Now in pot experiments the most important point is to have the same number of plants per pot. To achieve this you plant more seeds and then you thin them after emergence to keep the same number of uniform plant per pot.
Now for calculating fertilizer rate of application in pots, you calculate according to soil weigh as you correctly indicated 2.2 M Kg/ha. You don't have to weigh the soil, just use the bulk density to calculate weigh from volume. Forget about space in pot experiment. you will have a lot of problems since pots have different shapes and forms!
Another recommandation mix soil and fertilizers for each treatment for the number of replicate pots. If you are using 5 replicates pot of 2 Kg soil/ pot, mix the fertilizers you want to apply to the 5 pots with 10 Kg of soil and after mixing well (preferably mechanically) distribute the same volume of soil in each one of the 5 pots.
If the amount of fertilizer to apply is small mix with some soil first and mix well before mixing to the whole soil. The idea is to have as much as possible, a uniform distribution.
You might also consider fractionating you nitrogen source if it will be leached.
Now according to the exact aim of your work other method sof fertilizationare possible.
Finally remember that maize is a mycorrhizal plant and this beneficial symbiosis can be influenced by the amount of soluble P you are adding.
Wishing you a lot of success in your work
hope it's help you plz mark as brain list.......!!!!!!!!!!!!!!!!
hope it will helps you
ashley here
HELLLPPPPP!!!!!!!!!!!!!!!!!!
Answer:
1}6 times
Step-by-step explanation:
The highest number of president born in Virginia minus the highest number of president born in Texas2}Yes.New York and Mast has the same number of president which is four
3}Yes,this can be done using piechart.
4}I am still working on this question
james cuts 2 of his neighbor's lawn the first is 1000 m long and 100 m wide what is the area
Step-by-step explanation:
The formula for area is l x b. This stands for length and breadth. I can multiply 1000(100) to get 100,000m. The area of the lawn is 100,000 m.
HOPE IT HELPS YOU
MARK ME BRAINLIEST
what is 5cd when c = 3 and d = 4
[tex] \sf \: c = 3 \\ \sf \: d = 4 \\ \\ \sf \: 5cd \: = \: ?\\ \\ \sf \:5 cd \hookrightarrow \\ \sf = 5 \times (3) \times (4) \\ \sf = 5 \times 12 \\ = \underline{ \bf \: 60}[/tex]
-> Just substitute the values given for variables c & d in the equation 5cd & you'll get the answer.
The ratio of Seema's age to the age of her mother is 5:12. The age difference is 21 years. What will be the ratio of Seema's age and her mother's age after three years?
Let ages of Seema and her mother be “5x” years and “12x” years respectively.
Difference between ages is 21 years
Hence,
12x - 5x = 21
7x = 21
x = 3
Therefore,
Age of Seema = 5 × 3 = 15 years
Age of her mother = 12 × 3 = 36 years
Ratio of ages after three years = ( 15+3 ) / (36+3 )
= 18 / 39
= 6 / 13
= 6 : 13
40) what is the area of a rectangular porch measuring 8 ft x 12/f
45) Create a stem and leaf plot to represent this set of data.
30, 62, 32, 63, 43, 77, 48, 78, 49, 82, 51, 84, 60,
please make sure to answer both questions
3000 dollars is invested in a bank account at an interest rate of 7 percent per year, compounded continuously. Meanwhile, 20000 dollars is invested in a bank account at an interest rate of 5 percent compounded annually.
To the nearest year, when will the two accounts have the same balance?
9514 1404 393
Answer:
after 89 years
Step-by-step explanation:
For principal p, interest rate r, and number of years t, the two account balances are ...
a = p·e^(rt) . . . . continuous compounding
a = p(1+r)^t . . . . annual compounding
Using the given values, we have
3000·e^(0.07t) . . . . . compounded continuously
20000·1.05^t . . . . . . compounded annually
We want to find t so these are equal.
3000·e^(0.07t) = 20000·1.05^t
0.15e^(0.07t) = 1.05^t . . . . divide by 20,000
ln(0.15) +0.07t = t·ln(1.05) . . . . take natural logarithms
ln(0.15) = t·(ln(1.05) -0.07) . . . . subtract 0.07t
t = ln(0.15)/(ln(1.05) -0.07) ≈ -1.8971/-0.02121 . . . . . divide by the coefficient of t
t ≈ 89.4 ≈ 89
The two accounts will have the same balance after 89 years.
