Answers
Answer
As the angle of incidence increases in Figure 2.8, a point is finally reached where the refracted ray does not emerge at the second layer but lie along the interface. This particular angle of incidence at which the angle of refraction is 90° and the refracted ray lies along the interface is known as the critical angle. At and beyond the critical angle, there is no transmitted ray and therefore a very high reflected ray will be recorded .
Therefore,
sinθisin90=Vp1Vp2
But, sin 90 = 1.
At critical angle,
sinθcritical=Vp1Vp2
A critical refracted wave travels along the interface between layers and is refracted back into the upper layer at the critical angle. The waves refracted back into the upper layer are called head waves or first-break refractions because at certain distances from a source, they are the first arriving energy. Recorded first-break refraction is shown in Figure 2.10.
Note that these first-break refractions can give us important information about the shallow velocities on land seismic data.
Note also that seismic data are acquired in such a way that reflections from horizons of interest are in the pre-critical region, even at the farthest offset in the data.
In reality, part of the seismic energy arriving at an interface is transmitted and refracted, and another part of the energy is reflected at that same interface. Given that there are many reflectors in the subsurface, there will be many paths from source to receiver, each of them with a different travel time. The proportion of energy reflected depends on the material properties of the two bounding layers and on the angle of incidence
Related Questions
On a frictionless air track, a 0.30 kg glider moving at 0.40m/s to the right collides with a stationary 0.80kg glider moving at 0.15 m/s to the left. The collision is cushioned by a bumper made of perfectly elastic spring steel. a. What is the velocity of each glider after the collision? b. What is the minimum amount of total kinetic energy during the collision? c. Where is the missing energy?
Answers
Answer:
Explanation:
It is the case of perfectly elastic collision . So we shall apply formula of velocity after collision as follows .
Let m₁ and m₂ be the mass colliding with velocity u₁ and u₂ and their velocity become v₁ and v₂ after collision .
[tex]v_1=\frac{(m_1-m_2)u_1 }{m_1+m_2)} +\frac{2 m_2u_2}{(m_1+m_2)}[/tex]
Putting the values
[tex]v_1=\frac{ (.30-.80).40 }{( .30+.80)} +\frac{2\times .80\times(-.15) }{(.30+.80 )}[/tex]
= - 0.4 m /s
So direction of .30 kg mass will be reversed .
[tex]v_2=\frac{ ( m_2-m_1) u_2 }{( m_1+m_2)} +\frac{2 m_1u_1}{(m_1+m_2)}[/tex]
putting the values
[tex]v_2=\frac{ ( .80-.30)(-.15) }{( .30+.80)} +\frac{2 \times.30\times.40}{(.30+.80)}[/tex]
= .15 m /s
The direction of .80 kg will become from left to right ie its direction will be reversed .
b ) Minimum amount of kinetic energy will be at the position when they move with common velocity
common velocity
v = .3 x .4 - .8 x .15 / (.3 + .8)
= 0
c )
Missing energy is stored as elastic potential energy in the spring .
solve 1 for x if a=-9.8, v=2.7, and t= 35
Answers
Answer:
6097 = x
Explanation:
x = VT + at²/2
x= 2.7 * 35 + 9.8 * (35)²/2
x=6097
Communication satellites are often put in a geo-synchronous orbit, meaning they have an orbital period of 24 hours and stay over the same spot above the equator at all times. Given that the Earth has a mass of 5.97 x 1024 kg and a radius of 6.37 x 106 meters, determine the following: a. What is the orbital height of the satellite relative to the surface of the Earth
Answers
Answer:
h = 35857 km
Explanation:
A geosynchronous orbit can be defined as circular orbit which lies on the Earth's equatorial plane and follows the direction of the Earth's rotation in a period that's equal to the Earth's rotational period and thereby appearing motionless, at a fixed position in the sky relative to the ground observers.
