Answer:
-46
Step-by-step explanation:
5 x -10 + 4 = -50 + 4 = -46
solve pls brainliest
Answer:
first put 2 in the numerator for the first blank and 2/9 in the second blank
Step-by-step explanation:
1/3 equals 3/9 and 3/9-1/9=2/9
Answer:
[tex]\frac{3}{9}[/tex]
Step-by-step explanation:
Please help xxxxxxxx
Answer:
a. [tex]\bold{45000\times \:10^7}[/tex]b. [tex]\bold{3500}[/tex]Step-by-step explanation:
a. [tex]\left(5\times \:10^3\right)\left(9\times \:10^7\right)[/tex]
[tex]5\times 10^3 = 5000\\\\5000\times \:9\times \:10^7[/tex]
[tex]\mathrm{Multiply\:the\:numbers:}\:5000\times \:9=45000[/tex]
[tex]=45000\times \:10^7[/tex]
b. [tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)[/tex]
[tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)=\frac{7\times \:10^5}{2\times \:10^2}[/tex]
[tex]\frac{10^5}{10^2} = 10^3[/tex]
[tex]\frac{7\times \:10^3}{2}[/tex]
[tex]\mathrm{Factor}\:\: 10^3 : 2^3\times5^3[/tex]
[tex]\frac{7\times \:2^3\times \:5^3}{2}[/tex]
[tex]\frac{2^3}{2}=2^2[/tex]
[tex]7\times \:2^2\times \:5^3=3500[/tex]
find the value of x. only type the “number”
Step-by-step explanation:
5x - 6 = 3x + 2
5x - 3x = 2 + 6
2x = 8
x = 8/2
x = 4
A car is moving at 12 m/s and has a mass of 600 kg. What is the kinetic energy of the car? (Formula: KE = 1/2mv^2) WILL GIVE BRAINLEST
Answer:
The kinetic energy of the car is 43,200 Joules.
Step-by-step explanation:
KE = (1/2)mv^2
KE = (1/2)(600 kg)(12 m/s)^2
KE = (1/2)(600 kg)(144 m^2/s^2)
KE = 43,200 kg*m^2/s^2 = 43,200 Joules
Answer:
Step-by-step explanation:
KE= 1/2mv^2
KE = 1/2(600) 12^2
KE = 300 * 144 = 43200J
find the value of 4x-6y when x=3 and y= -2
Answer:
here the answer is 24
Step-by-step explanation:
answerrrrrerrr issss hereeeeeee
Answer:
0
Step-by-step explanation:
4 multiply by x(3) = 12
6 multiply by y(2) = 12
12 -12 =0
The diameter of the rear tire of a bike is 34 inches. In low gear, you need to rotate the pedals 3 times to make the rear tire rotate 360° all the way around. How far will you travel in low gear each time you rotate the pedals? (Hint: find the circumference of the tire, then divide it by the number of rotations needed of the pedals.) Round the answer to the nearest hundredth. *
PLEASE DO NOT PUT INAPPROPIATE CONTENT!!!
a radioactive substance has a half-life of 2 seconds. A scientist begins with a sample of 20 grams. How much of the substance remains after 8 seconds?
Answer:
1.25 g
Step-by-step explanation:
you start with 20g at 0 seconds.
divide by half after 2 seconds and you have 10g.
at 4 seconds you have 5g.
at 6 seconds you have 2.5g.
at 8 seconds you have 1.25g.
The size of the substance after 8 seconds will be 1.25 g
What is an expression?The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.
Given that a radioactive substance has a half-life of 2 seconds. A scientist begins with a sample of 20 grams.
Start with 20g at 0 seconds and divide by half after 2 seconds and you have 10g.
4 seconds you have 5g.
6 seconds you have 2.5g.
8 seconds you have 1.25g.
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1.) From a group of 8 people, 5 will each win $1,000. How many different winning groups are
possible?
A.) 56
B.) 6720
C.) 168
D.) 336
Anwser 6720 ways different
Step-by-step explanation:
In this case, we must calculate the different ways using the permutation formula:
nPr = n! / (n - r)!
where n is the total number of people and r would come being the group of person that you want to put together the groups, therefore n = 8 and r = 5
replacing:
8P5 = 8! / (8 - 5)!
8P5 = 6720
That is to say that there are 6720 ways different winning groups are possible
Write in slope-intercept form an equation of the line that passes through the given points. (0,−1),(−8,−2)
What is the 4th equivalent fraction to 1/12?
Answer:
Where's the Answer? There's No
Hello there!
Remember that equivalent fractions have the same value.
[tex]\frac{1}{2} , \frac{2}{24} ,\frac{3}{36}, \frac{4}{48}[/tex]
Therefore, the 4th equivalent fraction to 1/12 is [tex]\frac{4}{48}[/tex]Hope this helps you!
~Just a felicitous girlie
#HaveASplendidDay
[tex]SilentNature :)[/tex]
Write 2.04 × 10 ⁴ as an ordinary number
Answer:
20400
Step-by-step explanation:
its 2.03x10x10x10x10 so first ten: 20.4 and ten: 204 3rd ten: 2040 last ten :20400
help!! !,
is it right or not
Answer:
No
Step-by-step explanation:
The answer is to find the sum of each number, because factors are pulling out from total numbers, but when multiplying you don't need to pull out anything so it would be number
Yep!!! Your correct
Write two Pythagorean triplets each having one of the numbers as 5.
Answer:
3, 4, 5 and 5, 12, 13
Step-by-step explanation:
The square of the largest side is equal to the sum of the squares of the other 2 sides.
5² = 3² + 4²
13² = 5² + 12²
The 2 triplets are (3, 4, 5 ) and (5, 12, 13)
2x2-5x-2 solve by quadratic formula 9leave answers in simplest radical form)
Answer:
-5x+2
Step-by-step explanation:
1. Multiply number 2 and 2=4 so it is
4-5x-2
2. Combine like terms
-5x+4-2
3. Subtract the numbers
-5x+2
If we convert 0.14 x10^3 to scientific notation, which direction should the
decimal move and how spaces should it move?
Answer:
Move it to the right by 3 spaces.
Step-by-step explanation:
10^3 is 1000
On a number line the negative numbers are on the left and the positive numbers are on the right. So since the exponent is a positive 3 we move it to the right by 3 spaces to get 140
Which ratio is equivalent to 7:3?
217
49:9
12: 8
28:12
Answer:
i think it is 49:9
Step-by-step explanation:
because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9
Answer:
28:12
Step-by-step explanation:
Multiply both 7 and 3 by 4 and you get the ratio 28:12.
1. Which of the following equations is equivalent to y = ? 048 = 7x - 21 28 = 12x - 36 O 4x - 3 = 84 O4x - 12 = 84
Answer:
4x - 12 = 84
Step-by-step explanation:
The last answer choice is correct because when you cross-multiply:
[tex]4(x-3) = 12(7)[/tex] [tex]4x - 12 = 84[/tex]you get 4x - 12 = 84.
Therefore, the last option is correct.
Answer:
D would be the answer (4x-12=84)
Step-by-step explanation:
4/7=12/x-3
=>1/7=3/x-3
=>x-3=21
Multiplying both sides by 4
4(x-3)=4x21
=>4x-12=84
Hope this helped :)
Which best describes the error in finding the area of the parallelogram?
15 meters was used for the height instead of 13 meters.
15 meters was used for the height instead of 13 meters.
8 meters was used for the height instead of 13 meters.
8 meters was used for the height instead of 13 meters.
The product of 8 and 15 is not 120.
The product of 8 and 15 is not 120.
The formula to use should have been A=12bh instead of A=bh.
The formula to use should have been, cap A is equal to 1 half b h instead of cap A is equal to b h.
Question 2
Correct the error.
A=
=
m2
Answer:
104
Step-by-step explanation:
write a peacewise function for the graph
please help me
Answer:
[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]
Step-by-step explanation:
If you look at the graph you see that:
before 0, the graph has same y as it has x, or y=x.
after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.
Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Question ~}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Prove that ~
[tex] \dfrac{d}{dx}\sec(x) = \sec(x) \tan(x) [/tex]
by using first principle of differentiation ~
Answer:
METHOD I:(by using the first principle of differentiation)
We have the "Limit definition of Derivatives":
[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]
Here, f(x) = sec x, f(x+h) = sec (x+h)
Substituting these in eqn. (i)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]
sec x can be written as 1/ cos(x)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]
Taking LCM[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]
By Cosines sum to product formula, i.e.,[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]
=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]
I shifted a 2 from the first limit to the second limit, since the limits ar ein multiplication this transmission doesn't affect the result[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]
2/ h can also be written as 1/(h/ 2)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]
We have limₓ→₀ (sin x) / x = 1.[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]
h→0 means h/ 2→0Substituting 0 for h and h/ 2
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]
sin x/ cos x is tan x whereas 1/ cos (x) is sec (x)[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]
Hence, we got
[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
METHOD II:(by using other standard derivatives)
[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]
sec x can also be written as (cos x)⁻¹We have a standard derivative for variables in x raised to an exponent:
[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]
Therefore,
[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]
Any base with negative exponent is equal to its reciprocal with same positive exponent[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]
The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,
while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.
The inner function that remains is cos x whose derivative is -sin x.[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]
cos²x can also be written as (cos x).(cos x)[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]
sin x/ cos x is tan x, while 1/ cos x is sec x[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]
= sec x. tan x
Hence, Proved!if y varies inversely as n and m = 8 when n = 3 find m whenn =12
Answer:
24
Step-by-step explanation:
m=8x4 n=3x4 so that is the answer
9. 2 less than 3 times a number is the same as 2114. What is the number?
