been working on this for a while and can’t figure it out, can someone help?

Answer:

0.83

Step-by-step explanation:

volume = length*height*width

1500=L*30*60

1500=1800L

1500/1800 = 0.83

length = 0.83

Comparing the numbers, it is found that the tenths value first determines which of the numbers 6.399 or 6.400 is the larger number.

The decimal numbers are 6.399 and 6.400.

The tenths digit is the first in which there is a difference, hence, it determines which of the numbers 6.399 or 6.400 is the larger number.

A similar problem is given at https://brainly.com/question/17248958

Answer:

21417500

Step-by-step explanation:

Calculate 50% of the given amount then 13% of result

50% of 329500000

= [tex]\frac{50}{100}[/tex] × 329500000

= 0.5 × 329500000

= 164750000

Then

13% of 164750000

= [tex]\frac{13}{100}[/tex] × 164750000

= 0.13 × 164750000

= 21417500

Answer:

Quadratic

Step-by-step explanation:

Formula: ax^2+bx+c

Answer:

y=1/2x

Step-by-step explanation:

I first did point-slope form which is

y+1=1/2(x-2)

Then, I converted it into slope-intercept form which is

y=1/2x

Answer:cold weather pose, there are armies that have and can conduct large-scale, ... to one inch (2.5 centimeters) per hour accumulates.

Step-by-step explanation:

Answer:

1.5 × ? = 9

9÷1.5 = 6

so the answer would be 6 hours

2x = x - 4

2x - x = - 4

x = - 4

________

Hope it helps ⚜

Answer:

x=-4

Step-by-step explanation:

2x=x-4

2x-x=-4

x=-4

Proof

2*(-4)=-4-4

-8=-8

Answer:

Step-by-step explanation:

This is a geometric series.

First term = - 2

Ratio = second term ÷ first term = 8 ÷ (-2) = -4

Next three terms are:

-32 *(-4) = 128

128*(-4) = - 512

-512*(-4) = 2048

Answer:

The next 3 terms would be 128, -512, 2048

Step-by-step explanation:

Since we are dealing with a Geometric Sequence we use this formula [tex]a_{n}=a_{1} *r^{n-1}[/tex]

Since the first term([tex]a_{1}[/tex]) is -2 and for us to find R we have to divide 8 by -2 = -4

So we would rewrite the equations to find the next three terms as

[tex]a_{4}=-2*-4^{4-1}=-2*-4^3=128[/tex]

[tex]a_{5}=-2*-4^{5-1}=-2*-4^4=-512[/tex]

[tex]a_{6}=-2*-4^{6-1}=-2*-4^5=2048[/tex]

https://www.algebra.com/algebra/homework/Circles/Circles.faq.question.407869.html

Answer:

12 cups

Step-by-step explanation:

There are 48 hours in two days.

48 · 2 = 96 ( 2 being fluid ounces per hour )

96 ÷ 8 = 12 ( 8 being fl oz in each cup )

I hope that this helped!!!

Answer:

d

Step-by-step explanation:

Answer: should be 86°, not sure.

Step-by-step explanation:

Answer:

40

Step-by-step explanation:

Answer:

40.20 luv:)

Step-by-step explanation:

Answer:

You would need the intial fee in dollars/cents

Expression:

c=initial fee

x=amount of miles

[tex]1.80x+c=12[/tex]

Step-by-step explanation:

You would need the intial fee in dollars/cents

Expression:

c=initial fee

x=amount of miles

[tex]1.80x+c=12[/tex]

Answer:

x = 38/6

Step-by-step explanation:

x/5 - 2/3 = 3/2

3x - 2x5/3x2 = 3/2

3x-10/6 = 3/2

2(3x-10) = 3x6

6x-20 = 18

6x = 18+20

6x =38

x =38/6 or x = 6.33

The expected gain or loss is an illustration of mean and expected values.

The expected total gain is 83 points

The given parameters are:

The probability of rolling a 6 in a fair die is 1/6.

The probability of not rolling a 6 in a fair die is 5/6.

So, the expected gain in each game is:

[tex]\mathbf{E(x) = 20 \times \frac 16 - 3 \times \frac 56}[/tex]

[tex]\mathbf{E(x) = \frac{20}6 - \frac{15}6}[/tex]

Take LCM

[tex]\mathbf{E(x) = \frac{5}6}[/tex]

[tex]\mathbf{E(x) = 0.83}[/tex]

The number of games is 100.

So, the expected gain is:

[tex]\mathbf{Gain = 100 \times 0.83}[/tex]

[tex]\mathbf{Gain = 83}[/tex]

Hence, the expected total gain is 83 points

Read more about expected value at:

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Answer: First do 145 - 25, which is 120. Then do 120 ÷ 15 = 8. Therefore the slope intercept is y ÷ 15 = x. Their voyage will last 8 days.

Explanation: Brainliest please

Answer:

decrease

Step-by-step explanation:

the percent change measures FROM the first value. A change from 50 to 75 is a change of 50% (25 is the difference between the two numbers, and 25 is 50% of 50). A change from 75 to 50 is a change of -33.3% (25 is still the difference between the two. 25 is 33.3% of 75

It looks like given matrices are supposed to be

[tex]\begin{array}{ccccccc}\begin{bmatrix}3&2\\2&3\end{bmatrix} & & \begin{bmatrix}1&-1\\2&-1\end{bmatrix} & & \begin{bmatrix}1&2&3\\0&2&3\\0&0&3\end{bmatrix} & & \begin{bmatrix}3&1&1\\1&3&1\\1&1&3\end{bmatrix}\end{array}[/tex]

You can find the eigenvalues of matrix A by solving for λ in the equation det(A - λI) = 0, where I is the identity matrix. We also have the following facts about eigenvalues:

• tr(A) = trace of A = sum of diagonal entries = sum of eigenvalues

• det(A) = determinant of A = product of eigenvalues

(a) The eigenvalues are λ₁ = 1 and λ₂ = 5, since

[tex]\mathrm{tr}\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3 + 3 = 6[/tex]

[tex]\det\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3^2-2^2 = 5[/tex]

and

λ₁ + λ₂ = 6   ⇒   λ₁ λ₂ = λ₁ (6 - λ₁) = 5

⇒   6 λ₁ - λ₁² = 5

⇒   λ₁² - 6 λ₁ + 5 = 0

⇒   (λ₁ - 5) (λ₁ - 1) = 0

⇒   λ₁ = 5 or λ₁ = 1

To find the corresponding eigenvectors, we solve for the vector v in Av = λv, or equivalently (A - λI) v = 0.

• For λ = 1, we have

[tex]\begin{bmatrix}3-1&2\\2&3-1\end{bmatrix}v = \begin{bmatrix}2&2\\2&2\end{bmatrix}v = 0[/tex]

With v = (v₁, v₂)ᵀ, this equation tells us that

2 v₁ + 2 v₂ = 0

so that if we choose v₁ = -1, then v₂ = 1. So Av = v for the eigenvector v = (-1, 1)ᵀ.

• For λ = 5, we would end up with

[tex]\begin{bmatrix}-2&2\\2&-2\end{bmatrix}v = 0[/tex]

and this tells us

-2 v₁ + 2 v₂ = 0

and it follows that v = (1, 1)ᵀ.

Then the decomposition of A into PDP⁻¹ is obtained with

[tex]P = \begin{bmatrix}-1 & 1 \\ 1 & 1\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}1 & 0 \\ 0 & 5\end{bmatrix}[/tex]

where the n-th column of P is the eigenvector associated with the eigenvalue in the n-th row/column of D.

(b) Consult part (a) for specific details. You would find that the eigenvalues are i and -i, as in i = √(-1). The corresponding eigenvectors are (1 + i, 2)ᵀ and (1 - i, 2)ᵀ, so that A = PDP⁻¹ if

[tex]P = \begin{bmatrix}1+i & 1-i\\2&2\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}i&0\\0&i\end{bmatrix}[/tex]

(c) For a 3×3 matrix, I'm not aware of any shortcuts like above, so we proceed as usual:

[tex]\det(A-\lambda I) = \det\begin{bmatrix}1-\lambda & 2 & 3 \\ 0 & 2-\lambda & 3 \\ 0 & 0 & 3-\lambda\end{bmatrix} = 0[/tex]

Since A - λI is upper-triangular, the determinant is exactly the product the entries on the diagonal:

det(A - λI) = (1 - λ) (2 - λ) (3 - λ) = 0

and it follows that the eigenvalues are λ₁ = 1, λ₂ = 2, and λ₃ = 3. Now solve for v = (v₁, v₂, v₃)ᵀ such that (A - λI) v = 0.

• For λ = 1,

[tex]\begin{bmatrix}0&2&3\\0&1&3\\0&0&2\end{bmatrix}v = 0[/tex]

tells us we can freely choose v₁ = 1, while the other components must be v₂ = v₃ = 0. Then v = (1, 0, 0)ᵀ.

• For λ = 2,

[tex]\begin{bmatrix}-1&2&3\\0&0&3\\0&0&1\end{bmatrix}v = 0[/tex]

tells us we need to fix v₃ = 0. Then -v₁ + 2 v₂ = 0, so we can choose, say, v₂ = 1 and v₁ = 2. Then v = (2, 1, 0)ᵀ.

• For λ = 3,

[tex]\begin{bmatrix}-2&2&3\\0&-1&3\\0&0&0\end{bmatrix}v = 0[/tex]

tells us if we choose v₃ = 1, then it follows that v₂ = 3 and v₁ = 9/2. To make things neater, let's scale these components by a factor of 2, so that v = (9, 6, 2)ᵀ.

Then we have A = PDP⁻¹ for

[tex]P = \begin{bmatrix}1&2&9\\0&1&6\\0&0&2\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}1&0&0\\0&2&0\\0&0&3\end{bmatrix}[/tex]

(d) Consult part (c) for all the details. Or, we can observe that λ₁ = 2 is an eigenvalue, since subtracting 2I from A gives a matrix of only 1s and det(A - 2I) = 0. Then using the eigen-facts,

• tr(A) = 3 + 3 + 3 = 9 = 2 + λ₂ + λ₃   ⇒   λ₂ + λ₃ = 7

• det(A) = 20 = 2 λ₂ λ₃   ⇒   λ₂ λ₃ = 10

and we find λ₂ = 2 and λ₃ = 5.

I'll omit the details for finding the eigenvector associated with λ = 5; I ended up with v = (1, 1, 1)ᵀ.

• For λ = 2,

[tex]\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}v = 0[/tex]

tells us that if we fix v₃ = 0, then v₁ + v₂ = 0, so that we can pick v₁ = 1 and v₂ = -1. So v = (1, -1, 0)ᵀ.

• For the repeated eigenvalue λ = 2, we find the generalized eigenvector such that (A - 2I)² v = 0.

[tex]\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}^2 v = \begin{bmatrix}3&3&3\\3&3&3\\3&3&3\end{bmatrix}v = 0[/tex]

This time we fix v₂ = 0, so that 3 v₁ + 3 v₃ = 0, and we can pick v₁ = 1 and v₃ = -1. So v = (1, 0, -1)ᵀ.

Then A = PDP⁻¹ if

[tex]P = \begin{bmatrix}1 & 1 & 1 \\ 1 & -1 & 0 \\ 1 & 0 & -1\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}5&0&0\\0&2&0\\0&2&2\end{bmatrix}[/tex]

Answer: What do you mean? if you till me i can help you

Step-by-step explanation:

Let y = cos⁻¹(x), so that cos(y) = x.

For some angle y between 0 and π, cos(y) takes on some value between -1 and 1.

For the y in this range, we have cos(y) = -1/2 exactly when y = 2π/3.

Then

tan(cos⁻¹(-1/2)) = tan(2π/3) = sin(2π/3)/cos(2π/3) = (√3/2)/(-1/2) = -√3

Answer:

I have attached the answer below.

Step-by-step explanation:

The diagram which has red ink cannot take a perfect feeding path.

Hopefully this helps.

Answer:

6,0 10,4

Step-by-step explanation:

find the y Axis and then the x Axis

Answer:

a.

Step-by-step explanation:

Answer:

A, B, E

Step-by-step explanation:

I just put the number of fiction books over the number of nonfiction books. Then I plugged it into a calculator and if the answer was the same as 15/22, then it was right!

2385/3498=15/22

3945/5786=15/22

2340/3588≠15/22

2480/3410≠15/22

4650/6820≠15/22

2310/3696=15/22

Transformation involves changing the form of the function

The transformation that is not performed is (a) vertical shift

The function is given as:

[tex]\mathbf{y = cot(x)}[/tex]

From the complete question, the transformed function is:

[tex]\mathbf{y=3cot[\frac 15(x+2)]}[/tex]

On y = cot(x); start by translating the function 2 units left.

The rule of this transformation is:

[tex]\mathbf{(x,y) \to (x +2,y)}[/tex]

So, we have:

[tex]\mathbf{y = cot(x + 2)}[/tex]

Next, stretch the function horizontally by a factor of 1/5

The rule of this transformation is:

[tex]\mathbf{(x,y) \to (\frac 15x,y)}[/tex]

So, we have:

[tex]\mathbf{y=cot[\frac 15(x+2)]}[/tex]

Lastly, stretch the function vertically by a factor of 3

The rule of this transformation is:

[tex]\mathbf{(x,y) \to (x,3y)}[/tex]

So, we have:

[tex]\mathbf{y=3cot[\frac 15(x+2)]}[/tex]

From the above transformations, we have:

Hence, the transformation that is not performed is (a) vertical shift

Read more about transformations at:

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Answer:

vertical shift

Step-by-step explanation:

edge