calculate the expected value e(x) of the given random variable x. x is the number of tails that come up when a coin is tossed 10 times. e(x)

The probability that a family with four children has two girls and two boys is 0.3734, or approximately 0.3734 rounded to four decimal places. We can solve it in the following manner.

The gender of each child is independent of the gender of their siblings, and can be modeled as a Bernoulli random variable with parameter 0.49 for female and 0.51 for male. Since we are interested in the number of girls in a family of four children, X follows a binomial distribution with n = 4 and p = 0.49.

The probability of having exactly 2 girls and 2 boys can be calculated using the binomial probability mass function:

P(X = 2) = (4 choose 2) * 0.49² * 0.51²

= 6 * 0.2401 * 0.2601

= 0.3734

Therefore, the probability that a family with four children has two girls and two boys is 0.3734, or approximately 0.3734 rounded to four decimal places.

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The area of the surface obtained by rotating the curve about the x-axis.

y = X²⁾⁴- ln x is 2.8.

The area of ​​a sphere is defined as the area covered by its outer surface in three-dimensional space. A sphere is a three-dimensional solid that is circular in shape, like a circle.

Based on the Question:

Knowing the area of ​​a solid obtained by rotating a curve governed by the function f(x) around the y-axis, where a ≤ x ≤ b, is represented by a single integral given below:

Surface Area = [tex]2\pi \int\limits^b_a {f(x)\sqrt{1+f(x')^2} } \, dx[/tex]

Consider the curve equation y(x) where 1 ≤ x ≤ 2 is shown below.

        [tex]y(x) = \frac{x^2}{4} -\frac{ln x}{2}[/tex]

Now,

Derivations the above equation:

   [tex]y'(x) =\frac{d}{dx} {\frac{x^2}{4} -\frac{ln x}{2} }[/tex]

⇒ [tex]y'(x)=\frac{x}{2} -\frac{1}{2x}[/tex]

⇒ [tex]y'(x) = \frac{x^2-1}{2x}[/tex]

Calculate the numerical value of the obtained area value to obtain the desired result.

Surface area = 5.30144 - 2.55493

                      = 2.74651 ≈ 2.8

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Answer:

In mathematics, an inequality is a statement that compares two values, indicating that they are not equal, and specifies the relationship between them. In other words, an inequality expresses a relative difference between two values or quantities, rather than an exact equality.

There are different types of inequalities, but the most common ones involve comparisons between numerical values or algebraic expressions using inequality symbols, such as:

Greater than: x > y (read as "x is greater than y")

Less than: x < y (read as "x is less than y")

Greater than or equal to: x ≥ y (read as "x is greater than or equal to y")

Less than or equal to: x ≤ y (read as "x is less than or equal to y")

Inequalities can also involve multiple variables and can be used to describe ranges of values or conditions that must be satisfied. For example, x + y > 5 is an inequality that describes a region of the xy-plane where the sum of x and y is greater than 5.

Inequalities are used extensively in many areas of mathematics, including algebra, calculus, and optimization, and also have applications in other fields such as economics, physics, and engineering.

Step-by-step explanation:

Answer:

Noah would need to work 30 hours to equal Mason's earning for 40 hours

Step-by-step explanation:

Mason;

8.10 x 40 = 324

324 ÷ 10.80 = 30 hours.

Helping in the name of Jesus.

Answer:

30 hours

Step-by-step explanation:

40 times 8.10 is 324 and 324 divided by 10.8 is 30 hours

The measure of HI based on the given diagram is 70 units.

A triangle mid segment is the line joining the midpoint of any two sides of the triangle which is parallel to the third side and is also half of the length of the third side.

HI = 3x + 5

EF = -3x + 55

So,

HI = 1/2(EF)

3x + 5 = 1/2(-3x + 55)

3x + 5 = (-3x + 55) / 2

cross product

2(3x + 5) = -3x + 55

open parenthesis

6x + 10 = - 3x + 55

6x + 3x = 55 - 10

9x = 45

divide both sides by 9

x = 45/9

x = 5

Therefore, the measure of HI and EF are;

HI = 3x + 5

= 3(5) + 55

= 15 + 55

= 70

EF = -3x + 55

= -3(5) + 55

= -15 + 55

= 40

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Answer:

p < -4

Step-by-step explanation:

-6(4p+5) > 34 - 8p

-24p - 30 > 34 - 8p

-16p - 30 > 34

-16p > 64

p < -4

The expression's fully factored form is:[tex]72x^{3} + 72x^{2} + 18x = 18x(4x^{2} + 1)(x + 1)[/tex]

Factored Value, also known as "trended value," is the base annual value plus a yearly inflation factor based on a variation in the cost if live that is not to exceed 2% and is set by the State Agency of Equalization.

Rewriting an expression as the sum of factors is referred to as factor expressions or factoring. For instance, 3x + 12y may be expressed as 3 (x + 4y), which is a straightforward equation. The computations get simpler in this method. Three or (x + 4y) were examples of factors.

We can factor out [tex]18x[/tex] from each term to simplify the expression:

[tex]72x^{3} + 72x^{2} + 18x = 18x(4x^{3} + 4x^{2} + 1)[/tex]

An expression enclosed in parentheses can now be calculated by grouping or factoring.

[tex]4x^{3} + 4x^{2} + 1 = (4x^{2} + 1)(x + 1)[/tex]

The expression's properly factored version has the following result,

[tex]72x^{3} + 72x^{2} + 18x = 18x(4x^{2} + 1)(x + 1)[/tex]

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Answer:

Step-by-step explanation:

Let's call the number we're looking for "x".

The problem tells us that "if the sum of a number and eight is doubled, the result is seven less than the number", which can be translated into an equation:

2(x+8) = x-7

Now let's solve for x:

2x + 16 = x - 7

2x - x = -7 - 16

x = -23

Therefore, the number we're looking for is -23.

The area of the triangle with the given base and height where a = 4 and c = 2 is: 608 cm²

Area = 1/2(base)(height).

Given the parameters:

If a = 4 and c = 2, then:

Area = 1/2(base)(height) = 1/2(2ac²)(2ac² + 6)

Area = 1/2(2 × 4 × 2²)(2 × 4 × 2² + 6)

Area = 1/2(32)(38)

Area = 608 cm²

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The mix design and w/c ratio used in the concrete mix are commonly used for M15 grade concrete, and achieving a compressive strength of 18 MPa after 7 days of curing may be reasonable depending on the target strength and other design specifications.

The actual compressive strength of 18 MPa achieved after 7 days of curing may be lower or higher than the target strength, depending on the design specifications and requirements.

However, the mix design of 3:2:1 (cement:sand:aggregate) with a water-cement (w/c) ratio of 0.50 is a commonly used mix proportion for M15 grade concrete. With proper curing and compaction, this mix design should be capable of achieving a compressive strength of at least 15 MPa at 28 days of curing.

The compressive strength is typically measured after 28 days of curing, not just 7 days. Therefore, it may be premature to conclude whether the achieved compressive strength of 18 MPa is reasonable without testing the concrete at 28 days of curing.

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_____The given question is incomplete, the complete question is given below:

do the compression values seem resonable given the  3:2:1. mix design, 0.50 w/c ratio and 7 days of curing. M 15 grade concrete

Cement = 3 Part

Sand = 2 Part

Aggregate = 1 Part

Total dry volume of Material Required = 1.57 cu.m

actual compressive strength of the concrete = 18 MPa

36.92 lbs. of the $3.45 tea and 43.08 lbs. of the $2.15 tea are needed.

Let x and y be the amount of tea that sells fo 3.45 and 2.15 a pound respectively:

x+y=80....................eq 1

3.45x+2.15y=2.75(80)......eq 2

:

rewrite eq 1 to x=80-y and plug that value into eq 2

:

3.45(80-y) +2.15y=2.75(80)

:

276-3.45y+2.15y=220

:

-1.3y=56

:

y=43.07 pounds of $2.15 tea

:

28x=80-43.07=36.93 pounds of $3.45 tea

Let a= the pounds of the more expensive tea needed

Let b= the pounds of the less expensive tea needed

(1) a+%2B+b+=+80

(2) 345a+%2B+215b+=+80%2A275 (in cents)

--------------------------

In words, (2) says.

(lbs of 'a' tea x price/lb) + (lbs of 'b' tea x price/lb) =

(lbs of mixture x price/lb of mixture)

-------

Multiply both sides of (1) by 215 and then.

subtract from (2)

345a+%2B+215b+=+80%2A275

-215a+-+215b+=+-80%2A215

130a+=+80%2A60

130a+=+4800

a+=+36.92

and, from (1)

(1) a+%2B+b+=+80

36.92+%2B+b+=+80

b+=+80+-+36.92

b+=+43.08

36.92 lbs. of the $3.45 tea and 43.08 lbs. of the $2.15 tea are needed.

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The mixture contains 34 pounds of black tea and 46 pounds of Earl Gray tea.

What is an algebraic expression?

An algebraic expression is a mathematical phrase that contains variables, constants, and mathematical operations.

Let's denote the amount of black tea in pounds by "x" and the amount of Earl Gray tea in pounds by "y".

Since the total amount of mixture is 80 lb, we have:

x + y = 80 ----(1)

We also know that the mixture sells for $2.75 a pound, so the total revenue from selling 80 lb of mixture is:

80 x $2.75 = $220

On the other hand, the cost of the mixture is the sum of the costs of the black tea and the Earl Gray tea, which is:

3.45x + 2.15y

Since the company wants to make a profit, the revenue must be greater than the cost, so we have:

3.45x + 2.15y < $220

We can simplify this inequality by dividing both sides by 0.1:

34.5x + 21.5y < 2200 ----(2)

Now we have two equations with two unknowns (equations (1) and (2)), which we can solve using substitution or elimination.

Substitution method:

From equation (1), we have:

y = 80 - x

Substituting this into equation (2), we get:

34.5x + 21.5(80 - x) < 2200

Simplifying and solving for x, we get:

x < 34.5

Rounding x to the nearest pound, we get x = 34.

Substituting this value into y = 80 - x, we get y = 46.

Therefore, the mixture contains 34 pounds of black tea and 46 pounds of Earl Gray tea.

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Answer:

Step-by-step explanation:

To find the limit of (n!)^(1/n) as n approaches infinity, we can use the Stirling's approximation for n!, which is:

n! ≈ (n/e)^n √(2πn)

where e is the mathematical constant e ≈ 2.71828, and π is the mathematical constant pi ≈ 3.14159.

Using this approximation, we can rewrite (n!)^(1/n) as:

(n!)^(1/n) = [(n/e)^n √(2πn)]^(1/n) = (n/e)^(n/n) [√(2πn)]^(1/n)

Taking the limit as n approaches infinity, we have:

lim (n!)^(1/n) = lim (n/e)^(n/n) [√(2πn)]^(1/n)

Using the fact that lim a^(1/n) = 1 as n approaches infinity for any constant a > 0, we can simplify the second term as:

lim [√(2πn)]^(1/n) = 1

For the first term, we can rewrite (n/e)^(n/n) as [1/(e^(1/n))]^n and use the fact that lim a^n = 1 as n approaches infinity for any constant 0 < a < 1. Thus, we have:

lim (n/e)^(n/n) = lim [1/(e^(1/n))]^n = 1

Therefore, combining the two terms, we have:

lim (n!)^(1/n) = lim (n/e)^(n/n) [√(2πn)]^(1/n) = 1 x 1 = 1

Hence, the limit of (n!)^(1/n) as n approaches infinity is 1.

Answer:1

Step-by-step explanation:

The x-intercept is (3.2, 0), and the y-intercept is (0, -32) if the equation of the line is y = 10x - 32.

Answer:  x= 3.2

Step-by-step explanation:

by graphing we can see where the line crosses the x axis at 3.2

I attached a graph to show you this method

to solve algebraically, y = 10x - 32 is your equation

put this in standard form ax + by = c

-10x + y = -32

to solve for x, substitute 0 for y and solve

-10x + 0 = -32

divide both sides by -10

-10/-10 x = -32/ -10

x = 3.2

The correct matches are: 4 in. → 10.2 cm   ,   7 kg → 15.4 lb

6 gal → 22.7 L   and  65 ft → 19.8 m.

Conversions refer to the process of changing a measurement from one unit to another unit that measures the same quantity.

For example, converting distance from miles to kilometers, or converting weight from pounds to kilograms.

Here are the conversions:

1 inch = 2.54 cm (approx.)

1 kg = 2.205 lb (approx.)

1 gal = 3.785 L (approx.)

1 ft = 0.3048 m (approx.)

Using these conversions, we can find the equivalent measures:

4 in. → 4 × 2.54 = 10.16 ≈ 10.2 cm

7 kg → 7 × 2.205 = 15.435 ≈ 15.4 lb

6 gal → 6 × 3.785 = 22.71 ≈ 22.7 L

65 ft → 65 × 0.3048 = 19.812 ≈ 19.8 m

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Perfect numbers between 1 and n (where n is a positive integer) are 6, 28, 496, 8128.

A positive integer that is the sum of its appropriate divisors is referred to as a perfect number. The sum of the lowest perfect number, 6, is made up of the digits 1, 2, and 3. The digits 28, 496, and 8,128 are also ideal.

Perfect numbers are whole numbers that are equal to the sum of their positive divisors, excluding the number itself. Examples of perfect numbers include 6 (1 + 2 + 3 = 6), 28 (1 + 2 + 4 + 7 + 14 = 28) and 496 (1 + 2 + 4 + 8 + 16 + 31 + 62 + 124 + 248 = 496).

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The complete question is:

What are all the perfect numbers between 1 and n (where n is a positive integer)?

Using the power property to simplify the expression (9¹⁺⁴)⁷⁺², we have 9^7/8

Given the expression

(9¹⁺⁴)⁷⁺²

To simplify this expression using the power of a power property, we need to multiply the exponents:

(9¹⁺⁴)⁷⁺² = 9(¹⁺⁴ ˣ ⁷⁺²)

Simplifying the exponents in the parentheses:

(9¹⁺⁴)⁷⁺² = 9⁷⁺⁸ or 9^7/8

Therefore, (9¹⁺⁴)⁷⁺² simplifies to 9^(7/8).

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A parametric equation is one where the x and y coordinates of the curve are both written as functions of another variable called a parameter; this is usually given the letter t or θ . And the value of a= 8, b= 1, c= -2 and d= 0.

Equation of this form is known as a parametric equation; it uses an independent variable known as a parameter (often represented by t) and dependent variables that are defined as continuous functions of the parameter and independent of other variables.
You require 4 independent solutions because there are 4 unknowns.  You can put two equations at each end point if you know t at each end point. (one for the x value and one for the y value).
At (8,-2), time is equal to zero as follows: 8 = a + bt = a + b(0)  a = 8 -2 = c + dt = c + d(0)  c = -2
At (9,-2), t = 1 because 9 = a + bt = 8 + b(1)  b = 1 and -2 = c + dt = -2 + d(1)  d = 0.
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The answer of the given question based on determining the second break in the break is  1.1.1 The second break is from 11:25 AM to 11:40 AM, which means it is 15 minutes long , 1.1.2 Rhandzu is doing 8 subjects , Rhandzu has Mathematical Literacy on Day 3 and Day 7, which means it is a 4-day cycle.

Sepedi is  Bantu language spoken in South Africa by Pedi people. It is one of the 11 official languages of South Africa and is primarily spoken in  northern parts of  country, like Limpopo, Gauteng, and Mpumalanga provinces.

Sepedi is also known as Sesotho sa Leboa and is closely related to Sesotho (Southern Sotho) and Setswana (Tswana). Sepedi Home Language refers to  study of Sepedi as  first language or mother tongue in South African schools. It is an important subject in South African education system, as it helps to preserve and promote use of indigenous languages and cultural heritage.

1.1.1 The second break is from 11:25 AM to 11:40 AM, which means it is 15 minutes long.

1.1.2 Rhandzu is doing 8 subjects, which are English Home Language, Mathematics, Life Orientation, Physical Sciences, Life Sciences, Agricultural Sciences, Mathematical Literacy, and Sepedi Home Language.

1.1.3 Rhandzu has Mathematical Literacy on Day 3 and Day 7, which means it is a 4-day cycle. Therefore, in an eight-day cycle, Rhandzu would have Mathematical Literacy on Day 3, Day 7, Day 3 again, and Day 7 again.

It is important to schedule breaks on the time-table because they allow students to rest and recharge between lessons. Breaks can also help students to stay focused and engaged during lessons by giving them time to process and reflect on what they have learned. Additionally, breaks can provide opportunities for social interaction and physical activity, which can have a positive impact on students' well-being and academic performance.

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The second break is from 11:25 AM to 11:40 AM, which means it is 15 minutes long , Rhandzu is doing 8 subjects , Rhandzu has Mathematical Literacy on Day 3 and Day 7, which means it is a 4-day cycle.

Sepedi is  Bantu language spoken in South Africa by Pedi people. It is one of the 11 official languages of South Africa and is primarily spoken in  northern parts of  country, like Limpopo, Gauteng, and Mpumalanga provinces.

Sepedi is also known as Sesotho sa Leboa and is closely related to Sesotho (Southern Sotho) and Setswana (Tswana). Sepedi Home Language refers to  study of Sepedi as  first language or mother tongue in South African schools. It is an important subject in South African education system, as it helps to preserve and promote use of indigenous languages and cultural heritage.

1.1.1 The second break is from 11:25 AM to 11:40 AM, which means it is 15 minutes long.

1.1.2 Rhandzu is doing 8 subjects, which are English Home Language, Mathematics, Life Orientation, Physical Sciences, Life Sciences, Agricultural Sciences, Mathematical Literacy, and Sepedi Home Language.

1.1.3 Rhandzu has Mathematical Literacy on Day 3 and Day 7, which means it is a 4-day cycle. Therefore, in an eight-day cycle, Rhandzu would have Mathematical Literacy on Day 3, Day 7, Day 3 again, and Day 7 again.

It is important to schedule breaks on the time-table because they allow students to rest and recharge between lessons. Breaks can also help students to stay focused and engaged during lessons by giving them time to process and reflect on what they have learned. Additionally, breaks can provide opportunities for social interaction and physical activity, which can have a positive impact on students' well-being and academic performance.

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The measure of angle BAC is 55°, which is closest to option B (50°).

The ratio of the length of the side directly opposite an acute angle to the side directly adjacent to the angle is known as the tangent in trigonometry. Only triangles with straight angles can have this.

Let's give the angles shown in the diagram the following labels:

Angle ACD = 55°

Angle ABD = 35°

Angle BCD = 90°

To determine the size of angle ABC, we can use the knowledge that a triangle's total angles equal 180°. Because the straight line formed by angles ABD and BCD, we have:

[tex]Angle ABC = 180° - Angles ABD and BCD.[/tex]

[tex]Angle ABC = 180° - 35° - 90°Angle ABC = 55°[/tex]

Given that triangle ABC has two angles, we can use the knowledge that a triangle's total of angles equals 180° to determine the size of angle BAC:

[tex]Angle BAC = 180° - Angle ABC - Angle ACBAngle BAC = 180° - 55° - 70°Angle BAC = 55°[/tex]

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It is most similar to option B (50°) when the angle BAC is 55°.

What is a tangent angle?

The tangent in trigonometry is the length of the side directly opposite an acute angle divided by the length of the side directly next to the angle.

This property can only be found in triangles with straight angles.

Let's give the angles shown in the diagram the following labels:

Angle ACD = 55°

Angle ABD = 35°

Angle BCD = 90°

We can use the fact that a triangle's total number of angles is 180° to calculate the size of angle ABC. due to the fact that the straight line created by angles ABD and BCD

Triangle ABC has two angles, so we can use the fact that a triangle's sum of angles is 180° to calculate the size of angle BAC.

Therefore, the BAC measurement is 55°, which is closest to option B's 50°.C is 55°, which is closest to option B (50°).

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Answer:

Proofs attached to answer

Step-by-step explanation:

Proofs attached to answer

Answer:1

Step-by-step explanation:

2/2=1

1^-3=1

1/1times1times1

Answer:

1

Step-by-step explanation:

[tex]\frac{2}{2}[/tex] = 1

[tex]1^{-3}[/tex] To make a negative exponent positive, put it under one.

[tex]\frac{1}{1^{3} }[/tex] = [tex]\frac{1}{1}[/tex] = 1

Helping in the name of Jesus.

Answer: 2/13

Step-by-step explanation:

There are four jacks and four tens in a standard deck of 52 cards. However, the jack of spades and the ten of spades are counted twice since they are both a jack and a ten. Therefore, there are 8 cards that are either a jack or a ten, and the probability of drawing one of these cards at random is:

P(Jack or Ten) = 8/52 = 2/13

So the answer is 2/13.

Step-by-step explanation:

a probability is airways the ratio

desired cases / totally possible cases

in each of the 4 suits there is one Jack and one 10.

that means in the whole deck of cards we have

4×2 = 8 desired cases.

the totally possible cases are the whole deck = 52.

so, the probability to draw a Jack or a Ten is

8/52 = 2/13

The ROC of a given signal's Z-transform can be determined without actually computing the Z-transform by identifying the maximum and minimum magnitude of the signal and checking for any poles of the Z-transform within the resulting annular region.

Let's take a signal as an example, suppose x[n] = {1, -2, 3, -4, 5}. In order to determine the ROC of its Z-transform, we are firstly required to first look for any regions in the complex plane where the sum of the absolute values of the Z-transform is found finite. It can be done by looking for the maximum and minimum magnitude of x[n] and denote them as R1 and R2 respectively. Then, the ROC of the Z-transform will be the annular region between R1 and R2, excluding any poles of the Z-transform that lie within this annular region.

In this case, the maximum absolute value of x[n] is 5 and the minimum is found being 1. So, the ROC of the Z-transform will be the annular region between |z| = 1 and |z| = 5. We can denote this as 1 < |z| < 5. We also need to check if there are any poles of the Z-transform within this annular region. Since we haven't actually computed the Z-transform, we cannot determine the exact location of any poles.

However, we can check for any values of z that would make the Z-transform infinite. For example, if x[n] is a causal signal (i.e., x[n] = 0 for n < 0), then the ROC cannot include any values of z for which |z| < 1, since this would make the Z-transform infinite.

So, the ROC of the Z-transform for the given signal x[n] can be written as 1 < |z| < 5, assuming that x[n] is a causal signal.

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The complete question is :

Can you explain how to determine the ROCs (regions of convergence) for the Z-transform of a given signal without actually computing the Z-transform? Please provide an example signal with random data and demonstrate how to find its ROCs using this method.

Yes. they can in fact, more than two independent variables can have the same distribution. Two random vectors follow the same distribution, which means that each marginalized variable must follow the same distribution.

In probability theory and statistics, the marginal distribution of a subset of a set of random variables is the probability distribution of the variables contained in that subset. It gives the probability of different values ​​of variables in the subset without reference to the values ​​of other variables. This contrasts with conditional distributions, which give probabilities based on the values ​​of other variables.

The marginal variables are the variables of the subset of variables which are retained. These concepts are "marginal" because they can be found by adding the values ​​of the rows or columns of a table and writing the sum in the blank space of the table.

The distribution of the marginal variable (marginal distribution) is obtained by marginalizing the distribution of the suppressed variable (that is, focusing on the sum in the margin), and the suppressed variable is called marginalized.

Complete Question:

If two random variables have the same PDF/PMF, then does this mean they have the same distribution?

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The width of the blanket to the nearest tenth of an inch is approximately 67.4 inches.

What is width in rectangle ?

In a rectangle, the width refers to the measurement of the shorter side of the rectangle, which is perpendicular to its length.

Let x be the width of the blanket in inches. Then the length of the blanket is x + 18 inches.

The area of the blanket is given by:

Area = Length x Width

5760 sq inches = (x + 18) inches * x inches

Expanding the right-hand side and solving for x, we get:

[tex]x^2 + 18x - 5760 = 0[/tex]

We can solve this quadratic equation using the quadratic formula:

[tex]x = (-b \pm \sqrt{(b^2 - 4ac)}) / 2a[/tex]

where a = 1, b = 18, and c = -5760. Plugging in these values, we get:

[tex]x = (-18 \pm \sqrt{(18^2 - 4(1)(-5760))}) / 2(1)[/tex]

[tex]x = (-18 \pm \sqrt{(18^2 + 23040)}) / 2[/tex]

x ≈ 67.42 or x ≈ -85.42

Since the width cannot be negative, the width of the blanket to the nearest tenth of an inch is approximately 67.4 inches.

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The answer is A, rhombus.

We can see that p(p + 1)(p − 1) is not always divisible by 7, but it is always divisible by 5, 4, and 3. Thus, the correct answer is (G) 5.

A positive integer is a whole number greater than zero. In other words, it is a number that can be written without any fractional or decimal components, and is larger than zero. Positive integers are commonly denoted by the symbol "N" or "Z+".

A negative integer is a whole number less than zero. In other words, it is a number that can be written without any fractional or decimal components, and is smaller than zero. Negative integers are commonly denoted by the symbol "Z−".

In the given question,

We can simplify p(p + 1)(p − 1) as follows:

p(p + 1)(p − 1) = p(p² - 1) = p³- p

Now, we can consider the remainders when p is divided by each of the answer choices:

F. 7: If p = 7, then p³- p = 7³ - 7 = 342, which is not divisible by 7.

G. 5: If p = 5, then p³ - p = 5³ - 5 = 120, which is divisible by 5.

H. 4: If p = 4, then p³ - p = 4³ - 4 = 60, which is divisible by 4.

J. 3: If p = 3, then p³ - p = 3³ - 3 = 24, which is divisible by 3.

Therefore, we can see that p(p + 1)(p − 1) is not always divisible by 7, but it is always divisible by 5, 4, and 3.

Thus, the correct answer is (G) 5.

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Step-by-step explanation:

Use the 110 to find the 70 degree angle   (they form a straight line = 180°)

   then 70 + 64 + R angle = 180°    ( sum of angles of a triangle)

        then  :    R angle = 46°

then the R angle + 2x-10 = 90°    ( because the two lines are perpendicular)

(2x -10)°   + 46 °  = 90 °

x = 27

Answer:

Distance in the coordinate plane iready

Step-by-step explanation:

Sure, I can help with distance in the coordinate plane!

The distance between two points (x1, y1) and (x2, y2) in the coordinate plane can be found using the distance formula:

d = √((x2 - x1)^2 + (y2 - y1)^2)

Here's an example:

Let's say we want to find the distance between the points (3, 4) and (6, 8).

We can plug these coordinates into the distance formula:

d = √((6 - 3)^2 + (8 - 4)^2)

Simplifying the expression inside the square root:

d = √(3^2 + 4^2)

d = √(9 + 16)

d = √25

d = 5

Therefore, the distance between the points (3, 4) and (6, 8) is 5 units.