Which of the following represents knowledge as a set ofâ rules? A. Neural networks.B. Machine learning systems.C. Robotics.D. Expert systems.E. Genetic algorithms.

Answer:

d. test case generation

Explanation:

Testing should be automated, so that bugs and other errors can be identified without a human error and lack of concentration.

The System Development Life Cycle (SDLC) phase that has seen a substantial amount of automation is the A. code generation.

Thus, while automation will be useful with all the SDLC phases, substantial amount of automation initiatives have been seen with the code generation phase.

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Answer:

architect Christopher Alexander is the person who originally introduced the idea of patterns as a solution design concept.

The person who originally introduced the idea of patterns as a solution design concept named as Christopher Alexander who was an architect.

Architecture is referred to as an innovative technique or artwork based on buildings or physical structures that aims at creating cultural values for upcoming generations to understand the importance of history.

The external layout can be made to best support human existence and health by using a collection of hereditary solutions known as the "pattern language." It creates a set of helpful relationships by combining geometry and social behavior patterns.

Christopher Alexander, a British-American engineer and design theorist of Austrian heritage, is renowned for his several works on the design and construction process introduced the idea of patterns as a solution design concept.

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Answer:

Hre the complete implementation of python code that reads two files and merges them together.

def merge_file(past_file_path,proposed_file_path, merged_file_path):

   past_file_contents=load_file(past_file_path)

   proposed_file_contents=load_file(proposed_file_path)

   proposed_customer_name = []

   for row in proposed_file_contents:

       proposed_customer_name.append(row[1])

   with open(merged_file_path,'w') as outputf:

       outputf.write("Customer Number, Customer Name, Address\r\n")

       for row in proposed_file_contents:

           line = str(row[0]) +", " + str(row[1]) + ", " + str(row[2]) +"\r\n"

           outputf.write(line)

       for row in past_file_contents:

           if row[1] in proposed_customer_name:

               continue

           else:

               line = str(row[0]) + ", " + str(row[1]) + ", " + str(row[2]) + "\r\n"

               outputf.write(line)

       print("Files merged successfully!")

# reads the file and returns the content as 2D lists

def load_file(path):

   file_contents = []

   with open(path, 'r') as pastf:

       for line in pastf:

           cells = line.split(",")

           row = []

           for cell in cells:

               if(cell.lower().strip()=="customer number"):

                   break

               else:

                   row.append(cell.strip())

           if  len(row)>0:

               file_contents.append(row)

   return file_contents

past_file_path="F:\\Past Customer.txt"

proposed_file_path="F:\\Proposed Customer.txt"

merged_file_path="F:\\Merged File.txt"

merge_file(past_file_path,proposed_file_path,merged_file_path)

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

double average(double s1, double s2, double s3, double s4, double s5){

   double avg = (s1 + s2 + s3 + s4 + s5)/5;

   return avg;}

char lGrade(double score){

   char grade;

   if(score>= 90 && score <= 100){ grade ='A'; }

   else if(score>= 80 && score <= 89){ grade ='B'; }

   else if(score>= 70 && score <= 79){ grade ='C'; }

   else if(score>= 60 && score <= 69){ grade ='D'; }

   else if(score < 60){ grade ='F'; }

   return grade;}

int main(){

   double s1,s2,s3,s4,s5;

   cin>>s1>>s2>>s3>>s4>>s5;

   double avg = average(s1,s2,s3,s4,s5);

   cout<<s1<<" "<<lGrade(s1)<<endl;

   cout<<s2<<" "<<lGrade(s2)<<endl;

   cout<<s3<<" "<<lGrade(s3)<<endl;

   cout<<s4<<" "<<lGrade(s4)<<endl;

   cout<<s5<<" "<<lGrade(s5)<<endl;

   cout<<avg<<" "<<lGrade(avg)<<endl;

   return 0;}

Explanation:

The three functions to include in the program are not stated; so, I used the following functions in the program

1. The main function

2. average function

3. Letter grade function

The average function begins here

double average(double s1, double s2, double s3, double s4, double s5){

This calculates the average

   double avg = (s1 + s2 + s3 + s4 + s5)/5;

This returns the calculated average

   return avg;}

The letter grade function begins here

char lGrade(double score){

This declares the grade

   char grade;

