Help ! ASAP please and thank you !!

9514 1404 393

Answer:

  (x, y) = (3, 12)

Step-by-step explanation:

The first step in any problem solving is to look at the problem. Here, we see that the first equation can be reduced to standard form by dividing it by 2. This would give both terms a coefficient of 1.

We see that the second equation already has a variable with a coefficient of 1.

When solving a system by substitution, it can save some effort if you start by finding a variable with a coefficient of 1 or -1. Since we see that in the second equation, we choose to solve the second equation for y:

  y = 4x . . . . . . . add 4x to both sides of the second equation

Now, we have an expression for y that we can substitute into the first equation.

  2x +2(4x) = 30 . . . . substitute for y

  10x = 30 . . . . . . . . simplify

  x = 3 . . . . . . . . . . divde by 10

  y = 4(3) = 12 . . . . . find y using y=4x

The solution is (x, y) = (3, 12).

__

Additional comment

I doesn't matter what variable gets substituted. The purpose of the exercise is to reduce the number of variables in the equation. Here, we start with an equation that has 2 variables. Substituting for one of them gives an equation with only one variable, a lot easier to solve.

You don't have to find an expression for the "bare" variable. We could solve the second equation for 2x, for example: 2x = y/2, then substitute for 2x in the first equation: y/2 +2y = 30   ⇒   y = (2/5)(30) = 12. Or, we could solve the first equation for 2x and substitute into the second: 2x=30-2y, y-2(2x) = 0 ⇒ y-2(30-2y) = 0 ⇒ y = 60/5 = 12.

The substitution property of equality says you can make any substitution of equal values anywhere. "butter = margarine" means you can substitute butter for margarine, or vice versa, wherever you may wish.

Answer:

3[tex]\sqrt{10}[/tex]

Step-by-step explanation:

Assuming you mean [tex]\sqrt{90}[/tex]

Using the rule of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex] , then

[tex]\sqrt{90}[/tex]

= [tex]\sqrt{9(10)}[/tex]

= [tex]\sqrt{9[/tex] × [tex]\sqrt{10}[/tex]

= 3[tex]\sqrt{10}[/tex]

Answer:

y=0.5x + 5

Step-by-step explanation:

The points are (0,5) and (-10,0)

to find the slope do

0-5/-10-0 = 5/10 = 1/2 = 0.5

next plug one of the points into point slope formula

y-y1=m(x-x1)

lets use the point (-10,0)

y1=0

x1= -10

m= 0.5

y-0=0.5(x- -10)

y = 0.5(x+10)

distribute the 0.5

y=0.5x+5

Answer:

Equation:

2x^2 = 50

Divide by 2:

x^2 = 25

Take the square root:

x = 5, or -5.

Let me know if this helps!

Answer:

x=5

x=−5

Step-by-step explanation:

Answer:

Step-by-step explanation:

When the quadrilateral JKLM is rotated - 270° about the origin then the image of rotated quadrilateral is shown below.

"It is a transformation in which the object is rotated about a fixed point. "

For given question,

Quadrilateral JKLM is rotated - 270° about the origin.

This means, quadrilateral JKLM is rotated 270° clockwise about the origin.

We know, if point P(x, y) is rotated 270° clockwise or 90° anticlockwise then  the coordinated of rotated point would be (-y, x).

From figure, the coordinates of the quadrilateral JKLM are:
J = (3, 3)

K = (5, -5)

L = (-3, -7)

M = (3, -3)

After rotating -270° about the origin the coordinates of the quadrilateral would be,

J' = (-3, 3)

K' = (5, 5)

L' = (7, -3)

M' = (3, 3)

And the image of the rotated quadrilateral J'K'L'M' is shown below.

Therefore, when the quadrilateral JKLM is rotated - 270° about the origin then the image of rotated quadrilateral is shown below.

Learn more about rotation here:

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Answer:

40

Step-by-step explanation:

1+2+3=6

1/6×120=20

2/6×120=40

3/6×120=60

Answer:

rectangle

Step-by-step explanation:

Perimeter of 20 feet

rectangle (square is technically a rectangle):

sides 5 and 5

5*5 = 25ft²

Circle:

20/(2π) = 3.18309...

3.1809...²π = 31.831ft²

Max area of rectangle (i.e. square) has a smaller area than a circle.

Answer:

A and B

Step-by-step explanation:

Both points are in the shaded/blue zone

I hope this helps!

pls ❤ and give brainliest pls

Answer:

Yea both A and B are correct.

Step-by-step explanation:

if you can see you can put (-12,0) inside the shaded triangle also for (-10,1)

you can give brainlist to the person above :D

the function is given, and it's value is where the object is ("how far to the right").

so as long as it rises (going more right), this will be apply.

in the screenshot I graphed the function. of course t is graphed as x and "along the x-axis" is graphed as y, but the pattern is the same anyways.

for the first 1.25 seconds the object goes to the left, and after that always to the right.

since we look at t to calculate x, t effectively takes the role of the important variable that is normally given to x. the calculation pattern are just the same. so let's find the lowest point of this function by calculating it out.

x(t) = 2t² – 5t – 18

x'(t) = 4t -5

x'(t) = 0

0 = 4t -5

5 = 4t

1.25 = t

plugging it into the second derivative

x''(t) = 4

x''(1.25) = 4

it's positive, so at t=1.25 there is a low point

(of course the second derivative is constant anyways.)

the object is traveling toward the right

the object is traveling toward the rightfor t > 1.25

The object is moving to the right, for t > 1.25, the object is moving in a rightward direction.

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

We have:

An object travels along the x-axis so that its position after t seconds is given by:

x(t) = 2t² – 5t – 18

x'(t) = 4t - 5

x'(t) = 0

4t -5 = 0

t = 5/4 = 1.25 seconds

x''(t) = 4

x''(1.25) = 4

x''(1.25) > 0

At t = 1.25 the object travels at a low point.

Thus, the object is moving to the right, for t > 1.25, the object is moving in a rightward direction.

Learn more about the inequality here:

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Answer:

[tex]\displaystyle \int {84} \, dx = 84x + C[/tex]

General Formulas and Concepts:

Calculus

Integration

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int {84} \, dx[/tex]

Step 2: Integrate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Integrations

9514 1404 393

Answer:

  (11, -13)

Step-by-step explanation:

If midpoint M is halfway between A and B:

  M = (A +B)/2

Then B is ...

  B = 2M -A

  B = 2(4, -9) -(-3, -5) = (8+3, -18+5)

  B = (11, -13)

Answer:

Use the midpoint formula:

[tex]midpoint=(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})[/tex]

Substitute in the values:

[tex](4, -9)=(\frac{-3+x_{2}}{2} +\frac{-5+y_{2}}{2} )[/tex]

[tex]4=\frac{-3+x_{2}}{2} \\4(2)=-3+x_{2}\\8+3=x_{2}\\x_{2}=11[/tex]      [tex]-9=\frac{-5+y_{2}}{2} \\(-9)(2)=-5+y_{2}\\-18+5=y_{2}\\y_{2}=-13[/tex]

Therefore, Point B = (11, -13)

Markdown is the difference (at sale) between the price an item is placed at for retail sale, and the actual price the item is sold

The correct option is; B. GHC 50.00

The reason for choosing option B is as follows;

The known parameters

The percentage by which damaged items are marked down = 25% to 40%

The percentage markdown offered by the newspaper coupon = 10%

The original marked price of the item = GHC 100

Strategy:

Apply the damaged items and coupon markdown percentages to the original marked price of GHC100 sum the results to find the total markdown

Solution:

Markdown due to damage:

Given that the item is damaged, to have the lowest price, we apply the largest markdown of 40%;

40% is removed from the price to which the item marked down due to damage, as follows;

The markdown due to damage = 40/100 × GHC 100 = GHC 40

Markdown due to Coupon Holder:

The markdown the coupon holder is to get = 10% off the retail price

Given that the damage is not mentioned in the newspaper, we have;

∴ The markdown the coupon holder is to get = 10/100 × GHC 100 = GHC 10

Total markdown:

The total markdown is therefore equal to GHC 40 + GHC 10 = GHC 50

The Lowest Price of A Damaged Items marked GHC100:

The lowest price of the item = Original price - Maximum markdown

The lowest price of the item = GHC 100 - GHC 50 = GHC 50

Learn more about markdown and markup concepts here;

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answer=

X<-4

.............................................................

Answer:

(-8/7 ; 5/7)

Step-by-step explanation:

5t + 1/2s = 3 - - - (1)

3t - 6s = 9 - - - - - (2)

Multiply (1) by 12 and (2) by 1

Add the result to eliminate s

60t + 6s = 36

3t - 6s = 9

____________

63t = 45

t = 45 / 63

t = 5/7

Put t = 5/7 in either (1) or (2) to obtain the value of s

3(5/7) - 6s = 9

15/7 - 6s = 9

-6s = 9 - 15/7

-6s = (63 - 15)/7

-6s = 48/7

s = 48/7 * - 1/6

s = - 8/7

Answer:

[tex]A\approx 282.7\ m^2[/tex]

Step-by-step explanation:

1. Approach

The easiest method to solve this problem is to use the Pythagorean theorem to find the height of the cone. Then one can substitute the values given and found on the cone into the formula to find the surface area in order to solve for the surface area of the given cone.