We are given;
Radius of earth(R) = 6.37 x 10^(6) m
Mass of earth (Me) = 5.97 x 10^(24) kg
Gravitational constant = 6.67 × 10^(-11) m³/kg.s²
The earth has a rotational period of 24 hours per day. This gives in seconds
T = 24 × 60 × 60
T = 86400 s
Let's make the height of the orbit from Earth's surface to be h
Also, let ω be the uniform angular velocity in rad/s with which the satellite rotates in the geosynchronous orbit
Now, equating the centripetal force with the gravitational force gives us;
mω²(R + h) = G•Me•m/(R + h)²
m will cancel out. Also ω can be written as 2π/T
Thus,we now have;
(R + h) = ∛(G•Me•T²/(4π²))
Plugging in the relevant values, we have;
(R + h) = ∛(6.67 × 10^(-11) × 5.97 x 10^(24) × 86400²/(4π²))
(R + h) = 42227 Km
Since R = 6.37 x 10^(6)m = 6370 km
Thus;. h = 42227 - 6370 = 35857 km
an object is +2 m from the reference point. the object starts from rest it travels for 3 seconds and has a final position of -16 m. what is the acceleration of the object?
Answers
Answer:
Solution
Given:
initial velocity (u)=0m/s (because an object
starts from the rest)
time (t)=3sec
diatance travelled(s)=14m(16-2=14)
acceleration (a)=?
Now,
According to the formula
s=ut+1/2at^2
or,14 =0×3+1/2×a×3^2
or, 14=0+a/2×9
or, 14=9a/2
or, 9a=28
or, a=28/9
or, a=3.1 m/s^2
Therefore, the acceleration of the object is 3.1m/s^2 ans.
A copper-nickel alloy of composition 50 wt% Ni-50 wt% Cu is slowly heated from a temperature of 1200°C (2190 °F). (a) At what temperature does the first liquid phase form? (b) What is the composition of this liquid phase? (c) At what temperature does complete melting of the alloy occur? (d) What is the composition of the last solid remaining prior to complete melting?
Answers
Answer:
HELLO BELOW IS THE ATTACHED DIAGRAM USED TO ANSWER YOUR QUESTION AS IT WAS MISSING
A) 1270⁰c
B) 65%
C) 1320⁰c
D) 62%
Explanation:
Nickel alloy composition : 50 wt% Ni - 50 wt%
initial temperature = 1200⁰c = 2190⁰F
A) The temperature at which the first liquid phase form
from the attached diagram the temperature at which the first liquid if formed is 1270⁰c ( at point 2 )
B ) The composition of this liquid phase ( THE FIRST LIQUID )
the composition is found at point 3
wt % of Nickel = 35%, wt% of copper = 100 - 35 = 65%
C ) The temperature at which the alloy melts completely
from the attached diagram the temperature = 1320⁰c ( point 4 )
D) The composition of the last solid remaining prior to complete melting
this can be gotten at point 5 and calculated as
wt % of Ni = 62%
wt % of Cu = 100 - 62 = 38%
If the boy on the bicycle in the preceding problem accelerates from rest to a speed of 10.0 m/s in 10.0 s, the angular acceleration of the tires is:_______
Answers
Answer:
The angular acceleration is 3.33 rad/s²
Explanation:
Here is the preceding problem as well as the given problem:
A boy rides his bicycle 2.00 km. The wheels have radius 30.0 cm. What is the total angle the tires rotate through during his trip?
21.
If the boy on the bicycle in the preceding problem accelerates from rest to a speed of 10.0 m/s in 10.0 s, what is the angular acceleration of the tires?
Explanation:
To determine the angular acceleration, we will first find the linear accelerationFrom one of the equations of kinematics for linear motion
v = u + at
Where v is the final speed
u is the initial speed
a is the linear acceleration
and t is time
From the question, the boy starts from rest, hence,
u = 0.0 m/s
v = 10.0 m/s
t = 10.0 s
a = ??
From, v = u + at
a = [tex]\frac{ v - u}{t}[/tex]
a = [tex]\frac{10 - 0}{10}[/tex]
a = 1 m/s²
Now, for the angular acceleration, [tex]\alpha[/tex]
The relationship between linear acceleration, a and angular acceleration, [tex]\alpha[/tex] is
a = [tex]\alpha[/tex]r
where r is radius
From the previous question, r = 30.0cm = 0.3m
From the equation, a = [tex]\alpha[/tex]r
[tex]\alpha[/tex] = a / r
[tex]\alpha[/tex] = 1 / 0.3
[tex]\alpha[/tex] = 3.33 rad/s²
A speed that will permit a train or other equipment to stop within one half the range of vision short of a train, engine, railroad car, man or equipment fouling a track, stop signal or a derail or switch lined improperly. When a train or engine is required to move at restricted speed, the crew must keep a lookout for a broken rail and not exceed 20 mph:__________
Answers
Answer:
This is called restricted speed
If forces acting on an object are unbalanced, the object could experience a change in ________.
Answers
Answer:
velocity
Explanation:
Unbalanced forces on an object cause it to accelerate. Acceleration is a change in velocity over time.
Answer:
a
Explanation:
none
A rifle bullet with mass 8.00 g and initial horizontal velocity 280 m/s strikes and embeds itself in a block with mass 0.992 kg that rests on a frictionless surface and is attached to one end of an ideal spring. The other end of the spring is attached to the wall. The impact compresses the spring a maximum distance of 15.0 cm. After the impact, the block moves in SHM. Calculate the period of this motion.
Answers
Answer:
0.4113772 s
Explanation:
Given the following :
Mass of bullet (m1) = 8g = 0.008kg
Initial horizontal Velocity (u1) = 280m/s
Mass of block (m2) = 0.992kg
Maxumum distance (x) = 15cm = 0.15m
Recall;
Period (T) = 2π√(m/k)
According to the law of conservation of momentum : (inelastic Collison)
m1 * u1 = (m1 + m2) * v
Where v is the final Velocity of the colliding bodies
0.008 * 280 = (0.008 + 0.992) * v
2.24 = 1 * v
v = 2.24m/s
K. E = P. E
K. E = 0.5mv^2
P.E = 0.5kx^2
0.5(0.992 + 0.008)*2.24^2 = 0.5*k*(0.15)^2
0.5*1*5.0176 = 0.5*k*0.0225
2.5088 = 0.01125k
k = 2.5088 / 0.01125
k = 223.00444 N/m
Therefore,
Period (T) = 2π√(m/k)
T = 2π√(0.992+0.008) / 233.0444
T = 2π√0.0042910
T = 2π * 0.0655059
T = 0.4113772 s
The period of the simple harmonic motion (SHM) is 0.42 s.
The given parameters;
mass of the bullet, m₁ = 8 g = 0.008 kginitial horizontal velocity of the bullet, u = 280 m/smass of the block, m₂ = 0.992 kginitial velocity of block, u₂ = 0extension of the spring, x = 15 cm = 0.15 mThe final velocity of the system after the impact is calculated as follows;
[tex]m_1 u_1 + m_2u_2 = v(m_1 + m_2)\\\\0.008(280) \ + \ 0.992(0) = v(0.008 \ + \ 0.992)\\\\2.24 = v(1) \\\\v = 2.24 \ m/s[/tex]
The spring constant is calculated as follows;
[tex]\frac{1}{2} kx^2 = \frac{1}{2} mv^2\\\\k = \frac{mv^2}{x^2} \\\\k = \frac{(0.008 + 0.992))\times 2.24^2}{(0.15)^2} \\\\k = 223 \ N/m[/tex]
The angular speed of the simple harmonic motion (SHM) is calculated as follows;
[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{223}{(0.008 + 0.992)} }\\\\\omega = 14.933 \ rad/s[/tex]
The period of the oscillation is calculated as follows;
[tex]T = \frac{2\pi }{\omega} \\\\T = \frac{2\pi }{14.933} \\\\T = 0.42 \ s[/tex]
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What is the observation and what is the inference in the following text. Explain.
The chimpanzee climbed the tall tree. The chimpanzee must be very strong,
Answers
Observation: The chimpanzee climbed the tall tree.
Inference: The chimpanzee must be very strong,
Explanation:
An inference differs from an observation because an inference is a guess or possible explanation about a phenomenon. On the other hand, an observation is a statement based on evidence gathered through the senses. In this context, the sentence that is an observation is "The chimpanzee climbed the tall tree" because this statement is based on visual evidence. Moreover, the inference is "The chimpanzee must be very strong" because this is just a guess to explain how the chimpanzee climbed up the tree.
10.Un móvil recorre 26 m en el tercer segundo de su movimiento. Determinar la velocidad inicial del móvil, si su aceleración es de 8 m/s. AYUDA POR FAVOR
Answers
Answer: La velocidad inicial es 6m/s
Explanation:
Primero escribamos las ecuaciones de movimiento:
Sabemos que la aceleración es 8m/s^2.
a(t) = 8m/s^2.
Para obtener la velocidad, tenemos que integrar sobre el tiempo:
v(t) = (8m/s^2)*t + v0
donde v0 es la velocidad inicial.
Para la posición volvemos a integrar sobre el tiempo, y tenemos:
p(t) = (1/2)*(8m/s^2)*t^2 + v0*t + p0 = (4m/s^2)*t^2 + v0*t + p0
Donde p0 es la posición inicial.
Nosotros sabemos que en el tercer segundo, el móvil recorre 26m
Esto significa que:
p(3s) - p(2s) = 26m = (4m/s^2)(3s^2 - 2s^2) + v0(3s - 2s) + p0 - p0
26m = (4m/s^2)*5s^2 + v0*1s
De aquí podemos despejar el valor de v0:
26m = 20m + v0*1s
6m = v0*1s
v0 = 6m/s
An iron ball at 40°C is dropped in a mug containing water at 40°C.
The heat will
(a) flow from iron ball to water.
(b)
not flow from iron ball to water or from water to iron ball
(c)
flow from water to iron ball
(d) increase the temperature of both
10. A wooden spoon is dipped in a cup of ice cream. Its other end
(a) becomes cold by the process of conduction.
(b) becomes cold by the process of convection
(c) becomes cold by the process of radiation.
(d) does not become cold.
Answers
Answer:
1. option a
2. option d
Explanation:
HOPE IT HELPS YOU
Which is NOT true of balanced forces?
A. Balanced forces will cause the motion of an object to
increase
B. Balanced forces are two equal forces pushing against
each other on an object,
C. Balanced forces do not cause a change in the motion of
an object
Answers
Based on its location on the periodic table, which element would be most likely to form a negative ion? A. Bromine (Br) B. Strontium (Sr) C. Potassium (K) D. Magnesium (Mg)
Answers
your answer is...
C. potassium
Suppose an experiment is designed to test the durability of batteries in different conditions. All of the batteries tested are double-A (AA) Brand X. All sets of batteries are preconditioned in different environmental conditions for exactly 168 hours (1 week).
Set 1: 0°C (freezing point of water)
Set 2: 24°C (approximately room temperature)
Set 3: 37°C (approximately body temperature)
The batteries are then continuously used to power identical mechanical drummer toys. As long as the toy keeps drumming the battery is considered functional. The drumming time for each toy is measured as an indication of battery durability. In this experiment, which condition is not controlled?
A.) temperature
B.) brand of batteries
C.) test for durability
D.) type of battery (battery size)
Answers
Answer:
I assume its c. Since its talking about testing.
Explanation:
Answer:
The answer is test of durability
Explanation:
what's the difference between force of gravity and the earth's magnetic field?
Answers
Answer:
Gravitational fields are determined only by the mass ( or mass-energy) of a body. ... magnetic fields are produced by charged particles in motion, and depend on the charge and velocity of these particles, but not on their mass. Magnetic fields are 'polar' fields with a North and South polarity.
Explanation:
Need help finding the average speed.
Answers
Explanation:
To find the average of these numbers, we just have to add the three numbers together and divide by 3.
2.07 + 0. 74 + 1.33 = 4.14. 4.14 / 3 = 1.381.09 + 1.40 + 0.31 = 2.8. 2.8 / 3 ≈ 9.3333333/ 9 1/30.95 + 1.61 + 0.56 = 3.12 / 3 = 1.040.81 + 1.89 + 1.08 = 3.78 / 3 = 1.26A ball is ejected to the right with an unknown horizontal velocity from the top of a pillar that is 50 meters in height. At the exact instant, a carriage moving on rails is also released to the right from the bottom of the pillar. Calculate the velocity with which the carriage should be released so that the ball falls in the carriage after the carriage has traveled a distance of 50 meters on the ground.
A. 12.20 meters/ seconds
B. 13.23 meters/ seconds
C. 14.30 meters/ seconds
D. 15.65 meters/ seconds**
E. 16.00 meters/ seconds
I believe D is right = 15.65m/s
Also ** on Plato
Answers
Answer:
D. 15.65 meters/ seconds**
Explanation:
You're correct. Use kinematic equation to find V_final.
[tex] {v}^{2} = {v 0}^{2} + 2a(xf - x0)[/tex]
Then use the following to find time.
[tex]t = (vf - v0) \div a[/tex]
Then 50m/3.2s = 15.65m/s
An emf of 22.0 mV is induced in a 519-turn coil when the current is changing at the rate of 10.0 A/s. What is the magnetic flux through each turn of the coil at an instant when the current is 3.70 A?
Answers
Answer:
[tex]\phi=1.56\times 10^{-5}\ Wb[/tex]
Explanation:
Given that,
Emf, V = 22 mV
Number of turns in the coil us 519
Rate of change of current is 10 A/s.
We need to find the magnetic flux through each turn of the coil at an instant when the current is 3.70 A.
Let's find the inductance first. So,
[tex]L=\dfrac{\epsilon}{(dI/dt)}\\\\L=\dfrac{0.022}{10}\\\\L=0.0022\ H[/tex]
We have,
[tex]L=\dfrac{N\phi}{I}[/tex], [tex]\phi[/tex] is magnetic flux
[tex]\phi=\dfrac{LI}{N}\\\\\phi=\dfrac{0.0022\times3.7}{519}\\\\\phi=1.56\times 10^{-5}\ Wb[/tex]
So, the magnetic flux is [tex]1.56\times 10^{-5}\ Wb[/tex].
Which of the following illustrates an increase in potential energy? Group of answer choices a wind-up toy winding down a person climbs a set of stairs an apple dropping from a tree a firecracker explodes
Answers
Answer:
A person climbs a set of stairs
Explanation:
Potential energy is said to be possessed by an object due to its position. As the height from the ground level increase, the potential energy increases. It is calculated by the below formula as :
P = mgh
Out of the given options, the option that illustrates an increase in potential energy is option (b) i.e. a person climbs a set of stairs. As he steps one stair, its position from ground increases. It means its potential energy increases.
Compare diffusion of chlorine gas into air and into vaccuum. Explain your answer
Answers
Answer:
Diffusion depends among many other things also upon the concentration gradient of the diffusing substance.For example if there are two boxes with given particles first isolated from each other and if they are bought in contact, then there is a net diffusion of particles from a box with higher concentration of particles to box with lower concentration. And also diffusion rate depends at any instant directly on the concentration difference between them at that instant.Now the vaccum is equivalent to an empty box which means with this one leads to a maximum diffusion rate when bought in contact with a box with particles because there is maximum concentration difference.That is vaccum is empty ( except for energy perturbations and a small concentration of particles which will be zero for our purpose) and any bunch of particles will find least resistance to diffuse as just outside this bunch there is ‘0' concentration of the particles.
prove p=f/a science chapter pressure
Answers
Explanation:
Let 'F' be force acting perpendicularly, 'A' be the area and 'P' be the pressure exerted.
Then,
Pressure is directly proportional to the the force acting perpendicularly i.e.
P ∝ F ............. (i)
Pressure is inversely proportional to the area on which force acts i.e.
P ∝ 1/A ........... (ii)
Combining equations (i) and (ii),
P ∝ F/A
or, P = K × F/A [where K is a constant]
If F is 1N, A is 1m² and P is 1 N/m², then K is 1.
So, P = F/A proved...
Terrestrial coordinates expanded into infinite space onto a celestial sphere is called the
A) ecliptic plane
B) galactic plane
C) equatorial coordinate system
D) terrestrial coordinate system
Answers
Answer:
The correct option is;
C) Equatorial coordinate system
Explanation:
The equatorial coordinate system is which has the most wide spread use in coordinate system for astronomy for mapping the location of celestial bodies such as stars by use of an imaginary projected celestial sphere or to rectangular coordinates with the Earth at the center. Extending the Earth's axis onto the celestial sphere is essentially the projection of the Earths axis outwards to intersect the sphere at the celestial poles.
c, 'equatorial coordinate system'
its the correct answer on the test,,, goodluckk :))!!
An electron and a proton are 6.5x10 ^ -11 m apart, find the magnitude of the electric and gravitational force between the two particles
Answers
Explanation:
The electric force is:
F = k q₁ q₂ / r²
F = (9×10⁹ Nm²/C²) (-1.6×10⁻¹⁹ C) (+1.6×10⁻¹⁹ C) / (6.5×10⁻¹¹ m)²
F = 5.4×10⁻⁸ N
The gravitational force is:
F = G m₁ m₂ / r²
F = (6.67×10⁻¹¹ Nm²/kg²) (9.11×10⁻³¹ kg) (1.67×10⁻²⁷ kg) / (6.5×10⁻¹¹ m)²
F = 2.40×10⁻⁴⁷ N
A body with an initial velocity of 10m/s has an acceleration of 8m/s^2. Determine graphically the velocity after 5 seconds, & the distance travelled in that time. Verify your answer using the equations of motion.
Answers
Answer:
From the graph, at t = 5 seconds, the velocity = 50 m/s as shown also in the above table
Please find attached the graph
Explanation:
The initial velocity of the body = m/s
The acceleration of the body = 8 m/s²
The velocity after 5 seconds can be determined graphically and by calculation as follows;
Graphically, we have the data points which can be found by the straight line relation v = u + a×t,
Where ,
a = The slope = 8 m/s²
u = 10 m/s = The y-intercept
Which gives;
v = 10 + 8 × t
The following data can be calculated for various time t;
Time, t Velocity , v
0, 10
1, 18
2, 26
3, 34
4, 42
5, 50
6, 58
From the graph, at t = 5 seconds, the velocity = 50 m/s as shown also in the above table
Please find attached the graph
By calculation, we have;
v = u + a×t
Where;
v = The final velocity
u = The initial velocity = 10 m/s
a = The acceleration = 8 m/s²
t = The time = 5 seconds
v = 10 + 5× 8 = 50 m/s.
Lyla walks three times per week for 45 minutes at a speed of 4.0 miles per hour. She wants to increase her time what should she do
Answers
Answer:
C. Walk four times per week
Explanation:
If she wants to increase her time then, she has to walk four times per week.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.
The mathematical expression for speed is given by
speed = total distance /Total time
As given in the problem Lyla walks three times per week for 45 minutes at a speed of 4.0 miles per hour. She must walk four times a week if she wants to extend her time.
Thus, the correct answer is option C.
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The question is incomplete, the complete question is,
Lyla walks three times per week for 45 minutes at a speed of 4.0 miles per hour. She wants to increase her time. What should she do?
A. Walk at 4.5 miles per hour.
B. Walk for 50 minutes.
C. Walk four times per week.
D. Walk up and down more hills.
I have this question where I think the answer is "directed north of east," but apparently it is not. Can someone explain: vectors v1 andv2 shown below have equal magnitudes. the vectors represent the velocities of an object at times t1, and t2, respectively. the average acceleration of the object between time t1 and t2 was...
Answers
Answer:
North of west
Explanation:
Acceleration is the change in velocity over change in time.
a = Δv / Δt
The x component of the acceleration is:
aₓ = (0 − v₁ₓ) / (t₂ − t₁)
aₓ = -v₁ₓ / (t₂ − t₁)
aₓ < 0
The y component of the acceleration is:
aᵧ = (v₂ − v₁ᵧ) / (t₂ − t₁)
aᵧ > 0
Therefore, the acceleration points northwest.
The average acceleration of the object between time t1 and t2 was directed north of west.
What is Vector?
A quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude.Here , the velocities are V1 and V2.V1 has two components , one in X direction Vx and other is in Y direction Vy.Now . acceleration = change in velocity with respect to time , i.e.a = v/t
Now, The x component of the acceleration is:
aₓ = (V2 − V1x) / (t2 − t1)
aₓ = -V1x/ (t2 − t1)
Because the x component of V2 is 0.
aₓ < 0
Similarly, The y component of the acceleration is:
aᵧ = (v₂ − v₁ᵧ) / (t₂ − t₁)
aᵧ > 0
Thus, The average acceleration of the object between time t1 and t2 was directed north of west.
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what does grit mean in psychology
Answers
Answer:
The meaning of grit in psychology is a positive, non-cognitive trait based on an individual's perseverance of effort combined with the passion for a particular long-term goal or end state.
Explain what happens to the sound waves when a singer hits the high pitched notes during the National Anthem. Be sure to use the terms amplitude and frequency in your answer.
Answers
Answer: The frequency increases as the pitch increases, and the amplitude increases as the volume increases
Explanation:
Waves have the property of:
v = f*λ
where v is the speed of the wave (which is almost constant for soundwaves, v = 340 m/s)
f is the frequency of the wave, and λ is the wavelength.
Now, we know that when the pitch of a note increases, also does the frequency of the soundwave (so the wave oscillates faster).
Now, we also want to include the amplitude of the soundwave in this.
The amplitude is related to the volume of the soundwave (actually is related to the energy, and as higher is the energy, more "loud" is the sound).
As the high pitch part is usually "louder", we can assume that we have an amplitude increase.
Then the answer would be:
"The frequency increases as the pitch increases, and the amplitude increases as the volume increases"
observe the virual skateboarder coming down the hill and over the ramp describe how each of newton’s laws of motion can be observed in this action you can choose the dry wet or muddy conditions or some combination of these
Answers
Answer:
first part the skater goes down a constant slope ramp, initially he has Newton's second law
pply Newton's third law, the normal is the reaction to the support of the body on the surface
the ramp shoots off. axis becomes zero and therefore with Newton's first law its speed
Explanation:
It is the description of this movement let's write Newton's laws.
* The first law that a body goes at constant speed or zero if the sum of the external forces is zero
* the second law is F = m a
* The third law states that the forces act in pairs of equal magnitude and opposite direction, one applied to each body.
Let's apply these laws to our case
In the first part the skater goes down a constant slope ramp, initially he has Newton's second law when he accelerates from the initial velocity of zero to a terminal velocity.
The expression for this is
Wₓ - fr = ma
W sin θ - μ W cos θ = m a
W = mg
g (sin θ - μ cos) = a
the value of the coefficient of kinetic friction depends on the condition of the surface, dry, wet or muddy
This is Newton's second law
On the Y axis, which is perpendicular to the ramp we have
N- [tex]W_{y}[/tex] = 0
If we apply Newton's third law, the normal is the reaction to the support of the body on the surface, note that it can be different from the weight.
In the second part when he is on the ramp.
In the ramp the skater enters with a speed v, suppose that the ramp has an incline so that the skater can jump, in this case the angle is positive with respect to the axis x
In this case the analysis is similar to the previous one
Newton's second law gives the acceleration of the skater, who when he reaches the end of the ramp shoots off.
At this point the force in the x (horizontal) axis becomes zero and therefore with Newton's first law its speed this axis remains constant and the force in the y axis is the force of gravity and has an acceleration that changes if velocity according to Newton's second law
Answer:look at explanations
Explanation:
