Answer:
32m = 640------------------
The rate of typing is 32 words per minute.
For m minutes Hal can type 32m words.
If he types 640 words, we can set this as equation:
32m = 640By solving we get:
m = 20 minutesJerome has three pairs of jeans two pairs of joggers one pair of black pants and one pair of khaki pants it’s your room so likes his pants at random what is the probability he will select jeans or joggers P(jeans or joggers)=
The probability of Jerome selecting jeans or joggers from his collection of pants is 5/7, indicating a high likelihood of choosing either jeans or joggers.
Jerome has a total of 3 pairs of jeans and 2 pairs of joggers. Since the question asks for the probability of selecting jeans or joggers, we need to consider the favorable outcomes, which are the jeans and joggers, and the total number of possible outcomes, which is the total number of pants.
The total number of pants Jerome has is 3 (jeans) + 2 (joggers) + 1 (black pants) + 1 (khaki pants) = 7. Out of these 7 pants, the favorable outcomes are the jeans and joggers, which total 3 (jeans) + 2 (joggers) = 5.
Therefore, the probability of Jerome selecting jeans or joggers can be calculated as the favorable outcomes divided by the total number of outcomes: P(jeans or joggers) = 5/7.
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Which equation represents this problem? Twelve dollars is divided equally among 4 people
The equation that represents the problem of dividing twelve dollars equally among four people is as follows:12 / 4 = 3The given problem of dividing twelve dollars equally among four people can be represented by the equation 12/4 = 3.
Here, 12 represents the total amount of money that is being divided and 4 represents the number of people among whom the money is being divided .In this problem, we divide the total amount of money by the number of people to find out how much money each person will get. As there are four people to divide the money among, we divide the total amount of $12 by 4 to get $3 as the share of each person. Therefore, the equation that represents this problem is 12/4 = 3.
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Directions: Write your answer in the box. Do not use spaces.
Look at the system of equations.
+
y=-x+2
7x+4y=-1
What is the value of y for the solution to this system of equations?
V =
The given system of equations is: y = -x + 27x + 4y = -1. To find the value of y, substitute the value of x from the first equation in the second equation. So, 7x + 4y = -1 can be written as 7(-y + 2) + 4y = -1 ⇒ -7y + 14 + 4y = -1 ⇒ -3y = -15 ⇒ y = 5. Therefore, the value of y for the solution to this system of equations is 5.
In order to solve the given system of equations, we need to first find the values of x and y that satisfy both equations. The system of equations is: y = -x + 27x + 4y = -1. We can use any method, either substitution or elimination, to find the values of x and y. However, in this case, the substitution method would be more convenient because one of the variables has a coefficient of 1. So, we can solve one of the equations for x or y and then substitute that value into the other equation. Let's solve the first equation for x:y = -x + 2 x = -y + 2. Now, substitute this value of x in the second equation and solve for y: 7x + 4y = -1 7(-y + 2) + 4y = -1 -7y + 14 + 4y = -1 -3y = -15 y = 5. Therefore, the value of y for the solution to this system of equations is 5.
The solution to the given system of equations is y = 5.
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Penicillin stars being metabolized by your body as soon as you take it (true ofall medicications). Penicillin is eliminated expenentially. Suppose you receive a 300-mg dose of penicillin to combat strep throat. About 180-mg will remain
active in your blood after 1 day.
Penicillin is an antibiotic drug that is used to treat bacterial infections. The process of eliminating penicillin from the body is an important factor to consider when determining the correct dose of this drug.
This means that the amount of penicillin in the body decreases at a constant rate over time. Suppose a person receives a 300-mg dose of penicillin to combat strep throat. After one day, approximately 180-mg of the drug will remain active in their bloodstream. This is due to the fact that the elimination half-life of penicillin is approximately 1 hour. Therefore, after 1 hour, 150-mg of the drug will remain in the bloodstream. After 2 hours, this amount will decrease to 75-mg, and so on.
The expenential elimination of penicillin from the body is important to consider when determining the frequency and dose of this drug.
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3
Type the correct answer in the box. Use numerals instead of words.
