Answer:
abcd is a quadrilateral
so , d is ( -1,4 )
c is ( 0,-4 )
b is ( 0,-2)
and
a is ( 2,-2 )
Best answer gets brainliest and 5 star
Answer:
d no.
Step-by-step explanation:
because in my my personal opinion the function shown on the graph has a smaller rate of change, but a higher starting point
What is the value of the expression below when x=3
10x²- 7x + 10
Answer: 79
Concept:
Here, we need to understand the idea of evaluation.
When encountering questions that gave you an expression with variables, then stated: "If x = a, y = b, z = c" (a, b, c are all constants), this means you should substitute the value given for each variable back to the expression.
Solve:
Given information
10x² - 7x + 10
x = 3
Substitute the value into the expression
= 10 (3)² - 7 (3) + 10
Simplify by multiplication
= 10 (9) - 21 + 10
= 90 - 21 + 10
Simplify by subtraction
= 69 + 10
Simplify by addition
= 79
Hope this helps!! :)
Please let me know if you have any questions
Answer:
92
Step-by-step explanation:
The variable 'x' shows up twice in this expression. Replace each instance of 'x' with 3:
10(3)^2 - 7(3) + 10 = 10(9) - 21 + 19 = 92
(a-√a/√a-1) - (√a+1/a+√a) : √a+1/a. solve a
Answer:
Step-by-step explanation:
[tex]\displaystyle \ \Large \boldsymbol{} \frac{a-\sqrt{a} }{\sqrt{a}-1 } -\frac{\sqrt{a}+1 }{a+\sqrt{a} } :\frac{\sqrt{a}+1 }{a} = \\\\\\\frac{\sqrt{a}(\sqrt{a} -1 ) }{(\sqrt{a}-1) } -\frac{\sqrt{a}+1 }{\sqrt{a}(\sqrt{a}+1 )}\cdot \frac{\sqrt{a}\cdot \sqrt{a} }{\sqrt{a}+1 } = \\\\\\\sqrt{a} -\frac{\sqrt{a} }{1+\sqrt{a} } =\frac{a+\sqrt{a}-\sqrt{a} }{1+\sqrt{a} } = \\\\\\\frac{a}{\sqrt{a}+1 } \cdot \frac{\sqrt{a}-1 }{\sqrt{a}-1} } =\boxed{\frac{a\sqrt{a} -a}{a-1} }[/tex]
Three adults are picked at random from those with a mass of 70 kg or less.
Calculate the probability that one of them has a mass of 35 kg or less and the other two each have a
mass greater than 35 kg.
9 in.
13 in.
10 in
Drawing not to scale
b. 90 in?
45 in?
d. 292.5 in.
c. 32 in?
a.
Answer:
a, a, d
Step-by-step explanation:
44
The area (A) of a triangle is calculated as
A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the perpendicular height )
Here b = 10 and h = 9 , then
A = [tex]\frac{1}{2}[/tex] × 10 × 9 = 5 × 9 = 45 in² → a
45
The area (A) of a parallelogram is
A = bh ( b is the base and h the perpendicular height )
Here b = 2 and h = 4 , then
A = 2 × 4 = 8 m² → a
46
A = bh ( with b = 4 and h = 10 )
A = 4 × 10 = 40 m² → d
If the blue radius below is perpendicular to the chord AC which is. 14 units long, what is the length of the segment AB?
Answer:
C. 7 units
Step-by-step explanation:
The given parameters are;
The length of the chord of the circle, [tex]\overline{AC}[/tex] = 14 units
The orientation of the radius and the chord = The radius is perpendicular to the chord
We have in ΔAOC, [tex]\overline{AO}[/tex] = [tex]\overline{OC}[/tex] = The radius of the circle
[tex]\overline{OB}[/tex] ≅ [tex]\overline{OB}[/tex] by reflexive property
The angle at point B = 90° by angle formed by the radius which is perpendiclar to the chord [tex]\overline{AC}[/tex]
ΔAOB and ΔCOB are right triangles (triangles having one 90° angle)
[tex]\overline{AO}[/tex] and [tex]\overline{OC}[/tex] are hypotenuse sides of ΔAOB and ΔCOB respectively and [tex]\overline{OB}[/tex] is a leg to ΔAOB and ΔCOB
Therefore;
ΔAOB ≅ ΔCOB, by Hypotenuse Leg rule of congruency
Therefore;
[tex]\overline{AB}[/tex] ≅ [tex]\overline{BC}[/tex] by Congruent Parts of Congruent Triangles are Congruent, CPCTC
[tex]\overline{AB}[/tex] = [tex]\overline{BC}[/tex] by definition of congruency
[tex]\overline{AC}[/tex] = [tex]\overline{AB}[/tex] + [tex]\overline{BC}[/tex] by segment addition postulate
∴ [tex]\overline{AC}[/tex] = [tex]\overline{AB}[/tex] + [tex]\overline{BC}[/tex] = [tex]\overline{AB}[/tex] + [tex]\overline{AB}[/tex] = 2 × [tex]\overline{AB}[/tex]
∴ [tex]\overline{AB}[/tex] = [tex]\overline{AC}[/tex]/2
[tex]\overline{AB}[/tex] = 14/2 = 7
[tex]\overline{AB}[/tex] = 7 units.
Answer:
7 units
Step-by-step explanation:
After a 20% reduction, you purchase a tv for $336. What was the price of the tv before the reduction?
Answer:
$420
.8 x = 336
x = 336/.8
X=$420
Step-by-step explanation:
HELP ME PLS ITS PYTHAGOREAN THEOREM
Answer:
a= [tex]\sqrt{19}[/tex]
Step-by-step explanation:
Pythagorean Theorem: a^2+b^2=c^2
a^2+9^2=10^2
a^2+81=100
a^2=19
a=[tex]\sqrt{19}[/tex]
Answer:
b = 4.4 meters
write each number as a reduced fraction or mixed number. A. 16/24 B. 15/24. C. 4%
Answer:
A.1/3 B.5/8 C.1/25
Step-by-step explanation:
just simplify it down to the lowest
Answer:
Ä. 16/24 as reduced fraction = 2/3
B. 15/24 as reduced fraction= 5/8
A farmer has an orchard that covers an area of 40 acres. He grows apples on 25 acres, peaches on 7 acres, nectarines on 5 acres, and plums on 3 acres. The fruit trees are equally distributed within the orchard. A tree is chosen at random. Rounded to the nearest tenth of a percent, what is the theoretical probability that the tree is not within the acres of apple trees
Answer:
37.5%
Step-by-step explanation:
Calculation to determine the theoretical probability that the tree is not within the acres of apple trees
Using this formula
P=(Number of all orchard acres - Apple acres)/(Total orchard acres)*100
Where,
P represent Probability
Let plug in the formula
P=(40 acres- 25 acres)/40 acres
P=15 acres/40 acres *100
P=3/8*100
P=.375*100
P=37.5%
Therefore the THEORETICAL PROBABILITY that the tree is not within the acres of apple trees is 37.5%
Answer:
the answer is 37.5
Step-by-step explanation:
it is
Please help plssssssss
Answer:
.38
Step-by-step explanation:
Given that they have green eyes, we only look at the green row
Total is 3+5+5 = 13
Red hair is 5
P( red hair ) red / total = 5/13 =.384615385
Answer:
Condition relative frequency is 0.38
Step-by-step explanation:
P( red hair given that has green hair ):
[tex]{ \boxed{ \bf{P( \frac{red}{green}) }}}[/tex]
From baye's theorem:
[tex]P( \frac{R}{G} ) = \frac{P(RnG)}{P(G)} [/tex]
[tex]{ \sf{ = \frac{5}{(3 + 5 + 5)} }} \\ \\ = { \sf{ \frac{5}{13} }} \\ \\ = { \sf{0.384615…}}[/tex]
ESSENTIAL QUESTION How do graphs
and equations reveal information about a
relationship between two quantities?
Answer:
When you plot the graph, you may see a line or a curve. This presents the trend of the relationship of the two quantities when the independent variable changes.
Graphs visually depict patterns and trends, while equations provide precise mathematical descriptions, both revealing valuable information about the relationship between two quantities.
Graphs visually represent data and patterns, allowing us to identify the nature of the relationship between two quantities. The slope and intercepts of a graph provide information about the rate of change and the values when one quantity is zero.
Equations, on the other hand, offer precise mathematical descriptions of the relationship. The form of the equation reveals the nature of the relationship, while coefficients and constants provide specific information. Solving equations yields solutions that satisfy the relationship.
Both graphs and equations work together to provide a comprehensive understanding of the relationship between two quantities, with graphs offering visual insights and equations providing precise mathematical information.
Learn more about equations here;
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what is 13.5/10 simplified
Answer:
27/20
Step-by-step explanation:
[tex]\frac{13.5}{10} = \frac{13.5 * 2}{10 * 2} = \frac{27}{20}[/tex]
Question 16 of 17
Which of the following best describes the graph below?
A. Independent variable
0 o a
B. A relation that is a function
C. A relation that is not a function
D. Dependent variable
(c) 63 divided by 3 = 21 , Show how you use this to work out 0.63 divided by 0.3.
Answer:
0.63 ÷ 0.3 = 63 x 10^-2 ÷ 3 x 10^-1 = 63 / 3 x 10^(-2--1) = 21 x 10^-1 = 2.1
Answer:
2.1.
Step-by-step explanation:
63/3 = 21
0.63 = 63 / 100
and 0.3 = 3 / 10
so 0.63/0.3 = 63 /100 / 3/10 = 63/100 * 10/3
= 63/3 / 10
So the answer is 21 / 10 = 2.1.
Durning Saturday’s thunderstorms a total of 500 mm of rain fell in fell in 20 minutes.How many mm fell per minute
Answer
25mm of rain fell each second
Step-by-step explanation:
we know that 500 mm fell in 20 minutes
so, we have to divide 500 by 20 giving us the amount of rain that fell each minute:
500/20 = 25
therefore, 25mm of rain fell each minute
hope this helped:)
Answer:
25 mm per minute
Step-by-step explanation:
Take the amount of rain and divide by the number of minutes
500/20
25 mm per minute
Need help on #7 , #8 Asap
please help me out :))))
Answer:
Angle BCD=35°
HOPE IT HELPS
What are the x-intercepts of the graph of the function below?
y= x^2+3x – 28
A. (6,0) and (4,0)
B. (-7,0) and (-4,0)
C. (7,0) and (-4,0)
D. (-7,0) and (4,0)
Which set of integers are in the right order from least to greatest?
1-10], -3, 2,7
7, 1-10], -3,2
2, -3, 7, 1-10
-3, 2, 7, 1-10
Answer:
1-10, -3, 2, 7
im sorry if i give a wrong answer
Can someone PLEASE answer the Algebra Question CORRECTLY BELOW!
Thank you, I will mark brainiest!
Answer:
There are 0.454 kg in one pound.
So, in 120 pounds there are 0.454 x 120 kgs.
This is equal to 54.48, and the answer is 54.48 kg.
Let me know if this helps!
ALGEBRA 2
Name the property of real numbers illustrated by each equation.
#21
Answer:
The property showed in the number 21 is the distributive property
Which is a point on the circle whose center is (0, 0) and whose radius is 5?
A. (2, 3)
B. (0, 0)
C. (3, 4)
D. (4, 5)
The equation of the circle whose center is (0, 0) and whose radius 5 is x² + y² = 25.
What is an equation of a circle?A circle can be characterized by its center's location and its radius's length.
Let the center of the considered circle be at (h,k) coordinate.
Let the radius of the circle be 'r' units.
Then, the equation of that circle would be:
(x-a)²+(y-b)² = r²
Where (a, b) is the centre and 'r' is the radius
We have a circle with centre (0, 0) and radius of 5.
Now, Substituting these value into the equation form, we have
(x-0)²+(y-0)² = 5²
x² + y² = 25
Hence, the equation of the circle whose center is (0, 0) and whose radius 5 is x² + y² = 25.
Learn more about equation of a circle here:
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Parallelogram JKLM is shown. If KR=X+7, KM = 3x - 5. and JL = 4x - 10.
what is JR?
2 points
K
R
569
27°
72°
M
Answer:
Step-by-step explanation:
In a parallelogram, this one in particular:
KR = RM
JR = RL
We are looking in the end for the length of JR, but that means that we need to solve for x somehow to plug in the expression for JL, and then split that in half. Here's how we're going to go about it. I know that
KM = KR + RM, but since KR and RM are the same length, the equation becomes
KM = 2KR. Filling that in with the expressions I'm given for KM and KR:
3x - 5 = 2(x + 7) and
3x - 5 = 2x + 14 and
x = 19. Now I can find the length of JL:
JL = 4x - 10 so
JL = 4(19) - 10 and
JL = 66
Knowing that JR = RL and JL is 66 units long, JR = RL = 33 units each.
if x =2 y =3 find the value of x^2-xy^2+y^2
Answer:
i hope it will help
Step-by-step explanation:
I did not get the equation so I solve it with two methods
What is the difference between-5 and 2
Answer:
7
Step-by-step explanation:
Going from -5 to 2 we get
1) -4
2) -3
3) -2
4) -1
5) 0
6) 1
7) 2
So, in total, there are 7 numbers between -5 and 2
Can someone please help me with my maths question
Answer:
[tex]a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]
[tex]b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]
Step-by-step explanation:
The question relates with rules of indices
(a) The give expression is presented as follows;
[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}[/tex]
By expanding the expression, we get;
[tex]\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}[/tex]
Collecting like terms gives;
[tex]\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]
[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]
(b) The given expression is presented as follows;
[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4[/tex]
Therefore, we get;
[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}[/tex]
Collecting like terms gives;
[tex]x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )[/tex]
[tex]x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]
[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]
Two hikers are miles apart and walking toward each other. They meet in hours. Find the rate of each hiker if one hiker walks mph faster than the other.
Answer:
where are the numbers
Step-by-step explanation:
(a/b)^x-1 = (b/a)^x-3
Answer:
x = 2
Step-by-step explanation:
Why do 6.52 x 10^3 and 652,000 ÷ 10^2 have the same answer?
Answer:
6.52 x 10^3 is just basically 6.52 × 1000, which is 6520. But 652,000 ÷ 10^2 is just 652000 ÷ 100, which is 6520. That's why they have the same answer.