Answer:
The answer is C. SSA ≅ SSA.
Step-by-step explanation:
To check for similar triangles, SSA congruence would not work because the other side can be any length. Also, there is not an SSA postulate because this theorem by itself cannot prove congruence.
The other three properties do work because they show congruence unlike the other congruent factors.
Timothy invested $2,000 in an account earning 3.5% annual interest that is compounded continuously. How long will it take the investment to grow to $3,500?
Answer: 16 years
Step-by-step explanation:
The exponential function for continuous growth is given by :-
[tex]P=Ae^{rt}[/tex]
, where A = initial amount, r= rate of growth and t = time.
As per given , we have
A= $2,000, =r 3.5%=0.035 and P= $3500
put these vales in equation , we get
[tex]3500=2000e^{0.035t}\\\\\Rightarrow\ \dfrac{3500}{2000}=e^{0.035t}\\\\\Rightarrow\ 1.75=e^{0.035t}[/tex]
Taking log on both sides , we get
[tex]\ln 1.75=0.035t\\\\\Rightarrow\ t=\dfrac{\ln1.75}{0.035}=\dfrac{0.560}{0.035}=16[/tex]
Hence, it will take 16 years to grow to $3,500.
Actual time in seconds recorded when statistics students participated in an experiment t test their ability to determine when one minute 60 seconds has passed are shown below.Find the mean median mode of the listed numbers. 55 51 70 64 68 60 49?49
Step-by-step explanation:
mean add upp all the numbers and divide by how many they are
What is the true solution to the equation below? 2 in e in2×-in e in 10×= in 30 A x=30 B x=75 C x=150 D x=300
Answer:
Option B.
Step-by-step explanation:
Let as consider the given equation:
[tex]2\ln e^{\ln 2x}-\ln e^{\ln 10x}=\ln 30[/tex]
It can be written as
[tex]2(\ln 2x)-(\ln 10x)=\ln 30[/tex] [tex][\because \ln e^a=a][/tex]
[tex]\ln (2x)^2-(\ln 10x)=\ln 30[/tex] [tex][\because \ln a^b=b\ln a][/tex]
[tex]\ln \dfrac{4x^2}{10x}=\ln 30[/tex] [tex][\because \ln \dfrac{a}{b}=\ln a-\ln b][/tex]
[tex]\ln \dfrac{2x}{5}=\ln 30[/tex]
On comparing both sides, we get
[tex]\dfrac{2x}{5}=30[/tex]
Multiply both sides by 5.
[tex]2x=150[/tex]
Divide both sides by 2.
[tex]x=75[/tex]
Therefore, the correct option is B.
Answer:
b x=75
Step-by-step explanation:
The mean salary of federal government employees on the General Schedule is $59,593. The average salary of 30 state employees who do similar work is $58,800 with \sigmaσσ= $1500. At the 0.01 level of significance, can it be concluded that state employees earn on average less than federal employees? What is the critical value? Round your answer to the nearest hundredths.
