Which equation represents the line that passes through the point (5,7) and is parallel to the graph of y=2/3x-7?

To determine if the mean reduction in blood pressure is different between the two groups, you can use a statistical test such as a two-sample t-test. This test compares the means of two groups and determines whether the difference between the means is statistically significant.

To conduct the t-test, you will need the following information:

Once you have this information, you can use a statistical software or calculator to perform the t-test and determine the p-value. The p-value is a measure of the probability that the difference between the means is due to chance.

If the p-value is less than the level of significance (5% in this case), then the difference between the means is statistically significant and you can conclude that there is a significant difference in the mean reduction in blood pressure between the two groups.

If the p-value is greater than the level of significance, then the difference between the means is not statistically significant and you cannot conclude that there is a difference in the mean reduction in blood pressure between the two groups.

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A. Model is fitted using training dataset and E. Validation dataset is used to minimize model overfitting are true about machine learning algorithms

The process by which an AI system completes its task—generally, forecasting output values from provided input data—is known as a machine learning algorithm. Classification and regression are the two key operations of machine learning algorithms.

Simple linear regression, decision trees, logistic regression, the KNN algorithm, and other well-known supervised learning techniques are some examples.

Machine learning is crucial because it helps businesses identify trends in customer behaviour and operational patterns and facilitates the creation of new goods.

According to the question,

Option A and option E are correct about the machine learning algorithms

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Answer:

Hope this helps!

Step-by-step explanation:

for question 1, the change in y is the highest value takeaway the lowest value.

change in y = 10 - 1 = 9

change in x = 6 - (-3) = 9

9/9 = 1

therefore m = 1, this works for all the questions

The end behavior of the graph of the polynomial function:

As x approaches ∞, y approaches -∞

As x approaches -∞, y approaches ∞

What is an end behavior?

The behavior of the function graph at the "ends" of the x-axis is known as the end behavior of a function, or f.

Here, we have

f(x) = –x⁵ + 9x⁴ – 18x³

F(x) is a fifth-degree (odd function ) with a negative leading coefficient

If the exponent is odd and the leading coefficient is negative then the end behavior is

As x approaches ∞, y approaches -∞

As you go on the right, f(x) goes down

As x approaches -∞, y approaches ∞

As you go on the left, f(x) goes up.

Hence, the end behavior of the graph of the polynomial function: As x approaches ∞, y approaches -∞

As x approaches -∞, y approaches ∞

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Answer:

See below and attached graph

Step-by-step explanation:

If you are using a graphing calculator it is a breeze. You write down the equation as it is and it should plot it, depending on what calculator you use.

If you are doing this manually here are the steps
We are given y - 2 = 3(x-2)

Expand the brackets on the right hand side
3(x - 2) = 3x - 6

So the original equation becomes
y - 2 = 3x - 6

Adding 2 to both sides
y - 2 + 2 = 3x -6 + 2

y = 3x - 4   [1]

This form of equation is known as a slope-intercept form of the line

We need two points to plot a line. This can be done by choosing a value for x, finding the y value which gives one point. Then repeat for another value of x to get y for that value giving another point. Draw a straight line through both points

Point 1
Let's choose x = 2 and plug this into the equation [1]
y = 3·2 - 4 = 6- 4 = 2.
So (2, 2) is one point on the graph

Point 2

Choose another value for x, say x = 4

y = 3·4 - 4

y = 12-4

y = 8

So (4, 8) is another point

Draw a line through these two points

I'll go over problem 9 part (a) to get you started.

The sine rule, aka law of sines, is this

[tex]\frac{\sin(A)}{a} = \frac{\sin(B)}{b} = \frac{\sin(C)}{c}[/tex]

where the uppercase letters A,B,C are the angles and the lowercase letters a,b,c are the sides opposite those respective angles. Eg: angle B is opposite side b.

Some textbooks may have the lowercase letters up top, but it doesn't matter since it's the same ratio. All that matters is things stay consistent. The lowercase letters must be together on the same level, and same goes for the uppercase letters on their own separate level.

We can then break up that equation into these 3 separate equations, to make things more bite-sized so to speak.

[tex]\frac{\sin(A)}{a} = \frac{\sin(B)}{b}\\\\\frac{\sin(B)}{b} = \frac{\sin(C)}{c}\\\\\frac{\sin(A)}{a} = \frac{\sin(C)}{c}\\\\[/tex]

Let's focus on the 3rd equation and do a bit of algebraic manipulation like so

[tex]\frac{\sin(A)}{a} = \frac{\sin(C)}{c}\\\\\sin(A) = \frac{a\sin(C)}{c}\\\\\frac{\sin(A)}{\sin(C)} = \frac{a}{c}\\\\[/tex]

Through similar steps, we can say:

[tex]\frac{\sin(B)}{b} = \frac{\sin(C)}{c}\\\\\sin(B) = \frac{b\sin(C)}{c}\\\\\frac{\sin(B)}{\sin(C)} = \frac{b}{c}\\\\[/tex]

-------------------------------------------

To summarize the previous section, we found that:

[tex]\frac{\sin(A)}{\sin(C)} = \frac{a}{c}\\\\\frac{\sin(B)}{\sin(C)} = \frac{b}{c}\\\\[/tex]

It then allows us to do the following steps for problem 9, part (a)

[tex]\frac{a+b}{c} = \frac{\sin(A)+\sin(B)}{\sin(C)}\\\\\frac{a+b}{c} = \frac{\sin(A)}{\sin(C)}+\frac{\sin(B)}{\sin(C)}\\\\\frac{a+b}{c} = \frac{a}{c}+\frac{b}{c}\\\\\frac{a+b}{c} = \frac{a+b}{c}\\\\[/tex]

We have confirmed that the equation in problem 9 part (a) is indeed an identity. Take note how I kept the left hand side the same the entire time while the right hand side transformed into the left side.

Similar steps will be taken for problem 9, part (b). I'll let you do that part.

Answer:

Step-by-step explanation:

a) 1012⁵ can be written as:

1012⁵ = 15¹² + 05¹¹ + 1*5¹º

= 5¹² + 5¹º

= 3125 + 625

= 3750

(b) 101⁵ can be written as:

101⁵ = 15⁴ + 05³ + 1*5²

= 5⁴ + 5²

= 625 + 25

= 650

(c) 1.1⁵ can be written as:

1.1⁵ = 15¹ + 15º

= 5¹ + 5º

= 25 + 5

= 30

(d) 10.21⁵ can be written as:

10.21⁵ = 15² + 05¹ + 25º + 15⁻¹

= 5² + 2*5º + 5⁻¹

= 25 + 10 + 0.2

= 35.2

(e) 210⁵ can be written as:

210⁵ = 25⁴ + 15²

= 2*625 + 25

= 1250 + 25

= 1275

The central limit theorem's not needed when the original distribution is normal, the distribution of the sample mean is always normal in that case. So, option (a) is correct. If the sample size is reasonably large (for any population) is correct.

Given that,

The central limit theorem is important in statistics because it allows us to use the Normal distribution to find probabilities involving the sample mean,

In layman's words, the theorem asserts that regardless of the form of the initial population distribution, the sampling distribution of the mean tends to resemble a normal distribution as the sample size rises.

Statistics benefits from the Central Limit Theorem because it makes it safe to assume that the sampling distribution of the mean will be typically normal. As we will see in the next section, this means that we can benefit from statistical methods that presume a normal distribution.

The distribution of people's heights within a population is one illustration of how the central limit theorem is put to use. Even though the population's distribution of heights is not normal, when we sample this population, the distribution of the sample averages will be roughly normal.

Therefore,

The central limit theorem's not needed when the original distribution is normal, the distribution of the sample mean is always normal in that case. So, option (a) is correct. If the sample size is reasonably large (for any population) is correct.

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Answer:

The answer is (x + 10)

Step-by-step explanation:

(9x + 6) - (8x - 4)

9x + 6 - 8x + 4

Rearrange it

9x - 8x + 6 + 4

Combine like terms

x + 10

Thus, The answer is (x + 10)

Answer:

9

Step-by-step explanation:

3.4^0 = 1

9^1 = 9

1 * 9 = 9

Observing the nature of the provided equation and the degree of the polynomial , The answer is Cubic.

Sums of terms with the form  kxⁿ, where K is any number and N is a positive integer, are known as polynomials.

The highest degree of a polynomial's monomials (individual terms) with non-zero coefficients is referred to as the polynomial's degree in mathematics.

Expression : [tex]8x^{3}-1[/tex]

Degree of polynomial =3

The expression is a Cubic Expression.

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Observing the nature of the provided equation and the degree of the polynomial , The answer is Cubic.

Sums of terms with the form  kxⁿ, where K is any number and N is a positive integer, are known as polynomials.

The highest degree of a polynomial's monomials (individual terms) with non-zero coefficients is referred to as the polynomial's degree in mathematics.

Expression : 8x³ - 1

Degree of polynomial =3

The expression is a Cubic Expression.

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The correct statements regarding the transformations to the volumes are given as follows:

1. A cone's radius increases x 3: -> The cone's volume will increase x 9.

2. A cone's height increases x 3: -> The cone's volume will increase x 3

3. A sphere's radius increases x 3 -> The sphere's volume will increase x 27.

4. A cylinder's radius increases x 6 -> The cylinders volume will increase x 36.

The volume of a cone of radius r and height h is given as follows:

V = πr²h/3.

Then the scale factors are considered as follows:

The volume of an sphere of radius r is given as follows:

V = 4πr³/3.

Then when the radius is multiplied by 3, the volume is multiplied by 27, as 3³ = 27, and the radius is cubed in the equation.

The volume of a cylinder of radius r and height h is given as follows:

V = πr²h.

Then if the radius is multiplied by 6, the volume is multiplied by 36, as the variable r is squared in the equation for the volume.

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c. A greater proportion of adolescent girls with anorexia nervosa live in the South than live in the other regions when compared to the general US population.

Null Hypothesis, [tex]H_{0}[/tex] : All proportions are the same  

Alternative Hypothesis, [tex]H_{1}[/tex]: At least two of the proportions are not the same

The alternative and null are both population-based assertions. The reason for this is that the purpose of hypothesis testing is to draw conclusions about a population from a sample.

The null and alternative hypotheses are two competing claims that researchers weigh the evidence for and against using a statistical test:

Null hypothesis: There’s no effect on the population.

Alternative hypothesis: There’s an effect on the population.

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The interest accrued in the first four years is $1.69 and a half years is $0.21.

What is interest rate?

The amount that the lender charges the borrower above and beyond the principal amount is referred to as the interest rate. A person who deposits money in a bank or other financial institution also earns additional income in terms of the recipient, known as interest, taking into account the time value of money.

Given:

Jeff took out a 15 year unsubsidized loan for $9.800 to attend four years of college.

The rate is 4.3%.

We have to find the interest accrued in the first four-and-a-half years.

First to find the interest for first four years.

p = $9.800,  r  = 4.3% = 0.043,  t = 4

⇒ I = P x r x t

   I = 9.800 x 0.043 x 4

   I = 1.6856

   I = $1.69

Now to find the interest for a half years.

p = $9.800 ,  r = 4.3% = 0.043,  t = 1/2

I = p x r x t

I = 9.800 x 0.043 x 1/2

I = 0.2107

I = $0.21

Hence, the interest accrued in the first four years is $1.69 and a half years is $0.21.

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In the case where a=78, b=716, c=0.8, and d=14, the simplest form of a mixed number is -117/640.

The smallest equivalent fraction of the number is the form that is the simplest. How to find the most basic form: In the numerator and denominator, look for shared factors. Examine the fraction to see if one of the numbers is a prime number.

The term "reduced form" refers to the fraction's simplest form. As an illustration, the simplest form of a fraction with a common component of 1 is 34 However, while 2/4 can be further condensed and expressed as 12, it is not the most basic form.

When the top and bottom of a fraction cannot be any smaller while remaining whole numbers, it is said to be in its simplest form.

b a + c d

b= -7/16

a= 7/8

c= 08.(4/5)

d= 1/4

It can therefore be calculated as follows.

-7/16×7/8 + 4/5×1/4

-49/128 + 1/5

-246+128/640

= -117/640

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Answer:x+19-x+10 is equal to 29.

the measure of ∠LPM is 90°

the measure of ∠PMN is 102°

the length of LN is 10 units.

Define Rhombus.

A rhombus is a special case of a parallelogram, and it is a four-sided quadrilateral. In a rhombus, opposite sides are parallel and the opposite angles are equal.

For a Rhombus, LMNO

∠LON = 102°

NP = 5 units

By the properties of Rhombus, we know that

All sides of a rhombus are congruent (equal)

So, LM = MN = NO = OL

and

Opposite angles are equal and the opposite sides are parallel.

So, ∠LON = 102° = ∠LMN

Since Adjacent angles add up to 180°.

Therefore ∠L + ∠M = 180°

                 ∠M + ∠N = 180°

                 ∠N + ∠O = 180°

                 ∠O + ∠L = 180°

So, ∠N = 180° - ∠O = 180° - 102° =78°

      ∠L = 180° - ∠O = 180° - 102° =78°

      ∠M = 180° - ∠L = 180° - 78° =102°

Diagonals bisect each other at 90° or we can also say that each of the two diagonals in a rhombus is the perpendicular bisector of the other.

So, ∠LPM = ∠NP0 = ∠MPN = ∠LPO =90°

Thus, the measure of ∠LPM is 90°

         the measure of ∠PMN is 102°

         the length of LN is 10 units.

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Answer:

Lpm= 90

PMN=51

LN= 10

Step-by-step explanation:

Answer:

Y=6x-12

Step-by-step explanation:

whenever the X is at zero the number across from it is the Y-intercept. and to find the slope just count how much they are increasing or decreasing by.

According to Trigonometric Identity , tan(theta) = -5 / 13

Trigonometric Identities are equality statements that hold true for all values of the variables in the equation and that use trigonometry functions. The relationship between a triangle's side length and angle is expressed by a variety of specific trigonometric identities.

Sin, cos, and tan are the three fundamental trigonometric ratios. The reciprocals of sin, cos, and tan are represented by the three additional trigonometric ratios sec, cosec, and cot in trigonometry, respectively.

According to the given information

We know that

tan(theta) = 1/cot(theta)

                = 1 / -2.6

                = -1 / 2.6

                = -10 / 26

                = -5 / 13

According to Trigonometric Identity , tan(theta) = -5 / 13

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When tiles are drawn, with replacement, from a bag of lettered tiles, X is the number of vowels in 5 draws variable has binomial distribution

The possibility that a value would take one of two independent values given a particular combination of factors or assumptions is summarised by the statistical distribution known as the binomial distribution.

The basic presumptions of the binomial distribution are:

As opposed to a continuous distribution, like the normal distribution, the binomial distribution is a frequent discrete distribution used in statistics.

The probability of success raised to the power of the number of successes and the probability of failure raised to the power of the difference between the number of successes and the number of trials are multiplied to create the binomial distribution.

The result is then multiplied by the sum of the number of attempts and the number of successes.

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Using the two column proof, we have been able to prove that;

ΔPQR ≅ ΔTSR by AAS Congruency Postulate

A two-column proof is defined as a geometric proof that consists of a list of statements, and the reasons that we know those statements are true.

Thus, the two column proof required is as follows;

Statement 1: PR ≅ TR

Reason 1: Given

Statement 2: ∠PQR ≅ ∠TSR

Reason 2: Given

Statement 3: ∠PRQ ≅ ∠TRS

Reason 3: Opposite angles

Statement 4: ΔPQR ≅ ΔTSR

Reason 4: AAS Congruency postulate

AAS congruency postulate is one of the 5 major triangle congruency postulates that is defined as Angle-Angle-Side. This tells us that two angles and a non-included side of a triangle are equal to the corresponding angles and sides of another triangle, then the triangles are said to be congruent.

We can also say that Opposite angles are defined as the angles that are directly opposite each other where two lines cross. The intersection point in this regards is called the vertex, which is the point where the lines connect to form the angle. Opposite angles are also referred to as vertical angles

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The solution in inequality notation and in interval notation is (-∞ . -√5]∪[√5,36)

The term inequality refers the a relationship between two expressions or values that are not equal to each other is called 'inequality.

Here we have given the inequality (x² - 5)/ (x - 36) < 0

And we need to find the solution in inequality notation and in interval notation.

In order to find the inequality notation, we have to solve the given inequality, then we get.

(x² - 5)/ (x - 36) < 0

(x² - 5) < 0

x² < 5

x < √5

While we looking into the inequality we must know that the denominator must not be 0.

So, the interval notation can be written as,

=>  (-∞ . -√5]∪[√5,36)

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The equivalent expression for the given expression is 29/3.

Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value when we plug in the same value for the variable.

The given mixed fraction [tex]9\frac{2}{3}[/tex].

There are equivalent improper fractions for all mixed numbers. By multiplying the integer by the denominator and then adding the numerator, they are transformed. The numerator will not change.

Convert mixed fraction to improper fraction as follows

Improper fraction = [(Numerator × Denominator)+Numerator]/Denominator

[(9×3)+2]/3

=[27+2]/3

= 29/3

Therefore, the equivalent fraction for the given mixed fraction is 29/3.

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Answer: 1

Step-by-step explanation:

A 99% confidence interval for the true proportion of college students believing in ghosts is Option(c)  (0.4901, 0.6699)

According to the question,

A professor wanted to know what proportion of college students believe in ghosts.

For that he drawn a sample from the college.

Sample size : n = 200

Proportion of students that believed in ghosts in sample = 58%

=> p = 0.58

Proportion of students who does not believe in ghost : q = 1 - p

=> q = 0.42

We have to create a 99% confidence interval for a true proportion of college students believing in the ghosts

Formula of C.I = [tex]p \pm ( z_{\alpha} \sqrt{\frac{pq}{n}})[/tex]

Where p and q is sample proportion , z is value of CI at given α level of significance and n is sample size

C.I at 99% = 0.58 ± 2.576 √0.58×0.42/200

=> 0.58 ± 2.576 √0.001218

=>  0.58 ± 2.576 × 0.035

=> 0.58 ± 0.08958

C.I = ( 0.58 - 0.08958 , 0.58 + 0.08958)
=> C.I = (0.4901, 0.6699)

Hence, Option (c) is correct

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Answer:

41%

Step-by-step explanation:

So, the ordered pair which lies on the graph of the function y = -2x + 1 is (3,-5)

We will use the substitution method and check for all the ordered pair which are given

If the ordered pair lies on the graph, then it should satisfy the function.

So,

Given,

y = -2x+1

First check for (0,-2)

x=0, y=-2

Substitute the values,

y = -2x+1

-2=-2(0)+1

-2=1

It is false.

Next check for (2,-2)

x=2, y=-2

Substitute the values,

y = -2x+1

-2=-2(2)+1

-2=-3

It is false.

Next check for (3,-5)

x=3, y=-5

Substitute the values,

y = -2x+1

-5=-2(3)+1

-5=-5

It is true.

Next check for (5,2)

x=5, y=2

Substitute the values,

y = -2x+1

2=-2(5)+1

2=9

It is false.

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The value of y(0.4) is 1.04384484247985 using  Runge-Kutta method of fourth order .

What is  Runge-Kutta method of fourth order ?

The RK4 method, also known as the fourth-order Runge-Kutta method, is the Runge Kutta technique most frequently employed to get the answer to a differential equation. For a given point x, the Runge-Kutta technique returns an approximation of the value of y. The Runge Kutta RK4 method can only be used to solve first order ODEs.

The step size is h = 0.1

f(x,y) = (x²+y²)/10

Step 1:

x₁ = 0 + 0.1 = 0.1

k₁ =f(0,1) = 0.1

k₂ = f(1/20, 1.005) = 0.1012525

k₃ = f(1/20, 1.005062625) =0.101265088017189

k₄ = f(1/10, 1.01012650880172) = 0.103035556378395

y₁ = 1+ (1/10)/6 +(0.1 + 2⋅0.1012525 + 2⋅0.101265088017189 + 0.103035556378395) = 1.01013451220688

Step 2:

x₂ = x₁ + h = 1/5

k₁ =f(1/10,1.01013451220688)=0.103037173275143

k₂ = f(3/20,1.01528637087064) = 0.105330641487567

k₃ = f(3/20, 1.01540104428126) = 0.105353928072747

k₄ = f(1/5, 1.02066990501415) = 0.10817670550016

y₂ =1.01013451220688 + (1/10)/6 +(0.103037173275143 + 2⋅0.105330641487567 + 2⋅0.105353928072747 + 0.10817670550016) = 1.02067756250514

Step 3:

x₃ = x₂ + h = 3/10

k₁ =f(1/5, 1.02067756250514)=0.108178268660144

k₂ = f(1/4,1.02608647593815)=0.111535345610318

k₃ = f(1/4, 1.02625432978566)=0.111569794940382

k₄ = f(3/10, 1.03183454199918)=0.115468252206266

y₃ =1.02067756250514 + (1/10)/6 (0.108178268660144 + 2⋅0.111535345610318 + 2⋅0.111569794940382 + 0.115468252206266) = 1.03184184253794

Step 4:

x₄ = x₃ + h = 2/5

k₁ =f(3/10, 1.03184184253794) = 0.115469758801209

k₂ = f(7/20,1.037615330478)=0.119914557404297

k₃ = f(7/20, 1.03783757040816)=0.119960682255071

k₄ = f(2/5, 1.04383791076345)=0.1249597583947

y₄ = 1.03184184253794 + (1/10)/6 (0.115469758801209 + 2⋅0.119914557404297 + 2⋅0.119960682255071 + 0.1249597583947) = 1.04384484247985

y(0.4) ≈ 1.04384484247985

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The probability of selecting a white rabbit on the second draw, given that the first rabbit selected was a black rabbit is 3/5.

P(B∩W) = 1/4  getting a black and a white rabbit

P(B) = 5/12  getting a black rabbit

 P(W/B)

= P(B∩W) / P(B)

= (1/4) / (5/12)

= 12/20

= 3/5

Therefore, the conditional probability is 3/5.

Conditional probability is the chance of an event A occurring when another event B in relation to A has previously occurred. P(A|B) represents it. As seen in the picture above, S represents sample space, and A and B represent events.

The potential of an event or outcome occurring based on the existence of a preceding event or outcome is known as conditional probability. It is computed by multiplying the preceding event's probability by the renewed probability of the next, or conditional, occurrence.

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