Find the area of the shaded regions

Answer:

C) 2

Step-by-step explanation:

From the point (2,0), the next point on the graph is up 2, right 1, meaning that the slope is a positive 2.

Answer:

Step-by-step explanation:

x+y = 67

2x-y = 38

Add the equations together

3x = 108

x = 36

y = 67-x = 31

9514 1404 393

Answer:

  y = -1

Step-by-step explanation:

We assume you want the line with a slope of zero. That is a horizontal line, so y is a constant. In order to make the line go through the point with y=-1, the equation of the line is ...

  y = -1

Answer:

y=-2x+1

Step-by-step explanation:

The slope of the line is - 2. The y intercept is 1. Hence the equation is y=-2x+1

9514 1404 393

Answer:

  1 -√2

Step-by-step explanation:

  [tex]\tan(x/2)=\dfrac{1-\cos(x)}{\sin(x)}\\\\\tan\left(\dfrac{1}{2}\cdot\dfrac{7\pi}{4}\right)=\dfrac{1-\cos\dfrac{7\pi}{4}}{\sin\dfrac{7\pi}{4}}=\dfrac{1-\dfrac{1}{\sqrt{2}}}{-\dfrac{1}{\sqrt{2}}}=\boxed{1-\sqrt{2}}[/tex]

tan(7π/8) = 1 -√2

Answer:

15,300 units

Step-by-step explanation:

First, find how many units of Product B were sold:

34,000(0.3)

= 10,200

Find how many units of Product A were sold:

10,200(1.5)

= 15,300

So, 15,300 units of Product A were sold.

Product A  sold 15,300 units that is 1.5 times more than product B

Given :

Product A sells 1.5 times more than Product B. Product B sells 70% less than Product C.

Product C sold 34,000 units this month

Product C sold = 34000

Product B is 70% less than product C

So, product B is 100-70% =30% of product C

[tex]Product B=\frac{30}{100} \cdot 34000\\Product B \; sold = 10200[/tex]

Lets find out product A sold

Product A sold = 1.5 times more than product B

[tex]Product A= 1.5 \cdot product B\\Product A=1.5 \cdot 10200=15300[/tex]

15,300 units of product A were sold.

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Answer:

a.

[tex] \frac{36}{40} [/tex]

Answer:

-33

Step-by-step explanation:

-p/3-8=3

or,(-p-24)/3=3

or,(-p-24)=9

or,-p=33

Therefore, p=-33

Answer:

95%

Step-by-step explanation:

Mean , xbar = 64.3; standard deviation, s= 2.4

Using the empirical formula where ;

68% of the distribution is within 1 standard deviation from the mean ;

95% of the distribution is within 2 standard deviation from the mean

percent of heights that lie between 59.5 inches and 69.1 inches.

Number of standard deviations from the mean /

Z = (x - μ) / σ

(x - μ) / σ < Z < (x - μ) / σ

(59.5 - 64.3) / 2.4 < Z < (69.1 - 64.3) / 2.4

-2 < Z < 2

Thia is within 2 standard deviations of the means :

2 standard deviation form the mean = 95% according to the empirical rule.

Answer:

x = 8ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Answer:

x=4

Step-by-step explanation:

2x-2+x+2x-2+x=3+7+3+7

6x-4=20

6x=24

x=4

Step-by-step explanation:

here's the answer to your question

Answer:

B) C and G

Step-by-step explanation:

The radius is equal to 1/2 the diameter

r = 1/2 d

G has a diameter of 45

1/2 (45) = 22.5

C and G are the same

Answer:

c and g!

Step-by-step explanation:

Answer:

(-∞,∞) is the domain.

2 is the range

Step-by-step explanation:

First simplify the expression into polynomial form,

[tex](x-1)(x-3)(x+5)(x+7)=297[/tex]

[tex]x^4+8x^3-10x^2-104x+105=297[/tex]

[tex]x^4+8x^3-10x^2-104x-192=0[/tex]

Now factor into,

[tex](x-4)(x+8)(x^2+4x+6)=0[/tex]

Which means the solutions are,

[tex]x-4=0\implies\boxed{x_1=4}[/tex]

[tex]x+8=0\implies\boxed{x_2=-8}[/tex]

and then two complex solutions because determinant of the third factor [tex]D\lt0[/tex],

[tex]x^2+4x+6=0[/tex]

[tex]x^2+4x+4=-2[/tex]

[tex](x+2)^2=-2\implies\boxed{x_3=i\sqrt{2}-2},\boxed{x_4=-i\sqrt{2}-2}[/tex]

Hope this helps :)

Answer:

x=4

Step-by-step explanation:

(4-1)(4-3)(4+5)(4+7)=297

Answer:

Step-by-step explanation:

Is the function f(x) = 3x+1, f(x) = 3ˣ⁺¹, or f(x) = 3ˣ+1 ?

f(x) = 3x+1 is not an exponential function. It is a straight line.

f(x) = 3ˣ⁺¹ Is an exponential function. The base is 3.

f(x) = 3ˣ+1 is an exponential function. The base is 3.

