I need help answering this ASAP

Answer:

0.236

Step-by-step explanation:

Given :

x1 = 667 ; n1 = 10 s1 = 20

x2 = 679 ; n2 = 14 s2 = 15

Test statistic :

(x1 - x2) / √[Sp² (1/n1 + 1/n2)]

The pooled Variance, Sp² :

Sp² = [(n1 - 1)s1² + (n2 - 1)s2²] / (n1 + n2 - 2)

Sp² = [(9*20²) + (13*15²)] / (10+14-2)

Sp² = 6525 / 22 = 296.59

T = (667 - 679) / √(296.59*(1/10 + 1/14)

T = -12 / 50.844

T = 0.236

Test statistic = 0.236

Answer:

$247

Step-by-step explanation:

$95 = 5 h

1 h = 95 ÷ 5 = $19/h

$19 × 13h = $247

she would make $247 after 13 hours of work.

Answer:

The area formula is= 1/2(a+b)×height

1/2×20×6=60metres squared

Step-by-step explanation:

kindly correct me if am wrong

Answer: Look it up on internet

Step-by-step explanation: INTERNET

Answer:

53 by 83.5.

just divided the two numbers by 1/4

Answer:

848 and 1336

Step-by-step explanation:

You would actually multiply 212 and 334 by 4.

You need to multiply 1/4 by 4 to get 1.

212 x 4 = 848

334 x 4 =1336

Answer:

4842.24 cubic feet

Step-by-step explanation:

Use the formula for the volume of a cone, V = [tex]\pi[/tex]r²[tex]\frac{h}{3}[/tex]

The diameter of the cone is 34 ft, so the radius is 17 ft.

Plug in the radius and height into the formula, and solve for the volume:

V = [tex]\pi[/tex]r²[tex]\frac{h}{3}[/tex]

V = [tex]\pi[/tex](17)²[tex]\frac{16}{3}[/tex]

V = [tex]\pi[/tex](289)[tex]\frac{16}{3}[/tex]

V = 4842.24

So, the volume of the cone is 4842.24 cubic feet

Answer:

4,841.32 ft³.

Step-by-step explanation:

Let’s assume that this is a right circular cone and that the radius of the cone is r.

For our problem, r = (1/2)d = (1/2)34 = 17.

The volume of the cone is:

V = (1/3)pi r^2 h, where r is the radius and h is the height.

So, V = (1/3)pi(17^2)16 = 4,841.32 ft³.

Answer:

7 x 4

Step-by-step explanation:

Let the width be x, length will be 3x-5. ATQ, x(3x-5)=28. x=4 and x=-7/3, since length isn't negative, x=4. Width=4 and length=7

Answer:

The answer is c because6X^3 minus 5X^3 is just X^3 and 3Y^2 plus 2Y^2 is 5Y^2.

Answer:

Step-by-step explanation:

For the question 1:

The given is a special right triangle with angle measures of

90-60-30 and side lengths represented by :

a - a[tex]\sqrt{3}[/tex] and 2a

The side length that sees 90 degrees is represented with a

The side length that sees 60 degrees is represented with a[tex]\sqrt{3}[/tex]

The side length that sees 30 degrees is represented with 2a

Here the side length that sees angle measure 60 is given as [tex]\sqrt{6}[/tex]

so a[tex]\sqrt{3}[/tex] =  [tex]\sqrt{6}[/tex] to find the value of a we divide  [tex]\sqrt{6}[/tex] with [tex]\sqrt{3}[/tex]

[tex]\frac{\sqrt{6} }{\sqrt{3} }[/tex] = [tex]\sqrt{2}[/tex]

so y = [tex]\sqrt{2}[/tex] and x = 2[tex]\sqrt{2}[/tex]

for second question

the square value of hypotenuse is equal to sum of other two side length's square value

10^2 + 6^2 = x^2

100 + 36 = x^2

136 = x^2

[tex]\sqrt{136}[/tex] = x

Answer:

C=6cm

D=3cm

Step-by-step explanation:

C=6×6cm

36cm

D=3×3cm

=9cm

Answer:

354°15'38.99''

Step-by-step explanation:

Answer:

1/120

Step-by-step explanation:

For the first letter, you have a 1/5 chance of getting w

On the second you have a 1/4 chance to get the r

Then 1/3 and 1/2

Next you just multiply the bottom numbers

That gives you how many diffrent outcomes there can be. Put that over 1 and you have your answer.

Hope this helps <3

Answer:

c is the answer

[tex] \frac{1}{16} [/tex]

Answer:

[tex]12a^3d^2-6ad^3[/tex]

To factor an integer, we need to divide it by the ascending sequence of primes 2, 3, 5

In the end, the number of times each prime divides the original integer becomes its exponent.

