help me solve please

Answer:

the horizontal distance is the x-intercept, and the vertical distance is the y-intercept

1) x-int=1, y-int=1

2) x-int=6, y-int=5

Answer:

Domain is all real numbers, x ≠ -5

Range is all real numbers, y ≠ 0

Step-by-step explanation:

Answer:

Step 2

Step-by-step explanation:

9 was added to both sided so the equation would remain equal and the 9 would be cancelled out on the left side.

Answer:

x = -4

Step-by-step explanation:

logs (8 - 3x) = log20

Since we are taking the log on each side

log a = log b  then a = b

8 -3x = 20

Subtract 8  from each side

8 -3x-8 =20 -8

-3x = 12

Divide by -3

-3x/-3 = 12/-3

x = -4

Answer:

[tex] \boxed{\sf x = -4} [/tex]

Step-by-step explanation:

[tex] \sf Solve \: for \: x \: over \: the \: r eal \: numbers:[/tex]

[tex] \sf \implies log(8 - 3x) = log 20[/tex]

[tex] \sf Cancel \: logarithms \: by \: taking \: exp \: of \: both \: sides:[/tex]

[tex] \sf \implies 8 - 3x = 20[/tex]

[tex] \sf Subtract \: 8 \: from \: both \: sides:[/tex]

[tex] \sf \implies 8 - 3x - 8 = 20 - 8 [/tex]

[tex] \sf \implies - 3x = 12 [/tex]

[tex] \sf Divide \: both \: sides \: by \: - 3:[/tex]

[tex] \sf \implies \frac{-3x}{-3} = \frac{12}{-3} [/tex]

[tex] \sf \implies x = - 4[/tex]

Answer:

Step-by-step explanation:

Given the functions  f(x) =  3x² + 4 and g(x) = 2x − 3, to know that statements that is  true about f+g, we will need to add the functions together first.

f(x)+g(x) = 3x² + 4 + 2x - 3

f(x)+g(x) = 3x²+2x +4 - 3

f(x)+g(x)  = 3x²+2x + 1

The highest degree of a quadratic function is 2 and since the highest degree of the resulting function is 2, hence the resulting sum of the equations is quadratic.

Also the range of the values is all real numbers because the presence of x² in the function will always return a positive value greater than x.

Hence the correct statements are 'the range is all real numbers and it is a quadratic function'

Answer:

B AND D

Step-by-step explanation:

Answer:

554

Step-by-step explanation:

The largest number (5) should go in the hundreds place, the second-largest number (also 5) should go in the tens place and the smallest number (4) should go in the units place so the answer is 554.

Answer:

Proof in the explanation.

Step-by-step explanation:

I expanded both sides as a first step. (You may use foil here if you wish and if you use that term.)

This means we want to show the following:

[tex]3-9\tan^2(\theta)-4\sin^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]

[tex]=12\cos^2(\theta)-9-4\cos^2(\theta)\tan^2(\theta)+3\tan^2(\theta)[/tex].

After this I played with only the left hand side to get it to match the right hand side.

One of the first things I notice we had sine squared's on left side and no sine squared's on the other. I wanted this out. I see there were cosine squared's on the right. Thus, I began with Pythagorean Theorem here.

[tex]3-9\tan^2(\theta)-4\sin^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]

[tex]3-9\tan^2(\theta)-4(1-\cos^2(\theta))+12\sin^2(\theta)\tan^2(\theta)[tex]

Distribute:

[tex]3-9\tan^2(\theta)-4+4\cos^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]

Combine like terms and reorder left side to organize it based on right side:

[tex]4\cos^2(\theta)-1+12\sin^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

After doing this, I since that on the left we had products of sine squared and tangent squared but on the right we had products of cosine squared and tangent squared. This problem could easily be fixed with Pythagorean Theorem again.

[tex]4\cos^2(\theta)-1+12\sin^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

[tex]4\cos^2(\theta)-1+12(1-\cos^2(\theta))\tan^2(\theta)-9\tan^2(\theta)[/tex]

Distribute:

[tex]4\cos^2(\theta)-1+12\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

Combined like terms while keeping the same organization as the right:

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

We do not have the same amount of the mentioned products in the previous step on both sides. So I rewrote this term as a sum. I did this as follows:

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

Here, I decide to use the following identity [tex]\cos\theta)\tan(\theta)=\sin(\theta)[/tex]. The reason for this is because I certainly didn't need those extra products of cosine squared and tangent squared as I didn't have them on the right side.

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\sin^2(\theta)-9\tan^2(\theta)[/tex]

We are again back at having sine squared's on this side and only cosine squared's on the other. We will use Pythagorean Theorem again here.

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\sin^2(\theta)-9\tan^2(\theta)[/tex]

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8(1-\cos^2(\theta))-9\tan^2(\theta)[/tex]

Distribute:

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8+8\cos^2(\theta)-9\tan^2(\theta)[/tex]

Combine like terms:

[tex]12\cos^2(\theta)-9+3tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)[/tex]

Reorder again to fit right side:

[tex]12\cos^2(\theta)-9+4\cos^2(\theta)\tan(\theta)+3\tan^2(\theta)[/tex]

This does match the other side.

The proof is done.

Note: Reordering was done by commutative property.

Answer:

Option (1)

Step-by-step explanation:

Given equation is,

[tex]2^x=1-3^x[/tex]

To determine the solution of the equation we will substitute the values of 'x' given in the options,

Option (1)

For x = -0.75

[tex]2^{-0.75}=1-3^{-0.75}[/tex]

0.59 = 1 - 0.44

0.59 = 0.56

Since, values on both the sides are approximately same.

Therefore, x = -0.75 will be the answer.

Option (2)

For x = -1.25

[tex]2^{-1.25}=1-3^{-1.25}[/tex]

0.42 = 1 - 0.25

0.42 = 0.75

Which is not true.

Therefore, x = -1.25 is not the answer.

Option (3)

For x = 0.75

[tex]2^{0.75}=1-3^{0.75}[/tex]

1.68 = 1 - 2.28

1.68 = -1.28

Which is not true.

Therefore, x = 0.75 is not the answer.

Option (4)

For x = 1.25

[tex]2^{1.25}=1-3^{1.25}[/tex]

2.38 = 1 - 3.95

2.38 = -2.95

It's not true.

Therefore, x = 1.25 is not the answer.

Answer:

D. [tex]\sqrt{\frac{2*2*2*2*3}{5*5*7} }[/tex]

Step-by-step explanation:

48 divided by 2 is 24. Insert the 2.

24 divided by 2 is 12. Insert the 2.

12 divided by 2 is 6. Insert the 2.

6 divided by 2 is 3. Insert the 2 and 3:

[tex]48=2*2*2*2*3[/tex]

175 divided by 5 is 35. Insert the 5.

35 divided by 5 is 7. Insert the 5 and 7:

[tex]175=5*5*7[/tex]

:Done

Answer:

You can write in

Step-by-step explanation:

Lakhs

First write 100,203.

Put ones,tens,hundreds,thousands,ten thousands and lakh on top of each number from the extreme left.

This is how you can write 100,203 in another way. You can't write in any other way than this one.

Hope this helps....

Have a nice day!!!!

Answer:

Step-by-step explanation:

The triangle inequality theorem states that the sum of any two sides of a triangle os greater than the third side.

■■■■■■■■■■■■■■■■■■■■■■■■■■

First triangle:

Let a,b and c be the sides of the triangle:

● a = 10

● b = 20

● c = 30

Now let's apply the theorem.

● a+b = 10+20=30

That's equal to the third side (c=30)

●b+c = 50

That's greater than a.

● a+c = 40

That's greater than b.

These aren't the sides of a triangel since the first inequality isn't verified.

■■■■■■■■■■■■■■■■■■■■■■■■■

Second triangle:

● a = 122

● b = 257

● c = 137

Let's apply the theorem.

● a+b = 379

That's greater than c

● a+c = 259

That's greater than b

● b+c = 394

That's greater than a

So 122,257 and 137 can be sides of a triangle.

■■■■■■■■■■■■■■■■■■■■■■■■■■

The third triangle:

● a = 8.6

● b = 12.2

● c = 2.7

Let's apply the theorem:

● a+b = 20.8

That's greater than c

● b+c = 14.9

That's greater than a

● a+c = 11.3

That isn't greater than b

So theses sides aren't the sides of triangle.