If score is between 90 and 100 (inclusive), grade is A

   if(score>= 90 && score <= 100){ grade ='A'; }

If score is between 00 and 89 (inclusive), grade is B

   else if(score>= 80 && score <= 89){ grade ='B'; }

If score is between 70 and 79 (inclusive), grade is C

   else if(score>= 70 && score <= 79){ grade ='C'; }

If score is between 60 and 69 (inclusive), grade is D

   else if(score>= 60 && score <= 69){ grade ='D'; }

If score is less than 60, grade is F

   else if(score < 60){ grade ='F'; }

This returns the calculated grade

   return grade;}

The main begins here

int main(){

This declares the 5 scores

   double s1,s2,s3,s4,s5;

This gets input for the 5 scores

   cin>>s1>>s2>>s3>>s4>>s5;

This calls the average function for average

   double avg = average(s1,s2,s3,s4,s5);

This calls the letter grade function for the 5 scores

   cout<<s1<<" "<<lGrade(s1)<<endl;

   cout<<s2<<" "<<lGrade(s2)<<endl;

   cout<<s3<<" "<<lGrade(s3)<<endl;

   cout<<s4<<" "<<lGrade(s4)<<endl;

   cout<<s5<<" "<<lGrade(s5)<<endl;

This calls the average function for the average

   cout<<avg<<" "<<lGrade(avg)<<endl;

Answer:

Ex: If the input is:

5 50 60 140 200 75 100

the output is:

50 60 75

The 5 indicates that there are five integers in the list, namely 50, 60, 140, 200, and 75. The 100 indicates that the program should output all integers less than or equal to 100, so the program outputs 50, 60, and 75.

For coding simplicity, follow every output value by a space, including the last one.

Such functionality is common on sites like Amazon, where a user can filter results.

#include <iostream>

#include <vector>

using namespace std;

int main() {

/* Type your code here. */

return 0;

}

when an external device becomes ready to be serviced by the processor the device sends a(n) interrupt signal to the processor

Answer:

okay if I am it administration I will port 10000

To configure the computer in the lobby to use the corporate proxy server, you will need to follow these steps:

Settings > Networks&Internet > Proxy > Manual Proxy Setup > Address & proxy > save

A proxy server is a device or router that acts as a connection point between users and the internet.

Proxy Server settings would be the same for both Wifi and Ethernet connections, explaining about the configuration in Windows Operating System.

Open the internet browser on the laptop and go to the settings or preferences page. The exact location of the proxy settings will vary depending on the browser you are using.

In the settings or preferences page, look for the "Proxy" or "Network" section.

In the proxy settings, select the option to use a proxy server.

Enter the address of the corporate proxy server in the "Server" or "Address" field.

Enter the port number "9000" in the "Port" field.

Save the changes and close the settings or preferences page.

Test the proxy server configuration by attempting to access a website. If the configuration is correct, the laptop should be able to access the internet through the proxy server.

Settings > Networks&Internet > Proxy > Manual Proxy Setup > Address & proxy > save

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Answer:

In case I am looking for a specific book in a library, the way in which I would try to find it would be through consulting the library guide, or through inspection of the different books of the specific sector with which the book I'm looking for is listed, or by asking the library staff to help me with my search.

Answer:

Explanation:

The following code is written in Javascript and is a function called primes that takes in a single parameter as an int variable named n. An array is created and looped through checking which one is prime. If So it, changes the value to true, otherwise it changes it to false. Then it creates another array that loops through the boolArray and grabs the actual numberical value of all the prime numbers. A test case for n=150 is created and the output can be seen in the image below highlighted in red.

function primes(n) {

   //Boolean Array to check which numbers from 1 to n are prime

   const boolArr = new Array(n + 1);

   boolArr.fill(true);

   boolArr[0] = boolArr[1] = false;

   for (let i = 2; i <= Math.sqrt(n); i++) {

      for (let j = 2; i * j <= n; j++) {

          boolArr[i * j] = false;

      }

   }

   //New Array for Only the Prime Numbers

   const primeNums = new Array();

  for (let x = 0; x <= boolArr.length; x++) {

       if (boolArr[x] === true) {

           primeNums.push(x);

       }

  }

  return primeNums;

}

alert(primes(150));

Using a combination method to determine how many ways can 18 people be divided into programming teams of 3 members, the number of programming teams can be arranged in 816 ways.

