Find the surface area of the prism. Write your answer as a fraction or mixed number.

Find The Surface Area Of The Prism. Write Your Answer As A Fraction Or Mixed Number.

Answers

Answer 1

Answer:

The surface area of the prism is 8/3ft²

Step-by-step explanation:

To calculate the surface area of the prism we have to use the following formula:

a = area

w = side = 2/3 ft

h = height = 2/3 ft

l = length = 2/3 ft

a = 2 * (w * h) + 2 * (w * l) + 2 * (h * l)

we replace the values that ​​we know        

v = 2 * (2/3 ft * 2/3 ft) + 2 * (2/3 ft * 2/3 ft) + 2 * (2/3 ft * 2/3 ft)

v = 2 * 4/9ft²  + 2 * 4/9ft²  + 2 * 4/9ft²

v = 8/9ft²  + 8/9ft²  + 8/9ft²

v = 24/9ft²

v = 8/3ft²

The surface area of the prism is 8/3ft²

Answer 2

Answer:

2⅔ ft²

Step-by-step explanation:

A cube has 6 square faces

6 × (⅔)²

6 × 4/9

8/3

2⅔


Related Questions

At the beginning of the month, Tim has $50. He mows 2 lawns and washes 1 car. Then, he buys two video games that cost $15 each and a sweatshirt that costs $35. How much money does Tim have left? (please put just your answer with the $)

Answers

Answer:

Tim has $50. 15+15=30-35=5

Tim has $5 left

If the product of two whole numbers is zero then one number will be (ii) If the product of two whole numbers is zero then both number will be zero (a) OnlyIcanbetrue(b)onlyiicanbetrue(c)Bothcanbetrue(d)botharefalse

Answers

Answer:

If the product of two numbers is zero, there are two possibilities, namely;

1. One of the numbers is zero.

2. Both of the numbers are zero.

Step-by-step explanation:

As a rule in mathematics, when zero is used in multiplying any given whole number, the only result that would be obtained is zero.

Therefore,

1. If one of the numbers is zero, then the product of the two numbers is also zero. For example,

153, 000 * 0 = 0

2.  If both of the numbers are zero, then the product of the two numbers is zero. For example,

0 * 0 = 0.

So we can say that both can be true.

how much money does ron have each month

Answers

Answer:

after paying all expenses Ron will have $10 leftover each month.

Answer:

10 on edge

Step-by-step explanation:

I have 8 red Valentine card and 2 pink. How many reds and pinks would I need to add to my collection so that the proportion of pink is 44%? ​

Answers

Answer:

88%

Step-by-step explanation:

6 mor to go thanks you

Answers

Answer:

BGC

Step-by-step explanation:

They are both on a straight line and add up to 180 degrees.

BE5-3 Cha Company buys merchandise on account from Wirtz Company. The selling price of the goods is $780, and the cost of the goods is $470. Both companies use perpetual inventory systems. Journalize the transaction on the books of both companies.

Answers

Answer:

In the books of Wirtz, the selling party, the required entries are

Debit Accounts receivable $780

Credit Revenue $780

Being entries to recognize sales revenue on account

Debit Cost of sales $470

Credit Inventory  $470

Being entries to recognize the cost of items sold

In the books of Cha Company

Debit Inventory $780

Credit Accounts payable  $780

Being entries to record cost of inventory purchased

Step-by-step explanation:

When a company makes a sale, the effect of such sale is dual in the books of the company being that the company would first recognize revenue and then recognize the cost of items sold.

To recognize revenue,

Debit Cash/Accounts receivable

Credit Revenue

To record the cost of the item sold

Debit Cost of sales

Credit Inventory

For the party that makes the purchase

Debit Inventory

Credit Cash/Accounts payable

What is the distance between points A(13, 2) and B(7, 10)

Answers

Answer:

distance = sqrt((x2-x1)^2 + (y2-y1))

distance = sqrt((7-13)^2 + (10-2)^2)

distance = sqrt( -6^2 + 8^2)

distance = sqrt(36+64)

distance = 10

Step-by-step explanation:

Answer:

10 units

Step-by-step explanation:

d = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

d = [tex]\sqrt{(13 - 7)^2 + (2 - 10)^2}[/tex]

d = [tex]\sqrt{(6)^2 + (-8)^2}[/tex]

d = [tex]\sqrt{36 + 64}[/tex]

d = [tex]\sqrt{100}[/tex]

d = 10 units

Divya’s recipe calls for 3.25 pounds of beef, 0.65 pounds of onions, 0.2
pounds of potatoes, 0.15 pounds of tomatoes, and 0.33 pounds of asparagus.

How much will Divya pay for all the ingredients in the recipe? Show your work.

Answers

The beef price is $10.65

Onions price is $2.49

Potatoes are $3.29

Tomatoes are $8.45

Asparagus is $4.99

3.25 pounds of beef is          3.25 * 10.65 =  34.61

0.65 pounds of onions is      0.65 * 2.49   =  1.62

0.2 pounds of potatoes is     0.2 * 3.29     =  0.66

0.15 pounds of tomatoes is   0.15 * 8.45   =  1.27

0.33 pounds of asparagus is 0.33 * 4.99  =  1.65

Adding these up we get 34.61 + 1.62 + 0.66 + 1.27 + 1.65

This is equal to 39.81

                                           

A recipe is mixture of ingredients.

Divya will pay $39.81 for all the ingredients in the recipe.

The beef price is $10.65 per pound

So, price of 3.25 pounds of beef is ,  [tex]3.25 * 10.65 = 34.61[/tex]

Onions price is $2.49 per pound

So, price of 0.65 pounds of onions is,  [tex]0.65 * 2.49 = 1.62[/tex]

Potatoes are $3.29 per pound

So, price of 0.2 pounds of potatoes is ,  [tex]0.2 * 3.29 = 0.66[/tex]

Tomatoes price are $8.45 per pound.

So, price of 0.15 pounds of tomatoes is  , [tex]0.15 * 8.45 = 1.27[/tex]

Asparagus price is $4.99 per pound.

So, price 0.33 pounds of asparagus is , [tex]0.33 * 4.99 = 1.65[/tex]

Hence, total amount paid by Divya is,

             [tex]=34.61 + 1.62 + 0.66 + 1.27 + 1.65=39.81[/tex]

Thus, Divya will pay $39.81 for all the ingredients in the recipe.

Learn more:

https://brainly.com/question/18994792

What is the correct answer?

Answers

Answer:45

Step-by-step explanation:

Sin^-1= 5÷7

Josh is making a rectangular-shaped picture frame. The length of the frame is to be 5 inches more than twice the width. Which equation models the area, A, of the frame in terms of the width, w?

Answers

Answer:

A=2x^2+5x

Step-by-step explanation:

length of frame = 2x+5

width of frame = x

A=lw

A=(2x+5)x

A=2x^2+5x

The student body of 10 students want to elect a president, vice president, secretary, and treasurer.


A) Permutation

B) Combination

C) Circular permutation

Answers

Answer:

a

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Which expression is equivalent to (4 + 7(3 + 41)?
-16+37i
12-28i
16-37i
37+16i

Answers

Answer:

C

Step-by-step explanation:

Need help ASAP, marking first as brainliest. Rlly appreciate it.

Answers

Answer:

Choose answers B and D

Step-by-step explanation:

Answer:

Choose answers B and D.

Step-by-step explanation:

Una escalera está apoyada sobre la fachada de un edificio. Si la escalera mide 10 m de longitud y el pie de la escalera está a 5 m de la pared, ¿a qué altura de la pared llega la escalera? Expresa el resultado con radicales extrayendo todos los factores posibles.

Answers

Answer:

8.66 meters

Step-by-step explanation:

Assuming that the building is completely straight, a right angle is formed and therefore a right triangle.

Thanks to this we can calculate the height at which the ladder reaches the wall using the Pythagorean theorem, this height being one of the legs.

We have to:

c ^ 2 = a ^ 2 + b ^ 2

c = 10

a = 5

replacing

b ^ 2 = 10 ^ 2 - 5 ^ 2

b ^ 2 = 75

b = 8.66

that is to say that the height at which the ladder reaches the wall is 8.66 meters

Find the height of a right cylinder with surface area 240π ft2 and radius 5 ft.

The height of the right cylinder is __
ft.

Answers

Answer:

h ≈ 2.64ft

Step-by-step explanation:

A = 2πrh + 2πr2

h= A /2πr﹣r = 240 /2·π·5﹣5 ≈ 2.63944ft

Kono Dio Da!!

Secant TQ and tangent TR intersect at point T. Chord SR and chord PQ intersect at point V. Find the values of x and y. If necessary, round to the nearest tenth.

Answers

Answer:

x=4, y=9.6

Step-by-step explanation:

Using Theorem of Intersecting Secant and Tangent

[tex]TP X TQ=TR^2[/tex]

[tex]9(9+12+x)=15^2\\9(21+x)=225\\189+9x=225\\9x=225-189\\9x=36\\x=4[/tex]

Next, we apply Theorem of Intersecting Chords

SV X VR=PV X VQ

5 X y = x X 12

Recall: x=4

5y=4 X 12

5y=48

y=48/5=9.6

Therefore: x=4, y=9.6

Four students spoke to the Home and School parents for a total of 2/3 hour. Each student spoke for the same amount of time. How long did each student speak?

Answers

creo que la respuesta el 10 minutos, porque dice "horas" pero no dice a cuantas horas equivale :)      espero que te aya adudado auque sea un poquito

GEOMETRY DESPERATE HELP

Answers

Answer: Choice C) [tex]x^2 + (y-2)^2 = 4[/tex]

==========================================================

Explanation:

The center is at (0,2). So (h,k) = (0,2) leads to h = 0 and k = 2.

The radius is 2 units, meaning r = 2.

Plug h = 0, k = 2, r = 2 into the formula below and simplify

[tex](x-h)^2 + (y-k)^2 = r^2\\\\(x-0)^2 + (y-2)^2 = 2^2\\\\x^2 + (y-2)^2 = 4[/tex]

How do I solve this problem? I need to find the volume of this composite figure.

Answers

Step-by-step explanation:

V = (12*4*5) + (2*3*5) + (5*3*5) + (12*4*5)

V = 240 + 30 + 75 + 240

V = 585 cm^3

Find the volume of the figure

Answers

Answer:

450

Step-by-step explanation:

Compare the ordered pairs of the pre-image to the
image to answer these questions.
Is the dilation an enlargement or reduction?
The point of dilation is about what coordinate?
What is the scale factor?
Pre-image

Answers

Answer: Reduction

(0,0)

1/3

Step-by-step explanation:

Answer:

1-reduction

2-(0,0)

3-1/3

Step-by-step explanation:

If 3x and 71/x are two prime numbers V x equivalent to R, then number of x so that 3x + 71/x = 10 is/ are

Answers

Answer:

x = 5/3

Step-by-step explanation:

Guven two prime numbers to be 31/x and 71/x, if their sum is 10 as given;

3x + 71/x = 10 then to find the value of x, the following steps must be taken;

Step 1

Find the LCM of the given equation;

3x + 71/x = 10

[tex]\frac{3x^{2}+71 }{x} =10\\[/tex]

Step 2:

Cross multiplying;

[tex]3x^{2} +71=10x\\3x^{2} -10x+71 =0\\[/tex]

Using the general formula to get the value of x;

x = -b±√b²-4ac/2a

a=3, b=-10, c=71

= 10±√(-10)²-4(3)(71)/2(3)

= 10±√100-852/6

= 10±√-752/6

= 10±27.4i/6

= 10+27.4i/6 or 10-27.4i/6

x = 5/3+27.4i/6 or 5/3-27.4i/6

Since the values of x are real values then, our answer will be the real part of the complex number gotten.

x = 5/3

Which expressions are equivalent to g+h+(j+k) Check all that apply

Answers

Answer:

g+h+(j+k)

Step-by-step explanation:

(g+h)+j+k

(g+k)+j+h

(g+j)+h+k

(k+h)+j+h

(j+h)+g+k

Answer:

1 and 3

Step-by-step explanation:

dont mind me this needed to be longer wait still needs no be longer

1. If 5tanA=4, Find the value of (5sinA-3cosA)/(4cosA+5sinA)
2. Solve for θ, sinθ/(1+cosθ) + (1+cosθ)/sinθ =4, 0°<θ<90°
3. Prove that tan⁡〖θ-cot⁡θ 〗 = (〖2sin〗^2 θ-1)/sinθcosθ
4. Without using trigonometric tables ,show that
tan 10°tan15°tan75°tan80°=1
5. If x=acosθ-bsinθ and y=asinθ + bcosθ prove that x^2+y^2=a^2+b^2

Answers

Answer:

1. (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A))  = 1/8

2. θ = 30°

3. tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

from tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ) and sin²(θ) +  cos²(θ) = 1

4. tan10°·tan15°·tan75°·tan80°= 1 from;

sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]

cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]

5. x² + y² = a² + b² where x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ from;

cos²θ + sin²θ = 1

Step-by-step explanation:

1. Here we have 5·tan(A) = 5·sin(A)/cos(A) = 4

∴ 5·sin(A) = 4·cos(A)

Hence to find the value of (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) we have;

Substituting the value for 5·sin(A) = 4·cos(A) into the above equation in both the numerator and denominator we have;

(4·cos(A) - 3·cos(A)/(4·cos(A) + 4·cos(A)) = cos(A)/(8·cos(A)) = 1/8

Therefore, (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) = 1/8

2. For the equation as follows, we have

[tex]\frac{sin \theta}{1 + cos \theta} + \frac{1 + cos \theta}{sin \theta} = 4[/tex] this gives

[tex]\frac{2sin (\theta/2) cos (\theta/2) }{2 cos^2 (\theta/2)} + \frac{2 cos^2 (\theta/2)}{2sin (\theta/2) cos (\theta/2) } = 4[/tex]

[tex]tan\frac{\theta}{2} + \frac{1}{tan\frac{\theta}{2} } = 4[/tex]

[tex]tan^2\frac{\theta}{2} + 1 = 4\times tan\frac{\theta}{2}[/tex]

[tex]tan^2\frac{\theta}{2} - 4\cdot tan\frac{\theta}{2} + 1 = 0[/tex]

We place;

[tex]tan\frac{\theta}{2} = x[/tex]

∴ x² - 4·x + 1 = 0

Factorizing we have

(x - (2 - √3))·(x - (2 + √3))

Therefore, tan(θ/2) = (2 - √3) or (2 + √3)

Solving, we have;

θ/2 = tan⁻¹(2 - √3) or tan⁻¹(2 + √3)

Which gives, θ/2 = 15° or 75°

Hence, θ = 30° or 150°

Since 0° < θ < 90°, therefore, θ = 30°

3. We have tan(θ) - cot(θ) = tan(θ) - 1/tan(θ)

Hence, tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ)

∴  tan(θ) - 1/tan(θ) = (sin²(θ) -  cos²(θ))/(cos(θ)×sin(θ))...........(1)

From sin²(θ) +  cos²(θ) = 1, we have;

cos²(θ) = 1 - sin²(θ), substituting the value of sin²(θ) in the equation (1) above, we have;

(sin²(θ) -  (1 - sin²(θ)))/(cos(θ)×sin(θ)) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

Therefore;

tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

4. tan10°·tan15°·tan75°·tan80°= 1

Here we have since;

sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]

cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]

Then;

tan 10°·tan15°·tan75°·tan80° = tan 10°·tan80°·tan15°·tan75°

tan 10°·tan80°·tan15°·tan75° = [tex]\frac{sin(10^{\circ})}{cos(10^{\circ})} \times \frac{sin(80^{\circ})}{cos(80^{\circ})} \times \frac{sin(15^{\circ})}{cos(15^{\circ})} \times \frac{sin(75^{\circ})}{cos(75^{\circ})}[/tex]

Which gives;

[tex]\frac{sin(10^{\circ}) \cdot sin(80^{\circ})}{cos(10^{\circ})\cdot cos(80^{\circ})} \times \frac{sin(15^{\circ}) \cdot sin(75^{\circ})}{cos(15^{\circ})\cdot cos(75^{\circ})}[/tex]

[tex]=\frac{1/2[cos(80 - 10) - cos(80 + 10)]}{1/2[cos(80 - 10) + cos(80 + 10)]} \times \frac{1/2[cos(75 - 15) - cos(75 + 15)]}{1/2[cos(75 - 15) + cos(75 + 15)]}[/tex]

[tex]=\frac{1/2[cos(70) - cos(90)]}{1/2[cos(70) + cos(90)]} \times \frac{1/2[cos(60) - cos(90)]}{1/2[cos(60) + cos(90)]}[/tex]

[tex]=\frac{[cos(70)]}{[cos(70) ]} \times \frac{[cos(60)]}{[cos(60) ]} =1[/tex]

5. If x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ

∴ x² + y² = (a·cosθ - b·sinθ)² + (a·sinθ + b·cosθ)²

= a²·cos²θ - 2·a·cosθ·b·sinθ +b²·sin²θ + a²·sin²θ + 2·a·sinθ·b·cosθ + b²·cos²θ

= a²·cos²θ + b²·sin²θ + a²·sin²θ + b²·cos²θ

= a²·cos²θ + b²·cos²θ + b²·sin²θ + a²·sin²θ

= (a² + b²)·cos²θ + (a² + b²)·sin²θ

= (a² + b²)·(cos²θ + sin²θ) since cos²θ + sin²θ = 1, we have

= (a² + b²)×1 = a² + b²

The combined weight of Maia and Vashti is 102.45kg. If Maia weighs 2.15kg more than Vashti, calculate Vashti's weight.





Answers

Answer:

50.32 I think

Step-by-step explanation:

52,13+50,32=102.45

Vashti’s weight is 50.15kg Hope this helped!

PLEASE HELP!!!! NEED ANSWER ASAP

Answers

Answer:

X=25

Step-by-step explanation:

Since these 2 angles are vertically opposite angles so they are equal. (rule)

75°=(4x-25°)

75° + 25° = 4x

100=4x

X=100/4 = 25

___________

Hope this helps...

Margo can purchase tile at a store for $0.89 per tile and rent a tile saw for $45. At another store she can borrow the tile saw for free if she buys tiles there for $1.39 per tile. How many tiles must she buy for the cost to be the same at both stores?


Margo must buy ____ tiles for the cost to be the same at both stores.

Answers

Answer:

She must buy 90 tiles for the cost to be the same at both stores

Step-by-step explanation:

Let x be the no. of tiles bought for the cost to be the same at both stores

Margo can purchase tile at a store for $0.89 per tile at shop 1

Cost of x tiles =0.89x

She rent a tile saw for $45.

So, total cost at Store 1 = 0.89x+45

At another store she can borrow the tile saw for free if she buys tiles there for $1.39 per tile.

So, cost of 1 tile = 1.39

Cost of x tiles = 1.39x

ATQ

0.89x+45=1.39x

45=1.39x-0.89x

45=0.5x

[tex]\frac{45}{0.5}=x[/tex]

90=x

Hence She must buy 90 tiles for the cost to be the same at both stores

Which number is composite ??? A.11 B.5 C.9 D.2

Answers

Answer:

the correct answer is 9

The expression two square root of three minus square root of 27 is equivalent to

Answers

Answer:

-0.954(rounded)

Step-by-step explanation:

first write it in number form

√2(3)-√27

the exact form will be 3√2-3√27 = -0.954(rounded)

It’s rounded to 0.954

what is a=1/4 b if b is the subject?

Answers

Answer:

b = 4a

Step-by-step explanation:

Given

a = [tex]\frac{1}{4}[/tex] b

Multiply both sides by 4 to clear the fraction

4a = b

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