Enter your answer as a decimal or simplified mixed number in the box. The number is.
Answer:
705.3 repeated I don't know if that's what you want but
3 times of 705.33 and 2 subtracted is equal to 2114.
What is Simplification?Simplification in mathematical terms is a process to convert a long mathematical expression in simple and easy form.
Given that,
2 less than 3 times a number equal to 2114.
Let the required number is x.
According to given condition,
3x - 2 = 2114
3x = 2114 + 2
3x = 2116
x = 2116 / 3
x = 705.33
The required number is 705.33.
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The Sydney Harbour Bridge is approximately 1200 metres long. A model of the bridge is built with a scale of 1:6000. What is the length of the model?
Pick one:
5cm
20cm
200cm
720cm
Answer:
20cmStep-by-step explanation:
The Sydney Harbour Bridge is approximately 1200 metres long. A model of the bridge is built with a scale of 1:6000. What is the length of the model?
Pick one:
5cm
20cm
200cm
720cm
--------------------
scale = 1:6000
so
1200 : 6000 = 0.2m
0.2m = 20 cm
Answer:
20cm
Step-by-step explanation:
«A scale of 1:6000» means the model is smaller than the bridge by a factor of 6000. We can also make up a proportion [tex]\dfrac{1}{6000}=\dfrac{x}{1200}[/tex], where the left side is the scale, x is the model length, 1200 is the bridge length (in meters). So, finding x or just dividing 1200 by 6000, we get 0.2 meters. Provided 1 m = 100 cm, 0.2 m is 0.2 × 100 = 20 cm.
work out 4 1/2 - 1 1/3
Answer:
3 1/6
brainliest?
w + 12 = 20 *
ANSWER ASAP PLS
Answer:
the nwser is 8 please mark brainliest
Step-by-step explanation:
Three partners are investing a total of $900,000 to open a garden and landscaping store. Their investments are in the ratio of 2:3:5. .
Find the value if f(x) = -3x -8 and g(x) = x2 + 3. f(-3) =
Step-by-step explanation:
f(x) = -3x - 8
f(-3) = -3(-3) - 8
f(-3) = 9 - 8
f(-3) = 1
50 POINTS PLS HELP ME I'LL MARK BRAINLIEST
Find a polynomial of degree n that has only the given zeros. (There are many correct answers.)
x = −3, 8; n = 3
Thank you so much!!
Answer:
Step-by-step explanation:
Here we need to find a 3rd degree polynomial that has only two distinct zeros: {-3, 8}.
Focusing on the zero x = 8 and assuming that this 8 has a multiplicity of 2, we come up with the following polynomial in which the factor x - 8 shows up twice:
f(x) = a(x - 8)(x - 8)(x + 3), or f(x) = a(x - 8)^2(x + 3)
One such polynomial is thus
f(x) = a(x - 8)^2(x + 3), where 'a' is a constant coefficient. This polynomial has a double zero at x = 8 and a third zero at x = -3.
Step-by-step explanation:
The polynomial has degree 3 and two zeros: - 3 and 8.
Since it has degree 3 it should have 3 zero's.
Two possible scenarios
1. -3 has multiplicity of two:
a(x + 3)²(x - 8) - is the factored form of the polynomial where a is the constant2. 8 has multiplicity of two:
a(x + 3)(x - 8)² - is the factored form of the polynomialWhich of the following tables does not represent a function?
x y
-1 1
-2 1
-3 1
x y
-5 1
-5 -2
-5 -5
x y
-4 0
2 0
5 7
x y
-5 1
-3 -2
-1 -5
Step-by-step explanation:
the second one (with the -5 as x values) is not a function, because the valid x value -5 has more than one associated different solution value y.
for a function a valid x value can lead only to exactly one result y value.
Solve for x x^2 + 6x + 1 = 0
Answer:
x = -.1715 ≈ - .172 or x = -5.83
Step-by-step explanation:
x² + 6x + 1 = 0
x² + 6x = -1
Complete the square Add to both sides (1/2 of the x-term, then square it.)
x² + 6x + 9 = -1 + 9
(x + 3)(x + 3) = 8
(x + 3)² = 8
[tex]\sqrt{(x + 3)^{2}[/tex] = [tex]\sqrt{8}[/tex]
x + 3 = ± [tex]\sqrt{8}[/tex]
x = -3 ± [tex]\sqrt{8}[/tex]
x = -3 + [tex]\sqrt{8}[/tex] or x = -3 - [tex]\sqrt{8}[/tex]
x = -.1715 ≈ - .172 or x = -5.83