So a Quadratic function,A quadratic function is one of the form f(x) = ax2 + bx + c, where a, b, and c are numbers with a not equal to zero
Find the distance between the two points.
(3,-9) and (-93,-37)
Answer:
100
Step-by-step explanation:
√(x2 - x1)² + (y2 - y1)²
√(-93 - 3)² + [-37 - (-9)]
√(-96)² + (-28)²
√9216 + 784
√10000
= 100
What is the circumference of the given circle in terms of [tex]\pi[/tex]?
a. 14[tex]\pi[/tex] in.
b. 28[tex]\pi[/tex] in.
c. 42[tex]\pi[/tex] in.
d. 196[tex]\pi[/tex] in.
Answer:
b. 28[tex]\pi[/tex] in.
Step-by-step explanation:
circumference of a circle = 2 [tex]\pi[/tex] r
whrere r is the radius of rhe circle
= 2 × [tex]\pi[/tex] × 14 in.
= 28 [tex]\pi[/tex] in.
that is option b
We have to find,
The circumference of the given circle in terms of the π.
The formula we use,
→ C = 2πr
Then we can find the circumference,
→ 2 × π × r
→ 2 × π × 14
→ 28π in.
Hence, option (b) is correct answer.
Determine the domain and range of the function
Answer:
Domain: -4 ≤ x ≤ -1
Range: -1 ≤ y ≤ 3
Step-by-step explanation:
Hi there!
The domain is the possible x-values of a function.
The lowest x-value the function contains is -4, and the greatest is -1.
Therefore, the domain is -4 ≤ x ≤ -1.
The range is the possible y-values of a function.
The lowest y-value the function contains is -1, and the greatest is 3.
Therefore the range is -1 ≤ y ≤ 3.
I hope this helps!
What is the volume of the composite figure if both the height and the diameter of the cylinder are 3.5 feet? Give the exact answer and approximate to two decimal places.
Answer:
Volume of composite figure = 44.9 feet³
Step-by-step explanation:
Given:
Height of cylinder = 3.5 feet
Diameter of cylinder = 3.5 feet
Diameter of hemisphere = 3.5 feet
Find:
Volume of composite figure
Computation:
Radius of cylinder and sphere = 3.5/2 = 1.75 feet
Volume of composite figure = Volume of cylinder + Volume of hemisphere
Volume of composite figure = πr²h + (2/3)πr³
Volume of composite figure = (3.14)(1.75)²(3.5) + (2/3)(3.14)(1.75)³
Volume of composite figure = (3.14)(3.0625)(3.5) + (2/3)(3.14)(5.359375)
Volume of composite figure = 33.656875 + 11.2189583
Volume of composite figure = 44.8758
Volume of composite figure = 44.9 feet³
The mean weight of the packages Joan shipped was 2.5 pounds. If Joan mailed four packages and three of them had weights of 1.8, 3.2 and 2.7 pounds, then what did the other package weigh?
Answer:
2.3 pounds
Step-by-step explanation:
First, the mean is equal to the sum divided by the number of numbers.
There are four packages, so there are four numbers. Let's say the fourth package has a weight of x. We can then write
mean = sum / number of numbers
2.5 = (1.8+3.2+2.7+x)/4
multiply both sides by 4 to remove the denominator
10 = 1.8+3.2+2.7+x
10 = 7.7 + x
subtract 7.7 from both sides to isolate the x
x = 2.3 pounds
Solve the simultaneous equations
6
x
+
2
y
=
12
5
x
+
2
y
=
8
Answer: x=4, y=-6
Step-by-step explanation:
The area of a circle is 3.142cm square.find the radius and diameter of the circle
Answer:
50.24 or 50.272
Step-by-step explanation:
Square radius and then times by 3.14 or 3.142
4^2*3.14 = 50.24
4^2*3.142 = 50.272
simplify 3 / 8 (–2 / 7 +(–3 / 8 ×2 / 5)
Answer:
so the answer is 0.16339
Find the distance between the two points.(-7,4/19) and (7,4/9)
Answer:
d=(14,0)Step-by-step explanation:
√(7-(-7))^+(4/19-4/19)^√(7+7)^+(0)^√(14)^+0= 14Please help!! Picture included!
Answer: the answer is c
Step-by-step explanation:brainlist [tex]\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right][/tex]
Let (-5. 4) be a point on the terminal side of ø
Find the exact values of cos, csc , and tan
Answer:
[tex] \cos(x) = - \frac{5}{ \sqrt{41} } [/tex]
[tex] \csc(x) = \frac{ \sqrt{41} }{4} [/tex]
[tex] \tan(x) = - \frac{4}{5} [/tex]
Step-by-step explanation:
We know that (-5,4) is the terminal side. This means out legs will measure 5 and 4 if we graph it on a triangle.
