Find the value of y

Help please

Given:

The equation is:

[tex]3-2|0.5x+1.5|=2[/tex]

One solution of this equation is -2.

To find:

The another solution of the given equation.

Solution:

We have,

[tex]3-2|0.5x+1.5|=2[/tex]

It can be written as:

[tex]-2|0.5x+1.5|=2-3[/tex]

[tex]-2|0.5x+1.5|=-1[/tex]

Divide both sides by -2.

[tex]|0.5x+1.5|=0.5[/tex]

After removing the modulus, we get

[tex]0.5x+1.5=\pm 0.5[/tex]

Case I:

[tex]0.5x+1.5=0.5[/tex]

[tex]0.5x=0.5-1.5[/tex]

[tex]0.5x=-1[/tex]

Divide both sides by 0.5.

[tex]x=-2[/tex]

Case II:

[tex]0.5x+1.5=-0.5[/tex]

[tex]0.5x=-0.5-1.5[/tex]

[tex]0.5x=-2[/tex]

Divide both sides by 0.5.

[tex]x=-4[/tex]

One solution of the given equation is [tex]x=-2[/tex] and the another one is [tex]x=-4[/tex].

Therefore, the correct option is B.

Répondre:

Benoit a 10 ans

Explication étape par étape :

Laisser :

Âge de Thomas = x

Benoit age = y

il y a 5 ans :

x - 5 = 5 (y - 5)

x - 5 = 5y - 25 - - (1)

Aujourd'hui :

x = 3y - - (2)

Mettez x = 3y dans (1)

3 ans - 5 = 5 ans - 25

Recueillir des termes similaires

3 ans - 5 ans = - 25 + 5

-2a = - 20

Diviser les deux côtés par - 2

y = 10

Answer:

565.2cm³

Step-by-step explanation:

the radius= 6/2= 3 cm

the height= 20cm

the volume= 3.14× 3²×20

= 3.14×180= 565.2 cm³

Check the picture below.

Answer:

14

Step-by-step explanation:

[tex]f(x) = {x}^{2} + 10 \\ \therefore \: f(2) = {2}^{2} + 10 \\ \therefore \: f(2) = 4 + 10 \\ \therefore \: f(2) = 14 \\ \\ g(x) = |x| \\ \therefore \:g(2) = |2| \\ \therefore \:g(2) = 2 \\ \\ f(2) + g(2) = 14 + 2 \\ \red{ \bold{(f + g)(2) = 14}}[/tex]

Step by step Explanation:

[tex]f(x) = x2 + 10g(x) = 1[/tex]

[tex](f + g)(2).[/tex]

Step 1

The equation is in standard form.

Step 2

Divide both sides by x.

Step 3

Dividing by x undoes the multiplication by x.

Step 4

Divide x 2 + 10 g x by x.

My Answer is.

Answer:

[tex]x=1,\\y=9[/tex]

Step-by-step explanation:

When solving a system of equations, one of the faster methods to solve this system is the process of elimination. This process involves manipulating one of the equations (by multiplying it by a certain value), such that when one adds the two equations in the system, one of the variables cancels. One can then solve for the other variable in the system. Then backsolve for the other variable; by substituting the value of the found variable into the system, simplifying and using inverse operations to solve for the other variable.

[tex]-6x=48-6y\\\\-4x=50-6y[/tex]

Manipulate, multiply one of the equations by a certain value such that the coefficient of the like term in the other equation is the additive inverse of it.

[tex](-6x=48-6y)*(-1)\\\\-4x=50-6y[/tex]

Simplify,

[tex]6x=-48+6y\\\\-4x=50-6y[/tex]

Add the equations in the system,

[tex]6x=-48+6y\\\\-4x=50-6y[/tex]

[tex](6x)+(-4x)=(-48)+(50)+(6y)+(-6y)[/tex]

Simplify,

[tex](6x)+(-4x)=(-48)+(50)+(6y)+(-6y)[/tex]

[tex]2x=2[/tex]

Inverse operations,

[tex]2x=2[/tex]

[tex]x=1[/tex]

Backsolve to find the value of (y).

[tex]-4x=50-6y[/tex]

[tex]x=1[/tex]

Substitute,

[tex]-4(1)=50-6y[/tex]

Simplify,

[tex]-4=50-6y[/tex]

Inverse operations,

[tex]-4=50-6y[/tex]

[tex]-54=-6y[/tex]

[tex]9=y[/tex]

Answer:

a) 120°

Step-by-step explanation:

i think this is the right answer

Answer:

[tex] {x}^{3} + 5 {x}^{2} - x - 5 \\ {x}^{2} (x + 5) - 1(x + 5) \\ (x + 5)( {x}^{2} - 1)[/tex]

What is the value of tan in the unit circle below?

The value of tan in the unit circle below is

[tex] \frac{ \sqrt{3} }{2} [/tex]

Note:- Please attach the full question next time.

Answer:

car(c.p)=$8400

Step-by-step explanation:

L%=(c.p-s.p)100%

c.p

10%=(c.p-7560)100%

c.p

10c.p=100c.p-756,000

(10-100)c.p= -756,000

-90c.p= -756,000

-90 -90

c.p=8400

Answer:

(10, - 1 )

Step-by-step explanation:

Given the 2 equations

x - 3y = 13 → (1)

x + 2y = 8 → (2)

Rearrange (1) making x the subject by adding 3y to both sides

x = 3y + 13 → (3)

Substitute x = 3y + 13 into (2)

3y + 13 + 2y = 8

5y + 13 = 8 ( subtract 13 from both sides )

5y = - 5 ( divide both sides by 5 )

y = - 1

Substitute y = - 1 into (3) for corresponding value of x

x = 3(- 1) + 13 = - 3 + 13 = 10

solution is (10, - 1 )

Step-by-step explanation:

Simple interest=principal x rate x time÷100

amount borrowed=$500

I=$500x7x6÷100

I=$210

therefore you will pay

amount borrowed+interest

$500+$210

$710

hope this is helpful

Answer:

[tex]{ \bf{15x + 30 = 180}}[/tex]

Answer:

Moving 4 to the right on the x axis

Answer:

C. 16 mi.

Step-by-step explanation:

This situation forms a right triangle: the distances 32 miles south and 24 miles east are the legs, and the original southeast course is the hypotenuse.

Use the pythagorean theorem, a² + b² = c² to solve for c, the length of the southeast course.

a² + b² = c²

32² + 24² = c²

1600 = c²

40 = c

So, the southeast course is 40 miles long.

Find how many miles the pilot traveled on the alternate route:

32 + 24

= 56

Find the difference in extra miles:

56 - 40

= 16

So, the pilot was forced to fly 16 extra miles.

The correct answer is C. 16 mi.

Answer:

16

Step-by-step explanation:

On Edge 2022

Answer:

the answer is already in the question

D. 130°

D. 130

Answer:

Step-by-step explanation:

Given a triangle with angles 60° and 60°. Let the third angle be represented by x, so that;

x + 60° + 60° = [tex]180^{o}[/tex] (sum of angle in a triangle)

x + 120 = [tex]180^{o}[/tex]

x = [tex]180^{o}[/tex] - 120

x = 60°

Thus, since the third angle of the triangle is 60°, then the triangle is an equilateral triangle. For an equilateral triangle, all sides are equal and all its angles are equal. So that the other sides of the triangle is 10 each.

<ABC ≅ <BAC ≅ < ACB ≅ 60°

AB = BC = AC = 10 cm

The required construction for the question is attached to this answer for more clarifications.

Answer:

It's an obtuse angle

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

Given equation of the Circle is ,

[tex]\sf\implies x^2 + y^2 = 25 [/tex]

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

[tex]\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2[/tex]

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

[tex]\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }[/tex]

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

Answer:

these points lie INSIDE THE CIRCLE

Hope it helps

have a nice day

Answer:

Step-by-step explanation:

Answer:

hello there

here is your answer:

120 miles

Step-by-step explanation:

because every 30 mile jayce drives is by 1 hour.

jayce  travels for 4 hours so that 120 miles

also because you can mutiply 30*4=120

hope this helps have a good day bye

Answer:

m(x)

Step-by-step explanation:

Answer:

3/5

Step-by-step explanation:

prependicular / hypotenuse

sin C=ED/CD

=3/5

Answer:

Quadratic.

Step-by-step explanation:

Both linear and exponential equations are monotone increasing or monotone decreasing functions.

This means that, as the input increases, the output will only increase or only decrease, but never both.

Here for our data, we can see that first we have:

x = -8

y = 13

Then x increases to x = -6, and y decreases to y = 9

Then x increases to x = -4 and y increases to y = 13

Then this function is not monotone increasing nor monotone decreasing, so the data can not describe a linear nor an exponential function.

Then the correct option is quadratic.

Answer:

5/14

Step-by-step explanation:

There are 15 tiles in total

5 white| 6 black | 4 blue

event A results in the subject pulling a white tile and not replacing it

5-1= 4

so the first answer should be 4/15

event B results in the subject pulling another tile, a black one and not replacing it.

6-1= 5

given this answer, there is one less tile in the total, since we removed another tile.

So our answer would be-

5/14 or D

Answer:

5

Step-by-step explanation:

Have a phd in mathematics! Congrats on your first question!!!! Send me a brainlist :)

Answer:

Step-by-step explanation:

Perimeter of the rectangle = P

Base = b

Height = h

Area = A

P = 2b + 2h

P = 66

STEP 1:

2(2x + 1) + 2(x + 5) = 66

Distribute

4x + 2 + 2x + 10 = 66

STEP 2:

Combine like terms and isolate the variable

6x + 12 = 66

6x = 54

x = 9

STEP 3:

Plug in x

A = (2(9) + 1) * (9 + 5)

STEP 4:

Simplify

A = (18 + 1) * (14)

A = (19)(14)

A = 266

[tex]\displaystyle\bf P=2(2x+1+x+5)=66\\\\6x+12=66\\\\6x=54\\\\\boxed{x=9}\\\\2x+1=19\\\\x+5=14 \\\\S=ab=14\cdot19=266 cm^2[/tex]

Answer:

[tex]\frac{4}{3}\:\mathrm{cm^2}[/tex]

Step-by-step explanation:

The area of a trapezoid can be found by multiplying the average of its bases and its height.

We're given:

To find the average of a set of [tex]n[/tex] values, add all the values in the set and divide by [tex]n[/tex]. Therefore, to find the average of the two bases, we add 4 to 12 and divide by 2.

The average of the bases is therefore [tex]\frac{4+12}{2}=\frac{16}{2}=8[/tex]

Thus, the area of the trapezoid is [tex]8\cdot \frac{1}{6}=\frac{8}{6}=\boxed{\frac{4}{3}\:\mathrm{cm^2}}[/tex]

Answer:

8 - 4[tex]\sqrt{3}[/tex]

Step-by-step explanation:

Given: [tex]\frac{26}{4 + \sqrt{3} }[/tex]

To express the given question in the form a + b[tex]\sqrt{3}[/tex], we first have to rationalize the denominator of the expression.

Rationalizing the denominator, we have;

[tex]\frac{26}{4 + \sqrt{3} }[/tex] * [tex]\frac{4 - \sqrt{3} }{4 - \sqrt{3} }[/tex]  = [tex]\frac{104 -26\sqrt{3} }{16 -4\sqrt{3} + 4\sqrt{3}- 3 }[/tex]

= [tex]\frac{104 - 26\sqrt{3} }{16 - 3}[/tex]

 = [tex]\frac{26(4 - \sqrt{3} }{13}[/tex]

= 2(4 - [tex]\sqrt{3}[/tex])

= 8 - 4[tex]\sqrt{3}[/tex]

The required form of the given question is therefore 8 - 4[tex]\sqrt{3}[/tex]

Answer:

$3

Step-by-step explanation:

Let c represent the cost of a box of cereal and let m represent the cost of a jug of milk.

Create a system of equations:

2c + m = 8.5

3c + 2m = 14

Solve by elimination by multiplying the top equation by -2:

-4c - 2m = -17

3c + 2m = 14

Add them together and solve for c:

-c = -3

c = 3

So, a box of cereal costs $3

A box of cereal cost $3 if two boxes and a jug of milk cost $8.50, and three boxes and two jugs of milk cost $14.00.

An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.

It is given that, two boxes of cereal and a jug of milk cost $8.50, and three boxes of cereal and two jugs of milk cost $14.00

Let c stand for the price of a box of cereal and m for the price of a milk jug.

The obtained system of equations is as follows,

2c + m = 8.5

3c + 2m = 14

Multiply the top equation by -2 to reach the solution by elimination:

-4c - 2m = -17

3c + 2m = 14

Put them all together to find c:

-c = -3

c = 3

Thus, a box of cereal cost $3 if two boxes and a jug of milk cost $8.50, and three boxes and two jugs of milk cost $14.00.

Learn more about the equation here,

https://brainly.com/question/10413253

#SPJ2

Answer:

6 yds

Step-by-step explanation:

If we label the shorter side as x, the longer side can be represented as 2x + 2. Now, we can write an equation to model the situation. The area of a rectangle is the sides multiplied by each other:

84 = x(2x + 2)

84 = 2x^2 + 2x

Since all terms are divisible by two, we can divide both sides by it:

42 = x^2 + x

We can write the quadratic equation in standard form:

x^2 + x - 42 = 0

Now, we can factor. We are looking for numbers that multiply to -42 and add to 1. These numbers are 7 and -6. Factored the equation would be written as followed:

(x + 7)(x - 6) = 0

Using the zero-product property, we can obtain two equations and solve them:

x + 7 = 0

x  = -7

x - 6 = 0

x = 6

Since the side of a rectangle can't be negative, the answer must be 6 yds.