help help help pls pls

Answer:

254m

Step-by-step explanation:

The setup will be in form of a right triangle. Hence;

The angle of elevation = 64degrees

distance from herself to the base of the castle = 124 meters (Adjacent)

Required

Height of the castle (Opposite)

Using the SOH CAH TOA identity

Tan theta = opp/adj

Tan 64 = H/124

H = 124tan64

H = 124(2.05030)

H = 254.23

H ≈ 254m

Hence the height of the castle to the nearest whole meters is 254metres

Answer:

x = 6

Step-by-step explanation:

x = 3 sin(90) / sin (30)

x = 3(1)/(1/2)

x = 3 ÷ [tex]\frac{1}{2}[/tex]

x = 6

Answer:

A

Step-by-step explanation:

because 3-8= -5

and -2-3=-5

Answer:

1. a) x1 = -8 y x2 = -4

b) x1 = -1/3

2. a) x1 = 0 y x2 = -5

b) x1 = 4 y x2 = -4

3. m debe ser 6. Asi tendriamos (x+3)²=0

4. a) x1 = 4, x2 = -4, x3 = 3 y x3 = -3

b) x1 = 3, x2 = -3 las otras dos raices son complejas.  

Step-by-step explanation:

1. a) [tex]x^{2}+12x+32=0[/tex]

Factorizando:

[tex](x+8)(x+4)=0[/tex]

Entonces: x1 = -8 y x2 = -4

4. a) x1 = 4, x2 = -4, x3 = 3 y x3 = -3

b) [tex]9x^{2}+6x+1=0[/tex]

Factorizando:

[tex](3x+1)(3x+1)=0[/tex]

[tex](3x+1)^{2}=0[/tex]

Entonces: x1 = -1/3

2. a) [tex]2x^{2}+5x=0[/tex]

Aplicando factor comun:

[tex]x(x+5)=0[/tex]

Entonces: x1 = 0 y x2 = -5

b)  [tex]2x^{2}-32=0[/tex]

Despejamos x.

[tex]2x^{2}=32[/tex]

[tex]x^{2}=16[/tex]

Entonces: x1 = 4 y x2 = -4

3. m debe ser 6. Asi tendriamos (x+3)²=0

4. a)  [tex]x^{4}-25x^{2}+144=0[/tex]

Hacemos cambio de variable: [tex]w=x^{2}[/tex]

[tex]w^{2}-25w+144=0[/tex]

Ahara podemos factorizar:

[tex](w-16)(w-9)=0[/tex]  

Usando el cambio de variable nuevamente.

[tex](x^{2}-16)(x^{2}-9)=0[/tex]    

Entonces los valores de x son: x1 = 4, x2 = -4, x3 = 3 y x3 = -3

b)  [tex]x^{4}+9x^{2}-162=0[/tex]

Hacemos cambio de variable: [tex]z=x^{2}[/tex]

[tex]z^{2}+9z-162=0[/tex]

Ahara podemos factorizar:

[tex](z-9)(z+18)=0[/tex]    

Usando el cambio de variable nuevamente.

[tex](x^{2}-9)(x^{2}+18)=0[/tex]            

Entonces los valores de x son: x1 = 3, x2 = -3 las otras dos raices son complejas.  

Espero ye haya servido!

Answer:

w ≈ 33.9 in

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

w² + w² = 48²

2w² = 2304 ( divide both sides by 2 )

w² = 1152 ( take the square root of both sides )

w = [tex]\sqrt{1152}[/tex] ≈ 33.9 in ( to the nearest tenth )

Answer:

(5,-3) in the 4th quadrant

Step-by-step explanation:

Presumably, ln⁵(x) is the same as (ln(x))⁵ (as opposed to a quintuply-nested logarithm, log(log(log(log(log(x)))))).

Then substituting u = ln(x) and du = dx/x gives

[tex]\displaystyle\int\frac{\mathrm dx}{x\ln^5(x)} = \int\frac{\mathrm du}{u^5} = -\frac1{4u^4}+C = \boxed{-\frac1{4\ln^4(x)}+C}[/tex]

Answer:

32:3/4

33:4/3

34:40

35:48

Answer:

A) R=1850-25t

B) 1700

C) 74

Answer:

4 days

Step-by-step explanation:

The time it would take the group of 40 workers to deliver the work, [tex]t_{estimated}[/tex] = 16 days

The number of workers that retired after 4 days = 10 workers

Therefore, the number of workers remaining = 40 - 10 = 30 workers

The time it would take 1 worker to do the work = The number of work days in the construction = 40 × 16 = 640 work days

The amount of work done in 4 days = 40 × 4 = 160 work days

The amount of work remaining after the elapsed 4 days = (640 - 160) work days = 480 work days

