Answer:
[tex]\rm\displaystyle 0,\pm\pi [/tex]
Step-by-step explanation:
please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation
===========================
we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first
cancel tanγ from both sides which yields:
[tex] \rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma ) [/tex]
factor out tanγ:
[tex]\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)[/tex]
divide both sides by tanαtanβ-1 and that yields:
[tex]\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}[/tex]
multiply both numerator and denominator by-1 which yields:
[tex]\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)[/tex]
recall angle sum indentity of tan:
[tex]\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta ) [/tex]
let α+β be t and transform:
[tex]\rm\displaystyle \tan( \gamma ) = - \tan( t) [/tex]
remember that tan(t)=tan(t±kπ) so
[tex]\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi ) [/tex]
therefore when k is 1 we obtain:
[tex]\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi ) [/tex]
remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus
[tex]\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi ) [/tex]
recall that if we have common trigonometric function in both sides then the angle must equal which yields:
[tex]\rm\displaystyle \gamma = - \alpha - \beta \pm \pi [/tex]
isolate -α-β to left hand side and change its sign:
[tex]\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }[/tex]
when is 0:
[tex]\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 ) [/tex]
likewise by Opposite Angle Identity we obtain:
[tex]\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 ) [/tex]
recall that if we have common trigonometric function in both sides then the angle must equal therefore:
[tex]\rm\displaystyle \gamma = - \alpha - \beta \pm 0 [/tex]
isolate -α-β to left hand side and change its sign:
[tex]\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }[/tex]
and we're done!
Answer:
-π, 0, and π
Step-by-step explanation:
You can solve for tan y :
tan y (tan a + tan B - 1) = tan a + tan y
Assuming tan a + tan B ≠ 1, we obtain
[tex]tan/y/=-\frac{tan/a/+tan/B/}{1-tan/a/tan/B/} =-tan(a+B)[/tex]
which implies that
y = -a - B + kπ
for some integer k. Thus
a + B + y = kπ
With the stated limitations, we can only have k = 0, k = 1 or k = -1. All cases are possible: we get k = 0 for a = B = y = 0; we get k = 1 when a, B, y are the angles of an acute triangle; and k = - 1 by taking the negatives of the previous cases.
It remains to analyze the case when "tan "a" tan B = 1, which is the same as saying that tan B = cot a = tan(π/2 - a), so
[tex]B=\frac{\pi }{2} - a + k\pi[/tex]
but with the given limitation we must have k = 0, because 0 < π/2 - a < π.
On the other hand we also need "tan "a" + tan B = 0, so B = - a + kπ, but again
k = 0, so we obtain
[tex]\frac{\pi }{2} - a=-a[/tex]
a contradiction.
A brick is in the shape of a rectangular prism with a length of 6 inches, a width of 3 inches, and a height of 5.5 inches. The brick has a density of 2.7 grams per cubic centimeter. Find the mass of the brick to the nearest gram.
pls pls pls help
y............. xnxnxnxnxnccncncncnnncncjcjnf
Two kids, Albert and Bhara, are 20.0 m apart. Albert sees a soccer ball 25.0 m away. If the angle between the line formed by Albert and Bhara and the line from Albert to the soccer ball is 25 degrees, how far is Bhara from the soccer ball? Correctly round your answer to the nearest tenth of a meter.
Answer:
11m
I did it by Geometry and used the scale : 1cm represents 5m
1.
Write a function rule for the table.
Answer:
Step-by-step explanation:
If you plot these points on a graph, you would see that this is definitely a line. Let's find the slope of the line first:
[tex]m=\frac{2-1}{6-5}=1[/tex] (I used the last 2 coordinates on the table because I don't like negatives; and since the slope is the same for the whole entire line, it doesn't matter which points you pick to go into your slope formula)
And then use that slope and any other point in the table to write the equation. I am going to use (4, 0), since I like the 0 (less work!)
In point-slope form:
y - 0 = 1(x - 4) and
y = x - 4
That's the function rule (aka equation) for the table.
(PLEASE ANSWER ASAP I JUST NEED TO SEE IF I GOT THE RIGHT ANSWER PLEASE EXPLAIN ALSO)
Answer:
37.15 pounds left
Step-by-step explanation:
Add the two pound values
1.3+1.75= 3.05
Subtract it from the total number of pounds in the bag
40.2-3.05
=37.15
I am really bad at algebra please help!!
I need it now please with explanation ☺️
Answer:
E. 7x
Step-by-step explanation:
3x plus 4x is equal to 7x because they both have the same terms and when added cannot the X of 3x and 4x cannot be joined together .
So they remain the same.
(e) 12x
(f) 12x²
(g) 12x²
(h) 1x
(I) 2x²
(J) 2x²
(K) -10x
(L) -20x
(M) 6x²
(N) 20x²
(O) -15x²
(P) -12x³
Your answers were wrong so i did all of them
Quick tip the power comes only when you multiply and not when you add
For example x + x = 2x
x × x = x²
All the answers
Must click thanks and mark brainliest
Find: (6m5 + 3 – m3 – 4m) – (–m5 + 2m3 – 4m + 6)
Answer: 7m⁵ -3m³ - 3
Working:
= (6m⁵ + 3 - m³ - 4m) -(-m⁵ + 2m³- 4m +6)
= 6m⁵ + 3 - m³ - 4m +m⁵-2m³+4m - 6
= 6m⁵ + m⁵-m³ -2m³ -4m + 4m - 6 +3
= 7m⁵ -3m³ - 3
Answered by Gauthmath must click thanks and mark brainliest
How to you write 1/25 using exponents
Answer:
[tex]5^{-2}[/tex]
Step-by-step explanation:
Using the rule of exponents
[tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{a^{m} }[/tex] , then
[tex]\frac{1}{25}[/tex] = [tex]\frac{1}{5^{2} }[/tex] = [tex]5^{-2}[/tex]
In exponent form, it should be written as [tex]5^{-2}[/tex].
Given that,
The fraction is [tex]\frac{1}{25}[/tex]We need to write in the exponent form
Based on the above information, the calculation is as follows:
[tex]a^{-m} = \frac{1}{a^{m}} \\\\\frac{1}{25} = \frac{1}{5^{2}}[/tex]
[tex]5^{-2}[/tex]
Learn more: brainly.com/question/17429689
how prove the following
cos²(120°-A) + cos²A + cos²(120°+A)= 3/2
Answer:
Sorry if it is not clear enough
A giant pie is created in an attempt to break a world record for baking. The pie is shown below:
A circle is shown with a central angle marked 45 degrees and the diameter marked 15 feet.
What is the area of the slice of pie that was cut, rounded to the nearest hundredth?
22.08 ft2
24.45 ft2
26.32 ft2
28.97 ft2
Answer:
22.08 ft^2
Step-by-step explanation:
First find the area of the full circle
A = pi r^2
The diameter is 15 so the radius is 1/2 (15) = 7.5
A = (3.14) (7.5)^2
=176.625
45 degrees is a fraction of a circle which is 360 degrees
45/360 = 1/8
Multiply the area of the circle by this fraction
1/8 (176.625) =22.078125
Rounding to the nearest hundredth
22.08
Answer:
22.08 ft2
Step-by-step explanation:
ignore drawings of triangles and the answer is not D !! Thank you!!
Answer:
it's A
Step-by-step explanation:
the two triangles make up a parallelogram
PLEASE simplfy 8^15÷8^−3
Answer:
8^18
Step-by-step explanation:
We know that a^b ÷ a^c = a^(b-c)
8^15÷8^−3
8^(15 - -3)
8^(15+3)
8^18
ASAP!! can i get some help on this question please, and can i get a step by step explanation, thank you.
Answer:
2xy^2
Step-by-step explanation:
8/4=2
x^3/x^2=x
y^5/y^3=y^2
Answer:
2xy^2
Step-by-step explanation:
First, 8/4 is 2.
2x^3y^5 / 4x^2y^3
Then, we can bring the x^2 up. It becomes the -x^2. Combined with the x^3, we have x. Finally, we can bring the y^3 up, where it becomes -y^3. Combined with the y^5, we get y^2.
Our final answer is 2xy^2.
PLEASE HELP I WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
correct option is A
Step-by-step explanation:
mark me
Please Help Asap Its Pre-Calculus
The point (−2, 2) is a solution to which of the following systems?
y > −2x + 2 and y > x + 5
y < x + 2 and y > x − 1
y < 2x + 8 and y ≥ −x − 3
y < 2x + 3 and y ≥ −2x − 5
The point [tex](-2,2)[/tex] is a solution of the system given by [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex]
Given point: [tex](-2,2)[/tex]
Given systems:
[tex]y>-2x+2[/tex] and [tex]y>x+5[/tex] [tex]y<x+2[/tex] and [tex]y>x-1[/tex] [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex] [tex]y<2x+3[/tex] and [tex]y \geq -2x-5[/tex]To find: The system to which the given point is a solution
If a point is a solution of a system, then the coordinates of the point satisfies all the equation(s) or inequation(s) of the system. So, we can substitute the x & y coordinates of the given point into the inequalities of each of the given systems and check if the inequalities are satisfied by the coordinates of the point.