30 points PLEASE HELP!!!!
Find the volume of the pyramid.
76.34 ft3
458.06 ft3
916.11 ft3
305.37 ft3
Answer:
916.11 ft³
Step-by-step explanation:
(9×6)×7.83/2×13/3
= 211.41×13/3
= 916.11 ft³
Answered by GAUTHMATH
Answer:
916.11 ft³
Step-by-step explanation:
The inequalities x < -5 and -X > -5 are the same.
True
False
QUESTION-:
The inequalities x < -5 and -X > -5 are the same.
True
False
ANSWER-:
FALSE
!! HOPE ITS HELP U !!
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!
Which ratio is not equivalent to the others?
A. 1:3
B. 36
C. 7 to 14
D. 816
Answer:
a. 1:3
Step-by-step explanation:
theres a pattern of x^2 but 1:3 is 1x3
Yeah uh I have no idea how to do this.....
Use exponent laws to simplify this :
9√(a^-5 b^2)
The answer is 9b / a^5/2 I just don't know how so please show steps! Thank you
Answer:
9b /a^5/2
Step-by-step explanation:
9√(a^-5 b^2)
9 sqrt( a^ -5 b^2)
Rewriting sqrt as ^1/2
9 ( a^ -5 b^2)^1/2
9 ( a^ -5) ^1/2 ( b^2)^1/2
we know that an exponent to an exponent means multiply
9 a^ (-5*1/2) b^(2*1/2)
9 a^-5/2 b^1
9b a^ -5/2
We know that x^-y = 1/x^y
9b /a^5/2
Answer:
[tex]\frac{9b}{a^{2} }[/tex][tex]\sqrt{\frac{1}{a} }[/tex] should be the answer of the problem that you posted
if you try to solve using [tex]\sqrt{x}[/tex] as as [tex]x^{\frac{1}{2} }[/tex]
then [tex](a^{-5)} ^{\frac{1}{2} } \\[/tex] = [tex](a^{-5/2)}[/tex] = [tex]\frac{1}{a^{\frac{5}{2} } }[/tex]
[tex]\frac{1}{a^{\frac{5}{2} } }[/tex] * 9b = [tex]\frac{9b}{a^{\frac{5}{2 } } }[/tex]
Step-by-step explanation:
[tex]9 \sqrt{(a^-5 b^2)}[/tex]
[tex]x^{-1} = \frac{1}{x}[/tex]
[tex]a^{-5} = \frac{1}{a^{5} }[/tex]
[tex]\sqrt{b^{2} } = b[/tex]
[tex]a^{4}[/tex] a's can be removed from the radicle (one will be left in because you have a^5)
[tex]\frac{9b}{a^{2} }[/tex][tex]\sqrt{\frac{1}{a} }[/tex]
please
[tex] \sin(120) \\ \tan( \frac{3\pi}{4} ) [/tex]
help me I need help
Answer:
[tex] \sin(120) \\ = \sin(90 + 30) \\ = \cos(30) \\ = \frac{ \sqrt{3} }{2} \\ \\ \tan( \frac{3\pi}{4} ) \\ = \tan(135) \\ = \tan(90 + 45) \\ = - \cot(45) \\ = - 1[/tex]
[tex]\\ \rm\longmapsto sin120[/tex]
[tex]\\ \rm\longmapsto sin(90+30)[/tex]
[tex]\\ \rm\longmapsto cos30[/tex]
[tex]\\ \rm\longmapsto \dfrac{\sqrt{3}}{2}[/tex]
Now
[tex]\\ \rm\longmapsto tan\left(\dfrac{2\pi}{4}\right)[/tex]
[tex]\\ \rm\longmapsto tan135[/tex]
[tex]\\ \rm\longmapsto -1[/tex]
square of 5x+1 by 5x
Answer:
5x(5x+1)^2
= 5x(25x^2+10x+1)
= 125x^3+50x^2+5x
Can someone plz tell me what’s 9% of 41
Answer:
3.69
Step-by-step explanation:
9% of 41 is (9/100)*41=369/100=3.69
PLEASE HELP WILL MARK BRAINLIEST
Answer:
I believe its negative nonlinear association
Step-by-step explanation:
The line is going down so its definitely negative
And the line is not straight so its not linear
Therefore, its negative nonlinear association
Answer the following questions using 125 words or more:
Write about the similarity of the original comic to the enlargement. How similar are they and how can you tell? What would cause differences in the two pictures? If you drew another comic using a grid, is there anything you would do differently?
What would happen if you reduced the comic's size rather than enlarged it? Would the process be the same? What would you do differently?
Link to video 2min https://media-release.glynlyon.com/g_mat08_ccss_2016/4/media/html5/anm_scale_drawing_comic_project/media/video.mp4
Answer:
given in a triangle rst and another triangle ratOn a coordinate plane, triangle R S T has points (0, 0), (negative 2, 3), (negative 3, 1). Triangle R prime S prime T prime has points (2, ...
9 votes
PLEASE HELP URGENT!!! QUESTION IS IN PICTURE PLEASE
Angle 3 and Angle 5 are corresponding angles. Corresponding angles lie in the same relative position. As such, they are congruent.
50x - 100 = 25x + 25
25x - 100 = 25
25x = 125
x = 5
Angle 3 = 50(5) - 100 = 250 - 100 = 150
Angle 5 = 25(5) + 25 = 125 + 25 = 150
Hope this helps!
Christian has 1/2 of a foot of tape. His friend gives him 3/10 of a foot of tape. How much tape does Christian have now?
Answer:
4/5 foot
Step-by-step explanation:
Add the lengths together
1/2 +3/10
Get a common denominator
1/2 *5/5 + 3/10
5/10 + 3/10
8/10
Simplify the fraction by dividing the top and bottom by 2
4/5
[tex]\rm \implies \: Total \: \: length \: \: of \: \: tape \: = \: \frac{1}{2} \: + \: \frac{3}{10} \\ [/tex]
Now , we take LCM of denominators.LCM of 2 and 10 is 10.[tex]\bf \large \rightarrow \: \: \frac{5 \: + \: 3}{10} \: = \: \frac{8}{10} \\ [/tex]
Now , simplifying the fraction in simplest form.
[tex]\bf \large \rightarrow \: \: \cancel\frac{8 \: \: ^{4} }{10 \: \: ^{5} } \: = \frac{4}{5} \\ [/tex]
Christian have 4/5 foot of tape have now.
What is the solution of x + 1/5 (x - 1) = 1?
Answer:
1
Step-by-step explanation:
x-1+ 1 /5*( x-1)=0
(x-1)*6/5=0
x=1
please help (picture) 25 points
Answer:
1) perimeter = sum of all the sides = 3y+9+2y+4+y+3+2y+4 = 8y+20
2) P = 4(5x-2) = 20x-8
1_tanA/1+tanA=cotA_1/cotA+1
Answer:
here,
L.H.S;
1-tanA / 1+tanA
=1-1/cotA / 1+1/cotA
= cotA-1/cotA / cotA+1/cotA
=cotA-1 / cotA+1
= R.H.S
proved
Answer:
if it's a math proof, i will think this is answer
Step-by-step explanation:
I need help I don't understand this.
9514 1404 393
Answer:
∠4 = 108°
Step-by-step explanation:
Angles 2 and 4 together form a "linear pair". That is, the sum of them is 180°, a "straight angle." They are supplementary.
∠4 = 180° -∠2 = 180° -72°
∠4 = 108°
The volume of a rectangular prism with a cone shaped hole in it is approximately 163.22cm³ (as shown below).
✏️ What is the height of the cone?
