Choose all that apply:

1.Circle A and circle A', have the same circumference.
2.The radii of circle A and circle A', have the same lengths.
3. Points A and A', are both on the xxx-axis.
4. None of the above

Answer: a

Step-by-step explanation:

Answer:

Step-by-step explanation:

Do you mean 27 units² ?

A cube has six congruent, square faces. Area of one face = (27/6) units²

Length of one edge = √(27/6)

= √(9/2)

= √9/√2

= 3/√2

= 3√2/2 units

Answer:

(2x – 1)2 = 9

4x-2=9

4x=9+2

4x=11

x=11/4

x=2.75

Step-by-step explanation:

-x+4y= -15

-2x-3y=-8

the intersection point isn't (3,-5)

it's approximately (-1.1818 ,3.45455 )

Answer:

see below

Step-by-step explanation:

Check the solution in both equation

-x+4 = -15

-3 +4 = -15

1 does not equal -15 so it is not a solution

-2x-3y = -8

-2(3)+-3(-5) = -8

-6 +15 = -8

9 = -8

It is not a solution to either equation

9514 1404 393

Answer:

  (11, -13)

Step-by-step explanation:

If midpoint M is halfway between A and B:

  M = (A +B)/2

Then B is ...

  B = 2M -A

  B = 2(4, -9) -(-3, -5) = (8+3, -18+5)

  B = (11, -13)

Answer:

Use the midpoint formula:

[tex]midpoint=(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})[/tex]

Substitute in the values:

[tex](4, -9)=(\frac{-3+x_{2}}{2} +\frac{-5+y_{2}}{2} )[/tex]

[tex]4=\frac{-3+x_{2}}{2} \\4(2)=-3+x_{2}\\8+3=x_{2}\\x_{2}=11[/tex]      [tex]-9=\frac{-5+y_{2}}{2} \\(-9)(2)=-5+y_{2}\\-18+5=y_{2}\\y_{2}=-13[/tex]

Therefore, Point B = (11, -13)

Answer:

PW, BW,  GW, PY,  BY, GY

Step-by-step explanation:

We need to determine the sample space

pink(P), blue (B), and green (G) cards,   (W) and yellow (Y) envelopes

Each color card can match with each color envelope

Start with the white envelopes and each color card

and then the yellow envelopes with each color card

PW   BW  GW

PY  BY   GY

[tex]\begin{array}{c|c|c|c|c|c} p & q & r & p\land q & q\land \neg p & r \land q \\&&&&\\ T & T & T & T & F & T \\ T & T & F & T & F & F \\ T & F & T & F & F & F \\ T & F & F & F & F & F \\ F & T & T & F & T & T \\ F & T & F & F & T & F \\ F & F & T & F & F & F \\ F & F & F & F & F & F\end{array}[/tex]

An implication A => B is true if either A is false, or both A and B are true. So

[tex]\begin{array}{c|c|c}p\land q & (q\land\neg p) \implies (r\land q) & (p\land q) \implies \big[(q\land\neg p) \implies (r\land q)\big] \\&&\\T & T & \mathbf T\\T & T & \mathbf T\\F & T & \mathbf T\\F & T & \mathbf T\\F & T & \mathbf T\\F & F & \mathbf T\\F & T & \mathbf T\\F & T & \mathbf T\end{array}[/tex]

and the given statement is a tautology.

Answer:

The answer is "[tex]\frac{5 e^{5\sqrt{x} }}{2\sqrt{x}}[/tex]".

Step-by-step explanation:

Given:

[tex]y = e^{{\color{\red}5}\sqrt{x}}[/tex]

let

[tex]\to t= 5\sqrt{x}\\\\\frac{dt}{dx}= 5 \frac{1}{2\sqrt{x}}\\\\\frac{dt}{dx}= \frac{5}{2\sqrt{x}}\\\\[/tex]

and

[tex]\to y=e^t\\\\\to \frac{dy}{dt}=e^t\\[/tex]

[tex]\to \frac{dy}{dt}=e^{5\sqrt{x} }\\[/tex]

So,

[tex]\to \frac{dy}{dx}= \frac{dy}{dt} \times \frac{dt}{dx}[/tex]

         [tex]=e^{5\sqrt{x} }\times \frac{5}{2\sqrt{x}}\\\\= \frac{5 e^{5\sqrt{x} }}{2\sqrt{x}}[/tex]

OR

[tex]\to g(x) = 5\sqrt{x} \\\\\to f(x) = e^{(x)}\\\\[/tex]

Derivate:  

[tex]\to f''g' = \frac{e^{(5\sqrt{x})}5}{(2\sqrt{x})}[/tex]

Answer:

Step-by-step explanation:

When the quadrilateral JKLM is rotated - 270° about the origin then the image of rotated quadrilateral is shown below.

"It is a transformation in which the object is rotated about a fixed point. "

For given question,

Quadrilateral JKLM is rotated - 270° about the origin.

This means, quadrilateral JKLM is rotated 270° clockwise about the origin.

We know, if point P(x, y) is rotated 270° clockwise or 90° anticlockwise then  the coordinated of rotated point would be (-y, x).

From figure, the coordinates of the quadrilateral JKLM are:
J = (3, 3)

K = (5, -5)

L = (-3, -7)

M = (3, -3)

After rotating -270° about the origin the coordinates of the quadrilateral would be,

J' = (-3, 3)

K' = (5, 5)

L' = (7, -3)

M' = (3, 3)

And the image of the rotated quadrilateral J'K'L'M' is shown below.

Therefore, when the quadrilateral JKLM is rotated - 270° about the origin then the image of rotated quadrilateral is shown below.

Learn more about rotation here:

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Answer:

Commission Received refers to a percentage amount received by the company (or) an individual on the total sales incurred. It is an indirect income/revenue recorded on the credit side of profit and loss account.

Step-by-step explanation:

mark me brainliest if my answer is correct

Answer:

(-8/7 ; 5/7)

Step-by-step explanation:

5t + 1/2s = 3 - - - (1)

3t - 6s = 9 - - - - - (2)

Multiply (1) by 12 and (2) by 1

Add the result to eliminate s

60t + 6s = 36

3t - 6s = 9

____________

63t = 45

t = 45 / 63

t = 5/7

Put t = 5/7 in either (1) or (2) to obtain the value of s

3(5/7) - 6s = 9

15/7 - 6s = 9

-6s = 9 - 15/7

-6s = (63 - 15)/7

-6s = 48/7

s = 48/7 * - 1/6

s = - 8/7

answer=

X<-4

.............................................................

Answer:

[tex]\displaystyle \int {84} \, dx = 84x + C[/tex]

General Formulas and Concepts:

Calculus

Integration

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int {84} \, dx[/tex]

Step 2: Integrate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Integrations

Answer:

Approximately 68% of people have IQs between 84 and 116.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 100, standard deviation of 16.

Percentage of people with IQs between 84 and 116.

84 = 100 - 16

116 = 100 + 16

So within 1 standard deviation of the mean, which, by the Empirical Rule, is approximately 68%.

9514 1404 393

Answer:

  108.8 km/h at 84.3°

Step-by-step explanation:

The law of cosines can be used to find the resultant ground speed. In the attached diagram, the length of interest is OR. It will be found as ...

  OR² = OP² +PR² -2·OP·PR·cos(P)

  OR² = 130² +26² -2×130×26×cos(32°) ≈ 11843.19

  OR = √11843.19 ≈ 108.8

__

The angle POR can be found from the law of sines.

  sin(POR)/PR = sin(OPR)/OR

  sin(POR) = PR/OR×sin(32°) ≈ 0.12660

  ∠POR ≈ arcsin(0.12660) ≈ 7.27°

Then the bearing of the ground track of the airplane is 77° +7.27° = 84.27°.

The airplane is traveling at about 108.8 km/h on a bearing of 84.3°.

Answer:

at most

Step-by-step explanation:

The sample drawn from the population is a relative representation not the absolute representation. The box has 100 tickets in it and sample of tickets is selected to identify difference between sample sum and 252. The at most value for the sample sum can be 278.32 and value cannot exceed beyond this.

Answer:

40

Step-by-step explanation:

1+2+3=6

1/6×120=20

2/6×120=40

3/6×120=60

Answer:

rectangle

Step-by-step explanation:

Perimeter of 20 feet

rectangle (square is technically a rectangle):

sides 5 and 5

5*5 = 25ft²

Circle:

20/(2π) = 3.18309...

3.1809...²π = 31.831ft²

Max area of rectangle (i.e. square) has a smaller area than a circle.

Answer:

y=0.5x + 5

Step-by-step explanation:

The points are (0,5) and (-10,0)

to find the slope do

0-5/-10-0 = 5/10 = 1/2 = 0.5

next plug one of the points into point slope formula

y-y1=m(x-x1)

lets use the point (-10,0)

y1=0

x1= -10

m= 0.5

y-0=0.5(x- -10)

y = 0.5(x+10)

distribute the 0.5

y=0.5x+5

Markdown is the difference (at sale) between the price an item is placed at for retail sale, and the actual price the item is sold

The correct option is; B. GHC 50.00

The reason for choosing option B is as follows;

The known parameters

The percentage by which damaged items are marked down = 25% to 40%

The percentage markdown offered by the newspaper coupon = 10%

The original marked price of the item = GHC 100

Strategy:

Apply the damaged items and coupon markdown percentages to the original marked price of GHC100 sum the results to find the total markdown

Solution:

Markdown due to damage:

Given that the item is damaged, to have the lowest price, we apply the largest markdown of 40%;

40% is removed from the price to which the item marked down due to damage, as follows;

The markdown due to damage = 40/100 × GHC 100 = GHC 40

Markdown due to Coupon Holder:

The markdown the coupon holder is to get = 10% off the retail price

Given that the damage is not mentioned in the newspaper, we have;

∴ The markdown the coupon holder is to get = 10/100 × GHC 100 = GHC 10

Total markdown:

The total markdown is therefore equal to GHC 40 + GHC 10 = GHC 50

The Lowest Price of A Damaged Items marked GHC100:

The lowest price of the item = Original price - Maximum markdown

The lowest price of the item = GHC 100 - GHC 50 = GHC 50

Learn more about markdown and markup concepts here;

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Answer:

18

thả 5 sao nha.....

Step-by-step explanation:

..................

Answer:

A is the correct answer :)

Answer:

A

Step-by-step explanation:

checking if A is correct, if we get x as 76 then it is correct

if 5miles = 8 kilometers

47.5 miles= x

that is

5=8

47.5=x

cross multiply

5x=380

x=380/5

x=76

there fore A is correct

checking if B is correct, if we get x as 86 then it is correct

if 5miles = 8 kilometers

52.5 miles= x

that is

5=8

52.5=x

cross multiply

5x=420

x=420/5

x=84

therefore B is incorrect

checking if C is correct, if we get x as 34 then it is correct

if 5miles = 8 kilometers

22.5 miles=x

that is

5=8

22.5=x

Cross multiply

5x=180

x=180/5

x=36

therefore C is incorrect

checking if D is correct, if we get x as 22 then it is correct

if 5miles = 8 kilometers

12.5miles = x

that is

5=8

12.5=x

5x=100

x=100/5

x= 20

Answer:

absolutely B

Step-by-step explanation:

A is one type of tax

C) gross pay includes taxes, social security and something else

D) deductions are the type of fee

and B is the amount of money that he received

Alejandro should look at Net pay on his paystubs the answer is Net pay option (b) is correct.

It is defined as the tax rate applied on the solely earned money by a single entity.

It is given that:

Alejandro wants to determine how much money he made in the last month after taxes, social security, and Medicare were taken out of his paycheck.

The options are:

A) Federal tax amount

The Federal tax amount is one type of tax.

C) Gross pay

The gross pay includes taxes, social security, and other charges

D) Deductions

The deductions are the type of fee or negative amounts.

Alejandro should look at Net pay on his paystubs.

Thus, Alejandro should look at Net pay on his paystubs the answer is Net pay option (b) is correct.

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Answer:

The answer is "[tex]7.21 \times 10^{37}[/tex]".

Step-by-step explanation:

[tex]\to ^{n}_{C_r}=\frac{n!}{r!(n-r)!}[/tex]

       [tex]=^{66}_{C_{33}} \times ^{66}_{C_{22}} \times ^{55}_{C_{1}} \\\\=\frac{66!}{33! (66-33)!} \times \frac{66!}{22! (66-22)!} \times \frac{55!}{1! (55-1)!}\\\\=\frac{66!}{33! (33)!} \times \frac{66!}{22! (44)!} \times \frac{55!}{1! (54)!}\\\\=\frac{66!}{33! (33)!} \times \frac{66!}{22! (44)!} \times \frac{55\times 54!}{1! (54)!}\\\\=\frac{66!}{33! (33)!} \times \frac{66!}{22! (44)!} \times 55\\\\= 7219428434016265740 \times 182183167981760400\times 55\\\\[/tex]

       [tex]= 7.21 \times 10^{18} \times 1.82\times10^{17}\times 55\\\\= 7.21 \times 10^{35} \times 1.82\times 55\\\\=721.721 \times 10^{35}\\\\=7.21\times 10^{37}[/tex]

Answer:

C. [tex]5\frac{1}{4}[/tex]

Step-by-step explanation:

[tex]1\frac{1}{2}[/tex] cups of milk makes 1 quart of yogurt.

x cups  of milk makes [tex]3\frac{1}{2}[/tex] quarts of yogurt.

[tex]\frac{milk}{yogurt}= \frac{1\frac{1}{2} }{1} =\frac{x}{3\frac{1}{2} }[/tex]

Cross multiply.

[tex]1\frac{1}{2}[/tex] × [tex]3\frac{1}{2}[/tex] = 1 × x

You get:

[tex]5\frac{1}{4} =x[/tex]

I hope this helps!

pls ❤ and mark brainliest pls!

the function is given, and it's value is where the object is ("how far to the right").

so as long as it rises (going more right), this will be apply.

in the screenshot I graphed the function. of course t is graphed as x and "along the x-axis" is graphed as y, but the pattern is the same anyways.

for the first 1.25 seconds the object goes to the left, and after that always to the right.

since we look at t to calculate x, t effectively takes the role of the important variable that is normally given to x. the calculation pattern are just the same. so let's find the lowest point of this function by calculating it out.

x(t) = 2t² – 5t – 18

x'(t) = 4t -5

x'(t) = 0

0 = 4t -5

5 = 4t

1.25 = t

plugging it into the second derivative

x''(t) = 4

x''(1.25) = 4

it's positive, so at t=1.25 there is a low point

(of course the second derivative is constant anyways.)

the object is traveling toward the right

the object is traveling toward the rightfor t > 1.25

The object is moving to the right, for t > 1.25, the object is moving in a rightward direction.

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

We have:

An object travels along the x-axis so that its position after t seconds is given by:

x(t) = 2t² – 5t – 18

x'(t) = 4t - 5

x'(t) = 0

4t -5 = 0

t = 5/4 = 1.25 seconds

x''(t) = 4

x''(1.25) = 4

x''(1.25) > 0

At t = 1.25 the object travels at a low point.

Thus, the object is moving to the right, for t > 1.25, the object is moving in a rightward direction.

Learn more about the inequality here:

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