HELP ME ILL MARK YOU THE BRAINLIEST

HELP ME ILL MARK YOU THE BRAINLIEST

Answers

Answer 1

Option C: Later in the day, less power is developed in lifting each box

Answer 2

Answer:

Later in the day, less power is developed in lifting each box.

power= workdone÷time


Related Questions

a man runs 1200m on a straight line in 4 min . find his velocity.

Answers

Answer:

5m/sec^2

Explanation:

Distance=1200m

Time=4 min

1=60sec

4=4 x 60

=240sec

Velocity=Distance/Time

Velocity=1200/240

Velocity=5m/sec^2

Mark me as brainliest

The metal wire in an incandescent lightbulb glows when the lights is switch on and stops glowing when switched off. This simple process is which kind of a change?

Answers

Answer:

When the metal wire in an incandescent lightbulb glows when the light is switched on and stops glowing when it is switched off, this is an example of resistance, which provides light and heat.  

Explanation:

Opening or closing a circuit.

Vector B has components Bx = 6.18 and By = 4.43. Find the magnitude and direction counter clockwise from the positive x-axis.

Answers

Answer:

Explanation:

The formula for the magnitude of this resultant vector, which is in Q1, btw, is:

[tex]B_{mag}=\sqrt{6.18^2+4.43^2}[/tex] which gives us, to 3 sig fig's:

7.60 m. Since the resultant vector is in Q1, we don't need to add anything to the angle once we find it to 3 sig fig:

[tex]tan^{-1}(\frac{4.43}{6.18})[/tex] gives us an angle of 35.6 degrees

A 2 kg hammer is used to nail a 0.002 kg nail with a force of 10 N. How much force is applied to the hammer?

Answers

Answer:

10 N

Explanation:

Given that,

A 2 kg hammer is used to nail a 0.002 kg nail with a force of 10 N.

We need to find how much force is applied to the hammer.

We know that, every action has an equal and opposite reaction. Both the action and reaction occurs in two different objects.

Hence, the force applied to the hammer is equal to 10 N.

Si se aplic una fuerza de 150N en un área de de 0.4m2¿cual será la preciosa ejercida?

Answers

Answer:

P = 375 Pa

Explanation:

The question says that,"If a force of 150N was applied in an area of ​​0.4m², what will be the precious exerted?"

We have,

Force, F = 150 N

Area, A = ​​0.4m²

We need to find the pressure exerted. We know that,

Pressure = forece/area

So,

[tex]P=\dfrac{150\ N}{0.4\ m^2}\\\\P=375\ Pa[/tex]

So, the required pressure is equal to 375 pa.

a string 2m long used to whirl a 200gm stone in horizontal circle at a speed of 2m/s . find the tension in the string​

Answers

Answer:

Explanation:

First off, we need the mass in kg and it's in g so we have to convert it. Then we can do the problem. 200 g = .200 kg. Moving on.

The equation used to find the tension in the string is the same one we use to find the centripetal force, because the tension is what is upplying the centripetal force needed to keep the stone moving in a circular manner. The formula for that is

[tex]F_c=T=\frac{mv^2}{r}[/tex] where ma is the mass in kg, v is the velocity in m/s, and r is the radius of the circle about which the stone spins in meters.

Filling in:

[tex]T=\frac{(.200)(2)^2}{2}[/tex] which gives us

T = .4 N

If you have a cube that is 2x2x2 and weighs 5.29 g. How do you find the density?

Answers

Answer:

0.66

Explanation:

Follow the Density Formul d = m/v

so

d = 5.29/8

= 0.66 Density

Just correct me if I'm wrong, I mean like literally :> Thank you! ^^

.66 is the answer
Step by step explanation:
Because I said so

As Courtney switches on the TV set to watch her favorite cartoon, the electron beam in the TV tube is steered across the screen by the field between two charged plates. If the electron experiences a force of 3.0 * 10^6 N, how large is the field between the deflection plates?

Answers

Answer:

Explanation:

Force= (q1q2)/(4/\Ęr2)

3×10^6= (1.602×10^-19)^2/(r^2)

r^2=(2.27×10^-33)/(3×10^6)

r^2=8.55×10^-45

r= 9.25×10^-23

(b) During one day, 250 kg of water is pumped through
the solar panel. The température of this
water rises from 16°C to 38°C.
The water absorbs 25% of the energy incident on the solar panel. The
specific heat capacity
of water is 4200J/(kg °C).
Calculate the energy incident on the solar panel during that day.
Please explain how to find the incident energy

Answers

Answer: The energy incident on the solar panel during that day is [tex]9.24 \times 10^{7} J[/tex].

Explanation:

Given: Mass = 250 kg

Initial temperature = [tex]16^{o}C[/tex]

Final temperature = [tex]38^{o}C[/tex]

Specific heat capacity = 4200 [tex]J/kg^{o}C[/tex]

Formula used to calculate the energy is as follows.

[tex]q = m \times C \times (T_{2} - T_{1})[/tex]

where,

q = heat energy

m = mass of substance

C = specific heat capacity

[tex]T_{1}[/tex] = initial temperature

[tex]T_{2}[/tex] = final temperature

Substitute the values into above formula as follows.

[tex]q = 250 kg \times 4200 J/kg^{o}C \times (38 - 16)^{o}C\\= 250 kg \times 4200 J/kg^{o}C \times 22^{o}C[/tex]

As it is given that water absorbs 25% of the energy incident on the solar panel. Hence, energy incident on the solar panel can be calculated as follows.

[tex]\frac{25}{100} \times q = 250 kg \times 4200 J/kg^{o}C \times 22^{o}C\\q = 9.24 \times 10^{7} J[/tex]

Thus, we can conclude that the energy incident on the solar panel during that day is [tex]9.24 \times 10^{7} J[/tex].

Waves break on a beach due to:

reducing depth of water near beach
increasing wavelength near beach
turbulence near the shoreline

Answers

the answer is “increasing wavelength near beach”

Answer:

increasing wavelength near beach

Explanation:

When wavelength increases, frequency of these waves decreases and the waves suddenly stop.

This is also called damped oscillation.

Si un movil parte del reposo logrando una aceleracion de 5 metros por segundo al cuadrado durante 8 segundos calcular la velocidad final

Answers

Answer:

Velocidad final, V = 40 m/s

Explanation:

Dados los siguientes datos;

Aceleración = 5 m/s²

Velocidad inicial = 0 m/s (ya que comienza desde el reposo)

Tiempo = 8 segundos

Para encontrar la velocidad final, usaríamos la primera ecuación de movimiento;

[tex] V = U + at[/tex]

Dónde;

V es la velocidad final. U es la velocidad inicial. a es la aceleración. t es el tiempo medido en segundos.

Sustituyendo en la fórmula, tenemos;

[tex] V = 0 + 5*8 [/tex]

[tex] V = 0 + 40 [/tex]

[tex] V = 40 [/tex]

Velocidad final, V = 40 m/s

Bones are composed of three main components, what are they? (Choose all that apply)

Answers

Answer:

funny bone and compact bone

Explanation:

your funny bone only reacts if you hit it against something the compact bone is the heaviest and strongest bone in your body and the bone marrow is soft sponge like tissue in the center if most bones that produces white and red blood cells

A car with a mass of 500 kg is moving at a speed of 12 m/s. How much kinetic energy does it have?


someone please help me PLEASEEEE <3

Answers

Answer:

36000

Explanation:

1/2mv²=0.5×500×12²=36000j

How is an ammeter connected in a circuit to measure current flowing through it?

Answers

Answer:

It is connected in series with the circuit

Explanation:

This is because to measure the current in the circuit, the current in the circuit has to flow through the ammeter. As such, the ammeter must be connected in series with the circuit so as to measure the current flowing through the circuit.

So, to measure the current flowing through a circuit with an ammeter, the ammeter must be connected in series with the circuit.

If you were testing materials to see whether they conduct electricity using a circuit and bulbs, what variable would you be changing?

A. The strength of the battery
B. The number of bulbs
C. The material
D. The time it takes the electricity to complete the circuit

Answers

Answer: C. The material

Explanation:

In order to check whether a material conducts electricity, the first thing to do would be to design a circuit. Connect a positive wire to the batteries and then another wire from the battery to the bulb and then a wire from the bulb as well.

Then bring different materials to test for conductivity by connecting the wires to the material. If the bulb lights then it is a conductor and if it doesn't the material is not a conductor. The material is therefore the changing variable.

There is a bell at the top of a tower that is 45m high. The bell weighs 190N. The bell has ___________________ energy. Calculate it.




I NEED THE ANSWER PLEASE

Answers

Answer:

250mn

Explanation:

1 Ten (10) ml aqueous solutions of drug A (10% w/v) and drug B (25% w/v) are stored in two identical test tubes under identical storage conditions at 37°C for 3 months. If both drugs degrade by first-order, which drug will retain the highest percentage of initial concentration?

Answers

Answer:

YOUR answer is given below:

Explanation:

Drug B will retain the highest percentage of initial concentration.

First order degradation means that both solution will degrade by same amount in same time because first order is directly proportional relationship between given both aqueous solution.

Given that Ten (10) ml aqueous solutions of drug A (10% w/v) and drug B (25% w/v) are stored in two identical test tubes.

Since, initially concentration of Drug B is more. Therefore, at all instant concentration of Drug will be highest.

Learn more:

brainly.com/question/17029235

the volume of vessel is 6 litres. convert it into ml​

Answers

6000 ml
There are 1000ml in one liter

A certain capacitor, in series with a resistor, is being charged. At the end of 25 ms its charge is half the final value. The time constant for the process is about:

Answers

Answer:

  τ = 36 10⁻³ s

Explanation:

The charge of a circuit Rc is given by the expression

          q = q₀ (1 - [tex]e^{-t/ \tau }[/tex])

          q / q₀ = 1 - e^{-t/  \tau }

in this exercise they indicate that

          q / q₀ = ½

for a time t = 25 10⁻³ s

we substitute

          ½ = 1 - [tex]e^{- 25 \ 10^{-3} / \tau}[/tex]

          e^{- 25 \ 10^{-3} /  \tau} =  1 -½

         - 25 10⁻³ /τ = ln 0.5

         -25 10⁻³ / ln 0.5 = τ

         τ = 36 10⁻³ s

Multiplying a vector with another vector results in what type of answer.

A) a direction
B) a vector
C) either a vector or a scalar
D) a scalar

Answers

multiplication of two vectors yields a vector oroduy

how does energy change ? explain with example . how does bulb generate ? write with it's part.​

Answers

Answer:

According to the law of conservation of energy, energy is neither created nor destroyed but changes from one form to another

The energy in the light bulb comes from the movement of electrons through the resistance of the coil of the bulb, therefore, the energy in the bulb is changed from electric energy to heat and light energy as follows;

The friction between the moving electrons and the resistive filament of the light bulb results in the slowing down of the rapidly moving electrons

The part change in the (kinetic) energy of the electrons moving through the filament of the bulb as they slow down is observed as sensible heat which causes the bulb to be hot

Another part of the change in energy is given seen as the light given off by the bulb filament in an incandescent bulb as the filament becomes very hot from the movement of the electrons which causes the bulb to glow (produce light), due to the incandescent characteristics of the filament

Explanation:

a bell rings at a frequency of 75hz on a warm 25 degree evening. calculate the...
a. speed of the sound wave at this temperature.
b. wavelength of the sound wave

Answers

Answer:

Explanation:

We need 2 different equations for this problem: first the velocity of sound equation, then the frequency of the sound equation.

The velocity of sound is found in:

v = 331.5 + .606T

We need to find that first in order to fill it into the frequency equation which is

[tex]f=\frac{v}{\lambda}[/tex] where v is the velocity we will find the part a, f is frequency and lambda is the wavelength. Starting with the velocity of the sound:

v = 331.5 + .606(25) and

v = 331.5 + 15 and rounding correctly using the rules for sig fig when adding:

v = 347 m/s

Filling that into the frequency equation:

[tex]75=\frac{347}{\lambda}[/tex] and

[tex]\lambda=\frac{347}{75}[/tex] so

[tex]\lambda=4.6m[/tex]

what is parking orbit?​

Answers

A parking orbit is a temporary orbit used during the launch of a spacecraft. A launch vehicle boosts into the parking orbit, then coasts for a while, then fires again to enter the final desired trajectory.

Hope this helps!

Have a great day :)

Answer:

A temporary orbit in which a spacecraft awaits the next phase of its mission .

6.05 Infections and Health
Plese don't report me i am trying to get the assigment done
Introduction
Contaminated water is a health risk, and not all populations have access to clean water. You are going to use household items to design, test and revise a water filtration system. New technologies undergo testing and revision before they are released to the public. This lab will simulate how the scientific process is used to solve problems.

Purpose
The Purpose of your design is to filter dirt, sand and other sediment from “swamp” water. You do not need to make it drinkable during this design. You will begin with a water sample that has visible dirt, mud or other contaminants. You will design a way to filter the water and evaluate your design. You will not be able to test for microorganisms or to filter them out during this design process. Do not test the water by drinking it.

Important: Do NOT drink the water in your experiment.
Materials
“Swamp” water (You can get this from an outside source like a hole in the ground, puddle, lake, river or swamp. Or, you may add dirt and sediment to tap water.) The starting sample should have visible dirt or sediment.

You may use any household materials for your water filtration system. Here are some suggestions:

Cheesecloth
OId t-shirt
Coffee filters
Pantyhose
Cotton balls
Sock
Funnel
Water bottle









Data for Design One (6 points)
Describe the appearance and smell of the “swamp” water before and after filtration. Use complete sentences and detailed examples.
Skilled Scientist level from Rubric: Student gives thorough details about the appearance and smell of the water before and after the filtration for Design One and Design Two.



Water before filtration
Water after filtration
Description of appearance




Description of smell or other physical characteristics




Rate the visible cleanliness of the water on a scale of 1 to 10 with 10 being the cleanest.



Feedback ( 5 points)
Consulat a peer or a family member about ways your design could be improved. Describe the feedback and provide the name of the reviewer. These are only suggestions that you can use to plan for Design Two. Use complete sentences and detailed examples.
Skilled Scientist level from Rubric: Student thoroughly describes the feedback received from peer/family member, and it is clear a meaningful exchange about ways to improve the design took place.
List the name of peer/family member and relationship:






Describe the feedback given by your peer/family member. What changes do they suggest you make to your design in order to clean the water better?




Planning for DesignTwo (8 points)
Use this space to plan out how to improve your water filter. Based on the feedback you received, what part are you trying to improve? Why did you make the changes that you did? Use complete sentences and detailed examples. You may include sketches or diagrams.
Skilled Scientist level from Rubric: Student thoroughly explains the changes for the design and gives ample details about any improvements that were made.
List materials used:






Describe how Design Two will work:









What part of your design are you trying to improve?







Why did you make the changes you did?




Data for Design Two (6 points)
Use the data and feedback from your first design to make changes to your water filtration system. Test your new design. Record the appearance and smell of the “swamp” water before and after filtration. Use complete sentences and detailed examples.
Skilled Scientist level from Rubric: Student gives thorough details about the appearance and smell of the water before and after the filtration for Design One and Design Two.



Water before filtration
Water after filtration
Description of appearance




Description of smell or other physical characteristics




Rate the visible cleanliness of the water on a scale of 1 to 10 with 10 being the cleanest.






Conclusion (10 points)
Use your data from Design One and Design Two to answer the following questions. Use complete sentences and detailed examples.
Skilled Scientist level from Rubric: Student answers all questions using ample details and showing critical thinking skills to reflect on the design process.
Summarize the appearance and smell of the “swamp” water before and after the filtering process using Design One.




2. Describe the changes you made to your water filtration system.




3. What feedback helped you make changes to your water filtration system?




4. Summarize the appearance and smell of the “swamp” water before and after the filtering process using Design Two.




5. What did you learn about the process of planning, testing and revising a design?

Answers

The process of filtration of swamp water using a filtering material such as neat clothes will make the water clearer and remove any bad smell.

What is filtration?

Filtration is a separation technique used to separate insoluble solids from a liquid.

Filtration is employed in water purification.

Water purification is done in water purification plants.

A locally designed purification process for swamp water will involve using materials such as:

A T-shirt Funnel Water bottle

The T-shirt is used filter out mud and sediments.

Repeated filtrations will make the water clearer and remove any bad smell.

Learn more about filtration at: https://brainly.com/question/552187

A sphere of diameter 3.0cm is mounted into a thin uniform wire of diameter 0.2mm calculate the length of the wire in meters​

Answers

Answer:

Length of the wire in meters​ = 0.000628 meter (Approx.)

Explanation:

Given:

Diameter of wire = 0.2 mm

Find:

Length of the wire in meters​

Computation:

Radius of wire = 0.2 / 2

Radius of wire = 0.1

Length of the wire = Circumference of circle

Circumference of circle = 2πr

Length of the wire = 2πr

Length of the wire = 2(3.14)(0.1)

Length of the wire = 0.628 mm (Approx.)

1 meter = 1,000 mm

So,

Length of the wire in meters​ = 0.000628 meter (Approx.)

what is electricity?write any two defects of a simple cell.​

Answers

Answer:

Electricity is the set of physical phenomena associated with the presence and motion of matter that has a property of electric charge. Electricity is related to magnetism, both being part of the phenomenon of electromagnetism, as described by Maxwell's equations.

10 points
Calculate the force of attraction between the moon and the earth, if their masses and distance apart are 10^22Kg, 10^24kg and 6.4x10^6m. Take g = 6.67x10^-11Nm^2Kg^-2
a) 0.63x10^24N
b) 1.63x10^22N
c) 2.63x10^20N
d) 3.63x10^18N​

Answers

Answer:

Explanation:

You didn't fill in the proper masses which is why you never got an answer to this. But that's ok...I got you. I happen to know what they are! We will use the universal law of gravitation and the gravitational constant to solve this.

[tex]F_g=\frac{Gm_1m_2}{r^2}[/tex] and filling in:

[tex]F_g=\frac{(6.67*10^{-11})(5.98*10^{24})(7.36*10^{22})}{(3.84*10^8)^2}[/tex] The denominator is the radius of the earth plus the radius of the moon plus the distance between their surfaces, just FYI.

That gives us that

[tex]F_g=1.99*10^{20}N[/tex] Not sure what your choices entail, but I'd have to say, taking into consideration that maybe your problem didn't figure in the distance between the surfaces, you'd be at choice B.

A container of gas is at a pressure of 3.7 x 10^5 Pa. How much work is done by the gas if its volume expands by 1.6 m^3 ?

Answers

Answer:

592000 J

Explanation:

We'll begin by converting 3.7×10⁵ Pa to Kg/ms². This can be obtained as follow:

1 Pa = 1 Kg/ms²

Therefore,

3.7×10⁵ Pa = 3.7×10⁵ Kg/ms²

Next, we shall determine the workdone.

Workdone is given by the following equation:

Workdone (Wd) = pressure (P) × change in volume (ΔV)

Wd = PΔV

With the above formula, the work done can be obtained as follow:

Pressure (P) = 3.7×10⁵ Kg/ms²

Change in volume (ΔV) = 1.6 m³

Workdone (Wd) =?

Wd = PΔV

Wd = 3.7×10⁵ × 1.6

Wd = 592000 Kgm²/s²

Finally, we shall convert 592000 Kgm²/s² to Joule (J). This can be obtained as follow:

1 Kgm²/s² = 1 J

Therefore,

592000 Kgm²/s² = 592000 J

Therefore, the Workdone is 592000 J.

A cyclist is taking part in the Tour de France, which is a bicycle race that takes place every year.
a Two forces acting on the cyclist are weight and reaction. Name two other forces acting on him
as he cycles along.

Answers

Solve the following word problems.
1. The ratio of red marbles and blue marbles that Carlo has is 8: 3. When he
exchanged 35 red marbles for 20 blue marbles from his brother, he was left with
equal number of red and blue marbles.
How many red and blue marbles did he have at the beginning
How many red and blue marbles did he have now

A gas in a sealed container has a pressure of 50 kPa at 27°C. What will the pressure of the gas be if the temperature rises to 87°C?

Answers

Answer:

the final pressure of the gas is 60 kPa.

Explanation:

Given;

initial pressure of the gas, P₁ = 50 kPa = 50,000 Pa

initial temperature of the gas, T₁ = 27⁰ C = 27 + 273 = 300 k

final temperature of the gas, T₂ = 87⁰ C = 87 + 273 = 360 K

Let the final pressure of the gas = P₂

Apply pressure law;

[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\P_2 = \frac{P_1T_2}{T_1} = \frac{50,000 \times 360}{300} = 60,000 \ Pa = 60 \ kPa[/tex]

Therefore, the final pressure of the gas is 60 kPa.

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