Prime number 2  to the power of 2 equals 4 .

Prime number 3 to the power of 1 equals 3 .

[tex]2^{2} \times 3\times a^{3} \times b^{2} -(2\times3)ad^{3}[/tex]

Result:-  [tex]6ad^2\left(2a^2-d\right)[/tex]

 OAmalOHopeO

Answer:

115

Step-by-step explanation:

You divide 230 by 2 cause there are two peoples. I hope that helps :)

Answer:

$147

Step-by-step explanation:

0.15x = $22.05

Divide both sides by 15

22.05/0.15 = $147

Answer:

[tex]\displaystyle a=4, b= \frac{25}{4}, \text{ and } k = \frac{125}{2}[/tex]

Step-by-step explanation:

Note that the graph passes through the points: (0, 4), (1, 25), and (1.5, k).

The standard exponential function has the form:

[tex]\displaystyle y = ab^x[/tex]

The point (0, 4) tells us that y = 4 when x = 0. Therefore:

[tex](4) = a(b)^0[/tex]

Since anything raised to zero is one:

[tex]a=4[/tex]

Hence, our function is now:

[tex]y = 4(b)^x[/tex]

The point (1, 25) tells us that y = 25 when x = 1. By substituting:

[tex](25) = 4(b)^{(1)}[/tex]

Solve for b:

[tex]\displaystyle b = \frac{25}{4}[/tex]

Thus, our completed function is:

[tex]\displaystyle y = 4\left(\frac{25}{4}\right)^x[/tex]

To find k, simply substitute 1.5 for x. This yields:

[tex]\displaystyle y = k = 4\left(\frac{25}{4}\right)^{(1.5)}[/tex]

And evaluate. Hence:

[tex]\displaystyle \begin{aligned} k &= 4\left(\frac{25}{4}\right)^{3/2} \\ \\ &= 4\left(\left(\frac{25}{4}\right)^{1/2}\right)^3 \\ \\ &= 4\left(\frac{5}{2}\right)^3 \\ \\ &= 4\left(\frac{125}{8}\right) \\ \\ &= \frac{125}{2}\end{aligned}[/tex]

In conclusion:

[tex]\displaystyle a=4, b= \frac{25}{4}, \text{ and } k = \frac{125}{2}[/tex]

Answer:

1:-

[tex]\\ \sf\longmapsto 23123+11001+21302[/tex]

[tex]\\ \sf\longmapsto 55426[/tex]

2:-

[tex]\\ \sf\longmapsto 21031+12301+32211[/tex]

[tex]\\ \sf\longmapsto 65543[/tex]

3:-

[tex]\\ \sf\longmapsto 21003+12346+21220[/tex]

[tex]\\ \sf\longmapsto 54569[/tex]

4:-

[tex]\\ \sf\longmapsto 32101+12301+1032[/tex]

[tex]\\ \sf\longmapsto 45434[/tex]

5:-

[tex]\\ \sf\longmapsto 301242+123310+10002[/tex]

[tex]\\ \sf\longmapsto 434554[/tex]

Answer:

8

Step-by-step explanation:

4×16=64

[tex] \sqrt{64 } = 8[/tex]

What's the question? I can try and help..

Answer:

15.534% decrease

Step-by-step explanation:

Find the new number of boys and girls on the honor roll:

56(0.75) = 42 boys

150(0.88) = 132 girls

Find the new total number of students on the honor roll:

42 + 132 = 174

Find the percent decrease by dividing the difference in the number of students by the original number.

There were originally 206 total students on the honor roll. Find the difference:

206 - 174 = 32

Divide this by the original amount:

32/206

= 0.15534

So, the number of students on the honor roll decreased by approximately 15.534%

Answer: 22

Step-by-step explanation:

−2−(3)(−2)(4)

=22

Answer:

A= π ( 3.8)^2

A= 45.36

OAmalOHopeO

Step-by-step explanation:

area is 2xr(times your answer)

The null and alternate hypotheses are

H0 : u = 0.44  vs   Ha: u > 0.44

Null hypothesis: 44% of readers own a personal computer.

Alternate Hypothesis : greater than 44% of readers own a personal computer.

This is one tailed test and the critical region for this one tailed test for the significance level 0.1 is  Z >  ±1.28

The given values are

p1= 0.54 , p2= 0.44 ; q2= 1-p2= 0.56

Using z test

Z = p1-p2/√p2(1-p2)/n

Z= 0.54-0.44/ √0.44*0.56/200

z= =0.1/ 0.03509

z=  2.849

Since the calculated value of Z=  2.849 is greater than Z= 1.28  reject the null hypothesis therefore there is sufficient evidence to support the executive's claim.