■■■■■■■■■■■■■■■■■■■■■■■■■■

● a = 1/2

● b = 1/5

● c = 1/6

Let's apply the theorem.

● a+b = 7/10

That's greater than c

● a+c = 2/3

That's greater than b

● b+c = 11/30

That isn't greater than a

So these can't be the sides of a triangle.

Answer:

F , D, E

Step-by-step explanation:

The smallest angle is opposite the smallest side

The largest angle is opposite the largest side

DE is smallest so F is smallest

Then EF so D

DF is largest so E is the largest angle

Answer:

x = 9/4

y = 3/5

z = 2/3

w = -9/5

Step-by-step explanation:

Technically, the matrix is in reduced row echelon form. If there are zeros above and below the ones, it is RREF. If there are zeros only below the ones, then it's REF.

Since it is in RREF, the augmented numbers to the right of the bar are already your solutions. Simply label the variables.

Answer:

B. f(n) = 56(0.5)^n-1

Step-by-step explanation:

 First, You have to find out the starting population, if you look at the problem you see the population starts at 56

f(x) = 56

Second, you know that the population goes down 50% each week so it has a decay of 0.5

f(x) = 56(0.5)

 Third,  you need to add the exponent of n to make it exponential.  But, if you just add n then the the population would be 28 on week 1 which is incorrect. To fix that you make the exponent n-1 so when you are on week 1 it doesn't become 28 but it stays on 56, and on week 2 it's 28, ect

f(x) = 56(0.5)^n-1

X - (-20) = 5

When you subtract a negative, change it to addition:

X + 20 = 5

Subtract 20 from both sides:

X = -15

Answer:

[tex]\boxed{x=-15}[/tex]

Step-by-step explanation:

[tex]x-(-20)=5[/tex]

[tex]\sf Distribute \ negative \ sign.[/tex]

[tex]x+20=5[/tex]

[tex]\sf Subtract \ 20 \ from \ both \ sides.[/tex]

[tex]x+20-20=5-20[/tex]

[tex]x=-15[/tex]

Answer:

B. -75

Step-by-step explanation:

you count backwards from 5, 27 times

AC will be 4√2 when AB = 4 and BC = 4, in the given right triangle.

According to Pythagoras' Theorem, in a right triangle, the square of the length of the longest side, that is, the hypotenuse, that is, the side opposite to the right angle is equal to the sum of the squares of the lengths of the other two sides.

In the question, we are given a right triangle, with sides AB = 4 and BC = 4.

We are asked to find AC.

To find AC, we will use the Pythagoras theorem, according to which, we can write:

AC² = AB² + BC²

or, AC² = 4² + 4²,

or, AC² = 16 + 16,

or, AC² = 32,

or, AC = √32,

or, AC = √(16 * 2) = 4√2.

Therefore, AC will be 4√2 when AB = 4 and BC = 4, in the given right triangle.

Learn more about Pythagoras' Theorem at

https://brainly.com/question/231802

#SPJ2

Answer:

143.32 m

Step-by-step explanation:

Given the following :

Diameter of circular track = 80m

Hillary's speed = 300m per minute

Eugene's speed = 240m per minute

Run time = 50 minutes

Note: they both run in opposite direction.

Calculate the Circumference(C) of the circle :

C = 2πr or πd

Where r = radius ; d = diameter

Using C = πd

C = πd

C = π * 80

C = 251.327

Eugene's distance covered = (240 * 50) = 12000

Hillary's distance covered = (300 * 50) = 15000

Number turns :

Eugene = 12000/ 251.327 = 47.746561

Hillary = 15000/251.327 = 59.683201

Therefore ;

48 - 47.746561 = 0.253439

60 - 59.683201 = 0.316799

(0.253439+0.316799) = 0.570238

Distance which separates Eugene and Hillary when they finish :

0.570238 * 251.327 = 143.32 m

Answer: 880 cm

Step-by-step explanation:

Given: Radius of the hula hoop = 35 cm

Hula hoop is  circular in shape

Then, Circumference = [tex]2\pi r[/tex] , where r = radius

Now , Circumference of hula hoop = [tex]2\times \dfrac{22}{7}\times35=220\ cm[/tex]

Now , the distance the hula hoop rolls in 4 full rotations = 4 × (Circumference of hula hoop)

[tex]= 4 \times 220=880\ cm[/tex]

Hence, the required distance = 880 cm

Answer:

880

Step-by-step explanation:

Answer:

LOOK BELOW

Step-by-step explanation:

Mean= add all of the numbers together and divide by total amount of

            numbers

            aka=3

Median= put all the numbers in order and find the number in the middle

               aka=2.5

Minimum=0

Maximum=8

This data can only be found using a Box and Whisker Plot....

I can't really explain a box and whisker plot so you have to look that up to understand that..  SRY!!!

------------------------------------

First Quartile=1

Third Quartile=5

Interquartile Range=4

Answer:

Mean= add all of the numbers together and divide by total amount of

           numbers

           aka=3

Median= put all the numbers in order and find the number in the middle

              aka=2.5

Minimum=0

Maximum=8

This data can only be found using a Box and Whisker Plot....

I can't really explain a box and whisker plot so you have to look that up to understand that..  SRY!!!

------------------------------------

First Quartile=1

Third Quartile=5

Interquartile Range=4

Step-by-step explanation:

Answer:

x = 19 1/3

Step-by-step explanation:

6/14 = 7/(x-3)

Using cross products

6 * (x-3) = 7*14

6x -18 = 98

Add 18 to each side

6x-18+18 =98+18

6x = 116

Divide each side by 6

6x/6 = 116/6

x =58/3

x = 19  1/3

Answer= 58/3

Step by Step

Step 1: Cross-multiply.

6*(x−3)=(7)*(14)

6x−18=98

Step 2: Add 18 to both sides.

6x−18+18=98+18

6x=116

Step 3: Divide both sides by 6.

6x /6 = 116 /6

x= 58 /3

Answer:

x=27

Step-by-step explanation:

expanding the above expression we get

5x+5=4x+32

grouping numbers with coefficient of x at the left side and constant at the right side we get

5x-4x=32-5

x=27

Step-by-step explanation:

log 10 = 1.  So if log x < 1, then x < 10.  And if log x > 1, then x > 10.

The upper left number is the smallest, and can't be smaller than 1.  If the exponent is 0, we can put any number in the red box.

The fractions in the upper right and lower left need to be as large as possible.  The denominators will be small, and the numerators will be large.

From there, a little trial and error does the rest.  The are many possible answers.  I've included one.

Answer:

B) Associative Property of Multiplication

Step-by-step explanation:

*if it's wrong idk how, but I apologise*

Answer:

y=−2x−13.

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=−2x−5.

The slope of the parallel line is the same: m=−2.

So, the equation of the parallel line is y=−2x+a.

To find a, we use the fact that the line should pass through the given point: −1=(−2)⋅(−6)+a.

Thus, a=−13.

Therefore, the equation of the line is y=−2x−13.

Answer:

10 cm is the answer because 30÷3 angles

Answer:

The steps to construct a a line parallel to another line from a point includes

1) From the given line draw a transversal through the point

2) With the compass, copy the angle formed between the transversal and the given line to the point P

3) Draw a line through the intersection of the arcs of the angle construction to get the parallel line through the point P

Step-by-step explanation:

Answer:

The number to be added is 6.89

Step-by-step explanation:

Here, we want to know what number must be added to the expression to make it equal to zero.

Let the number be x

Thus;

-6.89 + 14.52 -14.52 + x = 0

-6.89 + x = 0

x = 6.89

Answer:

809.915$

Step-by-step explanation:

Amount of money = Principal x e^(rate x year)

                              = 600 x e^(0.05 x 6)

                              = 809.915$

Answer:

$809.92

Step-by-step explanation:

(see attached for reference)

Recall that the formula for compound interest (compounded continuously) is

A = P e^(rt)

where,

A = final amount (we are asked to find this)

P = principal = given as $600

r = interest rate = 5% = 0.05

t = time = 6 years

e = 2.71828 (mathematical constant)

Substituting the known values into the equation:

A = P e^(rt)

= 600 e^(0.05 x 6)

= 600 (2.71828)^(0.30)

= $809.92

Answer: 33

First you divide 55 by 5 to get the total number of squares in one part, which equals 11. Then you multiply by 3 since there are 3 parts of green squares to get your answer, 33.