Answer:
Height of the cone = 5 cm
Step-by-step explanation:
Volume of the rectangular prism with a cone shaped hole = Volume of the rectangular prism - Volume of the cone
Volume of the rectangular prism = Length × Width × Height
= 5 × 5 × 7
= 175 cm³
Volume of the cone = [tex]\frac{1}{3}\pi r^{2}h[/tex]
Here, r = Radius of the cone
h = Height of the cone
Volume of the cone = [tex]\frac{1}{3}\pi (\frac{3}{2})^{2}(h)[/tex]
= 0.75πh cm³
Volume of the rectangular prism with a hole = 163.22 cm³
175 - 0.75πh = 163.22
0.75πh = 175 - 163.22
0.75πh = 11.78
h = 5 cm
Can someone help me out
Answer: V=9.4 cm^3
Step-by-step explanation:
[tex]V=\pi r^2h\\V=\pi (1)^2(3)\\V=9.4cm^3[/tex]
Which ratio represents $20 for every 4 cups of lemonade sold?
4/1 or 4,
1/5,
5/1 or 5
Answer:
5/1 or 5
Step-by-step explanation:
4 cup of lemonade is $20
then,
1 cup of lemonade is 20 ÷4 =5
Simplify the expression.
7(5 +t) - 4(t + 4)
7(5 + t) - 4(t + 4) = [
7(5 + t) - 4(t + 4) =
= 35 + 7t - 4t - 16 =
= 7t - 4t + 35 - 16 = 3t + 19
Round each to the nearest cent.
$879.190
and
$532.626
Answer:
$879.190 = $879.19
$532.626 = $532.627
Step-by-step explanation:
You round up for the tenths place if the hundredths place is above five, but you round down for the tenths place if the hundredths place is below five. For example, 0 is below five for $879.190, so I round to 9.
A circle has a circumference of 1{,}133.541,133.541, comma, 133, point, 54 units.
What is the diameter of the circle?
Answer: Radius is 21.2537 units, to 6 sig figs
Step-by-step explanation:
I'll assume the circumference is simply 133.541 units^2. Circumference (C) is C = 2*pi*R, where R is the radius. Thus, R = C/(2*pi),
R = (133.541/2*(3.14159) to 6 sig figs
R = 21.2537 units
The frequency table represents the job status of a number of high school students. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for job with entries 12, 38, 50. The third column is labeled not looking for a job with entries 28, 72, 100. The fourth column is labeled total with entries 40, 110, 150. Which shows the conditional relative frequency table by column? A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.3, nearly equal to 0.33, 1.0. The third column is labeled not looking for job with entries 0.7, nearly equal to 0.65, 1.0. the fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0. A 4-column table with 3 rows titled job status. The first column is blank with entries currently employed, not currently employed, total. The second column is labeled Looking for a job with entries 0.12, 0.38, 050. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.00. The fourth column is labeled total with entries 0.4, 1.1, 1.5. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.24, 0.76, 1.0. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.0. The fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for job with entries 0.08, nearly equal to 0.25, nearly equal to 0.33. The third column is labeled not looking for a job with entries nearly equal to 0.19, 0.48, nearly equal to 0.67. The f
Answer:
[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {0.24} & {0.28} & {0.27} & {Not\ Employed} & {0.76} & {0.72} & {0.73}& {Total} & {1} & {1} & {1} \ \end{array}[/tex]
Step-by-step explanation:
The question is not properly formatted (see attachment for the frequency table and the options)
Required
The conditional relative frequency table by column
We have:
[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {12} & {28} & {40} & {Not\ Employed} & {38} & {72} & {110}& {Total} & {50} & {100} & {150} \ \end{array}[/tex]
To get the conditional frequency by column, we simply divide each cell by the corresponding total value (on the last row)
So, we have:
[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {12/50} & {28/100} & {40/150} & {Not\ Employed} & {38/50} & {72/100} & {110/150}& {Total} & {50/50} & {100/100} & {150/150} \ \end{array}[/tex]
[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {0.24} & {0.28} & {0.27} & {Not\ Employed} & {0.76} & {0.72} & {0.73}& {Total} & {1} & {1} & {1} \ \end{array}[/tex]
Explain how to combine the terms 5x an 3x
Answer:
below
Step-by-step explanation:
In short, we will add both coefficients together to combine like terms.
3x + 5x → x(3 + 5) → 8x
If you have a value like 2x and 2, you cannot combine them because they do not have the same variable.
Best of Luck!
what is the value of x in a decagon
Answer:
x = 54
y = 144
Step-by-step explanation:
y = (10-2)×180/10 = 144
x = 180-90-(180-144) = 54
Answered by GAUTHMATH