Answer:
Multiply the product of 16,544 x 7 by 10 as it id the same as multiplying 16,544 x 70.
What is the distance between point C and point D?
Question 5 options:
A)
17 units
B)
13 units
C)
12 units
D)
√85 units
Answer:
B. 13 units
Step-by-step explanation:
let
(x1 , y1) = (-4 , -6)
(x2 , y2) = (1 , 6)
distance between CD = root (x2 - x1)^3 + (y2 - y1)
= root {1 - ( -4)}^2 + {6 - ( -6)}^2
= root {1 +4}^2 + {6+6}^2
= root 5^2 + 12^2
= root 25 + 144
= root 169
= 13 units ans
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!! Chapt 15 part 2a
Explain the process of matrix multiplication. What are the dimensions 9f of the resulting matrix? Use the following matrices for your explanation of the process. AB. Show your work.
We are given the matrices A and B
[tex]A = \left[\begin{array}{ccc}2&3&-1\\0&2&5\\2&4&0\end{array}\right][/tex]
[tex]B = \left[\begin{array}{ccc}2\\1\\2\end{array}\right][/tex]
Multiplying these matrices:
We multiply matrices by taking the first column of the first matrix and the first row of the second matrix
we will multiply all the terms of the first column of the first matrix and multiply them by the terms of the first row of the second matrix, one by one
[tex]AB = \left[\begin{array}{ccc}2(2) + 3(1) + -1(2)\\0(2) + 2(1) + 5(2)\\2(2) + 4(1) + 0(2)\end{array}\right][/tex]
[tex]AB = \left[\begin{array}{ccc}5\\12\\8\end{array}\right][/tex]
9514 1404 393
Explanation:
Two matrices with dimensions (numbers of (rows, columns)) of (a, b) and (c, d) can only be multiplied if the number of columns in the left matrix is equal to the number of rows in the right matrix. That is, b=c. The dimensions of the product matrix will be (a, d).
For row i of the left matrix and column j of the right matrix, element a(i,j) of the product matrix is the dot-product of row i with column j. (The dot-product of two vectors is the sum of the products of corresponding elements.)
__
The example matrices have (row, column) dimensions (3, 3) and (3, 1), so can be multiplied with a result having dimensions (3, 1).
It is useful to refer to an element of a matrix by specifying the row and column in which it resides. An element of matrix 'A' in row 2 and column 3 can be referred to as A(2,3). Often, subscripts are used, as in ...
[tex]A_{i,j}[/tex]
For matrix C = A·B, the element C(1,1) will be the sum ...
A(1,1)B(1,1) +A(1,2)B(2,1) +A(1,3)B(3,1)
Calculators, apps, spreadsheets, and web sites are available that will perform this arithmetic for you. It can be a bit tedious to do by hand.
Here the product is ...
[tex]A\cdot B=\left[\begin{array}{ccc}2&3&-1\\0&2&5\\2&4&0\end{array}\right] \cdot\left[\begin{array}{c}2&1&2\end{array}\right] =\left[\begin{array}{c}2(2)+3(1)+(-1)(2)&0(2)+2(1)+5(2)&2(2)+4(1)+0(2)\end{array}\right] \\\\=\left[\begin{array}{c}5&12&8\end{array}\right][/tex]
Joes bait shop brought in a gross profit in sales of $4,100.00 in the month of June. During the same month their operating expenses totaled $1990.00. Calculate the net income of the bait shop for the month of June
Answer:
2110
Step-by-step explanation:
4100-1990=2110
Hey I need helping with solving thank you
Answer:
the answer to this equation is c (10)
Which transformation maps the pre-image to the image?
dilation
reflection
rotation
translation
Answer:
Reflection
Step-by-step explanation:
Because reflecting yourself in a mirror means pre image to image
Answer:
Step-by-step explanation:
dilation
Y=square root of x compare to y= - square root of x how they differ and why
Answer:
Simply because x=y2 doesn't imply that y=
√
x
.
During a one-month promotional campaign, Fran's Flix gave either a free DVD rental or a 12-serving box of microwave popcorn to new members. It cost the store $1 for each free rental and $2 for each box of popcorn. In all,46 new members were signed up and the store's cost for the incentives was $86. How many of each incentive were given away?
Factorize the following: cos²B + 5cosB - 6
Answer:
(cosB-1)(cosB+6)
Step-by-step explanation:
use u substitution . u = cosB
u^2+5u-6
factor
(u-1)(u+6)
put cosB back in for u
(cosB-1)(cosB+6)
find the common ratio of the geometric sequence 4,3,9/4
Answer:
3/4
Step-by-step explanation:
To find the common ratio, take the second term and divide by the first term
3/4
Check with the third and second terms
9/4 ÷3
9/4 *1/3= 3/4
The common ratio is 3/4
Help me plz need the steps
In Figure 7 (open photo), GH is a diameter of the circle. What is
x² + y² ?
A)58
(B) 49
(C) 10
D) 9
(E) It cannot be determined from the information given.
Answer:
[tex]A)58[/tex]
Step-by-step explanation:
[tex][Kindly\ refer\ the\ attachment]\\We\ are\ given:\\GH\ is\ the\ diameter\ of\ the\ circle.\\ Also,\\ GM=3\ units\ and\ MH=7\ units\\From\ the\ figure,\\GH\ subtends\ an\ angle\ at\ two\ points\ specifically\ M\ and\ N\ on\ the\\ arc.\\Now,\\We\ know\ that,\\'The\ Angle\ subtended\ by\ the\ diameter\ anywhere\ over\ the\ arc\ of\ the\\ circle\ is\ always\ 90\ degrees'.\\Hence,\\\angle GMH\ = \angle GNH=90\\[/tex]
[tex]Also,\\Pythagoras\ Theorem\ states\ that: 'In\ a\ right\ triangle,\ the\ sum\ of\ squares\\ \ of\ the\ legs\ is\ equal\ to\ the\ square\ of\ the\ hypotenuse'\\In\ \triangle GMH,\\Since\ \angle GMH=90,\\GM^2+MH^2=GH^2[Through\ Pythagoras\ Theorem]\\Hence,\\Substituting\ GM=3,\ MH=7:\\3^2+7^2=GH^2\\GH^2=9+49=58[/tex]
[tex]Similarly,\\In\ \triangle GNH,\\Since\ \angle GNH=90,\\GN^2+NH^2=GH^2\\Hence,\\Substituting\ GN=x\ and\ NH=y:\\x^2+y^2=GH^2\\x^2+y^2=58[/tex]
Mariah swam her leg of the race in 24.98 seconds and Janet swam her leg of the relay race in 25.874 seconds. What was their combined time for their part of the relay?
Answer:
50.854 seconds
Step-by-step explanation:
24.98 + 25.874 = 50.854 seconds
Help
Plz!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
angle G
sin inverse (21/29) = 46.4
GH
c^2 - b^2 = a^2
29^2 - 21^2 = a^2
a = √(29^2 - 21^2)
GH = 20
therefore ans is B) <G = 46.4º, <I = 43.6º, GH = 20
using the unit circle what is the exact value of tanpi/6
Answer:
[tex] \frac{ \sqrt{3} }{3} [/tex]
Step-by-step explanation:
[tex]\frac{1}{3} \div \sqrt{3} [/tex]
(a) How many different three-letter initials can people have: , (b) How many different three-letter initials with none of the letters repeated can people have: , (c) How many different three-letter initials with letters repeated begin with an X: , (d) How many different three-letter initials begin with a F and end in a D: .
Answer:
Step-by-step explanation:
A) 26*26*26 =17576
B)26*25*24=15600
C)26*26=676
D) 26
Given the linear function f(x) 2/3x + 6 evaluate f(-6)
the answer is on the photo
Put the following equation of a line into slope-intercept form, simplifying all fractions 2x-2y=14
Answer: y = x - 7
Slope intercept form: y = mx + b
[tex]2x-2y=14\\\\-2y=-2x+14\\\\y=\frac{-2x+14}{-2} =\frac{-2(x-7)}{-2} =x-7[/tex]
The sum of 'n' terms of an arithmetic sequence is 4n^2+3n. What is the first term, the common difference, and the sequence?
Answer:
The sequence has first term 7 and common difference is 8.
So the sequence is f(n)=7 + 8(n-1)
Step-by-step explanation:
Let a be the first term.
Let a+d be the second term where d is the common difference.
Then a+2d is the third....
And a+(n-1)d is the nth term.
Adding these terms we get:
an+(n-1)(n)/2×d
For the first term of this sum I seen we had n amount of a's and for the second term I used the well known identity sum of the first n positive integers is n(n+1)/2.
Let's simplify:
an+(n-1)(n)/2×d
Distribute:
an+(n^2d/2)-(nd/2)
Find common denominator:
(2an/2)+(n^2d/2)-(nd/2)
Combine terms into one:
(2an+n^2d-nd)/2
Reorder terms:
(n^2d+2an-nd)/2
Regroup terms:
(n^2d+(2a-d)n)/2
We want the following sum though:
4n^2+3n
This means d/2=4 (so d=8) and (2a-d)/2=3.
So plug d=8 into second equation to solve for a.
(2a-8)/2=3
2a-8=6
2a=14
a=7
The sequence has first term 7 and common difference is 8.
So the sequence is f(n)=7 + 8(n-1).
Which of the following shows the extraneous solution to the logarithmic equation below?
2 log Subscript 5 Baseline (x + 1) = 2
Answer:
x=4
Step-by-step explanation:
log5(x+1)=1, (x+1)=5, x=4
Answer:
x= -6
Step-by-step explanation:
i got it wrong and the answer is -6
What is one thousand minus on hundred and ten
Answer:
The answer is 890 . ...... :D
Given the formula A = 5h (B + b); solve for B.
2
Answer:
A=5h(B+b)
A/5h=B+b
A/5h - b= B
I need help please. Thank you
Answer:
0.0009765625
Step-by-step explanation:
This is what i got its probally incorrect
What is the dimension of the vector space consisting of five-by-one column matrices where the rows sum to zero and the first row is equal to the second row?
a. 5
b. 4
c. 3
d. 2
Answer:
Option c.
Step-by-step explanation:
If we have a vector of N components (or variables), and we have K linear independent restrictions for these N components (such that K < N, we can't have more restrictions than components.)
The dimension of the vector will be given by N - K.
Here we know that we have a vector of 5 components, that can be written as:
[tex]v = \left[\begin{array}{ccc}v_1\\v_2\\v_3\\v_4\\v_5\end{array}\right][/tex]
And we have two restrictions, so we can expect that the dimension of the vector is:
5 - 2 = 3
But let's see it, the restrictions are:
"the first row is equal to the second row"
Then we can rewrite our vector as:
[tex]v = \left[\begin{array}{ccc}v_1\\v_1\\v_3\\v_4\\v_5\end{array}\right][/tex]
Notice that now we have only 4 variables, v₁, v₃, v₄, and v₅
We also know that the sum of the rows is equal to zero, thus:
v₁ + v₂ + v₃ + v₄ + v₅ = 0
we know that v₂ = v₁, so we can replace that to get:
2*v₁ + v₃ + v₄ + v₅ = 0
Now we can isolate one of the variables, to write it in term of the others, for example, let's isolate v₅:
v₅ = -2*v₁ - v₃ - v₄
Now if we replace that in our vector, we have:
[tex]v = \left[\begin{array}{ccc}v_1\\v_1\\v_3\\v_4\\-2*v_1 - v_3 - v_4\end{array}\right][/tex]
Notice that our vector depends on only 3 variables, v₁, v₃, and v₄, so we can define our vector in a 3-dimensional space.
Then the correct option is c, the dimension of the vector space is 3.
Plz answer asap question in picture
Answer:
-1 <x < 7
(-1,7)
Step-by-step explanation:
open circle on the left means the number is greater than
-1 <x
Open circle on the right means the number is less than
x < 7
Since both statements are true. we combine them
-1 <x < 7
open circles means parentheses, closed circles mean brackets
PLEASE HELP THIS IS DUE ASAP (answer in decimal!!!!)
Suppose the volume of the cone is 324pi Find dy/dx when x=6 and y=27
Answer:
[tex]\displaystyle \frac{dy}{dx} \bigg| \limits_{x = 6} = -9[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityCalculus
Differentiation
DerivativesDerivative NotationBasic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Derivative Rule [Quotient Rule]: [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle V = \frac{1}{3} \pi x^2y[/tex]
[tex]\displaystyle V = 324 \pi[/tex]
[tex]\displaystyle x = 6[/tex]
[tex]\displaystyle y = 27[/tex]
Step 2: Differentiate
Substitute in volume [Volume Formula]: [tex]\displaystyle 324 \pi = \frac{1}{3} \pi x^2y[/tex][Equality Properties] Rewrite: [tex]\displaystyle y = \frac{972}{x^2}[/tex]Quotient Rule: [tex]\displaystyle \frac{dy}{dx} = \frac{(972)'x^2 - (x^2)'972}{(x^2)^2}[/tex]Basic Power Rule: [tex]\displaystyle \frac{dy}{dx} = \frac{0x^2 - (2x)972}{(x^2)^2}[/tex]Simplify: [tex]\displaystyle \frac{dy}{dx} = \frac{-1944x}{x^4}[/tex]Simplify: [tex]\displaystyle \frac{dy}{dx} = \frac{-1944}{x^3}[/tex]Step 3: Evaluate
Substitute in variables [Derivative]: [tex]\displaystyle \frac{dy}{dx} \bigg| \limits_{x = 6} = \frac{-1944}{6^3}[/tex]Simplify: [tex]\displaystyle \frac{dy}{dx} \bigg| \limits_{x = 6} = -9[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
A group of 6 children and 6 adults are going to the zoo. Child tickets cost $10, and adult tickets cost $14. How much will the zoo tickets cost in all?
Answer:
i believe it'll cost 200 dollars
help please i’ll give brainliest
Answer:
3rd option
..................[tex]A) \frac{4-2}{2-1} =2[/tex]
[tex]B)\frac{1-0.5}{4-2} =0.25[/tex]
[tex]C)>2[/tex]
[tex]D) 1[/tex]
~OAmalOHopeO
Answer:
The third one is your answer
if 2x + 1=7 what is the value of x
Answer:
x=3
Step-by-step explanation:
2x+1=7
2x=7-1
2x=6
x=6/2
x=3
Answer:
Solution,
2x + 1=7
or 2x = 7 - 1
or, 2x= 6
or, x = 6
2
or, x = 3
.:. x = 3
A speed training service wants to explore the effectiveness of some of the classes offered to their clients. They randomly select 300 high school athletes and record their 50-meter dash time. The 300 high school athletes are then randomly assigned to three groups with 100 in each. One hundred athletes will take a circuit training class, 100 athletes will take an interval training class, and 100 athletes will take a plyometrics training class. At the end of 10 weeks of taking these classes, their 50-meter dash time will be recorded a second time. Their times will be analyzed to see which class showed the greatest overall improvement in times.
Select all the sentences that correctly identify the components of the experiment.
The experimental units are subjects.
The subjects are the 50 athletes.
There is one treatment, the 50-meter dash.
There are three treatments.
One treatment is a circuit training class.
The factor is the type of class.
There are 10 levels of the factor.
Answer:
A,D,E,F
1,4.5,6
The experimental units are subjects.
There are three treatments.
One treatment is a circuit training class.
The factor is the type of class.
ED2021
Tại sao số mắt xích không được là bội số của số răng đĩa xích
Answer:
Nên sử dụng số răng lẻ cho đĩa xích dẫn động kết hợp với số lượng mắt xích chẵn để mài mòn đồng đều trên răng và trục lăn. Trong trường hợp này, một răng cụ thể của bánh xích không tiếp xúc với một mắt xích cụ thể của xích trong mỗi lần quay.
Step-by-step explanation:
Translated
It is preferable to use an odd number of teeth for the driving sprocket in combination with an even number of chain links for uniform wear and tear on the teeth and rollers. In this case, a particular tooth of the sprocket wheel does not come in contact with a particular link of the chain for every rotation.