This system of equations has been placed in a matrix:
y= 700x + 200
y= 5,000 - 75x
Complete the matrix by filling
The coefficients of the variables and the constants. [tex]\[\begin{bmatrix}\phantom{-}700 & -1 & \phantom{-}200 \\\phantom{-}75 & -1 & -5000\end{bmatrix}\][/tex].
To complete the matrix, we need to fill in the coefficients and constants from the given system of equations:
The given system of equations:
[tex]\[y &= 700x + 200 \\y &= 5000 - 75x\][/tex]
To complete the matrix, we'll organize the coefficients of the variables and the constants.
[tex]\[\begin{bmatrix}\phantom{-}700 & -1 & \phantom{-}200 \\\phantom{-}75 & -1 & -5000\end{bmatrix}\][/tex]
In the matrix, the coefficients of the variables [tex]\(x\)[/tex] and [tex]\(y\)[/tex] are arranged in the first two columns, and the constants are in the third column.
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Her wealth, power, and ________ were the fuel that would propel him forward.
timidity
scarcity
ambition
inconvenience
The blank in the given statement "Her wealth, power, and ________ were the fuel that would propel him forward" is filled by the term "ambition."
What is scarcity?
Scarcity refers to the limited supply of something. When a resource is in short supply, it becomes scarce. Scarcity is a concept that is often used in economics to explain the situation of insufficient resources to meet demand. Scarcity is a fundamental economic issue, and it is a crucial factor in how markets operate. When there is scarcity, people must decide how to allocate resources based on their own needs and wants.
What is ambition?
Ambition refers to a strong desire to achieve something. Ambition is often characterized by a willingness to work hard, take risks, and overcome obstacles in pursuit of a goal. People who are ambitious are usually driven by a desire to succeed and achieve their full potential. Ambition is an important motivator that drives people to work hard and strive for success in all areas of life.In the given statement "Her wealth, power, and ambition were the fuel that would propel him forward," the term ambition means the strong desire to achieve something.
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Differentiate from the first principle I obtain the gradient of the tangent to the curve
Y=2x2-5x+3 at the point where x=2
In calculus, there are different ways to differentiate the tangent to a curve. The first principle is one of the ways to differentiate the tangent to a curve.
Differentiation is the foundation of calculus, and it's used to find rates of change, maxima and minima, and the behavior of functions in general.The first principle of differentiation.
The first principle is the fundamental approach to finding derivatives, which involves finding the limit of the difference quotient, or f(x + h) – f(x) / h as h approaches zero. This difference quotient represents the slope of the line tangent to the curve at the point (x, f(x)).
The first principle formula for differentiation is given by:lim h → 0 [f(x + h) – f(x) / h]To differentiate the tangent to the curve y = 2x² – 5x + 3 at the point where x = 2 using the first principle, we need to find the slope of the line tangent to the curve at x = 2. We start by finding the equation of the tangent line and then calculate its slope using the first principle.To find the equation of the tangent line, we differentiate the given function, y = 2x² – 5x + 3:dy/dx = 4x – 5At x = 2, dy/dx = 4(2) – 5 = 3.
Thus, the slope of the tangent line at x = 2 is 3.
Now, we can use the point-slope form of the equation of a line to find the equation of the tangent line:
y – f(2) = m(x – 2)y – (2(2)² – 5(2) + 3) = 3(x – 2)y – 4 = 3x – 6y = 3x – 2
This is the equation of the tangent line to the curve
y = 2x² – 5x + 3
at the point where x = 2. The slope of the tangent line is 3.
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What values of p will the equation x^2=p have 0 real number solution why
The equation x^2 = p has 0 real number solution when p is less than or equal to 0. This is because the square of any real number is always non-negative. Therefore, if p is less than or equal to 0, then there is no real number x such that x^2 = p.
For example, if p = -1, then the equation x^2 = -1 has no real number solutions. This is because the square of any real number is always non-negative. Therefore, there is no real number x such that x^2 = -1.
However, if p is greater than 0, then there are two real number solutions to the equation x^2 = p. These solutions are x = sqrt(p) and x = -sqrt(p).
For example, if p = 4, then the equation x^2 = 4 has two real number solutions. These solutions are x = 2 and x = -2.
In conclusion, the equation x^2 = p has 0 real number solution when p is less than or equal to 0. This is because the square of any real number is always non-negative.
Can anyone help me with this? I need this done by today. Please and thank you.
Geometry.
Similarity statements
In geometry, similarity statements are used to indicate that two or more figures are similar. Similarity means that the figures have the same shape but may differ in size. A similarity statement consists of two parts: the corresponding sides and the corresponding angles.
The corresponding sides of similar figures are proportional, which means that the ratio of the lengths of corresponding sides is the same. For example, if we have two similar triangles, we can write their similarity statement as "Triangle ABC ~ Triangle DEF," indicating that the corresponding sides AB/DE, BC/EF, and AC/DF are all in the same ratio.
Similarly, the corresponding angles of similar figures are congruent, meaning that they have the same measure. In the case of our example triangles, the corresponding angles ∠A ≅ ∠D, ∠B ≅ ∠E, and ∠C ≅ ∠F.
By using similarity statements, we can solve various geometric problems. We can use the known ratios of corresponding sides to find missing side lengths, determine scale factors between similar figures, or establish relationships between different parts of the figures.
In conclusion, similarity statements are essential in geometry to express the similarity between figures. They provide a concise way to indicate that corresponding sides are proportional and corresponding angles are congruent. By applying the properties of similarity, we can solve problems involving similar figures and analyze their geometric properties. If you have specific questions or examples you'd like assistance with, please provide them, and I'll be glad to assist you further.
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13.) Jack was making a model volcano for his science project. He had 5
6/10 cups of baking soda in a box. He POURED 3 1/2 cups into the volcano.
How many cups of baking soda are LEFT in the box? *
There are 21/10 fractions of cups of baking soda left in the box. The correct answer is 21/10.
Initially, Jack had 5 6/10 cups of baking soda in the box. He poured 3 1/2 cups into the volcano. To find out how much baking soda is left in the box, we need to subtract the amount poured from the initial amount.
First, let's convert the mixed numbers to improper fractions. The initial amount of baking soda is 5 6/10 cups, which is equivalent to 56/10 cups. The amount poured into the volcano is 3 1/2 cups, equivalent to 7/2 cups.
To subtract fractions, we need a common denominator. In this case, the common denominator is 10. Now, we subtract the fractions: (56/10) - (7/2) = (56/10) - (35/10) = 21/10.
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Thor travels 24 miles per hour. How long does it take him to travel 2 miles? Your answer should be in hours, rounded to the nearest tenth.
Answer:
To calculate the time it takes for Thor to travel 2 miles at a speed of 24 miles per hour, we can use the formula:
Time = Distance / Speed
Given:
Distance = 2 miles
Speed = 24 miles per hour
Plugging these values into the formula, we have:
Time = 2 miles / 24 miles per hour
Calculating this, we get:
Time = 0.08333 hours
Rounding to the nearest tenth, the time it takes for Thor to travel 2 miles is approximately 0.1 hours.
Therefore, it takes Thor approximately 0.1 hours (or 6 minutes) to travel 2 miles at a speed of 24 miles per hour.
A farmer plants a rectangular pumpkin patch in the northeast corner of the square plot land. The area of the pumpkin patch is 600 square meters
A farmer plants a rectangular pumpkin patch in the northeast corner of the square plot land. The area of the pumpkin patch is 600 square meters. If the farmer wants to create the patch twice as long as it is wide, the dimensions of the rectangular pumpkin patch would be 20m by 30m.
Here is how the dimensions of the pumpkin patch are obtained:
Let's assume that the length of the patch is "l" and the width is "w".
The area of the pumpkin patch is given as 600 square meters, which means that:
lw = 600
Given that the length of the patch is twice its width, we can write:
l = 2w
Substituting l in terms of w in the area equation gives:
2w × w = 600
2w² = 600
w² = 300
Taking the square root of both sides:
w = 10√3
Since the length of the patch is twice its width, the length is:
l = 2(10√3) = 20√3
Therefore, the dimensions of the rectangular pumpkin patch are 20m by 30m (20√3 × 10√3).
