation:
1. The graphs are attached. F(x) is in red; g(x) is in blue.
__
2. The graph of g(x) = f(x -h) +k is the parent function translated by (h, k). Here we have (h, k) = (-2, -3), so g(x) is f(x) translated left 2 and down 3.
People's movements between places is called
Answer:
The three answers I can think of are migration, immigration, and emigration.
Step-by-step explanation:
Hope this helps!
Suppose a jar contains 9 red marbles and 40 blue marbles. If 2 marbles are randomly chosen from the jar at
the same time, find the probability that both marbles are red. Round your answer to four decimal places.
Answer:
0.0306
Step-by-step explanation:
I don't know if there is any significance to both being drawn at the same time. I'm going to say there isn't.
The first draw gives
9/49
Their is no replacement. That's because both marbles are drawn together. The second draw is
8/48
P(both red) = 9/49 * 8 / 48 = 3/98 = 0.03061 which rounds to 0.0306
The length of a rectangle is 13 centimeters less than three times its width. Its area is 56 square centimeters. Find the dimensions of the rectangle. Use the formula, area=length*width.
Answer:
The dimensions of the rectangle are 8 by 7 centimeters.
Step-by-step explanation:
The length of a rectangle is 13 centimeters less than three times its width. In other words:
[tex]\ell = 3w-13[/tex]
Given that the area of the rectangle is 56 square centimeters, we want to determine its dimensions.
Recall that the area of a rectangle is given by:
[tex]A = w \ell[/tex]
Substitute in known values and equations:
[tex](56)=w(3w-13)[/tex]
Solve for w. Distribute:
[tex]3w^2-13w=56[/tex]
Isolate the equation:
[tex]3w^2-13w-56=0[/tex]
Factor. We want to find two numbers that multiply to 3(-56) = -168 and that add to -13.
-21 and 8 suffice. Hence:
[tex]3w^2 - 21w + 8w - 56 = 0 \\ \\ 3w(w-7) + 8(w-7) = 0 \\ \\ (3w+8)(w-7) = 0[/tex]
Zero Product Property:
[tex]3w+8=0\text{ or } w-7=0[/tex]
Solve for each case:
[tex]\displaystyle w = -\frac{8}{3} \text{ or } w=7[/tex]
Since the width cannot be negative, we can ignore the first solution.
Therefore, the width of the rectangle is seven centimeters.
Thus, the length will be:
[tex]\ell = 3(7) - 13 = 8[/tex]
Thus, the dimensions of the rectangle are 8 by 7 centimeters.
What is the solution to this equation?
6
O A. x = 18
O B. x= -2
O c. x= -18
O D. X= 21
Write the monomial in its standard form. Name its coefficient and
identify its degree:
2
3
2 mºn :4.573
Answer:
A monomial in standard form is (essentially) the product of one or more factors: a constant coefficient and one factor for each variable in the expression.
Step-by-step explanation:
For example, in the monomial 4x2y3, the factors are 4, x2, and y3. First, the coefficient is 4. The next factor, x2, is the x-factor, whose degree is 2.
Suppose f(x)=x^2. What is the graph of g(x)=1/2f(x)?
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Answer:
see attached
Step-by-step explanation:
The graph of g(x) is a vertically scaled version of the graph of f(x). The scale factor is 1/2, so vertical height at a given value of x is 1/2 what it is for f(x). This will make the graph appear shorter and fatter than for f(x).
The graph of g(x) is attached.
Which statement is true about the net and the solid it can form?
A. The length of side a will be 5 m.
B. The length of side b will be 2 m.
C. The length of side c will be 7 m.
D. The length of side c will be 2 m.
Step-by-step explanation:
Option B
The length of side will be 2m...
hope it helps
There is a triangular number that has 55 dots in its shape. Which one is it? Write your answer as a number.
The triangular number that has 55 dots in its shape is the
-th triangular number.
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Answer:
10
Step-by-step explanation:
The n-th triangular number is given by ...
t(n) = n(n+1)/2
We went to find n when t(n) = 55.
55 = n(n+1)/2
110 = n(n+1)
Adding 1/4 completes the square.
110.25 = (n +0.5)^2
√110.25 = n+0.5 . . . . . we are interested in the positive value of n
n = 10.5 -0.5 = 10
The triangular number that has 55 dots in its shape is the 10-th number.
__
Additional comment
Here, we have gone to the trouble to formally complete the square to find the value of n. You may realize that it isn't really necessary to go to that trouble.
A reasonable estimate of the value of n is possible by considering that the product n(n+1) is a little more than n², so the value of n will be a little less than √110 ≈ 10.49. The nearest integer is 10, which is the answer we're looking for.
There are 40 children in a classroom and n of them do not wear spectacles. (4)/(5) of the boys and (2)/(3) of the girls wear spectacles. Express the number of boys who wear spectacles in terms of n.
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Answer:
b = 80 -6n . . . . boys who wear spectacles
Step-by-step explanation:
We know the ratio of boys who wear spectacles to those who don't is ...
(4/5) : (1 -4/5) = 4 : 1
If we let b represent the number of boys who wear spectacles, then the number who don't is b/4. Then total number of boys is then b +b/4 = 5b/4. The number of girls in the classroom is this number less than 40.
Let's define a few groups:
boys who wear spectacles: bboys who do not wear spectacles: b/4girls who wear spectacles: (2/3)(40 -5b/4)girls who do not wear spectacles (1/3)(40 -5b/4)Then the total of children who do not wear spectacles is ...
n = b/4 +(1/3)(40 -5b/4)
12n = 3b +(160 -5b) = 160 -2b . . . . multiply by 12
2b = 160 -12n . . . . . . . . . . . . . add 2b-12n
b = 80 -6n . . . . the desired relation, b = boys who wear spectacles
_____
Additional comment
The only values of n that make sense in this context are {8, 10, 12}, corresponding to {0, 15, 30} total girls and {40, 25, 10} total boys.
. Mildred bought an old
necklace and pair of earrings
while at an antique show. If
the cost of the jewelry is ]
and tax is 7%, which of the
following equations could be
used to find the total cost of
the jewelry?
a. .07 + ]
b. J +.07 x)
C. (.07x)) + ]
d. 7) + ]
Answer:
j * .07 +j
Step-by-step explanation:
The tax on the jewelry is J* .07
Add the tax to the cost of the jewelry to get the total cost
j * .07 +j
Lisa reads an equal number of pages of a book every week. The graph below shows the number of pages of the book left to read, y, after x weeks:
A graph titled Lisas Book Reading shows Number of Weeks on the x-axis and Number of Pages Left on the y-axis. The scale on the x-axis shows numbers from 0 to 6 at increments of 1, and the scale on the y-axis shows numbers from 0 to 350 at increments of 50. A straight line joins the ordered pairs 0, 250 and 1, 200 and 2, 150 and 3, 100 and 4, 50 and 5, 0.
Which equation best models the relationship between x and y?
y = −50x + 250
y = −5x + 50
y = −50x + 350
y = −5x + 250
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Answer:
(a) y = −50x + 250
Step-by-step explanation:
In case you don't realize that the graph starts at 250 and decreases by 50 for each increase of 1 in x, you can see if any of the equations match the given points. The only one that does is the first one:
y = -50x +250
Answer:
(a) y = −50x + 250
Step-by-step explanation:
Fraction in simplest form
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Answer:
27/64
Step-by-step explanation:
The fraction being cubed is already in simplest form, so the cube is ...
[tex]\left(\dfrac{3}{4}\right)^3=\dfrac{3^3}{4^3}=\boxed{\dfrac{27}{64}}[/tex]