Answer:
Yes it can be concluded that state employees earn on average less than federal employees
The critical value is [tex]Z_{\alpha } = - 2.33[/tex]
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = \$ 59593[/tex]
The sample size is n = 30
The sample mean is [tex]\= x = \$ 58800[/tex]
The standard deviation is [tex]\sigma = \$ 1500[/tex]
The significance level is [tex]\alpha = 0.01[/tex]
The null hypothesis is [tex]H_o : \mu = \$ 59593[/tex]
The alternative hypothesis is [tex]H_a : \mu < \$ 59593[/tex]
The critical value of [tex]\alpha[/tex] from the normal distribution table is [tex]Z_{\alpha } = - 2.33[/tex]
Generally the test statistics is mathematically evaluated as
[tex]t = \frac{\= x - \mu}{ \frac{ \sigma }{ \sqrt{n} } }[/tex]
=> [tex]t = \frac{ 58800 - 59593 }{ \frac{ 1500 }{ \sqrt{30} } }[/tex]
=> [tex]t = -2.896[/tex]
The p-value is obtained from the z-table
[tex]p-value = P(t < -2.896) = 0.0018898[/tex]
Since [tex]p-value < \alpha[/tex] , we reject the null hypothesis, hence it can be concluded that state employees earn on average less than federal employees
An economist is interested in studying the spending habits of consumers in a particular region. The population standard deviation is known to be $1,000. A random sample of 50 individuals resulted in an average expense of $15,000. What is the width of the 99% confidence interval for the mean of expense? a. 364.28 b. 728.55 c. 329.00 d. 657.99
Answer:
The width is [tex]w = \$ 729.7[/tex]
Step-by-step explanation:
From the question we are told that
The population standard deviation is [tex]\sigma = \% 1,000[/tex]
The sample size is [tex]n = 50[/tex]
The sample mean is [tex]\= x = \$ 15,000[/tex]
Given that the confidence level is 99% then the level of significance is mathematically represented as
[tex]\alpha = 100 - 99[/tex]
=> [tex]\alpha = 1\%[/tex]
=> [tex]\alpha = 0.01[/tex]
Next we obtain the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table, the value is
[tex]Z_{\frac{\alpha }{2} } = Z_{\frac{0.01 }{2} } = 2.58[/tex]
Generally margin of error is mathematically represented as
[tex]E = Z_{\frac{\alpha }{2} * \frac{\sigma }{\sqrt{n} }[/tex]
substituting values
[tex]E = 2.58 * \frac{1000 }{\sqrt{50} }[/tex]
[tex]E = 2.58 * \frac{1000 }{\sqrt{50} }[/tex]
[tex]E = 364.9[/tex]
The width of the 99% confidence interval is mathematically evaluated as
[tex]w = 2 * E[/tex]
substituting values
[tex]w = 2 * 364.9[/tex]
[tex]w = \$ 729.7[/tex]
A 14 sided die is rolled find the probability of rolling an odd number the set of equally likely outcomes is shown below
Answer:
Probability= 0.5
Step-by-step explanation:
A 14 sided die is rolled
Total number of occurrence= 14 numbers
Total odd numbers present
= 1,3,5,7,9,11,13
Total number of odd numvers present
= 7
Probability= number of required outcome/total possible outcome
Probability= 7/14
Probability= 0.5
A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has faces numbered 1, 2, 3, 4, 4, and 4. A die is selected at random and rolled four times. You are told that two rolls were 1's and two were 4's. Find the probability the die chosen was green.
Answer:
the probability the die chosen was green is 0.9
Step-by-step explanation:
Given that:
A bag contains two six-sided dice: one red, one green.
The red die has faces numbered 1, 2, 3, 4, 5, and 6.
The green die has faces numbered 1, 2, 3, 4, 4, and 4.
From above, the probability of obtaining 4 in a single throw of a fair die is:
P (4 | red dice) = [tex]\dfrac{1}{6}[/tex]
P (4 | green dice) = [tex]\dfrac{3}{6}[/tex] =[tex]\dfrac{1}{2}[/tex]
A die is selected at random and rolled four times.
As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = [tex]\dfrac{1}{2}[/tex]
The probability of two 1's and two 4's in the first dice can be calculated as:
= [tex]\begin {pmatrix} \left \begin{array}{c}4\\2\\ \end{array} \right \end {pmatrix} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^4[/tex]
= [tex]\dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4[/tex]
= [tex]\dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4[/tex]
= [tex]6 \times ( \dfrac{1}{6})^4[/tex]
= [tex](\dfrac{1}{6})^3[/tex]
= [tex]\dfrac{1}{216}[/tex]
The probability of two 1's and two 4's in the second dice can be calculated as:
= [tex]\begin {pmatrix} \left \begin{array}{c}4\\2\\ \end{array} \right \end {pmatrix} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^2 \times \begin {pmatrix} \dfrac{3}{6} \end {pmatrix} ^2[/tex]
= [tex]\dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times ( \dfrac{3}{6})^2[/tex]
= [tex]6 \times ( \dfrac{1}{6})^2 \times ( \dfrac{3}{6})^2[/tex]
= [tex]( \dfrac{1}{6}) \times ( \dfrac{3}{6})^2[/tex]
= [tex]\dfrac{9}{216}[/tex]
∴
The probability of two 1's and two 4's in both dies = P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )
The probability of two 1's and two 4's in both die = [tex]\dfrac{1}{216} \times \dfrac{1}{2} + \dfrac{9}{216} \times \dfrac{1}{2}[/tex]
The probability of two 1's and two 4's in both die = [tex]\dfrac{1}{432} + \dfrac{1}{48}[/tex]
The probability of two 1's and two 4's in both die = [tex]\dfrac{5}{216}[/tex]
By applying Bayes Theorem; the probability that the die was green can be calculated as:
P(second die (green) | two 1's and two 4's ) = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)
P(second die (green) | two 1's and two 4's ) = [tex]\dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}[/tex]
P(second die (green) | two 1's and two 4's ) = [tex]\dfrac{0.5 \times 0.04166666667}{0.02314814815}[/tex]
P(second die (green) | two 1's and two 4's ) = 0.9
Thus; the probability the die chosen was green is 0.9
Identify the decimals labeled with the letters A, B, and C on the scale below. Letter A represents the decimal Letter B represents the decimal Letter C represents the decimal
There are [tex]10[/tex] divisions between $3.2$ and $3.3$
so that means each division is $\frac{3.3-3.2}{10}=0.01$
A is the 3rd division after $3.2$, So A is $3.2+3\times0.01=3.23$
similarly, C is 3 division behind $3.2$ so it will be $3.17$
and B is $3.34$
A represents the decimal 3.23
B represents the decimal 3.34
C represents the decimal 3.17
Calculating the decimal values:We can see that there are 10 divisions between 3.2 and 3.3.
The difference between the two points for 10 divisions is 3.3 -3.2 = 0.1 unit.
Therefore, one division will be equal to 0.1/10 = 0.01 unit
So, point A is 3 divisions after 3.2, thus
A = 3.2 + 0.01×3
A = 3.23
Similarly,
B = 3.3 + 0.01×4
B = 3.34
And,
C = 3.2 - 0.01×3
C = 3.17
Learn more about decimals:
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Kim is earning money for a trip. She has saved and she earns per hour babysitting. The total amount of money earned (y) after (x) number of hours worked is given by the equation . How many hours will she need to work in order to earn for her trip?
Answer:
what is the amount of money Kim earn per hour of babysitting? Also I need to know how much trip cost to find out how many hours she need to work.
Step-by-step explanation:
What are the roots for x?
Answer:
B
Step-by-step explanation:
Use the quadractic equation, x=-b+or-sqrtb^2-4ac/2a, then simplify.
I'm really sorry that it looks messy, I don't know how to make my text look better :(
Find the measure of a.
A. 60
B. 57
C. 40
D. 80
Answer:
Option (C)
Step-by-step explanation:
Since angle 'a' is the inscribed angle of the given triangle
Therefore, angle measure of the intercepted arc will be equal to the double of the inscribed angle.
x = 2a ⇒ a = [tex]\frac{x}{2}[/tex]
By the tangent-chord theorem,
"Angle between a chord and tangent measure the half of the angle measure of intercepted minor arc"
[tex]\frac{x}{2}[/tex] = 40°
Therefore, a = [tex]\frac{x}{2}[/tex] = 40°
Option (C) will be the answer.
Please answer this correctly without making mistakes
Answer:
1/8
Step-by-step explanation:
3/8-1/8-1/8=1/8
Question:
If V7 - y = 6, then y =
A. -29
B. -5
C. 1
D. 29
[tex] \sqrt{7 - y = 6} [/tex]
Answer:
-29
Step-by-step explanation:
[tex] {\sqrt{7 - y }}^{2} = {6}^{2} [/tex]
[tex]7 - y = {6}^{2} [/tex]
y = 7-36
y = -29
Find the distance between (-8, 4) and (-8, -2).
10 units
2 units
6 units
8 units
Answer:
10
Step-by-step explanation:
A soup can has a height of 4 inches and a radius of 2.5 inches. What's the volume of soup in cubic inches that would fill one soup can? Question 3 options: A) 62.8 in3 B) 125.7 in3 C) 78.5 in3 D) 314 in3
Answer:
C. 78.5 in^3
Step-by-step explanation:
A soup can is in the shape of a cylinder. The volume of a cylinder can be found using the following formula:
[tex]v=\pi r^2h[/tex]
We know that the height is 4 inches and the radius is 2.5 inches.
r= 2.5 in
h= 4 in
[tex]v=\pi (2.5in)^2*4in[/tex]
Evaluate the exponent.
[tex](2.5 in)^2=2.5 in*2.5in=6.25 in^2[/tex]
[tex]v=\pi *6.25 in^2*4 in[/tex]
Multiply 6.25 in^2 and 4 in.
[tex]6.25 in^2*4 in=25 in^3[/tex]
[tex]v=\pi*25 in^3[/tex]
Multiply pi and 25 in^3.
[tex]v=78.5398163 in^3[/tex]
Round to the nearest tenth. The 3 in the hundredth place tells us to leave the 5 in the tenth place.
[tex]v=78.5 in^3[/tex]
78.5 cubic inches can fill one soup can.
Why is f (x) = (3x + 1/3)^2 + 8/9 not the vertex form of f (x)
not the vertex form of f (x) = 9x^2 +2x +1?
O The expression has a constant outside of the squared term.
O Some of the terms are fractions instead of integers.
O The expression is not the product of two binomials.
O The variable x has a coefficient.
Answer:
The Variable has a coefficient.
Step-by-step explanation:
A la propiedad fundamental de las proporcionas, comprueba si las siguientes son o no hay elementos a) 5/7 a 15/21 b) 20/7 a 5/3 c) 16/8 a 4/2
Answer:
fucuvucybycych tcy bic ttx TV ubtx4 cub yceec inivtxr xxv kb
Step-by-step explanation:
t tcextvtcbu6gt CNN tx r.c tct yvrr TV unu9gvt e tch r,e xxv t u.un4crcuv3cinycycr xxv yctzrctvtcrzecycyvubr xiu nyfex tut uhyh
Suppose log subscript a x equals 3, log subscript a y equals 7, and log subscript a z equals short dash 2. Find the value of the following expression. log subscript a open parentheses fraction numerator x cubed y over denominator z to the power of 4 end fraction close parentheses
Answer:
24Step-by-step explanation:
Given the following logarithmic expressions [tex]log_ax = 3, log_ay = 7, log_az = -2[/tex], we are to find the value of [tex]log_a(\frac{x^3y}{z^4} )[/tex]
[tex]from\ log_ax = 3, x = a^3\\\\from\ log_ay = 7,y = a^7\\\\from\ log_az = -2, z = a^{-2}[/tex]Substituting x = a³, y = a⁷ and z = a⁻² into the log function [tex]log_a(\frac{x^3y}{z^4} )[/tex] we will have;
[tex]= log_a(\frac{x^3y}{z^4} )\\\\= log_a(\dfrac{(a^3)^3*a^7}{(a^{-2})^4} )\\\\= log_a(\dfrac{a^9*a^7}{a^{-8}} )\\\\= log_a\dfrac{a^{16}}{a^{-8}} \\\\= log_aa^{16+8}\\\\= log_aa^{24}\\\\= 24log_aa\\\\= 24* 1\\\\= 24[/tex]
Hence, the value of the logarithm expression is 24
Find the equation of the para bola that has zeros of x = -2 and x = 3 and a y-intercept of (0,-30)
Answer:
y = 5x^2-5x-30
Step-by-step explanation:
A parabola with x-intercepts at (-2,0) and (3,0) has the equation
y = a(x+2)(x-3)
where a is to be determined.
We know that it passes through the point (0,-30), so
-30 = a(0+2)(0-3) = -6a
Therefore solve for a to get
a = 5
y = 5(x+2)(x-3)
y = 5(x^2-x+6)
y = 5x^2-5x-30
Identifying the Property of Equality
Quick
Check
Identify the correct property of equality to solve each equation.
3+x= 27
X/6 = 5
Answer:
a) Compatibility of Equality with Addition, b) Compatibility of Equality with Multiplication
Step-by-step explanation:
a) This expression can be solved by using the Compatibility of Equality with Addition, that is:
1) [tex]3+x = 27[/tex] Given
2) [tex]x+3 = 27[/tex] Commutative property
3) [tex](x + 3)+(-3) = 27 +(-3)[/tex] Compatibility of Equality with Addition
4) [tex]x + [3+(-3)] = 27+(-3)[/tex] Associative property
5) [tex]x + 0 = 27-3[/tex] Existence of Additive Inverse/Definition of subtraction
6) [tex]x=24[/tex] Modulative property/Subtraction/Result.
b) This expression can be solved by using the Compatibility of Equality with Multiplication, that is:
1) [tex]\frac{x}{6} = 5[/tex] Given
2) [tex](6)^{-1}\cdot x = 5[/tex] Definition of division
3) [tex]6\cdot [(6)^{-1}\cdot x] = 5 \cdot 6[/tex] Compatibility of Equality with Multiplication
4) [tex][6\cdot (6)^{-1}]\cdot x = 30[/tex] Associative property
5) [tex]1\cdot x = 30[/tex] Existence of multiplicative inverse
6) [tex]x = 30[/tex] Modulative property/Result
Answer:
3 + x = 27
✔ subtraction property of equality with 3
x over 6 = 5
✔ multiplication property of equality with 6
A ship leaves the port of Miami with a bearing of S80°E and a speed of 15 knots. After 1 hour, the ship turns 90° toward the south. After 2 hours, maintain the same speed. What is the bearing to the ship from port?
Answer:
The bearing is N 55.62° W
Step-by-step explanation:
ship leaves the port of Miami with a bearing of S80°E and a speed of 15 knots.
It then turns 90° towards the south after one hour.
Still maintain the same speed and direction for two hours.
The bearing is just the angle difference from the ship current location to where it started.
Let the speed be km/h
Distance covered in the first round
= 15*1
= 15km
Distance covered in the second round
=15*2
= 30 km
Angle at C = (90-80)+90
Angle at C = 10+90= 100
Let the distance between the port and the ship be c
C²= a² + b² -2abcos
C²= 15²+30²-2(15)(30)cos 100
C²= 225+900+156.28
C²= 1281.28
C= 35.8 km
Using sine formula
30/sin x= 35.8/sin 100
30/35.8 * sin 100 = sinx
0.838*0.9848= sin x
0.8253= sin x
Sin ^-1 0.8253 = x
55.62° = x
The bearing is N 55.62° W
Jan. 2 Purchased merchandise on account from Nunez Company, $20,000, terms 3/10, n/30. (Lily uses the perpetual inventory system.)
Feb. 1 Issued a 9%, 2-month, $20,000 note to Nunez in payment of account.
Mar. 31 Accrued interest for 2 months on Nunez note.
Apr. 1 Paid face value and interest on Nunez note.
July 1 Purchased equipment from Marson Equipment paying $10,000 in cash and signing a 10%, 3-month, $63,600 note.
Sept. 30 Accrued interest for 3 months on Marson note.
Oct. 1 Paid face value and interest on Marson note.
Dec. 1 Borrowed $22,800 from the Paola Bank by issuing a 3-month, 8% note with a face value of $22,800.
Dec. 31 Recognized interest expense for 1 month on Paola Bank note.
One more than the quotient of a number x and 4. Write an expression to represent:
Answer:
x/4 +1
Step-by-step explanation:
henry incorrectly said the rate 1/5 pound/ 1/20 quart can be written as the unit rate 1/100 pound per quart. What is the correct unit rate? What error did Henry likely make?
Answer:
4 pounds per quart
Step-by-step explanation:
Henry divided by 20 instead of multiplying by 20.
1/5 pound is the numerator and 1/20 quart is the denominator. To make the denominator equal to 1 quart, you need to multiply by 20.
So 1/5 x 20 = 4 pounds.
Literally, a unit rate means a rate for one.
The unit rate is 4 pounds per quartHenry used the wrong arithmetic operatorThe rate is given as:
[tex]\mathbf{Rate = \frac{1}{5}\ pound\ per\ \frac{1}{20}\ quart}[/tex]
Per means divide.
So, the expression becomes
[tex]\mathbf{Rate = \frac{1}{5}\ pound\ \div \frac{1}{20}\ quart}[/tex]
Express as products
[tex]\mathbf{Rate = \frac{1}{5}\ pound\ \times \frac{20}{1\ quart}}[/tex]
Simplify
[tex]\mathbf{Rate = \frac{1}{1}\ pound\ \times \frac{4}{1\ quart}}[/tex]
Rewrite as:
[tex]\mathbf{Rate = \frac{4\ pound}{1\ quart}}[/tex]
So, the unit rate is 4 pounds per quart
Henry's error is that: He multiplied 1/5 by 1/20, instead of dividing 1/5 by 1/20
Read more about unit rates at:
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I need some help pls! I'm getting stuck!
Answer: 3 pounds.
Step-by-step explanation:
We have two metals:
One that contains 20% nickel, let's call it metal A.
One that contains 80% nickel, let's call it metal B.
We have 6 pounds of metal B, in those 6 punds we have:
0.80*6lb = 4.8lb of nickel.
Now, if we add X pounds of metal A, then we will have:
X + 6lb in total weight.
4.8lb + 0.2*X of nickel.
And we want to have exactly 60% of nickel, so we must have that the quotient between the amount of nickel and the total weight is equal to 0.6
(4.8lb + 0.2*X)/(6lb + X) = 0.6
now we solve it for X:
(4.8lb + 0.2*X) = 0.6*(6lb + X) = 3.6lb + 0.6*X
4.8lb - 3.6lb = 0.6*X - 0.2*X
1.2lb = 0.4*X
1.2lb/0.4 = 3lb = X
We should use 3 pounds of the metal with 20% of nickel.
A 95% confidence interval indicates that:
A. 95% of the intervals constructed using this process based on samples from this population will
include the population mean
B. 95% of the time the interval will include the sample mean
C. 95% of the possible population means will be included by the interval
D. 95% of the possible sample means will be included by the interval
95% interval would be 95% of the population mean.
The answer should be:
A. 95% of the intervals constructed using this process based on samples from this population will
include the population mean
Answer:
A
Step-by-step explanation:
A 95% confidence interval indicates that 95% of the intervals constructed using this process based on samples from this population will
include the population mean
There were 18,652 geese on a lake. What is this number rounded to the ten
thousands place?
Answer:
20,000
Step-by-step explanation:
To round a number to the nearest ten thousands place, we have to look at the thousand place and see whether it crosses the "hill" of 5 as it's digit.
The thousand digit is 8, so it will round UP, making 18,652 become 20,000.
Hope this helped!
Answer:
[tex]\boxed{20,000}[/tex]
Step-by-step explanation:
Hey there!
Well the ten thousands number is 1 and the 1rst thousands place number is 8 so since 8 is more than 5 we have to round 1 UP to 2,
so the answer is 20,000.
