Answer:
X<6 or X>24
Step-by-step explanation:
How does sample size affect determinations of statistical significance? The smaller the sample size, the more confident one can be in one's decision to reject or retain the null hypothesis. The smaller the sample size, the greater the probability that the variable has an effect. The larger the sample size, the more accurate the estimation of the true population value. The larger the sample size, the greater the probability that the variable has an effect.
Answer:
The larger the sample size, the more accurate the estimation of the true population value.
Step-by-step explanation:
As large will be the sample size more data will be shown and more are the c c changes of it being an estimate of a true population. The sample size can be determined on the basis of use of experience, target variance, confidence level, and target for power.15% of 80 is 60% of what number? There were no answer choices please help!
Answer:
80
Step-by-step explanation:
15 percent of 80 is 12
and 12 is 60 percent of 80!
hope this helps :)
a road rises 16 feet for every 50 feet of horizontal distance covered. in percent what is the grade of the road?
Answer:
32%
Step-by-step explanation:
The slope of the road is measured as
slope = [tex]\frac{rise}{run}[/tex] = [tex]\frac{16}{50}[/tex]
To express as a percentage multiply the fraction y 100% , that is
slope = [tex]\frac{16}{50}[/tex] × 100% = 16 × 2 = 32%
find area of a square garden having a length 45m
Answer:
A = 2025 ft^2
Step-by-step explanation:
The area of a square is given by
A = s^2 where s is the side length
A = 45^2
A = 2025 ft^2
Answer:
Step-by-step explanation:
The area of any square is s^2
s in this case is 45
Area = s^2
Area = 45 * 45
Area = 2025 m^2
Question 13 plz show ALL STEPS
Step-by-step explanation:
Here are some of the graphs:
Blue is g(x) and Green is f(x). The 2nd graph is for the 13b. It shows our graph after 1 transformation. The 3rd graph is after both transformations.
13a. Let use the following values in
[tex]f(x) = \frac{2}{x} [/tex]
We know by definition of rational function x cannot be zero.
Let find some values across interval 2 through 4.
[tex]f(2) = \frac{2}{2} = 1[/tex]
[tex]f(3) = \frac{2}{3} [/tex]
[tex]f(4) = \frac{2}{4} = \frac{1}{2} [/tex]
Let use the following values in
[tex]g(x) = \frac{3x - 1}{x - 1} [/tex]
By definition of rational function, x cannot be 1 because it will make the denominator zero. Let use some values across the interval 0 through 4.
[tex]g(0) = \frac{0 - 1}{0 - 1} = 1[/tex]
[tex]g(2) = \frac{3(2) - 1}{2 - 1} = {5} [/tex]
[tex]g(3) = \frac{8}{2} = 4[/tex]
[tex]g(4) = \frac{11}{3} [/tex]
So graph this in a table of values. I'll post a picture of the table of values on the top.
13b. We need to write g(x) as a transformation of f(x). If we look at the graphs, g(x) has a asymptote at x=1 while f(x) has a asymptote of 0. This means that we need to move f(x) to the right one unit or move (x-1) units.
We will upgrade the graph.
Now we can just add 3 to f(x) to get to g(x).
In the 3rd graph, notice how both graphs coincide. Our transformations is complete.
The answer is
[tex]g(x) = f(x - 1) + 3[/tex]
13c. We can say this as we move f(x) to the right 1 unit and shift f(x) up 3 units.
(-1)×(-1)×(-1)×(2m+1) times where m is a natural number,is equal to?
1. 1
2.-1
3.1 or-1
4.None
Answer:
(2). -1
Step-by-step explanation:
The given parameter can be represented as:
[tex](-1)^{2m + 1}[/tex]
See comment for correct question
Required
The end result
From the question, we understand that m is a natural number
This means that:
[tex]2m + 1 \to[/tex] odd number
So:
[tex](-1)^{2m + 1} = -1[/tex] --- i.e. -1 to the power of an odd number will give -1
Hence; (2) is correct
What are Julie’s taxable wages as a data-entry operator if her withholding allowances total $1,500 and her annual gross pay is $24,500?
Julie's Taxable Wages:
Julie's taxable wages as a data-entry operator is:
= $23,000.
Data and Calculations:
a) Annual gross pay = $24,500
Total withholding allowances = 1,500
Taxable wages (income) = $23,000 ($24,500 - $1,500)
b) Julie's total withholding allowance of $1,500 is the total exemption that reduces how much income tax her employer can deduct from Julie's paycheck. This means that $1,500 will be deducted from $24,500, the gross pay, before arriving at her taxable income.
Thus, Julie's taxable wages represent the difference between her annual gross pay and her total withholding allowances.
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The BBQ club meets every Thursday. The meetings last 2 1/2 hours. There were 5 Thursdays in
September. How many hours did the BBQ club meet in September?
A.2 1/2 hours
B.5 hours
C.12 1/2 hours
D.10 hours
Answer:
12 1/2
Step-by-step explanation:
2 x 5 = 10
1/2 x 5 = 2 1/2
10 + 2 1/2 = 12 1/2
Using stoke theorem evaluate integral F.dr given that F(x,y,z) = z^2i + 2xj + y^2k and the normal surface is given by s: z = 1-x^2-y^2
Your description of the surface is incomplete. But it looks like you're considering some subset of the paraboloid z = 1 - x ² - y ², so I'll go ahead and assume it's the part of said paraboloid above the x,y-plane, so that the boundary is a circle centered at the origin with radius 1.
By Stokes' theorem, the line integral of F along this boundary (∂S) is equal to the surface integral of curl(F ) over the surface itself (S). We have
F(x, y, z) = z ² i + 2x j + y ² k
which has curl
curl(F ) = (∂(y ²)/∂y - ∂(2x)/∂z) i - (∂(y ²)/∂x - ∂(z ²)/∂z) j + (∂(2x)/∂x - ∂(z ²)/∂y) k
curl(F ) = 2y i + 2z j + 2k
Parameterize S by the vector function,
r(u, v) = u cos(v) i + u sin(v) j + (1 - u ²) k
with 0 ≤ u ≤ 1 and 0 ≤ v ≤ 2π.
Take the upward-pointing normal vector to S to be
n = ∂r/∂v × ∂r/∂u
n = (-u sin(v) i + u cos(v) j ) × (cos(v) i + sin(v) j - 2u k)
n = 2u ² cos(v) i + 2u ² sin(v) j + u k
Then the integral of curl(F ) over S - and hence the line integral of F over ∂S - is
[tex]\displaystyle \iint_S \mathrm{curl}(\mathbf F(x,y,z))\cdot\mathbf S \\\\ = \iint_S \mathrm{curl}(\mathbf F(\mathbf r(u,v)))\cdot\mathbf n\,\mathrm du\,\mathrm dv \\\\ = \int_0^{2\pi}\int_0^1 \left(2u\sin(v)\,\mathbf i + 2(1-u^2)\,\mathbf j + 2\,\mathbf k\right)\cdot\left(2u^2\cos(v)\,\mathbf i+2u^2\sin(v)\,\mathbf j+u\,\mathbf k\right)\,\mathrm du\,\mathrm dv \\\\ = \int_0^{2\pi}\int_0^1 \left(4u^3\sin(v)\cos(v)+4(1-u^2)u^2\sin(v)+2u\right)\,\mathrm du\,\mathrm dv \\\\ = \int_0^{2\pi}\left(\sin(v)\cos(v)+\frac8{15}\sin(v)+1\right)\,\mathrm dv \\\\ = \boxed{2\pi}[/tex]
Just to confirm this result, we can compute the line integral directly, since it's not so difficult to deal with. Parameterize ∂S by the vector function
r(t) = cos(t ) i + sin(t ) j
with 0 ≤ t ≤ 2π. (Note that there is a k component, but its coefficient is 0.) Then
dr/dt = -sin(t ) i + cos(t ) j
and the line integral is again
[tex]\displaystyle \int_{\partial S}\mathbf F(x,y,z)\cdot\mathrm d\mathbf r \\\\ = \int_{\partial S} \mathbf F(\mathbf r(t))\cdot\frac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt \\\\= \int_0^{2\pi} (\cos(t)\,\mathbf i+\sin(t)\,\mathbf j)\cdot(-\sin(t)\,\mathbf i+\cos(t)\,\mathbf j)\,\mathrm dt \\\\ = \int_0^{2\pi}2\cos^2(t)\,\mathrm dt \\\\ = \boxed{2\pi}[/tex]
WORTH 30 POINTS PLEASE HELP!!!!! WILL GIVE POINTS
Answer:
2/3 and 4/6
Step-by-step explanation:
5 times 3 times 2
show work
Answer:
30
Step-by-step explanation:
5x3=p
px2 = a
5x3 = 15 x 2 = 30
Answer:
5 times 3 times 2=30
Step-by-step explanation:
5×3=15×2=30
A car dealership is advertising a car for $16,299.99. If the sales tax rate is 6.5 percent, what
is the total tax paid for the car?
A. S993 34
B. $1.000.00
CS1.059 50
DS1.359.19
Answer:
C. 1059.50
Step-by-step explanation:
Sales price x sales tax rate = sales tax
16299.99 x .065 (6.5%) = 1059.50
in a school every student have two participate at least one of the activities athletes or music in a class of 50 students 30 participate in athlete and 25 students participate in music
Answer:
In a class of 50 students, 30 participated in athletics and 25 participated in music. Drawing a Venn- diagram , calculate how many students ...
Answer:
ok
Step-by-step explanation:
t7y7y8 I am not going out for the
If a < 0 and b > 0, then which of the following is true?
Select one:
a. a + b > 0
b. a + b < 0
c.
a + b = 0
d.
The relationship between a and b cannot be determined.
Answer:
d. The relationship between a and b cannot be determined.
Step-by-step explanation:
Given
[tex]a < 0[/tex]
[tex]b > 0[/tex]
Required
Which is true
To do this, we test each of the options using assumed values
[tex]a + b > 0[/tex]
Let:
[tex]a = -5[/tex] [tex]b= 1[/tex]
So:
[tex]-5 + 1 > 0[/tex]
[tex]-4 > 0[/tex] --- false
[tex]a + b < 0[/tex]
Let:
[tex]a = -5[/tex] [tex]b= 7[/tex]
So:
[tex]-5 + 7 < 0[/tex]
[tex]2 < 0[/tex] --- false
[tex]a + b = 0[/tex]
Let:
[tex]a = -5[/tex] [tex]b= 7[/tex]
So:
[tex]-5 + 7 = 0[/tex]
[tex]2 = 0[/tex] --- false
Hence, the relationship is not specific and cannot be determined
Which of the following rational functions is graphed below?
10
- 10
10
tho
A. F(x) =
3
X-7
B. F(x) = x + 3
X-7
C. F(x) =
(x+3)(x-7)
(x+3)(x-7)
D. F(X)
1
(x + 7(x-3)
7\x-
Check the picture out and please help me lol
Vertical asymptote:
A vertical asymptote is a value of x for which the function is not defined, that is, it is a point which is outside the domain of a function;
In a graphic, these vertical asymptotes are given by dashed vertical lines.
An example is a value of x for which the denominator of the function is 0.
In this graphic:
Dashed vertical lines at: [tex]x = -3, x = 7[/tex], thus, for [tex]x - (-3) = x+3[/tex] and [tex]x - 7[/tex] the denominator is zero.
Thus, the function graphed is:
[tex]F(x) = \frac{1}{(x+3)(x-7)}[/tex]
And the correct answer is given by option C.
To take a look at a problem with asymptote, you can check this item https://brainly.com/question/4084552.
The graph is for the rational function f(x) = 1/(x + 3)(x - 7).
Option C is the correct answer.
We have,
To understand the graph of the function f(x) = 1/((x + 3)(x - 7)).
Vertical Asymptotes:
The function has vertical asymptotes at the values of x for which the denominator becomes zero.
The denominator is (x + 3)(x - 7), so the vertical asymptotes occur at
x = -3 and x = 7.
Horizontal Asymptote:
The highest power of x in the denominator is x², and there is no x² term in the numerator, the function approaches 0 as x goes to positive or negative infinity.
The horizontal asymptote is y = 0.
x-Intercept:
To find the x-intercept, we set y = 0 and solve for x:
0 = 1/((x + 3)(x - 7))
Since the numerator can never be zero, the only way the fraction can be zero is if the denominator is zero:
(x + 3)(x - 7) = 0
Solving for x:
x + 3 = 0
x = -3
x - 7 = 0
x = 7
So, the x-intercepts are (-3, 0) and (7, 0).
y-Intercept:
To find the y-intercept, we set x = 0:
f(0) = 1/((0 + 3)(0 - 7)) = 1/(-3 * -7) = 1/21
The y-intercept is (0, 1/21).
Thus,
The graph is for the rational function f(x) = 1/(x + 3)(x - 7).
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Solve the following system of equations for x to the nearest hundredth : y + 2x + 1 = 0; 4y - 4x ^ 2 - 12x = - 7
Answer:
+3.464; -3.464
Step-by-step explanation:
call A = y + 2x + 1 = 0 => y = (1 - 2x)
call B: 4y - 4(x^2) - 12x = -7
=> replace y from A to B =>
4(1 - 2x) - 4(x^2) - 12x = -74 - 8x - 4(x ^ 2) - 12x = -7-8x - 4(x ^ 2) - 12x = -7 - 4 = -11-4(x^2) - (8x - 12x) = -11-4(x^2) + 4x = -11-4(x^2) + 4x + 11 = 0=> get delta Δ = (-4^2) - 4*(-4 * 11) = 192
=> Δ > 0 => got 2 No
=> x1 = [tex]\frac{-4 + \sqrt{192} }{2 * -4}[/tex] = [tex]\frac{1 - 2\sqrt{3} }{2}[/tex] = -1.232
=> x2 = [tex]\frac{-4 - \sqrt{192} }{2 * -4}[/tex]=[tex]\frac{1 + 2\sqrt{3} }{2}[/tex]= 2.232
=> replace x from B into A
=> y1 = (1 - 2x) = (1 - 2 * -1.232) = 3.464
=> y2 = (1 - 2x) = (1 - 2 * 2.232) = - 3.464
construct a 3×3 matrix aij=3j-2i Hellpppp ASAP
[tex]a_{ij}=3j-2i[/tex] is the formula for (i, j )-th entry (row i, column j ) of the matrix. So the matrix would be
[tex]\begin{bmatrix}3\times1-2\times1&3\times2-2\times1&3\times3-2\times1\\3\times1-2\times2&3\times2-2\times2&3\times3-2\times2\\3\times1-2\times3&3\times2-2\times3&3\times3-2\times3\end{bmatrix} = \begin{bmatrix}1&4&7\\-1&2&5\\-3&0&3\end{bmatrix}[/tex]
Solve For X: 12 * X+3=51
Answer:
x=4
Step-by-step explanation:
12 * X+3=51
Subtract 3 from each side
12x +3-3 = 51-3
12x = 48
Divide by 12
12x/12 = 48/12
x = 4
evaluate (-1)^6-4^0+(3/7)^0
Answer:
The answer is 1
.............
please mark this answer as brainlist
An advertising firm wanting to target people with strong desires for success conducted a study to see if such people differed in the types of television shows they watched. Randomly selected participants recorded the shows they watched for a week, then their desire for success was assessed, and finally they were divided into two groups. Low Success seekers watched 8 comedies, 15 romances, 6 documentaries, 13 dramas, and 3 news shows. High Success seekers watched 3 comedies, 3 romances, 9 documentaries, 7 dramas, and 8 news shows.
1. Use the five steps of hypothesis testing.
2. Sketch the chi-square distribution. Be sure your sketch gives a rough indication of its shape and shows the cutoff score and the sample's score.
3. Explain the logic of what you have done to a person who is familiar with the logic and steps of hypothesis testing for the t test and analysis of variance, but who knows nothing about chi-square tests.
4. Figure a measure of effect size and indicate whether it is small, medium, or large.
Answer:
Blablabla
Step-by-step explanation:
Bababa
Solve this inequality: 14 <-7x
Answer:
-2 > x
Step-by-step explanation:
14 <-7x
Divide each side by -7, remembering to flip the inequality
14/ -7 > -7x/-7
-2 > x
Word problems ! Please help
Answer:
19- 2(xy+yz+xz)
20- 16t(5-t)
Step-by-step explanation:
19) factor 2xy+2yz+2xz
2xy+2yz+2xz
=2(xy+yz+xz)
20) factor -16t^2 +80t
=80t-16t^2
=16(5t-t^2)
=16t(5-t)
Solve for x.
A. 1
B. 5
C. 3
D. 12
9514 1404 393
Answer:
A. 1
Step-by-step explanation:
Arc AB is twice the measure of the angle ABC. The sum of the arc measures around the circle is 360°.
2(43x)° +(272x +2)° = 360°
358x +2 = 360 . . . . . . . . . . . . divide by °, collect terms
358x = 358 . . . . . . . . subtract 2
x = 1 . . . . . . . . . . divide by 358
Please help me with this on the picture
Answer:
this is the chapter of linear equations in one variable?
During a test period, an experimental group of 10 vehicles using an 85 percent ethanol-gasoline mixture showed mean CO2 emissions of 667 pounds per 1000 miles, with a standard deviation of 20 pounds. A control group of 14 vehicles using regular gasoline showed mean CO2 emissions of 679 pounds per 1000 miles with a standard deviation of 15 pounds. At α = 0.05, in a left-tailed test (assuming equal variances) the test statistic is:______.
A. 1.321.
B. -2.508.
C. -2.074.
D. -1.717.
Answer:
-1.683
Step-by-step explanation:
Given :
Group 1 :
x1 = 667 ; n1 = 10 ; s1 = 20
Group 2 :
x2 = 679 ; n2 = 14 ; s2 = 15
The test statistic assuming equal variance :
x1 - x2 / √[Sp² * (1/n1 + 1/n2)]
sp² = [(n1 - 1)*s1² + (n2 - 1)*s2²] ÷ (n1 + n2 - 2)
Sp² = [(10 - 1)*20² + (14 - 1)*15²] = 296.59
Test statistic =
(667 - 679)/ √[296.59 * (1/10 + 1/14)]
-12 / 7.1304978
Test statistic = - 1.682
A (5,3) and B (2,-1) are two verticles of a square ABCD and D is on the x axis. Find the coordinate of C and D
Answer:
1) D(1,0), C(-2,-4) or 2) D(9,0), C(6,-4)
Step-by-step explanation:
The vector AB is (2-5, -1-3)= (-3,-4)
The modul of the vector is equal to sqrt (3squared+4squared)=5 (the length of the side AB of square)
Explore the point D (the coordinates of the point is (x,0), y=o, because it is an axis x). AD (x-5, -3)
The modul of AD is sqrt ((x-5)^2+(-3)^2)= sqrt (x^2-10x+25+9), it is equal to the side AD which is equal to AB
sqrt(x^2-10x+34)= 5
x^2-10x+34=25
x^2-10x+9=0
x=1, x=9
D is (1,0) or D is (9,0),
find C, (for D1(1,0))
Find the midpoint of BD (O)
xo= (2+1)/2= 1.5
y0=(-1+0)/2= -0.5
It is the midpoint of Ac too
x0= (xa+xc)/2 1.5 = (5+xc)/2 xc= -2
y0=(ya+yc)/2 -0.5= (3+yc)/2 yc=-4
c(-2,-4)
Find C2 (for D(9,0))
Find the midpoint of BD (O)
x0= (2+9)/2=5.5
y0= (-1+0)/2=-0.5
o(5.5, -0.5)
It is the midpoint of Ac too
x0= (xa+xc)/2 5.5= (5+x)/2 x=6
y0=(ya+yc)/2 -0.5= (3+x)/2 y=-4
if 405 is to be divided among three persons A, B, C in the ratio of 3:5:7, how much money does each one get? Express them in percentages.
Step-by-step explanation:
Pls Mark me
Brainliest!!!!Find the simple interest. The rate is an annual rate unless otherwise noted. Assume 365 days in a year and 30 days per month Round to the nearest cent $600 at 3% for 1 year
9514 1404 393
Answer:
$18
Step-by-step explanation:
The interest is computed using the formula ...
I = Prt
where P is the principal, r is the annual rate, and t is the number of years. The interest is ...
I = $600×0.03×1 = $18
33. The population of Canada, y (in millions), can be approximated by the relation y=
0.146x + 31, where x represents the number of years since 2000.
a. Approximate the population of Canada in the year 2006.
b. In what year did the population of Canada reach approximately 32,752,000?
Answer:x=6573/500,x=13(73/500
Step-by-step explanation:
It will takes 12 years to reach approximately 32,752,000.
What is Equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given:
y = 0.146x + 31
where x represents the number of years since 2000.
a) The population of Canada in the year 2006
x= 6
y= 0.146 x 6 + 31
y = 31.876
b) The population of Canada reach approximately 32,752,000 in
y = 32.752
0.146x + 31= 32.752
0.146x = 1.752
x= 1.752/0.146
x= 12
Hence, it will takes 12 years to reach approximately 32,752,000.
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what should be the rate of simpe interest such that the interest is double of the sun at 10 years
Answer:
you never showed the chocies
Step-by-step explanation:
