Automobile engines and transmissions are produced on assembly lines, and are inspected for defects after they come off their assembly lines. Those with defects are repaired. Let X represent the number of engines, and Y the number of transmissions that require repairs in a one-hour time interval. The joint probability mass function of X and Y is as follows: y x 0 1 2 3 0 0.13 0.10 0.07 0.03 1 0.12 0.16 0.08 0.04 2 0.02 0.06 0.08 0.04 3 0.01 0.02 0.02 0.02 Find the marginal probability mass function of X. Round the answers to two decimal places. pX(0) pX(1) pX(2) pX(3)

Answers

Answer 1

Answer:

[tex]\begin\\\begin{tabular}{|l|l|l|l|l|l|}x&0&1&2&4&Sum\\P(x)&0.33&0.40&0.20&0.07&1.00\end[/tex]

Step-by-step explanation:

From the question we are given the table

[tex]\begin\\\begin{tabular}{|l|l|l|l|l|} &&y \\x &0&1&2&3\\0 &0.13&0.1&0.07&0.03 \\1&0.12&0.16&0.08&0.04\\ 2&0.02&0.06&0.08&0.04\\ 3&0.01&0.02&0.02&0.02\end[/tex]

Generally the marginal probability mass function of X is mathematically given as

[tex]P(x)=\sum P(x,y)>y[/tex]

[tex]\sum P(0)=0.13+0.1+0.07+0.03=0.33\\\sum P(1)=0.12+0.16+0.08+0.04=0.40\\\sum P(2)=0.02+0.06+0.08+0.04=0.20\\\sum P(3)=0.01+0.02+0.02+0.02=0.07[/tex]

Therefore marginal probability mass function of X

[tex]\begin\\\begin{tabular}{|l|l|l|l|l|l|}x&0&1&2&4&Sum\\P(x)&0.33&0.40&0.20&0.07&1.00\end[/tex]


Related Questions

please help! 10 points

Answers

Answer:

2ddksdfkladfkjkafadfasf

PLEASE I WILL GIVE BRAINLYIEST Determine which numbers the equations can be multiplied by to create opposite terms of the x-variable.
1/2x-1/4y=-3
-1/3x + 2/3y = 5
Which number can the first equation be multiplied by?
Which number can the second equation be multiplied by?

Answers

Answer:

For the first 2 for the second 3

Step-by-step explanation:

first would be 1x the second would be -1x

Answer:

2 and 3

Step-by-step explanation:

Which are equations? Check all that apply.

Answers

Answer:

numbers 1,4,6,7 are all equations

Step-by-step explanation:

just look for the equal sign if there's no equal sign then its an expression not an equation

Answer:

All of the equations are the ones with the equal signs (=)

I hope this helps!

A circle has a diameter of
18
m. Find the area of the sector
whose central angle is 135°

Answers

Answer:

[tex]\boxed {\boxed {\sf \frac{ 243}{8} \pi , 95.3775, or \ 95.42587686 \ m^2 }}[/tex]

Step-by-step explanation:

When given the central angle in degrees, the formula for sector area is:

[tex]A=\frac{ \theta}{360} * \pi r^2[/tex]

where θ is the central angle and r is the radius.

We are given the diameter, so we must calculate the radius. The radius is half the diameter.

r= d/2

The diameter is 18 meters.

r= 18 m/2 r= 9 m

Now we know all the variables:

θ=135 r= 9 m

Substitute the values into the formula.

[tex]A=\frac{ 135}{360} * \pi (9)^2[/tex]

Solve the exponent first.

(9)²= 9 m *9 m= 81 m²

[tex]A=\frac{ 135}{360} * (81 \ m^2) \pi[/tex]

Solve the fraction.

[tex]A=\frac{ 3}{8} * (81 \ m^2) \pi[/tex]

Multiply the two rational numbers.

[tex]A=\frac{243}{8} \pi \ m^2[/tex]

The answer can be left like this, in terms of pi, or can be multiplied.

Using 3.14 as pi

[tex]A=\frac{243}{8} *3.14 \ m^2[/tex]

[tex]A= 95.3775 \ m^2[/tex]

Using the pi button as pi

[tex]A= 95.42587685 \ m^2[/tex]

The area is 243/8 π, 95.3775, or 95.42587685 square meters.

b) Simplify (4ab^2)^3​

Answers

Answer:

[tex]64a^{3} b^{6}[/tex]

Step-by-step explanation:

[tex](4ab^2)^3[/tex]

=> [tex]4^{3} a^{3} b^{6}[/tex]

=> [tex](4 \times 4 \times 4) a^{3} b^{6}[/tex]

=> [tex]64a^{3} b^{6}[/tex]

An experiment consists of first rolling a die and then tossing a coin.
(a) List the sample space. {(1, H), (2, H), (3, H), (4, H), (5, H), (6, H)} {(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)} {(3, H), (4, H)} {(1, T), (2, T), (3, T), (4, T), (5, T), (6, T)} {(3, H), (3, T), (4, H), (4, T)}
(b) Let A be the event that either a three or a four is rolled first, followed by landing a head on the coin toss. Find P(A). (Enter your probability as a fraction.)
P(A) =
(c) Suppose that a new experiment consists of first rolling a die and then tossing a coin twice. Let B be the event that the first and second coin tosses land on heads. Let C be the event that either a three or a four is rolled first, followed by landing a head on the first coin toss. Are the events B and C mutually exclusive? Explain your answer.
A. Events B and C are mutually exclusive because they have different probabilities.
B. Events B and C are mutually exclusive because the first and second coin tosses cannot land on heads when a three or four is rolled first.
C. Events B and C are not mutually exclusive because the first and second coin tosses can land on heads when a three or four is rolled first.
D. Events B and C are mutually exclusive because they are dependent events.

Answers

Answer:

A

Step-by-step explanation:

I think letter C the die is consisting of 6 number 1,2,3,4,5,6 and the coin H,T. The probability of tossing a coin are only two while rolling a die has six probability that it will land either three or fou.r

A. Function
B. Not a function

Answers

Answer:

a

Step-by-step explanation:

hope this helps

Determine wether the following statement is always, sometimes, or never true. A regular polygon has all sides and angles congruent.

Answers

Answer:

most likely always. either that or sometimes I hope that answers your question!

give me stuff thats equivalent to 2/10
plz
i dont know my mafs

Answers

1/5 hgghhshzhzhzhnxhdhdhd

Simplify (x-y-5) (x-2)

Answers

x^2 - 7x - xy + 2y +10

As part of a science experiment, a student observes the growth of a population of bacteria in four different media. The table below lists the observations the student made.
Medium
Observation
1
Population increases by 10 every hour
II
Population decreases by 10 every hour
THI Population increases by 10% overy hour
M Population decreases by 10% every hour
In which media can the change in the population of bacteria be modeled by a linear function?
media I and II
media I and III
media II and IV
media III and IV

Answers

Answer:

Step-by-step explanation:

Here is the graph and I’m not sure if my answer is correct or not


A town with a population of 5,000 grows 3% per year. Find the population at the end of
10 years.

Answers

Answer:

6,500

Step-by-step explanation:

5000x.03=150

150=3%

150x10=1500

1,500+5,000= 6,500

Using the rational root theorem, identify all the possible rational roots of the equation x^4+25x^3-14x^2-19x+30

Answers

Answer: D on Edg

Step-by-step explanation:

can someone help plssss

Answers

Answer:

Step-by-step explanation:

11y-36=63

11y=99

y=9

Simplify
57
leaving your answer in index form.

Answers

2(3) - (the cube number )x 7 + 1

Mrs. Write makes cookies for the school bake sale. She uses the equation y=0.50x to determine the cost, y, for x cookies. Which best represents the constant rate at which cookies are sold at the bake sale?
A) 5 cookies per dollar
B) $2 per cookie
C) 50 cookies per dollar
D) $0.50 per cookie ​

Answers

Answer:D

Step-by-step explanation: just trust me on this one i have a 103% in 9th grade math

The distance from Salvador’s job to his house is three times greater than the distance from his house to the school. If his house is between his job and the school and the distance from his job to the school is 6 miles, how far is it from Salvador’s house to the school?

SHOW YOUR WORK pls and ty

Answers

Answer:

His school is 1.5 miles away :)

Step-by-step explanation:

6/4 = 1.5 miles

1.5 miles means his house is 1.5 miles from his school

Check the answer (1.5 times 3) = 4.5 miles so his job is 4.5 miles away.

4.5 + 1.5 = 6 miles

The distance between Salvador's house and his school is 1.5 miles

Let :

Distance from house to school = d

Therefore;

Distance from job to house = 3d

Then ;

Distance from job to school = 6 miles

Since, house is in between job and school :

Distance from job to school = d + 3d 6 miles = 4d d = 6 ÷ 4 = 1.5 miles

The distance from house to school = d ; hence, distance between his house and school is 1.5 miles.

Learn more : https://brainly.com/question/8018593?referrer=searchResults

One Season The Cougars won 20 games. They played a total of 25 games. Use the equation 20 + g = 25 to find g, the number of games the team lost.

Answers

Answer:

Step-by-step explanation:

20 + g = 25

-20        -20

        g = 5

Could you help me plz

Answers

Answer:

Step-by-step explanation:

(For a circle)

Circumference formula: π*2r

Area formula: π*r^2

1:

A)

π*2(3) =>6π=>18.84 m

B)

π*(3)^2=>9π=>28.27 m^2

2.

A)

π*2(3.1)=>6.2π=>19.47 m

B)

π*(3.1)^2=>9.61π=>30.19 m^2

what is 2x+7 plus 5 simplified

Answers

Answer:

2x+12

Step-by-step explanation:

add the 7 and the 5, you don't need to answer the equation you just need to shorten the equation.

2x+12
just combine like terms which are 7 & 5 to get 2x+12

What is the value of x in the equation 1/5x - 2/3y = 30, when y = 15?

Answers

Answer:

x = (-150)/49

Step-by-step explanation:

Solve for x:

49 x + 150 = 0

Hint: | Isolate terms with x to the left hand side.

Subtract 150 from both sides:

49 x + (150 - 150) = -150

Hint: | Look for the difference of two identical terms.

150 - 150 = 0:

49 x = -150

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 49 x = -150 by 49:

(49 x)/49 = (-150)/49

Hint: | Any nonzero number divided by itself is one.

49/49 = 1:

Answer: x = (-150)/49

5x7=
5x7=5 x (_ + _)
5x7= (5x _) + (5x_)
5x7= _ + _
5x7=

Answers

5x7=35
5x7=5x(5+2)
5x7=(5x3)+(5x4)
5x7=20+15
5x7=35

This is how I would do it :)

Answer:

5x7=35

Step-by-step explanation:

In which part of the graph is the distance from home constant?
Distance from home
4
5
Time
A. 4
B. 3
C. 2
D. 1

Answers

Answer:

I chose B. 3

Step-by-step explanation:

I chose B because the person is either staying still, not moving, or something of the sort.

Kara sells bracelets for $5 each. She represents the price of x bracelets with the expression 5 x. Which expression represents another way Kara could determine the price of x bracelets?

a: x 10/2
b: x+5
c:(x divided by 5) times 5
d: (x divided by 2 ) times 10

Answers

Answer:

C. x divided by 5 times 5

Answer: A

Step-by-step explanation: X is a variable is does not actually have a value also because 10/2 =5 and that's the same as x 5 or 5 x

What is a function? *

Answers

Answer:

A function is a process or a relation that associates each element x of a set X, the domain of the function, to a single element y of another set Y (possibly the same set), the codomain of the function.

Step-by-step explanation:

hope this helps

An expression, rule, or law that defines a relationship between one variable and another variable.

The occupancy of the room must be less than 437 people

a) p 437

c) p ≤ 437

d) p ≥ 437

Answers

it would be p < 437.

what is the nearest number to 1000 but smaller than 1000 into which 38 will divide with no remainder​

Answers

Divide 1000 by 38:

1000/ 38 = 26.316

Use the whole number and multiply it by 38:

26 x 38 = 988

The number is 988

0.7 is 0.5% of what number?

Answers

...............140...............

140. Hope this helps !!(:

Riley used the distributive property to find the product of 37 and 24. Which expression could Riley have used to find the product of the two numbers?


20(30)+7


37(20)+4


24(30+7)


30(24+7)

Answers

Answer:

Step-by-step explanation:

The second one

Answer:

distributive property

Step-by-step explanation:

u should be use the 2nd one...

37(20)+7

Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumference by eye B: Measure the diameter with a ruler, then compute the circumference C: Measure the circumference with ruler and string D: Measure the circumference by rolling the ball along a ruler

Answers

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

[tex]\to \mu=\frac{\sum xi}{n}[/tex]

       [tex]=22.8[/tex]

[tex]\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}[/tex]

       [tex]=\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187[/tex]

In point b:

[tex]\to \mu=\frac{\sum xi}{n}[/tex]

       [tex]=20.6875[/tex]  

[tex]\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}[/tex]

       [tex]=\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251[/tex]

In point c:

 [tex]\to \mu=\frac{\sum xi}{n}[/tex]

         [tex]=21[/tex]  

[tex]\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}[/tex]

       [tex]=\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179[/tex]

In point d:

[tex]\to \mu=\frac{\sum xi}{n}[/tex]

       [tex]=20.8375[/tex]  

[tex]\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}[/tex]

       [tex]=\sqrt{\frac{8.2975}{16-1}}\\\\ =\sqrt{\frac{8.2975}{15}} \\\\ =\sqrt{0.553166667} \\\\ =0.7438[/tex]

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