find the surface area of prism

Answer:

you never showed the chocies

Step-by-step explanation:

Step-by-step explanation:

Pls Mark me

Answer:

d. The relationship between a and b cannot be determined.

Step-by-step explanation:

Given

[tex]a < 0[/tex]

[tex]b > 0[/tex]

Required

Which is true

To do this, we test each of the options using assumed values

[tex]a + b > 0[/tex]

Let:

[tex]a = -5[/tex]       [tex]b= 1[/tex]

So:

[tex]-5 + 1 > 0[/tex]

[tex]-4 > 0[/tex] --- false

[tex]a + b < 0[/tex]

Let:

[tex]a = -5[/tex]       [tex]b= 7[/tex]

So:

[tex]-5 + 7 < 0[/tex]

[tex]2 < 0[/tex] --- false

[tex]a + b = 0[/tex]

Let:

[tex]a = -5[/tex]       [tex]b= 7[/tex]

So:

[tex]-5 + 7 = 0[/tex]

[tex]2 = 0[/tex] --- false

Hence, the relationship is not specific and cannot be determined

Answer:

80

Step-by-step explanation:

15 percent of 80 is 12

and 12 is 60 percent of 80!

hope this helps :)

9514 1404 393

Answer:

  $18

Step-by-step explanation:

The interest is computed using the formula ...

  I = Prt

where P is the principal, r is the annual rate, and t is the number of years. The interest is ...

  I = $600×0.03×1 = $18

Answer:

-2 > x

Step-by-step explanation:

14 <-7x

Divide each side by -7, remembering to flip the inequality

14/ -7 > -7x/-7

-2 > x

Answer:

1) D(1,0), C(-2,-4)  or 2) D(9,0), C(6,-4)

Step-by-step explanation:

The vector AB is (2-5, -1-3)= (-3,-4)

The modul of the vector is equal to sqrt (3squared+4squared)=5 (the length of the side AB of square)

Explore the point D (the coordinates of the point is (x,0), y=o, because it is an axis x). AD (x-5, -3)

The modul of AD is sqrt ((x-5)^2+(-3)^2)= sqrt (x^2-10x+25+9), it is equal to the side AD which is equal to AB

sqrt(x^2-10x+34)= 5

x^2-10x+34=25

x^2-10x+9=0

x=1, x=9

D is (1,0) or D is (9,0),

find C, (for D1(1,0))

Find the midpoint of BD (O)

xo= (2+1)/2= 1.5

y0=(-1+0)/2= -0.5

It is the midpoint of Ac too

x0= (xa+xc)/2    1.5 = (5+xc)/2  xc= -2

y0=(ya+yc)/2      -0.5= (3+yc)/2   yc=-4

c(-2,-4)

Find C2 (for D(9,0))

Find the midpoint of BD (O)

x0= (2+9)/2=5.5

y0= (-1+0)/2=-0.5

o(5.5, -0.5)

It is the midpoint of Ac too

x0= (xa+xc)/2   5.5= (5+x)/2   x=6

y0=(ya+yc)/2    -0.5= (3+x)/2  y=-4

Let the numbers are x and y

According to the question

⇒x+y=1000.....eq1⇒x 2 −y 2

=256000∵x 2 −y 2

=(x+y)(x−y)

⇒1000∗(x−y)=256000

⇒x−y=256.....eq2

Adding eq1 and eq2

⇒2x=1256⇒x=628

Put the value of x in eq1

⇒628+y=1000⇒y=372

The numbers are 628 and 372

Hi I'm From PHILIPPINES

I'm here to help USA users like you

Answer:

2/3 and 4/6

Step-by-step explanation:

9514 1404 393

Answer:

  A.  1

Step-by-step explanation:

Arc AB is twice the measure of the angle ABC. The sum of the arc measures around the circle is 360°.

  2(43x)° +(272x +2)° = 360°

  358x +2 = 360 . . . . . . . . . . . . divide by °, collect terms

  358x = 358 . . . . . . . . subtract 2

  x = 1 . . . . . . . . . . divide by 358

Answer:

side AC is 5

Step-by-step explanation:

by using th pythagorean theorm you would square both sides add them together and the square root the sum to get you answer.

