Answer:
23. Congruent
24. Not congruent
Step-by-step explanation:
23. KJ and HL:
Since the side lengths are both 4 in, these segments are congruent.
24. EH and FG:
Since the side lengths are different numbers (0.45 cm and 0.5 cm), these segments are not congruent.
In the similarity
transformation of AACB
to AEFD, AACB was dilated by
a scale factor of [?], reflected
across the [ ], and moved
through the translation [ ].
HELP HELP HELO NOW NOW PLEASE ILL GIVE BRAINLEISTETWBEBEJHEUEJ
Therefore, In the similarity transformation of ΔACB to ΔEFD, ΔACB was dilated by a scale factor of 2, reflected across the y-axis, and moved through the translation 2 units
What is graph transformation?
The technique of altering an existing graph or graphed equation to create a different version of the following graph is known as graph transformation. In particular, the change of algebraic equations, it is a typical kind of algebraic problem.
Graphs can be extended, rotated, inverted, or any combination of these transformations; they can also be translated or moved along the xyxy plane. The formulas "move the function f(x)f(x) by cc units in some direction," "stretch the function f(x)f(x) by cc units," and "rotate the function f(x)f(x) by xx units about the xx-, yy-, or zz-axis" are frequently used in mathematical issues. In every instance, the transformation has specific, calculable effects on the underlying function.
Since the triangle ABC and DEF is similar
So we can write,
DE/BC=EF/AB=FD/CA
scale factor =Length of CA/length of DF
=6/3
=2:1
Reflected at y axis i.e x=0
and raised by 2 units.
Therefore, In the similarity transformation of ΔACB to ΔEFD, ΔACB was dilated by a scale factor of 2, reflected across the y-axis, and moved through the translation 2 units
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The sum of two expressions is 5m^2-3n^2. if one of the expressions is 3m^2+4mn-n^2,what is the other?
evaluate the impact of risky behaviour on your personal expectations in relation to your career help with maths too
Step-by-step explanation:
In triangle ADE:
sum of all angles is 180.
3x-10+58+42=180
3x+90=180
3x=180-90
3x=90
x=90/3
x=30
As line DA and CB are parallel:
angle D=angle C
angle y=58
In angle BCE, sum of angles is 180.
z+58+42=180
z+100=180
z=180-100
z=80
12- (17 + 1) = (12 - 17) + 1
O A. True
B. False
Answer:
False.
Step-by-step explanation:
.
17+1= 18
12= -6
12-17= -5 + 1 =-4.
Answer:
False
Step-by-step explanation:
12- (17 + 1) = (12 - 17) + 1
PEMDAS says parentheses first
12- (18) = (-5) + 1
Then add and subtract
-6 = -4
They are not equal
Interval notation of x<2
interval notation of x<2
x=1
Solve 1/3(2x - y) = z for x
PLEASE HELP SHOW WORK!!!!
Answer:
[tex] \frac{1}{3} (2x - y) = z \\ \frac{2}{3} x - \frac{y}{3} = z \\ \frac{2}{3} x = z + \frac{y}{3} \\ \frac{2}{3} x = \frac{3z + y}{3} \\ x = \frac{3z + y}{3} \div \frac{2}{3} \\ x = \frac{3z + y}{3} \times \frac{3}{2} = \frac{3(3z + y)}{6} \\ \\ x = \frac{3z + y}{2} \\ \\ x = \frac{3z}{2} + \frac{y}{2} [/tex]
I hope I helped you^_^
Olivia orders 24 cupcakes and a layer cake. The layer cake costs $16, and the total cost of the order is $52. What is the cost of each cupcake?
Answer:
The total cost was $52. Subtracting out the cost of the layer cake ($16) leaves us with $36 to pay for the 24 cupcakes. This means that each cupcake must have cost $1.50 ( = $36 / 24 cupcakes ).
Step-by-step explanation:
Answer:
Below
Step-by-step explanation:
First let us create an equation for this problem
(24 cupcakes)( $ of each cupcake) + ( $16 layer cake ) = $52
Let's say that C will represent the $ of each cupcake to make it easier
Solving it....
24C + 16 = 52
24C = 36
Divide both sides by 24
C = 1.5
Therefore, each cupcake cost $1.5
We can check to see if this works....
24(1.5) + 16 = total cost
36 + 16 = 52, so this is correct
Hope that helped! Best of luck <3
c=2, f(x)= {3-x, x<2
2, x=2
x/2, x>2
Answer:
ball$
Step-by-step explanation:
<3
Complete the set of ordered pairs for the relation.
{(x, y): y = 2 |x + 1| and x {-2, -1, 0, 1, 2}}.
(-2, __)
-2
-3
2
Answer:
Step-by-step explanation:
[tex]U=\{(x,y)\ \zeta\ y=|x+1| \ and\ x \in \{-2,-1,0,1,2\}\ \}\\\\\begin{array}{|c|c|}x&y\\---&---\\-2&2\\-1&0\\0&2\\1 & 4\\2&6\\---&---\\\end{array}\\\\U=\{(-2,2),(-1,0),(0,2),(1,4),(2,6)\}\\[/tex]
Answer:
2 / (-2,2)
Step-by-step explanation:
l find it difficult to solve this problem. Please help.
Answer:
27 square are there in the given figure
Anyone who is interested in construction, please help! Pweeeeseeee(;´༎ຶٹ༎ຶ`)
Answer:
I have ans in the picture form.
Step-by-step explanation:
Take it
Simplify the expression to a polynomial in standard form:
(3x2 - 4x – 5)(-2x2 + 2x + 2)
Answer:
- 6[tex]x^{4}[/tex] + 14x³ + 8x² - 18x - 10
Step-by-step explanation:
Given
(3x² - 4x - 5)(- 2x² + 2x + 2)
Each term in the second factor is multiplied by each term in the first factor, that is
3x²(- 2x² + 2x + 2) - 4x(- 2x² + 2x + 2) - 5(- 2x² + 2x + 2) ← distribute parenthesis
= - 6[tex]x^{4}[/tex] + 6x³ + 6x² + 8x³ - 8x² - 8x + 10x² - 10x - 10 ← collect like terms
= - 6[tex]x^{4}[/tex] + 14x³ + 8x² - 18x - 10
Charlotte read a 608-page book in 16hours last month. How many pages per hour was that
Answer:
33
Step-by-step explanation:
608pages/16h = 33pages/h
A total of 388 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student tickets sold was three times the number of adult tickets sold. How many adult tickets were sold?
Answer:
97
Step-by-step explanation:
388 (number of tickets) / 4 (number of groups (adults, and the 3 times as many kids))
If the number of student tickets sold was three times the number of adult tickets sold, 97 adult tickets were sold.
Let's assume the number of adult tickets sold is 'x.'
According to the information given, the number of student tickets sold was three times the number of adult tickets sold. So, the number of student tickets sold is 3x.
The total number of tickets sold is the sum of the adult and student tickets, which is 388:
x + 3x = 388
Now, combine like terms:
4x = 388
To find the value of 'x,' divide both sides of the equation by 4:
x = 388 / 4
x = 97
To verify the result, let's find the number of student tickets:
Number of student tickets = 3 * 97 = 291
Now, let's add the adult and student tickets:
97 (adult) + 291 (student) = 388
The result checks out, and we have 97 adult tickets and 291 student tickets, which together sum up to the total of 388 tickets sold for the school play.
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Please help!
3x – 4 = = 35
Answer:
13
Step-by-step explanation:
3x13-4=35 Hope this helps
Step-by-step explanation:
Hope it helps.
Thank you
what is the median of these numbers? 4, 14, 7, 8, 12, 12, 5, 10
The median of that data set is 9.
Sort the numbers from least to greatest and find the middle number (that should be your median)
If there are 2 numbers in the middle of the set, then you take the average and that would be your median.
please help me with this math is for my math homework
Answer:
that answer is (1)
hope that helps you
9514 1404 393
Answer:
1
Step-by-step explanation:
You can put either number in the form of the other to see they are equal. A number divided by itself gives a quotient of 1.
-1 1/10 = -(10·1 +1)/10 = -11/10 . . . . . matches the denominator
or
-11/10 = -1 1/10 . . . . . matches the numerator
__
(-11/10)/(-11/10) = 1 . . . . your quotient
_____
Additional comment
Here, we see that both numbers in the problem are negative, so we have an even number of minus signs. That means the quotient will be positive. Knowing this lets us eliminate the minus signs from the problem.
As you may know, there are a couple of (fully equivalent) ways to divide fractions.
1) "invert and multiply" or "dot swap"
(11/10) ÷ (11/10) = (11/10) · (10/11) . . . . . . . the denominator has been inverted
= (11·10)/(10·11) = 110/110 = 1
2) use the numerators when the denominators are equal.
(11/10) / (11/10) = 11/11 = 1 . . . . denominators of the fractions are both 10
Solve using Quadratic Formula
x^2 + 3x - 3 = 0
Answer:
a= 1 , b= 3 , c= –3
[tex]x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - 3 \frac{ + }{} {} \sqrt{ {3}^{2} - 4(1)( - 3)} }{2(1)} \\ = \frac{ - 3 \frac{ + }{} \sqrt{9 + 12} }{2} = \frac{ - 3 \frac{ + }{} \sqrt{21} }{2} \\ \\ x = \frac{ - 3 \frac{ + }{} \sqrt{21} }{2} \\ \\ x = 0.79 \\ x = - 3.79[/tex]
I hope I helped you^_^
If the cost price of 21 article is equalto the selling price of 18 articles. Find profit precent
Answer:
The selling price of 21 articles is equal to the cost price of 18 articles. Find the loss percent. Answer: answer is 100/7 %
Which one describes the algebraic expression for the phrase, "twice a number decreased by 5 is greater than 12"? 2n - 5 = 12
2n - 5 < 12
12 + 5n > 2
2n - 5 > 12
Answer:
2n - 5 > 12[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
Deana and Bernice are pen pals. The sum of
their ages is 48 years. Eight years from now
Deana will be three times Bernice's age. What
is Bernice's ages now?
Step-by-step explanation:
[tex]thank \: you[/tex]
6+m/2 = -3
Help me pleAseeee
Answer:
m = -18
Step-by-step explanation:
6 + m/2 = -3
Subtract 6 from each side
6 + m/2 -6 = -3-6
m/2 = -9
Multiply each side by 2
m/2 * 2 = -9*2
m = -18
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\boxed{\mathsf{6+ \dfrac{m}{2}=-3}}}\\\huge\boxed{\rightarrow\mathsf{6 + \dfrac{1}{2}m = -3}}[/tex]
[tex]\huge\boxed{\rightarrow \mathsf{\dfrac{1}{2}m+ 6 = -3}}\\\\\huge\boxed{\text{SUBTRACT 6 to BOTH SIDES}}\\\huge\boxed{\mathsf{\dfrac{1}{2}m + 6 - 6 = -3 + 3}}[/tex]
[tex]\huge\boxed{\mathsf{\dfrac{1}{2}m = -9}}[/tex]
[tex]\huge\boxed{\text{MULTIPLY 2 to BOTH SIDES}}[/tex]
[tex]\huge\boxed{\mathsf{\dfrac{1}{2}m \times 2 = 2 \times -9}}[/tex]
[tex]\huge\boxed{\mathsf{m = 2\times-9}}\\\huge\boxed{\mathsf{2\times-9 = m}}\\\huge\boxed{\mathsf{2\times-9 = \bf -18}}\\\\\huge\boxed{\textsf{Therefore, your answer: \bf -18}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]
s = n(a+1) for a
please answer asap
Step-by-step explanation:
for a=
[tex] \frac{s - n}{n} [/tex]
Which of the following set of points represents a function?
(4,3), (2, 1), (2, 9). (9, 4)
(3,5), (4,5), (5,9), (7.-2)
(-1,2). (-1, 4), (-1,8), (-1,9)
Answer:
Each of the domain values, x, should only output a single unique range value, y.
This example is a relation and not a function because the the domain value of -1 output 2 distinct range values.
-1 outputs a 3
and
-1 outputs a 5
If I were to draw a vertical line at the domain value of -1 that vertical line would intersect the points (-1,3) and (-1,5). Which indicates that the relation is not a function.
Answer:
None of the following set of points represents a function .
(
a. Find the distance around the park to the nearest yard.
39
The distance is about
yards.
b. A new path and a bridge are constructed from point Q to the midpoint M of PR Find QM to the nearest yard.
QM
yd
c. A man jogs from P to Q to M to R to Q and back to P at an average speed of 150 yards per minute. To the neare
long does it take him to travel the entire distance?
It takes about
minutes
Type here to con
We have that the distance around the park to the nearest yard,QM to the nearest yard and the Time of travel for man's jog is given respectively as
[tex]X=190yd[/tex][tex]QM=40yd[/tex][tex]T=1.5minutes.[/tex]From the Question we are told that
[tex]PQ=(50-10)=40\\\\QR=(80-10)70[/tex]
Generally the equation for the Resultant PR is mathematically given as
[tex]PR=\sqrt{PQ^2+QR^2}\\\\PR=\sqrt{70^2+40^2}\\\\PR=80yd[/tex]
a)
Generally the equation for the Distance around they park is mathematically given as
[tex]X=PQ+QR+PR\\\\X=80+70+40\\\\[/tex]
[tex]X=190yd[/tex]
b)
Generally the equation for the Path QM is mathematically given as
From the diagram we see that
[tex]QM=PM=MR\\\\QM=\frac{80}{2}\\\\[/tex]
[tex]QM=40yd[/tex]
c)
From the question we are told
Average speed of [tex]150yd/m[/tex]
Total distance traveled
[tex]D_t=40+40+40+70+40\\\\D_t=230yd[/tex]
Therefore
Time
[tex]T=\frac{D_t}{V}\\\\T=\frac{230}{150}[/tex]
[tex]T=1.5minutes.[/tex]
in conclusion
The distance around the park to the nearest yard,QM to the nearest yard and the Time of travel for man's jog is given respectively as
[tex]X=190yd[/tex][tex]QM=40yd[/tex][tex]T=1.5minutes.[/tex]For more information on this visit
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SOMEONE HELP PLEASE ILL GIVE BRAINLIEST TO THE RIGHT ANSWER!!
Answer:
[tex] {9}^{ - \frac{1}{2} }[/tex]Step-by-step explanation:
Given,
[tex] \frac{ \sqrt[4]{9} \sqrt{9} }{ \sqrt[4]{ {9}^{5} } } [/tex]
[tex] = \frac{ \sqrt[4]{9} \sqrt{9} }{ \sqrt[4]{9 \times 9 \times 9 \times 9 \times 9} } [/tex]
[tex] = \frac{ \sqrt[4]{9} \sqrt{9} }{9 \sqrt[4]{9} } [/tex]
[tex] = \frac{ \sqrt{9} }{9} [/tex]
[tex] = \frac{ {9}^{ \frac{1}{2} } }{ {9}^{1} } [/tex]
[tex] = {9}^{ \frac{1}{2} - 1} [/tex]
[tex] = {9}^{ - \frac{1}{2} } (ans)[/tex]
Plz help with these 2 questions WILL GIVE BRAINLIEST!!
Answer:
<ALS - <2 = <1
< LDA + <ADE = 180 degrees
Step-by-step explanation:
<ALS = <1+<2
<ALS - <2 = <1
< LDA + <ADE = 180 degrees since it forms a straight line
Solve the equation for Y. Then find the value of y for each value of X.
y+2x=5;x=-2,0,4
help me on this pls
Answer:
y=5-2x
2 5-2(2)=5-4=1
0 5-2(0)=5
4 5-2(4)=5-8=-3
X squared can be combined with X
true or false
Answer:
False, assuming "combined" means "added or subtracted and would simplify."
[tex]x^2[/tex] and [tex]x[/tex] cannot be combined with addition or subtraction. They are not like terms.
Step-by-step explanation:
Combining like terms only works if the variables and the powers on the variables match perfectly.
Examples:
[tex]x^2[/tex] and [tex]x[/tex] don't have matching powers, so they're not like terms.
[tex]x^2[/tex] and [tex]y^2[/tex] have the same powers, but the variables don't match, so they're not like terms.
Anything can be multiplied together though. So that's a different situation.
What is the cube root of 27?
The cube root of 27 is 3!!