2. Height of the cone

Imagine drawing a line from the tip of the cone down to the center of the base. This line will form a right angle with the base, thus, a right triangle is formed between the line, the radius (the distance from the center to the circumference or outer edge on a circle) of the base, and the incline of the cone. The Pythagorean theorem is a formula that relates the sides of a right triangle. This formula is as follows:

[tex]a^2+b^2=c^2[/tex]

Where (a) and (b) are the legs or the sides adjacent to the right angle of the right triangle, and (c) is the hypotenuse or the side opposite the right angle of the right triangle. Substitute the given values into the formula and solve for the unknown, or rather the height of the cone:

[tex]a^2+b^2=c^2[/tex]

[tex]a^2+5^2=13^2[/tex]

Simplify,

[tex]a^2+5^2=13^2[/tex]

[tex]a^2+25=169[/tex]

Inverse operations,

[tex]a^2+25=169[/tex]

[tex]a^2=144[/tex]

[tex]a=12[/tex]

[tex]h=12[/tex]

3. Find the surface area of the cone.

The following formula can be used to find the surface area of a cone:

[tex]A=\pi r(r+\sqrt{h^2+r^2})[/tex]

Where ([tex]\pi[/tex]) represents the numerical value (3.1415...), (r) represents the radius of the base, and (h) represents the height of the cone. Substitute the given values into the formula and solve for the surface area:

[tex]A=\pi r(r+\sqrt{h^2+r^2})[/tex]

[tex]A=\pi 5(5+\sqrt{12^2+5^2})[/tex]

Simplify,

[tex]A=\pi 5(5+\sqrt{12^2+5^2})[/tex]

[tex]A=\pi 5(5+\sqrt{144+25})[/tex]

[tex]A=\pi 5(5+\sqrt{169})[/tex]

[tex]A=\pi 5(5+13)[/tex]

[tex]A=\pi 5(18)[/tex]

[tex]A=\pi 90[/tex]

[tex]A\approx 282.743[/tex]

Answer:

absolutely B

Step-by-step explanation:

A is one type of tax

C) gross pay includes taxes, social security and something else

D) deductions are the type of fee

and B is the amount of money that he received

Alejandro should look at Net pay on his paystubs the answer is Net pay option (b) is correct.

It is defined as the tax rate applied on the solely earned money by a single entity.

It is given that:

Alejandro wants to determine how much money he made in the last month after taxes, social security, and Medicare were taken out of his paycheck.

The options are:

A) Federal tax amount

The Federal tax amount is one type of tax.

C) Gross pay

The gross pay includes taxes, social security, and other charges

D) Deductions

The deductions are the type of fee or negative amounts.

Alejandro should look at Net pay on his paystubs.

Thus, Alejandro should look at Net pay on his paystubs the answer is Net pay option (b) is correct.

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Answer: 1400 packages

Step-by-step explanation:

1150+1200+1900+1350 divided by the 4 day interval means and average of:

1400 packages per day

Answer:

see below

Step-by-step explanation:

7.  We can use the law of sines to solve

sin C         sin B

-------- = ----------

AB              AC

sin 45       sin 32

--------- = ----------

AB            6

Using cross products

6 sin 45 = AB sin 32

6 sin 45 / sin 32 = AB

8.00620 = AB

To the nearest tenth

8.0= AB

9.    We can use the law of sines to solve

sin A         sin B

-------- = ----------

CB              AC

sin A       sin 88

-------- = -----------

13             15

Using cross products

15 sin A = 13 sin 88

sin A = 13/15 sin 88

Taking the inverse sin of each side

sin^-1(sin A) = sin ^-1 (13/15 sin88)

A = 60.01298726

To the nearest tenth

A =60.0

9514 1404 393

Answer:

  108.8 km/h at 84.3°

Step-by-step explanation:

The law of cosines can be used to find the resultant ground speed. In the attached diagram, the length of interest is OR. It will be found as ...

  OR² = OP² +PR² -2·OP·PR·cos(P)

  OR² = 130² +26² -2×130×26×cos(32°) ≈ 11843.19

  OR = √11843.19 ≈ 108.8

__

The angle POR can be found from the law of sines.

  sin(POR)/PR = sin(OPR)/OR

  sin(POR) = PR/OR×sin(32°) ≈ 0.12660

  ∠POR ≈ arcsin(0.12660) ≈ 7.27°

Then the bearing of the ground track of the airplane is 77° +7.27° = 84.27°.

