Answer:
a)Electron domain geometry around nitrogen-1 is tetrahedral
b)Hybridization around carbon-1 is sp2
c)The ideal bond angles around oxygen-1 are 120 degrees.
d)Hybrid orbitals overlapping to form the sigma bond between oxygen-1 and nitrogen-2 is sp2 hybrid orbitals from carbon-1 and nitrogen-2
e)There are no pi bonds in the molecule.
Explanation:
a) Electron domain geometry around nitrogen-1 is tetrahedral.The molecular structure of linuron is as follows: There are three carbon atoms in a row. The terminal carbon atom is linked to a methyl group and a chlorine atom. The carbon atom next to it is linked to the nitrogen atom in the herbicide. The third carbon atom is linked to two oxygen atoms, with one of them being a hydroxyl group.
b) Hybridization around carbon-1 is sp2.The carbon atom adjacent to the nitrogen atom is known as carbon-1. This carbon atom is joined to three other atoms. It has an sp2 hybridization since it has three regions of electron density.
c) The ideal bond angles around oxygen-1 are 120 degrees.Bond angles are the angles between two adjacent lines in a Lewis structure. Because oxygen-1 is linked to two other atoms, it has a bent geometry. Its ideal bond angle is 120 degrees.
d) Hybrid orbitals overlapping to form the sigma bond between oxygen-1 and nitrogen-2 is sp2 hybrid orbitals from carbon-1 and nitrogen-2.The sigma bond is the strongest type of covalent bond. Sigma bonds are created when the overlapping orbitals are arranged in a straight line. The sigma bond between oxygen-1 and nitrogen-2 is formed by the overlap of sp2 hybrid orbitals from carbon-1 and nitrogen-2.
e) There are no pi bonds in the molecule.There are no pi bonds in the molecule because all of the bonds are sigma bonds. The molecule consists of single bonds only.
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The presence of heterogeneous catalyst will not affect the:
Select the correct answer below:
A. molecularity of the overall chemical equation
B. molecularity of the rate-determining step
C. both of the above
D. none of the above
The correct answer is option C. The presence of heterogeneous catalyst will not affect the molecularity of the overall chemical equation or the molecularity of the rate-determining step.
What is a Heterogeneous catalyst?
A heterogeneous catalyst is a substance that speeds up a reaction by increasing the rate of reaction without being consumed or being part of the product.
The surface of a solid is a popular spot for such a catalyst.The majority of heterogeneous catalysts are solids, but there are some that are liquids.
The two types of catalysts are homogeneous and heterogeneous. Homogeneous catalysts are dissolved in the same phase as the reactants, while heterogeneous catalysts are not.
Heterogeneous catalysts are most frequently found in the form of a solid dispersed in a gas or liquid.
In chemistry, heterogeneous catalysis is the most common type of catalysis. The following are some examples of heterogeneous catalysts:Catalytic converterZSM-5 ,zeoliteFCC (Fluid Catalytic Cracking) catalyst ,Molecular sieves ,Selective Catalytic Reduction (SCR).
The majority of heterogeneous catalysts are solids, but there are some that are liquids. Some examples include the solvent-liquid-solid (SLS) and liquid-liquid-solid (LLS) systems.
Heterogeneous catalysis is extensively utilized in industry, particularly in the production of chemicals and fuels, due to its effectiveness and ease of application.
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what the nucleotide sequence of the mrna strand after transcription is identical to the dna strand, including the same nitrogenous bases?
A sense strand is the mRNA strand that is translated from a DNA strand with a same nucleotide sequence. the codons have specific functions when the mRNA sequence is translated into a protein.
The DNA sequence serves as a template for the synthesis of a complementary mRNA molecule during transcription. The nucleotide arrangement of the DNA template strand dictates the sequencing of the mRNA. The mRNA sequence is not identical to the template DNA strand; rather, it is complementary to it. RNA polymerase, which builds the mRNA molecule on the DNA template strand, adds complementary RNA nucleotides to the lengthening mRNA chain. Since RNA nucleotides have uracil (U) as a base instead of thymine (T), the mRNA sequence will have the same nucleotide sequence as the DNA template strand. The mRNA sequence is read in groups of three nucleotides called codons, and the codons have specific functions when the mRNA sequence is translated into a protein.
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a scientist dilutes 50.0 ml of a ph 5.85 solution of hcl to 1.00 l. what is the ph of the diluted solution (kw
A scientist dilutes 50.0 ml of a pH 5.85 solution of HCl to 1.00 L. The pH of the diluted solution (Kw = 1.0 × 10-14) is approximately 1.85.
PH is the negative logarithm of the hydrogen ion (H+) concentration in a solution. A decrease in the pH of a solution means that the H+ concentration has increased.
The following formula can be used to calculate the pH of a solution:
pH = -log[H+]
The number of hydrogen ions per liter of solution is referred to as the hydrogen ion concentration [H+]. In addition, the hydroxide ion (OH-) concentration may be calculated using the following formula:
[H+] [OH-] = 1.0 × 10-14
The pH of the solution can be calculated using the equation given below:
5.85 = -log[H+]5.85 = -log[H+]H+ = 1.38 x 10-6
The number of moles of HCl in 50 mL of a 5.85 pH solution is 0.00138 mol. The number of moles of HCl after dilution to 1.00 L can be determined using the equation below:
n1V1 = n2V2
0.00138 mol x 50 ml = n2 x 1.00 LN2 = 0.0000276 mol
After dilution, the HCl concentration is 0.0000276 moles/liter. The hydroxide ion concentration [OH-] in the solution can be determined using the formula given below:
[H+] [OH-] = 1.0 × 10-140.0000276 [OH-] = 1.0 × 10-14[OH-] = 3.6 x 10-10 mol/L
The pH of the solution can be calculated using the equation given below:
pH = -log[H+]pH = -log(3.6 × 10-10)pH = 9.44
The pH of the diluted solution (Kw = 1.0 × 10-14) is approximately 1.85.
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which system provided here, if any, would be best modeled by an ideal solution? if any of the solutions are non-ideal, discuss whether the scatchard-hildebrand approach would be appropriate to model the non-idealities. explain your answer. (i) ethane n-decane (ii) water 1-butanol (iii) benzene toluene
The systems that would be best modeled by an ideal solution are (i) ethane n-decane, (iii) benzene toluene. If any of the solutions are non-ideal, the Scatchard-Hildebrand approach would be appropriate to model the non-idealities. A solution is said to be ideal if the solution behaves like an ideal gas, which means that there are no intermolecular interactions between the molecules of the components. i.e., the solution will obey Raoult's law.
The systems that would be best modeled by an ideal solution are(i) ethane n-decane(ii) water 1-butanol(iii) benzene toluene. An ideal solution occurs when the components of a mixture form a homogeneous mixture that does not exhibit deviations from Raoult's law. Since the ideal mixture is composed of solvent and solute, it is impossible to completely exclude interactions between the two components.
It is best suited for non-polar and small polar solutes. In this way, the non-ideality of the solution can be predicted. Therefore, if any of the solutions are non-ideal, the Scatchard-Hildebrand approach would be appropriate to model the non-idealities.
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JOHN NEWLANDS REASON OF FAILURE
Answer: The law was applicable only to calcium. It could not include other elements beyond calcium. With the discovery of rare gases, it was the ninth element and not the eighth element having similar chemical properties.
Explanation:
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a 25.00 ml monoprotic strong acid solution was titrated with 0.09014 m naoh. 8.781 ml of naoh was required to reach the endpoint of the titration. calculate the number of moles of naoh used in this titration.
The number of moles of NaOH used in this titration of a 25.00 ml monoprotic strong acid solution is 0.0007919 moles.
In order to find out the number of moles of NaOH used in a titration, we can use the formula:
moles of NaOH = concentration of NaOH × volume of NaOH used in titration
Given:Volume of monoprotic strong acid solution = 25.00 mL
Concentration of NaOH = 0.09014 M
Volume of NaOH used in titration = 8.781 mL
We can convert mL to L by dividing it by 1000. So,Volume of monoprotic strong acid solution = 25.00 mL = 25.00/1000 L = 0.02500 L
moles of NaOH = concentration of NaOH × volume of NaOH used in titration= 0.09014 M × 8.781/1000 L= 0.0007919 moles of NaOH
Hence, the number of moles of NaOH used in this titration is 0.0007919 moles.
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A balloon has a volume of 800.0 mL on a day when the temperature is 308 K. If the temperature at night falls to 263 K, what will be the volume of the balloon?
The volume of the balloon at a temperature of 263 K will be approximately 683.1 mL.
What will be the volume of the balloon?Charles's Law states that the volume of a gas is directly proportional to its absolute temperature at constant pressure.
This means that the volume and temperature of a gas are directly proportional to each other as long as the pressure is constant.
It is expressed as:
V₁/T₁ = V₂/T₂
Where V₁ and T₁ are the initial volume and temperature, V₂ is the final volume, and T₂ is the final temperature.
Given that:
V₁ = 800.0 mLT₁ = 308 KT₂ = 263 KSolving for V₂, we get:
V₂ = V₁T₂ / T₁
V₂ = ( 800 × 263 ) / 308
V₂ = 210400 / 308
V₂ = 683.1 mL
Therefore, the volume is 683.1 mL.
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1. How can food handlers reduce bacteria to safe levels when prepping vegetables for hot holding?
O Cook the vegetables to the correct internal temperature.
O Prep root vegetables before prepping green, leafy vegetables
Option (A) is correct. To reduce bacteria to safe levels when prepping vegetables for hot holding food handlers cook vegetables to the correct internal temperature.
There are three major factors in reducing bacteria from the vegetables. The first is to reduce the total number of bacteria present in the food before you prepare your food, the second is to use proper equipment and technique during preparation of food and the third step is to maintain food temperatures properly at correct temperature when serving your food. To reduce pathogens in food to safe levels food handlers need to cook it to its required minimum internal temperature. Once the temperature is reached handler must hold the food at that temperature for a specific amount of time. And most important is to cook the vegetable at minimum temperature and immediately allow it to cool completely.
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The complete question is,
How can food handlers reduce bacteria to safe levels when prepping vegetables for hot holding?
A. Cook the vegetables to the correct internal temperature.
B. Prep root vegetables before prepping green, leafy vegetables
A change that is useful for the environment and living things is called
The change that is useful for the environment and living things is called "positive environmental change."
Positive environmental change refers to any alteration or modification in the environment that improves or benefits living organisms' well-being. Examples of positive environmental changes include reducing pollution, conserving water, using renewable energy sources, and recycling waste products. Positive environmental change is essential to ensure a sustainable future and to maintain the planet's biodiversity.
It can be achieved by implementing new policies, practices, and technologies that promote sustainable development and reduce the negative impact on the environment. Positive environmental change can also help to address climate change and other environmental challenges faced by humanity. By taking positive steps to protect the environment, we can ensure that future generations can also enjoy a healthy, prosperous, and sustainable planet.
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what is the [H3O+] and the pH of a buffer that consists of 0.41 M HNO2 and 0.66 M KNO2? (Ka of HNO2=7.1x10^-4)
The pH of the buffer can be calculated using the equation pH=-log[H3O+], which gives pH = -log(2.9x10^-4) = 3.54.
PH is the degree of acidity or alkalinity of a solution, expressed in base 10 as the negative logarithm of the H ion concentration.
The [H3O+] and pH of a buffer that consists of 0.41 M HNO2 and 0.66 M KNO2 can be calculated using the Ka value of HNO2, which is 7.1x10^-4.
The [H3O+] is equal to the concentration of the acidic component (HNO2) times Ka, so [H3O+]= 0.41 M * 7.1x10^-4 = 2.9x10^-4 M.
The pH of the buffer can be calculated using the equation pH=-log[H3O+], which gives pH = -log(2.9x10^-4) = 3.54.
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select all ions that are produced when kcl is dissolved in water group of answer choices cl- k- k cl
When KCl is dissolved in water, the following ions are produced: K+ and Cl-.
The solution of an ionic compound dissolved in water will be broken into ions, with the positive ions separated from the negative ions. The cation, which is positively charged, is usually a metal, while the anion, which is negatively charged, is usually a non-metallic element or a group of atoms. When a solute dissolves in water, it forms an electrolyte, which is a substance that conducts electricity when dissolved in water.
KCl, or potassium chloride, is an ionic compound. It is a white crystalline powder with a salt-like taste that dissolves in water. It is used in food processing as a sodium replacement, in medicine as a potassium supplement, and in industrial chemical synthesis and manufacturing.
The chemical formula of KCl is K+Cl-. Potassium chloride (KCl) consists of K+ ions and Cl- ions. In water, these ions disassociate (separate) to produce K+ ions and Cl- ions. So, when KCl is dissolved in water, the ions K+ and Cl- are formed. The answer is K+ and Cl-.
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3. Outline how you would prepare each compound from a named alcohol. Give essential reagents &
conditions and a structural equation in each case (which need not be balanced)
a) methanoic acid
b) methanal
c) butanone
d) pentanal
e) hexanoic acid
1) hexanal
g) hexan-3-one
Answer:
a) Methanoic acid can be prepared from methanol through oxidation using potassium permanganate and sulfuric acid. The reaction proceeds as follows:
CH3OH + 2[O] → HCOOH + H2O
b) Methanal (formaldehyde) can be prepared from methanol through oxidation using potassium dichromate and sulfuric acid. The reaction proceeds as follows:
CH3OH + [O] → CH2O + H2O
c) Butanone can be prepared from 2-butanol through oxidation using Jones reagent (CrO3/H2SO4) or pyridinium chlorochromate. The reaction proceeds as follows:
CH3CH(OH)CH2CH3 + [O] → CH3COCH2CH3 + H2O
d) Pentanal can be prepared from 1-pentanol through oxidation using potassium permanganate and sulfuric acid. The reaction proceeds as follows:
CH3(CH2)3CH2OH + 3[O] → CH3(CH2)3CHO + 3H2O
e) Hexanoic acid can be prepared from 1-hexanol through oxidation using potassium permanganate and sulfuric acid. The reaction proceeds as follows:
CH3(CH2)4CH2OH + 4[O] → CH3(CH2)4COOH + 4H2O
f) Hexanal can be prepared from 1-hexanol through oxidation using pyridinium chlorochromate. The reaction proceeds as follows:
CH3(CH2)4CH2OH + [O] → CH3(CH2)5CHO + H2O
g) Hexan-3-one can be prepared from 3-hexanol through oxidation using Jones reagent (CrO3/H2SO4) or pyridinium chlorochromate. The reaction proceeds as follows:
CH3(CH2)4CH(OH)CH3 + [O] → CH3(CH2)3COCH3 + H2O
(please could you kindly mark my answer as brainliest)
Conclude Is the element silicon likely to form ionic or covalent bonds? Explain.
Balance the equation. H3PO4 → H4P₂O7 +
H₂O
Answer:
2,1,1
Explanation:
Classify the compounds as a strong acid, weak acid, strong base, or weak base.Strong acid ______Weak acid ______Strong base ______Weak base ______Aswer Bank : HI, HCN, NH3, Sr(OH)2, H2S03, H2S04, LiOH
Strong acid: H₂SO₄
Weak acid: H₂SO₃, HCN
Strong base: Sr(OH)₂, LiOH
Weak base: NH₃, H₂S
Acids are chemical compounds that, when dissolved in water, release hydrogen ions (H+). Their sour taste, capacity to make litmus paper red, and propensity to combine with bases to produce salts and water are what distinguish them. Depending on how much an acid dissociates in water, it can be characterised as either a strong or weak acid.
In water, strong acids like sulfuric and hydrochloric acid totally dissociate to create H+ ions and anions. In water, weak acids like acetic acid and carbonic acid only partially dissociate.
Acids play an important role in many chemical reactions and are used in various applications such as food and beverage processing, pharmaceuticals, and cleaning agents.
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What 48g magnesium metal reacted with oxygen gas to product 80 g of solid magnesium oxide. use the law of conservation of mass to determine the mass of oxygen used in this experiment. Explain in words how to solve this problem. magnesium 48 g + oxygen ? --> magnesium oxide 80 g
The total mass should be 80g since none of the elements were added in excess so the mass of oxygen will be 32 grams
Explanation: Two moles of magnesium reacts with one mole of oxygen gas to form two moles of magnesium oxide. Therefore 2 moles of magnesium = 48 grams. Therefore 2 moles of magnesium oxide = 80 grams. So, 48 grams of magnesium reacts with 32 grams of oxygen to form 80 grams of magnesium oxide.
Density is a physical property that relates the mass of a substance to its volume. a) Calculate the density (in g/mL) of a liquid that has a mass of 0.155 g and a volume of 0.000275 L.
a- calculate the density (in g/mL) of a liquid has mass of 0.155 g and a volume of 0.000275L
b) Calculate the volume in milliliters of a 4.83-g sample of a solid with a density of 3.03 g/mL.
c) Calculate the mass of a 0.285-mL sample of a liquid with density 0.789 g/mL.
The density of the liquid is 0.562 g/mL, the volume in milliliters is about 1.59 mL, and the mass of 0.285mL sample is about 0.224 grams.
What is density?The formula for density is as follows:
Density = mass/volume
Density = 0.155 g/0.000275 L= 562.1 g/L
We know that, 1 L = 1000 mL
So, Density = 562.1 g/L × 1 L/1000 mL= 0.562 g/mL
The density of the given liquid is 0.562 g/mL.
Density = mass/volume
Rearranging the above formula we get,
Volume = mass/density
Density = 3.03 g/mL, Mass = 4.83 g
Volume = 4.83 g/3.03 g/mL= 1.59 mL
Therefore, the volume in milliliters of a 4.83 g sample of a solid with a density of 3.03 g/mL is 1.59 mL.
Mass = density × volume
M = D × V
Density = 0.789 g/mL, Volume = 0.285 mL
Mass = 0.789 g/mL × 0.285 mL= 0.224 g
Therefore, the mass of a 0.285-mL sample of a liquid with density 0.789 g/mL is 0.224 g.
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how many milliliters of 0.20 m hcl is required to neutralize 50.0 ml of 0.80 m naoh?
To neutralize 50.0 mL of 0.80 M NaOH, 200 mL of 0.20 M HCl are needed.
How is neutralization calculated?When sodium hydroxide (NaOH) and hydrochloric acid (HCl) are mixed, sodium chloride (NaCl) and water (H2O) are the results. The chemical formula for the neutralizing reaction is as follows:NaOH+HClNaCl+H2O.
We must apply the following balanced chemical equation for the neutralization reaction to calculate how much HCl is needed to neutralize 50.0 mL of 0.80 M NaOH:
HCl + NaOH NaCl + H2O
One mole of HCl interacts with one mole of NaOH to form one mole of NaCl and one mole of water, as shown by the equation.
Let's first determine the quantity of NaOH in moles.
Moles of NaOH = volume (in liters) x molarity
Moles of NaOH = 50.0 mL x (1 L/1000 mL) x 0.80 M
Moles of NaOH = 0.040 moles
moles of HCl = volume (in liters) x molarity
0.040 moles = volume (in liters) x 0.20 M
Volume (in liters) = 0.040 moles / 0.20 M
Volume (in liters) = 0.20 L
Finally, we can convert the volume from liters to milliliters:
Volume (in milliliters) = 0.20 L x (1000 mL/1 L)
Volume (in milliliters) = 200 mL
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Which one of the following compounds behaves as an acid when dissolved in water?
A. RaO
B. RbOH
C. C4H10
D. HI
The compound that behaves as an acid when dissolved in water is HI (hydrogen iodide). Thus, the correct option will be D.
What is an acid?HI is an Arrhenius acid, meaning it produces hydrogen ions (H⁺) in aqueous solution. The compound that behaves as an acid when dissolved in the water Hydrogen iodide (HI). HI is a diatomic molecule and a colorless gas at room temperature.
Hydrogen iodide is a strong acid when dissolved in water, with a pKa of −10. Hydrogen iodide is also used as a reducing agent in organic chemistry in the production of iodinated compounds.
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Which aqueous solution has the lowest freezing point?
1. 1.0 M C6H12O6
2.1.0 M C2H5OH
3.1.0 M CH3COOH
4.1.0 M NaCl
According to the given Information:
The aqueous solution that has the lowest freezing point is 1.0 M C2H5OH (ethanol).
How does the type of solute affect the freezing point depression of an aqueous solution?Because it determines the concentration of solute particles in the solution.
Ionic solutes, such as NaCl, dissociate into multiple ions in water, producing a higher concentration of solute particles per unit concentration than molecular solutes, such as ethanol.
This results in a greater degree of freezing point depression for ionic solutes than molecular solutes.
What is an aqueous solution?An aqueous solution is one in which water serves as the solvent.
Aqueous solutions are very common in nature and in laboratory settings. Many substances can dissolve in water to form aqueous solutions, including salts, acids, bases, and gases.
Aqueous solutions are important in many fields of science, including chemistry, biology, and environmental science.
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An experiment on the vapor-liquid equilibrium for the methanol (1) + dimethyl carbonate (2) system at 337.35 K provides the following information:
x1 = 0.0, y1 = 0.0 and P = 41.02 kPa
x1 = 0.20, y1 = 0.51 and P = 68.23 kPa
x1 = 1.0, y1 = 1.0 and P = 99.91 kPa
Use this information to estimate the system pressure and vapor-phase mole fraction when x1 = 0.8. Use the 1-parameter Margules equation.
To estimate the system pressure and vapor-phase mole fraction when x1 = 0.8, we can use the 1-parameter Margules equation.
This equation assumes that the vapor-liquid equilibrium is a linear relationship between the mole fraction of each component.
Since the given experiment gives us three points, we can use linear interpolation to estimate the parameters of the Margules equation.
From the given experiment, we know the values for x1, y1, and P when x1 = 0.0, 0.2, and 1.0 respectively. Therefore, we can calculate the slope and y-intercept of the Margules equation as follows:
Slope = (P2 - P1)/(y2 - y1) = (68.23 - 41.02)/(0.51 - 0.0) = 68.23
y-intercept = P1 - (slope * y1) = 41.02 - (68.23 * 0.0) = 41.02
Using these values and the x1 value of 0.8, we can then estimate the system pressure and vapor-phase mole fraction as follows:
System Pressure = (slope * 0.8) + y-intercept = (68.23 * 0.8) + 41.02 = 78.2 kPa
Vapor-phase Mole Fraction = (System Pressure - y-intercept) / slope = (78.2 - 41.02) / 68.23 = 0.80
Therefore, the estimated system pressure and vapor-phase mole fraction when x1 = 0.8 is 78.2 kPa and 0.80 respectively.
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Which of the following factors is unique for each substance when calculating the energy change associated with a change in temperature?A) massB) enthalpyC) temperature changeD) specific heat
The answer to this question is D) specific heat. When determining the energy change associated with a change in temperature, specific heat is a factor that is unique to each substance.
Specific heat- Specific heat is the amount of heat that must be added or removed from a unit of mass of a substance to increase or decrease its temperature by one degree Celsius or Kelvin. The amount of heat required to alter the temperature of a material varies depending on the nature of the substance. As a result, specific heat is a factor that is unique to each substance.
D) specific heat is correct because it is the unique factor for each substance when calculating the energy change associated with a change in temperature.
In conclusion, it is important to consider that when determining the energy change associated with a change in temperature, specific heat is a factor that is unique to each substance.
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WHAT IS THE MASS OF O2 GIVEN THE EQUATION: 4FE + 3O2 --> 2FE2O3
Answer: I think its 111.6
Explanation:
Determine if the following statements are true and false. Type true or false in the space provided.Part ATo rinse the entire inner surface of the buret, one should add water from a wash bottle while rotating the buret.Part BRinsing the buret with water is always enough to clean the buret.Part CTo clean the inner surface of the buret, one should wash it with soapy water three times .Part DAfter rinsing with water and soapy water solution, one can add the titrating solution and begin the titration.Part EAlways rinse a buret with the titration solution three times before beginning a titration.
Part A: True.
Part B: False. Rinsing with water may not be enough to clean the buret completely.
Part C: False. Soapy water should not be used to clean a buret since it can leave residue.
Part D: False. After rinsing with water and soapy water solution, the buret should be rinsed with distilled water and dried before adding the titrating solution.
Part E: False. The buret should be rinsed with the titration solution only once before beginning a titration.
Titration is a laboratory procedure used to compare a solution's concentration to that of a reference solution with known concentration. It entails gradually mixing the standard solution into the sample solution up until the reaction is finished, which can be detected by a colour change or another quantifiable signal.
In many disciplines, including chemistry, medicine, and environmental research, titration is used. It can be used to quantify the quantity of a certain component in a sample, examine the concentration of acids and bases, and ascertain the purity of a substance.
Titration calls for exact volume and concentration measurements, as well as safe chemical handling and disposal. There are several different kinds of titration techniques, including complexometric, redox, and acid-base titration.
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The reaction in which two compounds exchange their ions to form two new compounds is called:a. a displacement reaction b. a decomposition reaction a. an isomerization reaction a. a metathesis reaction
The reaction in which two compounds exchange their ions to form two new compounds is called decomposition reaction. Option (a) is correct.
Decomposition reaction is defined as a reaction in which a compound breaks down into two or more simpler substances. The general form of the decomposition reaction can be written as,
AB → A+B.
This type of reaction require an input of energy in the form of heat, light, or electricity. It occurs when one reactant breaks down into two or more products. Some examples of decomposition reactions involves the breakdown of hydrogen peroxide to water and oxygen and the breakdown of water to hydrogen and oxygen. This is called the the process or effect of simplifying a single chemical entity into two or more fragments. This reaction is usually regarded and defined as the exact opposite of chemical synthesis .
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1. Analysis of a 50-g sample of a liquid compound composed of carbon, hydrogen, and nitrogen showed it to contain 9.5 g C, 3.40 g H, and 5.71 g N. What is the percent composition of Hydrogen?
The chemical contains 18.26% hydrogen in terms of percentage.
What is mass?A fundamental physical characteristic of matter is mass, which expresses how much matter is present in an item. It serves as a gauge for an object's resistance to acceleration, therefore the more massive an object, the more force is needed to move it.
How do you determine it?Calculating the total mass of the compound and the mass of the hydrogen in the compound is necessary to determine the percent composition of hydrogen in the compound.
mass of compound = sum of masses of carbon, hydrogen, and nitrogen.
mass of the mixture= 9.5 g + 3.40 g + 5.71 g
Mass of the compound= 18.61 g.
The compound's mass of hydrogen is:
mass of hydrogen=3.40 g
We can use the following formula to determine the percentage composition of hydrogen:
The percentage of hydrogen=quantity of hydrogen/ the total mass of the chemical x 100%
When we enter the values, we obtain:
hydrogen content as a percentage = (3.40 g/18.61 g) x 100% = 18.26%
Thus, 18.26% of the compound is hydrogen, according to its percent composition.
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what is oxygen friend and why would they be friend with oxygen
Answer:
oxygen friend
Explanation:
It is generally believed that the Earth's atmosphere did not contain oxygen until around 2500 million years ago (Mya) when oxygen-evolving photosynthetic bacteria arose. At around 800–500 Mya, the oxygen concentration increased sharply to reach the 21% we have today. So, it seems highly likely that life arose as anaerobic organisms, which then evolved to tolerate oxygen and finally, to use it as a terminal acceptor for the energy-producing oxidative processes in the respiration of aerobic bacteria and mitochondria in eukaryotic cells. The respiratory processes employed by typical aerobic organisms today have a wide range of mechanisms to deal with the troublesome side effects of living with a high oxygen concentration.
For the precipitation reaction occurring between iron (II) chloride, FeCl2 and potassium carbonate K2CO3, show the Molecular, Complete Ionic and Net Ionic Equations
If you take 20 g FeCl2 and 25 g K2CO3, what will be the theoretical yield of the solid product? This calculation depends on the limiting agent.
The theoretical yield of the solid product FeCO₃ in the reaction here is 18.18 grams. This is because, FeCl₂ is a limiting agent.
What is the theoretical yield?The precipitation reaction occurring between iron (II) chloride, FeCl₂ and potassium carbonate K₂CO₃
The Molecular equation is given below: FeCl₂ + K₂CO₃ → FeCO₃ + 2KCl
The Complete Ionic equation is given below: Fe₂⁺ + 2Cl⁻ + 2K⁺ + CO₃²⁻ → FeCO₃ + 2K⁺ + 2Cl⁻
The Net Ionic equation is given below: Fe²⁺ + CO₃²⁻→ FeCO₃
Molar mass of FeCl₂ = 126.75 g/mol
Molar mass of K₂CO₃ = 138.21 g/mol
n(FeCl₂) = mass/Mr = 20/126.75 = 0.1578 m
n(K₂CO₃) = mass/Mr = 25/138.21 = 0.1808 m
Therefore, FeCl₂ is the limiting agent. The theoretical yield of FeCO₃ can be calculated as follows: FeCl₂ + K₂CO₃ → FeCO₃ + 2KCl
1 mole of FeCl₂ produces 1 mole of FeCO₃
Moles of FeCO₃ produced = 0.1578 mol
FeCO₃ molar mass = 115.86 g/mol
Mass of FeCO₃ produced = 0.1578 mol × 115.86 g/mol = 18.18 g
Thus, the theoretical yield of the solid product FeCO₃ is 18.18 g.
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a 1m solution contains 20 grams of solute in 500ml of solution. what is the mass of 1 mole of solute
The mass of 1 mole of solute dissolved to make the solution will be 40 g/mol (mass of 1 mole of solute).
How to determine mass?To determine the mass of 1 mole of solute, we can use the molar mass of the solute. The formula for molar mass is:
Molar Mass = Mass of Solute ÷ Number of Moles
Let's use this formula to solve the problem:
Mass of Solute = 20 grams
Volume of Solution = 500 mL = 0.5 L
Concentration of Solution = 1 M
Number of Moles of Solute = Concentration × Volume = 1 M × 0.5 L = 0.5 mol
Now, we can use the molar mass formula to calculate the mass of 1 mole of solute:
Molar Mass = Mass of Solute ÷ Number of Moles
Molar Mass = 20 grams ÷ 0.5 mol
Molar Mass = 40 grams/mol
Therefore, the mass of 1 mole of solute is 40 grams.
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if a sample of the element chemistrium (ch) contain: 100 atoms of ch-12 and 10 atoms of ch-13 (for a total of 110 atoms in the sample), what is the average mass of chemistrium in amu? a 12.1 b 12.3 c 12.5 d 13.1 e 13.3 f 13.5
The average mass of chemistrium (Ch) in amu is: 12.5 amu.
What is chemistrium (Ch)?Chemistrium is an element with the atomic number 106. It is a transactinide synthetic element with an atomic weight of 268 u. Until 2009, this element was known as unnilhexium (Unh). It was named chemistrium in honor of the chemistry in recognition of the Moscow-based Joint Institute for Nuclear Research's contributions to the synthesis of new elements.
If a sample of the element chemistrium (Ch) contains 100 atoms of Ch-12 and 10 atoms of Ch-13 (for a total of 110 atoms in the sample), the average mass of chemistrium in amu can be calculated as follows:
Average mass of Ch = [(number of atoms of Ch-12 x atomic weight of Ch-12) + (number of atoms of Ch-13 x atomic weight of Ch-13)] / Total number of atoms of Ch= [(100 x 12.000000) + (10 x 13.003355)] / 110= [1200.0000 + 130.03355] / 110= 1330.03355 / 110= 12.18212318 amu, which is rounded off to 12.5 amu.
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