f(1,2)=(3,5) , f(0,2)=(4,-6) tìm ma trận của f đối với cơ sở của R^2 lả B={u=(1,1), v=(3,1)}

Answer:

21 bows

Step-by-step explanation:

Since 21/22 is just 1 short of a whole 1, we can first round it up to a whole 1, and subtract it later. 21 divided by 1 is just 21, and now is the time to subtract the part in which we rounded out. 1/22 times 21 is 21/22, so Layla can't make an entire bow with it.

Answer:

8 inches

Step-by-step explanation:

Let w represent the width.

If the length is 14 inches longer than the width, it can be represented by w + 14.

Use the perimeter formula, p = 2l + 2w. Plug in 60 as the perimeter and w + 14 as l, then solve for w:

p = 2l + 2w

60 = 2(w + 14) + 2w

60 = 2w + 28 + 2w

60 = 4w + 28

32 = 4w

8 = w

So, the width is 8 inches

Answer:

[tex]The \ two \ numbers \ are \ \frac{1}{6} \ and \ \frac{5}{6}[/tex]

Step-by-step explanation:

Let the two numbers be = x , y

Given:

    One of the number is 5 times other number, that is y = 5x ----- ( 1 )

    The sum of their reciprocals is 36/5 , that is

                                                                    [tex]\frac{1}{x} + \frac{1}{y} = \frac{36}{5}[/tex]   ------ ( 2 )

  Substitute y in the second equation.

      [tex]\frac{1}{x} + \frac{1}{5x} = \frac{36}{5}\\\\\frac{1 \times 5}{5 \times x} + \frac{1}{5x} = \frac{36}{5}\\\\\frac{5}{5x} + \frac{1}{5x} = \frac{36}{5}\\\\\frac{5+1}{5x} = \frac{36}{5}\\\\\frac{6}{5x} =\frac{36}{5}\\\\36 \times 5x = 6 \times 5\\\\x = \frac{6 \times 5}{36 \times 5} = \frac{1}{6}[/tex]

  Substitute x in first equation.

   [tex]y = 5x\\\\y = 5 \times \frac{1}{6} \\\\y = \frac{5}{6}[/tex]

Answer as an improper fraction = 16/5

Answer as a mixed number = 3 & 1/5

Answer in decimal form = 3.2

All of those values represent the same thing, but written in a different way.

=============================================================

Explanation:

I'm assuming HM stands for Harmonic Mean in this case.

If so, then we apply the reciprocal operation to each value to get 1/2 and 1/8 (from 2 and 8 respectively).

Add up those fractions:

1/2 + 1/8 = 4/8 + 1/8 = 5/8

Now we'll divide n = 2 over that result. The n = 2 refers to the number of items in the original set.

n divide over (5/8) = 2*(8/5) = 16/5 which is the answer as an improper fraction

-----------

To convert to a mixed number, we can do the following:

16/5 = (15+1)/5

16/5 = 15/5 + 1/5

16/5 = 3 + 1/5

16/5 = 3 & 1/5

Or if you need the answer in decimal form, then using a calculator would get you 16/5 = 3.2

9514 1404 393

Answer:

  13120

Step-by-step explanation:

The sum of terms of a geometric series is ...

  Sn = a1·(r^n -1)/(r -1)

You have n=8, a1=4, r=3, so the sum is ...

  S8 = 4·(3^8 -1)/(3 -1) = 2(3^8 -1) = 13,120

Answer:

Step-by-step explanation:

hope it helps u too

nah you good g shsgshagagagag

shshagsggsgsgwg

Answer: 4125

Step-by-step explanation:

S.I = P X R /100 X T

S.I = 110000 x 5/100 x 9/12 = 4125

= 4125

Answer:

Jhhhuujjjjhfuudjdjdjdjdirr

Answer : A,D,G

Step-by-step explanation:

A factor of experiment is the controlled independent variable.

The factor of experiments are,

Hence option d,e,f and g is the factor of experiment.

A factor of experiment is the controlled independent variable.

Given information

The experiment is conducted on the basis of age.

The experiment is not conducted on the basis of gender.

In the experiment the relation between watching TV a lot or playing video game and child's academic success at school and/or their success at sports tried to obtained.

Factors of this experiment-

Thus the factor of experiments are,

Hence option d,e,f and g is the factor of experiment.

Learn more about the  factor of experiments here;

https://brainly.com/question/840290

Answer:

Option (3)

Step-by-step explanation:

By applying the property of inscribed angle and intercepted arc in the given circle,

"Measure of an inscribed angle is half the measure of the intercepted arc"

[tex]m(\angle LKJ)=\frac{1}{2}m(\text{arc LJ})[/tex]

[tex]85=\frac{1}{2}(20x+10)[/tex]

[tex]170=20x+10[/tex]

[tex]20x=160[/tex]

[tex]x=8[/tex]

Therefore, Option (3) is the correct option.

