Convert 85 cm/min to m/s.

Answer:

The answer is 29 AU

Hoped I helped

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Answer:

29

Explanation:

Answer:

The answer  is The acceleration is double its original value.

Explanation:

Hope this helps....

Have a nice day!!!!

Answer:

The acceleration is half of its original value

Explanation:

Answer:

The first answer is W and Z, since they appear to be a period apart. Dont know the second question. I did what I could, hope someone can answer the second.

Answer:

[tex]\boxed{0}[/tex]

Explanation:

Momentum is the measure of mass in motion.

[tex]\sf momentum = mass \times velocity[/tex]

An object at rest has a velocity of 0.

[tex]p=mv[/tex]

[tex]p = 25 \times 0[/tex]

[tex]p=0[/tex]

The momentum of an object at rest is always 0.

The correct answer is $243

Explanation:

The hole in the fence is 3 meters, this means it is necessary to buy wood that covers this distance. Now, each meter is equal to 100 centimeters, this means 3 meters is equivalent to 300 centimeters ( 100 cm in each meter x 3). Besides this, it is known each plank covers 20cm and costs $16.20. In this context, the next step is to find how many planks are needed. The process is shown below:

300 cm (total width) ÷ 20 cm (width of 1 plank) = 15 planks

This means 15 planks are needed. Finally, fin the total cost

15 planks x $16.20 (cost of 1 plan) = $243

Explanation:

this is it. hope u understand

[tex] \huge{ \underline{ \boxed{ \bf{ \blue{Solution:}}}}}[/tex]

We will solve the above Question by using equations of motion that are:-

Here,

By using first equation of motion,

⇛ v = u + at

⇛ 10 = 15 + a(2)

⇛ -5 = 2a

Flipping it,

⇛ 2a = -5

⇛ a = -2.5 m/s² [ANSWER]

❍ Acclearation is negative because final velocity is less than Initial velocity.

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Answer:

I assume its c. Since its talking about testing.

Explanation:

Answer:

The answer is test of durability

Explanation:

Explanation:

current = velocity/resistance

I = V/R

15/4

current = 3.75A

hope this helps...

Answer:

47.17 m

Explanation:

From the diagram of the question attached, The length of the legs are 25 m and 40 m . This legs form a right angle triangle with the length of the swimming course (L).

Pythagoras theorem states that for a right angle triangle with hypotenuse a and legs b and c, then:

a² = b² + c²

In the triangle, the length of the swimming course (L) is the hypotenuse and the two legs are 25 m and 40 m. Using Pythagoras:

L² = 25² + 40²

L² = 625 + 1600

L² = 2225

L = √2225

L = 47.17 m

Answer:

1) The density of the object = 2500 kg/m³

2) The density of the oil = 1250 kg/m³

Explanation:

1) The information relating to the question are;

The mass of the object in air = 0.250 kgf

The mass of the object in water = 0.150 kgf

The mass of the object in the oil  = 0.125 kgf

By Archimedes's principle, we have;

The upthrust on the object in water = Mass in air - mass in water = The weight of the water displaced

The upthrust on the object in water = 0.250 - 0.150 = 0.1 kgf

∴ The weight of the water displaced = 0.1 kgf

Given that the object is completely immersed in the water, we have;

The volume of the water displaced = The volume of the object

The volume of 0.1 kg of water water displaced = Mass of the water/(Density of water)

The volume of 0.1 kg of water = 0.1/1000 = 0.0001 m³

The density of the object = (Mass in air)/ volume = 0.250/0.0001 = 2500 kg/m³

The density of the object = 2500 kg/m³

2) Whereby the mass of the object in the oil = 0.125 kgf

The upthrust of the oil = The weight of the oil displaced

The upthrust of the oil on the object = Mass of the object in air - mass of the object in the oil

The upthrust of the oil on the object = 0.250 - 0.125 = 0.125 kgf

The weight of the oil displaced = The upthrust of the oil

Given that the volume of the oil displaced = The volume of the oil, we have;

The volume of the oil displaced = 0.0001 m³

The mass of the 0.0001 m³ = 0.125 kg

Therefore the density of the oil = 0.125/0.0001 = 1250 kg/m³.

The density of the oil = 1250 kg/m³.

Explanation:

Distance = speed × time

d = (55 mi/hr) (6.5 hr)

d = 357.5 mi

Answer:

  2.4583 ± 0.0207 seconds

Explanation:

The time period of a pendulum is approximately given by the formula ...

  T = 2π√(L/g)

The maximum period will be achieved when length is longest and gravity is smallest:

  Tmax = 2π√(1.51/9.7) ≈ 2.47903 . . . seconds

The minimum period will be achieved for the opposite conditions: minimum length and maximum gravity:

  Tmin = 2π√(1.49/9.9) ≈ 2.43756 . . . seconds

If we want to express the uncertainty using a symmetrical range, we need to find half their sum and half their difference.

  T = (2.47903 +2.43756)/2 ± (2.47903 -2.43756)/2

  T ≈ 2.4583 ± 0.0207 . . . seconds

__

We have about 2+ significant digits in the given parameters, so the time might be rounded to 2.46±0.02 seconds.

Answer:

[tex]t = 0.75 \ hr = 0.75 *60 = 45 \ minutes[/tex]

Explanation:

From the question we are told that

   The  hydraulic conductivity is  [tex]Ks = 10\ mm/hr[/tex]

    The  effective matrix potential [tex]Ns = 20 \ mm[/tex]

    The  intensity of  rainfall is  [tex]I = 30 \ mm/hr[/tex]

    The runoff rate [tex]R = 15 \ mm/hr[/tex]

Generally the run off rate is mathematically represented as  

      [tex]R = (I - Ks) t[/tex]

Here t is the amount of runoff generated

=>   [tex]15 = (30 - 10) t[/tex]

=>  [tex]t = 0.75 \ hr[/tex]

converting to minutes

    [tex]t = 0.75 \ hr = 0.75 *60 = 45 \ minutes[/tex]

Answer:

Answer:

27.34 (no unit)

Explanation:

26.975*82.33%+29.018*17.67%

=27.34

Answer: 19 meters.

Explanation:

We want to find the total displacement between t = 2s and t = 4s.

To do it, we can integrate our function, first write our velocity equation.

for t ≤ 3s, we have a linear equation, let's write it:

A linear relationship can be written as:

y = a*t + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

Now we can see that our line passes through the points (1, 0) and (0, -2)

then the slope is:

a = (0 -(-2)/(1 - 0) = 2/1 = 2

and knowing that when t = 0s, v(0s) = -2m/s, then our equation is:

v(t) = (2m/s^2)*t - 2m/s for t ≤ 3s

now, for t ≥3s the equation is constant, v(t) = 4m/s.

then we have

v(t) = (2m/s^2)*t - 2m/s -------if t ≤ 3s

v(t) = 4m/s ----- if t ≥ 3s

Now we integrate over time to get the position:

for t ≤ 3s we have:

p(t) = (1/2)*(2m/s^2)*t^2 - 2m/s*t + C

where C is a constant of integration, as we are calculating the displacement  this constant actually does not matter, so we can use C = 0m

p(t) = (1m/s^2)*t^2 - 2m/s*t  for t ≤ 3s

and p(3s) =  (1m/s^2)*3s^2 - 2m/s*3s = 9m - 6m = 3m is the initial position of the other part of the function.

for t ≥ 3s we have:

p(t) = 4m/s*t + p(3s) = 4m/s*t + 3m

then the position equation is:

p(t) = (1m/s^2)*t^2 - 2m/s*t  ---- t ≤ 3s

p(t) = 4m/s*t + 3m --- if t ≥ 3s

Now the displacement will be:

p(4s) - p(2s) where for each time, you need to use the correct function:

p(4s) = 4m/s*4s + 3m = 16m + 3m = 19m

p(2s) =  (1m/s^2)*2s^2 - 2m/s*2s = 4m - 4m = 0m

p(4s) - p(2s) = 19m - 0m = 19m

The butterfly displacement x from t=2 to 4s is 19 meters.

The spacing between two specified points is represented by the one-dimensional quantity of displacement (symbolised as d or s), commonly known as length or distance.

The total displacement between t = 2s and t = 4s.

Integrate our function, the velocity equation.

for t ≤ 3s, we have a linear equation, let's write it:

A linear relationship can be written as:

y = a x t + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

The line passes through the points (1, 0) and (0, -2)

The slope is:

a = (0 -(-2)/(1 - 0) = 2/1 = 2

When t = 0s, v(0s) = -2m/s, then our equation is:

v(t) = (2m/s²) x t - 2m/s for t ≤ 3s

now, for t ≥3s the equation is constant, v(t) = 4m/s.

v(t) = (2m/s²) x t - 2m/s -------if t ≤ 3s

v(t) = 4m/s ----- if t ≥ 3s

Now we integrate over time to get the position:

for t ≤ 3s we have:

p(t) = (1/2) x (2m/s²) x t^2 - 2m/s x t + C

where C is a constant of integration, to calculate the displacement  this constant actually does not matter,

p(t) = (1m/s²)*t^2 - 2m/s x t  for t ≤ 3s

and p(3s) =  (1m/s^2) x 3s² - 2m/s x 3s = 9m - 6m = 3m is the initial position of the other part of the function.

for t ≥ 3s we have:

p(t) = 4m/s x t + p(3s) = 4m/s x t + 3m

then the position equation is:

p(t) = (1m/s^2) x t² - 2m/s x t  ---- t ≤ 3s

p(t) = 4m/s x t + 3m --- if t ≥ 3s

Now the displacement will be:

p(4s) - p(2s) where for each time, you need to use the correct function:

p(4s) = 4m/s x 4s + 3m = 16m + 3m = 19m

p(2s) =  (1m/s²) x 2s²- 2m/s x 2s = 4m - 4m = 0m

p(4s) - p(2s) = 19m - 0m = 19m

Thus, the displacement is 19 m.

To learn more about displacement, refer to the link:
https://brainly.com/question/11934397

#SPJ2

Answer:

Diameter of Wire = 4.5 mm

Explanation:

First, we need to find the fractional part of the reading. The fractional part o the reading can be given by the following formula:

Fractional Part = Circular Scale Reading x Least Count

where,

Circular Scale Reading = 50

Least Count = 0.01 mm

Therefore,

Fractional Part = (50)(0.01 mm)

Fractional Part = 0.5 mm

Now, the diameter of the wire can be given by using the following formula:

Diameter of Wire = Linear Scale Reading + Fractional Part

Diameter of Wire = 4 mm + 0.5 mm

Diameter of Wire = 4.5 mm

Answer:

[tex]\Large \boxed{\mathrm{5.67 \ seconds }}[/tex]

Explanation:

[tex]\displaystyle \mathrm{acceleration \ = \ \frac{final \ velocity - initial \ velocity }{elapsed \ time}}[/tex]

[tex]\displaystyle A \ = \ \frac{V_f - V_i }{t}[/tex]

[tex]\displaystyle 3 \ = \ \frac{25 - 8 }{t}[/tex]

[tex]\displaystyle 3 \ = \ \frac{17 }{t}[/tex]

[tex]\displaystyle t \ = \ \frac{17 }{3} \approx 5.67[/tex]

Answer:

The answer is either 47 or 23. Most likely 47

Answer:

Well if they playing a game like that

Answer and Explanation:

Data provided in the question

Force = 50N

Length = 5mm

diameter = 2.0m = [tex]2\times 10^{-3}[/tex]

Extended by = 0.25mm = [tex]0.25\times 10^{-3}[/tex]

Based on the above information, the calculation is as follows

a. The Stress of the wire is

[tex]= \frac{force\ applied}{area\ of \ circle}[/tex]

here area of circle = perpendicular to the are i.e cross-sectional  i.e

= [tex]\frac{\pi d^{2}}{4}[/tex]

= [tex]\frac{\pi(2\times 10^{-3})^2}{4}[/tex]

Now place these above values to the above formula

[tex]= \frac{4\times 50}{\pi\times 4 \times 10^{-6}} \\\\ = \frac{50}{\pi}[/tex]

= 15.92 MPa

As 1Pa = 1 by N m^2

So,

MPa = 10^6 N m^2

b. Now the strain of the wire is

[tex]= \frac{Change\ in\ length}{initial\ length} \\\\ = \frac{0.25\times 10^{-3}}{5}[/tex]

= [tex]5 \times 10^{-5}[/tex]

Answer:

HELLO BELOW IS THE ATTACHED DIAGRAM USED TO ANSWER YOUR QUESTION AS IT WAS MISSING

A) 1270⁰c

B) 65%

C) 1320⁰c

D)  62%

Explanation:

Nickel alloy composition : 50 wt% Ni - 50 wt%

initial temperature = 1200⁰c = 2190⁰F

A) The temperature at which the first liquid phase form

from the attached diagram the temperature at which the first liquid if formed is 1270⁰c ( at point 2 )

B ) The composition of this liquid phase ( THE FIRST LIQUID )

the composition is found at point 3

wt % of Nickel = 35%, wt% of copper = 100 - 35 = 65%

C ) The temperature at which the alloy melts completely

from the attached diagram the temperature = 1320⁰c ( point 4 )

D)  The composition of the last solid remaining prior to complete melting

this can be gotten at point 5 and calculated as

wt % of Ni = 62%

wt % of Cu = 100 - 62 = 38%

Answer:

The maximum torque, τ = 3.67 × 10⁻³ Nm

Explanation:

The torque τ = NiABsinθ where N = number of turns of circular coil = 50.5, i = current in circular coil = 22.5 mA = 0.0225 A, A = area of circular coil = πr² where r = radius of circular coil = 4.75 cm = 0.0475 m, B = magnetic field strength = 0.455 T and θ = 90° for maximum torque.

So, τ = NiABsinθ

τ = Niπr²Bsinθ

τ = 50.5 × 0.0225 A × π × (0.0475 m)² × 0.455 T × sin90°

τ = 0.003665 Nm

τ = 3.665 × 10⁻³ Nm

τ ≅ 3.67 × 10⁻³ Nm

So the maximum torque, τ = 3.67 × 10⁻³ Nm

Answer:

a)0.51°

b)1.47×10^-4m

Explanation:

a)for a single slit experiment, the minima that has an angle of θ towards the centre needs to satisfy the expression below.

bsin(θ)= mλ.........................(*)

Where b= width of the slit

The distance on the screen from Central angle can be expressed as

Sin(θ)= y/d............. (**)

d and y is the horizontal distance between slit and screen

If we input eqn(**) into equation (*) we have

y= mλd/b................(z)

In order to find angle (θ) we have

(θ)= sin-(1.99×10^-2)/2.25

= 0.51°

Therefore, angle of diffraction θ of the second minimum is 0.51°

b)to find the width of the sloth using eqn(z) by substitute the values, we have

b= (2)(649×10^-9)(2.25)/1.99×10^-2

b= 1.47×10^-4m

Therefore, the width of the slit is 1.47×10^-4m

Answer:

1. direction of propagation of sound

2.medium through which sound trsnsmitted

Answer:

answer is B

Explanation:

Acc. to Ohm's Law:

V = I.R and therefore R=( V/I )

For line A, R = 6/2 = 3

line B, R = 4/2 = 2 ( for all the points plotted on this line the ratio of V and I is 2)

Line C = 2/2 = 1

Line D < 1

Hence, the correct answer is Line B :-)

Answer:

first part the skater goes down a constant slope ramp, initially he has Newton's second law

pply Newton's third law, the normal is the reaction to the support of the body on the surface

the ramp shoots off.  axis becomes zero and therefore with Newton's first law its speed

Explanation:

It is the description of this movement let's write Newton's laws.

* The first law that a body goes at constant speed or zero if the sum of the external forces is zero

* the second law is F = m a

* The third law states that the forces act in pairs of equal magnitude and opposite direction, one applied to each body.

Let's apply these laws to our case

In the first part the skater goes down a constant slope ramp, initially he has Newton's second law when he accelerates from the initial velocity of zero to a terminal velocity.

The expression for this is

             Wₓ - fr = ma

             W sin θ - μ W cos θ = m a

             W = mg

             g (sin θ - μ cos) = a

the value of the coefficient of kinetic friction depends on the condition of the surface, dry, wet or muddy

This is Newton's second law

On the Y axis, which is perpendicular to the ramp we have

            N- [tex]W_{y}[/tex] = 0

If we apply Newton's third law, the normal is the reaction to the support of the body on the surface, note that it can be different from the weight.

In the second part when he is on the ramp.

In the ramp the skater enters with a speed v, suppose that the ramp has an incline so that the skater can jump, in this case the angle is positive with respect to the axis x

In this case the analysis is similar to the previous one

Newton's second law gives the acceleration of the skater, who when he reaches the end of the ramp shoots off.

 At this point the force in the x (horizontal) axis becomes zero and therefore with Newton's first law its speed this axis remains constant and the force in the y axis is the force of gravity and has an acceleration that changes if velocity according to Newton's second law

Answer:look at explanations

Explanation:

Answer:

kinetic and potential

Answer:

Water waves are an example of waves that involve a combination of both longitudinal and transverse motions. As a wave travels through the waver, the particles travel in clockwise circles. The radius of the circles decreases as the depth into the water increases.