Answer:
Hello,
[tex]\boxed{y'=2-\dfrac{200}{x^2} }\\[/tex]
Step-by-step explanation:
[tex](f(x)+g(x))'=f'(x)+g'(x)\\\\(2x)'=2*(x)'=2*1=2\\\\(\dfrac{200}{x} )'=200*(x^{-1})'=200*(-1)*x^{-1-1})=-\dfrac{200}{x^2} \\\\\\\boxed{y'=2-\dfrac{200}{x^2} }\\[/tex]
Answer:
[tex] \frac{dy}{dx } = 2 - \frac{200}{ {x}^{2} } [/tex]
Step-by-step explanation:
[tex]the \: equation \: can \: be \: rewriten \: as \\ y = 2x + 200 {x}^{ - 1} \\ \\ now \: differentiate \: the \: equation\ \\ \frac{dy}{dx} = 2 - 200 {x}^{ - 2} \\ \frac{dy}{dx} = 2 - \frac{200}{ {x}^{2} } [/tex]
Clara made two investments. Investment A has an initial value of $500 and
increases by $45 every year. Investment B has an initial value of $300 and
increases by 10% every year. Clara checks the value of her investments once a
year, at the end of the year. What is the first year in which Clara sees that
Investment B's value has exceeded investment A's value?
Answer:
The first year in which Clara will see that Investment B's value will exceed Investment A's value will be year 14.
Step-by-step explanation:
Since Clara made two investments, and Investment A has an initial value of $ 500 and increases by $ 45 every year, while Investment B has an initial value of $ 300 and increases by 10% every year, and Clara checks the value of her investments once to year, at the end of the year, to determine what is the first year in which Clara sees that Investment B's value has exceeded investment A's value, the following calculation must be performed:
500 + (45 x X) = A
300 x 1.1 ^ X = B
A = 500 + 45 x 5 = 500 + 225 = 725
B = 300 x 1.1 ^ 5 = 483.15
A = 500 + 45 x 10 = 950
B = 300 x 1.1 ^ 10 = 778.12
A = 500 + 45 x 15 = 1175
B = 300 x 1.1 ^ 15 = 1253.17
A = 500 + 45 x 14 = 1,130
B = 300 x 1.1 ^ 14 = 1,139.25
Therefore, the first year in which Clara will see that Investment B's value will exceed Investment A's value will be year 14.
A wire is to be cut into two pieces. One piece will be bent into an equilateral triangle, and the other piece will be bent into a circle. If the total area enclosed by the two pieces is to be 64 m2, what is the minimum length of wire that can be used? What is the maximum length of wire that can be used?
(Use decimal notation. Give your answer to one decimal place.)
⠀⠀⠀⠀⠀⠀⠀⠀⠀Stolen from GoogIe :p
The minimum length of wire needed is approximately 22.5 meters and the maximum length of wire needed is also approximately 22.5 meters.
How to get the Length?Let's assume the length of the wire is "L" meters. We need to find the minimum and maximum values of L that satisfy the given conditions.
To find the minimum length of wire needed, we should minimize the combined area of the equilateral triangle and the circle. The minimum occurs when the wire is distributed in a way that maximizes the area of the circle while minimizing the area of the equilateral triangle.
Minimum length (L_min):
Let "x" be the length of the wire used to form the equilateral triangle, and "y" be the length used to form the circle.
The area of an equilateral triangle is given by (√(3)/4) * side², where the side is the length of one of the triangle's equal sides.
The area of a circle is given by π * radius².
Since the perimeter of an equilateral triangle is three times the length of one of its sides, and the circumference of a circle is given by 2 * π * radius, we have:
x + y = L ...(1) (The total wire length remains constant)
x = 3 * side ...(2) (Equilateral triangle perimeter)
y = 2 * π * r ...(3) (Circle circumference)
The area enclosed by the two pieces is given by:
Area = (√(3)/4) * side² + π * r²
We want to minimize this area subject to the constraint x + y = L.
To find the minimum, we can use the method of Lagrange multipliers.
By solving this optimization problem, we find that the minimum value of the combined area is approximately 64 m² when x ≈ 7.5 m and y ≈ 15 m. Thus, the minimum length of wire needed (L_min) is approximately 7.5 + 15 = 22.5 meters.
Maximum length (L_max):
To find the maximum length of wire needed, we should maximize the combined area of the equilateral triangle and the circle. The maximum occurs when the wire is distributed in a way that minimizes the area of the circle while maximizing the area of the equilateral triangle.
By solving this optimization problem, we find that the maximum value of the combined area is approximately 64 m² when x ≈ 15 m and y ≈ 7.5 m. Thus, the maximum length of wire needed (L_max) is approximately 15 + 7.5 = 22.5 meters.
So, the minimum length of wire needed is approximately 22.5 meters, and the maximum length of wire needed is also approximately 22.5 meters.
Learn more about maximum length here: https://brainly.com/question/32886114
#SPJ2
what is the measure of m?
The required value of m for the given triangle is given as m = 12.
What are Pythagorean triplets?In a right-angled triangle, its sides, such as hypotenuse, and perpendicular, and the base is Pythagorean triplets.
Here,
Applying Pythagoras' theorem,
n² = m² - 6² - - - - (1)
m ² + base² = 24²
base² = 24² - m² - - - - (2)
n² + 18² = base²
From equation 1 and 2
m² - 6² + 18² = 24² - m²
2m² = 24² + 6² - 18²
m = 12
Thus, the required value of m for the given triangle is given as m = 12.
Learn more about Pythagorean triplets here:
brainly.com/question/22160915
#SPJ2
PLEASE HELP, WILL GIVE BRAINLIEST!!!
Find the inverse of f(x)=6x-4
and find f^-1(62)
Step-by-step explanation:
swap the variables:
y=6x−4 becomes x=6y−4.
Now, solve the equation x=6y−4 for y.
y=x+46 is the inverse function
f^-1(62)
substitude x=62
y=x+46
y= 62+46
y=108
f^-1(62)=108
brainliest please~
Describe how to determine the average rate of change between x=4 and x=6 for the function f(x)=2x^3+4. Include the average rate of change in your answer.
Answer:
Step-by-step explanation:
Average rate of change is the same thing as the slope of the line between 2 points. What we have are the x values of each of 2 coordinates. What we don't have are the y values that go with those. But we can find them! Aren't you so happy?
We can find the y value that corresponds to each of those x values by evaluating the function at each x value, one at a time. That means plug in 4 for x and solve for y, and plug in 6 for x and solve for y.
[tex]f(4)=2(4)^3+4[/tex] and doing the math on that gives us
f(4) = 132 and the coordinate is (4, 132).
Doing the same for 6:
[tex]f(6)=2(6)^3+4[/tex] and doing the math on that gives us
f(6) = 436 and the coordinate is (6, 436). Now we can use the slope formula to find the average rate of change (aka slope):
[tex]m=\frac{436-132}{6-4}=\frac{304}{2}=152[/tex] where m represents the slope
A Gallup survey of 2322 adults (at least 18 years old) in the U.S. found that 408 of them have donated blood in the past two years. Construct a 90% confidence interval for the population proportion of adults in the U.S. who have donated blood in the past two years.
Answer:
The 90% confidence interval for the population proportion of adults in the U.S. who have donated blood in the past two years is (0.1627, 0.1887).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
A Gallup survey of 2322 adults (at least 18 years old) in the U.S. found that 408 of them have donated blood in the past two years.
This means that [tex]n = 2322, \pi = \frac{408}{2322} = 0.1757[/tex]
90% confidence level
So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1757 - 1.645\sqrt{\frac{0.1757*0.8243}{2322}} = 0.1627[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1757 + 1.645\sqrt{\frac{0.1757*0.8243}{2322}} = 0.1887[/tex]
The 90% confidence interval for the population proportion of adults in the U.S. who have donated blood in the past two years is (0.1627, 0.1887).
Complete the square to form a true equation;
x^2-3/4x+__ = (x-__)^2
Answer: x² - (3/4)x + 9/64 = (x + 3/8)²
Step-by-step explanation:
Concept:
Here, we need to know the idea of completing the square.
Completing the square is a technique for converting a quadratic polynomial of the form ax²+bx+c to the form (x-h)²for some values of h.
If you are still confused, please refer to the attachment below for a graphical explanation.
Solve:
If we expand (x - h)² = x² - 2 · x · h + h²
Given equation:
x² - (3/4)x +___ = (x - __)²Since [x² - (3/4)x +___] is the expanded form of (x - h)², then (-3/4)x must be equal to 2 · x · h. Thus, we would be able to find the value of h.
(-3/4) x = 2 · x · h ⇔ Given-3/4 = 2 · h ⇔ Eliminate xh = -3/8 ⇔ Divide 2 on both sidesFinally, we plug the final value back to the equation.
x² - 2 · x · h + h² = (x - h)²x² - (3/4)x + (-3/8)² = (x + 3/8)²x² - (3/4)x + 9/64 = (x + 3/8)²Hope this helps!! :)
Please let me know if you have any questions
Help?? Please “Use a benchmark to compare 4/7 and 2/10”
Answer:
4/7 > 2/10
Step-by-step explanation:
4/7 is close to 1/2
2/10 is close to 0
4/7 > 2/10
Evaluate each expression.
HELP!!!!!!!!!!!!!
Answer:
Step-by-step explanation:
The residents of a city voted on whether to raise property taxes. The ratio of yes to no votes was 7 to 5. If there were 4115 no votes, what was the total number of votes?
Answer:
9876
Step-by-step explanation:
7:5
x:4115
To find x mulitply 7 by 823 (because this is what we multiplied 5 by in order to get 4115)
7*823= 5761
Take the sum to find the total number of votes
4115+5761= 9876
Hey, I’m new to this app i download the app today, and i hope if is there people who can help me with this question in the picture above!!
Step-by-step explanation:
For a quadratic equation, the second differences will always be the same.
First, we must calculate the first differences between the output, or the y values. This can be calculated as shown, taking the first value and subtracting the second value from that (e.g. 34 - 17 = 17, and 1-2 = -1):
34 17 6 1 2 9 22
\ / \ / \ / \ / \ / \ /
17 11 5 -1 -7 -13
The second differences are the differences between the differences we just calculated. This can be calculated as shown:
17 11 5 -1 -7 - 13
\ / \ / \ / \ / \ /
6 6 6 6 6
The second differences are all 6, and as a result, we can verify that this is a quadratic relation
Consider the function ƒ(x) = (x + 1)2 – 1. Which of the following functions stretches ƒ(x) vertically by a factor of 4?
A) ƒ(x) = 1∕4(x + 1)2 – 4
B) ƒ(x) = (1∕4x + 1)2 + 3
C) ƒ(x) = 4(x + 1)2 – 1
D) ƒ(x) = 4(4x + 1)2 – 1
Answer:
C f(x) = 4(x+1)2-1
Step-by-step explanation:
factor of 4 = 2^2
(x+1)2-1 = 4(x+1) 2-1 = with x
= 4(+1) 2-1 = without x
= (4 - 4) 2 = individual products of -1
= (8 - 8 ) = individual products of 2
= 8 - 8 = 2^2 -2^2
= 2^2 - 2^2
(x+1)2-1 = 4(x+1)2-1 = with x
= 2x^2 -2^2
-x = 2^2 -2^2
x = -2^2-2^2
x = 4
which proves f(x) is a factor of 4
The number of animals at a shelter from day to day has a mean of 37.6, with a standard deviation of 6.1 animals. The distribution of number of animals is not assumed to be symmetric. Between what two numbers of animals does Chebyshev's Theorem guarantees that we will find at least 89% of the days
Answer:
Between 19.3 and 55.9 animals.
Step-by-step explanation:
Chebyshev Theorem
The Chebyshev Theorem can also be applied to non-normal distribution. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].
In this question:
Mean of 37.6, standard deviation of 6.1.
Between what two numbers of animals does Chebyshev's Theorem guarantees that we will find at least 89% of the days?
Within 3 standard deviations of the mean, so:
37.6 - 3*6.1 = 19.3
37.6 + 3*6.1 = 55.9
Between 19.3 and 55.9 animals.
The sum of a number and twice its square is 105. Find the number.
Suppose you just received a shipment of seven televisions. Four of the televisions are defective. If two televisions are randomly selected, compute the probability
that both televisions work. What is the probability at least oone of the two televisions does not work?
The probability that both televisions work is
(Round to three decimal places as needed.).
The probability that at least one of the two televisions does not work is
(Round to three decimal places as needed.)
e
Answer:
- What is the probability at least one of the two televisions does not work?
The probability at least one of the two televisions does not work is 0.8163
- The probability that both televisions work is?
The probability that both televisions work is 0.1837
Step-by-step explanation:
Total televisions are 7
Faulty televisions are 4
Number of televisions selected is 2
You are installing new carpeting in a family room. The room is rectangular with dimensions 20 1/2 feet × 13 1/8 feet. You intend to install baseboards around the entire perimeter of the room except for a 3 1/2-foot opening into the kitchen. How many linear feet of board must you purchase?
Answer: 1. When you estimate, it is not an exact measurement. 3ft 8 in gets rounded to 4ft and 12 ft 3 in rounds to 12ft. now find the perimeter. P=2l+2w P= 2*12 +2*4 P=32feet
2. 3ft 8in = 3 8/12 or reduced to 3 2/3 12ft 3in = 12 3/12 or reduced to 12 1/4 The fractional part is referring to a fraction of a foot.
3. The perimeter of the room is P=2l+2w or P=2(12 1/4) + 2(3 2/3) p=24 1/2 + 7 1/3 P= 31 5/6 feet
4. The estimate and the actual are very close. They are 1/6 of a foot apart.
5a. Total baseboard 31 5/6ft - 2 1/4 ft = 29 7/12 feet needed.
5b. Take the total and divide it by 8ft = 29 7/12 divided by 8= 3.7 You are not buying a fraction of a board so you would need 4 boards.
14 ft
3 ft
6 ft
O 87
1313
252ft
0 262
52.31
Answer:
35
Step-by-step explanation:
19. Which of the following
statements is true about
angle K?
K
R
a. Angle K is obtuse
b. angle K is acute
C. angle K is greater than
90
d. angle K is a right angle
9514 1404 393
Answer:
b. angle K is acute
Step-by-step explanation:
We're often told not to draw any conclusions from the appearance of a figure in a geometry problem. Here, angle K appears to be somewhat less than 90°, so angle K is acute.
__
Additional comment
This choice of answer is confirmed by the fact that the other two (visible) choices say the same thing. If one of them is correct, so is the other one. Hence they must both be incorrect. (An obtuse angle is more than 90°.)
What are the equations of the asymptotes for the functiony=tan2pix where 0
9514 1404 393
Answer:
(b) x = 0.25, 0.75, 1.25, 1.75
Step-by-step explanation:
The asymptotes of tan(α) are found at ...
α = π/2 +nπ
We want to find x such that ...
2πx = α = π/2 +nπ
Dividing by 2π gives ...
x = 1/4 +n/2 . . . . . . . for integers n
In the desired range, the values of x are ...
x = 0.25, 0.75, 1.25, 1.75
What value of x makes the equation 3x+7=22 true?
Answer:
[tex]x=5[/tex]
Step-by-step explanation:
Given [tex]3x+7=22[/tex], our goal is to isolate [tex]x[/tex] such that will have an equation that tell us [tex]x[/tex] is equal to something.
Start by subtracting 7 from both sides:
[tex]3x+7-7=22-7,\\3x=15[/tex]
Divide both sides by 3:
[tex]\frac{3x}{3}=\frac{15}{3},\\x=\frac{15}{3}=\boxed{5}[/tex]
Therefore, the value of [tex]x=5[/tex] makes the equation [tex]3x+7=22[/tex] true.
Answer:
x = 5
Step-by-step explanation:
Subtract 7 from both sides: 3x + 7- 7 = 22 - 7
Simplify: 3x = 15
Divide both sides by 3
Simplify: x = 5
Hope this helps:)
Jul
attachments.office.net
6
7
A car journey is in two stages.
Stage 1 The car travels 110 miles in 2 hours.
Stage 2 The car travels 44 miles at the same average speed as Stage 1
Work out the time for Stage 2
Give your answer in minutes.
[3 m
9514 1404 393
Answer:
48 minutes
Step-by-step explanation:
Since the speed is the same for Stage 2, the time is proportional to the distance.
t2/(44 mi) = (120 min)/(110 mi)
t2 = (44/110)(120 min) = 48 min . . . . . . multiply by 44 mi
The time for Stage 2 was 48 minutes.
plssss
How much fat is in a mixture created
with x pints of 8% butterfat and y pints
of 15% butterfat?
Answer:
0.08x + 0.15y
Step-by-step explanation:
multiply the amount of pints with the given percent of fat
Answer:
Hence total fat in mixture is 8x+15y100 pints
A fruit company delivers its fruit in 2 types of boxes: large and small. A delivery of 3 large boxes and 5 small boxes has a total weight of 79 kilograms. A delivery of 12 large boxes and 2 small boxes has a total weight of 199 kilograms. How much does each type of box weight?
9514 1404 393
Answer:
large: 15.5 kgsmall 6.5 kgStep-by-step explanation:
Let x and y represent the weights of the large and small boxes, respectively. Then the two delivery weights give rise to the equations ...
3x +5y -79 = 0
12x +2y -199 = 0
Using the "cross multiplication method" of solving these equations, we find ...
d1 = (3)(2) -(12)(5) = 6 -60 = -54
d2 = 5(-199) -(2)(-79) = -995 +158 = -837
d3 = -79(12) -(-199)(3) = -948 +597 = -351
1/d1 = x/d2 = y/d3
x = d2/d1 = -837/-54 = 15.5
y = d3/d1 = -351/-54 = 6.5
The large boxes weigh 15.5 kg; the small boxes weigh 6.5 kg.
_____
Additional comment
My preferred quick and easy way to solve equations like this is using a graphing calculator. In addition to that, an algebraic method is shown.
The "cross-multiplication method" shown here is what I consider to be a simplified version of what you would find in videos. It is a variation of Cramer's rule and the Vedic maths methods of solving pairs of linear equations. I find it useful when "elimination" or "substitution" methods would result in annoying numbers. In such cases, it uses fewer arithmetic operations than would be required by other methods.
Short description: writing the coefficients of the general form equations in 4 columns, where the last column is the same as the first, a "cross multiplication" is computed for each of the three pairs of columns. Those computations are of the form ...
[tex]\text{column pair: }\begin{array}{cc}a&b\\c&d\end{array}\ \Rightarrow\ d_n=ad-cb[/tex]
The relationship between the differences d₁, d₂, and d₃ and the variable values is shown above.
HELP PLS DUE IN 6 MINUTES
6TH GRADE MATH
Answer:
C
Step-by-step explanation:
trust me its easy
Answer:
C: None of the above
Step-by-step explanation:
Please help, will give brainliest!!!!!
Answer:
third option
Step-by-step explanation:
Brainliest please~
Does the point (6, 0) satisfy the equation y = x2?
Replace x in the equation with the x value of the point (6) and solve. If it equals the y value (0) it is a solution if it noes not equal (0) it is not a solution.
Y = 6^2 = 36
36 is not 0 so (6,0) is not a solution
Answer:
No, point (6, 0) is not on the equation.
Step-by-step explanation:
To do this question the easiest way, you would use your scientific/graphing calculator and type in your equation. But you can do this with your mind.
Since the equation y = x^2 does not have any number in it (such as m = slope) it does not start anywhere. You will put it in the origin which is (0, 0) from there, you can tell that the equation will not reach (6, 0), but only (1, 1).
please help me with these question.
Answer:
1. B
2. C
Step-by-step explanation:
Solve for x. WILL GIVE BRAINIEST
Answer:
x≤16
Step-by-step explanation:
1/2x - 3 ≤5
Add 3 to each side
1/2x -3+3 ≤5+3
1/2x≤8
Multiply each side by 2
1/2x*2 ≤8*2
x≤16
the legs of a right triangle have the following measurements: 5 and 10 inches. What is the length of the hypotenuse??
Write your answer in SIMPLIFIED SQUARE ROOT FORM
Answer:
[tex]5\sqrt{5}[/tex]
Step-by-step explanation:
1. [tex]5^2 + 10^2 = c^2[/tex]
2.[tex]125 = c^2[/tex]
3. [tex]c=5\sqrt{5}[/tex]
Find dy/dx given that y = sin x / 1 + cos x
Answer:
[tex] \frac{1}{1 + \cos(x) } [/tex]
Step-by-step explanation:
[tex]y = \frac{ \sin(x) }{1 + \cos(x) } [/tex]
differentiating numerator wrt x :-
(sinx)' = cos x
differentiating denominator wrt x :-
(1 + cos x)' = (cosx)' = - sinx
Let's say the denominator was "v" and the numerator was "u"[tex] (\frac{u}{v} )' = \frac{v. \: (u)' - u.(v)' }{ {v}^{2} } [/tex]
here,
since u is the numerator u= sinx and u = cos x v(denominator) = 1 + cos x; v' = - sinx[tex] = \frac{((1 + \cos \: x) \cos \: x )- (\sin \: x. ( - \sin \: x) ) }{( {1 + \cos(x)) }^{2} } [/tex]
[tex] = \frac{ \cos(x) + \cos {}^{2} (x) + \sin {}^{2} (x) }{(1 + \cos \: x) {}^{2} } [/tex]
since cos²x + sin²x = 1
[tex] = \frac{ \cos \: x + 1}{(1 + \cos \: x) {}^{2} } [/tex]
diving numerator and denominator by 1 + cos x
[tex] = \frac{1}{1 + \cos(x) } [/tex]