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Louis drives a taxi cab. He records the total number of miles he travels each week for 15 weeks.
The mean and mean absolute deviation of the data are shown.
Mean: 3,642
Mean absolute deviation: 1,755
Problem
Select all the possible numbers of miles for day 16 that are within the mean absolute deviation.
The possible numbers of miles for day 16 that are within the mean absolute deviation are any values between 1,887 and 5,397 miles, including those two values.
To determine the possible numbers of miles for day 16 that are within the mean absolute deviation, we need to understand the concept of mean absolute deviation and its relationship to the data set.
Given information:
Mean: 3,642 miles.
Mean absolute deviation: 1,755 miles.
Mean absolute deviation (MAD) measures the average distance between each data point and the mean. It provides a measure of dispersion or spread of the data.
To find numbers of miles within the mean absolute deviation, we need to consider values that are within one MAD of the mean.
Calculate the lower and upper limits for day 16:
Lower limit: Mean - MAD = 3,642 - 1,755 = 1,887 miles.
Upper limit: Mean + MAD = 3,642 + 1,755 = 5,397 miles.
Any number of miles for day 16 within the range of 1,887 to 5,397 miles (inclusive) would be within the mean absolute deviation.
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How many total miles does Miguel need to ride on Saturday and Sunday to meet his goal?
15 and three-fifths miles
45 and one-fifth miles
62 and one-half miles
84 and two-fifths miles
Therefore, the closest answer choice to Miguel's goal is 30 miles is 15 miles on Saturday and 15 miles on Sunday.
In conclusion, Miguel needs to ride a total of 30 miles on Saturday and Sunday to meet his goal.
Distance is the total movement of an object without any regard to direction. We can define distance as to how much ground an object has covered despite its starting or ending point.
Miguel plans to ride 30 miles over the weekend, covering 15 miles on each day. In terms of fractions, 15 and three-fifths miles represents 15.6 miles, while 45 and one-fifth miles represents 45.2 miles, 62 and one-half miles represents 62.5 miles, and 84 and two-fifths miles represents 84.4 miles.
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A triangle has two sides of lengths 7 and 9. What value could the length of
the third side be? Check all that apply.
☐A. 10
B. 2
C. 8
OD. 5
E. 13
OF. 22
Three brothers Bob, Dan and Aaron were given $264 to share in the ratio of 2:3:1 respectively. How much money dis Dan receive?
A share in the ratio of 2:3:1 respectively Dan received $132.
To determine how much money Dan received, we need to calculate his share based on the given ratio. The total ratio is 2 + 3 + 1 = 6. To find the fraction that represents Dan's share, we divide his ratio by the total ratio: 3 / 6 = 1/2.
Next, we need to find the amount of money that corresponds to 1/2 of the total sum. We can do this by dividing the total amount of money by the total ratio and multiplying it by Dan's ratio: ($264 / 6) * 3 = $132.
Therefore, Dan received $132 out of the $264 that were shared among the three brothers. The ratio of 2:3:1 implies that Dan's share is three times the value of the smallest ratio, which is 2.
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Given A is the center of circle at (3, -2) , radius is 7 in and m angle E A F equal 135 degree
What is the equation of given circle?
The center of the circle is given as (3, -2) and the radius is given as 7 in. To find the equation of the circle, we can use the standard form equation for a circle, which is (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.
Substituting the given values, we get the equation as:(x - 3)² + (y + 2)² = 7²This is the equation of the given circle. Now, we need to find the measures of angles EAF and EBF. To do this, we can use the fact that the angle subtended by an arc at the center of the circle is twice the angle subtended by it at any point on the circumference.
Hence, we can say that:∠EAF = 1/2(arc EF)∠EBF = 1/2(arc EF)Since arc EF is the arc subtended by the angle EAFEBF, which is equal to the difference of the angles subtended by the same arc at the center of the circle, we can say that:arc EF = 360° - ∠EAFEBF = 360° - ∠EAF - 135°Now, we can substitute the value of arc EF and the measures of ∠EAF and ∠EBF in the above equations to get the values of both angles.
