định khoản nghiệp vụ sau : tạm ứng cho nhân viên A đi công tác bằng tiền mặt 50.000

Answers

Answer 1

Answer:

report on a fight you have witnessed


Related Questions

Elliptic curve cryptography is considered as the latest and probably the one with a future. Having seen RSA in earlier modules, in which ways do YOU think elliptic cryptography is more advanced than RSA. You may read other material or get this information from the internet to answer this question. But make sure to provide necessary references when you do cite others.

Answers

Answer:

The answer is below.

Explanation:

Some of the ways, how I think elliptic cryptography is more advanced than RSA are the following:

1. ECC - Elliptic Curve Cryptography uses smaller keys for the same level of security, particularly at greater levels of security.

2. ECC can work well and at a faster rate on a small-capacity device compared to RSA

3. It uses offer speedier SSL handshakes that enhance security

4. It offers fast signatures

5. It allows signatures to be computed in two stages, which enables lower latency than inverse throughput.

6. Relatively quick encryption and decryption

Car B is traveling a distance dd ahead of car A. Both cars are traveling at 60 ft/s when the driver of B suddenly applies the brakes, causing his car to decelerate at ft/s^2. It takes the driver of car A 0.75 s to react (this is the normal reaction time for drivers). When he applies his brakes, he decelerates at 18 ft/s^2.

Required:
Determine the minimum distance d between the cars so as to avoid a collision.

Answers

Answer:

Explanation:

Using the kinematics equation [tex]v = v_o + a_ct[/tex] to determine the velocity of car B.

where;

[tex]v_o =[/tex] initial velocity

[tex]a_c[/tex] = constant deceleration

Assuming the constant deceleration is = -12 ft/s^2

Also, the kinematic equation that relates to the distance with the time is:

[tex]S = d + v_ot + \dfrac{1}{2}at^2[/tex]

Then:

[tex]v_B = 60-12t[/tex]

The distance traveled by car B in the given time (t) is expressed as:

[tex]S_B = d + 60 t - \dfrac{1}{2}(12t^2)[/tex]

For car A, the needed time (t) to come to rest is:

[tex]v_A = 60 - 18(t-0.75)[/tex]

Also, the distance traveled by car A in the given time (t) is expressed as:

[tex]S_A = 60 * 0.75 +60(t-0.75) -\dfrac{1}{2}*18*(t-0.750)^2[/tex]

Relating both velocities:

[tex]v_B = v_A[/tex]

[tex]60-12t = 60 - 18(t-0.75)[/tex]

[tex]60-12t =73.5 - 18t[/tex]

[tex]60- 73.5 = - 18t+ 12t[/tex]

[tex]-13.5 =-6t[/tex]

t = 2.25 s

At t = 2.25s, the required minimum distance can be estimated by equating both distances traveled by both cars

i.e.

[tex]S_B = S_A[/tex]

[tex]d + 60 t - \dfrac{1}{2}(12t^2) = 60 * 0.75 +60(t-0.75) -\dfrac{1}{2}*18*(t-0.750)^2[/tex]

[tex]d + 60 (2.25) - \dfrac{1}{2}(12*(2.25)^2) = 60 * 0.75 +60((2.25)-0.75) -\dfrac{1}{2}*18*((2.25)-0.750)^2[/tex]

d + 104.625 = 114.75

d = 114.75 - 104.625

d = 10.125 ft

What is working fluid and mention five example of working fluid.​

Answers

Answer:

For fluid power, a working fluid is a gas or liquid that primarily transfers force, motion, or mechanical energy. ... Examples without phase change include air or hydrogen in hot air engines such as the Stirling engine, air or gases in gas-cycle heat pumps, etc.

Explanation:

Answer:

A working fluid is a gas or liquid that primarily transfers force, motion or mechanical energy

Examples:Air, pentane, chlorofluorocarbons, butane, propane and ammonia

Explain the LWD process why is it important in drilling operations?

Answers

Answer:

Logging while drilling (LWD) is a technique of conveying well logging tools into the well borehole downhole as part of the bottom hole assembly (BHA). ... In these situations, the LWD measurement ensures that some measurement of the subsurface is captured in the event that wireline operations are not possible.

Explanation:

pls mark brainliest

Race cars at the Indianapolis Speedway average speeds of 185 mi/h. After determining the altitude of Indianapolis, find the Mach number of these cars and estimate whether compressibility might affect their aerodynamics.

Answers

Answer:

- the Mach number is 0.24.

- Compressibility becomes effective when Mach number is greater than 0.3, the Mach number of the race cars is less than 0.3, hence, compressibility will not affect their aerodynamics.

Explanation:

Given the data in the question;

Average speed V = 185 miles per hour = ( 185 /2.237 ) m/s = 82.7 m/s

From Almanac, we can find that Indianapolis is at 220 m altitude.

So from table, at that altitude, the standard speed of sound will be 339.4 m/s .

Mach number of the race car will be;

Mach Number = Velocity / sound speed

we substitute

Mach Number = ( 82.7 m/s ) / ( 339.4 m/s )

Mach Number = 0.24

Therefore the Mach number is 0.24.

We know that, compressibility becomes effective when the Mach number is greater than 0.3.

Since the Mach number of the race cars is less than 0.3, compressibility will not affect their aerodynamics.

 

A pinion and gear pair is used to transmit a power of 5000 W. The teeth numbers of pinion
and gear are 20 and 50. The module is 5 mm, the pressure angle is 20o
and the face width is 45 mm. The
rotational speed of pinion is 300 rev/min. Both the pinion and the gear material are Nitralloy 135 Grade2 with a hardness of 277 Brinell. The quality standard number Qv is 5 and installation is open gearing
quality. Find the AGMA bending and contact stresses and the corresponding factors of safety for a
pinion life of 109
cycles and a reliability of 0.98

Answers

Answer:

mark me as a brainleast

Explanation:

209781

Which of the following is not a part sympathetic activation during the fight or flight response?

Answers

The parasympathetic division functions with actions that do not require immediate reaction. The sympathetic division initiates the fight-or-flight response and the parasympathetic initiates the rest-and-digest or feed-and-breed responses.

Answer:

Digestion functions become more active

Explanation:

I just took the text!

Why water parameters of Buriganga river vary between wet and dry seasons?
Explain.

Answers

I honestly don’t know because I honestly don’t know what I mean

How many numbers multiple of 3 are in the range [2,2000]?

Answers

i don’t even know lol i’m just tryna bring my points up sorry.

Biết op-amp có Vsat =  12V, R1=R2=R3=R4=R, dạng sóng điện áp Vi(t) được cho như
hình 2.16b
a. Tính V0 theo Vi, độ lợi áp AV
b. Vẽ lại dạng sóng điện áp V0(t) khi Vm= 3
8 V
c. Vẽ lại dạng sóng điện áp V0(t) khi Vm = 5V

Answers

Answer:

Hello bro

Explanation:

I think i can help you something but can you translate it on english plzz

The value of universal gas constant is same for all gases?
a) yes
b)No

Answers

Answer:

The answer of these questions is

Explanation:

b) NO

Design a ductile iron pumping main carrying a discharge of 0.35 m3/s over a distance of 4 km. The elevation of the pumping station is 140 m and that of the exit point is 150 m. The required terminal head is 10 m. Estimate the pipe diameter and pumping head using the explicit design procedure g

Answers

Answer:

[tex]D=0.41m[/tex]

Explanation:

From the question we are told that:

Discharge rate [tex]V_r=0.35 m3/s[/tex]

Distance [tex]d=4km[/tex]

Elevation of the pumping station [tex]h_p= 140 m[/tex]

Elevation of the Exit point [tex]h_e= 150 m[/tex]

Generally the Steady Flow Energy Equation SFEE is mathematically given by

[tex]h_p=h_e+h[/tex]

With

[tex]P_1-P_2[/tex]

And

[tex]V_1=V-2[/tex]

Therefore

[tex]h=140-150[/tex]

[tex]h=10[/tex]

Generally h is give as

[tex]h=\frac{0.5LV^2}{2gD}[/tex]

[tex]h=\frac{8Q^2fL}{\pi^2 gD^5}[/tex]

Therefore

[tex]10=\frac{8Q^2fL}{\pi^2 gD^5}[/tex]

[tex]D=^5\frac{8*(0.35)^2*0.003*4000}{3.142^2*9.81*10}[/tex]

[tex]D=0.41m[/tex]

Given : x² + 200x = 166400 The current park is a square, and the addition will increase the width by 200 meters to give the expanded park a total area of 166,400 square meters To Find : the side length of the current square park. Solution: x² + 200x = 166400 => x(x + 200) = 166400 166400 = 320 * 520 => (320)(320 + 200) = 166400 => x = 320 side length of the current square park. = 320 m Learn More: Which expression is a possible leading term for the polynomial ... brainly.In/question/13233517

Answers

Answer:

320 m

Explanation:

To find the side length of the current park, x, we solve the quadratic equation for the area of the park

x² + 200x = 166400

x² + 200x - 166400 = 0

We multiply -166400 by x² to get -166400x². We now find the factors of 166400x² that will add up to 200x. These factors are -320x and 520x

So, we re-write the expression as

x² + 200x - 166400 = 0

x² + 520x - 320x - 166400 = 0

We write out the factors of the expression,

x² + 520x - 320x - 320 × 520 = 0

Factorizing the expression, we have

x(x + 520) - 320(x + 520) = 0

(x + 520)(x - 320) = 0

x + 520 = 0 or x - 320 = 0

x = -520 or x = 320

Since x is not negative, we take the positive answer.

So, x = 320 m

What statement about the print() function is true?

print() has a variable number of parameters.

print() can have only one parameter.

print() can be used to obtain values from the keyboard.

print() does not automatically add a line break to the display.

Answers

Explanation:

print() has a variable number of parameters. this is the answer.

hope this helps you

have a nice day

What are three types of land reform ​

Answers

Answer:

Abolition of intermediaries (rent collectors under the pre-Independence land revenue system); Tenancy regulation (to improve the contractual terms including the security of tenure); A ceiling on landholdings (to redistributing surplus land to the landless);

Types of Land Reform

Abolition of Intermediaries

The first step taken by the Indian government under land reforms post-independence was passing the Zamindari Abolition Act. The primary reason of a backward agrarian economy was the presence of intermediate entities like, jagirdars and zamindar who primarily focussed on collecting sky-rocketing rents catering to their personal benefits, without paying attention to the disposition of farms and farmers. Abolition of such intermediaries not only improved conditions of farmers by establishing their direct connection with the government but also improved agricultural production.

Regulation of Rents

This was in direct response to the unimaginably high rents which were charged by intermediaries during British rule, which resulted in a never-ending cycle of poverty and misery for tenants. Indian government implemented these regulations to protect farmers and labourers from exploitation by placing a maximum limit on the rent that could be charged for land.

Tenure Security

Legislations were passed in all states of the country to grant tenants with permanent ownership of lands and protection from unlawful evictions on expiry of the lease. This law protects tenants from having to vacate a property immediately after their tenure is over unless ordered by law. Even in that case, ownership can be regained by tenants with the excuse of personal cultivation.

Unfiltered full wave rectifier with a 120 V 60 Hz input produces an output with a peak of 15V. When a capacitor-input filter and a 1k ohm load are connected the DC output voltage is 14V. What is... The value of the capacitor? The value of the peak to peak ripple voltage?

Answers

Answer:

[tex]V_{pp}=2V[/tex]

Explanation:

Source Voltage [tex]V= 120V[/tex]

Frequency [tex]f=60Hz[/tex]

Peak output voltage [tex]Vp=15V[/tex]

Peak Output Voltage with filter [tex]V_p'=14V[/tex]

Generally the equation for Peak to peak voltage is mathematically given by

[tex]V_p'=V_p-\frac{V_{pp}}{2}[/tex]

Therefore

[tex]V_{pp}=2(V_p-v_p')[/tex]

[tex]V_{pp}=2(15-14)[/tex]

[tex]V_{pp}=2V[/tex]

Assignment Using Perman's equation, estimate the potential evapotranspiration for the month of August in locality with the following data
latitude 20 degrees north
Elevation 200m
• Mean monthly temperature 20 degreeso
• Mean relative humidity: 75%
• Mean sunshine hour= 9hrs
Wind at 2 m height equal 85 km per day
nature of surface cover =green grass​

Answers

Answer:

what do you need help with

Explanation:

Future solution for air pollution in new zealand

Answers

Answer:

New Zealand may use some of these solutions to prevent air pollution

Explanation:

Using public transports.

Recycle and Reuse

No to plastic bags

Reduction of forest fires and smoking

Use of fans instead of Air Conditioner

Use filters for chimneys

Avoid usage of crackers

Select the correct statement(s) regarding IEEE 802.16 WiMAX BWA. a. WiMAX BWA describes both 4G Mobile WiMAX and fixed WiMax b. DSSS and CDMA are fundamental technologies used with WiMAX BWA c. OFDM is implemented to increase spectral efficiency and to improve noise performance d. all of the statements are correct

Answers

Answer:

d. all of the statements are correct.

Explanation:

WiMAX Broadband Wireless Access has the capacity to provide service up to 50 km for fixed stations. It has capacity of up to 15 km for mobile stations. WiMAX BWA describes both of 4G mobile WiMAX and fixed stations WiMAX. OFMD is used to increase spectral efficiency of WiMAX and to improve noise performance.

Explain ROLAP, and list the reasons you would recommend its use in the relational database environment.

Answers

Answer:

ROLAP  is a branch of OLAP that is used to contain Relational database ( RDB ). which is a very fast database ( quick process of queries )

Very fast to access and also fast in processing queries provides multidimensional view of data / supports multidimensional database schema with RDBMssupports large databases

Explanation:

ROLAP ( Relational On-line Analytical processing ) is a branch of OLAP that is used to contain Relational database ( RDB ).

Advantages of ROLAP ( reasons for the use of ROLAP )

Very fast to access ( fast in processing queries )provides multidimensional view of data / supports multidimensional database schema with RDBMssupports large databases

Hot air is to be cooled as it is forced to flow through the tubes exposed to atmospheric air. Fins are to be added in order to enhance heat transfer. Would you recommend attaching the fins inside or outside the tubes? Why? When would you recommend auaching fins both inside and outside the tubes?

Answers

Answer:

Fins should be attached outside the tube Fins can be attached on both sides when convection coefficient of air inside the tube is equal to the convection coefficient of atmospheric air outside the tube

Explanation:

The main function of the fins that are to be added is to ensure the speedy transfer of heat from the Hot air.

The fins should be attached outside the tube because the convection coefficient of air is higher inside the tube than the convection coefficient of the outside air ( atmospheric air ),  BUT

When convection coefficient of air inside the tube is equal to the atmospheric air outside the tube, it is recommended that the fins can be added on both sides of the tube ( i.e. in and outside the tube )

An ideal gas within a piston-cylinder assembly undergoes a Carnot refrigeration cycle. The isothermal compression occurs at 325 K from 2 bar to 4 bar. The isothermal expansion occurs at 250 K. Determine:

a. the coefficient of performance
b. the heat transfer to the gas during the isothermal expansion, in kj per kmol of gas
c. the magintude of the net work input, in kj per kmol of gas.

Answers

Answer:

a) [tex]\mu=3.3[/tex]

b)  [tex]Q=1440.7KJ/Kmol[/tex]

c)  [tex]W=1872.9KJ/Kmol[/tex]

Explanation:

From the question we are told that:

Initial Temperature [tex]T_1=325k[/tex]

initial Pressure [tex]P_1=2 bar[/tex]

Final Pressure [tex]P_2=4 bar[/tex]

iso-thermal expansion [tex]T_2=250k[/tex]

a)

Generally the equation for Coefficient of performance is mathematically given by

[tex]\mu=\frac{T_2}{T_1-T_2}[/tex]

[tex]\mu=\frac{250}{325-250}[/tex]

[tex]\mu=3.3[/tex]

b)

Generally the equation for Heat Expansion is mathematically given by

[tex]Q=RT_2 In(\frac{P_2}{P_1})[/tex]

Where

R=Gas constant

[tex]R=8.314462618[/tex]

Therefore

[tex]Q=8.314462618*250 In(\frac{4}{2})[/tex]

[tex]Q=1440.7KJ/Kmol[/tex]

c)

Generally the equation for work input is mathematically given by

[tex]W=RT_1 In(\frac{P_2}{P_1})[/tex]

[tex]W=8.314462618*250 In(\frac{4}{2})[/tex]

[tex]W=1872.9KJ/Kmol[/tex]

The coefficient of performance is 3.33, the heat transfer in the isothermal expansion is 1440.71kJ/K.mol and the work input is calculated as 1872.92kJ/K.mol

Given Data:

T1 = 325KP1 = 2 barP2 = 4 barT2 = 250K

Isothermal expansion occurs at 250K.

a) The coefficient of performance

This is calculated as

COP =[tex]\frac{T_2}{T_1-T_2}=\frac{250}{325-250} =3.33[/tex]

b) Heat Transfer in isothermal expansion

[tex]Q = RT_2In(\frac{p_2}{p_1})[/tex]

Therefore; In isothermal process du = 0

R = 8.314 AkJ/K.mol

Q = 8.314 * 250 In(4/2)

Q = 1440.71kJ/K.mol

c) Work Input

W[tex]_i_n[/tex]=[tex]RT_1In(\frac{p_2}{p_1})\\W_i_n=8.314*325In(4/2)\\W_i_n=1872.92kJ/K.mol[/tex]

The work input is 1872.92kJ/K.mol

Learn more on Carnot cycle here:

https://brainly.com/question/14983940

https://brainly.com/question/13170743

Block A hangs by a cord from spring balance D and is submerged in a liquid C contained in beaker B. The mass of the beaker is 1.20 kg; the mass of the liquid is 1.85 kg. Balance D reads 3.10 kg and balance E reads 7.50 kg. The volume of block A is 4.15 × 10−3 m3.
a) What is the density of the liquid?
b) What will the balance D read if block A is pulled up out of the liquid?
c) What will the balance E read if block A is pulled up out of the liquid?

Answers

Answer:

a)  [tex]m_e= 3.05 Kg[/tex]

b)  [tex]\rho=1072.3kg/m^3[/tex]

c)  [tex]m_e= 3.05 Kg[/tex]

Explanation:

From the question we are told that:

Beaker Mass [tex]m_b=1.20[/tex]

Liquid Mass [tex]m_l=1.85[/tex]

Balance D:

Mass [tex]m_d=3.10[/tex]

Balance E:

Mass [tex]m_e=7.50[/tex]

Volume [tex]v=4.15*10^{-3}m^3[/tex]

a)

Generally the equation for Liquid's density is mathematically given by

[tex]m_e=m_b+m_l+(\rho*v)[/tex]

[tex]\rho=\frac{7.50-(1.2+1.85)}{4.15*10^{-3}}[/tex]

[tex]\rho=1072.3kg/m^3[/tex]

b)

Generally the equation for D's Reading at A pulled is mathematically given by

m_d = mass of block - mass of liquid displaced

[tex]m_d=m- (\rho *v )[/tex]

[tex]m=3.10+ (1072.30 *4.15*10^{-3}m^3 )[/tex]

[tex]m=18.10kg[/tex]

c)

Generally the equation for E's Reading at A pulled is mathematically given by

[tex]m_e=m_b+m_l[/tex]

[tex]m_e = 1.20 + 1.85[/tex]

[tex]m_e= 3.05 Kg[/tex]

Compute the minimum length of vertical curve that will provide 220 m stopping sight distance for a design speed of 110 km/h at the intersection of a -3.50% grade and a +2.70% grade.

Answers

i have made notes and saved it as a pdf u can take it to answer question and make ur concept good

The minimum length of vertical curve that will provide 220 m stopping sight distance is; 458.8 m

We are given;

Stopping sight distance; S = 220 m

Design Speed; V = 110 km/h

Intersection grade 1; G1 = +2.7

Intersection Grade 2; G2 = -3.5

From the AASHTO Table attached, we can trace the value of the radius of vertical curvature for the given stopping sight distance and design speed.

From the table, at S = 220 m and V = 110 km/h, we can see that;

Radius of vertical curvature; K = 74

Now, the difference in grade given is;

A = G1 - G2

A = 2.7 - (-3.5)

A = 2.7 + 3.5

A = 6.2

Formula for the minimum length of vertical curve is;

L = KA

Thus;

L = 74 × 6.2

L = 458.8 m

Read more about stopping sight distance at; https://brainly.com/question/2087168

Transients (surges) on a line can cause spikes or surges of energy that can damage delicate electronic components. A SPD device contains one or more ________________ than bypass and absorb the energy of the transient.

Answers

Answer:

I think ( MOV Metal oxide varistors )

Transients (surges) on a line can cause spikes or surges of energy that can damage delicate electronic components. A SPD device contains one or more MOV Metal oxide varistors than bypass and absorb the energy of the transient.

A balanced three-phase inductive load is supplied in steady state by a balanced three-phase voltage source with a phase voltage of 120 V rms. The load draws a total of 10 kW at a power factor of 0.85 (lagging). Calculate the rms value of the phase currents and the magnitude of the per-phase load impedance. Draw a phasor diagram showing all tlme voltages and currents.

Answers

Answer:

Following are the solution to the given question:

Explanation:

Line voltage:

[tex]V_L=\sqrt{3}V_{ph}=\sqrt{3}(120) \ v[/tex]

Power supplied to the load:

[tex]P_{L}=\sqrt{3}V_{L}I_{L} \cos \phi[/tex]

[tex]10\times 10^3=\sqrt{3}(120 \sqrt{3}) I_{L}\ (0.85)\\\\I_{L}= 32.68\ A[/tex]

Check wye-connection, for the phase current:

[tex]I_{ph}=I_L= 32.68\ A[/tex]

Therefore,

Phasor currents: [tex]32.68 \angle 0^{\circ} \ A \ ,\ 32.68 \angle 120^{\circ} \ A\ ,\ and\ 32.68 -\angle 120^{\circ} \ A[/tex]  

Magnitude of the per-phase load impedance:

[tex]Z_{ph}=\frac{V_{ph}}{I_{ph}}=\frac{120}{32.68}=3.672 \ \Omega[/tex]

Phase angle:

[tex]\phi = \cos^{-1} \ (0.85) =31.79^{\circ}[/tex]

Please find the phasor diagram in the attached file.

A rod that was originally 100-cm-long experiences a strain of 82%. What is the new length of the rod?


122 cm


182 cm


82 cm


22 cm


108.2 cm

Answers

Answer: (b)

Explanation:

Given

Original length of the rod is [tex]L=100\ cm[/tex]

Strain experienced is [tex]\epsilon=82\%=0.82[/tex]

Strain is the ratio of the change in length to the original length

[tex]\Rightarrow \epsilon =\dfrac{\Delta L}{L}\\\\\Rightarrow 0.82=\dfrac{\Delta L}{100}\\\\\Rightarrow \Delta L=82\ cm[/tex]

Therefore, new length is given by (Considering the load is tensile in nature)

[tex]\Rightarrow L'=\Delta L+L\\\Rightarrow L'=82+100=182\ cm[/tex]

Thus, option (b) is correct.

4) A steel tape is placed around the earth at the equator when the temperature is 0 C. What will the clearance between the tape and the ground (assumed to be uniform) be if the temperature of the tape rises to 30 C. Neglect the expansion of the earth (the radius of the earth is 6.37 X 106 m)

Answers

Answer:

2102.1 m

Explanation:

Temperature at the equator = 0⁰

Radius of the earth = 6.37x10⁶

Required:

We how to find out what the clearance between tape and ground would be if temperature increases to 30 degrees.

Final temperature = ∆T = 303-273 = 30

S = 11x10^-6

The clearance R = Ro*S*∆T

=6.37x10⁶x 11x10^-6x30

= 2102.1m

Or 2.102 kilometers

Thank you

a video inspection snake is use

Answers

Answer:

very good thx

Explanation:

A binary system of species 1 and 2 consists of vapor and liquid phases in equilibrium
at temperature T. The overall mole fraction of species 1 in the system is z1 = 0.65. At
temperature T, lnγ1 = 0.67 x2
2; lnγ2 = 0.67 x1
2; P1
sat = 32.27 kPa; and P2
sat = 73.14 kPa.
Assuming the validity of Eq. (13.19),
Final PDF to printer
13.10. Problems 511
smi96529_ch13_450-523.indd 511 01/06/17 03:27 PM
(a) Over what range of pressures can this system exist as two phases at the given T and z1?
(b) For a liquid-phase mole fraction x1 = 0.75, what is the pressure P and what molar
fraction of the system is vapor?
(c) Show whether or not the system exhibits an azeotrope

Answers

The answer in photo
Please don't forget put heart ♥️
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