We need to find the cos, csc, and tan measure of this point.
We can find cos by using the formula of
[tex] \cos(x) = \frac{adj}{hyp} [/tex]
The adjacent side is -5 and we can find the hypotenuse by doing pythagorean theorem.
[tex] { - 5}^{2} + {4}^{2} = \sqrt{41} [/tex]
So using the info the answer is
[tex] \cos(x) = \frac{ - 5}{ \sqrt{41} } [/tex]
We can find tan but first me must find sin x.
[tex] \sin(x) = \frac{opp}{hyp} [/tex]
[tex] \sin(x) = \frac{4}{ \sqrt{41} } [/tex]
So now we just use this identity,
[tex] \tan(x) = \sin(x) \div \cos(x) [/tex]
[tex] \tan(x) = \frac{ \frac{4}{ \sqrt{41} } }{ \frac{ - 5}{ \sqrt{41} } } = - \frac{4}{5} [/tex]
So tan x=
[tex] - \frac{ 4}{5} [/tex]
We can find csc by taking the reciprocal of sin so the answer is easy which is
[tex] \frac{ \sqrt{41} }{4} [/tex]
The population of a city this year is 200,000. The population is expected to increase by 2.5% per year over the next 10 years. Which exponential equation models this situation?
Answer:
[tex]A = 200,000(1+.025) ^{t}[/tex]
[tex]A = 200,000(1+.025) ^{10}[/tex]
Step-by-step explanation:
Kim ran 9/10 of a mile. Adrian ran 3/5 of a mile Adrian claims that Kim ran 1 3/10 times farther than him Kim says that she actually ran 1/2 times farther than Adrian who is correct
9514 1404 393
Answer:
Kim
Step-by-step explanation:
The ratio of Kim's distance to Adrian's distance is ...
(9/10)/(3/5) = (9/10)/(6/10) = 9/6 = 3/2 = 1.5
__
You need to be very careful with the wording here. Kim ran 1 1/2 times as far as Adrian. That is, she ran Adrian's distance plus 1/2 Adrian's distance.
If we take the wording "1/2 times farther" to mean that 1/2 of Adrian's distance is added to Adrian's distance, then Kim is correct.
_____
In many Algebra problems, you will see the wording "k times farther" to mean the distance is multiplied by k. If that interpretation is used here, neither claim is correct, as Kim's distance is 1 1/2 times farther than Adrian's.
On the other hand, if the value of "k" is expressed as a percentage, the interpretation usually intended is that that percentage of the original distance is added to the original distance. Using this interpretation, Kim's distance is 50% farther than Adrian's. (Note the word "times" is missing here.)
__
Since Adrian ran 1 5/10 the distance Kim ran, Adrian's claim is incorrect regardless of the interpretation. If you require one of the two to be correct, then Kim is.
Find the area of the figure
Please help :)
9514 1404 393
Answer:
372 m²
Step-by-step explanation:
A vertical line down the center of the figure will divide it into two congruent trapezoids, each with bases 13 and 18, and height 12.
The area of one of them is ...
A = 1/2(b1 +b2)h
So, the area of the two of them together is ...
A = (2)(1/2)(b1 +b2)h = (b1 +b2)h
A = (13 m + 18 m)(12 m) = 372 m²
Order the following integers from smallest (left side) to biggest (right
side):
20, 0, 22, -35, 100, -59
Need help please
find the LCM of ;
(1+4x+4x2-16x) and (1+2x-8x3-16x4)
Answer:
16x4−4x2+4x−116x4−4x2+4x−1
=16x4−(4x2−4x+1)=16x4−(4x2−4x+1)
=(4x2)2−(2x−1)2∵a2−2ab+b2=(a−b)2=(4x2)2−(2x−1)2∵a2−2ab+b2=(a−b)2
=(4x2−2x+1)(4x2+2x−1)∵a2−b2=(a−b)(a+b
Step-by-step explanation:
Hannah would like to make an investment that will turn 8000 dollars into 33000 dollars in 7 years. What quarterly rate of interest, compounded four times per year, must she receive to reach her goal?
Answer:
20.76%
Step-by-step explanation:
[tex]33000=8000(1+\frac{i}{4})^{4*7}\\4.125=(1+\frac{i}{4})^{28}\\\sqrt[28]{4.125}=1+\frac{i}{4} \\i= .207648169[/tex]
which rounds to 20.76%
Answer:
About 0.2076 or 20.76%.