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7th grade math
Paula measured the auditorium and made a scale drawing. The stage, which is 56 feet long in real life, is 84 inches long in the drawing. What scale did Paula use?
3 inches : ____ feet
Paula made a scale drawing of the auditorium, which is a replica of the actual auditorium, but smaller in size. The scale drawing shows measurements of the actual auditorium at a reduced size.
Paula needs to determine the scale used to draw the auditorium. The scale is the ratio of the lengths of the corresponding sides of the actual auditorium and the scale drawing. We can use the following formula to find out the scale of the drawing:
Scale = (Length of the corresponding side of the actual object) / (Length of the corresponding side of the scale drawing)First, we have to convert 56 feet to inches:1 foot = 12 inches56 feet = 56 x 12 = 672 inchesNow, we can find the scale of the drawing as follows:
Now, we can use the scale to determine the length of other parts of the auditorium. For example, if a door in the auditorium is 32 inches long on the drawing, its actual length would be 32 x 8 = 256 inches or 21.3 feet. Therefore, the missing value in the ratio 3 inches : ____ feet is 2.333 feet. (This is obtained by dividing 84 inches by 36 inches, which is equivalent to 3 feet. Then multiplying the result by 3 inches, which gives 7/12 or 0.5833 feet or 7 inches. This can be written as 2.333 feet.)
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Jessica is trying to pack up her apartment and has a wall map that is 11 feet long when she rolls it up. Will it fit diagonally into her storage bin that is 8 feet long, by 6 feet wide, and 2 feet tall.
Given that Jessica has a wall map of length 11 feet and a storage bin with length 8 feet, width 6 feet, and height 2 feet. We have to determine if the wall map can fit diagonally into the storage bin. Diagonal of the storage bin = √(l²+w²+h²)
where l, w, and h are the length, width, and height of the bin respectively. The data collected through a census is used for a variety of purposes, including public policy-making, resource allocation, and research. To ensure that a census provides accurate and reliable data, it is necessary to sample the entire population. This means that every individual in the population must be included in the census sample.
In other words, a census is a complete enumeration of all the people living in a given area. Diagonal of the storage bin = √(8²+6²+2²) = √(64+36+4) = √104 feet Now, the length of the wall map is 11 feet, which is greater than the diagonal of the storage bin. The data collected through a census is used for a variety of purposes, including public policy-making, resource allocation, and research. To ensure that a census provides accurate and reliable data, it is necessary to sample the entire population. So, the wall map won't fit diagonally into the storage bin. Hence, the wall map won't fit diagonally into her storage bin.
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This hyperbola is centered at the origin find its equation. Foci: (0,-9) and (0,9) Vertices: (0,-7) and (0,7)
The equation of the hyperbola centered at the origin, with the given foci (0, -9) and (0, 9), and vertices (0, -7) and (0, 7), is x^2/32 - y^2/49 = 1.
The equation of the hyperbola centered at the origin with the given foci and vertices can be found as follows:
The foci of the hyperbola are located at (0, -9) and (0, 9). The distance between the center of the hyperbola (0, 0) and each focus is 9 units, which gives us the value of c.
The vertices of the hyperbola are given as (0, -7) and (0, 7). The distance between the center and each vertex is 7 units, denoted by a.
In a hyperbola, the distance between the center and each focus is related to the distance between the center and each vertex by the equation c^2 = a^2 + b^2.
Since the center is at the origin, the equation simplifies to c^2 = a^2 + b^2.
Substituting the known values, we have 9^2 = 7^2 + b^2.
Simplifying the equation, we get 81 = 49 + b^2.
By subtracting 49 from both sides, we find b^2 = 32.
Thus, the equation of the hyperbola centered at the origin is x^2/32 - y^2/49 = 1.
In this equation, the squared term with the positive coefficient is associated with the x-axis, while the squared term with the negative coefficient is associated with the y-axis. The center of the hyperbola is at the origin, and its foci and vertices are as given.
Therefore, the equation of the hyperbola centered at the origin, with the given foci (0, -9) and (0, 9), and vertices (0, -7) and (0, 7), is x^2/32 - y^2/49 = 1.
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Maricopa's Success scholarship fund receives a gift of $ 125000. The money is invested in stocks, bonds, and CDs. CDs pay 4. 25 % interest, bonds pay 4. 7 % interest, and stocks pay 7. 3 % interest. Maricopa Success invests $ 40000 more in bonds than in CDs. If the annual income from the investments is $ 6955 , how much was invested in each account?
The amounts invested were approximately:
CDs: $20,000
Bonds: $60,000
Stocks: $45,000
Let's solve this problem by setting up a system of equations.
Let's denote the amount invested in CDs as "x" (in dollars).
Since the investment in bonds is $40,000 more than in CDs, the amount invested in bonds is "x + $40,000".
The remaining amount, $125,000 - (x + (x + $40,000)), is invested in stocks.
Now, we can calculate the annual income from each investment:
CDs: x × 4.25%
Bonds: (x + $40,000) × 4.7%
Stocks: (125,000 - 2x - $40,000) × 7.3%
The sum of these three incomes should equal $6,955:
x × 4.25% + (x + $40,000) × 4.7% + (125,000 - 2x - $40,000) × 7.3% = $6,955
Now, let's solve this equation to find the value of x:
0.0425x + 0.047(x + $40,000) + 0.073(125,000 - 2x - $40,000) = $6,955
Simplifying and solving the equation:
x = $1,130 / 0.0565
x ≈ $20,000
So, approximately $20,000 was invested in CDs.
The amount invested in bonds is x + $40,000:
$20,000 + $40,000 = $60,000
Thus, $60,000 was invested in bonds.
The remaining amount, $125,000 - (x + (x + $40,000)), is invested in stocks:
$125,000 - ($20,000 + ($20,000 + $40,000)) = $125,000 - ($20,000 + $60,000) = $45,000
Therefore, $45,000 was invested in stocks.
In summary, the amounts invested were approximately:
CDs: $20,000
Bonds: $60,000
Stocks: $45,000
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c. Write a piecewise function modeling the car’s elevation over time.
Type your response here:
d. Jacob wants to know the average rate of change of the car’s elevation with respect to time over the time interval [5, 7]. Use the piecewise function you wrote in part c to find this.
Type your response here:
e. Identify an interval over which you will get an average rate of change of elevation with a sign opposite to the one you just found. Justify your answer by solving for that interval.
Type your response here:
f. For the function (x > 10), consider the interval [a, b]. If the starting point of the interval, a, remains fixed and the endpoint, b, keeps extending, what eventually happens to the average rate of change of elevation with respect to time?
Type your response here:
The slope is negative. If we extend the interval [a, b], the average rate of change of the elevation with respect to time will remain constant and equal to -8.
The car's elevation over time is a piecewise function and is shown below:Let h(t) be the elevation of the car at time t. For 0 ≤ t ≤ 5, the function is given by:h(t) = 80t - 16t^2For 5 ≤ t ≤ 7, We have to use the piecewise function to calculate the average rate of change of the car's elevation with respect to time over the interval [5, 7].d.
We'll use the piecewise function below to solve this problem:For 0 ≤ t ≤ 5, the function is given by:h(t) = 80t - 16t^2For 5 ≤ t ≤ 7, the function is given by:h(t) = 5t + 254We'll first calculate the average rate of change of the car's elevation over [5, 7] with respect to time.Using the slope formula to calculate the average rate of change, we obtain:Average Rate of Change = (h(7) - h(5)) / (7 - 5)Note that h(7) = 289 and h(5) = 279.
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Which could be used to solve this equation? 3 and one-fifth n = 9 Subtract 3 and one-fifth from both sides of the equation. 3 and one-fifth minus 3 and one-fifth n = 9 3 and one-fifth Add 3 and one-fifth to both sides of the equation. 9 3 and one-fifth = 12 and one-fifth.
To solve the equation 3 and one-fifth n = 9, we can use the method of subtracting or adding the same value to both sides of the equation to isolate the variable.
In this case, we can subtract 3 and one-fifth from both sides or add 3 and one-fifth to both sides of the equation.
To solve the equation 3 and one-fifth n = 9, we can subtract 3 and one-fifth from both sides of the equation, which gives us:
3 and one-fifth n - 3 and one-fifth = 9 - 3 and one-fifth.
Simplifying the left side of the equation, we get:
n = 9 - 3 and one-fifth.
Alternatively, we can add 3 and one-fifth to both sides of the equation, which gives us:
3 and one-fifth n + 3 and one-fifth = 9 + 3 and one-fifth.
Simplifying the left side of the equation, we get:
n = 9 + 3 and one-fifth.
In either case, we have isolated the variable n and obtained the solution by either subtracting or adding the same value to both sides of the equation.
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15×5-3 +4÷7×3 when Charlie gets 20 apples divide the apples by the answer to the first problem
When Charlie gets 20 apples and divides them by the answer to the first problem, he will get 35/143 of an apple. Firstly, let's solve the expression 15×5-3 +4÷7×3. Using the order of operations, we do the multiplication and division first. 15×5 = 75 and 4÷7×3 = 12/7.
Firstly, let's solve the expression 15×5-3 +4÷7×3. Using the order of operations, we do the multiplication and division first. 15×5 = 75 and 4÷7×3 = 12/7
So, 15×5-3 +4÷7×3 = 75 - 3 + 12/7
Next, we simplify the fraction by finding a common denominator. The common denominator for 7 and 1 is 7, so we multiply the numerator and denominator of 12/7 by 1 to get: 12/7 × 1/1 = 12/7
Now, 75 - 3 + 12/7 = 572/7. Therefore, the answer to the first problem is 572/7. Now, Charlie has 20 apples. If he divides these apples by the answer to the first problem, he will get: 20 ÷ 572/7
We can solve this by multiplying the dividend by the reciprocal of the divisor. In other words, we multiply 20 by 7/572.20 ÷ 572/7 = 20 × 7/572 = 140/572
We can simplify this fraction by finding a common factor of the numerator and denominator. Both 140 and 572 are divisible by 4.140/572 = 35/143
So, when Charlie gets 20 apples and divides them by the answer to the first problem, he will get 35/143 of an apple.
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What is the mode for the data set? 67, 73, 78, 71, 80, 74, 79, 76, 75, 70, 72 67 74 79 80 none.
Mode for the data set is 67, 74, 79, 80. Mode is defined as the most frequently occurring number or the number that appears most often in the data set. In this data set: 67 appears only once, 73 appears only once, 78 appears only once, 71 appears only once, 80 appears twice, 74 appears twice, 79 appears twice, 76 appears only once, 75 appears only once and 70 appears only once.
The mode for the data set is the set of numbers that appear most often. From the set of data, the following numbers are the most frequently occurring: 67, 74, 79, and 80. Therefore, the mode for the given data set is 67, 74, 79, 80.Note: The term "none" at the end of the data set is not considered a numerical value and it does not affect the calculation of the mode.
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Braedyn notices that there are Twenty-One short shelves and 9 tall shelves how can the expression 21 a + 9 B help him find the total number of items on the shelves?
Total number of items = 21a + 9b. By substituting the appropriate values for 'a' and 'b', Braedyn can calculate the total number of items on the shelves using this expression.
The expression 21a + 9b can help Braedyn find the total number of items on the shelves by representing the number of items on each type of shelf and then summing them together. Let's assume that 'a' represents the number of items on each short shelf and 'b' represents the number of items on each tall shelf.
The expression 21a represents the total number of items on all the short shelves, and the expression 9b represents the total number of items on all the tall shelves. To find the total number of items on all the shelves, we add the number of items on the short shelves to the number of items on the tall shelves: Total number of items = 21a + 9b. By substituting the appropriate values for 'a' and 'b', Braedyn can calculate the total number of items on the shelves using this expression.
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The total home attendance for a professional football team in 2010 was about 5.44 × 10^5, and in 2008 was about 4.32 × 10^5. About how many times as large was the attendance in 2010 as the attendance in 2008?
When compared to the number of persons who were there in 2008, the number of people who were present in 2010 was roughly 1.26 times higher.
In 2008, the professional football team's home games averaged an attendance of around 4.32 times 10-5 people. The number of people who attended from their homes reached around 5.44 times 10-5 in the year 2010. We can determine how many times larger the attendance was in 2010 in comparison to 2008 by dividing the number of people who attended in 2010 by the number of people who attended in 2008.
The approximate value that is arrived at after taking 5.44 x 10-5 and dividing it by 4.32 x 10-5 is 1.26. As a direct consequence of this, the total number of individuals who participated in the event in 2010 was roughly 1.26 times more than the total number of people who participated in the event in 2008.
Between the years 2008 and 2010, there was an increase in attendance that was approximately equivalent to a 26 percent increase. Attendance at the professional football team's games has increased, which is a direct reflection of the growing interest in, and support for, the team over the course of the past two years.
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In the past month, Dan rented 1 video game 5 and DVDs. The rental price for the video game was $2.70 . The rental price for each DVD was $4.60 . What is the total amount that Dan spent on video game and DVD rentals in the past month?
Dan spent $25.70 in the past month on video game and DVD rentals.
In the past month, Dan rented 1 video game and 5 DVDs. The rental price for the video game was $2.70, and the rental price for each DVD was $4.60.
Let's calculate the total amount that Dan spent on video game and DVD rentals in the past month.
The cost of renting a video game was $2.70, and Dan rented only one video game.
Total cost of renting one video game is = $2.70
The cost of renting one DVD is $4.60, and Dan rented five DVDs.
Total cost of renting five DVDs is = $4.60 × 5= $23
Therefore, Dan spent $2.70 + $23 = $25.70 in the past month on video game and DVD rentals.
In summary, Dan spent $25.70 in the past month on video game and DVD rentals.
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How many roots the functions have in common? f(x)=x 2 +4x
The function x²+ 4x = 0 has two roots in common with the equation g(x) = 0, which are x = 0 and x = -4.
To find the number of roots that the functions f(x) = x² + 4x and g(x) = 0 have in common, to solve the equation f(x) = g(x).
Setting the two functions equal to each other,
x² + 4x = 0
To solve this quadratic equation, factor out the common factor x:
x(x + 4) = 0
two possible solutions:
x = 0
x + 4 = 0, which gives x = -4
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You and your siblings decided to make 10 pies for a bake sale. There were 8 slices in each apple pie and 10 slices in each shoo-fly pie. At the sale, there were 84 slices available. How many of each pie were made?
4 apple and 6 shoo-fly
2 apple and 8 shoo-fly
6 apple and 4 shoo-fly
8 apple and 2 shoo-fly
To solve this problem, you can use a system of linear equations. Let's let a be the number of apple pies and s be the number of shoo-fly pies.
Then, we can write two equations based on the information given: Equation 1: a + s = 10 (because there were 10 pies made in total)Equation 2: 8a + 10s = 84 (because there were 84 slices available, and each apple pie had 8 slices while each shoo-fly pie had 10 slices)Now we can solve this system of equations. One way to do this is to solve Equation 1 for a (a = 10 - s) and substitute this expression for a in Equation 2.
Then we can solve for s:8a + 10s = 848(10 - s) + 10s
= 8480 - 8s + 10s
= 8480 + 2s
= 842s
= 42 - 80
= -38
we assumed that every slice of pie would be sold at the bake sale. However, there could be slices left over if some pies didn't sell out. Let's call the number of leftover slices L. Then we can write another equation: L = (10a + 10s) - 84L = 10a + 10s - 84L = 10(a + s) - 84L = 10(10) - 84L = 16 Now we can adjust Equation 2 to take this into account: 8a + 10s = 84 - L8a + 10s = 84 - 168a + 10s = -84 Now we can solve for a and s:8a + 10s = -848(10 - s) + 10s = -8480 - 8s + 10s = -84 + 880 + 2s = 4s = 4/2 = 2a = 10 - s = 8Therefore, there were 8 apple pies and 2 shoo-fly pies made.
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