The magnitude of the resulting acceleration of the block is 5.60 m/s.
What is Newton's second law?The product of the block's mass and acceleration is the net force acting on the block. Newton's second law of motion is what is known as this.
The following is the expression for Newton's second law:
F = ma
The net horizontal force acting on the block is as follows:
Fnet =F + FcosΘ
Here, F is the force acting on the block, and 8 is the angle at which the force is applied to the block.
Substitute 30Θ for 8 and 30 N for F.
Fnet =30 N + (30 N)cosΘ = 55.98 N
From Newton's second law, the expression for the force is.
Fnet = ma
Substitute 10.0 kg for m and 55.98 N for Fnet
55.98 N = (10 kg)a
a (55.98 N /10 kg)
a = 5.598 m/s2 a = 5.60 m/s
Therefore, the acceleration of the block is 15.60 m/s
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The question is incomplete. Your most probably complete question is given below: The figure is added.
A uniform plane wave with parallel polarization is propagating in a lossless dielectric medium (l is € 1), and is incident obliquely onto a plane boundary with another lossless dielectric medium (u 2, E 2). (30%) (a) Derive the Snell's laws of reflection and refraction in terms of the refractive indices and angles. (b) Derive the general expressions for the reflection and the transmission coefficients of the EM field. Find such expressions in terms of the refractive indices if both media are nonmagnetic, i.e., M F M 240. (c) Derive the general expression for the Brewster angle. Find such an expression in terms of the refractive indices if both media are nonmagnetic. (d) Prove that, under the condition of no reflection, the sum of the Brewster angle and the angle of refraction is 90° if both media are nonmagnetic. (e) For total reflection to occur, find the condition for the medium property and the critical angle.
Transmission coefficients are used in physics and electrical engineering when considering wave propagation in discontinuous media. The snells law is n₁sinθ1 = n₂sinθ2
The transmission coefficient describes the amplitude intensity or total power of the transmitted wave relative to the incident wave. The transmission coefficient is defined as the ratio of the transmitted particle flux to the incident particle flux and depends on the incident energy.
The sum of the reflected and transmitted energy must equal the total incident energy, so the transmission coefficient is calculated simply by subtracting the reflection coefficient. The ratio of the reflected wave amplitude to the incident wave amplitude is called the reflection coefficient.
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crane lifts a 400 kg crate upward with an acceleration of 3.00 m/?. Determine the force on the crane.
The crane is under 5120 N of force. The crane touches the rock boulder and uses mechanical force to lift it.
What are the units of a force?Force is a physical phenomenon that can change an object's shape as well as its state of motion or rest. The SI unit of force is the Newton.
Cranes fall under which of the following three forces?Jib, gantry, and overhead cranes are the three pieces of machinery used most frequently in the industry. Depending on the type of item to be moved, either a chain or wire rope hoist will be used. In the shipbuilding sector, material handling is the main use of overhead cranes during the assembly process.
Briefing:
Mass (m) = 400kg
Acceleration (a) = 3.00 m/s^2
Gravitational acceleration (g) = 9.81 m/s^2
Force (F) = mg + ma
Force (F) = m (g + a)
Force (F) = 400 (9.81+3)
Force (F) = 5120 N
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the following items describe observational characteristics that could indicate that an object is either a white dwarf or a neutron star. match each characteristic to the correct object.
When a white dwarf acquires enough mass for its carbon interior to start fusing, a white dwarf supernova results.
The white dwarf entirely explodes as the star's fusion starts nearly immediately throughout the entire star. When iron is produced during fusion in a star's core, a "massive stellar supernova" results. If a white dwarf in a near binary system acquires enough mass to surpass the "white dwarf limit (1.4 solar masses)," it will erupt as a supernova. The absence of hydrogen characteristics in type I supernovae's spectra at maximum luminosity is a crucial identifying trait. The remnant core of a low-mass star known as a white dwarf is protected from the force of gravity by electron degeneracy pressure. The mass of the Sun is often condensed into a body no bigger than Earth in a white dwarf.
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A student applies a force F at an angle of θ below the horizontal to a 50 kg desk, which causes the desk to move across the room at a constant speed.
Angle θ= 20 Degrees
Force= 200 N
Draw and label an appropriate force vector diagram for the desk.
What is the weight of the desk?
What is the magnitude of the normal force acting on the desk?
What is the magnitude of the friction force acting on the desk?
The magnitude of the weight, normal and friction forces are 490N, 455N and 16.66N respectively.
The force applied by the student at the angle of 20 degrees has a magnitude of 200N.
The desk is moving across the room with a constant speed.
The mass of the desk is Kg.
The weight of the desk is given by,
W = Mg
Where,
g is acceleration due to gravity.
Putting values,
W = 50 x 9.8
W = 490N.
The magnitude of the normal force is given by,
N = WcosA
Where,
A is the angle with x-axis.
Putting values,
N = 490 x cos(20)
N = 455N.
The magnitude of the Friction force is given by,
F = W x sin(20)
F = 490 x 0.34
F = 16.66N.
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for the circuit below all values are rms with a source frequency of 60 hertz. the generator impedance is negligible (0 w). calculate the value of ib and and determine the value of vb-n. now, calculate the rms values of apparent, real and reactive power of zb. (show units for all)
The reactive power of the branch (Qb) can be calculated from its voltage and current 676.16 VA.
What is reactive power?Reactive power is the power in an AC circuit that is required to establish and maintain a voltage across a load. It is associated with the storage and release of energy in the form of electric and magnetic fields. Reactive power does not contribute to the actual work output of a system and is measured in Volt-amperes reactive (VARs). Power factor is a measure of reactive power relative to the total power in a system.
Source frequency = 60 Hz
Generator impedance = 0 W
Circuit:
Vg = 170 V
R1 = 10 Ω
R2 = 20 Ω
Zb = 20 + j10 Ω
The current flowing through the generator (Ig) and the branch (Ib) can be calculated from Ohm's Law:
Ig = Vg/R1 + Vg/R2 = 170/10 + 170/20 = 17 A
Ib = Ig - Vg/Zb = 17 - 170/(20 + j10) = 17 - 16.4 + j4.4 = 0.6 + j4.4 A
Since Ib is a complex number, we can find its magnitude (|Ib|) and angle (θ):
|Ib| = √(0.6² + 4.4²) = 4.46 A
θ = tan⁻¹(4.4/0.6) = 80.16°
The voltage across the branch (Vb-n) can be calculated using Ohm's Law:
Vb-n = Ib × Zb = (0.6 + j4.4) × (20 + j10) = -8.4 + j74.4 V
The apparent power of the branch (Sb) can be calculated from its voltage and current:
Sb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = -45.48 + j367.04 VA
The real power of the branch (Pb) can be calculated from its voltage and current:
Pb = Vb-n × Ib = (-8.4 + j74.4) × (0.6 + j4.4) = -45.48 - j367.04 W
The reactive power of the branch (Qb) can be calculated from its voltage and current:
Qb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = 676.16 VA
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A 20 g ball of clay traveling east at 2.5 m/s collides with a 25 g ball of clay traveling north at 2.0 m/s .
What is the speed of the resulting 45 g ball of clay?
What is the direction of the resulting ball of clay?
The final velocity of the two balls after collision is 1.7 m/s and the direction is 45⁰.
The given parameters;
mass of the first clay ball, m₁ = 20 g = 0.02 kg
initial velocity of the first clay ball, u₁ = 3 m/s
mass of the second clay ball, m₂ = 30 g = 0.03 kg
initial velocity of the second ball, u₂ = 2 m/s
The initial momentum of the fist ball is calculated as follows;
P₁ = m₁u₁
P₁ = (0.02)(3)
P₁ = 0.06 kg.m/s
The initial momentum of the second ball is calculated as follows
P₂ = m₂u₂
P₂ = (0.03)(2)
P₂ = 0.06 kg.m/s
The resultant initial momentum of the two balls is calculated as follows;
Apply the principle of conservation of momentum, to determine the final velocity of the two balls;
The direction of the two ball's velocity is calculated as follows;
Thus, the final velocity of the two balls after collision is 1.7 m/s and the direction is 45⁰To know more about speed direction visit:
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Aspace station has a mass M and orbits Earth in a circular orbit at a height above Earth's surface. Space Station Earth A payload of mass m, where m < M is delivered to the space station. Soon after, the space station's orbit is adjusted so that it is 50 km farther away from Earth's surface than before. Which of the following best describes the effects of these changes on Earth's gravitational field strength at the space station's new location? The increase in mass of the space station has no effect on the field strength, and the increase in orbital radiun decreases the field strength A B The increase in mass increases the field strength, and the increase in orbital radius decreases the field strength, however, the field strength decreases overall A payload of mass m, where m
The increase in mass of the space station has no effect on the field strength, and the increase in orbital radium decreases the field strength
What is Earth's Gravitation Field?
Earth's gravitation field is the force any object experiences due to the gravitational pull by earth. It's formula is given below where G is the force, m is the mass of earth and r is radius of distance.
As seen through the formula, the gravitation field strength is only depend on earth's mass which is constant and radius of the distance. Hence, the increase in mass of the space station has no effect on the field strength, and the increase in orbital radium decreases the field strength.
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Field poles are electromagnets whose ____ change as the flow of current alternates in the field windings.
Field poles are electromagnets whose polarities change as the flow of current alternates in the field windings.
An electromagnet is a sort of magnet wherein the magnetic area is produced with the aid of an electric current. Electromagnets generally encompass cord wounds into a coil. A cutting edge through the wire creates a magnetic discipline that is focused inside the hole in the middle of the coil.
Electromagnets create a magnetic discipline through the application of power. When you introduce the modern, either from a battery or any other supply of strength, it flows through the wire. This creates a magnetic discipline around the coiled cord, magnetizing the metal as though it were a permanent magnet.
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when the glass gob comes out of the oven, it is dangerously hot. What happens to the thermal energy of the gob between that time and when it is a bottle than can be touched?
Answer:
decreases
Explanation:
The thermal energy of the gob decreases by heating the air around the gob and the mold in which the bottle is made
A(n) ____________________ is a dynamic variable on the free store without any pointer pointing to it.
A inaccessible object is a dynamic variable on the free store without any pointer pointing to it.
How to find the height of an inaccessible object using sextant?Utilize the sextant's arc to determine the angle. By dividing the object's distance from the point of observation by the tan of the angle you calculated, you may use a scientific calculator to get the object's height.
How can heights and distances that are absent or unavailable be measured?The measuring of heights and distances that are unreachable is made easier by right-triangle trigonometry. By drawing a right triangle with the unknown height or distance as one of its sides and a known side and angle on the other, it is possible to determine the unknown height or distance.
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Answer:
dynamic variable
two loops of wire are arranged so that a changing current in one will induce a current in the other. if the current in the first is increasing clockwise by one amp every second, the current in the second loop will? a. be increasing counterclockwise. b. stay constant. c. increase clockwise also. d. stay zero
Answer:
An induced current in a changing magnetic field will be in such a direction as to oppose the magnetic field causing the induced current.
Thus, the current in the second loop must be increasing in a counterclockwise direction (a)
The induced current must produce magnetic field that opposes the field producing the change or perpetual motion could occur.
find the finel angular velocity (w) when the intial angular velocity(w) is 5rad/s the Angular acceleration is 2rad/s² and the time of motion is 5sec
Answer:
15 rad/s
Explanation:
Given:
α = 2 rad/s²
ω₀ = 5 rad/s
t = 5 s
Find: ω
ω = αt + ω₀
ω = (2 rad/s²) (5 s) + (5 rad/s)
ω = 15 rad/s
Part B
The general kinematic equations of motion for vertical displacement can also be simplified significantly. Write the simplified equation for y in this case. Explain how you have been able to simplify it from this general displacement equation:
The general vertical displacement equation for object moving upwards is written as h = v₀t - ¹/₂gt².
What is the vertical displacement of an object?The vertical displacement of an object is the height travelled by the object.
The general kinematic equations of motion for vertical displacement is written as follows;
y = y₀ + v₀t + ¹/₂at²
where;
y₀ is initial vertical position of the objectv₀ is the initial vertical velocity of the objecta is the acceleration of the objectt is the time of motionIf the object is moving upwards, the new kinematic equation becomes;
h = 0 + v₀t - ¹/₂gt²
h = v₀t - ¹/₂gt²
where;
h is the vertical displacement of the objectv₀ is the initial vertical velocity of the objectg is the acceleration due to gravityt is the time of motion of the objectFor the simplified equation above, the acceleration of the object changes to acceleration due to gravity since the object is moving against gravity in the negative direction.
Thus, the general kinematic equations of motion for vertical displacement is written in terms of acceleration due to gravity in negative direction since it is moving upwards.
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A diffraction grating 20.0 mm wide has 6000 rulings. Light of wavelength 589 nm is incident perpendicularly on the grating. What are the (a) largest, (b) second largest, and (c) third largest values of theta at which maxima appear on a distant viewing screen?
6000 rulings are present on a 20.0 mm broad diffraction grating. The maximum value of theta at which maxima show on a distant viewing screen for light with a wavelength of 589 nm is 62.1 °, followed by 45.0 ° and 32.0 °.
Adjacent rulings are separated by a distance of d = 20.0mm/6000 = 0.00333mm = 3.33m. Let dsin equal m (0, 1, 2,...). The greatest value of corresponds to m=5, which results in = sin 1(m/d)= sin 1 (5(0.589m)/3.33m)=62.1 ° b) because m/d>1 for m6. The second-largest value of is equal to m=4, which results in the expression = sin 1 (m/d) = sin 1 (4(0.589 m)/ 3.33 m)= 45.0° c. When m=3—the third-largest value of —is used, the result is = sin 1 (m/d) = sin 1 (3(0.589 m)/3.33 m) = 32.0°.
Diffraction is the interference or bending of waves via an aperture or around an obstruction's corners into the region that is physically in its geometric shadow. In essence, the diffracting component or aperture becomes a second source of the wave. Francesco Maria Grimaldi, an Italian physicist, was the first to precisely record the occurrences of the phenomena in 1660 and also coined the name "diffraction".
An unlimited number of locations (three shown) along length d that project phase contributions from the wavefront cause a continuously varying intensity () to be created on the license plate.
The diffraction phenomenon is explained by the classical physics idea known as the Huygens-Fresnel principle, which views each point in a propagating wave front as a group of distinct spherical wavelets.
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if the sentence is true, write a response that would convince a classmate that the sentence is indeed true. If you think that the sentence is not true, write a response that would convince a classmate the sentence is not true
1.A 10 cm radius Styrofoam sphere is submerged in water. So is a 10 cm radius lead sphere. The buoyant force exerted by the water on the Styrofoam sphere is greater than the force exerted on the lead sphere
2.Hot air balloons could be improved by filling them with hydrogen instead of heated air.
A 10 cm radius Styrofoam sphere is submerged in water. So is a 10 cm radius lead sphere. The buoyant force exerted by the water on the Styrofoam sphere is greater than the force exerted on the lead sphere is true.
2.Hot air balloons could be improved by filling them with hydrogen instead of heated air is ta true statement.
How do you prove the statements above?Case I- Styrofoam sphere
The buoyant force exerted by a fluid on an object is equal to the weight of the fluid that the object displaces. This means that the buoyant force exerted on the Styrofoam sphere and the lead sphere will be determined by the amount of water that each sphere displaces when it is submerged.
The Styrofoam sphere has a lower density than water, so it will displace a greater volume of water than the lead sphere, which has a higher density than water. This means that the buoyant force exerted on the Styrofoam sphere will be greater than the force exerted on the lead sphere.
To calculate the buoyant force on each sphere, you can use the following formula:
Buoyant force = weight of displaced fluid
The weight of the displaced fluid is equal to the volume of the fluid displaced multiplied by the fluid's density. You can use the formula for the volume of a sphere (V = 4/3πr^³) to calculate the volume of water displaced by each sphere.
For example, if the density of water is 1 g/cm^³ and the radius of each sphere is 10 cm, the volume of water displaced by the Styrofoam sphere would be:
4/3π(10 cm)^³
= 4/3π1000 cm^³
= 4347.19 cm^³
The weight of the displaced water would be:
4347.19 cm^³ * 1 g/cm^³
= 4347.19 g.
The buoyant force on the Styrofoam sphere would therefore be 4347.19 g.
The volume of water displaced by the lead sphere would be the same as the Styrofoam sphere (4347.19 cm^3), but the weight of the displaced water would be greater, due to the higher density of lead.
The weight of the displaced water for the lead sphere would be:
4347.19 cm^³ * 11.34 g/cm^³
= 49359.93 g,
The buoyant force on the lead sphere would be:
49359.93 g.
Therefore, the buoyant force on the Styrofoam sphere would be less than the force on the lead sphere, as stated in the original statement.
Case 2-Hot air balloons
Hydrogen is a lighter-than-air gas, which means that it is less dense than air and has a lower molecular weight. This makes it a potential alternative to heated air as a lifting gas for hot air balloons.
One advantage of using hydrogen as a lifting gas is that it is more buoyant than air, so a hot air balloon filled with hydrogen would be able to lift a greater payload than a balloon filled with air. This could make it possible to design hot air balloons that are larger or carry more passengers or cargo.
However, there are also some significant drawbacks to using hydrogen as a lifting gas for hot air balloons. One concern is the flammability of hydrogen, which is highly explosive and can ignite easily. This makes it potentially dangerous to use in a hot air balloon, as any leaks or accidents could result in a fire or explosion.
Overall, while hydrogen has some potential advantages as a lifting gas for hot air balloons, the risks and costs associated with its use may make it less practical than other options.
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A point charge e moves along the x-axis with uniform velocity v, so that its position x at time t is given by x =v t . Derive an explicit expression for the potential φ(t ) at the point (0, b, 0). The differential equation obeyed by φ(x, t ) is ∇2φ− (1 /c2 )∂2φ /∂t 2 =−4πrho where rho is the charge density.
The potential at the point (0, b, 0) is given by: φ(t) = 0 This means that the potential at the point (0, b, 0) is constant in time and equal to zero.
The potential at a point in space is a measure of the electric potential energy per unit charge at that point. The potential at a point is affected by the presence of charges in the surrounding space. In this problem, a point charge e is moving along the x-axis with uniform velocity v, and we want to find the potential at the point (0, b, 0) at time t. To find the potential at this point, we used the differential equation for the potential: ∇2φ− (1 /c2 )∂2φ /∂t 2 =−4πrho. This equation relates the potential at a point to the charge density in the surrounding space. The charge density at any given time t is given by rho = eδ(x - vt), where δ is the Dirac delta function. This expression represents a point charge located at x = vt. Substituting this expression for the charge density into the differential equation for the potential, we obtained: ∇2φ− (1 /c2 )∂2φ /∂t 2 =−4πeδ(x - vt). However, the point (0, b, 0) is not on the x-axis, so it is not affected by the delta function. This means that the potential at the point (0, b, 0) is not influenced by the presence of the point charge, and is therefore constant in time and equal to zero.
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A certain 50.0-Hz AC power line radiates an electromagnetic wave having a maximum electric field strength of 13.0 kV/m. (a) What is the wavelength of this very low frequency electromagnetic wave? (b) What is its maximum magnetic field strength?
An electromagnetic wave radiating from a specific 50.0-Hz AC power line has a maximum electric field strength of 13.0 kV/m. This extremely low frequency electromagnetic pulse has a wavelength of 6.00 x [tex]10^{6}[/tex]m.
An electromagnetic wave is what?A sinusoidal graph illustrates electromagnetic waves. It is made up of time-varying electric and magnetic fields that are perpendicular to each other and to the direction that waves travel.
How do wavelength and frequency relate to one another?Inverse proportionality describes the relationship between frequency and wavelength. Longer wavelengths are correlated with lower frequency, and vice versa. The fact that a wave's speed is equal to the product of its frequency and wavelength helps to explain how these two properties are related.
Briefing:
Given that,
Frequency of the power line, f = 50.0 Hz
Value of maximum electric field strength of 13.0 kV/m
The wavelength of this very low frequency electromagnetic wave is given by using relation as:
[tex]c = f[/tex]λ
λ [tex]= \frac{c}{f}[/tex]
λ [tex]= \frac{3.8 * 10^{8} m/s }{50}[/tex]
λ = 6 x [tex]10^{6}[/tex] m
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A string with one fixed end and an open end is observed to form a standing wave with a frequency of 250 Hz in its fundamental mode. It will also form a standing wave at frequency A) 500 Hz 650 Hz C)) 750 H:z 800 Hz E) 1000 Hz f 250
It will also form a standing wave at frequency C)) 750 H:z
What is frequency?The frequency of a repeating event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarity. Hertz, which equals one event per second, is the unit used to measure frequency.
The formula for standing wave frequency goes with the order nf (n=1,3,5,7,....) for one end of the string fixed at one point and the other at the open end.
Here in nf, f means the fundamental frequency that is when the order, n =1 . Here given that the fundamental frequency (n=1) as 250 Hz. Hence the other frequencies that can be formed according to the formula nf (n=1,3,5,7,....) are 750 Hz (n=3) , 1250 Hz (n=5), 1750 Hz (n=7) .. and so on.
The available frequency under the question is 750 Hz , when it comes to the options.
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A customer can choose one of six speaker systems, one of five DVD players, and one of six flat screen televisions to design a home entertainment system.
A customer can choose one of six speaker systems, one of five DVD players, and one of six flat-screen televisions to design a home entertainment system:
In order to determine the number of possible system configurations
A customer is a person or business that buys items or offerings from another business. clients are vital due to the fact they generate sales. without them, organizations might go out of business.
A client is commonly defined as someone who buys a terrific, product, or carrier. more, in particular, clients are human beings or agencies currently shopping, have bought, or maybe inquisitive about buying services or products from every other character or enterprise.
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One of the most controversial ideas to come out of instinct theories of aggression was Lorenz's proposal that society provide acceptable ways of permitting , or the process of discharging built-up aggressive energy.
The general instinct hypothesis, which contends that people are physiologically predisposed to or possess inclinations for violent behaviours, is known as the instinct theory of aggression in psychology.
This theory is more focused on aggression. The instinct theory of aggressiveness holds that human aggression is akin to sex and hunger, and that it can only be regulated rather than eradicated.In an effort to understand why we become aggressive and whether that behaviours can be altered, psychologists have developed three primary theories of aggression. Although many hypotheses have been put out, these three have proven most reliable and are crucial to comprehending the origins of violence. These hypotheses comprise as,
Adversity theory based on instinctTheory of Frustration and AggressionTheory of Social LearningTo know more about theory of aggression
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The half-life for a 200 gram sample of radioactive element X is 5 days. How much of element X remains after 15 days have passed?
A. 200 g - no change
B. 25 g
C. 50 g
D. 12.5 g
Answer:
B.) 25g
Explanation:
The easiest way to solve this problem is to realize that the sample has gone through three half-lives (15÷5=3).
Use this information to calculate how much of the original 200g sample is left after the three half-lives:
[tex](\frac{1}{2})(200g)=100g\\(\frac{1}{2})(100g)=50g\\(\frac{1}{2})(50g)=25g[/tex]
So, after three half-lives, the remaining sample has a mass of 25g.
If a 10.4kg block rests on a rough horizontal table with a coefficient or friction of u=0.15 then what is the resulting force of friction on the block ?
Mathematically, F is1.56 represents the resulting force of friction on the block. The Frictioval force's mathematical equation is typically represented as F is uN.
How can the force of friction be calculated?The resistive friction force (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), a numerical value. The formula fr = Fr/N is used to represent it.The block will now start to slide as P is increased continuously, with the friction force acting on the block being: f = muK*N, where muK is the coefficient of kinetic friction, and f staying constant after that as P is increased.The resistive friction force (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), a numerical value.Explanation:
Mathematically, F=1.56 represents the resulting force of friction on the block.
The Frictioval force's mathematical equation is typically represented as F=uN.
u equals the friction coefficient.
N is normal force.
frictional force
As a result, the force of friction on the F=10.4*0.15 F=1.56
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In a diffraction experiment, a coherent light source illuminates a pair of identical slits in a barrier, and the resulting pattern is projected on a screen that is separated from the barrier by 2.05 m. A student sketches the pattern that appears on the screen. The locations of the centers of the bright and dark fringes are accurate, but the shading is only qualitative. The color chosen may not be an ideal match to the actual light source. TITUTE THI HT -50.0 -40.0 -30.0 -20.0 -10.0 0.0 10.0 20.0 30.0 40.0 50.0 y (cm) * 25% Part (a) Enter the ratio of the slit separation, d, to the slit width, D, as a whole number. d = D TT 7 8 9 HOME E 4 5 6 sino cos tan cotano asin acos atan acotan sinh cosho tanh) cotanh O Degrees Radians 1 2 3 + 0 END . VO BACKSPACE DE CLEAR Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. A 25% Part (b) Calculate and enter the ratio of the slit width to the wavelength of the light source. A 25% Part (C) If the slit separation is 17 um, then calculate and enter the wavelength, in nanometers, of the light source. 25% Part (d) What is the slit width, in micrometers?
(a) The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width, in micrometers;
d = 20.5 µm
(a) We know that Fringe width is given by,
[tex]\beta =\frac{D\lambda}{d}[/tex]
Where,
D = slit to screen distance
λ = wavelength
d = slit width
Given in the question,
D = 2.05 m
[tex]\beta =4 cm=0.04m[/tex]
Now,
[tex]\frac{d}{D} =\frac{\lambda}{\beta } =\frac{400*10^{-9} }{0.04}[/tex]
d/D = 0.0001
Hence,
The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b) Ratio of d & λ,
[tex]\frac{d}{\lambda} =\frac{D}{\beta }[/tex]
[tex]\frac{d}{\lambda}=\frac{2.05}{0.04}[/tex]
[tex]\frac{d}{\lambda}=51.25[/tex]
Hence,
The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength of the light source,
[tex]\lambda=\frac{D\beta }{d}[/tex]
[tex]\lambda=\frac{17*10^{-6} *0.04}{2.05}[/tex]
[tex]\lambda=331.7nm[/tex]
Hence,
The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width,
[tex]d =\frac{D\lambda}{\beta }[/tex]
[tex]d=\frac{400*10^{-9} *2.05}{0.04}[/tex]
[tex]d=20.5 \mu m[/tex]
Hence,
The slit width, in micrometers;
d = 20.5 µm
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A 50 gg mass rotates in a vertical plane--call it the xy-plane with the y-axis pointing up--at the end of a 75-cmcm-long, massless, rigid rod. The other end of the rod is attached to a frictionless pivot at the origin.
What is the gravitational torque about the pivot when the mass is 60 ∘∘ above the +x-axis? Give your answer using unit vectors.
The gravitational torque about the pivot when the mass is 60 ∘∘ above the +x-axis is (0.1838 Nm)k
What is torque?Torque is the turning effect of a force which causes rotation. It is given by τ = F × d where
F = force and d = perpendicular distance of force from point of action.What is the gravitational torque about the pivot when the mass is 60° above the +x-axis?Since a 50 g mass rotates in a vertical plane--call it the xy-plane with the y-axis pointing up--at the end of a 75-cm-long, massless, rigid rod.
The gravitational torque is given by τ = F × d where
F = component of weight perpendicular to rod = -(mgcosФ)j where m = mass, g = acceleration due to gravityФ = angle between rod and x axis and d = length of rodSo, τ = F × d
= -(mgcosФ)j × di
= mgdcosФ(-j × i)
= -mgdcosФ(j × i)
= -mgdcosФ(-k)
= (mgdcosФ)k
Given that
m = 50 g = 0.05 kgg = 9.8 m/s²,d = 75 cm = 0.75 m and Ф = 60°Substituting the values of the variables into the equation, we have
τ = (mgdcosФ)k
= (0.05 kg × 9.8 m/s² × 0.75 m × cos60°)k
= (0.05 kg × 9.8 m/s² × 0.75 m × cos60°)k
= (0.3675 kgm²/s² × 0.5)k
= (0.18375 kgm²/s²)k
= (0.18375 Nm)k
≅ (0.1838 Nm)k
So, the torque is (0.1838 Nm)k
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Titan, the largest satellite of Saturn, has a thick nitrogen atmosphere. At its surface, the pressure is 1.5 Earth-atmospheres and the temperature is 94 K.
A) What is the surface temperature in ?
B) Calculate the surface density in Titan's atmosphere in molecules per cubic meter.
C) Calculate the density of Earth's atmosphere at 22 .
A) Surface temperature is the temperature at the surface.
B) The surface density in Titan's atmosphere in molecules per cubic meter is 1.17 x 10²¹ molecule/m³
C) The density of Earth's atmosphere is 0.0012 g/cm³
A) Surface temperature is the temperature at the surface, it can be defined differently for different surfaces:
Surface air temperature, air temperature near the earth's surface.
Sea surface temperature, the temperature of water near the surface of the ocean.
Global surface temperature, the combined global average of surface air temperature and sea surface temperature.
The surface temperature of the star, often the effective temperature.
B) According to the Gas equation, PV = nRT
P: pressure = 1.5 Earth-atmospheres = 1.5 atm
R: ideal gas constant = 8.205 m^3.atm.mol^-1.K^-1
T: temperature in Titan = 94K
n: number of moles
So as to calculate no. of moles per cubic meter N = (n/v) = (P/RT)
N' = N*A = (AP/RT)
A: Avogadro's number = 6.022*109^23 molecules/mol
N': molecules per cubic meter
By putting all the values in the formula,
N' so obtained is 1.17 x 10²¹ molecule/m³
C) The density of Earth's atmosphere 0.0012 g/cm³ or 1.217 kg/m³.
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the two weights are released from rest. the coefficient of kinetic friction between the horizontal surface and the 5 lb weight is 0.18
The final velocity of the weights will be 3.31 m/s
Weight = 5 lb
Coefficient of kinetic friction (µ) = 0.18
let T be tension
[tex]m_{1}[/tex]*g-T =[tex]m_{1}[/tex]*a
[tex]m_{1}[/tex] =10 lb = 4.53 kg
T-(µ)[tex]m_{2}[/tex]g =[tex]m_{2}[/tex]a
Adding both equations, we have
([tex]m_{1}[/tex]-k[tex]m_{2}[/tex])g =[tex]m_{2}[/tex] a
a = (4.53-0.2*2.26)*10/2.26 =18.04 [tex]m/s^{2}[/tex]
Using the equation of motion, we have,
[tex]v^{2} -u^{2} =2as[/tex]
Since the body starts from rest, the initial velocity, that is, u is zero.
So, u = 0 m/s
Putting this value in the above equation to calculate the final velocity, we have,
[tex]v^{2}[/tex] = 2as
v = [tex]\sqrt{(2*18.04*0.304) }[/tex]= 3.31 m/s
Thus, the final velocity of the weights will be 3.31 m/s
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Filed sdi as269len insbude sil velfs ovom
What distance will a bus go if it is traveling at a rate of 50 km/hr for 3.8
hours?
A. 190.0 kilometers
B. 53.8 kilometers
C. 46.2 kilometers
D. 13.2 kilometers
The distance the bus will go, if it is travelling at a rate of 50 km/hr for 3.8 hours is 190 kilometers (Option A)
How do I determine the distance the bus will go?We know that speed is defined as distance travelled per unit time i.e
Speed = Distance travelled / time
Cross multiply
Distance travelled = Speed × time
With the above formula, we can calculate the distance the bus will go. Details below:
Speed = 50 km/hr Time = 3.8 hoursDistance travelled =?Distance travelled = Speed × time
Distance travelled = 50 × 3.8
Distance travelled = 190 kilometers
Thus, we can conclude that the distance the bus will go is 190 kilometers (Option A)
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if you are in a car with a helium balloon in the middle of the back seat and you turn left, which way does the balloon move and why? physics.stackexchange
If you are in a car with a helium balloon in the middle of the back seat and you turn left, the balloon moves towards right.
A change in the air's surrounding density causes a helium-filled balloon to move.
The balloon operates in opposition to what your body would normally do. Therefore, if the automobile stops, the balloon will move to the back. The secret is that you are composed of materials that are significantly heavier than air and that the balloon is loaded with helium (He).
Turn left, the balloon goes right. When you turn right, the balloon moves to the left; when you stop, it moves to the right.
It has to do with the motion of the air in your car. When you start moving forward while stationary, all of the air in the car rushes to the back, where it builds up an area of higher air pressure.
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show an example of the method described above. ii. why might your calculated value for the half-life of barium-137 from this method differ from the accepted value?
By monitoring a sample's activity as it decays, Ba-137m can be calculated. Utilizing AktivLab, the radioisotope Ba-137half-life, m's which was isolated from Cs-137, is found.
How is the experiment's half-life determined?After that, the half-life is calculated using the basic concept of activity, which is the sum of the radionuclide decay constant,, and the number of radioactive atoms present, N. By using the formula = ln2/T1/2, one may solve for and obtain the half-life.
Describe half-life in detail.?A half-life is the duration needed for something to reduce in quantity by half. The phrase is most frequently used in reference to radioactive decay, which takes place when unstable atomic particles shed energy. There are 29 elements that can travel through this, according to known facts.
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large redshifts move the positions of spectral lines to longer wavelengths and change what can be observed from the ground. for example, suppose a quasar has a redshift of z
Laboratory experiments on Earth have examined that each element in the periodic table emits photons only at definite wavelengths (determined by the excitation state of the atoms).
These photons are manifest as either emission or absorption lines in the spectrum of an astronomical object, and by observing the position of these spectral lines, we can detect which components are present in the object itself or along the line of sight.
although, when astronomers observe spectral lines in extragalactic objects (such as galaxies and quasars), they find that the wavelength of the notice spectral lines is different from the laboratory experiments.
In most cases, the wavelength of the spectral lines is longer and thus are shifted toward the red end of the spectrum they are redshifted.
There are many explanations for this redshift phenomenon.
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