AB =3 BC=4

9+16=25

25 square root is 5

makeing AC=5

Answer:

£25

Step-by-step explanation:

total distance travelled per week = 2 * 7.5 * 5 = 75

amount of fuel used = 75/30 = 2.5 gallons = 11.375 litre

cost of fuel = 11.375 * 1.14 = 12.9675

total cost = 5(2.5) + 12.9675 = 25.4675 ~~ 25

Answer:

+3.464; -3.464

Step-by-step explanation:

call A = y + 2x + 1 = 0 => y = (1 - 2x)

call B: 4y - 4(x^2) - 12x = -7

=> replace y from A to B =>

=> get delta Δ = (-4^2) - 4*(-4 * 11) = 192

=> Δ > 0 => got 2 No

=> x1 = [tex]\frac{-4 + \sqrt{192} }{2 * -4}[/tex] = [tex]\frac{1 - 2\sqrt{3} }{2}[/tex] = -1.232

=> x2 = [tex]\frac{-4 - \sqrt{192} }{2 * -4}[/tex]=[tex]\frac{1 + 2\sqrt{3} }{2}[/tex]= 2.232

=> replace x from B into A

=> y1 = (1 - 2x) = (1 - 2 * -1.232) = 3.464

=> y2 = (1 - 2x) = (1 - 2 * 2.232) = - 3.464

Vertical asymptote:

A vertical asymptote is a value of x for which the function is not defined, that is, it is a point which is outside the domain of a function;

In a graphic, these vertical asymptotes are given by dashed vertical lines.

An example is a value of x for which the denominator of the function is 0.

In this graphic:

Dashed vertical lines at: [tex]x = -3, x = 7[/tex], thus, for [tex]x - (-3) = x+3[/tex] and [tex]x - 7[/tex] the denominator is zero.

Thus, the function graphed is:

[tex]F(x) = \frac{1}{(x+3)(x-7)}[/tex]

And the correct answer is given by option C.

To take a look at a problem with asymptote, you can check this item https://brainly.com/question/4084552.

The graph is for the rational function f(x) = 1/(x + 3)(x - 7).

Option C is the correct answer.

We have,

To understand the graph of the function f(x) = 1/((x + 3)(x - 7)).

Vertical Asymptotes:

The function has vertical asymptotes at the values of x for which the denominator becomes zero.

The denominator is (x + 3)(x - 7), so the vertical asymptotes occur at

x = -3 and x = 7.

Horizontal Asymptote:

The highest power of x in the denominator is x², and there is no x² term in the numerator, the function approaches 0 as x goes to positive or negative infinity.

The horizontal asymptote is y = 0.

x-Intercept:

To find the x-intercept, we set y = 0 and solve for x:

0 = 1/((x + 3)(x - 7))

Since the numerator can never be zero, the only way the fraction can be zero is if the denominator is zero:

(x + 3)(x - 7) = 0

Solving for x:

x + 3 = 0

x = -3

x - 7 = 0

x = 7

So, the x-intercepts are (-3, 0) and (7, 0).

y-Intercept:

To find the y-intercept, we set x = 0:

f(0) = 1/((0 + 3)(0 - 7)) = 1/(-3 * -7) = 1/21

The y-intercept is (0, 1/21).

Thus,

The graph is for the rational function f(x) = 1/(x + 3)(x - 7).

Learn more about functions here:

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Answer:

-1.683

Step-by-step explanation:

Given :

Group 1 :

x1 = 667 ; n1 = 10 ; s1 = 20

Group 2 :

x2 = 679 ; n2 = 14 ; s2 = 15

The test statistic assuming equal variance :

x1 - x2 / √[Sp² * (1/n1 + 1/n2)]

sp² = [(n1 - 1)*s1² + (n2 - 1)*s2²] ÷ (n1 + n2 - 2)

Sp² = [(10 - 1)*20² + (14 - 1)*15²] = 296.59

Test statistic =

(667 - 679)/ √[296.59 * (1/10 + 1/14)]

-12 / 7.1304978

Test statistic = - 1.682

Step-by-step explanation:

Answer:

Blablabla

Step-by-step explanation:

Bababa

Answer: None of the above.