The airplane is traveling at about 108.8 km/h on a bearing of 84.3°.

Answer:

Bc is intersected by segment AD

Answer:

Bc is intersected by segment AD

Step-by-step explanation:

Answer:

The answer is "[tex]7.21 \times 10^{37}[/tex]".

Step-by-step explanation:

[tex]\to ^{n}_{C_r}=\frac{n!}{r!(n-r)!}[/tex]

       [tex]=^{66}_{C_{33}} \times ^{66}_{C_{22}} \times ^{55}_{C_{1}} \\\\=\frac{66!}{33! (66-33)!} \times \frac{66!}{22! (66-22)!} \times \frac{55!}{1! (55-1)!}\\\\=\frac{66!}{33! (33)!} \times \frac{66!}{22! (44)!} \times \frac{55!}{1! (54)!}\\\\=\frac{66!}{33! (33)!} \times \frac{66!}{22! (44)!} \times \frac{55\times 54!}{1! (54)!}\\\\=\frac{66!}{33! (33)!} \times \frac{66!}{22! (44)!} \times 55\\\\= 7219428434016265740 \times 182183167981760400\times 55\\\\[/tex]

       [tex]= 7.21 \times 10^{18} \times 1.82\times10^{17}\times 55\\\\= 7.21 \times 10^{35} \times 1.82\times 55\\\\=721.721 \times 10^{35}\\\\=7.21\times 10^{37}[/tex]

Answer:

106.25km

Step-by-step explanation:

8.5cm = 0.000085km

map:real life

1:1250000

0.000085km : 0.000085km * 1250000 = 106.25km

[tex]\begin{array}{c|c|c|c|c|c} p & q & r & p\land q & q\land \neg p & r \land q \\&&&&\\ T & T & T & T & F & T \\ T & T & F & T & F & F \\ T & F & T & F & F & F \\ T & F & F & F & F & F \\ F & T & T & F & T & T \\ F & T & F & F & T & F \\ F & F & T & F & F & F \\ F & F & F & F & F & F\end{array}[/tex]

An implication A => B is true if either A is false, or both A and B are true. So

[tex]\begin{array}{c|c|c}p\land q & (q\land\neg p) \implies (r\land q) & (p\land q) \implies \big[(q\land\neg p) \implies (r\land q)\big] \\&&\\T & T & \mathbf T\\T & T & \mathbf T\\F & T & \mathbf T\\F & T & \mathbf T\\F & T & \mathbf T\\F & F & \mathbf T\\F & T & \mathbf T\\F & T & \mathbf T\end{array}[/tex]

and the given statement is a tautology.

Answer:

18

thả 5 sao nha.....

Step-by-step explanation:

..................

Answer: a

Step-by-step explanation:

Based on the lines drawn on the given picture, the number of lines of symmetry are D. none.

Lines of symmetry are those that divide a shape such that each side can be said to be a reflection of the other.

In the above image, there are no lines of symmetry because when any of the lines given divides the shape, either side would not be identical.

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Answer:

The answer is "[tex]\frac{5 e^{5\sqrt{x} }}{2\sqrt{x}}[/tex]".

Step-by-step explanation:

Given:

[tex]y = e^{{\color{\red}5}\sqrt{x}}[/tex]

let

[tex]\to t= 5\sqrt{x}\\\\\frac{dt}{dx}= 5 \frac{1}{2\sqrt{x}}\\\\\frac{dt}{dx}= \frac{5}{2\sqrt{x}}\\\\[/tex]

and

[tex]\to y=e^t\\\\\to \frac{dy}{dt}=e^t\\[/tex]

[tex]\to \frac{dy}{dt}=e^{5\sqrt{x} }\\[/tex]

So,

[tex]\to \frac{dy}{dx}= \frac{dy}{dt} \times \frac{dt}{dx}[/tex]

         [tex]=e^{5\sqrt{x} }\times \frac{5}{2\sqrt{x}}\\\\= \frac{5 e^{5\sqrt{x} }}{2\sqrt{x}}[/tex]

OR

[tex]\to g(x) = 5\sqrt{x} \\\\\to f(x) = e^{(x)}\\\\[/tex]

Derivate:  

[tex]\to f''g' = \frac{e^{(5\sqrt{x})}5}{(2\sqrt{x})}[/tex]