Step-by-step explanation:

Consuelo Butler

08/07

Homework: Practice

Exam 3

Question 1, 12.1.13

HW Score: 10%, 3 of 30 points

Score: 1 of 1

A professor had students keep track of their social interactions for a week. The

number of social interactions over the week is shown in the following grouped

frequency distribution. How many students had at least 60 social interactions for

the week?

12

Number of Social

Interactions

30-34

35-39

40-44

45-49

50-54

55-59

60-64

65-69

70-74

75-79

Frequency

9

14

11

15

16

8

7

By calculating the greater than cumulative frequency using the given frequency table, 12 students had at least 60 social interactions for the week.

The greater than cumulative frequency is also known as the more than type cumulative frequency. Here, the greater than cumulative frequency distribution is obtained by determining the cumulative total frequencies starting from the highest class to the lowest class.

Class interval     Frequency     Cumulative frequency

30-34                9                   85

35-39                14                   76

40-44                11                   62

45-49                15                   51

50-54                16                   36

55-59                 8                   20

60-64                 7                   12

65-69                 3                    5

70-74                  1                    2

75-79                  1                     1

[We read the cumulative frequencies with respect to the corresponding lower class limits. For example, 85 students had 'more than 30' social interactions, 76 students had 'more than 35 social interactions and so on.]

By reading the greater than cumulative frequency, we find that 12 students had at least 60 social interactions for the week.

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Answer:

Option c, Scheme C

Step-by-step explanation:

scheme A: 45000/6 = 7500 per month

scheme B: 46800/9 = 5200 per month

scheme C: 48000/12 = 4000 per month

The correct answer of the question is "0.7062" and "0.835". The further solution is provided below.

Given:

Probability of student smoke,

P = 27.7%

  = 0.277

Number of students (n) = 632

[tex]q = 1-p[/tex]

  [tex]=1-0.277[/tex]

  [tex]=0.723[/tex]

(i)

Here,

Number of students (n) = 60

then,

⇒ [tex]n_P=60\times 0.277[/tex]

         [tex]=16.62[/tex]

⇒ [tex]n_q=60\times 0.723[/tex]

        [tex]=43.38[/tex]

We can see that [tex]n_P > 10[/tex] and [tex]n_q>10[/tex] so the normal approximation condition are met.

Now,

[tex]\mu = n_P= 16.62[/tex]

[tex]\sigma = \sqrt{n_{Pq}}[/tex]

  [tex]= \sqrt{60\times 0.277\times 0.723}[/tex]

  [tex]=3.9664[/tex]

Now,

⇒ [tex]P(X<19) = P(X<18.5)[/tex]

                      [tex]=P(Z_{18.5})[/tex]

The Z-score is:

= [tex]\frac{18.5-16.62}{3.4664}[/tex]

= [tex]0.5423[/tex]

hence,

The probability will be:

⇒ [tex]P(Z_{18.5}) = 0.7062[/tex]

or,

⇒ [tex]P(Z<19) = 0.7062[/tex]

(ii)

Here,

Number of students (n) = 75

[tex]\mu = n_P = 75\times 0.277[/tex]

            [tex]=20.775[/tex]

[tex]\sigma = \sqrt{n_{Pq}}[/tex]

   [tex]=\sqrt{75\times 0.277\times 0.723}[/tex]

   [tex]=3.8756[/tex]

Now,

⇒ [tex]P(X>17) = P(X> 17.5)[/tex]

                      [tex]=1-P(X \leq 17.5)[/tex]

                      [tex]=1-P(Z_{17.5})[/tex]

The Z-score is:

= [tex]\frac{17.5-20.775}{3.8756}[/tex]

= [tex]-0.9740[/tex]

then, [tex]P(Z_{17.5}) = 0.165[/tex]

hence,

The probability will be:

⇒ [tex]P(X>17) = 1-0.165[/tex]

                      [tex]=0.835[/tex]    

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Answer:

f(x) = 3ex - e

Step-by-step explanation:

In this equation we have basically the times e by 3x and -1

so first let's do e times 3x

here...

e X 3x = 3ex

so let's rewrite the equation

3ex - 1

now we times e by 1. (Note - Negative sign stays)

3ex - 1e

we don't have to write 1e cause 1e = e, they are the same.

