Form the quadratic equation in the form ax^2+bx+c=0 whose solutions are:
a) x=-6,-4
b) x=-12,3

Answer:

19:1

Step-by-step explanation:

There are 10000 headlights. If 5% are defective, then 500 are defective. Since we took that 500 out, we get 9500 good headlights. The ratio is 9500:500 or 19:1

The ratio of defective headlights to non-defective headlights will be 19:1.

The Percentage is defined as representing any number with respect to 100. It is denoted by the sign %. The percentage stands for "out of 100." Imagine any measurement or object being divided into 100 equal bits.

In mathematics, ratios are used to determine the relationship between two numbers it indicates how many times is one number to another number.

There are 10000 headlights. If 5% are defective, then 500 are defective. Since we took that 500 out, we get 9500 good headlights.

The ratio will be calculated as below:-

Ratio = 9500:500

Ratio = 19:1

Therefore, the ratio of defective headlights to non-defective headlights will be 19:1.

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Answer:

A

Step-by-step explanation:

You find the mean by adding all the values then dividing that sum by the amount of values

You find the median by putting the numbers in order from least to greatest and then find the middle number.

Surface area of a cuboid

= [2(length)(width)] + [2(width)(height)] + [2(height)(length)]

= {[2(4)(2.5)] + [2(2.5)(2)] + [2(2)(4)]} units²

= (20 + 10 + 16) units²

= 46 units²

Answer:

3.6

Step-by-step explanation:

Hi there!

We are given this expression:

.6√36 (.6*√36)

And we want to find the value of it

.6 can be re-written as 0.6

In that case,

0.6*√36

First, simplify what's under the radical: √36, which is equal to 6 (6*6=36)

The expression then becomes:

0.6*6

Multiply those numbers together

0.6*6=3.6

Hope this helps!

Answer:

No solutions

Step-by-step explanation:

Convert both equations into y = mx + b form, where m is the slope and b is the y intercept.

8x + 4y = 12

4y = -8x + 12

y = -2x + 3

Rearrange the other equation:

3y = -6x - 15

y = -2x - 5

So, both equations have a slope of -2. But, one has a y intercept of 3 and the other has a y intercept of -5.

Because the lines have the same slope but different y intercepts, the lines are parallel.

Parallel lines have no solutions, because they will never intersect.

So, the system has no solutions.

Answer:

                  Answer:bf                  

Step-by-step explanation:

Answer:

Một trục số đi từ âm 6 đến dương 6. Các điểm ở âm 6, âm 2, 5.

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

Answer:

x = 17

Step-by-step explanation:

(x-3)2 = 7

Divide both sides by two

(x-3)2 = 7

2 2

x-3= 31/2

x= 31/2-3

x= 1/2 or 0.5

Answer:

Principal, P = Rs. 2000

Step-by-step explanation:

Given the following data;

To find how much balance (principal) is to be saved, we would use the formula;

[tex] S.I = \frac {PRT}{100} [/tex]

Where;

Making "P" the subject of formula, we have;

[tex] P = \frac {100S.I}{RT} [/tex]

Substituting the values into the formula, we have;

[tex] P = \frac {100 * 120}{2 * 3} [/tex]

[tex] P = \frac {12000}{6} [/tex]

Principal, P = Rs. 2000

Therefore, you'll have to save up to Rs. 2000.

Answer:

[tex]a =-3[/tex]    [tex]b =2[/tex]

Step-by-step explanation:

Given

[tex]y = ab^x[/tex]

[tex](x_1,y_1) = (0,-3)[/tex]

Required

Find a and b

Substitute [tex](x_1,y_1) = (0,-3)[/tex] for x and y in [tex]y = ab^x[/tex]

[tex]-3 = ab^0[/tex]

[tex]-3 = a * 1[/tex]

[tex]-3 = a[/tex]

Rewrite as:

[tex]a =-3[/tex]

The above implies that (a) is correct;

Hence:

[tex]a =-3[/tex]    [tex]b =2[/tex]

So, the equation is:

[tex]y = -3(2)^x[/tex]

Answer: a=-3 b=2

Step-by-step explanation:

Answer:

x=6

pqs=82

sqr=59

Step-by-step explanation:

13x + 4 + 10x - 1 = 141

23x + 3= 141

23x = 136

x = 136/23 = 6

~~~~~~~~~~~~~~~

pqs = 13x + 4  = 13(6) + 4 = 78+4 = 82

sqr =  10x - 1 = 10(6)-1 = 60 - 1 = 59

Answer:

x = 6

Angle PQS is 82

Angle SQR is 59

Step-by-step explanation:

13x + 4 + 10x - 1 = 141

Group like terms : 23x + 3 = 141

Subtract 3 from both sides to get 23x = 138

Divide both sides by 23 to get x = 6

Angle PQS: Plug 6 into x  for 13x + 4 = 13 (6) + 4 = 82

Angle SQR: Plug 6 into x for 10x - 1 = 10 (6) -1 = 59

Answer:

C, D, E

Step-by-step explanation:

You just need to multiply the numbers together.  Whichever choice is equal to 24, is your answer

So when you multiply for each one...

A is 36

B is 48

C is 24

D is 24

E is 24

So since C, D, E multiply to 24, they are the correct answers.

Answer:

3rd Part

(14÷2) + 3

Step-by-step explanation:

The 3rd part is the answer and on solving the equation, 10 comes as the answer.

Answer:

(14 ÷ 2) + 3

Step-by-step explanation:

Answer:

1. AOC and BOD.

2. all radii of a circle are congruent

3. SAS

4. CPCTC

Step-by-step explanation:

I did it on edge. ALSO PLS GIVE ME BRAINLIEST

Answer:

1. AOC and BOD.

2. all radii of a circle are congruent

3. SAS

4. CPCTC

Step-by-step explanation:

Answer:

(x-3)^2+y^2=8

Step-by-step explanation:

I'm going to go ahead and assume the center is (3,0). The radius can be found by computing the distance from the center, (3,0), to a point on the circle, (5,-2).

The distance between two points is calculated by doing sqrt((distance between x's)^2+(distance between y's)^2).

The distance between our x's is 2.

The distance between our y's is 2.

The square of each then is 4 and 4 respectively.

So we have the distance is sqrt(4+4)=sqrt(8).

The radius is sqrt(8).

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is center and r is radius.

If r=sqrt(8), then r^2=8.

(h,k)=(3,0)

(x-h)^2+(y-k)^2=r^2

(x-3)^2+(y-0)^2=8

(x-3)^2+y^2=8

Answer:

D

Step-by-step explanation:

These diagrams can drive you crazy. The only way you can do this question is to ASSUME that the angle that looks like it is 90 really is 90. That is a very dangerous assumption.

Solution for y

cos(y) = adjacent / hypotenuse

adjacent = 12

hypotenuse = 13

Cos(y) = 12 / 13

Cos(y) = 0.92308

y = cos-1 (0.92308)

y = 22.6

Solution for x

x does not need trig to solve.

x = 180 - 90  - 22.6

x = 67. 4

So that's D

Answer:

D. 50°

Step-by-step explanation:

We know that there are 3 line segments that are forming the angles. Based on that, we can safely say that each line segment is 180°. Given that, we can find the other 2 interior angles of the triangle. We know that one of the exterior angles is 90° so that interior angle also has to be 90° because both angles have to sum to 180. The 2nd exterior angle that we know is 140, so 180-140 = 40°. Since we know the other 2 angles of the triangle now and we know that all the angles of a triangle must sum to 180°, we add 90 and 40 to get 130 and then subtract that from 180 to get 50°. That would look something like this: 180-(90+40) = 180 - 130 = 50°. Hope this helps!

Answer

The measure of p is 50 degrees.

Explanation

You can see that p is located in a triangle.

The interior angles of a triangle always add up to 180 degrees.

So, to solve this problem, you can find the other interior angles, then subtract those from 180 to find p.

The exterior angles are 140 and 90 degrees. To find the measure of the interior angles, you subtract them from 180, (because the exterior angles and interior angles add up to 180).

The measure of the interior angles are 40 and 90 degrees; 180-140=40 and 180-90=90.

Now you can subtract the measure of the two interior angles from 180 to find p; 180-40-90=50.

Answer:

Choices 2 and 3 (READ ALL EXPLANATIONS)

Step-by-step explanation:

To find out the rate of changes for Bush A, you have to choose coordinate points from the graph that hit the line. Then after doing so, you have (1,12) (3,16) and (5,20). You then have to subtract both the x and y values from each other to get your rate of change. Resulting in 4/2, which when simplified is 2. From there you can start building your slope-intercept form equation. Now that you have your rate of change, you then have to find out the initial height of the bush before it started growing. Mathematically worded as the y-intercept. To find the y-intercept from a graph you look at the y axis and see which number hit the line from there. An approximate estimate would be 10. Your finished equation for Bush A should look like y=2x+10. The next equation you want to form is your Bush B one. However, the information you need is already provided to create your equation, y=2.5x+7.5. Now that you have both your equations for both bushes you can look at the statements below to see which answers are corrects based on your data. The first statement is incorrect because Bush A's rate of change is 2 and Bush B's is 2.5. Therefore Bush B's rate of change is bigger not vise versa. The second statement is correct because Bush B's initial value or y-intercept is 7.5 and Bush A's is 10. Therefore, Bush B's initial value is less than that of Bush A's. The third statement is also correct because after substituting the 7 from the 7 years into both equations because the x is the number of years the plant has grown from the original height, Bush A's result was 24 and Bush B's result was 25. Therefore Bush B would be 1 inch taller in that time frame.

8.64E9 = 8,640,000,000

8.64E14 = 864,000,000,000,000

8.64E11 = 864,000,000,000

8.64E13 = 86,400,000,000,000

Step-by-step explanation:

profit =20 rs

profit% = 20/80*100

=25%

Answer:

Profit=20

Step-by-step explanation:

If SP>CP,

It is profit. [Profit=SP-CP]

If SP<CP,

It is loss. [Loss=CP-SP]

If SP=CP,

No gain no loss.

Solution:

SP=100

CP=80

SP>CP,

It is profit.

Profit=SP-CP=100-80=20

Answer:

D

Step-by-step explanation:

Equation of line is y=2x-2

Answer:

x= 1

Step-by-step explanation:

Work is shown in the picture

Answer:

Step-by-step explanation:

a = 6

c = 6

b = 13

ac = 6 * 6 = 36

4 and 9 multiply to 36 and 4 and 9 add to 13

Answer:

1)  [tex]\dfrac{2}{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}[/tex]

2)  [tex]-\dfrac{5}{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}[/tex]

3)  [tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} } =\dfrac{\sqrt{5} }{5} + \dfrac{ \sqrt{2} }{2}[/tex]

4)  [tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \sqrt{3} + \dfrac{\sqrt{6} }{3}[/tex]

5)  [tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} }= \dfrac{\sqrt{15} - \sqrt{6} }{3}[/tex]

Step-by-step explanation:

The rationalization of the denominator of the surds are found as follows;

1) [tex]\dfrac{2}{\sqrt{5} }[/tex]

[tex]\dfrac{2}{\sqrt{5} } \times \dfrac{\sqrt{5} }{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}[/tex]

[tex]\dfrac{2}{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}[/tex]

2) [tex]-\dfrac{5}{\sqrt{3} }[/tex]

[tex]-\dfrac{5}{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}[/tex]

[tex]-\dfrac{5}{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}[/tex]

3) [tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} }[/tex]

[tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} } \times \dfrac{ \sqrt{10} }{\sqrt{10} } = \dfrac{\sqrt{20} + \sqrt{50} }{10 } = \dfrac{2\cdot \sqrt{5} + 5 \cdot \sqrt{2} }{10} = \dfrac{\sqrt{5} }{5} + \dfrac{ \sqrt{2} }{2}[/tex]

[tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} } =\dfrac{\sqrt{5} }{5} + \dfrac{ \sqrt{2} }{2}[/tex]

4) [tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} }[/tex]

[tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \dfrac{3 \cdot \sqrt{3}+\sqrt{6} }{3 } = \sqrt{3} + \dfrac{\sqrt{6} }{3}[/tex]

[tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \sqrt{3} + \dfrac{\sqrt{6} }{3}[/tex]

5) [tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} }[/tex]

[tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} } = \dfrac{\sqrt{5} - \sqrt{2} }{\sqrt{5} - \sqrt{2} } = \dfrac{\sqrt{15} -\sqrt{6} }{5 - 2} = \dfrac{\sqrt{15} - \sqrt{6} }{3}[/tex]

[tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} }= \dfrac{\sqrt{15} - \sqrt{6} }{3}[/tex]

6) [tex]\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5} }[/tex]

[tex]\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5} } \times \dfrac{\sqrt{3} + \sqrt{5}}{\sqrt{3} + \sqrt{5}} = \dfrac{\sqrt{21} + \sqrt{35}}{{3} + {5}} = \dfrac{\sqrt{21} + \sqrt{35}}{8}[/tex]

[tex]\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5} } \times \dfrac{\sqrt{3} + \sqrt{5}}{\sqrt{3} + \sqrt{5}} =\dfrac{\sqrt{21} + \sqrt{35}}{8}[/tex]