Compute the decimal representation for each of the following numbers.

a. (1100110)2
b. (346)7
c. (1024)8
d. (3B2)16
e. (AF72)16
f. (120121)3
g. (A22)11

Answer:

"U > K > P" would be the appropriate answer.

Explanation:

Answer:

even = []

odd = []

for i in range(1,101):

if i % 2 == 0:

even.append(i)

else:

odd.append(i)

Using range(1,101), the list of even and odd number can be done in python as follows;

odd_numbers = []

even_numbers = []

for i in range(1, 101):

  if i%2 == 0:

     even_numbers.append(i)

  else:

     odd_numbers.append(i)

print(even_numbers)

print(odd_numbers)

The variable odd_numbers is initialise with an empty list

The variable even_numbers is initialise with an empty list.

Then we loop through the range 1 to 101 as required.

If the looped numbers is divided by 2 without a remainder then the number is appended to the empty list even_numbers.

Else if it has a remainder, the looped number are appended to the empty list, odd_numbers.

Then we print the even_numbers and odd_numbers.

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Answer:

Once you have a data source connected to your document, adding merge fields is a way to personalize a document with information from the data source.

Answer:

Option B (Organization) would be the correct answer.

Explanation:

The other options offered aren't relevant to the scenario presented. So, the solution here is just the right one.

Answer:

from socket import *

hostname = input('Enter the host to be scanned: ')

ip_add = gethostbyname(hostname)

connections = [ ]    

for i in range(133, 136):

   s = socket(AF_INET, SOCK_STREAM)

   conn = s.connect_ex((ip_add, i))

   print(conn)

   connections.append(conn)

if 0 in connections:

   print ('Host is online')

   s.close()

else:

   print ('system is unreachable')

Explanation:

The python source code above scans for all the available range of ports in the provided hostname, if any port is available, the host is online else the program print the error message "system is unreachable.

Answer:

Business equipment can be continually adjusted based on analysis of data

Explanation:

A P E X

public class JavaApplication78 {

   public boolean findChar(String string, String key){

       if (string.contains(key)){

           return true;

       }

      return false;

   }

   public static void main(String[] args) {

       JavaApplication78 java = new JavaApplication78();

       System.out.println(java.findChar("hello", "h"));

   }

}

First I created the findChar method using the contains method. It checks to see if a certain sequence of characters is in another string. We returned the result. In our main method, we had to create a new instance of our main class so we could call our findChar method.

Answer:

52 5,

Explanation:

num1 = float(input("Enter the first number: "))

num2 = float(input("Enter the second number: "))

print("{} + {} = {}".format(num1,num2,num1+num2))

Variables num1 and num2 prompt the user for a number. The print function then displays the answer and equation.

Answer:

Total number of character comparison = 43

Explanation:

Using the Brute force algorithm

The string of n characters is known as text, and the string of m characters is known as the pattern.

From the given information:

The text (n)=THERE_IS_MORE_TO_LIFE_THAN_INCREASING_ITS_SPEED

The pattern (m) = GANDHI

The total no of characters that we have in the text = 47

The total number of characters in pattern = 6

For a brute force algorithm;

Since; the first character of the pattern does not exist in the text, then the number of trials made can be attempted can be expressed as = n – m + 1

= 47 – 6 + 1

= 47 – 5

= 42

Thus; the algorithm will attempt the trial 42 times.

Now, for loop in the algorithm to run 42 times, the G in the pattern will have to align against the for T in the text, and in the last case, it will be aligned against the last space.

On each attempted trial, the algorithm will make one unsuccessful comparison.

However, at the trial at which the G in the pattern Is aligned with the G in the text, there will be two successful comparisons.

Hence, we can calculate the total number of character comparison as follows:

Total number of character comparison = [tex]\mathbf{\bigg ( ( 42 - (no. \ of \ failed \ comparison) ) \times 1 + (1 \times ( Two \ successful \ comparisons) ) \bigg ) }[/tex]

Total number of character comparison = ( (( 42 – 1) × 1 ) + ( 1 × 2) )

Total number of character comparison = 41 + 2

Total number of character comparison = 43

Answer:

Validation rule in a field will restrict the input from user into a field or table

Explanation:

Validation is used in database to ensure that the correct data type is entered in the fields. When validation is applied to a field, a message is displayed to the user if he enters the data of wrong datatype.

Hence,

Validation rule in a field will restrict the input from user into a field or table

Answer:

true

Explanation:

A database has one physical schema and one conceptual (logical) schema but many external schemas (views): a. True.

A database refers to a structured (organized) collection of data that are stored on a computer system and usually accessed in various ways such as electronically.

In database management, a database schema can be defined as a structure which is typically used to represent the logical design of the database. Thus, it denotes how data are stored (organized) and the relationships existing in a database management system (DBMS).

Generally, there are two (2) main types of a database schema and these include;

However, there are multiple number of external schemas (views) for each database because it is what an end user is interested in.

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Answer:

1. raster and vector

2. Resolution

3. Color depth

4. Forms, Shapes

5. Tone

6. Balance

7. White space

8. Aspect ratio

9. Focus

10. cropping

Hope this helped :)

Answer:

a) "Quit"  

c) "Q only

Explanation:

Given

String s = "Go";

while ((!s.equals("q"))&& (!s.equals("")))  {

System.out.println("In loop");

s = scnr.next();

}

Required

What input causes another execution

Analyzing the while condition

while ((!s.equals("q"))&& (!s.equals("")))  

This can be split into:

!s.equals("q")) && (!s.equals(""))

Meaning

When s is not equal to "q" and when s is not an empty string

In other words,

the loop will be executed when user input is not "q" and user input is not empty.

So, from the list of given options: The loop both will be executed when:

a) Input is "Quit"

c) Input is Q only

Input of q will terminate the loop, hence b and d are incorrect

The phrase “I suppose” helps Roosevelt create a humble kind of tone

for better understanding, lets understand what a humble tone means

From the above, we can therefore say that the answer The phrase “I suppose” helps Roosevelt create a humble kind of tone is correct

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Answer:

it's humble

Explanation:

Answer:

search more sa google

The Answer Of This Question Is C2C.

Answer:

C: AutoPlay

Explanation:

it is C because the definition of AutoPlay is: a functionality that causes a video, audio file, etc. to play automatically, without action from a user.

Answer:

left click, then click save image

Explanation:

Answer:

first try to do it on kami, then on Google docs, then on doc-hub

Answer:

The Answer is D

Answer:

Restart your WiFi!

Explanation:

It happened to me I did that and it fixed it

Answer:

Explanation:

Function telToNumbers with one parameter of a String input for the telephoneNumber

String var newTelephoneNum;

for loop through telephoneNumber {

Char var currentChar = current Character in the loop;

currentChar to lower Case;

Switch statement (currentChar) {

 case "a" or "b" or "c" : newTelephoneNum += "2"; break;

 case "d" or "e" or "f" : newTelephoneNum += "3"; break;

 case "g" or "h" or "i" : newTelephoneNum += "4"; break;

 case "j" or "k" or "l" : newTelephoneNum += "5"; break;

 case "m" or "n" or "o" : newTelephoneNum += "6"; break;

 case "p" or "q" or "r" or "s" : newTelephoneNum += "7"; break;

 case "t" or "u" or "v" : newTelephoneNum += "8"; break;

 case "w" or "x" or "y" or "z" : newTelephoneNum += "9"; break;

 default : newTelephoneNum += currentChar; break;

 }

}

print newTelephoneNum;

Answer: C

Explanation:

Answers with Explanations:

5 Products/Services Needed by People These Days.

1. Face mask/Surgical mask - The use of face mask is considered a common sense. Most countries mandate people to wear this every time they go out.

2. Food Delivery service - To prevent contracting corona virus, most people prefer to have their food delivered than to dine out. This increases the demand for the food delivery service.

3. Alcohol - It has become an important habit recently to disinfect hands and other things. This is also being advertised on TV, thus many people carry it along with them.

4. Infrared Forehead Thermometer - Many establishments use this in order to quickly check the temperature of people entering.

5. Internet service - The increase use of this service is due to online learning and remote-working situations.

We all need different product and services. In this pandemic time, the products/services needed by the people are;

A product is known to be a tangible goods that one buys or acquisition,  consume, etc.  Service is known as an intangible item.

A key reason for any new development is to give the best or new value to the customer and in this present time. Helping those who have lost their jobs, having mask mask,  etc., readily available will go a long way to help.

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Answer: B C

Explanation:

Answer:B,C,D

Explanation:

I think it's B but im not 100% sure sorry if im wrong

Answer: C

Explanation:

def func():  

 total = 0

 while True:

   pet = input("What pet do you have? ")

   if pet == "rock":

     return

   total += 1

   print("You have a {} with a total of {} pet(s)".format(pet, total))

func()

We wrapped our code in a function so that whenever the user enters rock, we can simply return and exit the function. If you have any other questions, I'll do my best to answer them.

Answer:

Explanation:

human resources

hoped this helped

Answer:

D

Explanation:

Answer:

B. If a is less than b, then set small to a, else set small to b.

If c is less than small, then set small to

Explanation:

Plato correct!!