Es frecuente que en las instalaciones eléctricas domésticas se utilice alambre de cobre de 2.05 mm de diámetro. Determine la resistencia de un alambre de ese tipo con longitud de 24.0 m

Answers

Answer 1

Answer:

The resistance is 0.124 ohm.

Explanation:

It is common for domestic electrical installations to use copper wire with a diameter of 2.05 mm. Determine the resistance of such a wire with a length of 24.0 m.

diameter, d = 2.05 mm

radius, r = 1.025 mm

Length, L = 24 m

resistivity of copper = 1.7 x 10^-8 ohm m

Let the resistance is R.

[tex]R =\rho \frac{L}{A}\\\\R = \frac {1.7\times10^{-8}\times 24}{3.14\times1.025\times1.025\times 10^{-6}}\\\\R = 0.124 ohm[/tex]


Related Questions

Kevin used a pulley to lift a piano to the third floor of his apartment. His input work was 12,000 J and the output work was 10,000 J. What was the mechanical efficiency of the pulley?

A . 50%
B. 83.3%
C . 120%
D. 16.7%

Answers

Answer:

B

Explanation:

Eff = output work/input work ×100

Hence, Eff = 10000/12000 × 100

Eff = 83.3%

WhAT is the change IN THE entropy of 2.0kg of h2o molecules when transform at a constant pressure of 1 atm from water at 100 degrees celcius to steam at the same tEMPERATURE?

Answers

Answer:

The entropy change is 45.2 kJ/K.

Explanation:

mass of water at 100 C = 2 kg

Latent heat of vaporization, L = 2260 kJ/kg

Heat is

H = m L

H = 2 x 2260 = 4520 kJ

Entropy is given by

S = H/T = 4520/100 = 45.2 kJ/K

The entropy change during the phase change of water from liquids to steam at constant pressure and same temperatures will be zero because, Δ T is zero here.

What is entropy?

Entropy is a thermodynamic parameter determining the measure of randomness in a system. Entropy of a natural reaction or change is always increasing.

According to second third law of thermodynamics the  entropy change of the universe is positive always. At constant pressure the entropy change a of substance of m g is written as:

ΔS = m Cp ln T2/T1.

Where Cp is the specific heat capacity at constant pressure.

Here, the initial temperature and final temperature is same 100 degree celsius. Thus T2/T1 becomes 1 and log 1 is zero. Therefore, the entropy  change in this phase change is zero.

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the internal resistance of each of the following cells E1 and E2 shown in the figure above is 2ohms. calculate the total current in the circuit​

Answers

Answer:

The total current in the circuit is 0.8 A.

Explanation:

internal resistance of each battery = 2 ohm

Total emf of the circuit, E = E1 + E2 = 2 = 2 = 4 V

Now total internal resistance is

[tex]r = \frac{2\times 2}{2 + 2}= 1 ohm[/tex]

Total resistance, R = 4 = 1 = 5 ohm

Let the current is I.

E = I R

4 = I x 5

I = 0.8 A

CITEC Option. Work done will if no net force act on the body. (a) maximum (b) minimum (c) zero (d) all of above​



quick answer

Answers

Explanation:

Yes, if force is acting on a body work done can be zero. When an object is at rest and no external force except gravity is acting on it in this case the work that would be zero as the force acting on it is perpendicular.

For example,

When an object is at rest and no external force except gravity is acting on it in this case the work that would be zero as the force acting on it is perpendicular. Therefore the displacement is zero and if displacement is zero work done would be zero.

We know that,

The work done

W=fs

Suppose that displacement is zero then,

W=f×0

W=0

The work done is zero.

A 17Kg sitting on a shelf has a potential energy of 350J. How high is the shelf? Round your number to the nearest whole number

Answers

Answer:

[tex]{ \bf{potential \: energy = mass \times gravitation \times height}} \\ 350 = 17 \times 10 \times h \\ 350 = 170h \\ height = 2.06 \: metres[/tex]

I need help with this question below ASAP!
What is the acceleration when an unbalanced force of 55 N is exerted on a 40 kg person?

Thank you for your help :)

Answers

Answer:

a = 1.375m/s²

Explanation:

F = m*a

55N = 40kg*a

a = 55N/40kg

a = 1.375m/s²

what is the answer to the question in the picture?​

Answers

Answer:

yes,

Explanation:

because a compound contains two or more chemical elements chemically bond together.

the direction of applied force has to be_____ to the distance in order to say work is done

Answers

Answer:

Explanation:

The direction of the applied force has to be parallel to the distance an object moved in order to say that work has been done.

Which wave has the largest amplitude?
A.D
B.B
C.C
D.A

Answers

Answer:

D. A

General Formulas and Concepts:

Simple Harmonic Motion

Parts of a wave

PeriodAmplitudeWavelengthCrest/Trough

Explanation:

The amplitude is the distance from the horizon to either the crest or trough of a wave.

In layman's terms, it is how high the wave is.

The "highest" wave would be wave A.

∴ our answer is D.

Topic: AP Physics 1 Algebra-Based

Unit: SMH

Answer:

A (The wave)

Explanation:

Wave A

Chiếu tia sáng lên một gương phẳng biết góc tới bằng 15⁰ hãy tính góc phản xạ bằng bao nhiêu

Answers

Answer:

góc phản xạ 15°

Explanatin

Define SI unit of measurement.​

Answers

Answer:

the group of units suggested by the international convention of scientists in 1960 AD to make similarties in meseurment all over the world is called SI units

Uma pilha AA (pilha de controle remoto) fornece ao circuito 1,5V, já uma bateria de carro fornece 12V. Qual a relação entre a energia fornecida entre esses elementos de circuito?

Answers

Answer:

The ratio of energy of AA battery to the car battery is 0.0156.

Explanation:

An AA battery (remote control battery) supplies the circuit with 1.5V, while a car battery supplies 12V. What is the relationship between the energy supplied between these circuit elements?

Supply by AA battery = 1.5 V

Supply by car battery = 12 V

The resistance of the circuit is R.

The energy supplied = V^2/R

The energy supplied by the AA battery is

E = 1.5 x 1.5 / R = 2.25/R

The energy supplied by the car battery is

E' = 12 x 12/ R = 144 / R

So, the ratio of

E : E' = 2.25 : 144 = 0.0156  

What conditions can impact the ecological tolerance of a species?
Pls Answer,30 points

Answers

Answer:

climatic changes

ambient changes

human interferance and the growt of cities and human civilization

and invasive especies

Explanation:

Many different physical factors can impact the ecological tolerance of a species like:-

temperature humidity soil chemistry pHsalinity oxygen levels

How physical factors impact the ecological tolerance of a species?Climatic factors such as temperature and precipitation are key drivers to control species distribution directly.Topographic features such as slope and elevation can impact local climate as well as soil conditions that in turn have varied effects on vegetation structure.The relative distance from a water source can also affect the composition and distribution of woody vegetation because of the resulting varying amount of water available for growth. Physical and chemical soil properties can inform vegetation patterns on a local scale.What is a tolerance range?

The portion of the abiotic factor's range of variation which a species can survive and function in is commonly defined as the tolerance range.

To know more about ecological tolerance here

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If the man pushes with a force of 2000N and friction is 500N, what is the resultant force?

Answers

Answer:

Explanation:

If the force of 2000 N is directed towards the right and the friction is directed towards the left, the 2000 N force is positive and the other is negative. To find the resultant force:

2000 - 500 = 1500 N to the right

What would be the electric field (magnitude and direction) of 1.50 cm to the right of a charge of -6.5 × 10-6 C?

Answers

Answer:

Explanation:

The formula for the electric field is

[tex]E=\frac{kQ}{r^2}[/tex]  where E is the magnitude of the electric field, k is Coulomb's constant, Q is the charge of the particle (which is NOT included in the formula), and r is the distance between the centers of the charges (for lack of a better description).

[tex]E=\frac{(9.0*10^9)*(6.5*10^{-6})}{(1.50)^2}[/tex] and we get, to 2 sig fig's

E = 2.6 × 10⁴ to the left (since electric fields are always pointing toward the negative charge and the electric field is to the right of the negative charge)

Which symbol and unit of measurement are used for electric current?
symbol. A, unit: 1
symbol: C, unit: A
symbol l; unit C
symbol: 1; unitA

Answers

Answer: Symbol is I and unit A

Explanation: A represents Amperes

HOPE THIS HELPS!!!!!!!!

In which phase(s) of matter are the atoms closely packed but still able to slide past each other? O gas O liquid O solid and gas O liquid and solid Save and Exit Next Summit Mark this and return​

Answers

Answer:

Liquid

Explanation:

In most liquids the particles are less densely packed giving them the ability to move around and slide past each other.

What uses non-renewable energy?
A)a gematrical heating system
B)a nuclear power station
C)a solar panel
D)a wind turbine

Answers

A nuclear power station



Renewable energy is energy that can be replenished as we use them

1.the student measures the mass of a piece of metal.its mass is 146g.
(a) the volume of the piece of metal is 20cmcube. calculate the density of the metal .
(b) state the unit.

Answers

Answer:

7.3 g/cubic cm

Explanation:

You divide the mass by the volume to calculate the density of the metal.

146g ÷ 20cm³ = 7.3g/cm³

An ice-skater with a mass of 80kg is holding a bowling ball with a mass of 8 kg. Suppose that the skater tosses the bowling ball forward with a speed of 6 m/s. What is the skater's reactive velocity? Show all work.

Answers

Answer:

0.6 m/s

Explanation:

The details of the masses and velocities are;

The mass of the ice skater, m₁ = 80 kg

The mass of the ball, m₂ = 8 kg

The speed with which the skater tosses the ball forward, v₂ = 6 m/s

Therefore;

According to the principle of conservation of linear momentum, we have;

m₁·v₁ = m₂·v₂

Where;

v₁ = The skater's reactive velocity

Therefore, we get;

80 kg × v₁ = 8 kg × 6 m/s

v₁ = 8 kg × 6 m/s/(80 kg) = 0.6 m/s

The skater's reactive velocity, v₁ = 0.6 m/s.

The moon is 3x10^5 km away from Nepal and the mass of the moon is 7x10^22 kg. Calculate the force with which the Moon pulls every kilogram of water in our rivers.

Answers

Answer:

Approximately [tex]5.19 \times 10^{-5}\; \rm N[/tex].

Explanation:

Let [tex]G[/tex] denote the gravitational constant. ([tex]G \approx 6.67 \times 10^{-11} \; \rm N \cdot kg^{-2} \cdot m^{2}[/tex].)

Let [tex]M[/tex] and [tex]m[/tex] denote the mass of two objects separated by [tex]r[/tex].

By Newton's Law of Universal Gravitation, the gravitational attraction between these two objects would measure:

[tex]\displaystyle F = \frac{G \cdot M \cdot m}{r^{2}}[/tex].

In this question: [tex]M = 7 \times 10^{22}\; \rm kg[/tex] is the mass of the moon, while [tex]m = 1\; \rm kg[/tex] is the mass of the water. The two are [tex]r = 3\times 10^{5}\; \rm km[/tex] apart from one another.

Important: convert the unit of [tex]r[/tex] to standard units (meters, not kilometers) to reflect the unit of the gravitational constant [tex]G[/tex].

[tex]\displaystyle r = 3 \times 10^{5}\; \rm km \times \frac{10^{3}\; \rm m}{1\; \rm km} = 3 \times 10^{8}\; \rm m[/tex].

[tex]\begin{aligned} F &= \frac{G \cdot M \cdot m}{r^{2}} \\ &= \frac{6.67 \times 10^{-11}\; \rm N \cdot kg^{-2}\cdot m^{2} \times 7 \times 10^{22}\; \rm kg \times 1\; \rm kg}{(3 \times 10^{8}\; \rm m)^{2}} \\ &\approx 5.19 \times 10^{-5} \; \rm N\end{aligned}[/tex].

Firing a small rocket that starts at rest, the VMS-2 rises vertically under uniform acceleration, and in 50 seconds all the fuel is burned out. What is the maximum height at which the rocket rises?​

Answers

It has to not be 50 because that’s already the seconds for the fuel burned out

5. According to the law of reflection, the
is equal to the angle of incidence and a line drawn perpendicular to the reflecting surface.
O reflected ray
angle of reflection
O angle of refraction

Answers

Answer:

the answer is ....angle of reflection

You are trying to hold your 550 g physics books with your hand against a vertical wall. Using a force sensor you know that the force you are applying is 10.0 N. Below the book on the floor you have placed a motion sensor. The position time graph for the book is given. Find the coefficient of kinetic friction.

Answers

The book's position is changing linearly with time, so its velocity is constant. This means that the net force acting on the book in the direction parallel to the surface is

F = 10.0 N - n = 0

where n is the magnitude of the normal force on the book due to the wall, and the net force perpedicular to the surface is

F = f - (0.550 kg) g = 0

where f is the mag. of kinetic friction, and f = µn where µ is the coefficient of kinetic friction.

Then

n = 10.0 N

• f = (0.550 kg) g = 5.39 N

• 5.39 N = µ (10.0 N)

==>   µ = 0.539

Answer:

Above answer

Explanation:

The book's position is changing linearly with time, so its velocity is constant. This means that the net force acting on the book in the direction parallel to the surface is

∑ F = 10.0 N - n = 0

where n is the magnitude of the normal force on the book due to the wall, and the net force perpedicular to the surface is

∑ F = f - (0.550 kg) g = 0

where f is the mag. of kinetic friction, and f = µn where µ is the coefficient of kinetic friction.

Then

• n = 10.0 N

• f = (0.550 kg) g = 5.39 N

• 5.39 N = µ (10.0 N)

==>   µ = 0.539

In which condition is relative velocity known by adding the velocity od the first body and that of the second body ?​

Answers

Answer:

when a two bodies A and B are moving at an angle 180° with each other then the relative velocity is the sum of bodies the velocity .i.e,

when the bodies move the opposite direction

then their relative velocity is the sum of individual velocities.

Pluto has a shape that is nearly round,and it orbits the sun,it has five known moons.why is it called a dwarf planet and not a planet?

Answers

There are three things needed to be classified as a planet.

Pluto meets 2 of the 3.

The one it does not meet is it doesn’t “clear the neighborhood” which means a planet needs to be gravitationally dominant over all objects around it. Meaning smaller bodies ( asteroids) would either combine with the larger body making it bigger or pushing them away ( out of their orbit) so they do not collide with the larger body.

A stone is thrown vertically upwards with an initial velocity of 20m/sec. Find the maximum height ot reaches and the time taken by it to reach the height. (g=10m/s2)

plz short numerical ASAP​

Answers

Answer:

The height reached is 20m, The time taken to reach 20m is 2 seconds

Explanation:

Observing the equations of motion we can see that the following equation will be most helpful for this question.

[tex]v^{2} = u^{2} + 2as[/tex]

We are given initial velocity, u

We know that the stone will stop at its maximum height, so final velocity, v

Acceleration, a

And we are looking for the displacement (height reached), s

Substitute the values we are given into the equation

[tex]0^{2} = 20^{2} + 2(10)s[/tex]

Rearrange for s

[tex]0^{2} -20^{2} =20s[/tex]

[tex]-400=20s[/tex]

[tex]\frac{-400}{20} =s[/tex]

s = -20 (The negative is just showing direction, it can be ignored for now)

The height reached is 20m

Use a different equation to find the time taken

[tex]s = vt - \frac{1}{2} at^{2}[/tex]

Substitute in the values we have

[tex]-20=(0)t - \frac{1}{2} (10)t^{2}[/tex]

Rearrange for t

[tex]-20 =0 -5 t^{2}[/tex]

[tex]\frac{-20}{-5} =t^{2}[/tex]

[tex]4 = t^{2}[/tex]

t = 2s

The time taken to reach 20m is 2 seconds

please answer me my question​

Answers

3 - b) weight decreases
4 -a) 50 kg as mass is same everywhere
5 - b) 200 dynes

Room heaters are placed on the floor of a room; Give reason:

Answers

Room heaters are placed on the floor of a room so that the air heated by it rises up and sets up the convection current in the room quickly and uniformly.

Imagine a landing craft approaching the surface of Callisto, one of Jupiter's moons. If the engine provides an upward force (thrust) of 3456 N, the craft descends at constant speed; if the engine provides only 2333 N, the craft accelerates downward at 0.39 m/s2. What is the weight of the landing craft in the vicinity of Callisto's surface

Answers

Answer:

[tex]W=3456 N[/tex]

Explanation:

Force 1 [tex]F_1=3456[/tex]

Force 2 [tex]F_2=2333N[/tex]

Acceleration at stage 2 [tex]a_2=0.39[/tex]

Generally the weight of the Craft W is given as

W= upward force(thrust)

Therefore

[tex]W=3456 N[/tex]

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