Help please!! I will mark brainilist and give a lot of points.



This is Pythagorean theorem.


Formula: a^2+b^2=c^2


When I say ^2 I mean to the power of 2.


The question is asking me to solve for a.


Then give me b and c which is b = 17 1/3 and c = 16.


How do I solve for a when b is greater than c? Won’t that give me a negative a? You can’t have a negative a right?


Unless I’m wrong.



Please help my solve this!!!!! :D

Answers

Answer 1

Answer:

a = 23.588

Step-by-step explanation:

a^2 = 17 1/3^2 + 16^2

a^2 = 300.4 + 256

a^2 = 556.4

a = 23.588 (I rounded to thousandths but you can round to whatever)

Answer 2

Hello there,

I just looked into the question and you are absolutely right whatever you inferred.I think the question might be wrong.The value of c should be greater than b.I guess it will like this:[tex]b = 16 \: \: \: c = 17 \frac{1}{3} [/tex]The values should be like this.I am solving the equation by this:[tex] {a}^{2} = {c}^{2} - {b}^{2} \\ = > {a}^{2} = {(17 \frac{1}{3}) }^{2} - {(16)}^{2} \\ = > {a}^{2} = {( \frac{52}{3} )}^{2} - {(16)}^{2} \\ = > {a}^{2} = ( \frac{52}{3} - 16)( \frac{52}{3} + 16) \\ = > {a}^{2} = ( \frac{52 - 48}{3} )( \frac{52 + 48}{3} ) \\ = > {a}^{2} = \frac{4}{3} \times \frac{100}{3} \\ = > {a}^{2} = \frac{400}{9} \\ = > a = \sqrt{ \frac{400}{9} } \\ = > a = \frac{20}{3} \\ = > a = 6 \frac{2}{3} [/tex]So, the value of a is [tex]a = 6 \frac{2}{3} [/tex]

Hope you could get an idea from it.

Doubt clarification - use comment section.


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Answers

Answer:

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Step-by-step explanation:

So, Bill planted -

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

I got a 100% on my test

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Refer to the attachment

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Answer:

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Step-by-step explanation:

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Answers

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Answers

Answer:

Q14. Percentage decrease in price of TV

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Answer: q = 0

-----------------------------

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Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Answers

Step-by-step explanation:

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Answers

Answer:

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Answer

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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A baseball pitcher has made 53 pitches in the first four innings of a baseball game and plans to pitch 3 mote innings. The manager of the team has committed to allowing his pitcher to throw, at most, pitches during the game. Write an inequality to find the average number of pitches the pitcher can throw over the next three innings Solve the inequality from Part 1. What is the maximum number of pitches the pitcher can make in cach of the next 3 innings ? Graph your solution from Part 2 on a number line and explain what your solution means. If the pitcher threw just 6 pitches in the fifth inning, what is the greatest number of pitches the pitcher can throw per inning he wishes to pitch nine innings? Write and solve an inequality to answer this part.

Answers

Answer:

at most 17 pitches per inning

Step-by-step explanation:

It is given that a baseball pitcher makes 53 pitches in the first 4 innings of a game and plans to pitch in the next 3 innings.

We need to write and solve an inequality to find the possible average pitches per inning the pitcher made in the next 3 innings if the pitcher is assigned a maximum of 105 pitches.

From part (a) we know  3 p + 53 3p+53 represents the total number of pitches made if the pitcher makes an average of  p pitches per inning in the next 3 innings.

If the pitcher can make at most 105 pitches, then:

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at most 17 pitches per inning

(Hope this helps can I pls have brainlist (crown)☺️)

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Answers

Step-by-step explanation:

The Real Answer Is 63

Maybe Positive Or Negative

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