The number of days, n, it would take the remaining 30 workers to do the remaining work, is given as follows;

n = 480 work days/(30 workers) = 16 days

The actual total number of work days it took for the work to be delivered, [tex]t_{actual}[/tex] = 4 days + 16 days = 20 days

The number of days delay the construction will be delivered, [tex]t_{delay}[/tex], is given as follows = [tex]t_{actual}[/tex]

[tex]t_{delay}[/tex] = [tex]t_{actual}[/tex] - [tex]t_{estimated}[/tex]

∴ [tex]t_{delay}[/tex] = 20 days - 16 days = 4 days

The number of days delay the construction will be delivered,  [tex]t_{delay}[/tex] = 4 days

Answer:

c. f(-2)= -21

b. g(x)=8

c. h(3)= -19

h(4)= -5

Step-by-step explanation:

Answer:

The width is 5 cm

Step-by-step explanation:

The perimeter of a rectangle is

P = 2(l+w)

Substitute what we know

24 = 2(7+w)

Divide each side by 2

24/2 = 2/2(7+w)

12 = 7+w

Subtract 7 from each side

12-7 = 7+w-7

5 =w

The width is 5 cm

The formula for perimeter = 2 x length  + 2 x width

Fill in the known dimensions:

24 = 2 x 7 + 2 x width

Simplify:

24 = 14  + 2 x width

Subtract 14 from both sides:

10 = 2 x width

Divide both sides by 2:

Width = 5 cm

Answer: Width = 5 cm.

Answer:

It will take him 10 minutes to jog 1 mile.

Step-by-step explanation:

can i have brianliest please

Answer: Choice A

2(2L + L)  = 42

=================================================

Explanation:

The length is L, which is some placeholder for a positive number.

The width is twice as much as this, so it's 2L

The perimeter is found by adding up the four sides (two of which are L, the other two are 2L)

So we have L+L+2L+2L = 2(2L+L) representing the perimeter.

Or we could use this formula

P = 2(L+W)

where L and W are the length and width respectively.

Either way, we end up with 2(2L + L) = 42

Answer:

42 = 2( l+2l)

Step-by-step explanation:

width = 2 length

Perimeter = 2 (l+w)

42 = 2( l+2l)

Divide each side by 2

42/2 = 2 (3l) /2

21 = 3l

Divide by 3

21/3 = 3l/3

7 = l

The length is 7

width is 2*l = 2*7 = 14

Answer:

5.1 cm

Step-by-step explanation:

(Probable) Question;

Given a circle with center O and radius 2.4 cm. P is a point on the tangent that touches the circle at point Q, such that the length of the tangent from P to Q is 4.5 cm. Find the length of OP

The given parameters are;

The radius of the circle with enter at O, [tex]\overline{OQ}[/tex] = 2.4 cm

The length of the tangent from P to the circle at point Q, [tex]\overline{PQ}[/tex] = 4.5 cm

The length of OP = Required

By Pythagoras's theorem, we have;

[tex]\overline{OP}[/tex]² = [tex]\overline{OQ}[/tex]² + [tex]\overline{PQ}[/tex]²

∴ [tex]\overline{OP}[/tex]² = 2.4² + 4.5² = 26.01

[tex]\overline{OP}[/tex] = √26.01 = 5.1

The length of OP = 5.1 cm

Answer:

A is the correct one

cause according to function rule the vertical line should cut only on a one point to be function

as here we can see that vertical line cuts here at two point

Answer:

see above

Step-by-step explanation:

Answer right xa hola

Answer:

-6

Step-by-step explanation:

2n can be the smallest integer, and 2n + 18 will be the largest integer.

The sum of this, divided by two, will result in the average/mean.

(2n + 2n + 18)/2 = 3

Multiply each side by 2:

(2n + 2n + 18)/2 ⋅ 2 = 3 ⋅ 2

2n + 2n + 18  =  6

Combine the like terms:

4n + 18 = 6

Subtract 18 from both sides:

4n + 18 - 18 = 6 - 18

4n = -12

Divide each side by 4:

4n/4 = -12/4

n = -3

Since we decided to go by 2n:

2n = 2(-3) = -6

Answer:

Let the polynomial be f(x) = 5x – 4x^2 + 3

Now, for x = 2,

f(2) = 5(2) – 4(2)^2 + 3

=> f(2) = 10 – 16 + 3 = –3

Or, the value of the polynomial 5x – 4x^2 + 3 at x = 2 is -3.

Similarly, for x = –1,

f(–1) = 5(–1) – 4(–1^)2 + 3

=> f(–1) = –5 –4 + 3 = -6

The value of the polynomial 5x – 4x2 + 3 at x = -1 is -6.