Step-by-step explanation:
Recall that compound interest is given by the formula:
[tex]\displaystyle A=P\left(1+\frac{r}{n}\right)^{nt}[/tex]
Where A is the final amount, P is the principal, r is the interest rate, n is the number of times the interest is applied per year, and t is the number of years.
Since Hannah wants to turn an $8,000 investment into $33,000 in seven years compounded quarterly, we want to solve for r given that P = 8000, A = 33000, n = 4, and t = 7. Substitute:
[tex]\displaystyle \left(33000\right)=\left(8000\right)\left(1+\frac{r}{4}\right)^{(4)(7)}[/tex]
Simplify and divide both sides by 8000:
[tex]\displaystyle \frac{33}{8}=\left(1+\frac{r}{4}\right)^{28}[/tex]
Raise both sides to the 1/28th power:
[tex]\displaystyle \left(\frac{33}{8}\right)^{{}^{1}\! / \! {}_{28}}= 1+\frac{r}{4}[/tex]
Solve for r. Hence:
[tex]\displaystyle r= 4\left(\left(\frac{33}{8}\right)^{{}^{1}\! / \! {}_{28}}-1\right)[/tex]
Use a calculator. Hence:
[tex]r=0.2076...\approx 0.2076[/tex]
So, the quarterly rate of interest must be 0.2076, or about 20.76%.
The graph of f(x) with the graph of w(x)=(x-6)^2
Answer:
A
Step-by-step explanation:
graph is 6 units to the right
if it had been (x+6)^2
it would have been 6 units to left
Helppppppppp ASAP!!!!!
The graphs below have the same shape . The equation of the blue graph is f(x) =2^x . Which of these is the equation of the red graph
Answer:
[tex]{ \bf{c). \: g(x) = {2}^{x} - 2 }}[/tex]
HELP WILL MARK BRAINLIESG
Write an equation that represents the line,
Use exact numbers.
Answer:
3/2 + 7
Step-by-step explanation:
What is the following product? Assume d>0 3vd•3vd•3vd
Answer:
A. d
Step-by-step explanation:
If you find the 3rd square root or whatever its called, and multiply it by itself again 3 times, You end up with d again.
Let Y1 and Y2 denote the proportions of time (out of one workday) during which employees I and II, respectively, perform their assigned tasks. The joint relative frequency behavior of Y1 and Y2 is modeled by the density function.
f (y 1,y2)=y 1+y 2 o<=y 1<=1, 0<=y2<=1(0 elsewhere)
a. Find P (Y1< 1/2,y2>1/4)
b. Find P(Y 1+Y2<=1)
Are Y1 and Y2 independent?
(a) The region Y₁ < 1/2 and Y₂ > 1/4 corresponds to the rectangle,
{(y₁, y₂) : 0 ≤ y₁ < 1/2 and 1/4 < y₂ ≤ 1}
Integrate the joint density over this region:
[tex]P\left(Y_1<\dfrac12,Y_2>\dfrac14\right) = \displaystyle\int_0^{\frac12}\int_{\frac14}^1 (y_1+y_2)\,\mathrm dy_2\,\mathrm dy_1 = \boxed{\dfrac{21}{64}}[/tex]
(b) The line Y₁ + Y₂ = 1 cuts the support in half into a triangular region,
{(y₁, y₂) : 0 ≤ y₁ < 1 and 0 < y₂ ≤ 1 - y₁}
Integrate to get the probability:
[tex]P(Y_1+Y_2\le1) = \displaystyle\int_0^1\int_0^{1-y_1}(y_1+y_2)\,\mathrm dy_2\,\mathrm dy_1 = \boxed{\dfrac13}[/tex]
Y₁ and Y₂ are not independent because
P(Y₁ = y₁, Y₂ = y₂) ≠ P(Y₁ = y₁) P(Y₂ = y₂)
To see this, compute the marginal densities of Y₁ and Y₂.
[tex]P(Y_1=y_1) = \displaystyle\int_0^1 f(y_1,y_2)\,\mathrm dy_2 = \begin{cases}\frac{2y_1+1}2&\text{if }0\le y_1\le1\\0&\text{otherwise}\end{cases}[/tex]
[tex]P(Y_2=y_2) = \displaystyle\int_0^1 f(y_1,y_2)\,\mathrm dy_1 = \begin{cases}\frac{2y_2+1}2&\text{if }0\le y_2\le1\\0&\text{otherwise}\end{cases}[/tex]
[tex]\implies P(Y_1=y_1)P(Y_2=y_2) = \begin{cases}\frac{(2y_1+1)(2y_2_1)}4&\text{if }0\le y_1\le1,0\ley_2\le1\\0&\text{otherwise}\end{cases}[/tex]
but this clearly does not match the joint density.
rotation 90 degrees counterclockwise about the origin
Answer:
Point W = (-3, 3)Point X = (-3, 2)Point V = (-2, 3)The rotation rule states that rotation 90° counterclockwise means (x, y) = (-y, x)
The new points would be equal to:
Point W' = (-3, -3)Point X' = (-2, -3)Point V' = (-3, -2)Try graphing it to see if the new points make sense(because I'm not too sure :\)
The slope of diagonal OA is ? and its equation is ?
Answer:
Slope = [tex]\frac{4}{3}[/tex]
Equation of the line → [tex]y=\frac{4}{3}x[/tex]
Step-by-step explanation:
Let the equation of diagonal OA is,
y = mx + b
Here, m = Slope of the line OA
b = y-intercept
Slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,
m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,
m = [tex]\frac{4-0}{3-0}[/tex]
m = [tex]\frac{4}{3}[/tex]
Since, line OA is passing through the origin, y-intercept will be 0.
Therefore, equation of OA will be,
[tex]y=\frac{4}{3}x[/tex]
Which choice is equivalent to(√6)( √8). How do you solve
A. 4√6
B. 4√3
C. 16√3
D. 3√16
Answer:
B
Step-by-step explanation:
(6)^1/2 × (8)^1/2
6^1/2 × 2 (2)^1/2
4 (3)^1/2
What is the prime factorization of 30?
O A. 2.2.3.5
O B. 5.6
O C. 3.10
O D. 2.3.5
D. 2.3.5 is the correct answer
Help and explain !!!!!!
Answer:
x = -4 or x = 5
Step-by-step explanation:
To solve the absolute value equation
|X| = k
where X is an expression in x, and k is a non-negative number,
solve the compound equation
X = k or X = -k
Here we have |2 - 4x| = 18
In this problem, the expression, X, is 2 - 4x, and the number, k, is 18.
We set the expression equal to the number, 2 - 4x = 18, and we set the expression equal to the negative of the number, 2 - 4x = -18. Then we solve both equations.
2 - 4x = 18 or 2 - 4x = -18
-4x = 16 or -4x = -20
x = -4 or x = 5
Answer:
x = -5 . x= 4
Step-by-step explanation:
because |4| = 4 and |-4| = 4
you can see that TWO inputs can get an output of (lets say) 4
The absolute value function can be seen as a function that ignores negative signs
so to get an OUTPUT of "18" using the absolute value function
there are really two ways of getting there
"2-4x = 18" AND "2-4x = -18"
if you solve both of those you will find that -5 and 4 will
produce the 18 and -18
Identify the sampling techniques used, and discuss potential sources of bias (if any). Assume the population of interest is the student body at a university. Questioning students as they leave an academic building, a researcher asks 341 students about their eating habits.
1. What type of sampling is used?
a. Systematic sampling is used, because students are selected from a list, with a fixed interval between students on the list.
b. Cluster sampling is used because students are divided into groups, groups are chosen at random, and every student in one of those groups is sampled.
c. Simple random sampling is used because students are chosen at random.
d. Stratified sampling is used because students are divided into groups, and students are chosen at random from these groups.
e. Convenience sampling is used because students are chosen due to convenience of location.
2. What potential sources of bias are present if any. Select all that apply.
a. University students may not be representative of all people in their age group.
b. The sample only consists of members of the population that are easy to get. These members may not be representative of the population.
c. Because of the personal nature of the question, students may not answer honestly.
d. There are no potential sources of bias.
Answer:
1. e. Convenience sampling is used because students are chosen due to convenience of location.
2. a. University students may not be representative of all people in their age group.
Step-by-step explanation:
Samples may be classified as:
Convenient: Sample drawn from a conveniently available pool.
Random: Basically, put all the options into a hat and drawn some of them.
Systematic: Every kth element is taken. For example, you want to survey something on the street, you interview every 5th person, for example.
Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.
Stratified: Also divides the population into groups. However, then only some elements of the group are surveyed.
Questioning students as they leave an academic building, a researcher asks 341 students about their eating habits.
Students sampled as they leave the build, which is convenience, in this case convenience of location, which means that the correct answer to question 1 is given by option e.
2. What potential sources of bias are present if any. Select all that apply.
Only members of one group are asked(university students), and this may not be representative of the rest of the population, which means that the correct answer to question 2 is given by option a.
Which equation represents the line that passes through points (1, –5) and (3, –17)?
Answer:
equation : y= -6 + 1
Step-by-step explanation:
Find the length of side ab, give your answer to 1 decimal place 62 and 12
Answer:
Huh? is it triangle? and right triangle? if it is its 62^2 = 12^2 + x^2
Step-by-step explanation: