Answer:
15 rad/s
Explanation:
Given:
α = 2 rad/s²
ω₀ = 5 rad/s
t = 5 s
Find: ω
ω = αt + ω₀
ω = (2 rad/s²) (5 s) + (5 rad/s)
ω = 15 rad/s
Joan is initially driving her car at 10 m/s when she decides to go faster. She accelerates uniformly at 4 m/s2 for 100 meters. How fast is Joan going?
a
50 m/s
b
35 m/s
c
30 m/s
d
26 m/s
Joan is going with speed 30 m/s. Hence, option (C) is correct.
What is acceleration?Acceleration is the rate at which a velocity changes over time. It qualifies as a vector quantity because it possesses both direction and magnitude. Meter/second^2 (m/s^2) is the SI unit of acceleration.
Given that: initial speed of the car: u = 10 m/s.
Uniform acceleration of the car: a = 4 m/s^2.
Distance travelled: s = 100 meters.
Let, the final speed is = v
Using the formula v² = u² + 2as, we get:
v = √(10² + 2×4×100) m/s.
= 30 m/s.
Hence, final speed of the car is 30 m/s.
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A(n) ____________________ is a dynamic variable on the free store without any pointer pointing to it.
A inaccessible object is a dynamic variable on the free store without any pointer pointing to it.
How to find the height of an inaccessible object using sextant?Utilize the sextant's arc to determine the angle. By dividing the object's distance from the point of observation by the tan of the angle you calculated, you may use a scientific calculator to get the object's height.
How can heights and distances that are absent or unavailable be measured?The measuring of heights and distances that are unreachable is made easier by right-triangle trigonometry. By drawing a right triangle with the unknown height or distance as one of its sides and a known side and angle on the other, it is possible to determine the unknown height or distance.
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Answer:
dynamic variable
aphasia
Due to an automobile accident, Jenny suffered damage to her cerebral cortex in Broca's area. Jenny is most likely to experience:
Due to an automobile accident, Jenny suffered damage to her cerebral cortex in Broca's area. Jenny is most likely to experience: aphasia.
Aphasia is the inability to understand or form language due to damage to certain areas of the brain The main causes are stroke and head trauma. Although the prevalence is difficult to determine, aphasia due to stroke is estimated at 0.1-0.4% in the Global North. Aphasia can also be the result of a brain tumor, brain infection, or neurodegenerative disease (such as dementia).
To be diagnosed with aphasia, communication after an acquired brain injury Speech or language must be significantly impaired in one (or more) of the four aspects of Alternatively, in the case of progressive aphasia, it must have decreased significantly over a short period of time. The four dimensions of communication are auditory comprehension, verbal expression, reading and writing, and functional communication.
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One of the most controversial ideas to come out of instinct theories of aggression was Lorenz's proposal that society provide acceptable ways of permitting , or the process of discharging built-up aggressive energy.
The general instinct hypothesis, which contends that people are physiologically predisposed to or possess inclinations for violent behaviours, is known as the instinct theory of aggression in psychology.
This theory is more focused on aggression. The instinct theory of aggressiveness holds that human aggression is akin to sex and hunger, and that it can only be regulated rather than eradicated.In an effort to understand why we become aggressive and whether that behaviours can be altered, psychologists have developed three primary theories of aggression. Although many hypotheses have been put out, these three have proven most reliable and are crucial to comprehending the origins of violence. These hypotheses comprise as,
Adversity theory based on instinctTheory of Frustration and AggressionTheory of Social LearningTo know more about theory of aggression
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A 50 gg mass rotates in a vertical plane--call it the xy-plane with the y-axis pointing up--at the end of a 75-cmcm-long, massless, rigid rod. The other end of the rod is attached to a frictionless pivot at the origin.
What is the gravitational torque about the pivot when the mass is 60 ∘∘ above the +x-axis? Give your answer using unit vectors.
The gravitational torque about the pivot when the mass is 60 ∘∘ above the +x-axis is (0.1838 Nm)k
What is torque?Torque is the turning effect of a force which causes rotation. It is given by τ = F × d where
F = force and d = perpendicular distance of force from point of action.What is the gravitational torque about the pivot when the mass is 60° above the +x-axis?Since a 50 g mass rotates in a vertical plane--call it the xy-plane with the y-axis pointing up--at the end of a 75-cm-long, massless, rigid rod.