Answered by GAUTHMATH

Answer:

x=2 => 5×2 - 4×2² + 3 = 10-16+3 = -3

x=-1 => 5×-1 - 4×(-1)² + 3 = -5 - 4 + 3 = -6

Step-by-step explanation:

is in the answer.

remember that squaring a negative number creates a positive result.

Answer: The correct answer is in the first option.

Step-by-step explanation:

Equation of an Ellipse

[tex]\dfrac{x^{2} }{a^{2} } +\dfrac{y^{2} }{b^{2} } =1\\\\25x^{2} - 150x + 9y^{2} = 0\\\\\text {Let's \: perform \: the \: transformations:}\\\\\dfrac{25x^{2} }{25 \cdot 9} -\dfrac{150x}{25 \cdot 9} +\dfrac{9y^{2} }{25 \cdot 9} =0\\\\\dfrac{x^{2} }{3^{2} } -\dfrac{6x}{3^{2} } +\dfrac{y^{2} }{5^{2} } =0\\\\\dfrac{x^{2} -6x}{3^{2} } +\dfrac{y^{2} }{5^{2} } +\dfrac{3^{2} }{3^{2} } -\dfrac{3^{2} }{3^{2} } =0\\\\\dfrac{x^{2} -6x+3^{2} }{3^{2} } +\dfrac{y^{2} }{5^{2} } =\dfrac{3^{2} }{3^{2} }[/tex]

[tex]\dfrac{(x-3)^{2} }{3^{2} } +\dfrac{y^{2} }{5^{2} } =1[/tex]

Answer:

The formula to determine the area of the circle.

Step-by-step explanation:

↔

Answer:

A relation but not a function

Step-by-step explanation:

A relation is a relationship between two sets of information ( x and y in this case )

This graph shows a relation as the x and y values share some sort of relationship

A function is a relation in which each input has it's own output.

We can determine if a relation is a function on a graph by using the vertical line test.

If you draw a vertical line and more than 1 point is on that line then the relation is not a function

If we were to draw a vertical line on the y axis there would be three points on that line therefore the relation is not a function

So we can conclude that the picture represents a relation but not a function

Answer:

the third option - they are perpendicular to each other.

Step-by-step explanation:

for a perpendicular slope we need to exchange the x and y values (remember, a slope is the ratio of y/x) and flip the sign.

and that is exactly what happened here.

Answer:

Answer is 90 ways

Step-by-step explanation:

You multiply the members (30) by the number of positions (3) to get your answer

Answer:

polygon is 15 side

Step-by-step explanation:

Here sum of interior angels is 2340 degrees. Therefore, the polygon is 15 side

Step-by-step explanation:

here's the answer to your question

Answer:

[tex]\frac{1}{a^{\frac{-5}{6} } }[/tex]

OAmalOHopeO

Answer:

1. not continuous, as the function definitions deliver different function values at x=1 when approaching this x from the left and from the right side.

2.

2 = a + b

3.

0 = 2a + b

4.

a = -2

b = 4

Step-by-step explanation:

the function is continuous at a specific point or value of x, if the f(x) = y functional value is the same coming from the left and the right side at that point.

1. that means that for x=1

3 - x = ax² + bx

so,

3 - 1 = a×1² + b×1 = a + b

2 = a + b

we have to use a=2 and b=3

2 = 2 + 3 = 5

2 is not equal 5, so the assumed equality is false, so the function is not continuous there.

2. point 1 gave us already the working relationship between a and b.

2 = a + b

only if that is true, is the function continuous at x=1.

3. now for x=2

5x - 10 = ax² + bx

5×2 - 10 = a×2² + b×2 = 4a + 2b

10 - 10 = 4a + 2b

0 = 4a + 2b

0 = 2a + b

4. to find a and b to be continuous at both locations x=1 and x=2 both expressions in a and b must apply.

so, they establish a system of 2 equations with 2 variables.

2 = a + b

0 = 2a + b

a = 2 - b

0 = 2×(2-b) + b = 4 - 2b + b = 4 - b

b = 4

therefore

a = 2 - 4 = -2

5. I cannot draw a graph here.

just use now the function

3 - x, x < 1

‐2x² +4x, 1 <= x < 2

5x - 10, x >= 2

Answer:

A' (9,4)

B' (8,-1)

C' (5,1)

Answered by GAUTHMATH

Answer:

A' = 9,4

B' = 8,-1

C' = 5,1

Step-by-step explanation:

Answer:

see explanation

Step-by-step explanation:

Given f(x) then f(x) + c is a vertical translation of f(x)

• If c > 0 then a shift up of c units

• If c < 0 then a shift down of c units

The graph of g(x) is the graph of f(x) shifted up by 4 units