Decide whether the graphs of the given euqations are parallel perpendicular or neither

Decide Whether The Graphs Of The Given Euqations Are Parallel Perpendicular Or Neither

Answers

Answer 1
Answer: C) perpendicular

Explanation:

Each equation given to you is in y = mx+b form (aka slope intercept form).

The slope m is what we'll focus on.

The first equation has slope of 1, while the second equation has slope -1.

The two slopes multiply to -1. This is a property of any pair of perpendicular lines, as long as neither line is vertical nor horizontal.

Or you could note that -1 is the negative reciprocal of 1, or vice versa.

So there are a few options to see why the lines are perpendicular.


Related Questions

Which graphs are the graphs of even functions?

Answers

the one in the top left corner

A sector of a circle has an arc length of pi cm and a central angle of pi over 6 radians. What is the area of the sector?

Answers

Answer:

Area of sector is 6pi cm^2

Step-by-step explanation:

Mathematically pi radians is 180 degrees

thus pi/6 radians is 180/6 = 30 degrees

The formula for the length of an arc is;

theta/360 * 2 * pi * r

where theta in this case is 30 degrees

And the arc length is pi

so we have

30/360 * 2 * pi * r = pi

30/360 * 2 * r = 1

60r = 360

r = 360/60

r = 6 cm

Now the area of a sector is;

theta/360 * pi * r^2

30/360 * pi * 36

= 6pi cm^2

Use special right triangle ratios to find the lengths of the other leg and the hypotenuse

Answers

Answer:

leg = 18

hypotenuse = 18 sqrt(2)

Step-by-step explanation:

We know that sin theta = opp side / hypotenuse

sin 45 = 18 / hyp

hyp sin 45 = 18

hyp = 18 / sin 45

hyp = 18 sqrt(2)

Since this is an isosceles triangle ( the two angles are the same measure), the two legs have to be the same length

leg = 18

the lengths of the other leg and the hypotenuse

is 18 units and 18[tex]\sqrt{2}[/tex]units respectively.

Answer:

Solution given:

Let <C=<B=45°

AB=18 units

BC=?

AC=?

again

By using

By usingspecial right triangle ratios

sin C=opposite/hypotenuse=AB/AC=18/AC

Sin 45=18/AC

AC=18/sin45

AC=hypotenuse=18[tex]\sqrt{2}[/tex]units

again

Tan A=opposite/adjacent=BC/AB=BC/18

Tan45=BC/18

BC=Tan45*18

BC=length of another leg=18 units.

HELP!!!!!
If anyone knows the answer please tell me as soon as possible PLEASE!!!!

Answers

Answer:

Plotting the points on graph and joining them gives a right angle triangle

Answer:

right angle triangle

Step-by-step explanation:

Slope = (Y1-Y2)/(X1-X2)

The slope of AC is 1/3. The slope of BC is -3. Therefore AC is perpendicular to BC (right angle).

HELP PLEASE!

Given that sin A=3/7, cos B=-2/5, and both AA and B are in quadrant II, find cos (A-B). Simplify to a single value and leave it in the form of a rational number.

Answers

First, recall that

cos(A - B) = cos(A) cos(B) + sin(A) sin(B)

so you just need to find cos(A) and sin(B).

Since both A and B end in the second quadrant, you know that

• cos(A) and cos(B) are both negative

• sin(A) and sin(B) are both positive

Then from the Pythagorean identity, you get

cos²(A) + sin²(A) = 1   ==>   cos(A) = -√(1 - sin²(A)) = -2√10/7

cos²(B) + sin²(B) = 1   ==>   sin(B) = +√(1 - cos²(B)) = √21/5

You'll end up with

cos(A - B) = (-2√10/7) (-2/5) + (3/7) (√21/5)

… = (4√10 + 3√21)/35

(which makes the last sentence in the question kind of confusing, because this expression doesn't get much simpler and it's certainly not a rational number)

The value of cos(A - B) is approximately 23/25

Given that A and B are in the second quadrant, we have

sin A = 3/7cos B = -2/5

To find cos(A - B), we have to use trigonometric functions

cos(A - B) = cosAcosB + sinAsinB ...equation(i)

but

cos A

[tex]cos^2A + sin^2A =1 \\cos^2A = 1 - sin^2A\\cos^2A = 1 - (\frac{3}{7})^2 = 1 - \frac{9}{49}= cosA= -\frac{2\sqrt{5} }{7}[/tex]

Having the value of cos A, let's solve for cosB

Cos B

cos B = -2/5

[tex]sin^2B = 1-cos^2B\\sin^2B = 1-(-\frac{2}{5})^2= 1-\frac{4}{25}\\sinB = \sqrt{\frac{21}{25} }=\frac{\sqrt{21} }{5}[/tex]

cos(A-B)

substituting the values if sinA, cosA, sinB, cosB into equation(i) above;

[tex]cos(A-B)=cosAcosB+sinAsinB\\cos(A-B)=(-\frac{2\sqrt{5} }{7})(-\frac{2}{5})+(\frac{3}{7})(\frac{\sqrt{21} }{5})\\cos(A-B)=\frac{3\sqrt{21}+4\sqrt{5} }{35} \\cos(A-B) = 23/35[/tex]

The value of cos(A-B) is given above

Learn more on trigonometric functions here;

https://brainly.com/question/4326804

[tex]3f^{2} - 15f - 108[/tex]

Answers

Answer:

3(f - 9)(f + 4)

Step-by-step explanation:

Assuming you require to factorise the expression

3f² - 15f - 108 ← factor out 3 from each term

= 3(f² - 5f - 36) ← factor the quadratic

Consider the factors 0f the constant term (- 36) which sum to give the coefficient of the f- term (- 5)

The factors are - 9 and + 4 , since

- 9 × 4 = - 36 and - 9 + 4 = - 5 , then

f² - 5f - 36 = (f- 9)(f + 4)

Then

3f² - 15f - 108 = 3(f - 9)(f + 4)

Please help me !!!!!!!!!!

Answers

Answer:

[tex]EF=6[/tex]

Step-by-step explanation:

In this problem, one is given a circle with two secants (that is a line that intersects a circle at two points). One is given certain measurements, the problem asks one to find the unknown measurements.

The product of the lengths theorem gives a ratio between the lengths in the secants. Call the part of the secant that is inside the circle (inside), and the part of the secant between the exterior of the circle and the point of intersection of the secants (outside). The sum of (inside) and (outside) make up the entire secant, call this measurement (total). Remember, there are two secants, ([tex]secant_1[/tex]) and ([tex]secant_2[/tex]) in this situation. With these naming in mind, one can state the product of the length ratio as the following:

[tex]\frac{total_1}{outside_2}=\frac{total_2}{outside_1}[/tex]

Alternatively, one can state it like the following ratio:

[tex]\frac{inside_1+ouside_1}{outside_2}=\frac{inside_2+outside_2}{outside_1}[/tex]

Apply this ratio to the given problem, substitute the lengths of the sides of the secants in and solve for the unknown.

[tex]\frac{EF+FG}{HG}=\frac{SH+HG}{FG}[/tex]

[tex]\frac{2x+4}{5}=\frac{x+5}{4}[/tex]

Cross products, multiply the numerator and denominators of opposite sides of the fraction together,

[tex]\frac{2x+4}{5}=\frac{x+5}{4}[/tex]

[tex]4(2x+4)=5(x+5)[/tex]

Simplify,

[tex]4(2x+4)=5(x+5)[/tex]

[tex]8x+16=5x+25[/tex]

Inverse operations,

[tex]8x+16=5x+25[/tex]

[tex]3x+16=25\\3x=9\\x=3[/tex]

Substitute this value into the equation given for the measure of (EF),

[tex]EF=2x\\x=3\\\\EF=2x\\=2(3)\\=6[/tex]

You wait in line for hours to get the new special edition Nikes for $250, but you have to pay 5.3% in Virginia state sales tax. What is the total you will pay?

Answers

Answer:

263.25

Step-by-step explanation:

250 x .053 (5.3%) = 13.25 tax

250 + 13.25 = 263.25 price plus sales tax

Answer:

263.25

Step-by-step explanation:

Which of these is the absolute value parent function?
A. f(x) = 13x
B. f(x) = x + 2
C. f(x) = 1x1
D. f(x) = x - 11

Answers

Answer:

it's 'A' I guess

Step-by-step explanation:

hope it helps

Which of the following describes graphing y ≥ |x| + 4?

A. Translate y = |x| down 4 units and shade inside the V.
B. Translate y = |x| right 4 units and shade inside the V.
C. Translate y = |x| left 4 units and shade inside the V.
D. Translate y = |x| up 4 units and shade inside the V.

Answers

Answer:

The choose (D)

D. Translate y = |x| up 4 units and shade inside the V.

Prime numbers which are the sum and difference of other two prime numbers at the same time.

Answers

Answer:

Let a be the smaller of the two primes.

Now the middle of 2 primes is always even. So the middle number a+1 is divisible by 2.

Next the smaller of the primes when divided by 3 can have remainders 1,2.

1 is ruled out as possible remainder because then the remainder of a+2, the bigger of the primes would be (a+2) mod 3=(1+2) mod 3=3 mod 3=0,a contradiction since a prime number(except 3) when divided by 3 cannot have 0 as remainder.

So 2 is the only possible remainder of a. So the remainder of the bigger of the two primes when divided by 3 is (a+2) mod 3= (2+2) mod 3=4 mod 3=1.

This implies the middle number must have remainder (a+1)mod 3=(2+1)mod 3=3 mod 3=0. So the middle number is divisible by 3 also.

Hence a+1 is divisible by both 3 and 2 and since 2 and 3 have no common factors, so the middle number is divisible by 6

The graph of the function g(x) is given for #1 - 5.
1. Which of the following is the given function's
average rate of change on the interval PLS HELP. ASAP

Answers

Answer:

sorry mistalely hai Don Bosco school leave gareko he'llo you so much for your time and consideration and I will mark as the brillianest plzzzzzzzzzzzzzzzzzzzz seetq you so much for your time and consideration and I will mark as the brillianest plzzzzzzzzzzzzzzzzzzzz seetq you so much for your time and consideration and I will mark as the brillianest plzzzzzzzzzzzzzzzzzzzz seetq you so much for your time and consideration and I will mark as the brillianest plzzzzzzzzzzzzzzzzzzzz seetq you so much for

write 5 lcms of 100 and 120

Answers

Answer:

The LCM of 100 and 120 is 600.

The LCM of 5 and 120 is 120.

LCM of 5 and 100 is 100.

Step-by-step explanation:

I think this is the answer . If it is not sorry .

Use the expression, X^2-7
What is the value of the expression above when n=5

Answers

Answer:

18

Step-by-step explanation:

X^2 - 7 =

Since we need to evaluate the expression when X = 5, we replace X with 5.

= 5^2 - 7

Now, according to the correct order of operations, we need to do the exponent first. 5^2 = 5 * 5 = 25

= 25 - 7

Finally, we subtract.

= 18

Answer: 18

Each of 8 students reported the number of movies they saw in the past year. This is what they reported:
11, 17, 14, 11, 4, 7, 11, 11
Find the mean and median number of movies that the students saw.
If necessary, round your answers to the nearest tenth.

Answers

Answer:

10.75

11

Step-by-step explanation:

the mean is the average, so add up all of the values and divide by 8 because there are 8 values :

(11 + 17 + 14 + 11 + 4 + 7 + 11 + 11)/8 = 10.75

the median is the middle value when the numbers are written in ascending or descending order :

4, 7, 11, 11, 11, 11, 14, 17

we can cross out the values on the ends, to get to the middle. if we do this, we are left with 11, 11

find the average of these numbers :

which is 11.

the mean is 10.75
the median is 11
the mode is 11

(x+2y)^2
(2x+3y)^2
(3x-2y)^2

Answers

Answer:

(x+2y)(x+2y)

x²+2xy+2xy+2y²

x²+4xy+2y²

(2x+3y)(2x+3y)

4x²+6xy+6xy+9y²

4x²+12xy+9y²

ASAP HELP!! PLEASEEEE!!

