Answer: I do not know what you mean, but you could do burpees, and sit ups.
If 40 men working on a U.S. government project can complete the job in 100 hours, how many men would be required to complete the job in 80 hours?
Answer:50
Step-by-step explanation:(40x100):80
Answer: 50 workers
Let the ratio be
(40×100):80
= 400/80
= 50
Therefore 50 workers will complete the same work in 80 hours.
Must click thanks and mark brainliest
Read the image for instructions
Answer:
4 ther are 4 line symmetery
Answer:
two lines of symmetry
(a vertical and a horizontal)
the mean of 200 item was 50 later on it was found that two items were wrongly taken as 92 and 8 instead of 192 and 88 find the correct mean.
Answer:
Since, mean of 200 items was 50 and number of items =200
So, mean =50
Also, we know mean = number of itemssum of items
∴50=200sum of items
Sum of items = 200×50=10000
Later on, it was discovered that the two items were misread as 92 and 8 instead of 192 and 88 respectively
Then misread instead Correct item
92 192 192-92=100
8 88 88-8=80
∴ Correct sum of items =10000+180=10180
∴ Correct mean = number of items/sum of items
=10180/200 =50.9
Answer:
Hello,
203.6
Step-by-step explanation:
Sum of the item first= 50*200=10000
new sum is 10000+(192-92)+(88-8)=10180
New mean=10180/200=50.9
Auto technicians working at a shop in a rural residential area noticed that the depth of tire treads was smaller among cars that have more miles on the odometer.
What are the explanatory variable and response variable for this relationship?
Explanatory variable: type of residential area
Response variable: depth of tire tread
Explanatory variable: depth of tire tread
Response variable: miles on the car odometer
Explanatory variable: miles on the car odometer
Response variable: depth of tire tread
Explanatory variable: type of residential area
Response variable: miles on the car odometer
I think its, (B):
Explanatory variable: depth of tire tread
Response variable: miles on the car odometer
Answer:
Your answer is (C)
Explanatory variable: miles on the car odometer
Response variable: depth of tire tread
ED2021
[tex]\sqrt{-25[/tex]
Answer:
±5i
Step-by-step explanation:
sqrt(-25)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(-1) sqrt(25)
±i 5
±5i
When two resistors with resistances of A ohms and
B ohms are in a parallel-series circuit, the total
resistance, R, in ohms, is given by the equation above.
According to this equation, which of the following
resistances of the two resistors would yield the greatest
total resistance?
A) 1 ohm and 1 ohm
B) 1 ohm and 2 ohms
C) 1 ohm and 4 ohms
D) 2 ohms and 2 ohms
Step-by-step explanation:
Answer: D) 2 ohms and 2 ohms
Use the order of operations to simplify 3/4+8(2.50-0.5).
Answer:
16[tex]\frac{3}{4}[/tex]
Step-by-step explanation:
Will mercury with a density of 13.6 g/mL float or sink?
Mercury will sink
(sorry if Im wrong)
Answer:
Sink.
Step-by-step explanation:
Mercury is a quicksilver and hence will sink.
a 800g boulder has a density of 8g/cm^3. What is the volume of the boulder?
Answer:
Below
Step-by-step explanation:
You can use this formula to calculate the volume of an object
Volume = Mass / Density
Plugging everything in...
Volume = 800g / 8 g/cm^3
= 100 cm^3
Hope this helps!
The volume of the boulder will be equal to 100 cubic centimeters.
What are volume and density?A substance's density is defined as its mass per unit volume. The density in other words can be defined as the ratio of mass and volume. Its unit will be kg per cubic meter.
The volume is defined as the space occupied by an object in three-dimensional geometry.
It is given that an 800g boulder has a density of 8g/cm^3. The volume will be calculated by using the formula below:-
Volume = Mass / Density
Volume = 800g / 8 g/cm^3
= 100 cm^3
Therefore, the volume of the boulder will be equal to 100 cubic centimeters.
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I need help with C,D,E,F,G thank you
Answer:
D = 120 Degrees , E : x = 14 , F: <JHK = 21, G: Summplementary Angle is 96 Degrees
Step-by-step explanation:
4X+2X = 180
6X=180
X=30
<ABD = 4X = 4(30) = 120
What’s the range of A and B and both
This is of Both
Range = Highest - Lowest data
Range = 45 - 10
Range = 35
Only A
Range = 45 - 10
Range = 35
Only B
Range = 40 - 15
Range = 25
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Prove that: sec⁴B - sec²B = tan⁴B + tan²B.
Step-by-step explanation:
sec⁴B - sec²B = sec²B(sec²B - 1)
= (1 + tan²B)(tan²B)
= tan⁴B + tan²B
= Right-hand side (Proven)
Hi! I'd appreciate if you could help me on this question.
Liam is buying bottles of soda in packages that contain 8 bottles each. If the total number of sodas Liam bough t was between 45 and 50, how many did he buy? Explain your answer.