Hope this helps :)
A market researcher believes that brand perception of one of the company's products may vary between different groups. After interviewing 307 persons, the following data was compiled. Can we conclude that brand perception is dependent on age?
Age Favorable Unfavorable Neutral Total
18-30 67 24 20 111
30-45 50 14 16 80
Over 45 69 41 26 116
Total 186 59 62 307
Find the value of the test statistic.
Answer:
The value for the Chi -square test statistics = 1.149
Step-by-step explanation:
The observed value Table can be shown better as:
Observed Value
Age Favorable Unfavorable Neutral Total
18-30 67 24 20 111
30-45 50 14 16 80
Over 45 69 21 26 116
Total 186 59 62 307
NOTE: when computing the question, in the third row and the second column, there is a mistake , the value is supposed to be 21 and not 41 because :
69 +21+ 26 will eventually give = 116
69 + 41 + 26 = 136
With that error being fix , let's get started.
Expected Value
The expected value can be determined by using the formula:
[tex]Expected \ Value = \dfrac{ row \ total \times column \ total }{grand \ total }[/tex]
For 67; (111 * 186)/307 = 67.251
For 24 : (111 * 59)/307 = 21.332
For 20 : (111 * 62)/307 = 22.417
For 50 :(80*186)/307 = 48.469
For 14 : (80* 59)/307 = 15.375
For 16 : ( 0 * 62)/307 = 16.156
For 69 : (116 * 186)/307 = 70.280
For 21 : (116* 59)/307 = 22.293
For 26 : (116*62)/307 = 23.427
Expected Value :
Age Favorable Unfavorable Neutral Total
18-30 67.251 21.332 22.417 111
30-45 48.469 15.375 16.156 80
Over 45 70.280 22.293 23.427 116
Total 186 59 62 307
The Chi - square test statistics = [tex]\dfrac{(observed \ value - Expected \ value)^2}{Expected \ value}[/tex]
For 67.251 : ( 67 - 67.251)²/67.251 = 0.0009
For 21.332 : ( 24 - 21.332)²/21.332 = 0.3337
For 22.417 : ( 20 - 22.417)²/ 22.417 = 0.2606
For 48.469 : ( 50 - 48.469)²/ 48.469 = 0.0484
For 15.375 : ( 14 - 15.375)²/ 15.375 = 0.1230
For 16.156 : ( 16 - 16.156)²/ 16.156 = 0.0015
For 70.280 : ( 69 - 70.280)²/ 70.280 = 0.0233
For 22.293 : ( 21 - 22.293)²/ 22.293 = 0.0750
For 23.427 : ( 26 - 23.427)²/ 23.427 = 0.2826
The chi square table is as follows:
Age Favorable Unfavorable Neutral Total
18-30 0.0009 0.3337 0.2606 0.5952
30-45 0.0484 0.1230 0.0015 0.1729
Over 45 0.0233 0.0750 0.2826 0.3809
Total 0.0726 0.5317 0.5447 1.149
The value for the Chi -square test statistics = 1.149
Help with this please
[tex](f+g)(x)=\sqrt{4x+6}+\sqrt{4x-6}[/tex]
Answer:
[tex]\huge\boxed{Option \ 4: (f+g)(x) = \sqrt{4x+6} + \sqrt{4x-6}}[/tex]
Step-by-step explanation:
[tex]f(x) = \sqrt{4x+6}\\ g(x) = \sqrt{4x-6}[/tex]
Adding both
[tex](f+g)(x) = \sqrt{4x+6} + \sqrt{4x-6}[/tex]
Find the volume of the cylinder. Round your answer to the nearest tenth.
Answer:
716.75 m^3
Step-by-step explanation:
Volume of a cylinder:
=> PI x R^2 x H
H = Height
R = Radius
=> PI x 3.9^2 x 15
=> PI x 15.21 x 15
=> PI x 228.15
=> 228.15 PI
or
=> 228.15 x 3.14159
=> 716.75 m^3
