Given: -1/2x > 6. Choose the solution set. A {x | x R, x > -12} B{x | x R, x > -3} C{x | x R, x < -3}D {x | x R, x < -12}

Answer:

the slope of the line x+y = 6 is -1.

Step-by-step explanation:

slope = - coefficient of x

----------------------

coefficient of y

slope = -1 /1

slope = -1

Answer:

A: -1

Step-by-step explanation:

Answer: -10 points

Step-by-step explanation:

She lost 110,so that loss -the gain(100) is the total score at the end of three games

Answer:

31° change

Step-by-step explanation:

If we want to find the change between two numbers, we need to imagine it like a number line.

<-------------0------------->

Let's plot -7 and 24 on this number line.

<----------[tex]-7[/tex]--0------------24>

If we want to get from -7 to 0, we increase by 7. To get from 0 to 24, we increase by 24.

So the total change is [tex]7 + 24 = 31[/tex].

Hope this helped!

Answer:

by tracking data of how much money was made on one product in a certain amount of time

Step-by-step explanation:

Answer:

The vertex is (3,4)

Step-by-step explanation:

f (x) = x^2 - 6 x + 13

Completing the square

-6/2 = -3 and squaring it = 9

    = x^2 -6x +9 +4

   = ( x-3) ^2 +4

The equation is now in vertex form

a( x-h) ^2 +k

where the vertex is ( h,k)

The vertex is (3,4)

Answer:

C on edge

Step-by-step explanation:

Answer:

        4hx - 8x - 3h - 4

k  =  ------------------------

                  5

            8x + 5k + 4

h  =  ------------------------

              4x - 3

Step-by-step explanation:

4 (hx - 1) - 3 (x + h) = 5 (x + k)

4hx - 4 - 3 (x + h) = 5 (x + k)

4hx - 4 - 3x - 3h = 5 (x + k)

4hx - 4 - 3x - 3h = 5x + 5k                   add 3h both sides

4hx - 4 - 3x - 3h + 3h = 5x + 5k + 3h   simplify

4hx - 4 - 3x = 5x + 5k + 3h                   add 4 both sides

4hx - 4 - 3x + 4 = 5x + 5k + 3h + 4       simplify

4hx - 3x = 5x + 5k + 3h + 4                  subtract 5x from both sides

4hx - 3x - 5x = 5x + 5k + 3h + 4 - 5x   simplify

4hx - 8x = 5k + 3h + 4                          

4hx - 8x - 3h - 4 = 5k  

      4hx - 8x - 3h - 4

k  =  ------------------------

                5

solving for h;

4hx - 3h = 8x + 5k + 4

h(4x - 3) = 8x + 5k + 4

          8x + 5k + 4

h  =  ------------------------

            4x - 3

The value of h and k are h = (8x + 5k + 4) / (4x - 3) and k = (4hx - 8x - 3h - 4) / 5 respectively

Given:

4 (hx - 1) -3 (x +h) ≡ 5 (x + k)

open parenthesis

4hx - 4 - 3x - 3h = 5x + 5k

4hx - 4 - 3x - 3h - 5x - 5k = 0

4hx - 8x - 3h - 5k - 4 = 0

For k

4hx - 8x - 3h - 4 = 5k

[tex]k = (4hx - 8x - 3h - 4) / 5[/tex]

For h

4hx - 8x - 3h - 5k - 4 = 0

4hx - 3h = 8x + 5k + 4

h(4x - 3) = 8x + 5k + 4

[tex]h = (8x + 5k + 4) / (4x - 3)[/tex]

Therefore, the value of h and k are h = (8x + 5k + 4) / (4x - 3) and k = (4hx - 8x - 3h - 4) / 5 respectively

Read more:

https://brainly.com/question/21406377

Answer:

-3

Step-by-step explanation:

-7+4=-3

The absolute value of -3 is 3

The negative sign in front of the absolute value bracket makes it -3

Answer:

LOOK BELOW

Step-by-step explanation:

I would not call the explanation a formula

All you have to do to solve mean or average is add all of the numbers up and divide by the total amount of numbers

so for example

0,2,4,0,2,3,2,8,6  <-------- lets find the mean/average

0+2+4+2+3+2+8+6= 27/amount of numbers

amount of numbers=9

(count the zeros too!)

27/9=3

3 is the mean or average!!!

Answer: 5 (7.50-3 )

Step-by-step explanation:

Given: Previous price of calculator = $7.50

Number of client =5

Total price = (Number of calculators) x (Price for each calculator)

Total price of 5 calculators = (5 x $7.50)

New price of calculator = $5.00

Number of client =3

Total price of 3 calculators  = (3 x $5)

Price will receive = (Total price of 5 calculators) -(Total price of 3 calculators  )

= (5 x $7.50) -  (3 x $5)

= 5 (7.50-3 )

Required expression: 5 (7.50-3 )

Answer:

[tex]1035[/tex]

Step-by-step explanation:

(63756×60)/(70×5280)

=1035

Answer:

28 - 10 - 15 - 3

=> 18 - 15 - 3

=> 3 - 3

=> 0

Another way:

=> 28 - 10 - 15 - 3

=> 28 - 25 - 3

=> 28 - 28

=> 0

Answer:

1 and 11/15.

Step-by-step explanation:

To solve, we can separate the integers from the fractions.

(6 - 4) + (2/5 - 2/3)

= 2 + (6/15 - 10/15)

= 2 + (-4/15)

= 1 + 15/15 - 4/15

= 1 + 11/15

= 1 and 11/15

Hope this helps!

Answer:

3x and 9y and -31 is the correct answer if you are bloviating.

Step-by-step explanation:

bloviate the factors of x and y.

Answer:

8, 19

Step-by-step explanation:

let group 1 have x students and group 2 have y students

x + y = 27

but group 2 has 2x + 3 students

the sum of students from both groups is 27

x + 2x + 3 = 27

3x + 3 = 27

3x = 24

x = 8

y = 2x + 3

y = 19

===========================================

Explanation:

Refer to the diagram below.

In order for triangle TOP to be isosceles, the missing side x must be either 5 or 7. This way we have exactly two sides that are the same length.

--------

If TP = 5, then the value of y could be either 5 or 11 to ensure that triangle TIP has exactly two sides the same length.

If TP = 7, then y = 7 or y = 11 for similar reasons.

--------

Therefore, the possible lengths for segment TO are 5, 7, and 11.

Answer:

7, 11

Step-by-step explanation:

its right- trust me-

Answer:

[tex]l = 28[/tex]

Step-by-step explanation:

Given

[tex]S = \sum (2k - 3); k = 4\ to\ l[/tex]

Required

What is l when S = 725

This can be solved using Sum of n terms of an AP;

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

Where

[tex]S_n = 725[/tex]

[tex]T_1 = first\ term[/tex]

To get T1; we substitute 4 for k in 2k - 3

[tex]T_1 = 2 * 4 - 3[/tex]

[tex]T_1 = 8 - 3[/tex]

[tex]T_1 = 5[/tex]

[tex]T_n = last\ term[/tex]

To get Tn; we substitute l for k in 2k - 3

[tex]T_n = 2 * l - 3[/tex]

[tex]T_n = 2l - 3[/tex]

n = the number of terms;

Since k = 4 to l, then

[tex]n = l - 4 +1[/tex]

[tex]n = l - 3[/tex]

Substitute these values in [tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

[tex]725 = \frac{l-3}{2}(5 + 2l - 3)[/tex]

Collect Like Terms

[tex]725 = \frac{l-3}{2}(2l + 5- 3)[/tex]

[tex]725 = \frac{l-3}{2}(2l + 2)[/tex]

Open the bracket

[tex]725 = \frac{l-3}{2} * 2l + \frac{l-3}{2} * 2[/tex]

[tex]725 = (l-3) * l + (l-3)[/tex]

[tex]725 = l^2-3l + l-3[/tex]

[tex]725 = l^2-2l -3[/tex]

Subtract 725 from both sides

[tex]725 - 725 = l^2-2l -3 - 725[/tex]

[tex]l^2-2l -3 - 725 = 0[/tex]

[tex]l^2-2l - 728 = 0[/tex]

[tex]l^2 + 26l - 28l - 728 = 0[/tex]

[tex]l(l + 26) - 28(l + 26) = 0[/tex]

[tex](l - 28)(l + 26) = 0[/tex]

[tex]l - 28 = 0[/tex] or [tex]l + 26 = 0[/tex]

[tex]l = 28[/tex] or [tex]l = -26[/tex]

But l must be positive;

Hence, [tex]l = 28[/tex]

Answer:

[tex]\huge\boxed{Mass = 11600\ kg}[/tex]

Step-by-step explanation:

Given:

Density = ρ = 2900 kg/m³

Volume = V = 4 m³

Required:

Mass = m = ?

Formula:

Mass = Density × Volume

Solution:

Mass = 2900 * 4

Mass = 11600 kg

Answer:

Number of push up = 8 + 2x

Step-by-step explanation:

Keenan can do 8 push ups each day. He plans to do 2 extra day until he is doing 30 push ups. Each day he does an additional 2 push up, on the first day he does 8 + 2 = 10 push up, on the second day he does 10 + 2 = 12 push ups. This can be represented by the expression:

Number of push up = 8 + 2x

where x is the number of days.

To do 30 push ups, we can calculate the number of days needed:

30 = 8 + 2x

2x = 30 - 8

2x = 22

x = 11

Answer:

8+2x its from khan academy

Step-by-step explanation:

give person above brainliest :)

Hi there! :)

Answer:

[tex]\huge\boxed{x = 3}[/tex]

Given the equation:

[tex]3(11)^{x} = 3993[/tex]

Divide both sides by 3:

[tex](11)^{x} = 1331[/tex]

Rewrite both sides of the equation with a base of 11.

[tex]1331 = 11^{3}[/tex], therefore:

[tex](11)^{x} = 11^{3}[/tex]

x = 3.

Answer:

121

Step-by-step explanation:

121 x 33 = 3993

Answer:

122

Step-by-step explanation:

5!=5 x 4 x 3 x 2 x 1 = 120

2!=2 x 1 = 2

120+2=122

Answer:

6. No. See explanation below.

7. 18 months

8. 16

Step-by-step explanation:

6. To rewrite a sum of two numbers using the distributive property, the two numbers must have a common factor greater than 1.

Let's find the GCF of 85 and 99:

85 = 5 * 17

99 = 3^2 + 11

5, 3, 11, and 17 are prime numbers. 85 and 99 have no prime factors in common. The GCF of 85 and 99 is 1, so the distributive property cannot be used on the sum 85 + 99.

Answer: No because the GCF of 85 and 99 is 1.

7.

We can solve this problem with the lest common multiple. We need to find a number of a month that is a multiple of both 6 and 9.

6 = 2 * 3

9 = 3^2

LCM = 2 * 3^2 = 2 * 9 = 18

Answer: 18 months

We can also answer this problem with a chart. We write the month number and whether they are home or on a trip. Then we look for the first month in which both are on a trip.

Month                Charlie          Dasha

1                          home             home

2                          home             home

3                          home             home

4                          home             home

5                          home             home

6                         trip                home

7                          home             home

8                          home             home

9                          home             trip

10                         home             home

11                         home             home

12                         trip               home

13                         home             home

14                         home             home

15                         home             home

16                         home             home

17                         home             home

18                         trip                 trip

Answer: 18 months

8.

First, we find the prime factorizations of 96 an 80.

96 = 2^5 * 3

80 = 2^4 *5

GCF = 2^4 = 16

Answer: 16

Answer:

16. 1 miles

Step-by-step explanation:

Using Pythagorean Theorem,

a^2 + b^2 = c^2

Since the road that goes from his home to work directly is c^2...

Plug in the rest of the numbers

16^2 + 2^2 = c^2

256 + 4 = c^2

260 = c^2

The reverse square of 260 is

16. 1 miles

Answer:

1

Step-by-step explanation:

We will use x instead of theta

● cos^2 x *(1+tan^2x)

We khow that: 1+ tan^2 x = 1/cos^2 x

Replace 1+tan^2 x by the new expression

● cos^2 x (1/cos^2 x)

● cos^2x/ cos^2 x

● 1

Answer:

The total duration of the trip is 48 hours.

Step-by-step explanation:

Let suppose that ship travels at constant speed during its travel. Each stage is represented by the following kinematic equation:

[tex]v =\frac{\Delta s}{\Delta t}[/tex]

Where:

[tex]\Delta s[/tex] - Travelled distance, measured in kilometers.

[tex]\Delta t[/tex] - Time, measured in hours.

[tex]v[/tex] - Speed, measured in kilometers per hour.

Now, each stage is represented by the following expressions:

Outbound trip

[tex]v = \frac{700\,km}{\Delta t}[/tex]

Return trip

[tex]v + 10\,\frac{km}{h} = \frac{700\,kh}{\Delta t - 8\,h}[/tex]

By eliminating [tex]v[/tex] and simplifying the resulting expression algebraically:

[tex]\frac{700\,km}{\Delta t} + 10\,\frac{km}{h} = \frac{700\,km}{\Delta t -8\,h}[/tex]

[tex](700\,km)\cdot \left(\frac{1}{\Delta t - 8\,h}-\frac{1}{\Delta t} \right) = 10\,\frac{km}{h}[/tex]

[tex]\frac{1}{\Delta t - 8\,h}-\frac{1}{\Delta t} = \frac{1}{70}\,\frac{1}{h}[/tex]

[tex]\frac{8\,h}{\Delta t \cdot (\Delta t-8\,h)} = \frac{1}{70}\,\frac{1}{h}[/tex]

[tex]560\,h^{2} = \Delta t\cdot (\Delta t - 8\,h)[/tex]

[tex](\Delta t )^{2}-8\cdot \Delta t - 560 = 0[/tex]

This equation can be solved by means of the Quadratic Formula, whose roots are presented below:

[tex]\Delta t_{1} = 28\,h[/tex] and [tex]\Delta t_{2} = -20\,h[/tex]

Only the first roots offers a physically resonable solution. Then, total duration of the trip is:

[tex]t_{T} = 28\,h +20\,h[/tex]

[tex]t_{T} = 48\,h[/tex]

The total duration of the trip is 48 hours.

Answer:

v = -54

Step-by-step explanation:

27= -v/2

Multiply each side by -2

27 *-2= -v/2 *-2

-54 = v

Answer:

-54

Step-by-step explanation:

[tex]27=\frac{-v}{2}[/tex] .... Equation to start with

[tex]27 x 2= \frac{-v}{2} x2[/tex] ..... Cancelling out the denominator and multiplying on the other side

[tex]54 = -v[/tex] .... Multipling

[tex]-54 =v[/tex] ..... Solving for v, not -v, so bring the negative over to the other side

Hope you understood:)

Answer:

-3.5

Step-by-step explanation:

The problem you have stated is (y-z)/z where y=-2 and z = 4/5. To solve, substitute the values of y and z into the problem. Then, you have (-2-4/5)/4/5. (-2-4/5) simplifies to -14/5 so then you have (-14/5)/4/5. To divide, multiply -14/5 by 5/4 {multiplying by the reciprocal}. That equals -70/20 which is equal to -3.5

Answer:

[tex]\large\boxed{-3.5}[/tex]

Step-by-step explanation:

(y - z) ÷ z          y = -2 and z = 4/5

Substitute in the given values for y and z into the equation

(y - z) ÷ z  

(-2 - 4/5) ÷ 4/5

Subtract inside the parenthesis (-2 - 4/5)

-2.8 ÷ 4/5

Convert 4/5 into a decimal (in this case that can be done by multiplying both the numerator and denominator by 20)

4/5 = (4 * 20) / (5 * 20) = 80 / 100

80 / 100

Divide numerator and denominator by 10

8/10 = 0.8

Substitute into previous equation

-2.8 ÷ 4/5 = -2.8 ÷ 0.8

Divide

[tex]\large\boxed{-3.5}[/tex]

Hope this helps :)

Answer: Angle Addition Postulate

Step-by-step explanation:

In the given picture, we have ∠MRO and ∠MRS on line SRO.

So, ∠SRO = ∠MRO +∠MRS  [By angle addition postulate]

So the postulate that justify the statement " ∠SRO = ∠MRO +∠MRS" is Angle Addition Postulate.

Answer:

Question (i):

Reduce = 15% of Rs 40 = 0.15 x 40 = Rs 6

Price after reduced = Rs 40 - Rs 6 = Rs 36

Answer: Rs 36

-

Question (ii):

Reduce = 15% x 20.40 = 0.15 x 20.40 = Rs 3.60

Price after reduced = Rs 20.40 - Rs 3.60 = Rs 17.34

Answer: Rs 17.34

-

Answer:

6 scarves

Step-by-step explanation:

So we know that 3/4 yd. = 1 (scarf)

We have 4 2/3 material to make the scarves

=> convert to an improper fraction 4 2/3 = 14/3

=> Divide material by needed amt.

=> 14/3 x 4/3 = 56/9

56/9 = 6 2/9

But 6 2/9 is not our answer. Since we need a full amt. of scraves, we round down to our final answer of 6 scarves.

Hope this helps!