Emily made a pot of cream of pumpkin soup for thanksgiving dinner. She put 5
cups of cream in the soup. She poured the soup into 24 small soup bowls. How
much cream (measured in oz.) is used for each small bowl of soup?

Answer:

  see the attachment

Step-by-step explanation:

The repetitive scaling is best handled by a spreadsheet.

Part A

We know the scale factor is 3/2, so we can multiply the number of servings and everything else by 3/2. The scaled recipe will make 9 servings.

__

Part B

Since 15 = 6 + 9, we could arrive at this recipe by adding the Part A recipe to the original recipe. Instead, our spreadsheet uses the suggested 15/6 multiplier.

The formula used is shown in the spreadsheet attachment. It is filled to the right and down to cover all of the recipes and ingredients.

Answer:

Angle E.

Step-by-step explanation:

Hope this helps!

Answer:

The answer is "[tex]\bold{\frac{2}{5}\ \ and \ \ \frac{6}{13}}[/tex]".

Step-by-step explanation:

You have 4/10 opportunities to choose a white ball, and there'll be 7 white balls and 6 black balls out of 13, and so the second time they choose a white one is 7/13, as well as the second time they choose a black, 6/13. people will also have a 4/10 chance.  

There are 6/10 chances which users pick its black ball and 4 white balls would still be picked, but 9 black balls and out 13 balls and thus, its second and third time you select the white one is 4/13 but you are likely to pick a black for the second time is 9/13.  

Taking the diagram of the next tree. The very first draw is marked with a and the second draw is marked with b.

[tex]\to P(a) = \frac{4}{10}\ \ \ \ \ \ \ \ \ P(b) = \frac{6}{10}\\\\\to P(\frac{a2}{a1}) = \frac{7}{13} \ \ \ \ \ \ \ \ \ \ P(\frac{a}{b}) = \frac{4}{13}\\\\\to P(\frac{b2}{a1}) = \frac{6}{13} \ \ \ \ \ \ \ \ \ \ P(\frac{b2}{b1}) = \frac{9}{13}[/tex]

Calculating the second drawn ball is white:

[tex]\to P(b2)=P(a)P(\frac{a2}{b1})+P(b)P(\frac{a}{b})\\[/tex]

              [tex]=\frac{4}{10}\frac{7}{13}+\frac{6}{10}\frac{4}{13}\\\\=\frac{28}{130}+\frac{24}{130}\\\\=\frac{28+24}{130}\\\\=\frac{52}{130}\\\\=\frac{2}{5}\\\\[/tex]

In point b:

[tex]\to P(\frac{b}{a1})= \frac{P(B)P(\frac{a}{b})}{P(a)P(\frac{a2}{b1})+P(b)P(\frac{a}{b})\\}[/tex]

              [tex]=\frac{\frac{6}{10} \frac{4}{13}}{\frac{52}{130}}\\\\=\frac{\frac{24}{130}}{\frac{52}{130}}\\\\=\frac{24}{130} \times \frac{130}{52}\\\\=\frac{24}{52}\\\\=\frac{6}{13}\\[/tex]

Answer:

y = -9x - 82

Step-by-step explanation:

Line with slope m=-9 passing through A(x1, y1) =A(-9,-1)

y-y1 = m(x-x1)

Substitute values

y-(-1) = -9(x-(-9)

y+1 = -9x -81

y = -9x - 82

Answer:

Step-by-step explanation:

We first examine a simple hidden Markov model (HMM). We observe a sequence of rolls of a four-sided die at an "occasionally dishonest casino", where at time t the observed outcome x_t Element {1, 2, 3, 4}. At each of these times, the casino can be in one of two states z_t Element {1, 2}. When z_t = 1 the casino uses a fair die, while when z_t = 2 the die is biased so that rolling a 1 is more likely. In particular: p (x_t = 1 | z_t = 1) = p (x_t = 2 | z_t = 1) = p (x_t = 3 | z_t = 2) = p (x_t = 4 | z_t = 1) = 0.25, p (X_t = 1 | z_t = 2) = 0.7, p (X_t = 2 | z_t = 2) = p (X_t = 3 | z_t = 2) = p (X_t = 4 | z_t = 2) = 0.1. Assume that the casino has an equal probability of starting in either state at time t = 1, so that p (z1 = 1) = p (z1 = 2) = 0.5. The casino usually uses the same die for multiple iterations, but occasionally switches states according to the following probabilities: p (z_t + 1 = 1 | z_t = 1) = 0.8, p (z_t = 2) = 0.9. The other transition probabilities you will need are the complements of these. a. Under the HMM generative model, what is p (z1 = z2 = z3), the probability that the same die is used for the first three rolls? b. Suppose that we observe the first two rolls. What is p (z1 = 1 | x1 = 2, x2 = 4), the probability that the casino used the fair die in the first roll? c. Using the backward algorithm, compute the probability that we observe the sequence x1 = 2, x2 = 3, x3 = 3, x4 = 3 and x5 = 1. Show your work (i.e., show each of your belief for based on time). Consider the final distribution at time t = 6 for both p (z_t = 1) = p (z_t = 2) = 1.

ANSWER:

Let say we have that the first state of the die is state 1. Therefore the probability of this is p(z1=1)=0.5.

Also the probability that the same die is used(i.e. casino would be in the same state) is p(z2=1|z1=1)=0.8.

Again, suppose the first state of the die is state 2. So, p(z1=2)=0.5 and p(z2=2|z1=2)=0.9.

Other transition probabilities can be written as

p(zt+1=2|zt=1)=1-p(zt+1=1|zt=1)=.2

p(zt+1=1|zt=2)=1-p(zt+1=2|zt=2)=.1

p(z3=1|z1=1) = [p(z3=1|z2=2)*p(z2=2|z1=1)]+[p(z3=1|z2=1)*p(z2=1|z1=1)] = 0.1*0.2+0.8*0.8 = 0.66

p(z3=2|z1=2) = [p(z3=2|z2=2)*p(z2=2|z1=2)]+[p(z3=2|z2=1)*p(z2=1|z1=2)] = 0.9*0.9+0.2*0.1 = 0.83

With this, the total probability that the same die is used for the first three rolls (i.e. casino would be in the same state) is  given thus;

{p(z1=1)*p(z3=1|z1=1)}*{p(z1=2)*p(z3=2|z1=2)}

=  0.5*0.66+0.5*0.83 = 0.745

Prob = 0.745

Answer:63

Step-by-step explanation:

Answer:

88%.

Step-by-step explanation:

Multiply the fraction by 100:

(22/25) * 100

= 22 * 4

= 88%.

Answer:

  18

Step-by-step explanation:

Each exterior angle is the supplement of the adjacent interior angle, so is ...

  180° -160° = 20°

The total of all n of these exterior angles is 360°, so we have ...

  n(20°) = 360°

  n = 18 . . . . . . . . . divide by 20°

The polygon is an 18-gon. It has 18 sides.

Answer:

18 Sides

Step-by-step explanation:

Each interior angle = 160°

Each exterior angle = 180° - 160° = 20°

The sum of the exterior angles = 360°

Hence the number of exterior angles =360°/20°

= 18

The polygon has 18 sides (since it has 18 exterior angles).

Hope this helps.

Please mark me as Brainliest.

Complete Question

The complete question is shown on the first uploaded image

Answer:

The coefficient  is  [tex]r =0.81[/tex]

Step-by-step explanation:

From the question we are told that

      [tex]cov(x, y )= 1260[/tex]

      [tex]s_x^2 = 1600[/tex]

     [tex]s_y^2 = 1225[/tex]

Generally the coefficient of determination is mathematically represented as

      [tex]r = [ \frac{cov(x,y)}{ \sqrt{s_x^2} * \sqrt{s_y^2} } ]^2[/tex]

substituting values

      [tex]r = [ \frac{ 1260}{ \sqrt{1600} * \sqrt{1225} } ]^2[/tex]

     [tex]r =0.81[/tex]

let the function be [tex]y=ax^2+bx+c[/tex]

put $x=0, \, y=6$ , to get $c=6$

put $x=2, \, y=16$ , $16=4a+2b+6\implies 2a+b=5$

put $x=3, \, y=33$ , $33=9a+3b+6\implies 3a+b=9$

subtract the two equation, to get $a=4$

now substitute $a$ in first equation, to get $b=5-2\cdot4=-3$

so, $f(x)=4x^2-3x+6$

Answer:

The probability that at least, one of the four children the couple has is a boy is 0.8.

Step-by-step explanation:

Given that boys and girls are equally likely, we want to find the probability of having at least, one boy, from four children..

Note that it is possible to have the following for 4 children:

1. 4 boys, 0 girls

2. 3 boys, 1 girl

3. 2 boys, 2 girls

4. 1 boy, 3 girls

5. 0 boys, 4 girls.

To have at least, one boy, out of the 5 options, only 4 is possible.

1. 4 boys, 0 girls.........YES

2. 3 boys, 1 girl ...........YES

3. 2 boys, 2 girls.........YES

4. 1 boy, 3 girls.............YES

5. 0 boys, 4 girls..........NO

The probability is therefore,

(Probability of event = 4) ÷ (Total possible outcome = 5)

P = 4/5 = 0.8

Answer: 600 students.

Step-by-step explanation:

Ok, we start with 15,000 students.

40% of them had tuition, so the actual number of them that had tuition is:

15,000*0.40 = 6,000.

Now we want to find the number of students that studied math and science.

50% only studied math,

30% only studied science

10% studied other subjects.

So 50% + 30% + 10% did NOT studied both math and science

90% is the percentage that did not study math and mathematics as well as science, then the other 10% did.

Then, out of the 6,000 students that had tuition, 10% studied math and science, the total number is:

6,000*0.10 = 600

Answer:

B(-1,1) so you can find that when you calculation for the basic principles

Answer:

The probability is  [tex]P( \= X \ge 70 ) = 0.07311[/tex]

Step-by-step explanation:

From the question we are told that

    The  population mean is  [tex]\mu = 68[/tex]

      The standard deviation is  [tex]\sigma = \sqrt{36} = 6[/tex]

      The  sample size is  [tex]n = 19[/tex]

Generally the standard error of the mean is mathematically represented as  

            [tex]\sigma_{\= x } = \frac{\sigma }{\sqrt{n} }[/tex]

=>         [tex]\sigma_{\= x } = \frac{6 }{\sqrt{19} }[/tex]

=>         [tex]\sigma_{\= x } = 1.3765[/tex]

Generally the probability that their average score will be at least 70 is mathematically represented as

            [tex]P( \= X \ge 70 ) = 1 - P( \= X < 70 ) = 1 - P(\frac{ \= X - \mu }{\sigma_{\= x}} < \frac{70 - 68}{ 1.3765} )[/tex]

Generally [tex]\frac{ \= X - \mu }{\sigma_{\= x}} = z(The \ z-score \ of \ \= X )[/tex]

So

          [tex]P( \= X \ge 70 ) = 1 - P( \= X < 70 ) = 1 - P(Z <1.453 )[/tex]

From the z-table

            [tex]P(Z <1.453 ) = 0.92689[/tex]

=>          [tex]P( \= X \ge 70 ) = 1 - P( \= X < 70 ) = 1 - 0.92689[/tex]

=>         [tex]P( \= X \ge 70 ) = 1 - P( \= X < 70 ) = 0.07311[/tex]

=>          [tex]P( \= X \ge 70 ) = 0.07311[/tex]

Answer:

-19

Step-by-step explanation:

By looking at the 2 numbers provided, -10 and -4, you can work out that there is a gap of 6 numbers as(-4) - (-10) = 6

There are 2 intervals between -10 and -4, so each interval is

6/2 = 3

a gap of 3

This means the number to the left of -4 is -7, then -10 which works.

From there, you count how many intervals there is between -10 and the ?

There are 3 intervals, so you have to decrease -10 by -3x3 or -9

Therefore the ? is -19

Another way is to just count it directly

The number directly left of -10 is going to be -13, then -16 and finally -19

Answer:

b. steepest slope

Step-by-step explanation:

The cumulative relative frequency curve also known as Ogive is used for reading the median, upper quartile, lower quartile from the curve and calculating the semi-interquartile range when needed.

From the cumulative relative frequency curve, the interval with the highest proportion of measurements is the interval with the steepest slope. This is because the cumulative relative frequency curve always have a positive slope, and given that the interval has the highest proportion, then the slope will be steepest.

[tex] \Large{ \boxed{ \bf{ \color{blue}{Solution:}}}}[/tex]

By using the fact that,

When,

[tex] \large{ \sf{ {a}^{x} =b}}[/tex]

Then, With logarithm base a of a number b:

[tex] \large{ \sf{ log_{a}(b) = x}}[/tex]

☃️So, Let's solve ths question....

To FinD:

[tex] \large{ \sf{log_{2}(256) }}[/tex]

Let it be x,

[tex] \large{ \sf{ \longrightarrow{ log_{2}(256) = x}}}[/tex]

Proceeding further,

[tex] \large{ \sf{ \longrightarrow \: {2}^{x} = 256}}[/tex]

[tex] \large{ \sf{ \longrightarrow \: {2}^{x} = {2}^{8} }}[/tex]

Then, We have same base 2, So

[tex] \large{ \sf{ \longrightarrow \: x = 8}}[/tex]

Or,

➙ log₂(256) = log₁₀(256) / log₁₀(2)

➙ log₂(256) = 2.40823996531 / 0.301029995664

➙ log₂(256) = 8

☕️ Hence, solved !!

━━━━━━━━━━━━━━━━━━━━

Answer:

256

Step-by-step explanation:

log     256 can most easily be found by rewriting 256 as a power of 2:

      2

2^5 * 2^3 = 32*8 = 256, so 2^ (5 + 3) = 2^8.    

Then we have:

  log     256

2        2             = 256

Alternatively, write:

log (down)2 256 = log (down)2 2^8 = 2*8 = 256

Note that your "log (down)^2 and the function y = 2^x are inverse functions that effectively cancel one another.

Answer:

542

Step-by-step explanation:

We are required to find the sample size at 98% confidence interval in this question

E = 0.04

P* = 20% = 0.20

n = p* x (1-p)(Zα/2÷E)²

α = 1 - 0.98

= 0.02

To get Critical value

= 0.02/2 = 0.01

The critical value at 0.01 is 2.33

Inserting values into formula:

O.2 x 0.8(2.33/0.04)²

= 0.8 x 0.2 x 58.25²

= 542.89

The value of n must be an integer therefore the answer is 542.

Answer:

z -score = 0.0459

Step-by-step explanation:

Given that:

the number of children with food allergies at a sample of elementary schools: 3, 9, 5, 5, 14, 10, 5, 11, 9, 6, 1, 8, 10, 7, 9, 13, 18, 9, 8, 11, 9, 7, 6, 14, 12.

The objective is to find the z- score , but before we can do that , we need to determine the mean and the standard deviation of the sample.

Mean = sum of the sample/ total number of the sample

Mean = (3+9+ 5+ 5+ 14+ 10+ 5+ 11+ 9+ 6+ 1+ 8+ 10+ 7+ 9+13+ 18+ 9+ 8+11+ 9+ 7+ 6+ 14+ 12)/25

Mean = 219/25

Mean = 8.76

Standard deviation = [tex]\sqrt{\dfrac {\sum (x_i - \mu)^2}{N}}[/tex]

Mean (in order )= 1, 3,5,5,5,6,6,7,7,8,8,9,9,9,9,9,10,10,11,11,12,13,14,14,18)

Standard deviation = [tex]\sqrt{\dfrac { (8.76 - 1)^2}{25} + \dfrac { (8.76 - 3)^2}{25} +\dfrac { (8.76 - 5)^2}{25} +...+ \dfrac { (8.76 - 18)^2}{25} }[/tex]

Standard deviation = 5.2174

The standard z score formula is:

[tex]z = \dfrac{X- \mu}{\sigma}[/tex]

where X = median (13th observation ) = 9

[tex]z = \dfrac{9- 8.76}{5.2174}[/tex]

[tex]z = \dfrac{0.24}{5.2174}[/tex]

z -score = 0.0459

[tex]10[/tex] divisions between $15.59$ and $15.6$ so each division is $\frac{15.60-15.59}{10}=0.001$

A is 5 division from $15.59$, so, A is $15.59+5\times 0.001=15.595$

similarly, C is 4 division behind $15.59$ so it is $15.590-4\times0.001=15.586$

and B is $15.601$

Answer:

The answer is below

Step-by-step explanation:

The Freeman family barbecued veggie burgers, corn cobs, and mushroom caps. 3/8 of the items barbecued are veggie burgers, and 1/3 of the items barbecued are corn cobs.

Let the total number of berbecued items be x. Therefore:

x = barbecued veggie burgers + barbecued corn cobs + barbecued mushroom caps

Barbecued veggie burgers = (3/8)x, barbecued corn cobs = (1/3)x, Let barbecued mushroom caps be y

Substituting:

x = (3/8)x + (1/3)x + y

Multiply through by 24

24x = 9x + 8x + 24y

24x = 17x + 24y

24y = 24x - 17x

24y = 7x

y = (7/24)x

barbecued mushroom caps = (7/24) of items

7/24 of the items barbecued are mushroom caps

Using fractions, it is found that the fraction of barbecued items that are mushroom caps is of [tex]\frac{7}{24}[/tex].

---------------------------

---------------------------

Thus:

[tex]\frac{3}{8} + \frac{1}{3} + x = 1[/tex]

Then:

[tex]\frac{3\times3 + 8\times1 + 24x}{24} = 1[/tex]

[tex]\frac{17 + 24x}{24} = 1[/tex]

[tex]17 + 24x = 24[/tex]

[tex]24x = 7[/tex]

[tex]x = \frac{7}{24}[/tex]

The fraction of barbecued items that are mushroom caps is of [tex]\frac{7}{24}[/tex].

A similar problem is given at https://brainly.com/question/4231000

Answer:

The two choices are true by CPCTC. Are there other choices that were not posted?

Answer:

e. HS

Step-by-step explanation:

The argument:

[(P ≡ T) • (H • N)] ⊃ (T ⊃ ~S)

(T ⊃ ~S) ⊃ [(H ∨ E) ∨ R]

[(P ≡ T) • (H • N)] ⊃ [(H ∨ E) ∨ R]

is an instance of one of hypothetical syllogism (HS).

Hypothetical syllogism contains conditional statements for its premises.

Let

p = [(P ≡ T) • (H • N)]

q = (T ⊃ ~S)

r = [(H ∨ E) ∨ R]

The this can be interpreted as:

p ⊃ q

q ⊃ r

p ⊃ r

This interprets that:

If p then q

but if q then r

therefore if p then r

Thus, in logic HS is a valid argument form:

p → q

q → r

∴ p → r

Note that ⊃ symbol is used to symbolize implication relationships. This is used in conditional statements which are represented in the if...then... form.  For example p ⊃ q means: if p then q. So the type of Hypothetical syllogism used in this is conditional syllogism.

There are three parts of syllogism:

major premise

minor premise

conclusion

An example is:

If ABC is hardworking, then ABC will go to a good college.  

Major premise: ABC is hardworking.

Minor premise: Because ABC is hardworking , ABC will score well.

Conclusion: ABC will go to a good college.

Example of Hypothetical syllogism:

If AB is a CD, then EF is a GH

if WX is a YZ, then AB is a CD

therefore if WX is a YZ, then EF is a GH

This can be understood with the help of an example:

If you study the topic, then you will understand the topic.  

If you understand the topic, then you will pass the quiz.

Therefore, if you study the topic, then you will pass the quiz.

Complete question is;

A machine used to fill gallon-sized paint cans is regulated so that the amount of paint dispensed has a mean of 128 ounces and a standard deviation of 0.20 ounce. You randomly select 35 cans and carefully measure the contents. The sample mean of the cans is 127.9 ounces. Does the machine need to be? reset? Explain your reasoning.

(yes/no)?, it is (very unlikely/ likely) that you would have randomly sampled 35 cans with a mean equal to 127.9 ?ounces, because it (lies/ does not lie) within the range of a usual? event, namely within (1 standard deviation, 2 standard deviations 3 standard deviations) of the mean of the sample means.

Answer:

Yes, we should reset the machine because it is unusual to have a mean equal to 127.9 from a random sample of 35 as the mean of 127.9 doesn't fall within range of a usual event with 2 standard deviations of the mean of the sample means.

Step-by-step explanation:

We are given;

Mean: μ = 128

Standard deviation; σ = 0.2

n = 35

Now, formula for standard error of mean is given as;

se = σ/√n

se = 0.2/√35

se = 0.0338

Normally, the range of values should be within 2 standard deviations of mean. In this case, normal range of values will be;

μ ± 2se = 128 ± 0.0338

This gives; 127.9662, 128.0338

So, Yes, we should reset the machine because it is unusual to have a mean equal to 127.9 from a random sample of 35 as the mean of 127.9 doesn't fall within range of a usual event with 2 standard deviations of the mean of the sample means.

Answer:

The two numbers are: 8 and 16.

Step-by-step explanation:

Let the two unknown numbers be a and b.

The sum of the two number is 24. In other words:

[tex]a+b=24[/tex]

The second number is equal to twice the first number. In other words:

[tex]a=2b[/tex]

This is a system of equations. Solve by substitution:

[tex]a+b=24\\a=2b\\\\2b+b=24\\3b=24\\b=8\\a=2b\\a=2(8)=16[/tex]

Answer:

Since the critical f-value of the test statistic is less than the f value of 2.9130, we will fail to reject the null hypothesis and conclude that there's no sufficient evidence to support the claim that there is a difference in the variation in the listening times for men and women

Step-by-step explanation:

We are given;

Sample size for men; n1 = 13

Sample size for women; n2 = 11

standard deviation for men; s1 = 8 minutes

Standard deviation for women; s2 = 18 minutes.

Significance level; α = 0.1

Let's state the hypothesis;

Null hypothesis;H0: (μ1)² = (μ2)²

Alternative hypothesis;Ha: (μ1)² ≠ (μ2)²

The value of the test statistic would be;

F = (s1)²/(s2)²

F = 8²/18² = 0.1975

Now, degree of freedom for n1 is;

DF1 = n1 - 1

DF1 = 13 - 1

DF1 = 12

Also, degree of freedom for n2 is;

DF2 = 11 - 1

DF2 = 10

Now, since it's two tailed, we will make use of α/2 for the F-distribution table.

Thus, α/2 = 0.1/2 = 0.05

So,from the f-table attached, at df1 = 12 and df2 = 10,the F-Critical value is;

F_α/2 = 2.9130

Since,the critical f-value of the test statistic is less than 2.9130, we will fail to reject the null hypothesis and conclude that there's no sufficient evidence to support the claim that there is a difference in the variation in the listening times for men and women

Answer:

4 cups of flour is needed and 4/3 cups of sugar

Step-by-step explanation:

Given

2 dozen Muffins; 3 cups of flour and 1 cup of sugar

Required

Determine the cups of flour if 18 muffins is used

First, we have to determine the proportion of the number of muffins used previously and now;

Represent this with p;

[tex]p = \frac{2\ dozen}{18}[/tex]

[tex]p = \frac{2 * 12}{18}[/tex]

[tex]p = \frac{24}{18}[/tex]

[tex]p = \frac{4}{3}[/tex]

Multiply this to the previous cups of flours and sugars;

Cups of flour = p * previous cups of flour

[tex]Cups\ of\ flour = \frac{4}{3} * 3[/tex]

[tex]Cups\ of\ flour = 4[/tex]

Cups of Sugar = p * previous cups of sugar

[tex]Cups\ of\ sugar= \frac{4}{3} * 1[/tex]

[tex]Cups\ of\ sugar= \frac{4}{3}[/tex]

Hence, 4 cups of flour is needed and 4/3 cups of sugar

Answer:

B. ​No, because the probability of success is different for each trial.

The experiment is not binomial.

Step-by-step explanation:

The trials are not independent  because they are chosen without replacement.

There are successes and failures but the trials are dependent.

So it is not binomial.

When the balls are not replaced the probability of success becomes different for each ball.

Suppose  we have 10 balls and we pick out 1 so the p1 = 1/10

but when we again pick out another without replacement the p2= 1/9

This explains why it is not binomial. In binomial the n is fixed.

Answer:

6 pounds 10 ounces

Step-by-step explanation:

I take this to mean "a baseball weighs approximately 3 pounds and a golf ball three pounds ten ounces."

Adding these two weights together, we get 6 pounds 10 ounces.

Answer:

ans right down there

Step-by-step explanation:

Here,Part 1

if the circle has a radius r so,

15 = r theta

here, theta is in radian.

Part 2

[tex]theta = \frac{15}{6} = 2.5[/tex]

part 3

[tex]theta = \frac{2.5 \times 180}{\pi} [/tex]

or theta =

143.2394487827058021919953870352629258310136811664108038729006