In mathematical model, a combination is a mathematical approach for calculating the number of potential arrangements in a set of things without taking the order arrangement of the items is into consideration.

It can be expressed by using the formula;

[tex]\mathbf{ _nC_r = \dfrac{n !}{ r!(n-r)! } }[/tex]

where:

[tex] \mathbf{ _nC_r = \dfrac{18!}{ 3!(18-3)! } }[/tex]

[tex]\mathbf{ _nC_r = \dfrac{18!}{ 3!(15)! } }[/tex]

[tex] \mathbf{ _nC_r = \dfrac{18 \times \: 17 \times \: 16 \times 15!}{ 3!(15)! } }[/tex]

[tex]\mathbf{ _nC_r = \dfrac{18 \times \: 17 \times \: 16 }{ 3 \times \: 2 \times 1} }[/tex]

= 816 ways

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Answer:

Currently, raster (bitmap files) and vector graphics are used in web design. But if you want to make a great logo and fully enjoy the use of it you should pick vector graphics for it in the first place. And this is why most designers opt for it.

Explanation:

Answer:

Please find the complete solution in the attached file.

Explanation:

In this question, the system for both the Savings account should also be chosen, the same should be done and for checking account. Will all stay same in. 

Answer:

yessss I tooo have a fire at my home

lolololololololololo

ok have a great day what is your name ?

Answer:

..... ....

.... .....

....................

....................

Answer:

The ping will change.

Explanation:

Assuming you mean ping from device with SIM card to another host (no mater what host), the ping will change. Ping changes even on the same device because network speed and performance of all the nodes on the route changes continuously. However, if two of your devices (phone & router) are configured differently (use different routing under the hood), then it will also affect the ping.

Answer:

See attachment for algorithm (flowchart)

Explanation:

The interpretation of the question is to design a flowchart for times 2 multiplication table (see attachment for the flowchart)

The explanation:

1. Start ---> Start the algorithm

2. num = 1 ---> Initializes num to 1

3. while num [tex]\le[/tex] 12 ---> The following loop is repeated while num is less than 12

 3.1 print 2 * num ----> Print the current times 2 element

 3.2 num++ ---> Increment num by 1

4. Stop ---> End the algorithm

Answer:

They demonstrate the behavior of system aspects.

The statement true regarding the dynamic design diagram is that it demonstrates the behavior change in the system. Thus, option C is correct.

A dynamic design diagram is given as the model that has been expressing the development of the operations, actions, and the behavior of the system over time.

The dynamic design diagram is thereby the demonstration of the behavior of system aspects. Thus, option C is correct.

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Answer:

A string, for example, is a data type that is used to classify text and an integer is a data type used to classify whole numbers. When a programming language allows a variable of one data type to be used as if it were a value of another data type, the language is said to be weakly typed. Hope it help's! :D

Answer:

Explanation:

This code was written in Java. It creates the Cars class with the requested variables and methods. It also creates the TestCars class which asks the user for the necessary inputs and then creates three Cars objects and passes the input values to the constructors. Finally, it uses the show() method on each object to call the information. A test has been created and the output can be seen in the attached image below.

import java.util.Scanner;

class TestCars{

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.print("Enter Car Make: ");

       String make1 = in.next();

       System.out.print("Enter Car Model: ");

       String model1 = in.next();

       System.out.print("Enter Car Year: ");

       int year1 = in.nextInt();

       System.out.print("Enter Car Make: ");

       String make2 = in.next();

       System.out.print("Enter Car Model: ");

       String model2 = in.next();

       System.out.print("Enter Car Year: ");

       int year2 = in.nextInt();

       System.out.print("Enter Car Make: ");

       String make3 = in.next();

       System.out.print("Enter Car Model: ");

       String model3 = in.next();

       System.out.print("Enter Car Year: ");

       int year3 = in.nextInt();

       Cars car1 = new Cars(make1, model1, year1);

       Cars car2 = new Cars(make2, model2, year2);

       Cars car3 = new Cars(make3, model3, year3);

       car1.show();

       car2.show();

       car3.show();

   }

}

class Cars {

   String makes, models;

   int years;

   public Cars(String makes, String models, int years) {

       this.makes = makes;

       this.models = models;

       this.years = years;

   }

   public void show() {

       System.out.println("Car's make: " + this.makes);

       System.out.println("Car's model: " + this.models);

       System.out.println("Car's year: " + this.years);

   }

}

Answer:

operating system (os)is translator between the operator (user)and the computer

Answer:

#include<iostream>

using namespace std;

int main()

{

  int a[20],n;

  int *p;

  cout<<"\n enter how many values do you want to enter:";

  cin>>n;

  for(int i=0;i<n;i++)

  {

      cout<<"\n Enter the "<<i+1 <<"th value :";

      cin>>*(p+i);

      //reading the values into the array using pointer

  }

  cout<<"\n The values in the array using pointer is:\n";

  for(int i=0;i<n;i++)

  {

      cout<<"\n (p+"<<i<<"): "<<*(p+i);

      //here we can use both *(p+i) or p[i] both are pointer subscript notations

  }

}

Output:

Answer:

The answer is "Option c".

Explanation:

This required user access policy is a tool used for a central authority that assigns access privileges depending on regulations.

It is a security method that limits the capacity of foreign firms to give or refuse access to a file program's resource objects.

It is a system that imposed access control on the premise of object labels and subject clearance. Such topics and items, like confidential, secret, and top-secret, have clearances and designations, appropriately.

Answer:

def main():

   name = input("What is your name? ")

   if not name == "" or "":

       age = int(input("What is your age? "))

       print("Hello " + name + "! You were born in " + str(2021 - age))

main()

Explanation:

Self explanatory

Answer:

fiikslid wugx uesbuluss wuz euzsbwzube

You could use recursion to write java method for computing fibonacci numbers. Though it will be inefficient for n > about 50, it will work.

public static int fibonacci(int n) {

if (n < 0) { return -1; }

if (n < 2) { return n; }

else { return fibonacci(n-1)+fibonacci(n-2); }

}

Hope this helps.

The current term of a Fibonacci series is derived by adding the two previous terms of its sequence; and the first two terms are 0 and 1.

The code segment (without comments) that completes the program is as follows:

int T1 = 0, T2 = 1, cT;

   if (n < 0){

       return -1;     }

   for (int i = 2; i <= n; i++) {

       cT = T1 + T2;

       T1 = T2;

       T2 = cT;     }

   return T2;

With comments (to explain each line)

/*This declares the first term (T1), the second term (T2) and the current term (CT).

T1 and T2 are also initialized to 0 and 1, respectively

*/

int T1 = 0, T2 = 1, cT;

//This returns -1, if n is negative

   if (n < 0){         return -1;    

}

//The following iterates through n

   for (int i = 2; i <= n; i++) {

//This calculates cT

       cT = T1 + T2;

//This passes T2 to T1

       T1 = T2;

//This passes cT to T2

       T2 = cT;

   }

//This returns the required term of the Fibonacci series

   return T2;

At the end of the program, the nth term of the series would be returned to the main method for output.

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Answer:

I still mad for that spam

Explanation:

Answer:

The bits are the smallest chunk of info that is used by computers.

Explanation:

Bit: A short abbreviation for binary digit which is the smallest unit of data.

You're welcome.

I hope I helped you.

Answer:

The list that would be helpful in this situation would be a list of people in the airport

Hope This Helps!!!

Answer:

Explanation:

The following is written in Java and uses a for loop to add 10 elements to the ArrayList since the first element is manually added as 1. Then it calculates each element by multiplying the previous element (saved in count) by 2. The program works perfectly and without bugs. A test output can be seen in the attached image below.

import java.util.ArrayList;

class Brainly {

   public static void main(String[] args) {

       ArrayList<Integer> numberList = new ArrayList<>();

       numberList.add(0, 1);

       int count = 1;

       for (int i = 1; i < 11; i++) {

           numberList.add(i, (count * 2));

           count = count * 2;

       }

       for (Integer i : numberList) {

           System.out.println(i);

       }

   }

}

Answer:

public void removePrefixStrings(List<String> list , String prefix) {

if(list==null || list.size()==0)

return;

for(int i=0; i<list.size();) {

if(list.get(i).startsWith(prefix))

list.remove(i);

else

++i;  

}  

}  

Time Complexity: If the prefix is the same as String length, Then finding all prefix match will take n *n = n2

Then removal is also n  

So the total time complexity is O(n3)