Quadrants I and IV
When we graph y^2 = x - 4, we see that it is on the x axis, and goes up into Quadrant I, and down into Quadrant IV
Write equations for the vertical and horizontal lines passing through the point (5,-9).
Answer:
the vertical line is:
x = 5
The horizontal line is:
y = -9
Step-by-step explanation:
A vertical line has a fixed x-value, while a horizontal line has a fixed y-value.
Then we can write a vertical line as:
x = a
and a horizontal line as
y = b
Then, if we want a vertical line that passes through the point (5, -9), remember that the x-vale will be fixed, then we fix the x-value at the same x-value of the point, which we know that is 5, then the vertical line that passes through the point (5, -9) is:
x = 5
While the horizontal line that passes through the point (5, -9) will be a line with the y-value fixed at the y-value of the point, which we know is -9
Then the horizontal line is:
y = -9
Help me, please
I really need
Answer:
answrr
yes ok
Step-by-step explanation:
4+4-4#_44
The sum of first three terms of an arithmetic series is 21. If the sum of the first two terms is subtracted from the third term then it would be 9. find the three terms of the series. The first and last bra
Answer:
The terms are - 1, 7 and 15.
Step-by-step explanation:
Let the terms be a-d, a, a+d.
ATQ, a-d+a+a+d=21, a=7 and a+d-(a-d+a)=9. 2d-a=9, d=8. The terms are - 1, 7 and 15.
The first three terms will be : -1, 7, 15
We have sum of first three terms of an arithmetic series is 21. It is given that if the sum of the first two terms is subtracted from the third term then it would be 9.
We have to find the three terms of the series.
What is Arithmetic progression or sequence?An arithmetic progression or sequence with common difference [tex]d[/tex] is given as -
a, a + d, a + 2d, a + 3d .....
According to the question -
a + (a + d) + (a + 2d) = 21
3a + 3d = 21
3(a + d)=21
a + d = 7 (Eqn. 1)
(a + 2d) - (a + a + d) = 9
a + 2d - a - a - d = 9
d - a = 9
a = d - 9
Substituting the value of 'a' in Eqn. 1, we get -
d - 9 + d = 7
2d - 9 = 7
2d = 16
d = 8
Therefore -
a = 8 - 9
a = -1
The three terms are -
a = -1
a + d = -1 + 8 = 7
a + 2d = -1 + 2 x 8 = 15
Hence, the first three terms will be - -1, 7, 15
To solve more questions on Arithmetic Sequences and finding the terms, visit the link below -
https://brainly.com/question/20384906
#SPJ2
30 Points cuz I need help ASAP
Answer:
the answer is option 1
Step-by-step explanation:
the negative angle => a quarter round angle (clockwise) = ¼ x ( -360°) = -90°
and
the positive angle => a full round angle + 270° = (360°)+270°
= 630°
Answer:
correct answer is -90 and 630
Step-by-step explanation:
if a hexagonal prism has a volume of 539 cubic meters and is 16 meters tall, find the area of the hexagonal base
Base Area= ___ m^2
9514 1404 393
Answer:
33 11/16 m² = 33.6875 m²
Step-by-step explanation:
The volume of a prism is given by ...
V = Bh
where B is the area of the base, and h is the height. Solving for B, we find ...
B = V/h
B = (539 m³)/(16 m) = 33 11/16 m² = 33.6875 m²
in a class ,ratio of the number of girls to boys is13:7 , find the percentage of boy
3.41 repeating as a fraction?
Answer: the answer is 3 41/99
Step-by-step explanation: got it from khan pls mark me 5 stars
I need help FAST!!!Make sure you can explain the problem
Answer:
AB is not a tangent to the circle
Step-by-step explanation:
The angle between a tangent and the radius at the point of contact = 90°
Using Pythagoras' identity to determine if the triangle is right at A
If the square of the longest side is equal to the sum of the squares on the other 2 sides then A is right.
longest side = 15 , then 15² = 225
8² + 9² = 64 + 81 = 145 ≠ 225
Then AB is not a tangent to the circle
1st point: (1,2)
2nd point: (4,4)
Answer:
y = 2/3x + 4/3
Step-by-step explanation:
i found the slope using [tex]\frac{rise}{run}[/tex]. so it would be 2/3. next i just kinda tested similar numbers in the graph to find b.
if you aren't allowed to put factions i would say put:
y = 0.67x + 1.33
Answer:
[tex]2x - 3y + 4 = 0[/tex]
Step-by-step explanation:
The formula of finding equation of two different point is
[tex] \frac{x - x1}{x1 - x2} = \frac{y - y1}{y1 - y2} [/tex]
here, x1 =1, x2=4, y1= 2 and y2= 4
hope you can understand.
Answer always, sometimes, or never.
Answer:
always
never
always
always
Every week, Judy goes to the supermarket and buys the following: $5$ carrots at $\$1$ each, $3$ bottles of milk at $\$3$ each, $2$ pineapples at $\$4$ each, $2$ bags of flour at $\$5$ each, and a giant $\$7$ container of ice cream. This week the store has a sale and pineapples are half price. Judy also has a coupon for $\$5$ off any order of $\$25$ or over. How much money does Judy spend on this shopping trip
Answer:
She spends $30 in total.
Step-by-step explanation:
Suppose that you buy X units of a given product with a price Y, then the total cost here is X*Y, with this we can solve our problem:
Every week Judy buys:
5 carrots, at $1 each, so she spends 5*$1 = $5 in carrots.
3 bottles of milk at $3, so she spends 3*$3 = $9 in milk bottles.
2 pineapples at $4 each (but the pineapples are at half price, so this week the pineapples cost $4/2 = $2), so she spends 2*$2 = $4 in pineapples.
2 bags of flour at $5 each, so she spends 2*$5 = $10 in flour.
1 giant container of ice cream, she spends $7 on it.
So the total money that she speends is:
$5 + $9 + $4 + $10 + $7 = $35
And she has a coupon for $5 in any order equal to or larger than $25, his order is larger than $25, so she can use the coupon.
So she will spend a total of $35 - $5 = $30
She spends $30 in total.
Rewrite using exponents
AxAxAxAxAxAxA
need answer quick!!! please
Answer:
A^7
Step-by-step explanation:
Best answer gets brainliest and 5 stars
Answer:
A
Step-by-step explanation:
pgt states if the square of the length of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle.
Answer:
Does the answer help you?
Find the length of side x in simplest radical form with rational denominator.
Answer:
sqrt(20)
Step-by-step explanation:
The two perpendicular side lengths are equal, so using Pythagoras theorem:
x = sqrt( sqrt(10)^2 + sqrt(10)^2 )
x = sqrt(10 + 10)
x = sqrt(20)
a local community college has 860 students. Of these 860 students, 220 ride bicycles. Write the number of bike riders as a fraction of the number of students at the college in simplest form
Answer:
11/43
Step-by-step explanation:
A local community college has 860 students
Out of this 860 students, 220students ride bikes
Therefore the fraction of bike riders to the number of students can be calculated as follows
= 220/860
= 11/43
Debt is a result of spending more than you make.
True
False
In a competition, four of the participants have completed their performances. Their scores are 9.61, 9.66, 9.64, and 9.60. The highest score wins. Which score will enable the last participant to win the competition?
9.67
9.65
9.62
9.06
For some reason, the scores your teacher gave you and the answer choices don't match up. I'm not sure why this is. Perhaps some kind of typo. Please double check and get back to me.
A number, y, is equal to the difference of a larger number and 3. The same number is one third of the sum of the larger
number and 9 Which equations represent the situation?
x+y 3 and - 3y -27
Oxxy-3
and-3--
Oy - 3
and-3--27
X-Y-3 and x-3y --9
Answer:
Set the larger number as x"A number, y, is equal to the difference of a larger number and 3."
[tex]y=x-3[/tex]
You can rearrange this equation to find the matching answer choice:
[tex]y-x=-3\\x-y=3[/tex]
"The same number is one third of the sum of the larger number and 9."
[tex]y=\frac{1}{3} (x+9)[/tex]
You can rearrange this equation to find the matching answer choice:
[tex]y=\frac{1}{3} x+3\\3y=x+9\\3y-x=9\\x-3y=-9[/tex]
-2z² + 4z + 2z² = ?
Anyone know this?
Answer:
4
Step-by-step explanation:
Let's simplify step-by-step.
−2z2+4z+2z2
Combine Like Terms:
=−2z2+4z+2z2
=(−2z2+2z2)+(4z)
=4z
Answer:
4z
Hope this helps <3 Need thanks?
Comment /hearthelp
[tex]\\ \sf\longmapsto -2z^2+4z+2z^2[/tex]
Combine like. variables[tex]\\ \sf\longmapsto -2z^2+2z^2+4z[/tex]
[tex]\\ \sf\longmapsto (-2+2)z^2+4z[/tex]
[tex]\\ \sf\longmapsto 0z^2+4z[/tex]
[tex]\\ \sf\longmapsto 4z[/tex]
8 ÷ -2 · 42 + 9 i need help please
Any help would be nice
Answer:
11. angles on a straight line add up to 180
so 180 -133 equal to b.b=47
12.Vertical opposite angles are equal.
therefore b=50
What are the solutions to the system of equations? {y=2x2+6x−10 y=−x+5
Answer:
I think this is mistake because y=2x^2+6x-10 y=x+5 this is the right
1. Write three different solutions of 4x - 2y = 8. plzz answer fast
Answer:
y=-4+2x
x=(4+y)/2
2x-y=4
ABCD is a parallelogram, AE=16, AB=24, EC=2y-4, DE=67, and EB = 2x+7. Solve for x. (Round your answer to one decimal place, if necessary.) Plz help will give brainliest
Answer:
x = 30
Step-by-step explanation:
The diagonals are bisected so DE =EB
67 = 2x+7
Subtract 7
67-7 = 2x+7-7
60 =2x
Divide by 2
60/2 =2x/2
30 = x
PLEASE HELP!!!! I’m about to rip my hair out over this.
