Answer:
5-Cy/r = d
Step-by-step explanation:
C=r(5-d)/y
Multiply each side by y
Cy=r(5-d)/y *y
Cy=r(5-d)
Divide each side by r
Cy/r=r(5-d)/r
Cy/r=(5-d)
Subtract 5 from each side
Cy/r - 5 = 5-d-5
Cy/r - 5 = -d
Multiply by -1
-Cy/r + 5 = d
5-Cy/r = d
[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]
[tex]C=\dfrac{r(5-d)}{y}\\\\cy=r(5-d)\\\\5-d=\dfrac{cy}{r}\\\\-d=\dfrac{cy}{r-5}\\\\d=-\dfrac{cy}{r}+5\\\\d=5-\dfrac{cy}{r}[/tex]
Multiply (8 + 3i)(3 + 5i).
39 + 491
9+ 491
24 + 152
24 + 491 + 15/2
(8+3)(3+5)=88
88+(39+491)= 618.
88+(9+491)= 588
88+(24+152)= 264.
sorry could not find the last ansswer..
3x-2=2(x-5)
find the value of x
Now we have to,
find the required value of x.
Let's begin,
→ 3x-2 = 2(x-5)
→ 3x-2 = 2x-10
→ 3x-2x = -10+2
→ x = -8
Hence, value of x is -8.
Answer:
x = -8
Step-by-step explanation:
3x - 2 = 2 ( x + 5
Solve for x.
Let's solve,
3x - 2 = 2 ( x + 5 )
Step 1:- Distribute 2.
3x - 2 = 2 × x + 2 × 5
3x - 2 = 2x - 10
Step 2 :- Move constant to the right-hand and change their sign.
3x = 2x - 10 + 2
Step 3:- Add -10 and 2.
3x = 2x - 8
Step 4 :- Move variable to the left-hand side and change their sign.
3x - 2x = -8
Step 5 :- Subtract 2x from 2x.
x = -8
Hence, value of x = -8.
d = 3.2(t+1)(2t - 3)
An air pump increases the oxygen levels in
an aquarium and reduces the build-up of
waste materials. The equation shown above
gives the depth, d, in inches of an air
bubble beneath the surface of the water t
seconds after it emerges from the air pump.
After how many seconds does the air
bubble reach the surface?
Answer:
3/2=1.5 sec
Step-by-step explanation:
Equate d=0 and solve the expression, t=-1 and 3/2 but t can't be negative.
The air bubble will reach the surface in 1.5 seconds.
What is an expression?Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.
The given expression is d = 3.2(t+1)(2t - 3) where d is the height of the aquarium and t is the time taken by the bubbles to come to the surface.
When the bubble will come to the surface height D becomes zero.
d = 3.2(t+1)(2t - 3)
3.2(t+1)(2t - 3) = 0
t + 1 = 0 and 2t - 3 = 0
t = -1 and t = 3 / 2 = 1.5
Therefore, the air bubble will reach the surface in 1.5 seconds.
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Find dy/dx given that y = 1 - cos x / sin x
Answer:
tan x
Step-by-step explanation:
The given function y is a quotient, so we must apply the quotient rule first. Recall that (d/dx)cos x = -sin x and that (d/dx)sin x = cos x.
Then the derivative of the given quotient is:
(sin x)[0 - (-sin x)] [sin x]^2
dy/dx = --------------------------- = ----------------- = 1
[sin x]^2 [sin x]^2
Use the distributive property to remove parentheses.
-8(x-3w-2)
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Answer:
= -8x +24w +16
Step-by-step explanation:
The factor outside multiplies each term inside parentheses.
-8(x -3w -2) = (-8)(x) +(-8)(-3w) +(-8)(-2)
= -8x +24w +16
the angles of a quadrilateral are x°,3x°,5x°and 6x° find x and hence calculate the angles of the quadrilateral.
Answer:
Step-by-step explanation:
The sum of the angles of a quadrilateral is 360°
x + 3x + 5x + 6x = 360
15x = 360
x = 24
Angles:
x = 24°
3x = 72°
5x = 120°
6x = 144°
Isaac records the following temperatures (in degrees Fahrenheit) at noon during one week:
87, 88, 84, 86, 88, 85, 83
These temperatures do not contain an extreme value.
Which measure of center should Isaac use to describe the temperatures?
A.
Interquartile range
B.
Mean absolute deviation (MAD)
C.
Either the mean or the median. The values are about the same.
D.
Range
please help. im new to brainly, but i will upvote you
Answer:
first, we put them in order
78,[80],83,(85),86,[87],90
Q1 = 80
Q2 (median) = 85
Q3 = 87
Interquartile range (IQR) = Q3 - Q1 = 87 - 80 = 7 <==
Hope this helps!
Find the sum of the series if possible, if not possible explain why:
1+(−2/5)+(−2/5)^2+(−2/5)^3+⋯
Answer:
Step-by-step explanation:
5/7
Sum of a geometric series is a/(1-r) = 1/(1-(-2/5)) = 5/7
When male workers were asked how many hours they worked in the previous week, the mean was with a standard deviation of . Does this suggest that the population mean work week for men exceeds hours
Answer:
We can conclude that the population mean work week for men exceed 40 hours.
Step-by-step explanation:
Given that :
Mean, xbar = 45.6
Standard deviation, s = 14.6
Sample size, n = 893
x = 40
Hypothesis :
H0 : μ = 40
H1 : μ > 40
Using test statistic for one sample t test :
Test statistic = (xbar - μ) ÷ (s/√(n))
Test statistic = (45.6 - 40) ÷ (14.6/√(893))
T = (5.6 / 0.4885703)
Test statistic = 11.46
Using the Pvalue approach :
Reject H0 : if Pvalue < α
Pvalue for test statistic of 11.46 will be approximately 0 (Extremely low)
Hence, Pvalue < α ; We reject H0 ; and conclude that population mean work week for men exceed 40 hours
Please help, I will give brainliest if you answer.
An angle measures 78.6° more than the measure of its supplementary angle. What is the measure of each angle?
Answer:
so required angles are 50.7°and 129.3°
Step-by-step explanation:
Let the angle be x
another angle = x + 78.6°
so,
x + x + 78.6° = 180° {being sum of supplementary angle}
so, 2x + 78.6° = 180°
or, 2x = 180° - 78.6°
or, x = 101.4/2
so, x = 50.7°
so another angle = x + 78.6°
= 50.7° + 78.6°
= 129.3°
2. What polygon is formed if you divide this figure into three equal parts? A squares B. triangles C. rhombuses D. kites
Answer: C
Step-by-step explanation:
I need help pls help me in geometry homework
(2 + i)-(4 - 6/)(-3 +3/)
Answer:
C
Step-by-step explanation:
(2+i)-(4-6i)(-3+3i)
=(2+i)-(-12+12i+18i-18i^2)
=(2+i)-[-12+30i-18(-1)]
=(2+i)-(-12+30i+18)
=(2+i)-(30i+6)
=2+i-30i-6
=-4-29i
A store offers different brands of a product. It decides to eliminate the brand
that is most likely to be returned. The table shows the number of items of
each brand that were returned over the past year and the total sold.
Retums
Total sold
Brand A
40
913
Brand B
38
792
Brand C
21
626
Brand D
15
451
Which brand should the store eliminate?
Answer:
In my points of view brand D should elimininate.In table have show the brand of D.If I am wrong I am sorry for talking 5pbt
The brand B must be eliminated since it has highest percentage 4.79%.
What is percentage?Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".
Here,
Brand A percentage = 40/913 ×100
= 4.38%
Brand B percentage = 38/792 ×100
= 4.79%
Brand C percentage = 21/626 ×100
= 3.35%
Brand D percentage = 15/451 ×100
= 3.32%
Therefore, brand B must be eliminated since it has highest percentage 4.79%.
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many ® Black pencils cost N75 each and coloured pencils cost N105 each. If 24 mixed pencils cost #2010, how of them were black? (Hint: Let there be x black pencils. Thus there are 24 - x) coloured pencils.)
Answer:
85
Step-by-step explanation:
I hope my answer help you
The owner of a small pet supply store wants to open a second store in another city, but he only wants to do so if more than one-third of the city's households have pets (otherwise there won't be enough business). He samples 150 of the households and finds that 64 have pets.
Define the appropriate parameter(s) and state the hypotheses for testing if this sample provides evidence that more than one-third of households in this city own pets.
Following are the calculation to the right-tailed test:
Calculating the null and alternative hypothesis:
[tex]H_0 : p = 0.3333\\\\H_a : p > 0.3333\\\\n = 150\\\\x = 64\\\\\hat{p} = \frac{x}{n} = \frac{64}{150} = 0.4267\\\\P_0 = 0.3333\\\\1 - P_0 = 1 - 0.3333 = 0.6667\\\\[/tex]
[tex]z = \frac{\hat{p} - P_0}{[\sqrt{\frac{P_0 \times (1 - P_0 )}{n}}]}[/tex]
[tex]= \frac{0.4267 - 0.3333}{[\sqrt{\frac{(0.3333 \times 0.6667)}{150}}]}\\\\= 2.426[/tex]
Calculating the right-tailed test:
[tex]P(z > 2.426) = 1 - P(z < 2.426) = 1 - 0.9924 = 0.0076\\\\P-value = 0.0076\\\\\alpha = 0.05\\\\P-value < \alpha[/tex]
Therefore, we reject the null hypothesis, Its example shows that more than a third of the families own pets in this town.
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An object is dropped from 24 feet below the tip of the pinnacle atop a 1468-ft tall building. The height h of the object after t seconds is given by the equatior h= - 16t2 + 1444. Find how many seconds pass before the object reaches the ground. seconds pass before the object reaches the ground. (Type an integer or a decimal.)
Answer:
9.5 seconds pass before the object reaches the ground.
Step-by-step explanation:
Height of the ball:
The height of the ball after t seconds is given by the following equation:
[tex]h(t) = -16t^2 + 1444[/tex]
Find how many seconds pass before the object reaches the ground.
This is t for which h(t) = 0. So
[tex]h(t) = -16t^2 + 1444[/tex]
[tex]-16t^2 + 1444 = 0[/tex]
[tex]16t^2 = 1444[/tex]
[tex]t^2 = \frac{1444}{16}[/tex]
[tex]t^2 = 90.25[/tex]
[tex]t = \pm \sqrt{90.25}[/tex]
Since it is time, we only take the positive value.
[tex]t = 9.5[/tex]
9.5 seconds pass before the object reaches the ground.
The height (in meters) of a shot cannonball follows a trajectory given by h(t) = -4.9t^2 + 14t - 0.4 at time t (in seconds). As an improper fraction, for how long is the cannonball above a height of 6 meters? Please show steps. Thank you!
how many terms are there in the series. 201.208.215......319
Answer:
222
Step-by-step explanation:
add 7 no. to each of like 201+7 = 208, 208+7=215 ,215+7=222
Type your answer into the box. X 30° Calculate the size of angle x. angle x =
Answer:
x = 60°Step-by-step explanation:
We know:
All triangles have internal angles that add up to 180°.
And
All right triangles have acute angles that up to 90°.
Therefore
x + 30° + 90° = 180°
x + 120° = 180° |subtract 120° from both sides
x + 120° - 120° = 180° - 120°
x = 60°orx + 30° = 90° |subtract 30° from both sides
x + 30° - 30° = 90° - 30°
x = 60°The size of angle x will be 60°
TriangleIt is a plane figure with three straight sides and three angles.
What are steps to solve this problem?The steps are as follow:
As per rule of triangle, the sum of all three internal angle must be equal to 180°The given triangle is right angle triangle having one angle 30° and other we have to findGiven:z = 90°
y = 30°
x = ?
∴ x + y + z = 180°
∴ x + 30 + 90 = 180
∴ x + 120 = 180
∴ x = 60°
So the size of angle x will be 60°
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Jarvis invested some money at 6% interest. Jarvis also invested $58 more than 3 times that amount at 9%. How much is invested at each rate if Jarvis receives $1097.19 in interest after one year? (Round to two decimal places if necessary.)
Use the variables x and y to set up a system of equations to solve the given problem.
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Answer:
$3309 at 6%$9985 at 9%Step-by-step explanation:
Let x and y represent amounts invested at 6% and 9%, respectively.
y = 3x +58 . . . . . . . the amount invested at 9%
0.06x +0.09y = 1097.19 . . . . . . total interest earned
__
Substituting for y, we have ...
0.06x +0.09(3x +58) = 1097.19
0.33x + 5.22 = 1097.19 . . . . . . . . . simplify
0.33x = 1091.97 . . . . . . . . . . . . subtract 5.22
x = 3309 . . . . . . . . . . . . . . . . divide by 0.33
y = 3(3309) +58 = 9985
$3309 is invested at 6%; $9985 is invested at 9%.
Which of the following is true about congruent figures?
Which set of statements explains how to plot a point at the location (Negative 3 and one-half, negative 2)?
A: Start at the origin. Move 3 and one-half units right because the x-coordinate is Negative 3 and one-half. Negative 3 and one-half is between 3 and 4. Move 2 units down because the y-coordinate is -2.
B: Start at the origin. Move 3 and one-half units down because the x-coordinate is Negative 3 and one-half. Negative 3 and one-half is between -3 and -4. Move 2 units left because the y-coordinate is -2.
C: Start at the origin. Move 3 and one-half units down because the x-coordinate is Negative 3 and one-half. Negative 3 and one-half is between -3 and -4. Move 2 units right because the y-coordinate is -2.
D: Start at the origin. Move 3 and one-half units left because the x-coordinate is Negative 3 and one-half. Negative 3 and one-half is between -3 and -4. Move 2 units down because the y-coordinate is -2.
Answer:
D: Start at the origin. Move 3 and one-half units left because the x-coordinate is Negative 3 and one-half. Negative 3 and one-half is between -3 and -4. Move 2 units down because the y-coordinate is -2.
[tex]\lim_{x \to \4} x^{2} -3x[/tex]
(4)^2-3(4)=4Answer:
Step-by-step explanation:
1/2 litre of kerosene costs $1.50what is the cost ofn2 litre of kerosene
Answer:
$6
Step-by-step explanation:
1.5 × 2 = 3
1 liter = $3
3 × 2 = 6
2 liters of kerosene is $6
Solve - 2x - 7 > X+ 8.
O A. x<-3
O B. x<-5
O C. x>-5
O D. x>-3
Answer:
x < -5
Step-by-step explanation:
- 2x - 7 > x+ 8
Add 2x to each side
- 2x+2x - 7 > x+2x+ 8
-7 > 3x+8
Subtract 8 from each side
-7-8 > 3x+8-8
-15 > 3x
Divide by 3
-15/3 > 3x/3
-5 >x
x < -5
surface areas of two similar figures are given. the volume of the larger figure is given. find the volume of the smaller figure
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Answer:
216 in³
Step-by-step explanation:
The ratio of volumes is the 3/2 power of the ratio of areas.
small volume = ((small area)/(large area))^(3/2) × (large volume)
= (212/1325)^(3/2) × 3375 in³ = (4/25)^(3/2) × 3375 in³ = (8/125)×3375 in³
small volume = 216 in³
Write an expression representing the unknown quantity.
There are 5,682,953 fewer men than women on a particular social media site. If x represents the number of women using that site, write an expression for the number of men using that site.
The expression for the number of men is
.
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Answer:
x - 5,682,953
Step-by-step explanation:
If x is the number of women, and the number of men is 5,682,953 less, then the number of men is x -5,682,953
Simplify: 4- (3 1)2 - 6 2 4 2. Combine like terms: 7x3 2x - 5x2 6 x 9 3x3 12x2 3. Simplify: (2x5- ... Multiply: 3x2(4x3 - 2x2 7x - 4) 5. Evaluate: 6x2 ...
Answer:
The complete question is defined in the attached file please find it.
Step-by-step explanation:
For question 1:
[tex]\to 4-(3+1)^2 - 6\div 2 +4 \\\\\to 4-(4)^2 - 6\div 2 +4\\\\\to 4-16 - 3 +4\\\\\to 4-19 +4\\\\\to 4-15\\\\\to -11[/tex]
For question 2:
[tex]\to 7x^3 +2x -5x^2+6+ x+ 9+ 3x^3 +12x^2 \\\\\to 7x^3 +3x^3+12x^2 -5x^2+2x+x+9+6 \\\\\to 10x^3 +7x^2+3x+15 \\\\[/tex]
For question 3:
[tex]\to (2x^5- 3x^2+4)-(x^5+2x^2+7)\\\\\to 2x^5- 3x^2+4-x^5-2x^2-7\\\\\to x^5- 5x^2-3\\\\[/tex]
For question 4:
[tex]\to 3x^2(4x^3- 2x^2+7x -4) \\\\\to 12x^5- 6x^4+21x^3 -12x^2 \\\\[/tex]
For question 5:
[tex]\to 6x^2+9x-7 \ \ \text{when} \ \ x=2\\\\\to 6(2)^2+9(2)-7 \\\\\to 6(4)+9(2)-7 \\\\\to 24+18-7 \\\\\to 24+11 \\\\\to 35[/tex]
1 + 1 = 3 is this right
Answer:
1 + 1 = 3 - 1 = 2
Step-by-step explanation:
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