Compare the value of the following expression with zero. 5a^3b^2/a+b, where a<0, b<0

Answers

Answer 1

Answer:

The given expression will be greater than zero.

Step-by-step explanation:

If a < 0 and b < 0, then 5a^3 is < 0 (5a^3) is negative;

but b^2 is > 0.

Then (5a^3)*(b^2) < 0

and if we divide this quantity by a + b (which is negative), the end result will be > 0.


Related Questions

The graph below shows the solution set of which inequality?

Answers

[tex]\Large \boldsymbol{} \pmb {Answer: |x|<6}[/tex]

Step-by-step explanation :

[tex]\displaystyle \Large \boldsymbol{} |x|< 6 =>{ \left \{ {{\!\!\!x< 6} \atop {x> -6}} \right. } => \boxed{x \in (-6 ; 6 )} \ \ right[/tex]

find the missing side.​

Answers

Answer:

I htink x ≈ 8

Step-by-step explanation:

Answer:

X is approximately 7.8.

Step-by-step explanation:

You can use SOH-CAH-TOA to help figure out what function (sin, cos, tan) you need to use in order to figure out the missing side.

For this one, we can see the angle is pointing to the opposite side (x length), and we have been given the hypotenuse (18). So we want to use the sin function.

[tex]sin\ (angle)=\frac{opposite}{hypotenouse}[/tex]

[tex]sin (26)=\frac{x}{18}[/tex]

[tex]0.438=\frac{x}{18}[/tex]

[tex]7.890... = x[/tex]

Using Pythagorean theorm, you can figure out the other side if need be :)

For reference:

[tex]sin (angle)=\frac{opposite}{hypotenuse}[/tex]

[tex]cos(angle)=\frac{adjacent}{hypotenuse}[/tex]

[tex]tan(angle)=\frac{opposite}{adjacent}[/tex]

URGENT PLEASE HELP. In the triangles below, DF MN, DG MP, D P. Can you prove that DFG MNP? Explain your answer. (15 points)

Answers

Answer:

FDG=NMP

Step-by-step explanation:

You can see below that the bases DG and MP are equal, and one of the saides DF and NM are equal, and D=P, so the triangles are the same, you can also see the triangles are isosceles, so they are the same since NM=FD=FG=NP and FD=NM is shown in the picture

On another map, the distance between Saugerties and
Kingston is 2 inches. What would the distance from
Saugerties to Catskill be on this map?

Answers

Answer:

10miles

Step-by-step explanation:

Answer:

I have no clue what is going on wit dis g

I need help for this question 3 so can anyone help me please

Answers

Bsjsjsjssj jdjsjsjsjsks lłsskj

What is the period of the graph of y=1/2 sin (2πx) -3?
A. 1
B. 1/2
C. 3
D. 2π

Answers

Answer:

A. 1

Step-by-step explanation:

Since this graph is in the form A sin (B(x+c))+d, where

the amplitude is the absolute value of AThe period is 2pi/BPhase Shift is CMidline is y=D

Therefore, the values are

A=1/2

B=2pi

C=0

D=-3

So the period is 2pi/2pi which is 1.

Write an inequality and show on a number line all numbers:
less than 4 but greater than or equal to 0

Answers

Answer:

the inequality is 0<x<4

Step-by-step explanation:

(0,4)

Hola pordrian ayudarme con esto:
Resuelve las ecuaciones aplicando la fórmula general
a) 2xsobre2-7×+3=0
Hace mucho que ni hacia este tipo de problemas y por eso les pido su ayuda

Answers

Answer:

sorry I don't understand can somebody help him??

Find the slope of the line that passes through (-26, 9) and (32, 71).

Answers

Answer:

[tex]Slope = \frac{31}{29}[/tex]

Step-by-step explanation:

Step 1:  Define the slope formula

[tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

Step 2:  Find the slope

[tex]Slope = \frac{71-9}{32-(-26)}[/tex]

[tex]Slope = \frac{62}{58}[/tex]

[tex]Slope = \frac{31}{29}[/tex]

Answer:  [tex]Slope = \frac{31}{29}[/tex]

3/5 of 1 hour is? pls give me the answer

Answers

1hr=60min

[tex]\\ \sf\longmapsto \dfrac{3}{5}\;of\;60min[/tex]

[tex]\\ \sf\longmapsto \dfrac{3}{5}\times 60[/tex]

[tex]\\ \sf\longmapsto \dfrac{180}{5}[/tex]

[tex]\\ \sf\longmapsto 36min[/tex]

simplify
please to the end

Answers

THIS MIGHT NOT BE RIGHT CAUSE I'M SICK

• What is the smallest distance, in meters, needed for an airplane touching the runway with a velocity of 360 km/h and an acceleration of -10 m/s2 to come to rest? HELP​

Answers

Answer:

i think ..................

Step-by-step explanation:

society idsbwj ja

Please help me solve this!

Answers

Answer:

Step-by-step explanation:

Reference angle = 27

height = 2

Sin(27) = opposite / hypotenuse

hypotenuse = opposite / sin(27)

opposite = 2

hypotenuse = 2 / sin(27)

hypotenuse = 4.405

The ramp has to be 4.41 feet long.

Can someone help me here and check out the other two i have posted there both due soon and i have no clue how to do them

Answers

Answer:

Since the question doesn't mention in what tide the answer should be, I will be giving a solution to both, the high and low tide. Hope this helps :)

Step-by-step explanation:

Using a cosine function, where time is measured in hours past high

tide:  y=4cos30x + 10

Using a cosine function, where time is measured in hours past low

tide:  y = 4cos[30(x-6)]+10

An Olympic diver starts at 7.5 m above the water. During her dive, she goes
1.5
m below the water. What is the vertical distance the diver travels?

Answers

Given that an Olympic diver starts at 7.5 m above the water, during her dive, she goes 1.5 m below the water, the vertical distance the diver travels is 9 meters.

To determine what is the vertical distance the diver travels the following calculation must be performed:

The initial height must be subtracted from the final height, in order to obtain the difference between the two heights.

1.5 - (-7.5) = X1.5 + 7.5 = X9 = X  

Therefore, the vertical distance the diver travels is 9 meters.

Learn more about this topic in https://brainly.com/question/22089868?referrer=searchResults.

The vertical distance traveled by the Olympic diver is 6 m

The given parameters include:

initial position of the Olympic diver, x₁ = 7.5 m above the waterfinal position of the Olympic diver, x₂ = 1.5 m below the water

The sketch of the Olympic diver's displacement is as follows;

                                   x₁ ---------- 7.5 m

                                         |

                                         |

                                         |

                                         |

                                    ----------- water surface

                                         |

                                         ↓

                                  x₂ ------------ 1.5 m below water surface

The vertical distance from x₁ to x₂  = 7.5 m - 1.5 m = 6 m

Therefore, the vertical distance traveled by the Olympic diver is 6 m

To learn more about distance visit: https://brainly.in/question/7482539

1. In a group of 500 students, 280 like bananas, 310 like apples, and 55 dislike both the fruits.
i) Find the number of students who like both the fruits.
ii) Find the number of students who like only one fruits.
iii) Show the result in venn-diagram

Answers

Answer:

Please see the attached images

Step-by-step explanation:

Evaluate the Expression z(z-7) when z=10

Answers

Answer:

30

Step-by-step explanation:

z(z-7)

Let z= 10

10(10-7)

Parentheses first

10 (3)

Multiply

30

Answer:

[tex]\huge\boxed{\sf 30\\}[/tex]

Step-by-step explanation:

= z ( z - 7 )

Put z = 10

= 10 ( 10 - 7 )

= 10 ( 3 )

= 30

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807Peace!

if 1/a=1/b+1/c+1/d find c when a=2, b=3 and d=5

guys help me with this question please​

Answers

Answer:

c is -30

Step-by-step explanation:

I. 1/a - 1/b - 1/d = 1/c

II. 1/2 - 1/3 - 1/5 = 1/c

III. (15-10-6)/30 = 1/c

IV. -1/30 = 1/c

V. so c.value is -30

The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the common difference of the
sequence?

Answers

Answer:

53=-3+14d

56=14d

d=4 that is the common difference

Line A is represented by the following equation: X + y = 2

What is most likely the equation for line B so the set of equations has no solution?

Answers

Answer:

x+y=3

Step-by-step explanation:

For an equation to have no solution, their slope needs to be same and y intercept needs to be different,

so in this case where x+y=2

doing simply, x+y=3 makes a set of equation which has no solution, you can take any real value which is not 2

Worth 6 points please help!!

Answers

Answer:

-9

Step-by-step explanation:

The average rate of change is found by

f(5) - f(2)

------------

5-2

10 - 37

----------

5-2

-27

-----

3

-9

If x^2-ax+b and x^2-cx+d both have a factor x-m prove that m=d-b/c-a

Answers

Answer:

see explanation

Step-by-step explanation:

Given (x - m) is a factor of both then x = m make both expressions equal to zero.

m² - am + b = 0

m² - cm + d = 0

Then

m² - am + b = m² - cm + d ( subtract m² - cm from both sides )

cm - am + b = d ( subtract b from both sides )

cm - am = d - b ← factor out m from each term on the left side

m(c - a) = d - b ← divide both sides by (c - a)

m = [tex]\frac{d-b}{c-a}[/tex] ← as required

Michelle gets10rewards points for each of her purchases at Starbucks. With 500 rewards points, she can get a free smoothie. If she has 370 points saved, how many purchases will it take her to get her free smoothie?

Answers

she needs 130 points saved up

Answer:

13

Step-by-step explanation:

If $a$ and $b$ are positive integers such that $\gcd(a,b)=210$, $\mathop{\text{lcm}}[a,b]=210^3$, and $a

Answers

Answer:

[tex]a * b = 210^4[/tex]

Step-by-step explanation:

Given

[tex]a,b>0[/tex]

[tex]gcd(a,b) = 210[/tex]

[tex]lcm(a,b) = 210^3[/tex]

Required

The product of a and b --- missing from the question

To do this, we make use of the following formula:

[tex]a * b = gcd(a, b) * lcm(a, b)[/tex]

So, we have:

[tex]a * b = 210 * 210^3[/tex]

Using the product law of indices, we have:

[tex]a * b = 210^4[/tex]

This means that the product of a and b gives [tex]210^4[/tex]

9. An equation representing the height of a burning candle is H = 2(9 - 2t), where
H is the height of the candle in cm and
t is the amount of time that the candle has been burning in minutes.
How long will it take for the candle to burn down to a height of 4 cm?
a. 2 min
b. 3.5 min
C. 5.5 min
d. 7 min

Answers

Answer:

H= 4cm

we want t

4=2(9-2t)

2=(9-2t)

-7=-2t

t=3.5 minutes

HELP PLS HELP MEEEEE IM FAILING PYTHAGOREAN THEOREM

Answers

7^2 + 6^2 = h^2

49 + 36 = h^2

85 = h^2

√85 = h

h = 9.21m

Answered by Gauthmath must click thanks and mark brainliest

2x+3y=19 // 6x+2y=22​

Answers

Answer:

(2, 5 )

Step-by-step explanation:

Given the 2 equations

2x + 3y = 19 → (1)

6x + 2y = 22 → (2)

Multiplying (1) by - 3 and adding to (2) will eliminate the x- term

- 6x - 9y = - 57 → (3)

Add (2) and (3) term by term to eliminate x

0 - 7y = - 35

- 7y = - 35 ( divide both sides by - 7 )

y = 5

Substitute y = 5 into either of the 2 equations and solve for x

Substituting into (1)

2x + 3(5) = 19

2x + 15 = 19 ( subtract 15 from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

solution is (2, 5 )

am thinking of a number multiplying it by 4 then subtracting 6 the answer is greater than 14. Write the inequality

Answers

Answer:

4x - 6 > 14

Step-by-step explanation:

4x - 6 > 14

4x = 20

x = 5

Please answer this!!

Answers

Answer:

C, 5/12

Step-by-step explanation:

The tangent of an angle is defined as the side opposite to that angle divided by the side adjacent to that angle. The tangent of angle A would be equal to the value of side BC divided by side AB. The value of side BC is 5, and the value of side AB is 12. The answer is 5/12.

Answer: ∠A=[tex]\frac{5}{12}[/tex]

Step-by-step explanation:

Tangent is opposite over adjacent.

Write the equation of the line with a slope of 4 that contains the point (5, 8).

Answers

Answer:

y = 4x - 12

Step-by-step explanation:

y = 4x + b

8 = 4(5) + b

8 = 20 + b

-12 = b

[tex] \green{ \boxed{\boxed{\begin{array}{cc} \maltese \bf \: \: \: we \: know \: that \: \\ \sf \: if \: any \: equation\:of \: line \: which \: slope (m) \\ \sf \: and \: passes \: through \: (x_1,y _1) \: \: then \: its \\ \sf equation \: is \: : \\ \\ \red{ \boxed{ \bf y - y_1 = m(x - x_1)}}\bf\end{array}}}}[/tex]

Given that,

A equation of the line with a slope of m = 4 and that contains / passes through the point (5, 8).

So,

[tex] \green{ \boxed{\boxed{\begin{array}{cc} \bf \: x_1 = 5 \: \: \: \\ \bf y_1 = 8 \\ \bf \: m \: = 4 \: \: \end{array}}}}[/tex]

NOW,

The equation is :

[tex] \green{ \boxed{\boxed{\begin{array}{cc} \bf \: y - 8 = 4(x - 5) \\ \\ = > \bf \: y - 8 = 4x - 20 \\ \\ = > \pink{ \boxed{\bf\:4x - y - 12 = 0}} \end{array}}}}[/tex]

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