Answer:
a.125.89..............
PLS HELP 19 POINTS!!!!!!!!
Answer:
Step-by-step explanation:
15. = 2.39
and jus use mathaway lma
For each relation, decide whether or not it is a function.
Answer:
Step-by-step explanation:
Relation 1 is a function
Relation 2 is not a function
Relation 3 is a function
Realation 4 is not a function
PLS HELP!
When rolling a single number cube, what are the odds, in simplest form, in favor of rolling a 4 or a 5? A. 1:1 B. 1:2 C. 1:3 D. 1:5
Answer: 1:3
Step-by-step explanation:
The odds are 2/6 because you’re given 2 choices from the 6 side die you can then simplify that fraction to 1:3
HELP ASAP
1.
(8,4)
(-4,2)
(4,-8)
(-8,4)
2.
(6,6)
(12,-12)
(-12,12)
(12,12)
3.
(-2,6)
(-4,12)
(4,12)
(12,-4)
Answer:
A(-2,1)》A1(-8, 4)
B(-3,3)》B1(-12,12)
C(-1,3)》C1(-4,12)
HOPE IT HELPS....
What is the length of each leg of the hypotenuse of the triangle below?
Answer:
H^2 = P^2 + B^2
H^2 = ( 3 root 2 )^2 + ( 3 root 2)^2
H^2 = 18 + 18
H^2 = 36
H = 6
Hence , option A is correct
hope that helps ✌
pls pls pls pls help me with this
Answer:
5 up and 2 to the right
Step-by-step explanation:
The center will be at the same spot as circle D, dilate by 3, then the dilation maps circle C into circle D.
-2(5x + 1) > 49
Solve for the inequality and enter your solution
Answer:
x < -51/10
General Formulas and Concepts:
Pre-Algebra
Equality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityStep-by-step explanation:
Step 1: Define
Identify
-2(5x + 1) > 49
Step 2: Solve for x
[Division Property of Equality] Divide -2 on both sides: 5x + 1 < -49/2[Subtraction Property of Equality] Subtract 1 on both sides: 5x < -51/2[Division Property of Equality] Divide 5 on both sides: x < -51/10Answer:
x < -51/10
Step-by-step explanation:
-10x -2 > 49
-10x > 51
x < -51/10
HELP PLEASE 50 POINTS DONT ANSWER IF YOU DONT KNOW
The ratio 2:3 means for every 2 inches on the original, the photocopy would be 3 inches.
3/2 = 1.5
The photocopied image is 1.5 times larger than the original.
Side BG on the original is side FG on the copy:
14 x 1.5 = 21 meters
FG = 21 meters
Answer:
FG = 21
Step-by-step explanation:
The ratio is 2:3
2 BC
----- = ----------------
3 FG
2 14
----- = ----------------
3 FG
Using cross products
2FG = 3*14
2FG = 42
Divide by 2
FG = 21
Lisa flips 2 fair coins.
What is the probability of obtaining two tails?
Answer:
1/4
Step-by-step explanation:
Each coin has a probability of 1/2 of landing on tails
What you do is multiply these probabilities together to get 1/4
Overline MD cong overline LS additional information is necessary to show that triangle MTD cong triangle LGS by SSS?
Answer:
[tex]TD \cong GS[/tex]
Step-by-step explanation:
See comment for complete question
Given:
[tex]TM \cong GL[/tex]
[tex]MD \cong LS[/tex]
Required
The information that shows [tex]\triangle MTD \cong \triangle LGS[/tex] by SSS
By SSS implies that, the three sides of both triangles are congruent
Already, we have:
[tex]TM \cong GL[/tex]
[tex]MD \cong LS[/tex]
The third side of [tex]\triangle MTD[/tex] is [tex]TD[/tex]
The third side of [tex]\triangle LGS[/tex] is [tex]GS[/tex]
So, for both to be congruent by SSS, the third sides must be congruent
i.e.
[tex]TD \cong GS[/tex]
Find the missing length of the following trapezoid with midsegment drawn
**You will earn 15 points for both of the problems**
Answer:
UV = 10
HG = 25
Step-by-step explanation:
UV = (11+9)/2 = 20/2 = 10
HG = (28+22)/2 = 50/2 = 25
Answer:
Below in bold.
Step-by-step explanation:
First problem:
The length of the mid segment is the mean of the 2 outer segments.
So it is (11+9)/2
= 20/2
= 10.
Second problem:
As above, it is (22+28) / 2
= 50/2
= 25.
pleaseee help mee helpp meeee
Answer:
i can help you i know this answer
Simplify: 45 ÷ 3 + 2 × 8 - 12 + 42
Answer:
61
Step-by-step explanation:
45/3 = 15
2*8 = 16
15+16-12+42 = 61
Answer:
15 + 16 + 30
and that is in total 61
Step-by-step explanation:
45/3 = 15
2×8 = 16
-12 + 42 = 30
you simplify an expression by calculating the part expressions, to be left only with the main terms and main operations.
Thank you so much, my friend
Answer:
Step-by-step explanation:
This is quite a doozy, my friend. We will set up a d = rt table, fill it in...and pray.
The table will look like this before we even fill anything in:
d = r * t
SUV
sedan
Ok now we start to pick apart the problem. Motion problems are the hardest of all story problems ever. This is because there are about 100 ways a motion problem can be presented. So far what we KNOW for an indisputable fact is that the distance from Georgetown to Greenville is 120 km. So we fill that in, making the table:
d = r * t
SUV 120
sedan 120
The next part is derived from the sentence "After an hour, the SUV was 24 km ahead of the sedan." This tells us the rate of the SUV in terms of the sedan. If the SUV is 24 km ahead of the sedan in 1 hour, that tells us that the rate of the sedan is r and the rate of the SUV is r + 24 km/hr. BUT we have other times in this problem, one of them being 25 minutes. We have a problem here because the times either have to be in hours or minutes, but not both. So we will change that rate to km/min. Doing that:
24 [tex]\frac{km}{hr}[/tex] × [tex]\frac{1hr}{60min}=.4\frac{km}{min}[/tex] So now we can fill in the rates in the table:
d = r * t
SUV 120 = r + .4
sedan 120 = r
They left at the same time, so now the table looks like this:
d = r * t
SUV 120 = r + .4 * t
sedan 120 = r * t
We will put in the time difference of 25 minutes in just a sec.
If d = rt, then the equation for each row is as follows:
SUV: 120 = (r + .4)t
sedan: 120 = rt
Since the times are the same (because they left at the same time, we will set the equations each equal to t. The distances are the same, too, I know that, but if we set the distances equal to each other and then solve the equations for a variable, the distances cancel each other out, leaving us with nowhere to go. Trust me, I tried that first! Didn't work.
Solving the first equation for time:
sedan: [tex]\frac{120}{r}=t[/tex] That's the easy one. Now the SUV. This is where that time difference of 25 minutes comes in from the last sentence. Let's think about what that sentence means in terms of the times of each of these vehicles. If the sedan arrived 25 minutes after the SUV, then the sedan was driving 25 minutes longer; conversely, if the sedan arrived 25 minutes after the SUV, then the SUV was driving 25 minutes less than the sedan. The latter explanation is the one I used in the equation. Again, if the SUV was driving 25 minutes less than the sedan, and the equations are solved for time, then the equation for the SUV in terms of time is
[tex]\frac{120}{r+.4}=t-25[/tex] and we solve that for t:
[tex]\frac{120}{r+.4}+25=t[/tex]
Again, going off the fact that times they both leave are the same, we set the equations equal to one another and solve for r:
[tex]\frac{120}{r+.4}+25=\frac{120}{r}[/tex]
I began by first multiplying everything through by (r + .4) to get rid of it in the denominator. Doing that:
[tex][r+.4](\frac{120}{r+.4}) +[r+.4](25)=[r+.4](\frac{120}{r})[/tex] which simplifies very nicely to
[tex]120+25(r+.4)=\frac{120}{r}(r+.4)[/tex] So maybe it's not so nice. Let's keep going:
[tex]120+25r+10=\frac{120r}{r}+\frac{48}{r}[/tex] and keep going some more:
[tex]130+25r=120+\frac{48}{r}[/tex] and now we multiply everything through by r to get rid of THAT denominator:
[tex]r(130)+r(25r)=r(120)+r(\frac{48}{r})[/tex] giving us:
[tex]130r+25r^2=120r+48[/tex] Now we have a second degree polynomial we have to solve by factoring. Get everything on one side and factor using the quadratic formula.
[tex]25r^2+10r-48=0[/tex]
That factors to
r = 1.2 and r = -1.6 and both of those rates are in km/minute. First of all, we cannot have a negative rate (this is not physics where we are dealing with velocity which CAN be negative) so we throw out the -1.6 and convert the rate of 1.2 km/minute back to km/hr:
[tex]1.2\frac{km}{min}[/tex] × [tex]\frac{60min}{1hr}[/tex] and we get
r = 72 km/h, choice B.
Wow...what a pain THAT was, right?!
If you have seven dimes how much money do you have
Answer:
70 cents or 0.70 dollars
Step-by-step explanation:
one dime is 10 cents so if you have 7 than you have 70 cents
Instructions: Find the missing side. Round your answer to the nearest tenth.
24°
х
27
Answer:
x = 60.6 units
Step-by-step explanation:
Hi there!
In this right triangle, we're given the measure of an angle, the side opposite that angle and another side adjacent to that angle (that is not the hypotenuse). In this circumstance, we can use the tangent ratio to help us solve for the missing side:
[tex]tan\theta=\frac{opp}{adj}[/tex]
Plug in the given information:
opp = 27, adj = x, θ = 24
[tex]tan(24)=\frac{27}{x}\\x=\frac{27}{tan(24)} \\x=60.6[/tex]
Therefore, the length of the missing side is 60.6 units when rounded to the nearest tenth.
I hope this helps!
What is the graph of the solution set of the inequality?
Answer:
The Tasty Beans Coffee House being planned for the corner of SE 12th and Main will ruin a perfectly nice neighborhood. Besides the fact that Tasty Beans already has coffee shops all over the city, it will pull business away from local coffee houses that have been here for decades. In addition, there is already a parking problem on that street, and the new business will just add to the congestion. They're planning a drive-up window, too, and that will mean a steady stream of traffic in a very high-volume area. Ask anyone walking down the street, and they'll tell you this is a bad idea. I speak for my whole neighborhood when I say, "Go away, Tasty Beans!"
Step-by-step explanation:
One of the diagonals of a rhombus of perimeter 120m is 36m. Find its area and the length of the other diagonal. pls answer fasttt
Answer: [tex]864\ m^2,\ 24\ m[/tex]
Step-by-step explanation:
Given
Perimeter of the rhombus is [tex]120\ m[/tex]
Length of one of the diagonal is [tex]d_1=36\ m[/tex]
All the sides of the rhombus are equal
[tex]\Rightarrow 4a=120\\\Rightarrow a=30\ m[/tex]
Area of the rhombus with side and one diagonal is
[tex]\Rightarrow \text{Area=}\dfrac{1}{2}d\sqrt{4a^2-d^2}[/tex]
Insert the values
[tex]\Rightarrow \text{Area=}\dfrac{1}{2}\times 36\times \sqrt{4\cdot 30^2-36^2}\\\\\Rightarrow \text{Area= }18\sqrt{3600-1296}\\\Rightarrow \text{Area= }18\times 48\\\Rightarrow \text{Area= }864\ m^2[/tex]
Area with two diagonals length can be given by
[tex]\Rightarrow \text{Area =}0.5\times d_1\times d_2 \\\text{Insert the values}\\\Rightarrow 864=36\times d_2\\\Rightarrow d_2=24\ m[/tex]
Thus, the area of the rhombus is [tex]864\ m^2[/tex] and the length of the other diagonal is [tex]24\ m[/tex]
Solve these inequalities:
a) x + 14 < 4x + 2 < 3x + 11
b) x + 8 < 8x - 6 < 5x + 12
Answer:
A) 4.7 < x < -3
B) 1.14 < x < 1.09
Step-by-step explanation:
a)
x + 14 < 4x + 2 < 3x + 11
x + 14 < 4x
14 < 4x - x
14 < 3x
4.7 < x
2 < 3x + 11
2 - 11 < 3x
-9 < 3x
-3 < x
4.7 < x - 3 < x
4.7 < x < -3
b)
x + 8 < 8x - 6 < 5x + 12
x + 8 < 8x
8 < 8x - x
8 < 7x
1.14 < x
-6 < 5x + 12
12 < 5x + 6
12 < 11x
1.09 < x
1.14 < x 1.09 < x
1.14 < x < 1.09
Find the H.C.F of these expressions.(2a²+6ac,4a²c+12ac²)
Answer:
Hello,
Answer 8a²c(a+3c) =8a³c+24a²c
Step-by-step explanation:
2a²+6ac=2a(a+3c)
4a²c+12ac²=4ac(a+3c)
H.C.F=2a(a+3c)*4ac=8a²c(a+3c)
Answer:
1st expression:2a×a+2×3×a×c
2nd expression:2×2×a×a+2×2×3×a×c×c
here,
2×a×a+2×3×a×c
2a^a+6ac
Angles 4 and 6 are
because they are
angles.
Answer: Is this a question? Or statement Yes they can be angles
Step-by-step explanation:
Johanna will plant up to 32 acres on her farm with wheat and corn. Fewer than 11 acres will be planted with wheat
The answer is
w + c ≤ 32
w < 11
w - the number of acres of wheat
c - the number of acres of corn
Johanna will plant up to 32 acres on her farm with wheat and corn:
w + c ≤ 32
Fewer than 11 acres will be planted with wheat:
w < 11
The two inequalities are:
w + c ≤ 32
w < 11
Find the length of the hypotenuse of a right angle triangle if remaining side are 3 cm and 4 cm.
Answer:
5 cm
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
let h be the hypotenuse , then
h² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )
h = [tex]\sqrt{25}[/tex] = 5
How many roots does the equation -11x5+5x-3=0 have?
11
3
5
Answer:
5
Step-by-step explanation:
The Fundamental theorem of Algebra states that a polynomial of degree n has n roots, some may be complex.
11[tex]x^{5}[/tex] + 5x - 3 = 0 ← is a polynomial of degree 5
Thus the equation will have 5 roots
Which best explains why all equilateral triangles are similar?
O All equilateral triangles can be mapped onto each other using dilations.
O All equilateral triangles can be mapped onto each other using rigid transformations.
O All equilateral triangles can be mapped onto each other using combinations of dilations and rigid transformations.
O All equilateral triangles are congruent and therefore similar, with side lengths in a 1:1 ratio.
Answer:
the correct answer is option 1.
The correct explanation is: All equilateral triangles are congruent and therefore similar, with side lengths in a 1:1 ratio.
What are similar triangles?Those triangles look the same but are different in size.
And in similar triangles,
the corresponding sides are in proportion to each other and the corresponding angles are equal to each other.
In an equilateral triangle, all three sides are congruent, and all three angles are congruent.
Therefore, any equilateral triangle can be transformed into any other equilateral triangle through a combination of translations, rotations, and reflections, without changing the size or shape of the triangle.
Thus, all equilateral triangles are similar, with side lengths in a 1:1 ratio, since they have the same shape but may differ in size.
To learn more about similar triangles;
https://brainly.com/question/14926756
#SPJ7
______ is a contract based on your promise to pay in the future for goods and services you receive today.
allocation
credit
principal
interest
Solve 4(x - 3) - 2(x - 1) > 0.
A. {x | x < -5}
B. {x | x > -5}
C. {x | x > 5}
D. {x | x < 5}
Answer:
Apply the distributive property.
4
x
+
4
⋅
−
3
−
2
(
x
−
1
)
>
0
Multiply
4
by
−
3
.
4
x
−
12
−
2
(
x
−
1
)
>
0
Apply the distributive property.
4
x
−
12
−
2
x
−
2
⋅
−
1
>
0
Multiply
−
2
by
−
1
.
4
x
−
12
−
2
x
+
2
>
0
Given:- 4(x - 3) - 2(x - 1) > 0.
Solving It:-
4(x - 3) - 2(x - 1) > 0
4x - 12 - 2x + 2 > 0
2x -10 > 0
2x > 10
x > 10/2
x > 5
So Correct Solution Set Will Be:-C. {x | x > 5}Hope This Helps YouThe total enclosed area is ____ square units. Round to the nearest tenths place (1 decimal place).
Answer: 47.6
Is this right?
Answer:
siis corretoed
Step-by-step explanation:
Shilpa's gym membership includes a one-time fee of $20. She then pays a discounted fee of $5 for each visit. The function that shows her average cost after x visits is: Recall the general form of a rational function: Which statement defines the horizontal asymptote? m < n, so y = 0 is the horizontal asymptote. m = n, so y = am / bn is the horizontal asymptote. m = n, so y = 0 is the horizontal asymptote. m > n, so there is no horizontal asymptote.
Answer:
See explanation
Step-by-step explanation:
Given
[tex]Flat = 20[/tex]
[tex]Visit = 5[/tex]
Required
The function to represent x visits
This is calculated as:
[tex]f(x) = Flat + Visit * x[/tex]
So, we have:
[tex]f(x) = 20 + 5 * x[/tex]
[tex]f(x) = 20 + 5x[/tex]
The second question is incomplete; however, I will explain how to calculate the horizontal asymptote of a rational function.
For polynomials with the same degree (i.e. m = n), the horizontal asymptote is calculated by dividing the coefficients of the highest degrees.
e.g.
[tex]f(x) = \frac{6x^2 + 1}{3x^2 + 4}[/tex] ---the degrees of both is 2
So, the horizontal asymptote is:
[tex]y = 6/3[/tex]
[tex]y =2[/tex]
If the numerator has a higher degree, then there is no horizontal asymptote.
If the denominator has a higher degree, then the horizontal asymptote is:
[tex]y = 0[/tex]
Answer:
First one is B, Second is 5
Step-by-step explanation:
got it right on edge
Solve: 3/x-4 >0
x < 4
x > -4
x > 4
x < -4
Answer:
x>4
Step-by-step explanation:
3/(x-4) >0
Divide each side by 3
3/(x-4) * 1/3 >0*1/3
1/(x-4) >0
We know if 1/(x-4) >0 then x-4 > 0
x-4>0
Add 4 to each side
x-4+4 >0+4
x>4
[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]
[tex]:\implies{\dfrac{3}{x-4}>0}\\\\:\hookrightarrow{\dfrac{3}{x-4}×\dfrac{1}{3}>0×\dfrac{1}{3}}\\\\:\longrightarrow{x-4>0}\\\\:\implies{x-4+4>0+4}\\\\ :\dashrightarrow{\sf{x>4}}[/tex]