Step-by-step explanation:

I got it right on khan. I’ll explain a little though. Semifinals median=47.05. Finals median=53.05.  Therefore A is not and option and B is DEFINITLEY not an option. Sorry I’m not good at explaining

Answer:

None of the above

Step-by-step explanation:

Got it right on test

Step-by-step explanation:

Here are some of the graphs:

Blue is g(x) and Green is f(x). The 2nd graph is for the 13b. It shows our graph after 1 transformation. The 3rd graph is after both transformations.

13a. Let use the following values in

[tex]f(x) = \frac{2}{x} [/tex]

We know by definition of rational function x cannot be zero.

Let find some values across interval 2 through 4.

[tex]f(2) = \frac{2}{2} = 1[/tex]

[tex]f(3) = \frac{2}{3} [/tex]

[tex]f(4) = \frac{2}{4} = \frac{1}{2} [/tex]

Let use the following values in

[tex]g(x) = \frac{3x - 1}{x - 1} [/tex]

By definition of rational function, x cannot be 1 because it will make the denominator zero. Let use some values across the interval 0 through 4.

[tex]g(0) = \frac{0 - 1}{0 - 1} = 1[/tex]

[tex]g(2) = \frac{3(2) - 1}{2 - 1} = {5} [/tex]

[tex]g(3) = \frac{8}{2} = 4[/tex]

[tex]g(4) = \frac{11}{3} [/tex]

So graph this in a table of values. I'll post a picture of the table of values on the top.

13b. We need to write g(x) as a transformation of f(x). If we look at the graphs, g(x) has a asymptote at x=1 while f(x) has a asymptote of 0. This means that we need to move f(x) to the right one unit or move (x-1) units.

We will upgrade the graph.

Now we can just add 3 to f(x) to get to g(x).

In the 3rd graph, notice how both graphs coincide. Our transformations is complete.

The answer is

[tex]g(x) = f(x - 1) + 3[/tex]

13c. We can say this as we move f(x) to the right 1 unit and shift f(x) up 3 units.

Answer:x=6573/500,x=13(73/500

Step-by-step explanation:

It will takes 12 years to reach approximately 32,752,000.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given:

y = 0.146x + 31

where x represents the number of years since 2000.

a) The population of Canada in the year 2006

x= 6

y= 0.146 x 6 + 31

y = 31.876

b) The population of Canada reach approximately 32,752,000 in

y = 32.752

0.146x + 31= 32.752

0.146x = 1.752

x= 1.752/0.146

x= 12

Hence, it will takes 12 years to reach approximately 32,752,000.

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Answer

its uhhhhh i dont know

Step-by-step explanation:

Answer:

Option A, the parent function has been translated up

Option B, the parent function has been compressed

Option C, the parent function has been translated to the right

Answer:

12 1/2

Step-by-step explanation:

2 x 5 = 10

1/2 x 5 = 2 1/2

10 + 2 1/2 = 12 1/2

Answer:

19- 2(xy+yz+xz)

20- 16t(5-t)

Step-by-step explanation:

19) factor 2xy+2yz+2xz

2xy+2yz+2xz

=2(xy+yz+xz)

20) factor -16t^2 +80t

=80t-16t^2

=16(5t-t^2)

=16t(5-t)

Answer:

x=4

Step-by-step explanation:

12 * X+3=51

Subtract 3 from each side

12x +3-3 = 51-3

12x = 48

Divide by 12

12x/12 = 48/12

x = 4

Answer:

"She's really angry; she ordered the product last Wednesday, Don in customer  service said it would arrive a week later. It was a dollhouse for her niece, Can you take it from here?" is the best option

Step-by-step explanation:

Your description of the surface is incomplete. But it looks like you're considering some subset of the paraboloid z = 1 - x ² - y ², so I'll go ahead and assume it's the part of said paraboloid above the x,y-plane, so that the boundary is a circle centered at the origin with radius 1.

By Stokes' theorem, the line integral of F along this boundary (∂S) is equal to the surface integral of curl(F ) over the surface itself (S). We have

F(x, y, z) = z ² i + 2x j + y ² k

which has curl

curl(F ) = (∂(y ²)/∂y - ∂(2x)/∂z) i - (∂(y ²)/∂x - ∂(z ²)/∂z) j + (∂(2x)/∂x - ∂(z ²)/∂y) k

curl(F ) = 2y i + 2z j + 2k

Parameterize S by the vector function,

r(u, v)  = u cos(v) i + u sin(v) j + (1 - u ²) k

with 0 ≤ u ≤ 1 and 0 ≤ v ≤ 2π.

Take the upward-pointing normal vector to S to be

n = ∂r/∂v × ∂r/∂u

n = (-u sin(v) i + u cos(v) j ) × (cos(v) i + sin(v) j - 2u k)

n = 2u ² cos(v) i + 2u ² sin(v) j + u k

Then the integral of curl(F ) over S - and hence the line integral of F over ∂S - is

[tex]\displaystyle \iint_S \mathrm{curl}(\mathbf F(x,y,z))\cdot\mathbf S \\\\ = \iint_S \mathrm{curl}(\mathbf F(\mathbf r(u,v)))\cdot\mathbf n\,\mathrm du\,\mathrm dv \\\\ = \int_0^{2\pi}\int_0^1 \left(2u\sin(v)\,\mathbf i + 2(1-u^2)\,\mathbf j + 2\,\mathbf k\right)\cdot\left(2u^2\cos(v)\,\mathbf i+2u^2\sin(v)\,\mathbf j+u\,\mathbf k\right)\,\mathrm du\,\mathrm dv \\\\ = \int_0^{2\pi}\int_0^1 \left(4u^3\sin(v)\cos(v)+4(1-u^2)u^2\sin(v)+2u\right)\,\mathrm du\,\mathrm dv \\\\ = \int_0^{2\pi}\left(\sin(v)\cos(v)+\frac8{15}\sin(v)+1\right)\,\mathrm dv \\\\ = \boxed{2\pi}[/tex]

Just to confirm this result, we can compute the line integral directly, since it's not so difficult to deal with. Parameterize ∂S by the vector function

r(t) = cos(t ) i + sin(t ) j

with 0 ≤ t ≤ 2π. (Note that there is a k component, but its coefficient is 0.) Then

dr/dt = -sin(t ) i + cos(t ) j

and the line integral is again

[tex]\displaystyle \int_{\partial S}\mathbf F(x,y,z)\cdot\mathrm d\mathbf r \\\\ = \int_{\partial S} \mathbf F(\mathbf r(t))\cdot\frac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt \\\\= \int_0^{2\pi} (\cos(t)\,\mathbf i+\sin(t)\,\mathbf j)\cdot(-\sin(t)\,\mathbf i+\cos(t)\,\mathbf j)\,\mathrm dt \\\\ = \int_0^{2\pi}2\cos^2(t)\,\mathrm dt \\\\ = \boxed{2\pi}[/tex]

Julie's Taxable Wages:

Julie's taxable wages as a data-entry operator is:

= $23,000.

Data and Calculations:

a) Annual gross pay =           $24,500

Total withholding allowances = 1,500

Taxable wages (income) =  $23,000 ($24,500 - $1,500)

b) Julie's total withholding allowance of $1,500 is the total exemption that reduces how much income tax her employer can deduct from  Julie's paycheck.  This means that $1,500 will be deducted from $24,500, the gross pay, before arriving at her taxable income.

Thus, Julie's taxable wages represent the difference between her annual gross pay and her total withholding allowances.

Learn more about taxable income here: https://brainly.com/question/8653999

Answer:

1 - 0.9887 = 0.0113

Step-by-step explanation: