Evaluate i^15 i^12
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Hello!

(1/3)^2x = (1/3)^x+14 <=>

<=> 2x = x + 14 <=>

<=> 2x - x = 14 <=>

<=> x = 14

Good luck! :)

Answer:

K=30

Step-by-step explanation:

120÷4 = 30

k=30

The value of k for selecting 40 teachers out of 120 is 1 / 3.

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

Probability = Number of favourable outcomes / Number of sample

Given that there are 120 teachers in an ABC school and 40 teachers need to be selected,

The value of k will be calculated by the concept of probability as below,

k =  Number of favourable outcomes / Number of sample

k = 40 / 120

k = 1/3

Therefore, the value of k for selecting 40 teachers out of 120 is 1 / 3.

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Answer: John Graunt

Step-by-step explanation:

John Graunt is referred to as the Columbus of statistics because his book made a fundamental contribution by attempting to demonstrate the quantitative characteristics of birth and death data.

He's regarded as the founder of demography which is the statistical study of the population of human beings.

Answer:

pay = $500 + (.08*Sales)

Step-by-step explanation:

Given:

Clicks = 50

Impressions = 5000

To find:

The CTR percentage.

Solution:

We know that,

[tex]CTR=\dfrac{\text{Clicks}}{\text{Impressions}}\times 100[/tex]

Substituting the given values, we get

[tex]CTR=\dfrac{50}{5000}\times 100[/tex]

[tex]CTR=\dfrac{1}{100}\times 100[/tex]

[tex]CTR=1\%[/tex]

Therefore, the correct option is A.

Answer:

Rotation 90⁰ clockwise about point (-1,-1)

Answer:

Hence, the required answers are (i) r= -s/(2nm-1) and r=g.

Step-by-step explanation:

solution: m= r-s/2nr

i) m= r-s/2nr  2)  m(2nr) = r-s (i) s=117 ,m=2, n=-3

2) 2xnxmxr= r-s        2) r= -s/(2nm-1)

3) move the "r" on the right to the 2)   r=  -117/(2x(-3)x2)-16

-2nrm-r= -s

- r(r-2nm-1)= -s                     2)  r= (-117/-13)=)r=g

- r= -s/(2nm-1)

Hence, the required answers are (i) r= -s/(2nm-1) and r=g.

Hi there!

[tex]\large\boxed{f''(x) = 2 - \frac{4}{x^{3}}}[/tex]

[tex]f(x) = x^2 - \frac{2}{x}[/tex]

Recall the power rule:

[tex]\frac{dy}{dx} x^n = nx^{n-1}[/tex]

Rewrite the function for ease of differentiation:

[tex]f(x) =x^2 - 2x^{-1}[/tex]

Use the power rule:

[tex]f'(x) = 2x + 2x^{-2}[/tex]

Take the derivative once more:

[tex]f''(x) = 2 - 4x^{-3}[/tex]

Rewrite:

[tex]f''(x) = 2 - \frac{4}{x^{3}}[/tex]

Answer:

Hollerith tabulating machine

Step-by-step explanation:

The Hollerith tabulating machine was invented by Herman Hollerith in other to assist in the data processing of the United States 1890 election. This machine was used to read and summarize the information stored on punchcards. This machine paved the way for the development of enhanced models which were employed for accounting and some other aspects related to business management.

³√5 / ⁴√5 = ¹²√5 = 5^1/12

5^1/12

Answer:

the answer is  5/|1 5

Step-by-step explanation:

Answer:

Each area is equal to half the area of ABCD

Step-by-step explanation:

AX ≅ CY    

In parallelogram, opposite sides are equal.

AB = CD

AX + XB = CY + YD

 CY + XB = CY + YD

          XB = CY + YD - CY

XB  = CY

Both trapezoids have equal area

Area of AXYD + area of BXYC =  area of ABCD        

Answer:

A. )  Each area to equal to half of the area of ABCD

Step-by-step explanation:

Edge 2021

Hello,

Answer is C

[tex]a_1=0.5=\dfrac{1}{2} \\\\a_2=-0.1=-\dfrac{1}{10} =a_1*(-\dfrac{2}{10} )=a_1*(-\dfrac{1}{5} )\\\\a_3=0.02=\dfrac{2}{10^2} =a_2*(-\dfrac{2}{10} )=a_2*(-\dfrac{1}{5} )=a_1*(-\dfrac{1}{5} )^2\\...\\a_n=a_1*(-\dfrac{1}{5} )^{n-1}\\\\\boxed{a_n=0.5*(-0.2)^{n-1}}\\[/tex]

Answer:

x = 2.1

Step-by-step explanation:

We have:

[tex]\frac{x}{sin90}[/tex] = [tex]\frac{1.3}{sin38}[/tex]

=> sin38 × x = sin90 × 1.3

=> x = 1.3 ÷ sin38

=> x = 2.11155001... = 2.1

<3 Have a nice day!!

The value of x for the given triangle will be, x = 2.1.

Trigonometry is a branch of mathematics that deals with the study of the relationships between the sides and angles of triangles. It is used to solve problems involving angles and distances and is applied in a wide range of fields such as engineering, physics, architecture, and navigation, among others.

The value of x will be calculated as,

x / sin(90) = 1.3/ sin(38)

sin38 × x = sin90 × 1.3

x = 1.3 ÷ sin38

x = 2.11155001...

x = 2.1

The value of x will bed x =2.1.

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Given:

The x- intercepts of a parabola are (0,-6) and (0,4).

The parabola crosses the y- axis at -120.

Lucas said that an equation for the parabola is [tex]y=5x^2+10x-120[/tex] and that the coordinates of the vertex are (-1, -125).

To find:

Whether Lucas is correct or not.

Solution:

The x- intercepts of a parabola are (0,-6) and (0,4). It means (x+6) and (x-4) are the factors of the equation of the parabola.

[tex]y=a(x+6)(x-4)[/tex]             ...(i)

The parabola crosses the y- axis at -120. It means the equation of the parabola must be true for (0,-120).

[tex]-120=a(0+6)(0-4)[/tex]

[tex]-120=a(6)(-4)[/tex]

[tex]-120=-24a[/tex]

Divide both sides by -24.

[tex]\dfrac{-120}{-24}=a[/tex]

[tex]5=a[/tex]

Substituting [tex]a=5[/tex] in (i), we get

[tex]y=5(x+6)(x-4)[/tex]

[tex]y=5(x^2+6x-4x-24)[/tex]

[tex]y=5(x^2+2x-24)[/tex]

[tex]y=5x^2+10x-120[/tex]

So, the equation of the parabola is [tex]y=5x^2+10x-120[/tex].

The vertex of a parabola [tex]f(x)=ax^2+bx+c[/tex] is:

[tex]Vertex=\left(-\dfrac{b}{2a},f(-\dfrac{b}{2a})\right)[/tex]

In the equation of the parabola, [tex]a=5,b=10,c=-120[/tex].

[tex]-\dfrac{b}{2a}=-\dfrac{10}{2(5)}[/tex]

[tex]-\dfrac{b}{2a}=-\dfrac{10}{10}[/tex]

[tex]-\dfrac{b}{2a}=-1[/tex]

Putting [tex]x=-1[/tex] in the equation of the parabola, we get

[tex]y=5(-1)^2+10(-1)-120[/tex]

[tex]y=5-10-120[/tex]

[tex]y=-125[/tex]

So, the vertex of the parabola is at point (-1,-125).

Therefore, Lucas is correct.

Answer:

I think it would be Maxine's, since they did more tests.

Answer:

2.5 dB/100 ft

Explanation:

If 5 dB was lost after 200 ft of cable and 100 ft is half of 200 ft, then the rate of loss should be 2.5 dB per 100 ft.

Step-by-step explanation:

The total loss is 9 dB

Since we have 250 ft of cable that has a loss rate of 3.6 dB per 100 ft, we need to find the total loss of the 250 ft of cable.

To find this total loss, we multiply the loss rate by the total length of cable.

So, the total loss for the 250 ft of cable, L = loss rate × length of cable.

Since loss rate = 3.6 dB per 100 ft and the length of cable = 250 ft, substituting the values of the variables into the equation, we have

L = loss rate × length of cable.

L =  3.6 dB/100 ft × 250 ft.

L = 3.6 dB/10  × 25.

L = 3.6 × 25/10 dB

L = 3.6 × 2.5 dB

L = 9 dB

So, the total loss is 9 dB

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Answer:

-2,456,000

Step-by-step explanation:

-2.456 x  [tex]10^{6}[/tex] = -2,456,000

Answer:

Solution given;

<ABD=<BAC+<ACB

Since exterior angle of a triangle is equal to the sum of two opposite interior angle

26x+20=19x-15+9x+25

solve like terms

26x+20=28x+10

subtracting both by 10

26x+20-10=28x+10-10

Subtracting both side by 26x

10=28x-26x

2x=10

dividing both side by 2

2x/2=10/2

x=5

Now

<ABD=26*5+20=l50°

The value of <ABD is 150°

Answer:

57.3 minutes

Step-by-step explanation:

We know that the temperature as a function of time of an object is described by the equation:

[tex]T(t) = T_a + (T_0 - Ta)*e^{-k*t}[/tex]

Where:

k is a constant

Tₐ =  room temperature = 68°F

T₀ =  initial temperature of the object = 375°F

Replacing these in our equation we will get

T(t) = 68°F + (375°F - 68°F)*e^{-k*t} = 68°F + (307°F)*e^{-k*t}

And we know that after 25 minutes, at t = 25min, the temperature of the casserole is 190°F

then:

T(25min) = 190°F = 68°F + (307°F)*e^{-k*25 min}

Now we can solve this for k:

190°F = 68°F + (307°F)*e^{-k*25 min}

190°F - 68°F = (307°F)*e^{-k*25 min}

(122°F)/(307°F) = e^{-k*25 min}

Now we can apply the natural logarithm in both sides:

Ln( 122/307) = Ln(e^{-k*25 min}) = -k*25min

Ln( 122/307)/(-25 min) = k = 0.0369 min^-1

Then the temperature equation is:

T(t) = 68°F + (307°F)*e^{-0.0369 min^-1*t}

Now we want to find the value of t such that:

T(t) = 105°F = 68°F + (307°F)*e^{-0.0369 min^-1*t}

We can solve this in the same way:

105°F - 68°F =  (307°F)*e^{-0.0369 min^-1*t}

37°F =  (307°F)*e^{-0.0369 min^-1*t}

(37°F)/(307°F) = e^{-0.0369 min^-1*t}

Ln( 37/307) = -0.0369 min^-1*t

Ln( 37/307)/( -0.0369 min^-1 ) = 57.3 min

So after 57.3 minutes, the temperature of the casserrole will be 105°F

Answer:

There will be 97 trees in each orchard.

Step-by-step explanation:

Given that,

Nissa is going to plant 485 trees this year.

Nissa plants 5 orchards of trees.

We need to find the number of trees in each orchard. Let it is n. So, we can find it as follows :

[tex]n=\dfrac{485}{5}\\\\n=97[/tex]

So, there will be 97 trees in each orchard.

Answer:

5/4

Step-by-step explanation:

To Find :-

Solution :-

By question ,

=> cos a = 5/3 = b/h

=> p = √ 5² - 3² = √ 25 -9 = 4

Therefore ,

=> cot a = b/p = 5/4

Answer:

Dude

Answer:

[tex]g(-2)=20[/tex]

Step-by-step explanation:

Given [tex]g(x)=2x^2-2x+8[/tex], substitute what is in the parentheses for [tex]x[/tex] to find an output.

For [tex]g(-2)[/tex], the term [tex]-2[/tex] is in the parentheses. Thus, substitute [tex]x=-2[/tex] into [tex]2x^2-2x+8[/tex] to find [tex]g(-2)[/tex]:

[tex]g(-2)=2(-2)^2-2(-2)+8,\\g(-2)=2\cdot 4+4+8,\\g(-2)=8+4+8,\\g(-2)=\boxed{20}[/tex]

Answer:

a) 8

b) 20

c) 20

Step-by-step explanation:

a) Insert X=0 from g(0) to the equation: 2(0) power of 2 - 2x0 +8.

b) Insert X=(-2) from g(-2) to the equation: 2(-2) power of 2 - 2x(-2) +8.

c) Insert X=3 from g(3) to the question 2(3) power of 2 - 2x3 +8.

Answer:

b^4 / a

Step-by-step explanation:

I have attached the explanation above. hopefully this will help

Hi there!  

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I believe your answer is:  

(0.286, 5.587)

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Here’s why:  

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Hope this helps you. I apologize if it’s incorrect.  

Answer:

x=37

Step-by-step explanation:

because

y=y

or as, 2x-12=x+22+3

or as, 2x-x=12+22+3

or as, x = 37

Answer: ∠1 = 48°, ∠2 = 42°

Step-by-step explanation:

∠M = 90° = ∠1 + (3x)° = (2x + 20)° + (3x)°

2x + 20 + 3x = 90

2x + 3x = 90 - 20

5x = 70

x = 14

∠1 = 2x + 20 = 2(14) + 20 = 28 + 20 = 48°

∠2 = 3x = 3(14) = 42°

(I hope this is right :\)