1. A ball is thrown into the air at an initial velocity of 18 meters per second from an initial height of 10 meters. The equation that models the path of the ball is given by h=-4.9t^2+18t+10. When does the ball reach its Maximum height?
2. A ball is thrown into the air at an initial velocity of 18 meters per second from an initial height of 10 meters. The equation that models the path of the ball is given by h=-4.9t^2+18t+10. When does the ball hit the ground?
3. A ball is thrown into the air at an initial velocity of 18 meters per second from an initial height of 10 meters. The equation that models the path of the ball is given by h=-4.9t^2+18t+10. How high is the ball at 3 seconds?
4. Logan is doing a handstand dive from a 12 meter platform. The equation that models the path of her dive is given by h=-4.9t^2+12, where t is seconds. At what height will she be after 1 second?
I absolutely hate math with all of my heart.
Step-by-step explanation:
1. The equation graph is a parabola, so the maximum height will be the vertex of the parabola. You can find the vertex coordinate t using the formula:
t = -b/2a
t = -18/2•(-4.9)
t = -18/-9.8
t = 1.84 seconds
2. The height of the ground is 0, so the balls hit the ground when the equation result is 0:
0 = -4.9t²+18t+10
Now you solve it using Bhaskara:
Δ = b² -4ac
Δ = 18² -4•(-4.9)•10
Δ = 520
t = (-b ±√Δ)/2a
t = (-18 ± √520)/2•(-4.9)
t1 = (-18 - 20.8)/-9.8
t1 = 3.96 seconds
t2 = (-18 +20.8)/-9.8
t2 = -0.28
Doesn't exist negative time, so we pick the first value found, t = 3.96 seconds
3. Now you just need to put 3 in place of t to find the result:
h = -4.9•3² +18•3 +10
h = -4.9•9 + 54 + 10
h = -44.1 + 64
h = 19.9 meters
4. You just need to put 1 in place of t to find the height:
h = -4.9•1²+12
h = -4.9+12
h = 7.1 meters
(x-5)^2 - (x+1)^2+ (x+3)*(x-3)
Step-by-step explanation:
here's the answer to your question
You and six friends play on a basketball team. A sponsor paid $100 for the league fee, x dollars for each player’s T-shirt, and $68.25 for trophies. Write an expression for the total amount paid by the sponsor
Answer:
Total amount paid by the sponsor = 175 + 6d
Step-by-step explanation:
You and 5 friends = 6 people
Cost of renting a bus = $75
Team entry fee = $100
Cost of each student t shirts = $d
Cost of 6 student t shirts = $d × 6= $6d
Write an expression for the total amount the sponsor paid.
Total amount paid by the sponsor = Cost of renting a bus + Team entry fee + Cost of 6 student t shirts
= $75 + $100 + $6d
= $175 + $6d
Total amount paid by the sponsor = 175 + 6d
Where,
d = cost of each student t shirts
x^5+x-1
x^5+x-1
x^5+x-1
Step-by-step explanation:
x⁵+x-1
(2x-x+1) ( x³+x²-1 )
HELP ASAP KHAN NEED HELP NOW ITS KHAN
Answer:
[tex]{ \bf{ \green{line \: B}}}[/tex]
It's a direct proportionality
Which graph represents the function f (x) = StartFraction 2 Over x minus 1 EndFraction + 4?
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = negative 4.
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = negative 1, and the horizontal asymptote is at y = negative 4.
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = negative 1, and the horizontal asymptote is at y = 4.
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.
Answer:
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4
Step-by-step explanation:
The given function is presented as follows;
[tex]f(x) = \dfrac{2}{x - 1} + 4[/tex]
From the given function, we have;
When x = 1, the denominator of the fraction, [tex]\dfrac{2}{x - 1}[/tex], which is (x - 1) = 0, and the function becomes, [tex]\dfrac{2}{1 - 1} + 4 = \dfrac{2}{0} + 4 = \infty + 4 = \infty[/tex] therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote
Also we have that in the given function, as x increases, the fraction [tex]\dfrac{2}{x - 1}[/tex] tends to 0, therefore as x increases, we have;
[tex]\lim_ {x \to \infty} \dfrac{2}{(x - 1)} \to 0, and \ \dfrac{2}{(x - 1)} + 4 \to 4[/tex]
Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1
When -∞ < x < 1, we also have that as x becomes more negative, f(x) → 4. When x = 0, [tex]\dfrac{2}{0 - 1} + 4 = 2[/tex]. When x approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left
Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.
Answer:
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4
Step-by-step explanation:
The given function is presented as follows;
From the given function, we have;
When x = 1, the denominator of the fraction, , which is (x - 1) = 0, and the function becomes, therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote
Also we have that in the given function, as x increases, the fraction tends to 0, therefore as x increases, we have;
Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1
When -∞ < x < 1, we also have that as x becomes more negative, f(x) → 4. When x = 0, . When x approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left
Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.