Null hypothesis is rejected

There is sufficient evidence to support the executive's claim at 0.10 significance level.

https://brainly.com/question/2642983

Answer:

g(x) = x² + 2x + 1

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Functions

Step-by-step explanation:

Step 1: Define

Identify

g(x) = f(x + 1)

f(x) = x²

Step 2: Find

Answer:

[tex](a)\ f(4) = v[/tex]

(b) There are 7 gallons left in the tank after 4 minuted

Step-by-step explanation:

Given

[tex]f(t) = v[/tex]

[tex]t \to[/tex] time since water began draining

[tex]v \to[/tex] gallons in the tank

Solving (a): Notation for gallons remaining at 4 minutes

This means that [tex]t=4[/tex]

[tex]f(t) = v[/tex] becomes

[tex]f(4) = v[/tex]

Solving (b): Interpret f(4) = 7

We have:

[tex]f(t) = v[/tex]

[tex]t \to[/tex] time since water began draining

[tex]v \to[/tex] gallons in the tank

This means that:

[tex]t =4[/tex]

[tex]v =7[/tex]

It can be interpreted as:

There are 7 gallons left in the tank after 4 minuted

Step-by-step explanation:

question 1

angle DBA=90°, meaning to find m<D you have to add 90+38 then subtract by 180, because ABD is a triangle

90+18+m<D=180

108+m<D=180

m<D=180-108

=72°

question 2

m<D again in this case angle ABD is also 90

m<D=180-(90+48)

=180-138

=42°

I hope this helps

Answer:

4

Step-by-step explanation:

Pick two points on the line

(0,-5)  and (1,-1)

We can find the slope using

m = (y2-y1)/(x2-x1)

   = ( -1 - -5)/(1 - 0)

  (-1+5)/(1-0)

    4/1

  = 4

Answer:

a) the probability that the defective board was produced during the first hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

b) the probability that the defective board was produced during the  last hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

c) the required probability is 0.2000

Step-by-step explanation:

Given the data in the question;

During a specific ten-hour period, one defective circuit board was found.

Lets X represent the number of defective circuit boards coming out of the machine , following Poisson distribution on a particular 10-hours workday which one defective board was found.

Also let Y represent the event of producing one defective circuit board, Y is uniformly distributed over ( 0, 10 ) intervals.

f(y) = [tex]\left \{ {{\frac{1}{b-a} }\\\ }} \right _0[/tex];   ( a ≤ y ≤ b )[tex]_{elsewhere[/tex]

= [tex]\left \{ {{\frac{1}{10-0} }\\\ }} \right _0[/tex];   ( 0 ≤ y ≤ 10 )[tex]_{elsewhere[/tex]

f(y) = [tex]\left \{ {{\frac{1}{10} }\\\ }} \right _0[/tex];   ( 0 ≤ y ≤ 10 )[tex]_{elsewhere[/tex]

Now,

a) the probability that it was produced during the first hour of operation during that period;

P( Y < 1 )   =   [tex]\int\limits^1_0 {f(y)} \, dy[/tex]

we substitute

=    [tex]\int\limits^1_0 {\frac{1}{10} } \, dy[/tex]

= [tex]\frac{1}{10} [y]^1_0[/tex]

= [tex]\frac{1}{10} [ 1 - 0 ][/tex]

= [tex]\frac{1}{10}[/tex] or 0.1000

Therefore, the probability that the defective board was produced during the first hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

b) The probability that it was produced during the last hour of operation during that period.

P( Y > 9 ) =    [tex]\int\limits^{10}_9 {f(y)} \, dy[/tex]

we substitute

=    [tex]\int\limits^{10}_9 {\frac{1}{10} } \, dy[/tex]

= [tex]\frac{1}{10} [y]^{10}_9[/tex]

= [tex]\frac{1}{10} [ 10 - 9 ][/tex]

= [tex]\frac{1}{10}[/tex] or 0.1000

Therefore, the probability that the defective board was produced during the  last hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

c)

no defective circuit boards were produced during the first five hours of operation.

probability that the defective board was manufactured during the sixth hour will be;

P( 5 < Y < 6 | Y > 5 ) = P[ ( 5 < Y < 6 ) ∩ ( Y > 5 ) ] / P( Y > 5 )

= P( 5 < Y < 6 ) / P( Y > 5 )

we substitute

 [tex]= (\int\limits^{6}_5 {\frac{1}{10} } \, dy) / (\int\limits^{10}_5 {\frac{1}{10} } \, dy)[/tex]

[tex]= (\frac{1}{10} [y]^{6}_5) / (\frac{1}{10} [y]^{10}_5)[/tex]

= ( 6-5 ) / ( 10 - 5 )

= 0.2000

Therefore, the required probability is 0.2000