Therefore the answer is 3ex - 1e

Following are the calculation of inverse:

Given:  

[tex]\to f(x)=e^{3x-1}[/tex]

To find:

inverse function=?

Solution:

A function g is the inverse of function F if for [tex]y=f(x), x=g(y)[/tex]

[tex]\to y=e^{3x-1}[/tex]

Replacing the value of x with y  

[tex]\to x=e^{3y-1}[/tex]

Solve for [tex]y, x=e^{3y-1}[/tex]

Therefore, the answer is [tex]\frac{\log(x)+1}{3}[/tex].

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Answer:

Step-by-step explanation:

No that is true. I can't make anything more out of it.

Answer:

It will be 31.4 cm rounded off for circumference

It will be 78.53 cm2 rounded off for area

Step-by-step explanation:

Diameter = 10 cm

Radius = 10/2 cm = 5 cm

Circumference = 2×pi×radius

= 2pi×5

= 31.4 cm

Area = pi × r square

= 25 pi

= 78.53cm2

Answer:

The real reason of post test is to measure it's result in comparison to a pre test and determine d how much student has progressed over a term of instruction.

Answer:

2(w+3)

Step-by-step explanation:

2(w+3) or 2w+6

The value of g across from angle G is 5feet

According to sine rule

[tex]\frac{e}{sinE}=\frac{f}{sinF}=\frac{g}{sinG}[/tex]

Given the following

∠G = 45°

∠F = 82°

f = 7feet

Required

side g

Substitute the given values into the formula

[tex]\frac{f}{sinF}=\frac{g}{sinG}\\ \frac{7}{sin82}=\frac{g}{sin45}\\\frac{7}{0.9903}=\frac{g}{0.7071}\\7.0686=\frac{g}{0.7071}\\g=7.0686*0.7071\\g=4.998\\g\approx5ft[/tex]

Hence the value of g across from angle G is 5feet

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The length of the line segment EF ([tex]g[/tex]) is approximately 5 feet.

Let be [tex]EFG[/tex] a Triangle, whose expression derived from the Law of Sines is described below:

[tex]\frac{e}{\sin E} = \frac{f}{\sin F} = \frac{g}{\sin G}[/tex] (1)

Where:

[tex]e[/tex] - Measure of the line segment FG, in feet.

[tex]f[/tex] - Measure of the line segment EG, in feet.

[tex]g[/tex] - Measure of the line segment EF, in feet.

[tex]E[/tex] - Angle at vertex E, in sexagesimal degrees.

[tex]F[/tex] - Angle at vertex F, in sexagesimal degrees.

[tex]G[/tex] - Angle at vertex G, in sexagesimal degrees.

We can determine a missing length, by knowing the length of a neighboring side and two consecutive angles. If we know that [tex]f = 7\,ft[/tex], [tex]G = 45^{\circ}[/tex] and [tex]F = 82^{\circ}[/tex], then the measure of the line segment EF is:

[tex]g = f\cdot \left(\frac{\sin G}{\sin F} \right)[/tex] (2)

[tex]g = (7\,ft)\cdot \left(\frac{\sin 45^{\circ}}{\sin 82^{\circ}} \right)[/tex]

[tex]g\approx 4.998\,ft[/tex]

[tex]g \approx 5\,ft[/tex]

The length of the line segment EF ([tex]g[/tex]) is approximately 5 feet.

everything seems to be correctly filled.

if you wanted confidence by confirmation: here, take some

It is an exponentially decaying function.

An exponential function is where the independent variable is in the exponent. Generally the the independent variable is in the power of a constant term e.

Exponential functions are of two types one is exponentially growing function and exponentially decaying function.

when the we have a positive exponent the function is exponentially growing and when we have a negative exponent the function is exponentially decaying.

In the given question f(x) = 8e⁻ˣ

when, x = 0 f(x) = 8

f(x) = 8e⁻ˣ

f(0) = 8e⁰

f(0) = 8

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Answer:

5180.56 Dollars...........