Answer:

Here the answer is given as follows,

Step-by-step explanation:  

The last three parts are coming with a question mark, so can't answer those parts. post the image or write it properly  

a) Every student is taking at least one course.  

[tex]\forall x \exists y T(x,y)[/tex]  

So for all x, there is a y such that T(x,y) is a true will be given by the above statement  

b) There is a part-time student who is not taking any math courses.  

[tex]\exists x \forall y [A(x) \Lambda (M(y) \rightarrow ~T(x,y))][/tex]

Answer:B

Step-by-step explanation: There is a mathematical way to do this , but the simplest way is just to imagine all of the transformations and choose the most reasonable one. All of the other answers are ridiculous.

Answer:

y = 6/5x -7

Step-by-step explanation:

Answer:

good point I don't know that either

Answer:

LCM = 1440

Step-by-step explanation:

           2 | 72 , 96 , 120

           2 | 36, 48, 60

           2 | 18 , 24 , 30

           2 | 9 , 12 , 15

           2 | 9 , 6 , 15

           3 | 9 , 3 , 15

           3 | 3 , 1 , 5

           5 | 1 , 1 , 5

             | 1 , 1 , 1

LCM = 2 x 2 x 2 x 2 x 2 x 3 x 3 x 5 = 1440

9514 1404 393

Answer:

  8√3 ≈ 13.86 ft

Step-by-step explanation:

The light source is usually placed at the focus, so the focus-vertex distance is p=3 ft. The equation for the parabola with its vertex at the origin is ...

  y = 1/(4p)x^2

  y = 1/12x^2

The opening for some y-value extends ±x from the axis of symmetry, so is a total of 2x in width.

For y=4, the corresponding value of x is ...

  4 = 1/12x^2

  48 = x^2

  √48 = x = 4√3

Then the width of the searchlight opening is ...

  2(4√3 ft) = 8√3 ft ≈ 13.86 ft

Answer:

1st option

Step-by-step explanation:

Given the zero product

(x - 3)(x + 5) = 0 , then

x - 3 = 0 ; x + 5 = 0

Answer:

3

Step-by-step explanation:

(10, 5) and (15,20)

m = rise/run

m = ∆y/∆x

m = (y₂ - y₁) / (x₂ - x₁)

m = (20 - 5) /(15 - 10)

m = 15/5

m = 3

Answer:

Kindly check explanation

Step-by-step explanation:

Given :

Pool dimension :

rectangular floor that measures 22 feet by 13 feet and a flat ceiling that is 7 feet above the floor

Floor area = length * width

Floor area = 22 * 13 = 286 ft²

Volume of the pod :

Floor area * height = 286ft² * 7ft = 2002 ft³

2.)

Surface area = length * width

Surface area = 28 * 20 = 560 ft²

Volume of the pool :

Surface area * deptb = 560ft² * 7ft = 2002 ft³

3.)

Area of flower bed = length * width

Floor area = 30 * 5 = 150 ft²

Volume of the soil flowerbed holds :

Depth = 1.1 m

Area of flowerbed * depth =150ft² * 1.2ft = 180 ft³

The solution is given below.

A number line is a pictorial representation of numbers on a straight line. In elementary mathematics, a number line is a picture of a graduated straight line that serves as visual representation of the real numbers. Every point of a number line is assumed to correspond to a real number, and every real number to a point.

here, we have,

Refer to the fraction strip to show 3/4 & 6/8 are same.

Also if you reduce 6/8 by dividing 2 to numerator & denominator…

it’s 3/4.

The solution is attached below.

To learn more on number line click:

brainly.com/question/29162579

#SPJ2

Answer:

so that you will multiply 15 * 4.

Step-by-step explanation:

15*4 = 60 now you divide 60 by 4 and the answer will be 15.

Đáp án là C: 8+25i nhé

8+ 25i

Answer:

C. 8+25i

Just took it, it's correct :)

Answer:

Problem 20)

[tex]\displaystyle \frac{dy}{dx}=(\cos x)^x\left(\ln \cos x-x\tan x\right)[/tex]

Problem 21)

A)

The velocity function is:

[tex]\displaystyle v(t) =2\pi(\cos(2\pi t)-\sin(\pi t))[/tex]

The acceleration function is:

[tex]\displaystyle a(t)=-2\pi^2(2\sin(2\pi t)+\cos(\pi t))[/tex]

B)

[tex]s(0)=2\text{, }v(0) = 2\pi \text{ m/s}\text{, and } a(0) = -2\pi^2\text{ m/s$^2$}[/tex]

Step-by-step explanation:

Problem 20)

We want to differentiate the equation:

[tex]\displaystyle y=\left(\cos x\right)^x[/tex]

We can take the natural log of both sides. This yields:

[tex]\displaystyle \ln y = \ln((\cos x)^x)[/tex]

Since ln(aᵇ) = bln(a):

[tex]\displaystyle \ln y =x\ln \cos x[/tex]

Take the derivative of both sides with respect to x:

[tex]\displaystyle \frac{d}{dx}\left[\ln y \right]=\frac{d}{dx}\left[x \ln \cos x\right][/tex]

Implicitly differentiate the left and use the product rule on the right. Therefore:

[tex]\displaystyle \frac{1}{y}\frac{dy}{dx}=\ln \cos x+x\left(\frac{1}{\cos x}\cdot -\sin(x)\right)[/tex]

Simplify:

[tex]\displaystyle \frac{1}{y}\frac{dy}{dx}=\ln \cos x-\frac{x\sin x}{\cos x}[/tex]

Simplify and multiply both sides by y:

[tex]\displaystyle \frac{dy}{dx}=y\left(\ln \cos x-x \tan x\right)[/tex]

Since y = (cos x)ˣ:

[tex]\displaystyle \frac{dy}{dx}=(\cos x)^x\left(\ln \cos x-x\tan x\right)[/tex]

Problem 21)

We are given the position function of a particle:

[tex]\displaystyle s(t)= \sin (2\pi t)+2\cos(\pi t)[/tex]

A)

Recall that the velocity function is the derivative of the position function. Hence:

[tex]\displaystyle v(t)=s'(t)=\frac{d}{dt}[\sin(2\pi t)+2\cos(\pi t)][/tex]

Differentiate:

[tex]\displaystyle \begin{aligned} v(t) &= 2\pi \cos(2\pi t)-2\pi \sin(\pi t)\\&=2\pi(\cos(2\pi t)-\sin(\pi t))\end{aligned}[/tex]

The acceleration function is the derivative of the velocity function. Hence:

[tex]\displaystyle a(t)=v'(t)=\frac{d}{dt}[2\pi(\cos(2\pi t)-\sin(\pi t))][/tex]

Differentiate:

[tex]\displaystyle \begin{aligned} a(t)&=2\pi[-2\pi\sin(2\pi t)-\pi\cos(\pi t)]\\&=-2\pi^2(2\sin(2\pi t)+\cos(\pi t))\end{aligned}[/tex]

B)

The position at t = 0 will be:

[tex]\displaystyle \begin{aligned} s(0)&=\sin(2\pi(0))+2\cos(\pi(0))\\&=\sin(0)+2\cos(0)\\&=(1)+2(1)\\&=2\end{aligned}[/tex]

The velocity at t = 0 will be:

[tex]\displaystyle \begin{aligned} v(0)&=2\pi(\cos(2\pi (0)-\sin(\pi(0))\\&=2\pi(\cos(0)-\sin(0))\\&=2\pi((1)-(0))\\&=2\pi \text{ m/s}\end{aligned}[/tex]

And the acceleration at t = 0 will be:

[tex]\displaystyle \begin{aligned} a(0) &= -2\pi ^2(2\sin(2\pi(0))+\cos(\pi(0)) \\ & = -2\pi ^2(2\sin(0)+\cos(0)) \\ &= -2\pi ^2(2(0)+(1)) \\ &= -2\pi^2(1) \\ &= -2\pi^2\text{ m/s$^2$} \end{aligned}[/tex]

Answer:

x + 5y = 237

5x + 5y = 465

Step-by-step explanation:

Let

x = length of cardio class

y = length of weightlifting class

x + 5y = 237 (1)

5x + 5y = 465 (2)

Using elimination method

Subtract (1) from (2) to eliminate y

5x - x = 465 - 237

4x = 228

x = 228/4

x = 57 minutes

Substitute x = 57 into (1)

x + 5y = 237 (1)

57 + 5y = 237

5y = 237 - 57

5y = 180

y = 180/5

y = 36 minutes

x = length of cardio class = 57 minutes

y = length of weightlifting class = 36 minutes

the answer is b no trend

Step-by-step explanation:

We have,

[tex]g(x)=x^3+x^2-x-2[/tex]

To find g(-1), put -1 in place of x i.e.

[tex]g(-1)=(-1)^3+(-1)^2-(-1)-2\\\\=-1[/tex]

To find g(1), put 1 in place of x i.e.

[tex]g(1)=1^3+1^2-1-2\\\\=-1[/tex]

To find g(2), put 2 in place of x i.e.

[tex]g(2)=2^3+2^2-2-2\\\\=8[/tex]

g(2) + g(1) = 8+(-1)

= 7

Hence, this is the required solution.

Answer:7

Step-by-step explanation: mark brainliest pls lol

Answer:6

Step-by-step explanation:

265-25

240/4

6

Answer:

60

Step-by-step explanai  o

n:

265 -25=  240

240/4=6 0