(1) [tex]y>-2x+2[/tex] and [tex]y>x+5[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y>-2x+2[/tex] to get,
[tex]2>-2(-2)+2[/tex]
[tex]2>4+2[/tex]
[tex]2>6[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
(2) [tex]y<x+2[/tex] and [tex]y>x-1[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<x+2[/tex] to get,
[tex]2<-2+2[/tex]
[tex]2<0[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
(3) [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<2x+8[/tex] to get,
[tex]2<2(-2)+8[/tex]
[tex]2<-4+8[/tex]
[tex]2<4[/tex]
This is a true inequality. Then, the given point satisfies the first inequality of the system.
We will now check if the point satisfies the second inequality of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y \geq -x-3[/tex] to get,
[tex]2 \geq -(-2)-3[/tex]
[tex]2 \geq 2-3[/tex]
[tex]2 \geq -1[/tex]
This is also a true inequality. Then, the given point also satisfies the second inequality of the system.
Thus, the given point is a solution of this system.
(4) [tex]y<2x+3[/tex] and [tex]y \geq -2x-5[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<2x+3[/tex] to get,
[tex]2<2(-2)+3[/tex]
[tex]2<-4+3[/tex]
[tex]2<-1[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
Thus, we can see that the coordinates of the given point [tex](-2,2)[/tex] satisfies the inequalities of the third system only.
Then, the point [tex](-2,2)[/tex] is a solution of the system given by [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex].
Learn more about geometric solutions of system of linear inequalities here:
https://brainly.com/question/17174433
b)
Four students represented the same pattern with the following equations:
Simon C = 4n + 1
Shania C = 3n + 4 + n-3
Tate C = (6n + 1) + (-2n)
Navdeep C = 2(2n + 3) -5
Use algebra skills to determine which of these four equations are equivalent. Show your work.
Simon
C = 4n + 1
Shania
C = 3n + 4 + n -3
C = 4n + 1
Tate
C = (6n + 1) + (-2n)
C = 6n + 1 - 2n
C = 4n + 1
Navdeep
C = 2(2n + 3) -5
C = 4n + 6 - 5
C = 4n + 1
Therefore all of them are equivalent.
Answered by Gauthmath must click thanks and mark brainliest
Factor the polynomial
Answer:
(x+8)(x+7)
Step-by-step explanation:
Find two numbers that add to
b
and mulitply to
a*c
so find two numbers that add to
15
and mulitply to
56
Those two numbers are 8 and 7
therefore the answer is
(x+8)(x+7)
A motorbike is for sale at $13000. Finance is available at $3000 deposit and monthly
repayments of $520 for 4 years. What is the interest paid?
520 x 12 months x 4 years = 24960
24960 + 3000 deposit = 27,960 total paid.
27,960 - 13,000 = 14,960 total interest paid
Given that cos 75 = X, show that cos 105 = −X
Step-by-step explanation:
cos(90) = 0
around this point the cos function "mirrors" with opposite signs. cos(<90) is positive and cos(>90) is negative.
but |cos(90-a)| = |cos(90+a)| for 0 <= a <= 90
75 = 90 - 15
105 = 90 + 15
so, a = 15
and because of
|cos(90-a)| = |cos(90+a)| for 0 <= a <= 90
cos (90-15) = cos(75) = -cos(90+15) = -cos(105)
come help me!! rack up those points!! needing lots of help with geometry today :)
Answer:
312 in^2
Step-by-step explanation:
Yet again, not the best way but let's add up all the sides...
2(24+96+36) = 2(156) = 312 in^2
Hope this helped!
CAN SOMEONE HELP ME PLEASE
Can someone help me on this please
The choices :
Three
B , E , D
I could really use a hand
Answer : -5a² + 10a
It was way easy ikr ~w~
Answer:
-5a2+10a
Step-by-step explanation:
distribute
-5a(a-2)
-5a2+ 10
18. DEFG is a rectangle. Find the
length of each side.
Answer:
DE=27
EF=13
DG=13
GF=27
Step-by-step explanation:
12x+3=5x+17
12x-5x=17-3
u'll get 14 then simply it by the numbe of X u'll get 2 then replace the X with the number
please help, i don't understand the subject so i need an answer to help me out:) i will give brainliest to a good answer.
To be honest, I don't think it has anything to do with the exponent part at all. Instead, I think it has to do with the fact that integers are inherently easier to grasp compared to fractions (which is exactly what rational numbers are).
For instance, it's much easier to say 2+3 = 5 than it is to say 1/2 + 1/4 = 3/4
So going back to the exponent example, it's easier to say
x^2*x^3 = x^(2+3) = x^5
than it is to say
x^(1/2)*x^(1/4) = x^(1/2+1/4) = x^(3/4)
So that's my opinion as to why rational exponents are more tricky to grasp compared to integer exponents. Of course, everyone learns math differently so maybe some find fractions easier than others.
8 x (5 - 2) = ( _ x 5) - ( _ x 2)
Answer:
8 x (5 - 2) = ( 8 x 5) - ( 8 x 2)
Step-by-step explanation:
8 x (5 - 2) = ( _ x 5) - ( _ x 2)
Distribute
8 x (5 - 2) = ( 8 x 5) - ( 8 x 2)
Subtract – 7x2 + 4x + 2 from x2 – 3.
Answer:
8x^2 - 4x - 5
See the steps below for better explanation:
make g the subject 4m+2g=p
Step-by-step explanation:
4m+2g=p
2g=p-4m
g=(p-4m)/2
Answer:
g = p/2 - 2m
Step-by-step explanation:
4m +2g = p
Subtract 4m from each side
4m -4m +2g = p-4m
2g = p -4m
Divide each side by 2
2g/2 = p/2 - 4m/2
g = p/2 - 2m
Please help will give brainliest, pls don’t just guess
Answer:
B = multiply both sides by 2y+1
Step-by-step explanation:
Answer:
B. multiply both sides by the equation 2y + 1
find the missing side of the triangle
Answer:
197 is the missing side of the triangle
Find an explicit formula for the geometric sequence \dfrac12\,,-4\,,\,32\,,-256,.. 2 1 ,−4,32,−256,..start fraction, 1, divided by, 2, end fraction, comma, minus, 4, comma, 32, comma, minus, 256, comma, point, point. Note: the first term should be \textit{a(1)}a(1)start text, a, left parenthesis, 1, right parenthesis, end text. a(n)=a(n)=a, left parenthesis, n, right parenthesis, equals
Answer:
a(n)= 1/2 * (-8) n-1
Step-by-step explanation:
In a geometric sequence, the ratio between successive terms is constant. This means that we can move from any term to the next one by multiplying by a constant value. Let's calculate this ratio over the first few terms:
\dfrac{-256}{32}=\dfrac{32}{-4}=\dfrac{-4}{\frac12}=\blue{-8}
32
−256
=
−4
32
=
2
1
−4
=−8start fraction, minus, 256, divided by, 32, end fraction, equals, start fraction, 32, divided by, minus, 4, end fraction, equals, start fraction, minus, 4, divided by, start fraction, 1, divided by, 2, end fraction, end fraction, equals, start color #6495ed, minus, 8, end color #6495ed
We see that the constant ratio between successive terms is \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed. In other words, we can find any term by starting with the first term and multiplying by \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed repeatedly until we get to the desired term.
Let's look at the first few terms expressed as products:
nn 111 222 333 444
h(n)\!\!\!\!\!h(n)h, left parenthesis, n, right parenthesis \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large0}\!\!\!\!\!\!
2
1
⋅(−8)
0
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, 0, end superscript \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large1}\!\!\!\!\!\!
2
1
⋅(−8)
1
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, 1, end superscript \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large2}\!\!\!\!\!\!
2
1
⋅(−8)
2
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, squared \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large3}
2
1
⋅(−8)
3
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, cubed
We can see that every term is the product of the first term, \red{\dfrac12}
2
1
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, and a power of the constant ratio, \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed. Note that this power is always one less than the term number nnn. This is because the first term is the product of itself and plainly 111, which is like taking the constant ratio to the zeroth power.
Thus, we arrive at the following explicit formula (Note that \red{\dfrac12}
2
1
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030 is the first term and \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed is the constant ratio):
a(n)=\red{\dfrac12}\cdot\left(\blue{-8}\right)^{\large{\,n-1}}a(n)=
2
1
⋅(−8)
n−1
a, left parenthesis, n, right parenthesis, equals, start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, n, minus, 1, end superscript
Note that this solution strategy results in this formula; however, an equally correct solution can be written in other equivalent forms as well.