Answer:
48
Step-by-step explanation:
We need to find the multiples of 8
8,16,24,32,40,48
48 is between 45 and 50 so he must have bought 48
Answer:
6 bottles
Step-by-step explanation:
For this question we need to know the multiple of 8 which are:
8 x 1 = 8
8 x 2 = 16
8 x 3 = 24
8 x 4 = 32
8 x 5 = 40
8 x 6 = 48
8 x 7 = 56
There is only one multiple, which is greater than 45 but less than 50, which is 8x6 l.
This means he bought 6 bottles.
Answered by g a u t h m a t h
The domain and range for function g are D(−infinity symbol, infinity symbol) and R(−infinity symbol, infinity symbol). Describe the following statement:
the limit as x approaches 3 of the function g of x equals 4
Select one:
a. The value of g at 3 is 4.
b. The value of g at 4 is 3.
c. As x gets closer to 4, the value of g gets closer to 3.
d. As x gets closer to 3, the value of g gets closer to 4.
The answer is d: As x gets closer to 3, the value of g gets closer to 4.
The limit of a function h of x as x approaches the value a, written as [tex]\lim_{x \to a} h(x) = L[/tex] is the value the function h(x) approaches as x tends to the value "a", written as x → a. In this case, L.
Given the domain and range for function g are D(−∞, ∞) and R(−∞, ∞) and that the limit as x approaches 3 of the function g of x equals 4.
This implies that as x gets closer and closer to 3, the value of g gets closer and closer to 4.
Since the value g gets closer to is 3 as x gets closer to 4, we can write that the limit as x approaches 3 of the function g of x equals 4.
we can write this as
[tex]\lim_{x \to 3} g(x) = 4[/tex]
So, as x gets closer to 3, the value of g gets closer to 4.
So, the answer is d: As x gets closer to 3, the value of g gets closer to 4.
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A number has ........... number of factors but ........... number of multiple.
A number has fixed number of factors but infinite number of multiples
Ex:-
Take a number 12
It has factors 1,2,3,4,6,12
It is fixed.
But
It has multiples 12,24,36,48,60...
It is infinite
The area of a rectangular piece of cardboard is represented by
the equation w(2w + 3) = 9 where w is the width of the
cardboard in feet. Find the width.
This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.
Area of a rectangle:
The area of rectangle of length l and width w is given by:
[tex]A = wl[/tex]
w(2w + 3) = 9
From this, we get that:
[tex]l = 2w + 3, A = 9[/tex]
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
[tex]ax^{2} + bx + c, a\neq0[/tex].
This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:
[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]
[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]
[tex]\Delta = b^{2} - 4ac[/tex]
In this question:
[tex]w(2w+3) = 9[/tex]
[tex]2w^2 + 3w - 9 = 0[/tex]
Thus a quadratic equation with [tex]a = 2, b = 3, c = -9[/tex]
Then
[tex]\Delta = 3^2 - 4(2)(-9) = 81[/tex]
[tex]w_{1} = \frac{-3 + \sqrt{81}}{2*2} = 1.5[/tex]
[tex]w_{2} = \frac{-3 - \sqrt{81}}{2*2} = -3[/tex]
Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.
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heyyyyyyyyy
PLEASE HELP AND BE CORRECT BEFORE ANSWERING
What percentage of area is above the mean on a normal curve?
Group of answer choices
34%
68%
97.35%
50%
Answer:
z=0
50%
Step-by-step explanation:
Solve for y. 14y-6(y-3)=22
Answer:
y=0.5
Step-by-step explanation:
14y-6(y-3)=22
14y-6y+18=22
8y+18=22
8y=4
y=0.5
Then we check our work...
14(0.5)-6((0.5)-3)=22
7-6(-2.5)=22
7+15=22
7+15 does equal 22, so this solution is correct.
Global Airlines operates two types of jet planes: jumbo and ordinary. On jumbo jets, 30% of the passengers are on business while on ordinary jets 25% of the passengers are on business. Of Global's air fleet, 60% of its capacity is provided on jumbo jets. (Hint: The 25% and 30% values are conditional probabilities stated as percentages.)
a) What is the probability a randomly chosen business customer flying with Global is on a jumbo jet?
b) What is the probability a randomly chosen non-business customer flying with Global is on an ordinary jet?
Answer:
a) 0.18 = 18% probability a randomly chosen business customer flying with Global is on a jumbo jet.
b) 0.3 = 30% probability a randomly chosen non-business customer flying with Global is on an ordinary jet.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
Question a:
Event A: Jumbo
Event B: Business
60% of its capacity is provided on jumbo jets.
This means that [tex]P(A) = 0.6[/tex]
On jumbo jets, 30% of the passengers are on business
This means that [tex]P(B|A) = 0.3[/tex]
Desired probability:
We want to find [tex]P(A \cap B)[/tex], so:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
[tex]P(A \cap B) = P(B|A)P(A) = 0.6*0.3 = 0.18[/tex]
0.18 = 18% probability a randomly chosen business customer flying with Global is on a jumbo jet.
b) What is the probability a randomly chosen non-business customer flying with Global is on an ordinary jet?
Event A: Ordinary
Event B: Non-business
60% of its capacity is provided on jumbo jets.
So 100 - 60 = 40% are ordinary, which means that [tex]P(A) = 0.4[/tex]
On ordinary jets 25% of the passengers are on business.
So 100 - 25 = 75% are non-business, that is [tex]P(B|A) = 0.75[/tex]
Desired probability:
We want to find [tex]P(A \cap B)[/tex], so:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
[tex]P(A \cap B) = P(B|A)P(A) = 0.75*0.4 = 0.3[/tex]
0.3 = 30% probability a randomly chosen non-business customer flying with Global is on an ordinary jet.
13% of a sample of 200 students do not like ice cream. What is the 95% confidence interval to describe the total percentage of students who do not like ice cream?
The 95% confidence interval is (8.3%,17.7%), and the correct option is C.
------------------------------------------
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
------------------------------------------
13% of a sample of 200 students do not like ice cream.
This means that [tex]\pi = 0.13, n = 200[/tex]
------------------------------------------
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
------------------------------------------
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.13 - 1.96\sqrt{\frac{0.13*0.87}{200}} = 0.083[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.13 + 1.96\sqrt{\frac{0.13*0.87}{200}} = 0.177[/tex]
------------------------------------------
As a percentage:
0.083x100% = 8.3%0.177x100% = 17.7%Thus, the 95% confidence interval is (8.3%,17.7%), and the correct option is C.
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The data recorded in following Table 1 shows the length of Medical checkup conducted by a Health & safety team, in meters,
20 25 33 47 39 41 21
39 33 32 38 41 37 49
59 60 31 28 48 36 60
b) Find the Mean and Median of the minutes.
c) Find Standard deviation also comment on the result.
d) Sketch Histogram and Frequency Polygon.
Answer:
yggnvfghg46777tuutyuyt6yffttgdfhurdvhu
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 6 students' scores on the exam after completing the course: 6,16,19,12,15,14.
Using these data, construct a 90% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Find the critical value that should be used in constructing the confidence interval.
Answer:
The critical value is [tex]T_c = 2.5706[/tex].
The 90% confidence interval for the average net change in a student's score after completing the course is (9.04, 18.30).
Step-by-step explanation:
Before building the confidence interval, we need to find the sample mean and the sample standard deviation:
Sample mean:
[tex]\overline{x} = \frac{6+16+19+12+15+14}{6} = 13.67[/tex]
Sample standard deviation:
[tex]s = \sqrt{\frac{(6-13.67)^2+(16-13.67)^2+(19-13.67)^2+(12-13.67)^2+(15-13.67)^2+(14-13.67)^2}{5}} = 4.4121[/tex]
Confidence interval:
We have the standard deviation for the sample, so the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 6 - 1 = 5
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 2.5706, that is, the critical value is [tex]T_c = 2.5706[/tex]
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.5706\frac{4.4121}{\sqrt{6}} = 4.63[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 13.67 - 4.63 = 9.04.
The upper end of the interval is the sample mean added to M. So it is 13.67 + 4.63 = 18.30.
The 90% confidence interval for the average net change in a student's score after completing the course is (9.04, 18.30).
Find the value of x.
A. 57
B. 72
C. 90
D. 124
Answer:
90
Step-by-step explanation:
Angle Formed by Two Chords= 1/2(SUM of Intercepted Arcs)
105 = 1/2 (120+x)
210 = 120+x
Subtract 120 from each side
210-120 = x
90 =x
The value of Intercepted Arcs x will be 90. so option C is correct.
What is the relation between line perpendicular to chord from the center of circle?If the considered circle has center O and chord AB, then if there is perpendicular from O to AB at point C, then that point C is bisecting(dividing in two equal parts) the line segment AB.
Or
|AC| = |CB|
Angle Formed by Two Chords= 1/2 (Sum of Intercepted Arcs)
105 = 1/2 (120+x)
210 = 120+x
Subtract 120 from each side;
210-120 = x
90 =x
Hence, the value of Intercepted Arcs x will be 90. so option C is correct.
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3x7-12-2=7?
I have no clue please help...
Answer:
X = 28/3, or 9 1/3 or 9.3
Step-by-step explanation:
Answer:
Step-by-step explanation:
Find the missing segment in the image below
simplify 27-{ 9+(12-5)÷4} with solution
Answer:
16.25
Step-by-step explanation:
first do 12 -5 = 7. then 7/4 = 1.75 then 9+1.75 = 10.75 and finally 27-10.75= 16.25
Books, and then you have 44+45x=?
Answer:
45x=-44
x=-44/45
Step-by-step explanation:
is this a free question?
Solve the following inequality using the multiplication principle.
-3 over 7 ≤ -4x
[tex]\\ \sf\longmapsto \frac{ - 3}{7} \leqslant - 4x \\ \\ \sf\longmapsto - 3 \leqslant 7( - 4x) \\ \\ \sf\longmapsto - 3 \leqslant - 28x \\ \\ \sf\longmapsto \ 3 \leqslant 28x \\ \\ \sf\longmapsto x \geqslant \frac{3}{28} [/tex]
Help me please and thank you
Step-by-step explanation:
jlejej
are u using chrome os
