Draw the parabola's axis of symmetry.

G(x)=2x+1 , vertical stretch by 2 units and shifted 1 unit up

Given :

Original function f(x)=x

To find :

Function G whose graph is a vertical stretch by 2  and move one unit up

We use the given function to for vertical stretch and shifting up

for Vertical stretch multiply the factor by f(x)

f(x) becomes  2f(x)

so the function becomes 2x

[tex]f(x)=2f(x)=2x\\[/tex]

For moving up , we need to add the units at the end of the function

f(x)+1

2x+1

Hence, G(x)=2x+1

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Answer:

x^2 +2x -6

Step-by-step explanation:

f(x)=2x+1

g(x)=x^2-7,

(f+g)(x) = 2x+1 + x^2 -7

Combine like terms

           = x^2 +2x -6

f (x) = 2x + 1

g (x) = x² - 7

(f+g) (x) = 2x+1 + x² - 7

Adding like terms

⇛ x² + 2x - 6

Answer:

B. 4/5

Step-by-step explanation:

Sin = Opposite/Hypotenuse

Sin∠A = 8/10 = 4/5

Answer:

A

Step-by-step explanation:

since there are 3 corresponding sides shown, the SSS similarity theorem can be utilized.

Answer:

8 hours 10 minutes

I hope this answers your question

Answer: paul has been away from home for 7 hours and 50 minutes.

Step-by-step explanation:

Answer:  Choice A

y=2x+3; y=-1/3x+3

==================================================

Explanation:

The left portion of the blue curve is y = 2x+3 but it is only graphed when x < 0 (we could argue that [tex]x \le 0[/tex] but I'll set that aside for the other portion).

The right portion is the line y = -1/3x + 3 and it's only graphed when [tex]x \ge 0[/tex]

So we could have this piecewise function

[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x < 0\\-\frac{1}{3}x+3 \ \text{ if } x \ge 0\\\end{cases}[/tex]

Or we could easily swap the "or equal to" portion to move to the first part instead like this

[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x \le 0\\-\frac{1}{3}x+3 \ \text{ if } x > 0\\\end{cases}[/tex]

Either way, we're involving the equations mentioned in choice A

9514 1404 393

Answer:

  D.) a+2b

Step-by-step explanation:

The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...

  A) 3(0) = 0 . . . even

  B) 1 +3 = 4 . . . even

  C) 2(1+0) = 2 . . . even

  D) 1 +2(0) = 1 . . . odd

_____

Additional comment

These rules apply to even/odd:

Then A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.

Answer:

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.

Step-by-step explanation:

There are mistakes in the statement, correct form is presented below:

[tex]5+\frac{\sqrt{3}}{7} + 2\sqrt{3} = a - b\cdot \sqrt{3}[/tex].

By direct comparison we have the following system of equations:

[tex]a = 5[/tex] (1)

[tex]\frac{\sqrt{3}}{7}+2\sqrt{3} = -b\cdot \sqrt{3}[/tex] (2)

In (2) we solve for [tex]b[/tex]:

[tex]\left(\frac{1}{7}+2 \right)\cdot \sqrt{3} = -b\cdot \sqrt{3}[/tex]

[tex]b = -\frac{15}{7}[/tex]

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.

Answer:

try 14n

Step-by-step explanation:

Answer:

[tex]r \: = 2sin2 \theta \\ = > r = 2.2sin\theta.cos\theta \\ = > r = 4sin\theta.cos\theta \: \\ \\ \sf \: we \: know \: that \: \\ x = r \: cos\theta \: \therefore \: cos\theta = \frac{x}{r} \\ \\ y = r \: sin\theta \: \therefore \: sin\theta = \frac{y}{r} \\ \\ \sf \: now \\ \\ r = 4 \times \frac{y}{r} \times \frac{x}{r} \\ = > {r}^{3 } = 4xy \\ \\ \sf \: again \: \: r = \sqrt{ {x}^{2} + {y}^{2} } \\ \\ = > {( \sqrt{ {x}^{2} + {y}^{2} } })^{3} = 4xy \\ = > {( {x}^{2} + {y}^{2} })^{ \frac{3}{2} } = 4xy \\ = > {( {x}^{2} + {y}^{2} })^{3} = 16 {x}^{2} {y}^{2} [/tex]

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Answer:

Step-by-step explanation:

Use the property of 30°-60°-90° right triangle.

The ratio of sides:

Compare with the given:

Apply the property of 30-90-60 angle

So

Answer:

The answer is 2.)

Step-by-step explanation:

Given initial velocity=135 ft/s

& cliff=76 foot

Given quadratic equation

⇒                      (let h=0 it is given)

⇒  

⇒  

⇒    t=8.96≈9 s (the other root is negative)

Hence, rocket will take 9 s to hit the ground after launched.

Answer:  Choice D

0 = 16t^2 + 135t + 76;  9 s

==============================================

Explanation:

The equation we start with is

[tex]h = -16t^2 + vt + c\\\\[/tex]

where v is the starting or initial velocity, and c is the starting height.

We're told that v = 135 and c = 76

We let h = 0 to indicate when the object hits the ground, aka the height is 0 ft.

That means the equation updates to [tex]0 = -16t^2 + 135t + 76\\\\[/tex]

Based on that alone, the answer is between A or D

-------------------

We'll use the quadratic formula to solve for t

We have

So,

[tex]t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\t = \frac{-135 \pm \sqrt{135^2 - 4(-16)(76)}}{2(-16)}\\\\t = \frac{-135 \pm \sqrt{23,089}}{-32}\\\\t \approx \frac{-135 \pm 151.9506}{-32}\\\\t \approx \frac{-135 + 151.9506}{-32} \ \text{ or } \ t \approx \frac{-135 - 151.9506}{-32}\\\\t \approx \frac{16.9506}{-32} \ \text{ or } \ t \approx \frac{-286.9506}{-32}\\\\t \approx -0.52971 \ \text{ or } \ t \approx 8.96721\\\\[/tex]

We ignore the negative t value because a negative time duration makes no sense.

The only practical solution here is roughly 8.96721 which rounds to 9.0 or simply 9 when we round to the nearest tenth (one decimal place).

In short, the object will hit the ground at the 9 second mark roughly. Or put another way: the object is in the air for about 9 seconds.

From this, we can see that the final answer is choice D.

Keep in mind that we aren't accounting for any wind resistance. Considering this variable greatly complicates the problem and requires much higher level mathematics. So we just assume that there is no wind at this moment.

Answer:

wyatt

Step-by-step explanation:

4:30 mins is 270 seconds

Answer:

-0.01

Step-by-step explanation:

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Answer:

-0.01

Step-by-step explanation:

Answer:

55 cm

Step-by-step explanation:

height = 4895/89 = 55 cm

Answer:

Find the domain by finding where the equation is defined.

Interval Notation:

(−∞,−4)∪(−4,7)∪(7,∞)

Set-Builder Notation:

{x|x≠−4,7}

Step-by-step explanation:

Answer:

all real numbers except x=-4 or x = 7

Step-by-step explanation:

The domain is the numbers that x can take

We have restrictions for this problem

the denominator cannot be zero

x^2 -3x-28 cannot be zero

(x-7)(x+4) ≠ 0

x-7≠0  x+4≠0

x≠7 x≠-4

Otherwise all real numbers are valid

Answer:

Does the answer help you?

Answer:

1.9

Step-by-step explanation:

You round when the numbers behind the decimal are 5 or greater. This being said, you need to round from the number furthest away from the decimal. In this case it would be 9. 9 is greater than 5 so we round 8 up to 9 and get rid of the number behind it. We are left with 1.9

Refer the attached image for the answer

HOPE SO IT HELPS YOU

Answer:[tex]\huge \boxed{x=180-26-90=64}[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

You have the angels 180, 26, 90(right angle) and x. So when you add them all up you should get 360 because there aren’t two straight lines. Only line makes a 180 angle. So...

180 + 26 + 90 + x = 360

296 + x = 360

x = 360 - 296

x = 64

Answer:

(a+b)³=a³+3a²b+3ab²+b³

Answer:

Step-by-step explanation:

Hello!

(a+b)(a+b)(a+b)

(a+b)(a+b) = a²+2ab + b²

(a²+2ab + b²) (a+b)=

a³ + a²b +  2a²b + 2ab² + ab² + b³ =

a³ + b³ +  2a²b + 2ab² + ab²  + a²b

Answer:

b-8=9

b=9+8

b=17

Step-by-step explanation:

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Answer:

b=17

Step-by-step explanation:

b-8=9

first isolate the variable by adding 8 to both sides

this gives us

b=17

Answer:

she baked 3 times as many cranberry than blueberry muffins

Step-by-step explanation:

i think that because 9×3=27

the amount of the cranberry muffins are 9

Answer:

22 m/s

Step-by-step explanation:

Take the distance and divide by the time

1210 m/55s

22 m/s

Answer:

Step-by-step explanation:

[tex]speed = \frac{distantce}{time} \\ = \frac{1210m}{55s} \\ = 22m {s}^{ - 1} [/tex]

Answer:

26

Step-by-step explanation:

Answer:

26

Step-by-step explanation:

(g•h)(x) = 2(x²+4)

(g•h)(3)=2(3²+4)

=2(9+4)

=2(13)

=26

Answer: the answer to your question is 7

Step-by-step explanation:

Answer:

9x^2 + 2x - 5

Step-by-step explanation:

7x^2 - 5x + 3

2x^2 + 7x - 8

__________

9x^2 + 2x - 5

Option B is the correct answer.

Answer:

B

Step-by-step explanation:

here we use trigonometric ratio involving soh,cah,toa

Answer:

The cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.

Step-by-step explanation:

Given that Sayad bought a watch and sold to Dakshes at 10% profit, and Dakshes again sold it to Sahayata for $ 6,050 at 10% profit, to find the cost price of Dakshes and the cost price of Sayad the following calculations must be performed:

6,050 / 1.1 = X

5,500 = X

5,500 / 1.1 = X

5,000 = X

Therefore, the cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.

Answer:

m

Step-by-step explanation:

Answer:

c) 21

Step-by-step explanation:

[tex] \sqrt{169} + \sqrt{64} [/tex]

13+8

answer is 21