Answer:
fohohcoufohohcouvhop
Step-by-step explanation:
typing mistake sorry
[tex]\\ \sf\longmapsto x+73=90[/tex]
[tex]\\ \sf\longmapsto x=90-73[/tex]
[tex]\\ \sf\longmapsto x=17[/tex]
Why?
Sum of two complementary angles is 90°
Write the following statement in equation form using variables x and y. "Sum of two numbers is 15 and difference is 11.
Answer:
see explanation
Step-by-step explanation:
Using x and y to represent the 2 numbers with x > y , then
x + y = 15 → (1)
x - y = 11 → (2)
Adding the 2 equations term by term to eliminate y
2x = 26 ( divide both sides by 2 )
x = 13
Substitute x = 13 into (1)
13 + y = 15 ( subtract 13 from both sides )
y = 2
The 2 numbers are 13 and 2
look at image for question and answer
19. Charlotte has a success rate of about 20%
for making baskets in attempts during
basketball games. She wants to determine
the probability that she will have to make at
least 5 attempts during a game in order to
make a basket. She designed a simulation
where she spun a spinner that was divided
into 5 equal sections, one of which was
colored red. She counted how many times
she had to spin the spinner in each trial
before it landed on red. The results of her
20 trials are shown below.
5, 2, 7, 2, 3, 4, 10, 6,4,6,
3, 6, 6, 4, 8,5,7,7,1,5
According to this simulation, what is the
probability that Charlotte will have to
make at least 5 attempts in order to make
a basket?
Answer:
[tex]P(x \ge 5) = 0.60[/tex]
Step-by-step explanation:
Given
[tex]S = \{5, 2, 7, 2, 3, 4, 10, 6,4,6,3, 6, 6, 4, 8,5,7,7,1,5\}[/tex]
[tex]n(S) = 20[/tex]
Required
[tex]P(x \ge 5)[/tex]
First, we count the number of trials that are at least 5
[tex]x = \{5, 7, 10, 6,6, 6, 6, 8,5,7,7,5\}[/tex]
So, we have:
[tex]n(x \ge 5) = 12[/tex]
So, we have:
[tex]P(x \ge 5) = \frac{n(x \ge 5)}{n(S)}[/tex]
This gives
[tex]P(x \ge 5) = \frac{12}{20}[/tex]
[tex]P(x \ge 5) = 0.60[/tex]
One of the angles of a triangle is 110° and the other two angles are equal.What is the measure of each of these equal angles?
Answer:
x = 35
Step-by-step explanation:
Let x be the one of the other angles
X is also the third angle since we know they are equal
The sum of the angles of a triangle is 180
110+x+x = 180
110 +2x= 180
2x = 180-110
2x= 70
Divide by 2
2x/2 = 70/2
x = 35
Answer:
[tex]x = 35 \degree[/tex]
Step-by-step explanation:
Let the unknown angle be x
Unknown Angles are equal to each other so,
[tex]x + x + 110 = 180[/tex]
sum of the interior angles in a triangle is 180°
[tex]2x + 110 = 180 \\ 2x = 180 - 110 \\ 2x = 70 \\ \frac{2x}{2} = \frac{70}{2} \\ x = 35 \degree[/tex]
Make sure to round it to tge nearest 10th
Answer:
13.9
Step-by-step explanation:
For the 41° angle, x is the opposite leg, and 16 is the adjacent leg. The trig ratio that relates the opposite leg and the adjacent leg is the tangent.
tan A = opp/adj
tan 41° = x/16
x = 16 * tan 41°
x = 13.9085...
Answer: 13.9
if tanA=2ab/a square-b square.find the value of cosA and sin A
Answer:
[tex]\displaystyle \displaystyle \cos A = \frac{a^2-b^2}{a^2 + b^2}\text{ and } \sin A = \frac{2ab}{a^2 + b^2}[/tex]
Step-by-step explanation:
We are given that:
[tex]\displaystyle \tan A = \frac{2ab}{a^2 - b^2}[/tex]
And we want to find the value of cos(A) and sin(A).
Recall that tangent is the ratio of the opposite side to the adjacent side.
Therefore, the opposite side measures 2ab, and the adjacent side measures a² - b².
Using the Pythagorean Theorem, solve for the hypotenuse:
[tex]\displaystyle \begin{aligned} c^2 &= a^2 + b^2 \\ \\ c&= \sqrt{(2ab)^2 + (a^2-b^2)} \\ \\ &= \sqrt{(4a^2b^2)+(a^4-2a^2b^2+b^4)} \\ \\ &= \sqrt{a^4 + 2a^2b^2 + b^4 } \\ \\ &= \sqrt{(a^2 +b^2)^2} \\ \\ &= a^2 + b^2\end{aligned}[/tex]
Thus, our hypotenuse is given by a² + b².
Cosine is the ratio between the adjacent side and the hypotenuse. Thus:
[tex]\displaystyle \cos A = \frac{a^2-b^2}{a^2 + b^2}[/tex]
And sine is the ratio between the opposite side and the hypotenuse. Thus:
[tex]\displaystyle \sin A = \frac{2ab}{a^2 + b^2}[/tex]
In conclusion:
[tex]\displaystyle \displaystyle \cos A = \frac{a^2-b^2}{a^2 + b^2}\text{ and } \sin A = \frac{2ab}{a^2 + b^2}[/tex]
Answer:
Step-by-step explanation:
[tex]sec^2A-tan^2A=1\\sec^2A=1+tan^2A=1+\frac{4a^2b^2}{(a^2-b^2)^2} =\frac{(a^2-b^2)^2+4a^2b^2}{(a^2-b^2)^2} =\frac{(a^2+b^2)^2}{(a^2-b^2)^2} \\cos^2A=\frac{(a^2-b^2)^2}{(a^2+b^2)^2} \\cos A=\frac{a^2-b^2}{a^2+b^2} \\sin A=\sqrt{1-cos^2A} =\sqrt{1-(\frac{a^2-b^2}{a^2+b^2} )^2} =\sqrt{\frac{(a^2+b^2)^2-(a^2-b^2)^2}{(a^2+b^2)^2} } =\sqrt{\frac{4a^2b^2}{(a^2+b^2)^2} }=\frac{2ab}{a^2+b^2}[/tex]
Help with number 11 anyone?
Answer:
y = 3/5×x + 1
Step-by-step explanation:
Slope intercept form y= mx + b
since slope = 3/5 => y= [tex]\frac{3}{5}[/tex]x + b
Plug point (-5,-2) to the equation -2 = [tex]\frac{3}{5}[/tex] x (-5) + b
=> b=1
helpp me solve it and pls explain
tyyy
Answer:
2=124 124/2
4=248 248/4
5=310 310/5
8=496 496/8
Step-by-step explanation:
40 + 22 = 62
62 x 2 = 124
62 x 4 = 248
62 x 5 = 310
62 x 8 = 496
i think
Find an equation of the line having the given slope and containing the given point m= - 8, (2,5) The equation of the line is y= (Simplify your answer. Type your answer in slope-intercept form. Use integers or fractions for any numbers in the expression)
Answer:
Equation of line is y = -8x + 21
Step-by-step explanation:
Slope, m = -8
General equation of line:
[tex]{ \boxed{ \bf{y = mx + c}}}[/tex]
At point (2, 5), y = 5 and x = 2:
[tex]{ \tt{5 = ( - 8 \times 2) + c}} \\ { \tt{c = 21}}[/tex]
Therefore:
[tex]{ \sf{y = - 8x + 21}}[/tex]
[tex]{ \underline{ \blue{ \sf{christ \:† \: alone }}}}[/tex]
square of 2x+3y.Please help me
Answer:
(2x+3y)^2
= (2x)^2 + 2(2x)(3y) + (3y)^2
= 4x^2 + 12xy + 9y^2
Answer:
4x^2 12xy +9y^2
Step-by-step explanation:
(2x+3y)^2
(2x+3y)(2x+3y)
FOIL
4x^2 + 6xy+6xy + 9y^2
4x^2 12xy +9y^2
A polynomial has one root that equals 2 + i. Name one other root of this
polynomial.
Answer:
sorry
Step-by-step explanation:
polynomial is not given
question is incomplete
answer i guess i will give brainly for corret answers.
Answer:
B. Never
Step-by-step explanation:
When a number is irrational, it means that it cannot be written as a fraction.
I hope this helps!
pls ❤ and mark brainliest pls!
Answer:
c) when it is improper fraction
help me find x please
Answer:
[tex]3\sqrt{3}[/tex]
[tex]\left(\frac{\left(6\cdot \:\:\:sin\left(30\right)\right)}{sin\left(90\right)}\right)^2+x^2=36[/tex]
Step-by-step explanation:
what is the volume of the circular cone below?
Answer:
200.96
Step-by-step explanation:
Volume of cone=(1/3)*pi*r^2*h
Volume=(1/3)*pi*16*12=64*3.14=200.96
How many hundred thousands 90 ten thousands
pls hurry
Answer:
0.9
Step-by-step explanation:
100,000 in 90,000
HELP PLEASE!! ASAP
If triangles ABC and DEF are similar, what is y? Show your work.
If both triangles are similar then ratio of sides will be same.
[tex]\\ \sf\longmapsto \dfrac{12}{14}=\dfrac{y}{21}[/tex]
[tex]\\ \sf\longmapsto 12(21)=14y[/tex]
[tex]\\ \sf\longmapsto 14y=252[/tex]
[tex]\\ \sf\longmapsto y=\dfrac{252}{14}[/tex]
[tex]\\ \sf\longmapsto y=18[/tex]
Answer:
y = 18
Step-by-step explanation:
Since the triangles are similar, the corresponding sides are in proportion, that is
[tex]\frac{BC}{EF}[/tex] = [tex]\frac{AC}{DF}[/tex] , substitute values
[tex]\frac{y}{12}[/tex] = [tex]\frac{21}{14}[/tex] ( cross- multiply )
14y = 252 ( divide both sides by 14 )
y = 18
Help anyone can help me do this question,I will mark brainlest.
Answer:
8 cm
Step-by-step explanation:
AM = MC = BM = (1/2) BC => AM , MC , BM = 5, => BC = 10apply pytago => (AC ^ 2) + (AB ^ 2) = (BC ^2)AB = [tex]\sqrt{BC ^2 - AC ^2}[/tex] = [tex]\sqrt{10 ^2 - 6 ^ 2}[/tex] = 8 (cm)Answer:
4
Step-by-step explanation:
So first let's write the information we got
Angle BAC = 90 degrees
Midpoint of BC = M
AC = 6cm
Am= 5cm
Also I found MC = BM, since it has a line that represents both lines are same
so to find it we have to Pythagoras theorem (A^2 + B^2 = C^2), well it is question we have the 'A value and C Value', also we need to find the value of B to find the length of MC and BM
A = 5
C = 6
so therefore to find B^2, we have to do the reverse, we don't add but subtract
C^2 - A^2 = B^2
___________________________________________________________
Moving on to Calculation
6^2 - 5^2 = B^2
36 - 25 = B^2
B^2 = 9
B = √9
B = 3
MC and BM Length = 3 cm
____________________________
Now, we know the length we again need to use Pythagoras theorem to solve this.
Since we know
A = 5
B = 3
So..
A^2 + B^2 = C^2
5^2 + 3^2 = C^2
25 - 9 = C^2
C^2 = 16
C = √16
C = 4
Algebraic expression for 2a+3b-c if a=3 b=-4 c=-2
Answer:
-4
Step-by-step explanation:
a = 3
b = -4
c = -2
2a + 3b - c
= 2(3) + 3(-4) - (-2)
= 6 + (-12) + 2
= -4
Please help me with this, I am stu pid. UnU
UDISJKDFJSFJDGLFS HELP
Answer:
I think E
Step-by-step explanation:
You know the shortest building is 25 m.
to find the rest, use trigo so Tan(20)=opposite/adjacent.
Adjacent is 50. Do the math and add the answer with 25.
Answer:
The answer would be E. 43.2
According to TOA, The opposite side is tan(20) x adjacent side( 50m)
the answer is 18.2( to 1 dp). Add the height of the second building together with 18.2 and you will get ur answer. HOpe this helps:)
a school has 2500 pupils. when 52 boys and 1/9 of the girls are absent, the number of the boys present is equal to the number of girls. how many does doe he school have
a school has 2500 pupils. when 52 boys and 1/9 of the girls are absent, the number of the boys present is equal to the number of girls. how many pupils does the school have ?
Solution :Let the number of boys be x
Data :
Total pupils = 2500
Absent no. of boys and girls = 52 and 1/9
Now,
First of all we need to get the number of girls then add it with the no. of boys absent and then subtract the whole from 2500 to get the required answer.Remaining no of pupils = 2500 - 52 ➝ 2448
Hence, the no. of girls absent = 1/9 of 2448 ➝ 272
Therefore,
Total no. of pupils absent = 52 + 272 ➝ 324
No. of pupils present = 2500 - 324 ➝ 2176
Henceforth, 2176 pupils are present
Klog earns $6.30 per hour. He worked 3.5 hours each day Monday through Friday plus 4 on Saturday. How much did he earn altogether?
Answer:
Klog earned $135.45 altogether.
Step-by-step explanation:
Hours
Monday - Friday : 5 days / 3.5 hours
Saturday : 1 day / 4 hours
3.5 · 5 + 4
= 17.5 + 4
= 21.5
Money
$6.30 per hours / 21.5 hours
6.30 · 21.5
= $135.45
If (5^(k-1))+(5^(k+1)) = m, what is 2*5^k in terms of m?
If [tex]5^k^-^1+5^k^-^1=m[/tex], what is [tex]2*5^k[/tex] in terms of m?
A) 5m
B) 5m÷2
C) 5m÷13
D) 5m÷26
Answer:
5m
Step-by-step explanation:
5^(k-1)+5^(k-1)=m
Going to combine like terms on left:
2×5^(k-1)=m
Law of exponents applied:
2×5^k×5^(-1)=m
Reciprocal:
2×5^k×1/5=m
Multiply 5 on both sides to obtain the requested:
2×5^k=5m
Combine like terms in the given polynomial. Then, evaluate for x = 4, y = – 2.
xy – 2xy + 3x2 y — 4x y2 + 2xy2
3x2 y + 2xy2 – xy; – 56
C - xy – 2xy2 + 3x2y; – 56
Cx? y2 – 2; 62
C
– 2x y2 + 3x2y – xy; – 120
Need explanation please
Answer:
- 2 x y^2+3 x^2 y -xy
-120
Step-by-step explanation:
xy – 2xy + 3x^2 y — 4x y^2 + 2xy^2
Combine like terms
xy – 2xy + 3x^2 y — 4x y^2 + 2xy^2
- x y+3 x^2 y - 2 x y^2
Let x = 4 y = -2
-(4)(-2) +3(4)^2 (-2) -2(4)(-2)^2
Exponents first
-(4)(-2) +3(16) (-2) -2(4)(4)
Multiply
+8 -96-32
Add and subtract
-120
Choose which is a statistical question: What are
the ages of the students in this class? or How
many pennies equal 1 dollar? Explain.
The statistical question is; "What are the ages of the students in this class?
What is a statistical question?A statistical question is always aimed at data collection which can subsequently used for analysis and decision making. Statistical questions are asked in the course of research.
Among the two questions, the statistical question is; "What are the ages of the students in this class?
Learn more about statistics:https://brainly.com/question/8058700
#SPJ1
A number is doubled and 7 is subtracted from the answer, if the result is -25.
-create an equation
-solve the equation to find the number
Please Respond
Set A and the universal set U are defined as follows.
U={1,2,3,4,5,6)
A= {2,4,6}
Find the following sets.
Write your answer in roster form or as Ø.
Part (a)
Answer: ØThis is the empty set
------------------
Explanation:
It doesn't matter what set A is composed of. Intersecting any set with the empty set Ø will always result in the empty set.
This is because we're asking the question: "What does some set A and the empty set have in common?". The answer of course being "nothing" because there's nothing in Ø. Not even the value zero is in this set.
We can write Ø as { } which is a set of curly braces with nothing inside it.
=========================================================
Part (b)
Answer: {1,2,3,4,5,6}-----------------
Explanation:
When you union the universal set with any other set, you'll get the universal set.
The rule is [tex]A \cup B = B[/tex] where I've made B the universal set to avoid confusion of the letter U and the union symbol [tex]\cup[/tex] which looks nearly identical.
Why does this rule work? Well if an item is in set [tex]\overline{A}[/tex], then it's automatically in set U (everything is in set U; it's the universe). So we're not adding anything to the universe when applying a union involving this largest set.
It's like saying
A = set of stuff inside a persons house[tex]\overline{A}[/tex] = set of stuff outside a persons house (ie stuff that is not in set A)U = set of every itemwe can see that [tex]\overline{A} \cup U[/tex] will basically form the set of every item, aka the universal set.
The points A,B,C and D divide the line segment AD in the ratio 4:3:1 , respectively , and AD = 72cm . What is the length of BD?
Segment addition postulate states that given points X, and Z, on a line, a point Y, can be located between X, and Z, ony if we have;
XZ = XY + YZ
The length of the segment BD is 36 cm
The reason the above value is correct is as follows:
Known:
The ratio in which the points A, B, C, and D divide the line segment = 4:3:1
The length of segment AD = 72 cm
Required:
The length of BD
Method:
Calculate the length of BC and CD and add their values to get BD
Solution:
Let the ratios be given unit proportions of the segment AD such that we have;
AB = 4 units
BC = 3 units
CD = 1 unit
By segment addition postulate, we have;
AD = AB + BC + CD
∴ AD = 4 units + 3 units + 1 unit = 8 units = 72 cm
∴ 1 unit = 72 cm/8 = 9 cm
1 unit = 9 cm
BD = BC + CD by segment addition postulate
BC = 3 units = 3 × 1 unit
∴ BC = 3 × 9 cm = 27 cm
BC = 27 cm
CD = 1 unit
∴ CD = 9 cm
∴ BD = 27 cm + 9 cm = 36 cm
The length of segment BD = 36 cm
Learn more about segment addition postulate here:
https://brainly.com/question/17015321
Find the value of the following (-42) + 15 + (-63) can someone say this and fast
[tex]\\ \sf\longmapsto (-42)+15+(-63)[/tex]
[tex]\\ \sf\longmapsto -42+15+(-63)[/tex]
[tex]\\ \sf\longmapsto -27+(-63)[/tex]
[tex]\\ \sf\longmapsto -27-63[/tex]
[tex]\\ \sf\longmapsto -90[/tex]
Answer:
42 + 15 + (-63) = -90
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
what is simplfiled for x^8 y^2 / x^3 y^9
Answer:
x^5/y^7
Step-by-step explanation:
x^8 y^2 / x^3 y^9
We know that a^b/ a^c = a^(b-c)
Simplify the x terms
x^8 / x^3 = x^(8-3) = x^5
Simplify the y terms
y^2 / y^9 = y^(2-9) = y^-7
We know a^-b = 1/a^b
y^-7 = 1/y^7
Put the terms back together
x^5/y^7