Given the two triangles are similar, what is the value of s? (DO NOT round your answer.)
Answers
Answer:
the value of s is 7.5 ...............
Answer:
s=7.5
Step-by-step explanation:
[tex]\frac{s}{6}=\frac{5}{4}[/tex]
[tex]s=6(\frac{5}{4})=\frac{30}{4} =7.5[/tex]
I hope this help you
Related Questions
Which ratio is equivalent to 7:3?
217
49:9
12: 8
28:12
Answers
Answer:
i think it is 49:9
Step-by-step explanation:
because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9
Answer:
28:12
Step-by-step explanation:
Multiply both 7 and 3 by 4 and you get the ratio 28:12.
Which linear inequality is represented by the graph?
Answers
Answer:
the first option
Step-by-step explanation:
if y varies inversely as n and m = 8 when n = 3 find m whenn =12
Answers
Answer:
24
Step-by-step explanation:
m=8x4 n=3x4 so that is the answer
If f(x) = 7x- 6, which of the following is the inverse of kx)?
Answers
Step-by-step explanation:
[tex]f(x) = 7x - 6[/tex]
[tex] \: [/tex]
Inverse
[tex]y = 7x - 6[/tex]
[tex]x = 7y - 6[/tex]
[tex]x + 6 = 7y[/tex]
[tex]y = \frac{x + 6}{7} [/tex]
[tex] {f}^{ - 1} (x) = \frac{x + 6}{7} [/tex]
Find the value of x.
Answers
Answer:
i think the answer should be 8
Step-by-step explanation:
If the parallel sides of a trapezium are 2 cm apart and their sum is 10 cm then find its area.
Answers
Answer:
[tex] {10cm}^{2} [/tex]Step-by-step explanation:
Given,
Sum of parallel sides of the trapezium = 10 cm
Distance between or Height of the trapezium = 2 cm
As we know,
Area of a trapezium
[tex] = \frac{1}{2} \times (sum \: of \: parallel \: sides) \times height[/tex]
Therefore,
Area of the given trapezium will be,
[tex] = \frac{1}{2} \times 10 \: cm \times 2 \: cm[/tex]
(On Simplification )= 1 × 10 cm × 1 cm
(On multiplying)[tex] = 10 {cm}^{2} [/tex]
Hence,
The Area of the trapezium is 10 sq.cm (Ans)
Given :
The parallel sides of a trapezium are 2 cm apart and their sum is 10 cm.To Find :
Its area.Solution :
We know that,
[tex]{ \qquad \: \pmb{ \dfrac{1}{2} \times (sum \: of \: the \: parallel \: sides) \times height} = \pmb{Area_{(trapezium)}}}[/tex]
Now, Substituting the given values in the formula :
[tex]\qquad { \dashrightarrow \: { \sf{ \dfrac{1}{2} \times 10\: \times 2 \: = {Area_{(trapezium)}}}}}[/tex]
[tex]\qquad { \dashrightarrow \: { \sf{ \dfrac{1}{2} \times 20 = {Area_{(trapezium)}}}}}[/tex]
[tex]\qquad { \dashrightarrow \: { \sf{ \dfrac{20}{2} = {Area_{(trapezium)}}}}}[/tex]
[tex]\qquad { \dashrightarrow \: { \sf{ 10 = {Area_{(trapezium)}}}}}[/tex]
⠀
Hence,
The area of the trapezium = 10 cm² .in your own words explain the phrases "claming first and second place respectively"
Answers
Answer:
If we divide twice the qualifier of Jose by 4 it results in less than 8. What is Jose's highest grade?
Tim worker went to his bank. He deposited $72.15 and the teller credited $5.79 to his account for interest. If Tim's initial balance was $1,226.14, what will his new balance be?
$1,159.78
$1,304.08
$1,148.20
$1,292.50
Answers
add 72.15 to the initial balance, then subtract 5.79
1.) From a group of 8 people, 5 will each win $1,000. How many different winning groups are
possible?
A.) 56
B.) 6720
C.) 168
D.) 336
Answers
Anwser 6720 ways different
Step-by-step explanation:
In this case, we must calculate the different ways using the permutation formula:
nPr = n! / (n - r)!
where n is the total number of people and r would come being the group of person that you want to put together the groups, therefore n = 8 and r = 5
replacing:
8P5 = 8! / (8 - 5)!
8P5 = 6720
That is to say that there are 6720 ways different winning groups are possible
6x - y^2 + 3z ;if x = 4,y = 7,z = 10
Answers
Explanation: You plug in each number for their corresponding variable.
6(4)-(7)^2+3(10) Simplify
24-49+30 Solve
5 Solution
Monique wants to check out as many books by her favorite author as possible. She can check out 3 books at a time from her library, where there are 6 books available written by her favorite author. How many different sets of 3 of these books can Monique choose
Answers
Monique can choose 20 different sets of 3 of the books
What is a combination?The set of books she can select from the library is an illustration of combination (or selection)
The expression that represents combination is represented as:
[tex]^nC_r = \frac{n!}{(n - r)!r!}[/tex]
Where:
The total number of books [tex]n = 6[/tex]The set of books to check out [tex]r = 3[/tex]So, we have:
[tex]^6C_3 = \frac{6!}{(6 - 3)!3!}[/tex]
Evaluate the differences
[tex]^6C_3 = \frac{6!}{3!3!}[/tex]
Evaluate the factorials
[tex]^6C_3 = \frac{720}{6 \times 6}[/tex]
Evaluate the products
[tex]^6C_3 = \frac{720}{36}[/tex]
Divide 720 by 36
[tex]^6C_3 = 20[/tex]
Hence, Monique can choose 20 different sets of 3 of the books
Read more about combination at:
https://brainly.com/question/11732255
Answer:
it is in fact 20 (for khan)
Step-by-step explanation:
credit goes to person above
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Question ~}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Prove that ~
[tex] \dfrac{d}{dx}\sec(x) = \sec(x) \tan(x) [/tex]
by using first principle of differentiation ~
Answers
Answer:
METHOD I:(by using the first principle of differentiation)
We have the "Limit definition of Derivatives":
[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]
Here, f(x) = sec x, f(x+h) = sec (x+h)
Substituting these in eqn. (i)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]
sec x can be written as 1/ cos(x)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]
Taking LCM[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]
By Cosines sum to product formula, i.e.,[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]
=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]
I shifted a 2 from the first limit to the second limit, since the limits ar ein multiplication this transmission doesn't affect the result[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]
2/ h can also be written as 1/(h/ 2)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]
We have limₓ→₀ (sin x) / x = 1.[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]
h→0 means h/ 2→0Substituting 0 for h and h/ 2
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]
sin x/ cos x is tan x whereas 1/ cos (x) is sec (x)[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]
Hence, we got
[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
METHOD II:(by using other standard derivatives)
[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]
sec x can also be written as (cos x)⁻¹We have a standard derivative for variables in x raised to an exponent:
[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]
Therefore,
[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]
Any base with negative exponent is equal to its reciprocal with same positive exponent[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]
The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,
while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.
The inner function that remains is cos x whose derivative is -sin x.[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]
cos²x can also be written as (cos x).(cos x)[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]
sin x/ cos x is tan x, while 1/ cos x is sec x[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]
= sec x. tan x
Hence, Proved!find the slope of the line
Answers
Answer:
3 i belive 100 pecent tho
Step-by-step explanation:
Please help me with this homework
Answers
√54/3, √13, 6, 8, 26/3
150 is 15% of what number
Answers
15 x = 150 * 100
x = 10 * 100
x = 1000
Answer:
1000
Step-by-step explanation:
15 = 15/100 x a
a = 150 ÷ 15/100
a = 150 x 100/15
a = 1000
Is 126 divisible by 3
Answers
Answer:
yes
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
126/3 = 42
If the probability for an event is 1/6,what would that be as a percent rounded to the nearest tenth?
Answers
Answer:
16.7%
Step-by-step explanation:
Putting 1/6 into a calculator gives you 16.67, the question is asking to round the the nearest tenth, so 16.7%.
Using the matrix solver on your calculator, find the solution to the system of
equations shown below.
5x - 4y= 1
4x - 2y = 8
Answers
-4y = 1 -5x
-2y = 0,5 - 2,5x
4x - 0,5 - 2,5x = 8
1,5x = 7,5
x = 5
replaying x for 5:
5x - 4y = 1
25 - 4y = 1
- 4y = 24
4y = 24
y = 6
Answer: x = 5, y = 6
Step-by-step explanation: took the quiz.
Anne goes out to buy lunch every Friday. On average she spends around $18 each time. How much money can she save in one year if she stops going out for lunch each week?
Answers
(Tried my best!)
write a peacewise function for the graph
please help me
Answers
Answer:
[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]
Step-by-step explanation:
If you look at the graph you see that:
before 0, the graph has same y as it has x, or y=x.
after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.
Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.
find the value of x. only type the “number”
Answers
Step-by-step explanation:
5x - 6 = 3x + 2
5x - 3x = 2 + 6
2x = 8
x = 8/2
x = 4
Multiply (x − 4)(x2 + 6x − 5).
x3 + 2x2 − 29x + 20
x3 − 5x2 − 14x + 20
x3 + 6x2 − 13x + 20
x3 + 10x2 − 19x + 20
Answers
Answer:
x3 + 2x2 − 29x + 20
Step-by-step explanation:
x(x2+6x−5)−4(x2+6x−5)
x3+6x2−5x−4(x2+6x−5)
x3+6x2−5x−4x2−24x+20
x3+2x2−5x−24x+20
x3 + 2x2 − 29x + 20
2x2-5x-2 solve by quadratic formula 9leave answers in simplest radical form)
Answers
Answer:
-5x+2
Step-by-step explanation:
1. Multiply number 2 and 2=4 so it is
4-5x-2
2. Combine like terms
-5x+4-2
3. Subtract the numbers
-5x+2
Using the appropriate Algebraic identity evaluate the following:(a²b - c)²
Answers
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
Answer:
Below.
Step-by-step explanation:
(a^2b - c)^2
= (a^2b - c)(a^2b - c)
= a^4b^2 - a^2bc - a^2bc + c^2
= a^4b^2 - 2a^2bc + c^2.
Maddie is packing moving boxes. She has one 3 cubic-foot box and one 6 cubic-foot box. How many cubic feet of clothing can she fit in the two boxes?
Answers
Answer:
She can fit 9 cubic feet of clothing in the two boxes.
Step-by-step explanation:
6 cubic feet + 3 cubic feet = 9 cubic feet.
-Lexi
Answer:
9 ft^3
Step-by-step explanation:
Add together the box capacities: 3 ft^3 + 6 ft^3 = 9 ft^3.
Maddie can pack a total of 9 ft^3 of clothing into these two boxes.
A car is moving at 12 m/s and has a mass of 600 kg. What is the kinetic energy of the car? (Formula: KE = 1/2mv^2) WILL GIVE BRAINLEST
Answers
Answer:
The kinetic energy of the car is 43,200 Joules.
Step-by-step explanation:
KE = (1/2)mv^2
KE = (1/2)(600 kg)(12 m/s)^2
KE = (1/2)(600 kg)(144 m^2/s^2)
KE = 43,200 kg*m^2/s^2 = 43,200 Joules
Answer:
Step-by-step explanation:
KE= 1/2mv^2
KE = 1/2(600) 12^2
KE = 300 * 144 = 43200J
1.) -3x-8=-14
2.) 4x-6=14
3.)-3-3x=-30
4.) -5x+5=5
Answers
4x-6=14 Answer x=5
-3-3x=-30 Answer x=9
-5x+5=5 Answer x=0
Answer:
1.) x = 2
2.) x = 5
3.) x = 9
4.) x = 0
Step-by-step explanation:
1.) -3x - 8 = -14
-3x = -6
x = 2
2.) 4x - 6 = 14
4x = 20
x = 5
3.) -3 - 3x = -30
-3x = -27
x = 9
4.) -5x + 5 = 5
-5x = 0
x = 0
Write the equation for 5x + 2y = 3 in slope-intercept form..
Answers
Answer:
[tex]y=-\frac{5}{2}x+\frac{3}{2}[/tex]
Step-by-step explanation:
[tex]5x+2y=3\\\\2y=-5x+3\\\\y=-\frac{5}{2}x+\frac{3}{2}[/tex]
Answer:
Step-by-step explanation:
Slope-intercept from: y = mx + b
5x + 2y = 3
2y = -5x + 3
Divide the whole equation by 2
[tex]\dfrac{2y}{2}=\dfrac{-5x}{2}+\dfrac{3}{2}\\\\y=\dfrac{-5}{2}x +\dfrac{3}{2}[/tex]
Write 2.04 × 10 ⁴ as an ordinary number
Answers
Answer:
20400
Step-by-step explanation:
its 2.03x10x10x10x10 so first ten: 20.4 and ten: 204 3rd ten: 2040 last ten :20400
What is the 4th equivalent fraction to 1/12?
Answers
Answer:
Where's the Answer? There's No
Hello there!
Remember that equivalent fractions have the same value.
[tex]\frac{1}{2} , \frac{2}{24} ,\frac{3}{36}, \frac{4}{48}[/tex]
Therefore, the 4th equivalent fraction to 1/12 is [tex]\frac{4}{48}[/tex]Hope this helps you!
~Just a felicitous girlie
#HaveASplendidDay
[tex]SilentNature :)[/tex]