Answers

Answer:

Step-by-step explanation:

5.1, please this is just a guess from using my head to calculate

Can someone please help me out

Answers

Step-by-step explanation:

[tex] \sqrt{ - 81} = 9i \\ \sqrt{ - 11} = i \sqrt{11} \\ \sqrt{ - 20} = i \sqrt{20} [/tex]

Can you guys help me find x for both

Answers

Answer:

x = 6 and x = 9

Step-by-step explanation:

16

MN is half the length of KL

MN = [tex]\frac{1}{2}[/tex] × 12 = 6

--------------------------------------------

17

Δ LMN and Δ LJK are similar triangles, so the ratios of corresponding sides are equal, that is

[tex]\frac{LM}{LJ}[/tex] = [tex]\frac{MN}{JK}[/tex] , substitute values

[tex]\frac{x}{x+9}[/tex] = [tex]\frac{8.5}{17}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )

2x = x + 9 ( subtract x from both sides )

x = 9

4. PLEASE HELP ME
Which of the quadratic functions has the widest graph?

A. y= -4/5x2

B. y= -4x2

C. y= 1/3x2

D. y= 0.3x2

Answers

Answer:

D. y= 0.3x2

Step-by-step explanation:

In quadratic functions, the value of a affects the wideness of the graph. The smaller the absolute value of a, the wider the graph. In these choices, 1/3 and 0.3 are the smallest. To understand which is smaller convert both to decimals; 1/3 is 0.3333 repeating. Therefore, 0.3 is slightly smaller and wider.

Given the sequence -14, -6, -2, 0, 1, ..., find the recursive formula.

Answers

2 I think is the answer

William wishes to view a frequency table for grouped data using his monthly credit card statements for the last 20 months, shown below. Construct the table for William using six classes. 1312, 1303, 809, 1477, 1263, 1444, 894, 1051, 1485, 1433, 1132, 1221, 1179, 945, 995, 1179, 1172, 1373, 906, 955 Provide your answer below: Lower Class Limit Upper Class Limit Frequency 809 1486

Answers

Frequency is the number of incidences of an occasion or value. A frequency table that displays the number of incidences of the goods and the number of times, and the further discussion can be defined as follows:

Lower class than adults who have little over two-thirds of a nationwide median's average household income.The higher class would include families with substantial wealth and biz incomes or where the primary breadwinner is utilized as a manager or a professional worker.

Calculation:

[tex]lower\ \ \ \ \ \ \ \ \ upper \ \ \ \ \ \ \ \ \ frequency\\\\809\ \ \ \ \ \ \ \ \ 921 \ \ \ \ \ \ \ \ \ 3\\\\922 \ \ \ \ \ \ \ \ \ 1034 \ \ \ \ \ \ \ \ \ 3\\\\1035 \ \ \ \ \ \ \ \ \ 1147\ \ \ \ \ \ \ \ \ 2\\\\1148 \ \ \ \ \ \ \ \ \ 1260\ \ \ \ \ \ \ \ \ 4\\\\1261 \ \ \ \ \ \ \ \ \ 1373 \ \ \ \ \ \ \ \ \ 4\\\\1374 \ \ \ \ \ \ \ \ \ 1486\ \ \ \ \ \ \ \ \ 4[/tex]

Learn more:

brainly.com/question/18359774

(c+d)^2+11(c+d)+30

Factor completely.

Answers

Answer:

firstable give c+b a polynomial value like x

so its will be x^2+11x+30

after the we have to factor it

30=6×5

and 11=6+5

so its will become

(x+6)×(x+5)=x^2+11x+30

x=c+d

(c+d+6)×(c+d+5)=(c+d)^2+11(c+d)+30

have a great day

5/21 as a decimal rounded to 3 decimal places

Answers

[tex] \sf \: \frac{5}{21 } \: rounded \: to \: 3 \: decimal \: places \: is \: \boxed{ \underline{ \bf0.238}}. \\ \longrightarrow \sf \: Just \: divide \: 5 \: by \: 21 \: upto \: 3 \: decimal \: places \\ \sf \: to \: get \: the \: answer.[/tex]


Find the distance between the points (10, 14) and (1,4) on a coordinate plane.

Answers

Sheeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeesh

If Ф ∈ (0, pi/2) and tan(pi cosФ) = cot(pi sinФ), then cos(Ф- pi/4) is equal to?\

Answers

Answer:

please see the answer in the picture.

What is the value of x that makes L1 ∣∣ L2?

A. 15
B. 29
C. 18
D. 25

Answers

Answer:

B

Step-by-step explanation:

For the lines to be parallel.

The 2 given angles are corresponding and congruent, that is

4x - 12 = 3x + 17 ( subtract 3x from both sides )

x - 12 = 17 ( add 12 to both sides )

x = 29 → B

The value of x will be 29°. Then the correct option is B.

What is a corresponding angle?

If two lines are parallel, then the third line. The corresponding angles are equal angles.

We know that the angle (3x + 17) and (4x – 12) are corresponding angle.

(3x + 17) = (4x – 12)

4x – 3x = 17 + 12

          x = 29°

The value of x will be 29°.

Then the correct option is B.

More about the corresponding angle link is given below.

https://brainly.com/question/1597341

#SPJ5

Which expression is equivalent to 4-2 _ 2-3

Answers

Answer:

16

Step-by-step explanation:

First you calculate the value

(2)÷2^-2

Then you simplify

2^4

=16

what’s the answer help pls

Answers

Answer:

D should be the anwser if im not mistaken!

Step-by-step explanation:

rp= 6 cm and as u can tell the side where q,s lies is a little bit longer so itll be 1 cm longer the r,p!!

Answer:

7

Step-by-step explanation:

Triangle Proportionality Theorem : If a line parallel to one side of a triangle intersects the other two sides of the triangle, then the line divides these two sides proportionally.

[tex]\frac{RP}{PT}[/tex] = [tex]\frac{SQ}{QT}[/tex]     Set up proportions

[tex]\frac{6}{18}[/tex] = [tex]\frac{x}{21}[/tex]        Cross multiply

18x = 126   Divide to isolate x

x = 7

What are the steps to this problem (along with the answer)?

Answers

Answer:

x = 3

Step-by-step explanation:

In this piece-wise function, there are three defined sections, each for a different range of x. To find an x where y is -9, we have to set all parts of it equal to -9.

-x,  x < -3

So, we can start by setting -x equal to -9 and solve for x:

-x = -9

x = 9

Our domain for this piece of the function is supposed to be x < -3. x = 9 does not fit into this range, meaning, in this range, there is no x for y = -9.

2x,   -3 ≤ x ≤ -2

We can set the value 2x equal to -9 and, again, solve for x:

2x = -9

x = -4.5

The solution x = -4.5 does not fit into the defined domain of -3 ≤ x ≤ -2, therefore it is not a solution.

-x^2,  x > -2

One last time, we can set -x^2 equal to -9 and solve for x:

-x^2 = -9

x^2 = 9

x = 3, x = -3

We are looking for a solution that fits into the domain, x > -2, x = -3 does not work, but x = 3 does.

In conclusion, the only solution where it fit the domain was x = 3

Answer:

x = 3

Step-by-step explanation:

x = - 3 in interval - 3 ≤ x ≤ - 2 then f(x) = 2x , so

f(- 3) = 2(- 3) = - 6 ≠ - 9

x = 9 in interval x > - 2 then f(x) = - x² , so

f(9) = - 9² = - 81 ≠ - 9

x = 3 in interval x > - 2 then f(x) = - x²

f(3) = - 3² = - 9

x = - 4.5 in the interval x < - 3 then f(x) = - x , so

f(- 4.5) = - (- 4.5) = 4.5

Thus

y = - 9 when x = 3

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