The gravitational torque is given by τ = F × d where
F = component of weight perpendicular to rod = -(mgcosФ)j where m = mass, g = acceleration due to gravityФ = angle between rod and x axis and d = length of rodSo, τ = F × d
= -(mgcosФ)j × di
= mgdcosФ(-j × i)
= -mgdcosФ(j × i)
= -mgdcosФ(-k)
= (mgdcosФ)k
Given that
m = 50 g = 0.05 kgg = 9.8 m/s²,d = 75 cm = 0.75 m and Ф = 60°Substituting the values of the variables into the equation, we have
τ = (mgdcosФ)k
= (0.05 kg × 9.8 m/s² × 0.75 m × cos60°)k
= (0.05 kg × 9.8 m/s² × 0.75 m × cos60°)k
= (0.3675 kgm²/s² × 0.5)k
= (0.18375 kgm²/s²)k
= (0.18375 Nm)k
≅ (0.1838 Nm)k
So, the torque is (0.1838 Nm)k
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If a 10.4kg block rests on a rough horizontal table with a coefficient or friction of u=0.15 then what is the resulting force of friction on the block ?
Mathematically, F is1.56 represents the resulting force of friction on the block. The Frictioval force's mathematical equation is typically represented as F is uN.
How can the force of friction be calculated?The resistive friction force (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), a numerical value. The formula fr = Fr/N is used to represent it.The block will now start to slide as P is increased continuously, with the friction force acting on the block being: f = muK*N, where muK is the coefficient of kinetic friction, and f staying constant after that as P is increased.The resistive friction force (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), a numerical value.Explanation:
Mathematically, F=1.56 represents the resulting force of friction on the block.
The Frictioval force's mathematical equation is typically represented as F=uN.
u equals the friction coefficient.
N is normal force.
frictional force
As a result, the force of friction on the F=10.4*0.15 F=1.56
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A staging that weighs Wstaging supports a painter weighing 300 N. The reading on the left scale is 580 N and the reading on the right scale is 270 N. What is the weight of the staging?
The weight of the staging is 550N.
The weight of an object, the gravitational force caused by the presence of a large second object such as the Earth or the Moon.
The unit of measurement for weight is indeed a unit of force. This unit in the International System of Units (SI) is the Newton.
Given data : Weight of the painter ([tex]W_{p}[/tex]) = 300 N
Left scale's weight reading [tex](W_{L} )[/tex] = 580 N
Right scale's weight reading [tex](W_{R} )[/tex] = 270 N
To find the weight of the staging [tex](W_{s} )[/tex], we will set all the weight in the equilibrium.
Since the force of the staging and painter's weight is going downward we will denote them as negative. The opposite will be placed for the reading of weight on the left and right scale, which is positive.
[tex]-W_{p} -W_{s} +W_{L}+W_{R} = 0[/tex]
[tex]-300N-W_{s} +580N + 270N = 0\\[/tex]
[tex]W_{s}[/tex] [tex]= -300N+580N+270N[/tex]
[tex]W_{s}[/tex] [tex]= 550N[/tex]
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if you are in a car with a helium balloon in the middle of the back seat and you turn left, which way does the balloon move and why? physics.stackexchange
If you are in a car with a helium balloon in the middle of the back seat and you turn left, the balloon moves towards right.
A change in the air's surrounding density causes a helium-filled balloon to move.
The balloon operates in opposition to what your body would normally do. Therefore, if the automobile stops, the balloon will move to the back. The secret is that you are composed of materials that are significantly heavier than air and that the balloon is loaded with helium (He).
Turn left, the balloon goes right. When you turn right, the balloon moves to the left; when you stop, it moves to the right.
It has to do with the motion of the air in your car. When you start moving forward while stationary, all of the air in the car rushes to the back, where it builds up an area of higher air pressure.
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when an object of unknown mass is attached to an ideal spring with force constant 130 n/m, it is found to vibrate with a frequency of 7.25 hz.
When a massless item is fastened to an ideal spring with a force constant of 130 n/m, it is discovered that it vibrates at a frequency of 7.25 hz. The motion lasts 0.138 seconds.
What does a spring's force constant mean?In accordance with Hooke's law, the force necessary to compress or enlarge a spring is directionally related to or proportionate to the length it is stretched to. K is used to indicate the force constant.
What exactly is a vibration's frequency?The rate of vibrations and oscillations is called frequency, and it is expressed in hertz (Hz) units. To distinguish and ascertain vibrational patterns, frequencies are used. Therefore, a faster-vibrating atom would be seen as having a greater frequency than a slower-vibrating one.
Briefing:T= 1/f = 1/7.25 Hz = 0.138s
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The given question is incomplete. The complete question is:
When an object of unknown mass is attached to an ideal spring with force constant 130 n/m, it is found to vibrate with a frequency of 7.25 hz. What is the period of the motion?
the following items describe observational characteristics that could indicate that an object is either a white dwarf or a neutron star. match each characteristic to the correct object.
When a white dwarf acquires enough mass for its carbon interior to start fusing, a white dwarf supernova results.
The white dwarf entirely explodes as the star's fusion starts nearly immediately throughout the entire star. When iron is produced during fusion in a star's core, a "massive stellar supernova" results. If a white dwarf in a near binary system acquires enough mass to surpass the "white dwarf limit (1.4 solar masses)," it will erupt as a supernova. The absence of hydrogen characteristics in type I supernovae's spectra at maximum luminosity is a crucial identifying trait. The remnant core of a low-mass star known as a white dwarf is protected from the force of gravity by electron degeneracy pressure. The mass of the Sun is often condensed into a body no bigger than Earth in a white dwarf.
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crane lifts a 400 kg crate upward with an acceleration of 3.00 m/?. Determine the force on the crane.
The crane is under 5120 N of force. The crane touches the rock boulder and uses mechanical force to lift it.
What are the units of a force?Force is a physical phenomenon that can change an object's shape as well as its state of motion or rest. The SI unit of force is the Newton.
Cranes fall under which of the following three forces?Jib, gantry, and overhead cranes are the three pieces of machinery used most frequently in the industry. Depending on the type of item to be moved, either a chain or wire rope hoist will be used. In the shipbuilding sector, material handling is the main use of overhead cranes during the assembly process.
Briefing:
Mass (m) = 400kg
Acceleration (a) = 3.00 m/s^2
Gravitational acceleration (g) = 9.81 m/s^2
Force (F) = mg + ma
Force (F) = m (g + a)
Force (F) = 400 (9.81+3)
Force (F) = 5120 N
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Aspace station has a mass M and orbits Earth in a circular orbit at a height above Earth's surface. Space Station Earth A payload of mass m, where m < M is delivered to the space station. Soon after, the space station's orbit is adjusted so that it is 50 km farther away from Earth's surface than before. Which of the following best describes the effects of these changes on Earth's gravitational field strength at the space station's new location? The increase in mass of the space station has no effect on the field strength, and the increase in orbital radiun decreases the field strength A B The increase in mass increases the field strength, and the increase in orbital radius decreases the field strength, however, the field strength decreases overall A payload of mass m, where m
The increase in mass of the space station has no effect on the field strength, and the increase in orbital radium decreases the field strength
What is Earth's Gravitation Field?
Earth's gravitation field is the force any object experiences due to the gravitational pull by earth. It's formula is given below where G is the force, m is the mass of earth and r is radius of distance.
As seen through the formula, the gravitation field strength is only depend on earth's mass which is constant and radius of the distance. Hence, the increase in mass of the space station has no effect on the field strength, and the increase in orbital radium decreases the field strength.
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A steam power plant operates on the simple ideal Rankine cycle between the pressure limits of 10 kPa and 10 MPa, with a turbine inlet temperature of 600 degree C. The rate of heat transfer in the boiler is 800 kJ/s. Disregarding the pump work, the power output of this plant is: A. 284 kW B. 800 kW C. 508 kW D. 243 kW E. 335 kW
Option E; The pump work, the power output of this plant is 335KW
Pressure. at turbine. inlet P1 = 10 Mpa.
Enthalpy at turbine inlet = h1=3625.84 KJ/kg.
Entropy at turbine inlet S1 =6.90 KJ/kg-K.
It is given that process performed acceording to ideal rankine cycle which is "Reversible adiabatic expansion' in case of turbine wor., Since it is reversible adiabatic expansion, entropy at turbine inlet and entropy at turbine outlet is constant. So quality at turbine outlet is evaluated by using this relation. S1 = S2.
Pressure at turbine outlet = 10 Kpa.
Enthalphy of steam = hg =2675.1 KJ/kg.
Enthaphy of liquid=hf =417.51 KJ/kg
Entropy of steam = Sg =7.3589 KJ/kg-K.
Entropy of liquid =Sf =1.302 KJ/kg-K.
We know S1 = S2 =6.090=1.302+x(7.3589 - 1.302).
Quality at turbine exit x =0.79.
Enthalphy at exit = h2 = 417.51+ 0.79*(2675.1 - 417.51) =2201 KJ/kg-K.
heat transfered= mass*(enthlphy at exit of condenser - enthalphy at turbine inlet), Since pump work negleted
At exit of condenser, steam gets converted into water at 10 Kpa pressure whose enthalphy is hf =417.51 KJ/kg.
800 = m(3625.84 - 417.51).
mass flow rate of steam = 0.24 Kg/sec.
Turbine work the power output of this plant is = m(h1 - h2) =0.24(3625.84 - 2201) = 335 KW.
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A customer can choose one of six speaker systems, one of five DVD players, and one of six flat screen televisions to design a home entertainment system.
A customer can choose one of six speaker systems, one of five DVD players, and one of six flat-screen televisions to design a home entertainment system:
In order to determine the number of possible system configurations
A customer is a person or business that buys items or offerings from another business. clients are vital due to the fact they generate sales. without them, organizations might go out of business.
A client is commonly defined as someone who buys a terrific, product, or carrier. more, in particular, clients are human beings or agencies currently shopping, have bought, or maybe inquisitive about buying services or products from every other character or enterprise.
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A car moving with a speed of 90km/hr was brought to rest by the application of the
Brakes in 10s How far did the car travel after the brakes were applied?
The distance travelled by the car after the brake was applied is 125 m.
What is the distance travelled by the car?
The distance travelled by the car is calculated by applying the following kinematic equation as shown below.
Mathematically, the distance travelled by the car at the given average speed is calculated as;
s = [ ( v + u ) / 2 ] t
where;
v is the final velocity of the car = 0u is the initial velocity of the car = 90 km/hr = 25 m/st is the time of motion of the car = 10 sThe distance travelled by the car is calculated as;
s = [ ( 0 + 25 m/s ) / 2 ] ( 10 s )
s = 125 m
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umama wants to enable user experience virtualization (ue-v) by configuring group policy settings. two important settings that she needs to configure are the setting storage location and settings template catalog location. which of the following is true of this scenario?
Correct. When new user profiles are created, the default profile is utilised. Umama wants to configure Group Policy settings to enable User Experience Virtualization (UE-V).
UEV policy settings: What are they?You can enable or disable User Experience Virtualization using this Group Policy setting (UE-V). Only versions of UE-V 2.x and earlier are affected by this setting. Use the Enable UE-V setting in Wind ows 10, version 1607, for UE-V. The location of the settings template catalogue and the location of the settings storage location are two crucial settings that she must set up.
Microsoft User Experience Virtualization: What is it?A programme called Micro soft UE-V (User Experience Virtualization) enables users to switch between Wind ows devices while keeping their current operating system (OS) and application settings.
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A 20 g ball of clay traveling east at 2.5 m/s collides with a 25 g ball of clay traveling north at 2.0 m/s .
What is the speed of the resulting 45 g ball of clay?
What is the direction of the resulting ball of clay?
The final velocity of the two balls after collision is 1.7 m/s and the direction is 45⁰.
The given parameters;
mass of the first clay ball, m₁ = 20 g = 0.02 kg
initial velocity of the first clay ball, u₁ = 3 m/s
mass of the second clay ball, m₂ = 30 g = 0.03 kg
initial velocity of the second ball, u₂ = 2 m/s
The initial momentum of the fist ball is calculated as follows;
P₁ = m₁u₁
P₁ = (0.02)(3)
P₁ = 0.06 kg.m/s
The initial momentum of the second ball is calculated as follows
P₂ = m₂u₂
P₂ = (0.03)(2)
P₂ = 0.06 kg.m/s
The resultant initial momentum of the two balls is calculated as follows;
Apply the principle of conservation of momentum, to determine the final velocity of the two balls;
The direction of the two ball's velocity is calculated as follows;
Thus, the final velocity of the two balls after collision is 1.7 m/s and the direction is 45⁰To know more about speed direction visit:
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Question 9 of 25
Describe the path of the light ray that hits a mirror after passing through its
focus.
OA. It reflects back through the focus.
B. It hits the mirror and reflects back exactly the way it came in.
C. It is refracted through the mirror.
D. It is reflected back parallel to the principal axis.
SUBMIT
The path taken by a light beam after passing through a mirror's focus is where it hits the mirror and reflects back in exactly the same direction as it went in.
What, when striking the surface, causes the light to reflect back?Specular reflection is the name for this. A smooth surface allows light to bounce back at the same angle that it was incident. Rays of light that are reflected off of a smooth surface go in that same direction.
Where does a light beam travel?The narrow beams of light that travel in straight lines along their courses as electromagnetic waves are known as rays. Though its path might be altered by reflection or refraction, light always moves in a straight line.
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a hollow metal sphere has inner radius a and outer radius b. the hollow sphere has charge 2 q. a point charge q sits at the center of the hollow sphere. you may want to review (page 658) . for help with math skills, you may want to review
The inner radius of a hollow metal sphere is a, and the outside radius is b. The hollow sphere has a point charge q in the center. There will be a distribution of q charges on the inner surface.
What is a charge of electricity?Electric charge can be interpreted as an excess or shortage of electrons and is the amount of imbalanced electricity (either positive or negative) in a body. There are two varieties: positive (+) and negative (–).
How is electricity produced?We all studied the structure of an atom with an equal amount of protons, neutrons, and electrons in physics and chemistry. Protons are positively charged, neutrons are neutrally charged, and electrons have a negative charge.
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The given question is incomplete. The complete question is:
A hollow metal sphere has inner radius 'a' and outer radius 'b'. The hollow sphere has charge +2Q. A point charge +Q sits at the center of the hollow sphere. How much charge is on the inside surface of the hollow sphere?
the two weights are released from rest. the coefficient of kinetic friction between the horizontal surface and the 5 lb weight is 0.18
The final velocity of the weights will be 3.31 m/s
Weight = 5 lb
Coefficient of kinetic friction (µ) = 0.18
let T be tension
[tex]m_{1}[/tex]*g-T =[tex]m_{1}[/tex]*a
[tex]m_{1}[/tex] =10 lb = 4.53 kg
T-(µ)[tex]m_{2}[/tex]g =[tex]m_{2}[/tex]a
Adding both equations, we have
([tex]m_{1}[/tex]-k[tex]m_{2}[/tex])g =[tex]m_{2}[/tex] a
a = (4.53-0.2*2.26)*10/2.26 =18.04 [tex]m/s^{2}[/tex]
Using the equation of motion, we have,
[tex]v^{2} -u^{2} =2as[/tex]
Since the body starts from rest, the initial velocity, that is, u is zero.
So, u = 0 m/s
Putting this value in the above equation to calculate the final velocity, we have,
[tex]v^{2}[/tex] = 2as
v = [tex]\sqrt{(2*18.04*0.304) }[/tex]= 3.31 m/s
Thus, the final velocity of the weights will be 3.31 m/s
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Field poles are electromagnets whose ____ change as the flow of current alternates in the field windings.
Field poles are electromagnets whose polarities change as the flow of current alternates in the field windings.
An electromagnet is a sort of magnet wherein the magnetic area is produced with the aid of an electric current. Electromagnets generally encompass cord wounds into a coil. A cutting edge through the wire creates a magnetic discipline that is focused inside the hole in the middle of the coil.
Electromagnets create a magnetic discipline through the application of power. When you introduce the modern, either from a battery or any other supply of strength, it flows through the wire. This creates a magnetic discipline around the coiled cord, magnetizing the metal as though it were a permanent magnet.
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show an example of the method described above. ii. why might your calculated value for the half-life of barium-137 from this method differ from the accepted value?
By monitoring a sample's activity as it decays, Ba-137m can be calculated. Utilizing AktivLab, the radioisotope Ba-137half-life, m's which was isolated from Cs-137, is found.
How is the experiment's half-life determined?After that, the half-life is calculated using the basic concept of activity, which is the sum of the radionuclide decay constant,, and the number of radioactive atoms present, N. By using the formula = ln2/T1/2, one may solve for and obtain the half-life.
Describe half-life in detail.?A half-life is the duration needed for something to reduce in quantity by half. The phrase is most frequently used in reference to radioactive decay, which takes place when unstable atomic particles shed energy. There are 29 elements that can travel through this, according to known facts.
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A taxi company is trying to decide whether to purchase brand A or brand B tires for its fleet of taxis. To estimate the difference in the two brands, an experiment is conducted using 12 of each brand. The tires are run until they wear out. The results are Brand A: \overline{x}_1 = 36. 300 x
1
=36.300 kilometers, s_1s 1
= 5000 kilometers. Brand B: \overline{x}_2 = 38. 100 x
2
=38.100 kilometers, s_2 = 6100s 2
=6100 kilometers. Compute a 95% confidence interval for \mu A − \mu BμA−μB assuming the populations to be approximately normally distributed. You may not assume that the variances are equal.
A 95% confidence interval for μA-μB is 0.025
If we want to make a 95% confidence interval estimate for an unknown population mean. This means that there is a 95% probability that the confidence interval will have the true population mean.
Thus, P( [sample mean] - margin of error < μ < [sample mean] + margin of error) = 0.95.
We have,
n1 = 12
s1 = 5000
mean x1 = 36300
n2= 12
s2 =6100
mean x2 =38100
We have to find 95%confidence interval for μA- μB
from 95% = 100 (1-α%)
1-α = 0.95
α = 1-0.95 =0.05
α/2 = 0.025
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for the circuit below all values are rms with a source frequency of 60 hertz. the generator impedance is negligible (0 w). calculate the value of ib and and determine the value of vb-n. now, calculate the rms values of apparent, real and reactive power of zb. (show units for all)
The reactive power of the branch (Qb) can be calculated from its voltage and current 676.16 VA.
What is reactive power?Reactive power is the power in an AC circuit that is required to establish and maintain a voltage across a load. It is associated with the storage and release of energy in the form of electric and magnetic fields. Reactive power does not contribute to the actual work output of a system and is measured in Volt-amperes reactive (VARs). Power factor is a measure of reactive power relative to the total power in a system.
Source frequency = 60 Hz
Generator impedance = 0 W
Circuit:
Vg = 170 V
R1 = 10 Ω
R2 = 20 Ω
Zb = 20 + j10 Ω
The current flowing through the generator (Ig) and the branch (Ib) can be calculated from Ohm's Law:
Ig = Vg/R1 + Vg/R2 = 170/10 + 170/20 = 17 A
Ib = Ig - Vg/Zb = 17 - 170/(20 + j10) = 17 - 16.4 + j4.4 = 0.6 + j4.4 A
Since Ib is a complex number, we can find its magnitude (|Ib|) and angle (θ):
|Ib| = √(0.6² + 4.4²) = 4.46 A
θ = tan⁻¹(4.4/0.6) = 80.16°
The voltage across the branch (Vb-n) can be calculated using Ohm's Law:
Vb-n = Ib × Zb = (0.6 + j4.4) × (20 + j10) = -8.4 + j74.4 V
The apparent power of the branch (Sb) can be calculated from its voltage and current:
Sb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = -45.48 + j367.04 VA
The real power of the branch (Pb) can be calculated from its voltage and current:
Pb = Vb-n × Ib = (-8.4 + j74.4) × (0.6 + j4.4) = -45.48 - j367.04 W
The reactive power of the branch (Qb) can be calculated from its voltage and current:
Qb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = 676.16 VA
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A uniform plane wave with parallel polarization is propagating in a lossless dielectric medium (l is € 1), and is incident obliquely onto a plane boundary with another lossless dielectric medium (u 2, E 2). (30%) (a) Derive the Snell's laws of reflection and refraction in terms of the refractive indices and angles. (b) Derive the general expressions for the reflection and the transmission coefficients of the EM field. Find such expressions in terms of the refractive indices if both media are nonmagnetic, i.e., M F M 240. (c) Derive the general expression for the Brewster angle. Find such an expression in terms of the refractive indices if both media are nonmagnetic. (d) Prove that, under the condition of no reflection, the sum of the Brewster angle and the angle of refraction is 90° if both media are nonmagnetic. (e) For total reflection to occur, find the condition for the medium property and the critical angle.
Transmission coefficients are used in physics and electrical engineering when considering wave propagation in discontinuous media. The snells law is n₁sinθ1 = n₂sinθ2
The transmission coefficient describes the amplitude intensity or total power of the transmitted wave relative to the incident wave. The transmission coefficient is defined as the ratio of the transmitted particle flux to the incident particle flux and depends on the incident energy.
The sum of the reflected and transmitted energy must equal the total incident energy, so the transmission coefficient is calculated simply by subtracting the reflection coefficient. The ratio of the reflected wave amplitude to the incident wave amplitude is called the reflection coefficient.
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A certain 50.0-Hz AC power line radiates an electromagnetic wave having a maximum electric field strength of 13.0 kV/m. (a) What is the wavelength of this very low frequency electromagnetic wave? (b) What is its maximum magnetic field strength?
An electromagnetic wave radiating from a specific 50.0-Hz AC power line has a maximum electric field strength of 13.0 kV/m. This extremely low frequency electromagnetic pulse has a wavelength of 6.00 x [tex]10^{6}[/tex]m.
An electromagnetic wave is what?A sinusoidal graph illustrates electromagnetic waves. It is made up of time-varying electric and magnetic fields that are perpendicular to each other and to the direction that waves travel.
How do wavelength and frequency relate to one another?Inverse proportionality describes the relationship between frequency and wavelength. Longer wavelengths are correlated with lower frequency, and vice versa. The fact that a wave's speed is equal to the product of its frequency and wavelength helps to explain how these two properties are related.
Briefing:
Given that,
Frequency of the power line, f = 50.0 Hz
Value of maximum electric field strength of 13.0 kV/m
The wavelength of this very low frequency electromagnetic wave is given by using relation as:
[tex]c = f[/tex]λ
λ [tex]= \frac{c}{f}[/tex]
λ [tex]= \frac{3.8 * 10^{8} m/s }{50}[/tex]
λ = 6 x [tex]10^{6}[/tex] m
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when the glass gob comes out of the oven, it is dangerously hot. What happens to the thermal energy of the gob between that time and when it is a bottle than can be touched?
Answer:
decreases
Explanation:
The thermal energy of the gob decreases by heating the air around the gob and the mold in which the bottle is made
Two point-like particles, each of mass m, are originally separated by a distance d and moving in opposite directions each with a speed of v. What is the maximum value for v so that the particles will eventually move back together under the influence of the mutual gravitational attraction?
The angular momentum of a system does not depend on the point about which it is taken, according to equation (iv). the particles eventually move back together because of mutual gravitational attraction.
How to repair?As depicted in the following diagram, assume that two particles are present at positions P and Q at some point in time.
Think about a point R that is y miles away from a point Q, or QR=y PR=dy.
LP=mv0+mvd=mvd is the system's angular momentum around point P.
I The system's angular momentum around point Q is given by LQ=mvd+mv0=mvd.....(ii)
System's angular momentum about point R is given by LR=mv(d, y)+mv(y, d)=mvd....(iii)
The result of comparing equations I (ii), and (iii) is L P = LQ = LR....... (iv)
The angular momentum of a system does not depend on the point about which it is taken, according to equation (iv).
What causes the gravitational pull of objects?All objects with mass are attracted to one another by the gravitational attraction, which has a magnitude that is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another.
What are the benefits of gravitational attraction?Our feet remain firmly planted on the ground thanks to gravity, which also keeps the Moon in orbit around the Earth, the Earth in orbit around the Sun, the Sun in orbit around the galactic core of our Milky Way galaxy, and the Milky Way and Andromeda galaxies orbiting each other.
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Part B
The general kinematic equations of motion for vertical displacement can also be simplified significantly. Write the simplified equation for y in this case. Explain how you have been able to simplify it from this general displacement equation:
The general vertical displacement equation for object moving upwards is written as h = v₀t - ¹/₂gt².
What is the vertical displacement of an object?The vertical displacement of an object is the height travelled by the object.
The general kinematic equations of motion for vertical displacement is written as follows;
y = y₀ + v₀t + ¹/₂at²
where;
y₀ is initial vertical position of the objectv₀ is the initial vertical velocity of the objecta is the acceleration of the objectt is the time of motionIf the object is moving upwards, the new kinematic equation becomes;
h = 0 + v₀t - ¹/₂gt²
h = v₀t - ¹/₂gt²
where;
h is the vertical displacement of the objectv₀ is the initial vertical velocity of the objectg is the acceleration due to gravityt is the time of motion of the objectFor the simplified equation above, the acceleration of the object changes to acceleration due to gravity since the object is moving against gravity in the negative direction.
Thus, the general kinematic equations of motion for vertical displacement is written in terms of acceleration due to gravity in negative direction since it is moving upwards.
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In a diffraction experiment, a coherent light source illuminates a pair of identical slits in a barrier, and the resulting pattern is projected on a screen that is separated from the barrier by 2.05 m. A student sketches the pattern that appears on the screen. The locations of the centers of the bright and dark fringes are accurate, but the shading is only qualitative. The color chosen may not be an ideal match to the actual light source. TITUTE THI HT -50.0 -40.0 -30.0 -20.0 -10.0 0.0 10.0 20.0 30.0 40.0 50.0 y (cm) * 25% Part (a) Enter the ratio of the slit separation, d, to the slit width, D, as a whole number. d = D TT 7 8 9 HOME E 4 5 6 sino cos tan cotano asin acos atan acotan sinh cosho tanh) cotanh O Degrees Radians 1 2 3 + 0 END . VO BACKSPACE DE CLEAR Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. A 25% Part (b) Calculate and enter the ratio of the slit width to the wavelength of the light source. A 25% Part (C) If the slit separation is 17 um, then calculate and enter the wavelength, in nanometers, of the light source. 25% Part (d) What is the slit width, in micrometers?
(a) The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width, in micrometers;
d = 20.5 µm
(a) We know that Fringe width is given by,
[tex]\beta =\frac{D\lambda}{d}[/tex]
Where,
D = slit to screen distance
λ = wavelength
d = slit width
Given in the question,
D = 2.05 m
[tex]\beta =4 cm=0.04m[/tex]
Now,
[tex]\frac{d}{D} =\frac{\lambda}{\beta } =\frac{400*10^{-9} }{0.04}[/tex]
d/D = 0.0001
Hence,
The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b) Ratio of d & λ,
[tex]\frac{d}{\lambda} =\frac{D}{\beta }[/tex]
[tex]\frac{d}{\lambda}=\frac{2.05}{0.04}[/tex]
[tex]\frac{d}{\lambda}=51.25[/tex]
Hence,
The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength of the light source,
[tex]\lambda=\frac{D\beta }{d}[/tex]
[tex]\lambda=\frac{17*10^{-6} *0.04}{2.05}[/tex]
[tex]\lambda=331.7nm[/tex]
Hence,
The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width,
[tex]d =\frac{D\lambda}{\beta }[/tex]
[tex]d=\frac{400*10^{-9} *2.05}{0.04}[/tex]
[tex]d=20.5 \mu m[/tex]
Hence,
The slit width, in micrometers;
d = 20.5 µm
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